The train was scheduled to arrive at 5:10 p.m. However٫it was delayed for 25 minutes. What time was it when the train arrived?

Answer:

22 is th area

Step-by-step explanation:

Answer: 17 inches

Step-by-step explanation:

The formula for finding the length of a diagonal in a rectangle is [tex]d=\sqrt{w^2+l^2}[/tex]

Where

d is the diagonal

w is the width (8 for this)

l is the length (15 for this)

Sub these values into the equation

[tex]d=\sqrt{w^2+l^2}\\d=\sqrt{(8)^2+(15)^2}[/tex]

Solve

[tex]d=\sqrt{(8)^2+(15)^2}\\d=\sqrt{64+225}\\d=\sqrt{289}\\d=17[/tex]

Answer:

Step-by-step explanation:

Answer:

13.5

Step-by-step explanation:

i just counted the whole squares and then counted the half and divided that number by 2 and added that number to the first number

9 + (9/2)

9 + 4.5

13.5

Answer:

[tex](f-g)(x)=-x^{2}+2x+8[/tex]

Step-by-step explanation:

[tex]\left( f-g\right) \left( x\right) =f\left( x\right) -g\left( x\right)[/tex]

                [tex]=2x+1-\left( x^{2}-7\right)[/tex]

                [tex]=2x+1-x^{2}+7[/tex]

                [tex]=-x^{2}+2x+8[/tex]

Answer:

1,080

Step-by-step explanation:

Multiply the different amounts of customizations to get all the possibilities 3 sizes × 4 choices of crust is 12 possibilities,
12 possibilities × 3 choices of sauce is 36 possibilities,
36 possibilities × 3 choices of cheese is 108 possibilities,
108 possibilities × 10 different toppings is 1,080 possibilities.    

Answer:

B is the answer

Step-by-step explanation:

A is a normal number
C is division along with D

So it is B

Answer:

density= 2 and 1/2

Step-by-step explanation:

The formula to find density is: density=[tex]\frac{mass}{volume}[/tex]

so the mass is 100, and the volume is 2x4=8x6=48,  100/48 equals 2 and 1/2

answer:

d

perimeter = 52.56 inches

area = 137.12 square inches

The total perimeter of the given figure is 60.56 inches and the total area of the given figure is 137.12 square inches. Therefore, option D is the correct answer.

The composite shape with trapezium and semicircle is given.

The perimeter of a shape is defined as the total distance around the shape. It is the length of the outline or boundary of any two-dimensional geometric shape. The perimeter of different figures can be equal in measure depending upon the dimensions.

The total perimeter = Perimeter of trapezium + Circumference of semicircle

Perimeter of trapezium = (8+10+10+20)

= 48 inches

Circumference of semicircle =πr

Here radius=8/2

= 4 inches

Now, 3.14×4 =12.56 inches

The total perimeter = 48+12.56

= 60.56 inches

Total area= Area of trapezium + Area of semicircle

Area of trapezium =1/2 (a+b)×h

= 1/2 (20+8)×8

= 28×4

= 112 square inches

Area of semicircle =πr²/2

= (3.14×4²)/2

= 25.12

Total area= 112+25.12

= 137.12 square inches

The total perimeter of the given figure is 60.56 inches and the total area of the given figure is 137.12 square inches. Therefore, option D is the correct answer.

To learn more about the perimeter visit:

https://brainly.com/question/6465134.

#SPJ2

Answer:

I think you need to link a picture or something

Step-by-step explanation:

Answer:

y=12

Step-by-step explanation:

y=k*x

3=5*k

k=3/5

y= (3/5)*x

y=(3/5)*20

y=12

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

let's solve ~

Perimeter of the composite figure :

Perimeter of rectangle + circumference of semi circle - common side.

Perimeter of rectangle :

[tex]\qquad \tt \dashrightarrow \:2(4 + 12)[/tex]

[tex]\qquad \tt \dashrightarrow \:2(16)[/tex]

[tex]\qquad \tt \dashrightarrow \:32 \: \: ft {}^{} [/tex]

Circumference of Semicircle :

[tex]\qquad \tt \dashrightarrow \:\pi r[/tex]

[tex]\qquad \tt \dashrightarrow \:3.14 \times 2[/tex]

[tex]\qquad \tt \dashrightarrow \:6.28 \: ft[/tex]

Length of common side = 4 feet

So, perimeter of composite figure :

[tex]\qquad \tt \dashrightarrow \:32 + 6.28 - 4[/tex]

[tex]\qquad \tt \dashrightarrow \:34.28 \: ft[/tex]

Answer:

x=15

Step-by-step explanation:

1. Solve

4x-6=54

4x-6+6=54+6 <=== Add 6 to both sides

4x=60

4x÷4=60÷4 <=== divide by 4 on both sides

x=15

2. Check

4x15-6=54 <=== Replace x with 15 to check

60-6=54 <=== 4x15 equals 60

54=54 <=== 60-6 equals 54 and 54=54

so it is correct!!

[tex] \huge\mathcal\green{ANSWER} [/tex]

[tex] \mathcal\red{755 \: minutes \: is \: equal \: to \: 12.58 \: hours.} [/tex]

[tex] \mathcal\blue{12.58 \: hours \: to \: the \: nearest \:hour \: is \: 13\: hours} [/tex]

Answer:

)-( Ï Ï'M Ä ÑËWßÏË YÖÜ ÇÄÑ WËLÇÖMË MË!!!

m∠MFE = 28°

======================

Angles m∠MFE, m∠MFP, m∠PFR lies on a straight line

→ m∠MFE + m∠MFP + m∠PFR = 180°

Solve for m∠MFE

Answer:

I do not know the full answer but its not the mean dropping

Step-by-step explanation:

i said the mean dropping and I got it wrong.

Answer:

The mean will change more than the median

Step-by-step explanation:

Answer:

20

Step-by-step explanation:

you add 15 and 5

Answer:

[tex]\sqrt{81}[/tex] = 9 :)

Step-by-step explanation:

Answer:

9

Step-by-step explanation:

Pythagorean theorem is a^2 + b^2 = c^2.

In this case, a = 12, c = 15, and we do not know the value of "b."

Let's solve by plugging the values in!

12^2 + b^2 = 15^2

144 + b^2 = 225

Subtract 144 on both sides:

b^2 = 81

b = sqrt 81

b = 9

Using the Heron's formula, the area of the parallelogram is 36.7 square units.

Heron's Formula = √[s(s - a)(s - b)(s - c)],

where,

Area of the parallelogram = 2(area of triangle)

Therefore,

The area of the triangle can be found using Heron's Formula

a = 5 units

b = 8 units

c = 11 units

s = 5 + 8 + 11 / 2 = 12 units

area of triangle = √[12(12-5)(12 - 8)(12 - 11)]

area of triangle = √12 × 7 × 4 × 1

area of triangle = √336

area of triangle = 18.3303027798

area of triangle= 18.33 units²

Therefore,

area of parallelogram = 2(18.33) = 36.6606055596

area of parallelogram = 36.7 unit²

learn more on Heron's formula here:https://brainly.com/question/12771530

The correct answer is 36.7 square units

Math

3/5 + 1/2

= 6/10 + 5/10

= 11/10

= 1(1/10)

= 1.10

Answer: If Rajan has [tex]\frac{1}{2}[/tex] of a chocolate bar, then he has to divide it 4.

[tex]\frac{1}{2}[/tex] ÷ 4 = [tex]\frac{1}{8}[/tex]

Step-by-step explanation:

[tex]\frac{1}{2}[/tex] ÷ 4

[tex]\frac{1}{2}[/tex] × [tex]\frac{1}{4}[/tex]

Multiply the numerators and denominators and you will get:    [tex]\frac{1}{8}[/tex]

Hope this helped!

Answer:

The third option

Step-by-step explanation:

the lowest point on function 1 is -7

the lowest point on function 2 is -9

Answer:

Domain: -2≤ x≤ 0

Range: -2≤ x≤ 2

The relation is a Function

Step-by-step explanation:

The Domain is all the x values.

All the x values are either equal to or greater than -2, and less than or equal to =-0

The Range is all the y values.

Apply the same logic as the domain.

A function is where no x values are the same, and since in this graph we see no vertical line, indicating the same x value, it means it is a function

Answer:

its Y (bottom left graph)

Step-by-step explanation:

i graphed the function on desmos and matched it

Answer:

10.5 units squared

Step-by-step explanation:

just count the squares up or use the formula (a+b)/2 * h .

Not sure what "each square is worth means" sorry, if you clarify I can answer

one square is 2 cm swuared.

trapezoid area = 1/2h(b1+b2)

area = 1/2(6)(10+4)

area = 3*14

area =42

When the sectors of the circle are rearranged, they are close to forming a trapezoid with a length of 2*pi*r units and a width of r units.

The area of the rearranged figure is equal to that of the circle. So, the area of the circular base 2*pi*r square units.

A trapezoid is a two-dimensional geometric shape that has four sides with only two being parallel.

Learn more about Trapezoid at:

https://brainly.com/question/1410008

Answer:

When the sectors of the circle are rearranged, they are close to forming a trapezoid with a length of 2*pi*r units and a width of r units.

What is the area of the rearranged figure?

The area of the rearranged figure is equal to that of the circle. So, the area of the circular base 2*pi*r square units.

Step-by-step explanation:

I got it right on Edmentum

The third term is 245 and the first term is 5 -> To get from the first term to the third term, we multiply it by 49.

Since in a geometric sequence, the difference between each term has to be a constant multiplier or a sequence of multipliers -> We can find the second number to be 5 x 7 = 35

So, this geometric sequence is 5 ; 35 ; 245 and so on.

-> The common ratio of this sequence is 7. (and sorry if the things above don't make sense)

Answer:

7

Step-by-step explanation:

Given:

Let the second term be "x".

⇒ 5, x, 245...

Thus, the following equations:

To find the common ratio between the three terms, we need to find the value of "x". Simplify both the equations to obtain the values of (something). Then compare both the values.

⇒ [5 × (something)] = x

⇒ [5 × (something)]/5 = x/5

⇒ (something) = x/5

⇒ x × (something) = 245

⇒ [x × (something)]/x = 245/x

⇒ (something) = 245/x

Now, let's compare both the results of (something).

⇒ x/5 = 245/x

⇒ x² = 5 x 245

⇒ x² = 1225

⇒ x = √1225 = 35

Substitute the second term into the sequence.

⇒ 5, x, 245 = 5, 35, 245

Looking at the sequence formed, we can tell that 7 is being multiplied to each term. Thus, 7 is the common ratio.

Answer:

a)  -2

b)  y = -2x + 6

Step-by-step explanation:

Question (a)

Point A = (-1, -2)

Point B = (7, 2)

[tex]\sf gradient\:of\:AB=\dfrac{change\:in\:y}{change\:in\:x}=\dfrac{2-(-2)}{7-(-1)}=\dfrac{4}{8}=\dfrac12[/tex]

If lines are perpendicular to each other, the product of their gradients will be -1.

Let g be the gradient of the perpendicular line:

[tex]\implies \sf \dfrac12 \times g=-1[/tex]

[tex]\implies \sf g=-1 \div \dfrac12=-2[/tex]

Therefore, the gradient of the line perpendicular to AB is -2

---------------------------------------------------------------------------------------------

Question (b)

[tex]\sf midpoint\:of\:line = \left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)[/tex]

[tex]\sf let\:point\:A=(x_1,y_1)=(-1,-2)[/tex]

[tex]\sf let\:point\:B=(x_2,y_2)=(7,2)[/tex]

[tex]\sf \implies midpoint\:of\:line\:AB = \left(\dfrac{-1+7}{2},\dfrac{-2+2}{2}\right)=(3,0)[/tex]

We now know the gradient and a point on the perpendicular line.

So we can use the point-slope form of a linear equation:

[tex]\sf y-y_1=m(x-x_1)[/tex]

[tex]\implies \sf y-0=-2(x-3)[/tex]

[tex]\implies \sf y=-2x+6[/tex]

yes it is true and second is false