SOLUTION:
Step 1:
In this question, we are given that:
There is sales tax of $9.00 on an item that costs $ 120.00 before tax.
The sales tax on a different item is $ 19.05.
We are meant to find how much the second item cost before tax.
Step 2:
Assuming that there is an equal percentage of tax,
and let the second item cost before tax be y,
then we have that:
[tex]\frac{9}{120}\text{ = }\frac{19.05}{y}[/tex]Cross-multiply, we have that:
[tex]\begin{gathered} 9\text{ x y = 19.05 x 120} \\ 9y\text{ = 2286} \\ \end{gathered}[/tex]Divide both sides by 9, we have that:
[tex]\begin{gathered} y\text{ = }\frac{2286}{9} \\ y\text{ = 254} \end{gathered}[/tex]CONCLUSION:
The cost of the second item before tax = $ 254
will give brainlist
The table shows a proportional relationship.
Workout (hours) 1 2 3
Calories Burned 320 640 960
Create a description in words for the table.
The number of hours working out is dependent on the number of calories burned. For a one-hour workout, there are 320 calories burned, and for a two-hour workout, there are 640 calories burned.
The number of hours working out is dependent on the number of calories burned. For every 320-hour workout, there is 1 calorie burned, and for every 640-hour workout, there are 2 calories burned.
The number of calories burned is dependent on the number of hours working out. For a one-hour workout, there are 320 calories burned, and for a two-hour workout, there are 640 calories burned.
The number of calories burned is dependent on the number of hours working out. For every 320-hour workout, there is 1 calorie burned, and for every 640-hour workout, there are 2 calories burned.
The description for the table in word will be A. The number of hours working out is dependent on the number of calories burned. For a one-hour workout, there are 320 calories burned, and for a two-hour workout, there are 640 calories burned.
What is a proportional relationship?Proportional connections are those in which the ratios of two variables are equal. Another way to think about them is that one variable in a proportional relationship is always a constant value multiplied by the other. This is known as the "constant of proportionality."
In this case, the table shows a proportional relationship between workout and calories burned. In 1 hour, 320 calories are burned.
In conclusion, the correct option is A.
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If you bought a stock last year for a price of $90 and it is gone down 13% since then how much is the stock worth now to the nearest cent
The stock worth is $78.3
Given,
Bought a stock last year for a price of $90
And, price gone down is 13%
To find how much is the stock worth?
No, According to the question
Firstly, find the 13% of 90 i.e.,
= 13/100 x90
= $11.7
Stock worth is
= 90 - 11.7
= 78.3
Hence, The stock worth is $78.3
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A website recorded the number of referrals it received from social media websites over a 10-year period. The results can be modeled by g = 2500(150), where is the year and SSRinterpret the values of a and & in this situation.a represents the number of referrals after 9 years, represents the growth factor of the number of referrals each yeara represents the number of referrals it received at the start of the model; &represents the decay factor of the number of referralsa represents the number of referrals after 9 years; b represents the decay factor of the number of referrals sach yeara represents the number of referrals it received at the start of the model & represents the growth factor of the number offWhat is the annual percent increase?The annual percent increase is %.
Given
[tex]y=2500(1.50)^t[/tex]Find
Interpret the values of a and b , also annual percent increase
Explanation
As the general form of growth exponential function is in the form of
[tex]\begin{gathered} y=ab^t \\ \end{gathered}[/tex]where a is the inital value
t is the time
b= 1+r = where r is the rate of growth
so , in given situation
a represents the number of referrals it received at the start of the model; and b represents the growth factor of the number of referrals
option 4 is the correct one.
now we have to find the annual percent increase
for this we have to find the final referrels after 1 years.
for this put t = 2in given equation
[tex]\begin{gathered} y=2500(1.50)^2 \\ y=5625 \end{gathered}[/tex]annual percent increase =
[tex]\begin{gathered} \frac{5625-2500}{2500}\times100 \\ \\ \frac{3125}{2500}\times100 \\ \\ 125\% \end{gathered}[/tex]Final Answer
Therefore , the correct option is d .
the annual percent increase is 125%
I can't find the last mark can someone help please
Step-by-step explanation:
right, M = ((xa + xb)/2, (ya + yb)/2) = (3.5, 3.5)
the line through O and M (I assume we need the slope-intercept form) is in general
y = ax + b
"a" is the slope, "b" is the y-intercept (the y-value when x = 0).
the slope is the ratio (y coordinate change / x coordinate change) when going from one point on the line to another.
so, our 2 points : (0, 0) and (3.5, 3.5).
x changes by +3.5 (from 0 to 3.5).
y changes by +3.5 (from 0 to 3.5).
so, the slope "a" is +3.5/+3.5 = 1.
the point (0, 0) gives us "b" (the y-value when x = 0) directly : 0.
so, the line equation is
y = x
consider triangle 1 and triangle 2for which value of Q would the two triangles be similar - 136 -105 -75-31
Given:
If the given triangles are similar.
The corresponding angles should be congruent.
Both triangles have the same angle 105 degrees.
The second angle is 31 degrees and q.
[tex]q=31^o[/tex]If triangles are similar then the value of q is 31 degrees.
A local company employs a varying number of employees each year, based on its needs. The labor costs for the company include a fixed cost of $47,312.00 each year, and $28,431.00 for each person employed for the year. For the next year, the company projects that labor costs will total $2,492,378.00. How many people does the company intend to employ next year?
For the line that passes through Y(3,0), parallel to DJ with D(-3,1) and J(3,3), complete the following: Find the slope. Write an equation in point-slope form. Graph the line.Slope:Point-slope form:
I am going to graph the situation on an external graphing utility and show you the answer, it will take a
minute, stay with me.
[tex]m\text{ = }\frac{rise\text{ }}{\text{run}}=\frac{change\text{ in y}}{\text{change in x}}=\frac{3}{1}=3[/tex][tex]y\text{ = mx+b}\rightarrow\text{ b =-1}[/tex]So the equation of the line is.
[tex]y\text{ =3x -1}[/tex][tex]y\text{ -1 = m(3-0)}[/tex]Which of the following are roots of the polynomial function?Check all that apply.F(x) = x3 + 3x2 - 9x+5A. 1 - 13B. 3 - 2C. 1D. 1. 13E. 3 + 2F. -5
we have
F(x) = x3 + 3x2 - 9x+5
solve by graphing
using a graphing tool
the figure in the attached image
REmember that the zeros
please wait a minute
the roots are -5 and 1
therefore
answer option C and F
Box #1 options is: A.true B.false
Box #2 options are: A.true B.false
Box #3 options are: A.enough B.not enough
Answers:
falsetruenot enough=======================================================
Explanation:
Let's say the claim is [tex]\text{x}^2 \ge \text{x}[/tex] true for any real number x. It certainly works for things like x = 5 and x = 27.
A counter-example to show this isn't true is to use x = 0.5
So,
[tex]\text{x}^2 \ge \text{x}\\\\0.5^2 \ge 0.5\\\\0.25 \ge 0.5\\\\[/tex]
The last statement is false, which thereby proves the original claim doesn't work for x = 0.5; by extension, the overall claim of that inequality working for any real number is false.
As you can see, all we need is one counter-example to contradict the claim to prove it false.
Unfortunately one single example is not enough evidence to prove a claim true. Think of it like saying "it's much easier to knock down a sand castle than to build it up".
Instead, we need to use a set of clearly laid out statements and reasons based on previously established theorems.
IF P(A)=0.2 P(B)=0.1 and P(AnB)=0.07 what is P(AuB) ?A.0.13 B. 0.23 C. 0.3 D.0.4
ANSWER
P(AuB) = 0.23
STEP-BY-STEP EXPLANATION:
Given information
P(A) = 0.2
P(B) = 0.1
P(AnB) = 0.07
What is P(AUB)
[tex]P(\text{AuB) = P(A) + P(B) }-\text{ P(AnB)}[/tex]The next step is to substitute the above data into the formula
[tex]\begin{gathered} P(\text{AuB) = 0.2 + 0.1 - 0.07} \\ P(\text{AuB) = 0.3 - 0.07} \\ P(\text{AuB) = 0.23} \end{gathered}[/tex]Draw the graph of the line that is perpendicular to Y= 4X +1 and goes through the point (2, 3)
Given:
[tex]\begin{gathered} y=4x+1 \\ \text{ point }(2,3) \end{gathered}[/tex]To find:
Draw a graph of a line that is perpendicular to the given line and passing through a given point.
Explanation:
As we know that relation between two slopes of perpendicular slopes of lines:
[tex]m_1.m_2=-1[/tex]Slope of given line y = 4x + 1 is:
[tex]m_2=4[/tex]So, the slope of line perpendicular to given line is:
[tex]m_2=-\frac{1}{4}[/tex]Also, so line equation that is perpendicular to given line is:
[tex]y=-\frac{1}{4}x+c...........(i)[/tex]Also, the required line is passing thorugh given point (2, 3), i.e.,
[tex]\begin{gathered} 3=-\frac{1}{4}(2)+c \\ c=3+\frac{1}{2} \\ c=\frac{7}{2} \end{gathered}[/tex]So, line equation that is perpendicular to given line is:
[tex]y=-\frac{1}{4}x+\frac{7}{2}[/tex]The required graph of line is:
3. Given x=2 and y=-3, evaluate the expression given below 2x - 3xy - 2y? A) -28 B) 28 C) 8 D) 44
Given:-
x=2,y=-3
[tex]2x-3xy-2y\text{?}[/tex]To find evalute the given expression,
[tex]2x-3xy-2y[/tex]
Subtitute the x and y value in above equation,
[tex]\begin{gathered} 2(2)-3(2)(-3)-2(-3) \\ =4-(6\times-3)+6 \\ =4-(-18)+6_{} \\ =4+18+6 \\ =28 \end{gathered}[/tex]So the required value is 28.
So the correct option B.
What is the 100th term of the arithmetic sequence below? 2x, 3x + 4, 13x - 1
We are given an arithmetic progression and are requested to find the 100th term of the progression. We need to find the value of x from the question by equating differences.
[tex]\begin{gathered} T_2-T_1=T_3-T_2 \\ 3x+4-2x=13x-1-(3x+4)=13x-1-3x-4 \\ x+4=10x-5 \\ \text{Collecting like terms gives us:} \\ 10x-x=4+5 \\ 9x=9 \\ x=1 \end{gathered}[/tex]Now we will find the actual value of our terms.
[tex]\begin{gathered} T_1=a=2(1)=2 \\ T_2=3(1)+4=7 \\ T_3=13(1)-1=12 \\ \text{Therefore,} \\ \text{ d = }T_2-T_1=T_3-T_2 \\ d=7-2=12-7=5 \end{gathered}[/tex]Common difference, d = 5
Lastly, we employ our AP formula to find the 100th term.
[tex]\begin{gathered} Tn=a+(n-1)d \\ T_{100}=2+(100-1)5 \\ T_{100}=2+(99)5=497 \end{gathered}[/tex]The 100th term is 497
At a point 125 feet from the base of a building, the angle of elevation to the third floor is 22°. What is the height of the third floor?A 53.9 feetB 14,124 feetC. 50.5 feetD. 333.3 feet
From the problem statement, we can draw the triangle shows below:
H is the height of the building we will solve for.
Shown below >>>
[tex]\begin{gathered} \tan 22=\frac{H}{125} \\ H=125\tan 22 \\ H=50.5\text{ f}eet \end{gathered}[/tex]AnswerCI need to find out how much money my school loans for donating 2200 pounds of clothing
Firs we need to find the equation of the line
x= clothing donations (pounds)
y= Amount earned (dollars)
We have the next points
(0,0)
(100,400)
We will calculate the slope
[tex]m=\frac{400-0}{100-0}=4[/tex]Therefore the equation is
y=4x
then if x=2200
y=4(2200)
y=8800
URGENT!! ILL GIVE
BRAINLIEST!!!!! AND 100 POINTS!!!!!
Answer:
-45 is an integer
√100 = 10 is a whole number
√89 is an irrational number-root
4.919191... is a rational decimal
-2/5 is a rational number-ratio
.12112111211112... is an irrational decimal
Finnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnn
An item is regularly priced at $35. Lena bought it on sale for 20% off the regular price. How much did Lena pay?
An item is regularly priced at $35.
Cost price of item = $35
Lena bought it on sale for 20% off the regular price
i.e. 20% of 35 is off in the item of cost $35
So, The amount Leena will paid = $35- 20% of 35
[tex]\begin{gathered} \text{Amount L}eena\text{ will pay =}35-20\text{ \%of35} \\ \text{Amount L}eena\text{ will pay}=35-\frac{20\times35}{100} \\ \text{Amount L}eena\text{ will pay}=35-7 \\ \text{Amount L}eena\text{ will pay}=28\text{ dollars} \end{gathered}[/tex]So, Leena will pay $28
Answer: $28
which of the relationships below represents a function with the same rate of change of the function y= -4x + 2
Given data:
The given equation of the line is y= -4x + 2.
Substitute 0 for x in the given equation.
[tex]\begin{gathered} y=-4(0)+2 \\ =2 \end{gathered}[/tex]Substitute 1 for x in the given equation.
[tex]\begin{gathered} y=-4(1)+2 \\ =-2 \end{gathered}[/tex]Thus, option (D) is correct.
Graph the following equation:(y + 4) = 2(x - 2)Step 1 of 3: Find a point on the line and the slope of the line.
Given:
The equation of line is,
[tex]y+4=2(x-2)[/tex]Find the slope of equation,
[tex]\begin{gathered} y+4=2(x-2) \\ y+4=2x-4 \\ y=2x-8 \\ \text{slope= 2} \end{gathered}[/tex]Find the points on line,
[tex]\begin{gathered} \text{For x=0,} \\ y=2x-8 \\ y=-8 \\ (x,y)=(0,-8) \\ \text{for x=4,} \\ y=2x-8 \\ y=2(4)-8 \\ y=0 \\ (x,y)=(4,0) \\ \text{For x=2} \\ y=2x-8 \\ y=2(2)-8=-4 \\ (x,y)=(2,-4) \\ \text{For }x=5 \\ y=2x-8 \\ y=2(5)-8=2 \\ (x,y)=(5,2) \end{gathered}[/tex]The graph of equation of line is,
In right triangle QRS, m S=73. In right triangle TUV m V=73.
To find:
Which theorem used to prove that both triangles are congruent.
Solution:
It is given that both triangles are right triangles. So, each one of the corresponding angles is 90 degrees.
angle M is given 73 degrees and angle V is given 73 degrees. So, we can see that two pairs of angles are equal in triangle.
Thus, AA similarity postulate can be use to prove that both triangles are congruent.
Thus, option C is correct.
Select all statements that are true about equilateral triangle ABC.
To determine statements that are correct, we proceed as follows:
Step 1: We recall the definition of an "equilateral" triangle
An equilateral triangle is one which"
- has all its sides equal to each other
- has all its internal angles equal to 60 degrees each
From the above definition, it can be concluded that
(A) Angles B and C are 60 degrees is a true statement
Step 2: We solve the triangle for x, as follows:
Now, consider the left right-triangle:
Now, we apply the sine trigonometric ratio to obtain the value of x,
[tex]undefined[/tex]Line g passes through the points (-2.6,1) and (-1.4.2.5), as shown. Find theequation of the line that passes through (0,-b) and (c,0).
The blue line passes through the points
(-2.6, 1) and (-1.4, 2.5)
I will label the coordinates as follows for reference:
[tex]x_1=-2.6,y_1=1,x_2=-1.4,y_2=2.5[/tex]Step 1: Find the slope of the blue line
The slope between two points is calculated with the formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]We substitute the values and we get that the slope of the blue line is:
[tex]m=\frac{2.5-1}{-1.4-(-2.6)}=\frac{1.5}{1.2}=1.25[/tex]The slope m of the blue line is 1.25.
step 2: With that slope, calculate b (the intercept of the blue line with the y axis).
For this we use the point - slope equation:
[tex]y=m(x-x_1)+y_1[/tex]Where we will use the sane x1 and x2 as in the previous step, so we get
[tex]\begin{gathered} y=1.25(x-(-2.6))+1 \\ y=1.25(x+2.6)+1 \\ y=1.25x+3.25+1 \\ y=1.25x+4.25 \end{gathered}[/tex]We compare this with the slope-intercept equation
[tex]y=mx+b[/tex]And we can see that the incercept b is 4.25
[tex]b=4.25[/tex]step 3: Find the value of c.
to find the value of c, we need to know at which point the blue line crosses the x axis.
Since we already have the equation of the blue line y=1.25x+4.25, and the line crosses the x axis at y=0, we substitute this to find the x value that is equal to c:
[tex]\begin{gathered} 0=1.25x+4.25 \\ -4.25=1.25x \\ \frac{-4.25}{1.25}=x \\ -3.4=x \end{gathered}[/tex]The blue line crosses the x axis at (-3.4,0), thus we can conclude that
[tex]c=-3.4[/tex]Step 4: Define the two point where the orange line passes through.
We know from the picture that the orange line passes through (c,0) and (0,-b)
Since we have the values of c = -3.4 and b=4.25, we can say that the orange line passes through (-3.4, 0) and (0, -4.25)
Step 5: Calculate the slope of the orange line.
the orange line passes through (-3.4, 0) and (0, -4.25), so we define:
[tex]undefined[/tex]AABC was dilated from point A to get AADE. Find the length of AD given a scale factor of 2.D0 3O 1005O 26EB6x-8X+2
Answer:
[tex]AD\text{ = 10}[/tex]Explanation;
Here, we want to get the length of AD
From the information given:
[tex]AD\text{ = 2AB}[/tex]Thus, mathematically:
[tex]\begin{gathered} 6x-8\text{ = 2\lparen x+2\rparen} \\ 6x-8\text{ = 2x + 4} \\ 6x-2x\text{ = 4+8} \\ 4x\text{ = 12} \\ x\text{ = }\frac{12}{4} \\ x\text{ = 3} \end{gathered}[/tex]Now, we can get AD
We simply substitute for the value of x
We have that as:
[tex]\begin{gathered} AD\text{ = 6x-8} \\ AD\text{ = 6\lparen3\rparen -8} \\ AD\text{ = 10} \end{gathered}[/tex]Hi hope you are well!!I have a question: When Debbie baby-sits she charges $5 to go the house plus $8 for every hour she is there. The expression 5+8h gives the amount in dollars she charges. How much will she charge to baby-sit for 5 hours? Please help me with this questionHave a nice day,Thanks
5 + 8h
h= number of hours
Replace h by 5 and solve
5 + 8(5)
5 +40
45
She will charge $45
What is the answer to 3/8 + 7 5/8
Given the Addition:
[tex]\frac{3}{8}+7\frac{5}{8}[/tex]You can find the sum as follows:
1. Covert the Mixed Number to an Improper Fraction:
- Multiply the Whole Number part by the denominator of the fraction.
- Add the result to the numerator.
- The denominator does not change.
Then:
[tex]7\frac{5}{8}=\frac{5+(7\cdot8)}{8}=\frac{5+56}{8}=\frac{61}{8}[/tex]2. Rewrite the Addition:
[tex]=\frac{3}{8}+\frac{61}{8}[/tex]3. Since the denominators are equal, you only need to add the numerators:
[tex]=\frac{3+61}{8}=\frac{64}{8}[/tex]4. Simplifying the fraction, you get:
[tex]=8[/tex]Hence, the answer is:
[tex]=8[/tex]Which of the following sets of ordered pairs represents a function?
A.
{ (0, -2), (-27, -13), (-10, -5), (-27, -12) }
B.
{ (-7, -14), (-9, -18), (-5, -10), (-6, -12) }
C.
{ (1, -1), (1, -27), (1, -26), (1, -17) }
D.
{ (81, 1), (81, -1), (83, 4), (86, 6) }
Answer: B
Step-by-step explanation:
For the set of ordered pairs to be a function, each x-value has to correspond to only one y-value.
In option A, the x-value of -27 corresponds to both -13 and -12.
In option C, the x-value of 1 corresponds to -1, -27, -26, and -17.
In option D, the x-value of 81 corresponds to both 1 and -1.
Question 10 of 10
Question 10
▸
Find the Error One cleaning solution uses 1 part vinegar with 2 parts water. Another cleaning solution uses 2 parts vinegar with 3 parts water
A student says that these mixtures are equivalent because, in each solution, there is one more part of water than vinegar. Find the error and
correct it.
In the first cleaning solution, the ratio of vinegar to water is
however, has a ratio of
Need help with this question?
Check Answer
The ratios
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The second solution.
equivalent
Done and
The error is that there is no proportional relationship between the ratios which is corrected and can be described as a linear relationship with the help of the equation y = m + 1.
What is the proportional relationship?Relationships between two variables that are proportional occur when their ratios are equal. Another way to consider them is that in a proportional relationship, one variable is consistently equal to the other's constant value. The "constant of proportionality" is the name of this constant.So, the ratios we have:
1:2 and 2:3.Then, performing:
1/2 = 0.52/3 = 0.67Hence, ratios of 1:2 and 2:3 are not equal.
Therefore, the error is that the relationship between the given ratios is not proportional.
As can be seen, each ratio has a difference of 1, that is:
2 - 1 = 13 - 2 = 1Therefore, when one variable changes by 1, the other variable only changes by a constant value (y = x = c).
It can therefore be described as a linear relationship, and the constant is 1.The equation has the following form:
y = x + 1Where y stands for the water solution and x for the vinegar component.
Therefore, the error is that there is no proportional relationship between the ratios which is corrected and can be described as a linear relationship with the help of the equation y = m + 1.
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Find the union of E and L.Find the intersection of E and L.Write your answers using set notation (in roster form).
For the intersection operation we have to look what elements both sets have in common, in this case both E and L has the number 8. Then the second answer is:
[tex]E\cap L=\lbrace8\rbrace[/tex]Now, the union operation adds the all elements into a single set without repetition, in this case the first answer is:
[tex]E\cup L=\lbrace-2,1,2,3,6,7,8\rbrace[/tex]Which of the following point-slope form equations could be produced with the points (3, 4) and (1, -7)?
Answer:
y - 4 = [tex]\frac{11}{2}[/tex] ( x - 3 )
Step-by-step explanation:
( [tex]x_{1}[/tex] , [tex]y_{1}[/tex] )
( [tex]x_{2}[/tex] , [tex]y_{2}[/tex] )
m = [tex]\frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex]
y - [tex]y_{1}[/tex] = m( x - [tex]x_{1}[/tex] )
~~~~~~~~~~~~~~~
( 3 , 4 )
( 1 , - 7 )
m = [tex]\frac{-7-4}{1-3}[/tex] = [tex]\frac{-11}{-2}[/tex] = [tex]\frac{11}{2}[/tex]
y - 4 = [tex]\frac{11}{2}[/tex] ( x - 3 )
23. At a company employing 140 people, 40% of the employees took the bus to work,and 5 % lived close enough to walk. The others drove cars. How many employeesdrive cars to work?Answer
Since the total percent of the employees is 100%
Since 40% of them took the bus
Since 5% walk
Add them and subtract the sum from 100% to get the percentage of who take the car
[tex]\begin{gathered} 40+5=45 \\ 100-45=55 \end{gathered}[/tex]Then 55% of the employees use cars
Since the total number of employees is 140, then
Let us find 55% of 140
Change 55% to a number by divide it by 100, then multiply it by 140
[tex]\begin{gathered} N=\frac{55}{100}\times140 \\ N=77 \end{gathered}[/tex]There are 77 employees who use cars