Answer:
D. Twice the magnitude and the same direction as vector A.
Explanation:
When multiplying a vector by a scalar (a number), the length changes but the direction stays the same.
Therefore, vector 2A is twice the magnitude of vector A, but in the same direction as vector A.
Answer:
D
Explanation:
Here the given vector to us is 2A . Here A is a vector and 2 is a Scalar number. say when you multiply a Scalar x by vector y the magnitude becomes x *y but the direction remains same . as scalar quantities have only magnitude but no direction. Here A is multiplied by 2 so the magnitude becomes 2 times but the direction remains same.
So from the given options option D , twice the magnitude and the same direction as vector A is the correct answer.
Why does a feather drift back and forth as it falls ?
(I’m confused I think it has something to do with terminal velocity though in my mind)
Answer:
you are very most correct
Explanation:
it does have something to do with terminal velocity and because the weight is so light of it any tiny gust of wind can push it back and forth and because wind is never stable thats why it moves side to side
Which scientist disproved aristotle’s idea that heavy objects fall faster than lighter objects? how?.
Galileo disproved Aristotle’s idea that heavy objects fall faster than lighter objects through his findings as specified in his books.
The study of the scientistsThe story goes that Galileo used this experiment to find that the objects fell with the same acceleration, disproving Aristotle’s theory of gravity (which states that objects fall at a speed proportional to their mass) and proving his prediction.
Before Galileo, Aristotle’s writings had been accepted as true for over a thousand years. He claimed that heavier objects fall faster than lighter ones and that an object that weighs twice as much as another will fall twice as fast.
In his book Two New Sciences, Galileo outlined his theories regarding falling objects and projectiles in general (1638).
The two disciplines were the study of motion, which helped establish physics as a discipline, and the science of materials and construction, which made significant contributions to engineering.
This theory of Galileo’s was totally based on a well-known thought experiment that he described in his book.
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a 60kg person walks from the ground to the roof of a 80m tall building. what is the person's potential energy once they get to the top?
A 60-kilogram individual ascends an 80 m-high building's roof by walking up from the ground. Once at the peak, the human has a potential energy of 44027.28 J.
This is our formula
Gravitational ability strength = mgh
here (GPE = mgh)
mg = 60.0 kg
h = 80
mg = 60.0 kg
in view that we're searching for pressure and the SI Unit for force is "N," we must convert this to force (N).
consequently, we will multiply 60.0 via nine.81.
60.0 × 9.81 = 588.6
Now that will be
⇒ mg = 588.6 N
⇒ h = 80
GPE = (588.6) × (80) = 47088 J
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A blinking light of constant period is situated on a lab cart. Which diagram best represents a photograph of light, taken every 2 seconds, as the cart moves with constant velocity?
The snapshot of light as the cart moves with constant velocity is represented by a graph with uniform displacement at each time interval.
The change in displacement with time is uniform at constant velocity. The displacement of the supplied moving item grows at the same pace.
The beginning velocity equals the ultimate velocity at constant velocity.
v₁ = v₂
The object's acceleration at constant velocity is zero since the velocity change with time is zero.
As a result, we may deduce that the graph with equal displacement at each time interval reflects a snapshot of light as the cart moves at a constant speed.
A moving object's displacement-time graph shows the distance traveled by a moving item as time passes. A vector quantity is displacement. The slope or gradient of this graph represents the velocity of the item. The displacement-time graph, also known as the position-time graph, describes an object's motion. In this graph, the displacement of the moving item is displayed on the y-axis as a dependent variable, while time is shown on the x-axis as an independent variable.
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there is an equilateral triangle with sides 2 meters in length. at one of the points is a 1 microcoulomb charge, at the second point there is a 2 microcoulomb charge, and at the third point there is a 3 microcoulomb charge. what is the magnitude of the force on the 2 microcoulomb charge?
With the concept of Coulomb's Law, the net force acting on the 2μC charge is 2.06 × 10⁻² newton.
What is Coulomb's Law?Coulomb's Law states that the force of attraction or repulsion exerted by a charged particle on another charged particle is given by,
F=kq₁q₂ / r²
Here q₁ and q₂ are the charges on the particles,
r is the separation between them
k is a constant known as Coulomb's constant, whose value is, k = 9 × 10⁹ N m²/C²
So here in the question, we have been given an equilateral triangle of side 2 meters with three-point charges at its vertices
q₁ = 1μC ,
q₂ = 2μC ,
q₃ = 3μC ,
r=2 m
From Coulomb's law,
F₂₁ = kq₁q₂/r²
F₂₁ = (9 × 10⁹ × 1 × 2 × 10⁻¹²) / 2²
F₂₁ =4.5 × 10⁻³ N
This is the force on charge q₂ because of q₁.
Similarly,
F₂₃ = kq₂q₃ / r²
F₂₃ = (9 × 10⁹ × 2 × 3 × 10⁻¹²) / 2²
F₂₃ = 18 × 10⁻³ N
Now, the resultant of the two forces will be,
F(net) = [tex]\sqrt{F_{21} ^2 + F_{23}^2 +2F_{21}F_{23}cos60}[/tex]
On substituting all the values the net force will be
F(net) = 2.06 × 10⁻² N
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effect experiment, first visible light is shone on a negatively charged electroscope. next light from a special ultraviolet light source is shone on the charged electroscope. both light sources can be made brighter or dimmer
While the flashlight light has no effect, the UV source's light discharges the electroscope.
What was Einstein's photoelectric effect experiment?According to Planck's formula, the energy of the particles that make up a beam of light is connected to their frequencies. The photons and atoms collide when that beam strikes a metal. The photoelectric effect is created by a collision when a photon's frequency is high enough to remove an electron.
What is the conclusion of the photoelectric effect?One electron interacts with each photon. The incident photon's energy is employed to both liberate the surface-bound electrons and give the expelled electrons energy.
Because it offers insights into the properties of solids as well as the properties of atoms and molecules, the photoelectric effect is extensively researched in the fields of quantum chemistry, condensed matter physics, and solid-state chemistry.
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A rocket is accelerating upward from the surface of earth with an acceleration of 4. 4 m/s2. On board the rocket is a 0. 060 kg chicken egg. What is the apparent weight of the egg?.
The apparent weight of the egg = 0.264N
Here the rocket is accelerating upward from the surface of the earth. The egg is on the rocket.
The acceleration due to gravity is 4.4m/[tex]s^{2}[/tex].
The mass of a chicken egg is 0.060 kg.
Form Newton's second law, the net force acting on a body is equal to the product of mass and acceleration due to gravity.
So form Newton's second law we know the formula i.e.,
F = m×a
= 0.06 × 4.4
= 0.264N
Therefore the apparent weight of the egg is 0.264N.
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how long does it take an automobile traveling in the left lane at 60.1 km/h to overtake (become even with) another car that is traveling in the right lane at 38.1 km/h, when the cars' front bumpers are initially 105.2 m apart?
An automobile traveling in the left lane at 60.1 km/h to overtake (become even with) another car that is traveling in the right lane at 38.1 km/h, when the cars' front bumpers are initially 105.2 m apart and the time taken is t = 17.21 seconds.
To find the time, the given values are,
Distance in,
Left lane = 60.1 km/hr
Right lane = 38.1 km/hr
Initial length d₀ = 105.2 m
What is Distance?The distance covered can be derived using the equation of motion with no acceleration.
distance d = speed v × time t
d = vt
For the first automobile,
v = 60.1 km/h
d₁ = 60.1
For the second automobile,
v = 38.1 km/h
Initial distance d = 105.2 m = 0.1052 km
d = vt + d₀.
d₂ = 38.1 t + 0.1052
For them to meet/overtake each other,
Their distance at that time must be equal.
d₁ = d₂
60.1 t = 38.1 t + 0.1052
60.1 t - 38.1 t = 0.1052
22 t = 0.1052
t = 0.1052 / 22 hr
Converting to seconds
t = 0.1052 / 22 × 3600s
t = 17.21 seconds.
The time taken for an automobile to travel is 17.21 seconds.
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What is the frequency of light emitted when an electron in a hydrogen atom jumps
from 2nd orbit to 1st orbit?
The frequency of light emitted is 24.63 x [tex]10^1^5[/tex] Hz when an electron jumps from the 2nd to the 1st orbit in a hydrogen atom.
According to Bohr, the electrons in the atom's structure are situated around the nucleus at particular energy levels. An electron must either acquire or lose energy as it transitions from one of these energy levels to another. It is known as an absorption when an electron obtains energy and as an emittance when it loses energy. Both processes involve the absorption or emission of a PHOTON energy particle, which in turn causes the absorption or emission of light. Because various elements have varying energies, they each emit or absorb light in varying quantities (wavelengths).
The wavelength or wave number is used to compute the frequency of light emitted.
The frequency of light emitted is inversely proportional to its wavelength.
Given:
Jump from 2nd orbit to 1st orbit
Planck’s constant, h = 6.626 x [tex]10^-^3^4[/tex]
To find:
Frequency of light emitted, υ = ?
Formula:
E = hυ
Calculations:
[tex]E = 13.6 * Z^2( \frac{1}{n_1^2} - \frac{1}{n_2^2} )[/tex]
E = hυ = 13.6 x 1 x [tex](1 - \frac{1}{4})[/tex]
υ x 6.626 x [tex]10^-^3^4[/tex] = 10.2 x 1.6 x [tex]10^-^1^9[/tex]
υ = 24.63 x [tex]10^1^5[/tex] Hz
Result:
The frequency of light emitted is 24.63 x [tex]10^1^5[/tex] Hz.
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When a gas undergoes a quasi-static isobaric change in volume from 10.0 to 2.0 l, 15 j of work from an external source are required. what is the pressure of the gas?
When a gas undergoes a quasi-static isobaric change in volume from 10.0 to 2.0 l, 15 j of work from an external source are required then the pressure of the gas is
Work done is given as
W=PdV
15 = P ×( 20-10)
P = 1.5 bar
Define pressure.The force delivered perpendicularly to an object's surface per unit area across which that force is dispersed is known as pressure (symbol: p or P). The pressure relative to the surrounding air is known as gauge pressure, also written gage pressure[a].
Pressure is expressed using a variety of units. Some of these result from dividing a unit of force by a unit of area; the pound-force per square inch (psi), which is equivalent to one newton per square meter (N/m2) in the SI, is the standard unit of pressure in the imperial and U.S.
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two large, parallel conducting plates carrying opposite charges of equal magnitude are separated by 2.20 cm. (a) if the surface charge density for each plate has magnitude 47.0 nc>m2 , what is the magnitude of e s in the region between the plates? (b) what is the potential difference between the two plates? (c) if the separation between the plates is doubled while the surface charge density is kept constant at the value in part (a), what happens to the magnitude of the electric field and to the potential difference?
In here E = 5.3 x 10^3 N/C, the potential difference (V) between the two plates is 116.6 V and if d is doubled, electric field E won't change but V gets doubled.
How to calculate by applying the concepts?a) The electric field of infinite parallel plates can be formulated as
E= σ/2ε0 → eq1
Surface charge density is given as 47.0 nc/m2
So, the electric field is independent on d.
Hence the, so the net field is
E = E1 + E2 = σ/2ε0 + σ/2ε0 = σ/ε0
Substituting in eq 1,
E = [47 x 10^(-9) ] / 8.85 x 10^-12 = 5.3 x 10^3 N/C
b) Since the electric potential between them at any point and is given by.
V=Ed → eq 2
So, Substituting in eq 2 yields
V= 2.2 x 10^-2 x 5.3 x 10^3 = 116.6 V
c) If the distance between plates is doubled it will make no changes on the field because the field is independent on d.
For the voltage, according to equation 2 the voltage depends on d so if d is doubled then the potential between plates must be doubled.
Thus, magnitude of e in the region is 5.3 x 10^3 N/C.
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A motorcycle starts from rest and accelerates to a speed of 20 m/s in a time of 8s. What is the motorcycle’s average acceleration?
Answer: Acceleration=Change in speed/time
=(20–8)/10
=1.2m/s²
We can find the distance travelled by using the kinematic equation
S=ut+½at²
S=8*10+½*1.2*100
S=80+0.6*100
S=80+60
S=140m
Explanation: hope this helps and good lucky!!
A rocket is accelerating upward from the surface of earth with an acceleration of 4. 4 m/s2. On board the rocket is a 0. 060 kg chicken egg. What is the apparent weight of the egg?.
The apparent weight of the egg is found to be 0.852 N.
Given here, the mass of the egg is m=0.06kg, acceleration due to gravity g =9.8m/s², acceleration of rocket a = 4.4m/s².
Now, we calculate apparent weight by the formula,
We = m (a + g)
= 0.06( 4.4+ 9.8)
= 0.8528 newton.
Thus, the apparent weight of the egg is found to be 0.8528N.
An object’s perceived weight, which reflects how heavy it is, is a quality. When the force of gravity acting on an object is not counter balanced by a force of equal but opposite normality, the apparent weight of the object will differ from the actual weight of the thing.
The buoyant force pushing up on the object is subtracted from the apparent weight, which is equal to the actual weight (w=mg). The apparent weight of the object at its lowest point would be equal to its normal force.
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A utility line worker is installing a new transformer to restore electric power to a neighborhood. She drops a
screwdriver. The screwdriver takes 3.5 seconds to hit the ground. What is the height of the utility pole she
has climbed?
The height of the utility pole she has climbed is 60 m
Motion Under GravityWhen an object is dropped under gravity, the initial velocity is zero. While at the maximum height reached by an object when thrown up, the final velocity will be zero.
Given that a utility line worker drops a screwdriver which takes 3.5 seconds to hit the ground. The height of the utility pole can be calculated by using the formula below
h = ut + 1/2gt²
but u = 0
h = 1/2gt²
Substitute all the parameters into the equation
h = 1/2 × 9.8 × 3.5²
h = 4.9 × 12.25
h = 60.025 m
Therefore, the height of the utility pole she has climbed is 60 m approximately.
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What causes cosmic microwave background energy
Answer: The Big Bang!
a ball is thrown directly downward with an initial speed of 8.35 m/s from a height of 29.6 m. after what time interval does it strike the gro
Answer:
The ball will be strike at the ground in 15.98s.Explanation:
Given that
a ball is thrown directly downward with an initial speed of 8.35 m/s from a height of 29.6 m.To find
what time interval does it strike the ground ?So, according the question
We have,
Initial speed [tex]u_i = 8.35 m/s[/tex]Initial Height [tex]y_i = 29.6m[/tex]The formula for the ball's height as a function of time is
[tex]y_f = y_i - u_it - \frac{1}{2} gt^2[/tex]------------------(1)
where,
[tex]y_f = final \;height=0\\y_i = initial \;height=29.6m\\u_i = initial \;velocity=8.35m/s\\\;\; g = acceleration \;due\; to\; gravity= 9.81m/s^2[/tex]
Now, putting the all given values ,
[tex]y_f = y_i - u_it - \frac{1}{2} gt^2[/tex]------------------(1)
[tex]0 = 29.6 - 8.35t - \frac{1}{2} \times9.81t^2[/tex]
or,
[tex]9.81t^2 + 16.7t -59.2 = 0\\\\t = \frac{-16.7 \pm \sqrt{(16.7)^2-4\times 9.81\times (-59.2)}}{2}}\\t = \frac{-16.7 \pm \sqrt{278.89+4\times 9.81\times 59.2}}{2}}\\t = \frac{-16.7 \pm \sqrt{278.89+2087.57}}{2}}\\t = \frac{-16.7 \pm \sqrt{2366.46}}{2}}\\t = \frac{-16.7 \pm 48.65}{2}}\\now \; we \; know \; that\; time\;always \; in\;only\;positive\\so,\\t = \frac{-16.7 + 48.65}{2}\\t = \frac{31.95}{2}\\t = 15.98s[/tex]
Answer:
The ball will be strike at the ground in 15.98s.To learn more about Free fall please click on link
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please help u have the answers but dont know how to decode it
Answer:
Q1: C
Q2: C
Q3: D
Q4: D
Code: Left, Down, Up, Right
Your welcome.
Answer: ctrl+U
ctrl+G
Explanation:
I don't know how else to help
The FitnessGram PACER Test is a multistage aerobic capacity test that progressively gets more difficult as it continues.
The test is used to measure a student's aerobic capacity as part of the FitnessGram assessment. Students run back and forth as many times as they can, each lap signaled by a beep sound. The test get progressively faster as it continues until the student reaches their max lap score.
The PACER Test score is combined in the FitnessGram software with scores for muscular strength, endurance, flexibility and body composition to determine whether a student is in the Healthy Fitness Zone™ or the Needs Improvement Zone™.
Aluminum chloride (AlCl3) has atoms ______ aluminum atoms and ______chlorine b. 3;1 a. 1;3 c. 1;7 d. 3;7
How many protons will there be if the atom has 3 electrons and a mass of 7 amu
Answer:
[tex]{ \tt{mass \: number = protons + neutrons}} \\ { \tt{7 = p + 3}} \\ { \tt{p = 4}}[/tex]
The scientific process is most similar to:
Answer:
the process of solving a mystery.
Explanation:
a mass m is moving with a constant velocity along a line parallel to the x-axis, away from the origin. its angular momentum with respect to the origin:
The Angular momentum of mass m moving with a constant velocity about origin is constant.
Explanation and conceptL= momentum × perpendicular distance of line of action of the momentum from origin.
L=mv×y
Here it is seen that mvy is a constant, therefore the angular momentum is constant.
Concept of angular momentumThe rotational equivalent of linear momentum in physics is called angular momentum, also known as moment of momentum or rotational momentum.
Because it is a conserved quantity, while calculating the total angular momentum of a closed system, it stays constant—it is significant in physics.
The direction and the amplitude of angular momentum are all conserved. The functional characteristics of bicycles and motorbikes, frisbees, rifled bullets, and gyroscopes are due to the conservation of angular momentum.
The conservation of angular momentum also explains why neutron stars rotate rapidly and hurricanes, build spiral structures. In general, conservation restricts a system’s potential motion but does not completely define it.
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Find a vector function that represents the curve of intersection of the paraboloid z=4x2 4y2 and the cylinder y=5x2. use the variable t for the parameter.
r(t)=ti+5t²j+(4t²+50t⁴)k, For t∈ (-∞, ∞)
First plug the equation of y into the equation of z, so that we get their intersection:
We plug
y=5x²
Into:
z=4x²+4y²
So, we get:
z=4x²+2(5x²)²
z=4x²+2(25x⁴)
z=4x²+50x⁴
Then we set
x=t
And plug that in the equation [tex]y=5x^{2}[/tex] and z.
So that we get:
[tex]y=[/tex]5t², [tex]z=[/tex]4t²+50t⁴
Hence, the vector function r(t) that represents the curve of intersection is:
r(t)=ti+5t²j+(4t²+50t⁴)k, For t∈ (-∞, ∞)
A curve of intersection is made up of the common points of two transversally intersecting surfaces, which means that the surface normals are not parallel at any common point. This restriction applies only when the surfaces are touching or share surface sections.
The intersection of two non-parallel planes in Euclidean 3-space is a line in the simplest situation.
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What are the initial speed, in m/s, and the hang time (total time in the air), in s of an athlete who jumps a vertical distance of 0.8 m?
The athlete who jumps a vertical distance of 0.8 m has a initial speed of: 3.959 m/s and his total time in the air is: 0.8078 s
The formulas for the vertical launch upward and the procedures we will use are:
y max = v₀²/(2*g)t max = v₀/ gt(of) =2*t maxWhere:
v₀ = initial velocityg = gravityy max = maximum heightt max = time to reach maximum heightt(of) = time of flightInformation about the problem:
g = 9.8 m/s²y max= 0.8v₀ = ?t(of)=?Applying the maximum height formula and clearing the initial velocity we get:
y max = v₀²/(2*g)
v₀ = √(y max * (2*g))
v₀ = √( 0.8 m * (2 * 9.8 m/s²))
v₀ = √( 0.8 m * 19.6 m/s²)
v₀ = √15.68 m²/s²
v₀ = 3.959 m/s
Applying the maximum time formula we get::
t max = v₀ / g
t max =(3.959 m/s)/(9.8 m/s²)
t max = 0.4039 s
Applying the time of flight formula we get::
t(of) =2 * t max
t(of) =2 * 0.4039 s
t(of) = 0.8078 s
What is vertical launch upwards?In physics vertical launch upwards is the motion described by an object that has been launched vertically upwards in which the height and the effect of the earth's gravitational force on the launched object are taken into account.
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If the mirror is immersed in water (refractive index 1.33), what is its focal length?
If the mirror is immersed in water whose index of refraction is 1.33 , No change in its focal distance . focal distance of mirrors does not depend on the external medium in which the mirror is immersed.
What happens when a mirror is immersed in water?As the focal length of the convex mirror does not depend on the factor such as the refractive index of any medium. Hence even after the convex mirror is immersed in water, the focal distance remains unchanged. Hence the facility of the convex mirror also remains same.
How is focal distance related to refractive index?Since from lens makers formula we will observe that focal length of lens is inversely proportional to refractive index of medium of lens . Hence net index of refraction of lens decreases when it is dipped in a denser medium than air, hence focal distance increases.
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DATE
CLASS
14. The Space Shuttle must achieve a velocity of 7,800 m/s in order to orbit the
Earth If the average acceleration of the Space Shuttle is 15.3 m/s², how long will
It take for the shuttle to reach orbital velocity? Convert your answer from seconds
to minutes. Show all your work for this calculation.
Answer:
8.49673 minutes ≈ 8.5 minutes
Explanation:
Acceleration, a is defined as the rate of change in velocity divided by the change in time to attain that velocity
[tex]\mathsf a = \dfrac{\Delta v}{\Delta t} \\\\\textsf {where } \mathsf {\Delta v = v-v_0} \textsf{ v being final velocity and v_0 initial velocity}[/tex], v = final velocity and v₀ the initial velocity
and Δt is the time required to attain final velocity
Δt = number of seconds since launch = t since t₀ = 0
Therefore,
[tex]a = \dfrac{v-v_0}{t}[/tex]
The space shuttle's initial velocity is 0 m/s and its final velocity must be 7800 m/s to escape earth's gravity
So v - v₀ = 7800 - 0 = 7800 m/s, t - t₀ = t = 0 = t seconds
a = 15.3 m/s²
We have the equation
a = 7800/t
a is given as 15.3 m/s² so
15.3 = 7800/t
t = 7800/15.3 = 509.80392 seconds
To convert to minutes, divide by 60
509.80392/60 = 8.49673 minutes ≈ 8.5 minutes
Olivia was riding her bike at a speed of 4m/s when she began rolling down a hill. The hill caused her to accelerate at a rate of 2m/s 2 until she reached the end of the hill 45m later. How fast was she going when she made it to the bottom of the hill?
The speed of Olivia when she made it to the bottom of the hill is 14m/s.
Kinematics is the study of mechanical points, bodies, and systems in motion without taking into account the forces acting on them or the corresponding physical qualities.
Kinematics equations of motion define the fundamentals of an object's motion, such as its position, velocity, or acceleration over time. These three equations of motion control how an item moves in one, two, and three dimensions.
Kinetics considers physical forces as well as material characteristics such as mass stiffness and tensile or compressive strength. These characteristics can be used to take a theoretical model from kinematics and use physics and thermodynamics to determine how to construct a workable, dependable, and functional real-world system.
Given,
Initial velocity, u = 4m/s
Acceleration, a = 2m/s-2
Displacement, s= 45m
we know that,
[tex]v^{2}= u^{2} + 2as[/tex], where v= final velocity
substituting the value in the above equation, we got
[tex]v^{2}[/tex] = [tex]4^{2} + 2(2)(45)[/tex]
v = [tex]\sqrt{196}[/tex]
v = 14 m/s
Thus, the speed of Olivia going down the hill is 14m/s.
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a block of unknown material is submerged in water. light in the water is incident on the block at an angle of 31°. the angle of refraction in the block is 27°. what is the index of refraction of the unknown material?: * a. 0.67 b. 1.2 c. 1.3 d. 1.5
The unknown material is glass because the refractive index is found out to be 1.5
Calculation and step-by step process[tex]u_{water\\}[/tex]= 1.33
[tex]u_{x}[/tex]=?
[tex]u_{1}[/tex]sini=[tex]u_{2}[/tex]sin27°
[tex]u_{2}[/tex] = 1.33 x [tex]\frac{sin31}{sin27}[/tex]
= 1.33 x (0.51/0.45)
= 1.50
so, deducing from it, we have refractive index = 1.50
Hence the unknown material is glass.
What is index of refraction?
The refractive index (or refraction index) of an optical media in optics is a dimensionless quantity that indicates the capacity of that medium to bend light. The refractive index controls how much light is refracted or twisted when it enters a substance.
The angle of incidence and angle of refraction of a ray as it crosses the interface between two media with refractive indices of n1 and n2 are, respectively, n1 sin 1 and n2 sin 2, which describes this.
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Did keeping the flies in constant dark conditions abolish the light-emission oscillations?
Yes, the statement is correct that keeping the flies in constant dark conditions abolish the light-emission oscillations
What is light-emission oscillations?The electromagnetic radiation spectrum produced when an electron changes from a high energy state to a lower energy state is known as the emission spectrum of a chemical element or chemical compound. The energy difference between the two states is equal to the photon energy of the emitted photon. Each atom contains a large number of potential electron transitions, and each transition has a distinct energy difference. An emission spectrum is made up of a variety of transitions that result in various radiated wavelengths. The emission spectra of each element is distinct. Therefore, components in materials with an unknown composition can be identified via spectroscopy. Similar to this, chemical examination of substances may make use of the emission spectra of molecules.
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Nadh and fadh2 carry high energy electrons from the other stages of respiration to the electron transport chain. What does the electron transport chain use these electrons to do?.
Electron transport chain use NADH and FADH2 molecules formed in Glycolysis and Krebs Cycle processes.
The third stage of cellular respiration is the electron transport chain. In cellular respiration, high-energy electrons are transported by NADH and FADH2 to the electron transport chain. In photosynthesis, NADPH transports energetic electrons to the electron transport chain.
Krebs cycle or the TCA cycle, the process of oxidizing acetyl-CoA, which is produced from proteins, carbs, and lipids, releases stored energy.
The process by which glucose is broken down to provide energy is known as glycolysis. It generates two pyruvate molecules, ATP, NADH, and water. There is no need for oxygen throughout the process, which occurs in the cytoplasm of a cell. Both aerobic and anaerobic respiration experience it.
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a water droplet falling through the air can oscillate with some angular frequency that depends on its surface tension, density, and radius. the surface tension may be interpreted as the energy per unit area of surface of the drop. if a certain drop oscillates with angular frequency $\omega,$ what is the oscillation angular frequency of a drop with half of the first drop's radius?
The oscillation angular frequency of a drop with half of the first drop's radius is 4ω
What is surface tension?Surface tension is the tension force exerted on an object by the surface of a liquid.
What is angular frequency?Angular frequency is the frequency of oscillation of a rotating object. It is given in rad/s.
What is the oscillation angular frequency of a drop with half of the first drop's radius?Given that
the angular frequency of the drop is ω and radius r.Since the energy of the drop is conserved, using the law of conservation of angular momentum, we have
Iω = I'ω' where
I = initial rotational inertia of droplet = mr² where m = mass of drop and r = initial radius of droplet, ω = initial angular frequency of droplet, I' = initial rotational inertia of droplet = mr² where m = mass of drop and r' = final radius of droplet, and ω = final angular frequency of dropletSo, Iω = I'ω'
Making ω' subject of the formula, we have
ω' = Iω/I'
ω' = mr²ω/mr'²
ω' = r²ω/r'²
Given that the drop is half of the first drop's radius, r' = r/2
So, ω' = r²ω/r'²
ω' = r²ω/(r/2)²
ω' = r²ω/r²/4
ω' = 4ω
So, the oscillation angular frequency of a drop with half of the first drop's radius is 4ω
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