We want to calculate the probability of this event A: "the outcome is less than 8". To calculate this probability, we should first note that we have a total of 9 outcomes. So, we will first identify out of this outcomes cause the event A to happen.
Since the event A is saying that the outcome is less than 8, then the outcomes that would make the event A to happen would be the numbers from 1 to 7. However, to calculate this probabilty, we will use this property of probability.
Given an event A, we have the
One-third of a number b multiplied by -11 is more than 3 2
(-1,2) and (3,32)
For each of the following, find the formula for an exponential function that passes through the two points given.
The required exponential function f(x) = (4)(2)ˣ which is passes through the two points (-1,2) and (3,32).
What is an exponential function?An exponential function is defined as a function whose value is a constant raised to the power of an argument is called an exponential function.
It is a relation of the form y = aˣ in mathematics, where x is the independent variable
Let the formula for an exponential function would be as
⇒ f(x) = abˣ
The exponential function passes through the two points (-1,2) and (3,32).
f(-1) = 2
f(3) = 32
2 = ab⁻¹
2b = a
32 = ab³
Substitute the value of a = 2b in the above equation,
32 = 2b×b³
32 = 2b⁴
b⁴ = 16
b⁴ = 2⁴
b = 2
Substitute the value of b = 2 in the equation a = 2b,
So a = 2×2 = 4
⇒ f(x) = (4)(2)ˣ
Therefore, the required exponential function f(x) = (4)(2)ˣ
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You want to hang a picture on your wall the wall is 20 feet long you want to have at least 3 feet on both sides of the painting for plans to be placed right a quality showing the possible lanes of you being mean
We can consider
x = length of the painting
20 ft wall long
we want at least 3 ft per side so the total available length is 20-6= 14
x must be shorter than 14
inequality
x< 20-2(3)
x<14
O GRAPHS AND FUNCTIONSGraphing a piecewise-defined function: Problem type 1
Answer:
Explanation:
To get the plot of h(x), we just plot the given values of y at the given values of x.
For example, we are told that between x = -3.5 and -2.5, h(x) = -3. Therefore, the plot gives
The hollow circle tells us that the value x = -3.5 itself is not included. The solid circle tells us that x = -.2.5 is included. All this comes from the fact that the interval given is -3.5 < x ≤ -2.5.
Using the same method for other entries on the graph, we get our desired plot.
A math teacher said that 18 out of 25 students passed the test. What percent of thestudents did NOT pass the test?C.72%A.18%D.28%B.82%
Let's begin by listing out the given information:
18 students passed
Total students = 25
Number of people who did not pass = 25 - 18 = 7
7 out of 25 students did not pass. This has its percentage as:
[tex]\begin{gathered} \frac{7}{25}\cdot100\text{\%}=28\text{\%} \\ \Rightarrow28\text{\%} \end{gathered}[/tex]Therefore, 28% of the students did not pass
Use four rectangles to estimate the area between the graph of the function f(x) = Ty and the taxis on the interval 12, 6) using the left endpointsof the subintervals as the sample points. Write the exact answer, Do not round,
To find the area using four rectangles, we will use the following equation:
[tex]Area\approx A_1_{}+A_2+A_3+A_4[/tex][tex]Area\approx f(x_1)\Delta x+f(x_2)\Delta x+f(x_3)\Delta x+f(x_4)\Delta x[/tex][tex]Area\approx f(3)\Delta x+f(4)\Delta x+f(5)\Delta x+f(6)\Delta x[/tex][tex]Area\approx(\frac{6}{7(3)})(1)+(\frac{6}{7(4)})(1)+(\frac{6}{7(5)})(1)+(\frac{6}{7(6)})(1)[/tex][tex]Area\approx\frac{57}{70}[/tex]x³ - 3x = 37
Help please :(
En un depósito había 127 bolsas de harina  cada una de 60 kg se sacaron ocho camiones de 12 bolsas cada uno cuantos kilogramos de harina quedaron en el depósito 
Based on the number of bags of flour that were taken by the trucks and the number that were in the warehouse, the amount of kilograms left in the warehouse is 1,860 kg
How to find the number of kilograms?First, find the number of bags that were taken by the trucks by the formula:
= Number of trucks x Number of bags per truck
= 8 x 12
= 96 bags
This means that the number of bags left are:
= 127 bags - 96 bags taken
= 31 bags left
The number of kilograms of flour left is:
= Number of bags left x Number of kilograms per bag
= 31 x 60
= 1,860 kg
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Multiplying Polynomials. Find the product and write the answer in standard form.
Given:
There are given that the expression:
[tex]-9b(a+4b)[/tex]Explanation:
Multiply -9b into the value of bracket.
So,
[tex]-9b(a+4b)=-9ab-36b^2[/tex]Final answer:
Hence, the equation is shown below:
[tex]-9ab-36b^2[/tex]
Evaluate the logarithmLog 6 1/36
Answer:
-2
Explanation:
By properties of logarithms, the logarithm of a fraction is equal to the difference of logarithms, so
[tex]\log _6(\frac{1}{36})=\log _61-\log _636[/tex]Now, log₆(1) = 0 and log₆36 = 2, so
[tex]\begin{gathered} \log _6(\frac{1}{36})=0-2 \\ \log _6(\frac{1}{36})=-2 \end{gathered}[/tex]Therefore, the answer is -2
In the diagram below, DE is parallel to yy. What is the value of x? 110° A. 90 0 B. 120 O C. 110 O D. 70
Angle shown x is corresponding angle to 110 degree angle shown (from property of transversal cutting a pair of parallel lines).
hence
x = 110
please helpppppp i dont get it
The subtraction of the mixed fractions and presenting the result in simplest form gives;
[tex] \displaystyle{9 \frac{2}{5} - 4 \frac{4}{5} = 14 \frac{1}{5}} [/tex]
What is are mixed fractions?A mixed fraction is one that has both a quotient part as a whole number, the remainder, as the numerator of the fraction part, and the divisor as the denominator of the fraction part.
The equation involves the subtraction of mixed fractions, which are expressed as follows;
[tex] \displaystyle{9 \frac{2}{5} - 4 \frac{4}{5} } = [/tex]
To subtract the mixed fractions, the mixed fraction can first be rearranged into improper fractions as follows;
[tex] \displaystyle{ \frac{5 \times 9 + 2}{5} - \frac{5 \times 4 + 4}{5} = \frac{47}{5} + \frac{24}{5} }[/tex]
[tex] \displaystyle{ \frac{47}{5} + \frac{24}{5} = \frac{71}{5} }[/tex]
The result of the addition of the improper fraction which is also an improper fraction can be rearranged into partial fractions again as follows;
71 = 5 × 14 + 1
Which gives;
[tex] \displaystyle{ \frac{71}{5} = 14 \frac{1}{5} }[/tex]
Therefore;
[tex] \displaystyle{9 \frac{2}{5} - 4 \frac{4}{5} = 14 \frac{1}{5}} [/tex]
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9) Professor Elderman has given the same multiple-choice final exam in his Principles ofMicroeconomics class for many years. After examining his records from the past 10 years, hefinds that the scores have a mean of 76 and a standard deviation of 12.Professor Elderman offers his class of 36 a pizza party if the class average is above 80. What isthe probability that he will have to deliver on his promise?
In this case, we'll have to carry out several steps to find the solution.
Step 01:
data:
score:
mean = 76
standard deviation = 12
Step 02:
probability:
normal distribution:
normal distribution diagram:
mean + 1 standard deviation = 76 + 12 = 88
probability (class average score is above 80):
p (score > 80) = 34% + 13.5% + 2.4% + 0.1% = 50% = 0.5
The answer is:
p (score > 80) = 50% = 0.5
a student teacher is given a guideline that a student should be able to finish a 32 question test in 28 minutes if the student teacher is planning to give a test that contains 160 questions and the average students complete question of the same rate as previously State how many minutes should you plan for the average student to complete the test.
since the student do 32 questions in a time of 28 minutes, then the rate of response is 32/28=8/7 questions/minute ,then the students will be able to complete 160 questions in 20(7)= 140 minutes
2 dot plots. Both number lines go from 0 to 10. Plot 1 is titled fifth grade. There are 2 dots above 1, 3 above 2, 1 above 3, 4 above 4, 5 above 5, 5 above 6, 2 above 7, 2 above 8, 0 above 9, 0 above 10. Plot 2 is titled seventh grade. There are 2 dots above 0, 2 above 1, 3 above 2, 5 above 3, 5 above 4, 3 above 5, 3 above 6, 1 above 7, and 0 above 8, 9, and 10.
The dot plot shows the number of hours, to the nearest hour, that a sample of 5th graders and 7th graders spend watching television each week. What are the mean and median?
The 5th-grade mean is
.
The 7th-grade mean is
.
The 5th-grade median is
.
The 7th-grade median is
.
The mean and the median for each data-set are given as follows:
5-th grade students:
Mean: 4.67Median: 5 hours.7-th grade students:
Mean: 3.46 hours.Median: 4 hours.Dot plotA dot plot shows the number of times that each observation appears on a data-set.
Hence the hours of the 5th-graders are as follows:
1, 1, 2, 2, 2, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 7, 7, 8, 8
The mean is the sum of all the numbers of hours divided by the number of students, hence:
Mean = (2 x 1 + 3 x 2 + 1 x 3 + 4 x 4 + 5 x 5 + 5 x 6 + 2 x 7 + 2 x 8)/(2 + 3 + 1 + 4 + 5 + 5 + 2 + 2) = 4.67.
There are 24 elements in the data-set, hence the median is the mean of the 12th and the 13th element, as follows:
Median = (5 + 5)/2 = 5.
Hence the hours of the 7th-graders are as follows:
0,0, 1, 1, 2, 2, 2, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 5, 5, 5, 6, 6, 6, 7.
Hence the mean is:
Mean = (2 x 0 + 2 x 1 + 3 x 2 + 5 x 3 + 5 x 4 + 3 x 5 + 3 x 6 + 1 x 7)/24 = 3.46.
The 12th element is of 3, the 13th of 5, hence the median is:
Median = (3 + 5)/2 = 4.
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Harper just lit a new candle and then let it burn all the way down to nothing. The length of the candle remaining unburned, in inches, can be modeled by the equation L=15-1.5t,L=15−1.5t, where tt represents the number of hours since the candle was lit. What is the slope of the equation and what is its interpretation in the context of the problem?
From the information given, the slope (m) of the equation is -1.5. This means that there is an inverse relationship between the Lenght of the Candle and the number of hours. Where, the longer the number of hours, the smaller the length of the candle. See further explanation below.
What is a slope?The slope of a line is its steepness as it goes from LEFT to RIGHT. The slope is the proportion of a line's rise, or vertical change, to its run, or horizontal change. The slope of a line is always fixed (it never changes) regardless of whatever two locations on the line are chosen.
When dealing with a linear relationship, the question is usually represented in this format:
y = mx + b; where
m = slope and
b= y-intercept (or constant)
From the case above, the equation shows the relationship between time (t) the candle spends burning and the length of the candle (l).
Logically, we can infer that there will be a negative relationship between the two but first lets us determine the slope.
Restating the equation in intercept format, we have:
L = 15 - 1.5t................................1; in intercept format the slope we have
L = -1.5t + 15 ...........................2.
Where L [tex]\sim[/tex] y; m [tex]\sim[/tex] -1.5 and t [tex]\sim[/tex] x; and b [tex]\sim[/tex] 15
Hence we can state that the m (slope) = -1.5 and that if plotted on a graph, the line crosses the y-axis at y = 15 where x = 0.
Also, if L (that is y) is set to zero, then the total time taken for ALL the candles to burn is 10 hours.
See attached graph as proof.
The logical interpretation above is hence confirmed that there is an inverse relationship between x and y. This means that the longer the time, the shorter the length of the candle.
This also means that the length of the candle cannot be or is not longer than 15.
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The slope of the equation is -3/2 describing the rate at which the length of the candle is decreasing.
What are lines and their slopes?We know lines have various types of equations, the general type is
Ax + By + c = 0.
We know slope is the rate of change of the y-axis with respect to the x-axis
also, rise over run which is (y₂ - y₁)/(x₂ - x₁).
The burning equation of the candle is represented by L = 15 - 1.5t.
Where L = length of the candle and any point of time and t = time in hours.
Now, we'll need two points from this equation to obtain the slope.
At, t = 2, L = 12. and at t = 4, L = 9.
So, the two points are (2, 12) and (4, 9).
∴ Slope(m) = (9 - 12)/(4 - 2).
Slope(m) = -3/2.
The slope of this equation describes the rate at which the height of the candle is changing.
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Solve Each System by Elimination:-12x-2y=30-4x+y=-5
We solve as follows:
-12x - 2y = 30
2(-4x + y = -5)
---------------------
-12x -2y = 30
-8x + 2y = -10
--------------------
-20x = 20 => x = -1
Now we replace the value of x in one of the original equations to solve for y, that is:
-4(-1) + y = -5 => 4 + y = -5 => y = -9
So, the solution is the point (-1, -9).
As I am completely brand new to this subject/branch of mathematics, please explain thoroughly, step by step on how to complete this This is a practice from my ACT prep guide take your time, as there is no rush *Ignore the last answer option
Remember that
The difference of squares is of the form
[tex](a+b)(a-b)=a^2-b^2[/tex]In this problem we have
[tex](3x-4y^2)(3x+4y^2)[/tex]so
a=3x
b=4y^2
therefore
Apply the difference of squares
[tex](3x-4y^2)(3x+4y^2)=(3x)^2-(4y^2)^2=9x^2-16y^4[/tex]A flower bed is in the shape of a rectangle. It measures7 yd long and 4 yd wide. Chris wants to use mulch tocover the flower bed. The mulch is sold by the squarefoot. Use the facts to find the area of the flower bed insquare feet.2ftX 5?Conversion facts for length1 foot (ft)1 yard (yd)1 yard (yd)===12 inches (in)3 feet (ft)36 inches (in) i need help with this math problem.
Answer
252 ft²
Step-by-step explanation
1 yard is equivalent to 3 feet. Using this conversion factor, the equivalence of 7 yd is:
[tex]\begin{gathered} 7\text{ yd =}7\text{ yd}\cdot\frac{3\text{ ft}}{1\text{ yd}} \\ \text{ Simplifying the units:} \\ 7\text{ yd =}\frac{7\cdot3}{1}\text{ ft} \\ 7\text{ yd }=21\text{ ft} \end{gathered}[/tex]Similarly, the equivalence of 4 yards is:
[tex]\begin{gathered} 4\text{ yd }=4\text{ yd}{}\cdot\frac{3\text{ ft}}{1\text{ yd}} \\ 4\text{ yd }=4\cdot3\text{ ft} \\ 4\text{ yd}=12\text{ ft} \end{gathered}[/tex]Therefore, the length of the bed is 21 ft and the width is 12 ft.
Finally, the area of the bed (a rectangle) is calculated as follows:
[tex]\begin{gathered} A=legnth\cdot width \\ A=21\cdot12 \\ A=252\text{ ft}^2 \end{gathered}[/tex]Nathan and some friends are going to the movies. At the theater, they sell a bag of popcorn for $6 and a drink for $4. How much would it cost if they bought 5 bags of popcorn and 7 drinks? How much would it cost if they bought pp bags of popcorn and dd drinks?Total cost, 5 bags of popcorn, and 7 drinks: Total cost, p bags of popcorn and d drinks:
a) Since the cost of a bag of popcorn is $6 and the cost of a drink is $4,
[tex]\begin{gathered} T=6\cdot5+7\cdot4 \\ \Rightarrow T=30+28=58 \\ \Rightarrow T=58 \end{gathered}[/tex]Therefore, the answer to the first question is $58.
b) Substitute 5 for p and 7 for d in the expression above; therefore,
[tex]T=6p+4d[/tex]The total cost is given by the equation T=6p+4d, where T is in dollars, p is the number of bags of popcorn and d is the number of drinks.
Which of the following is equal to - 7/4w expressed as a linear combination of vectors, if W= -1/2i- 3/2j?
Therefore, the scalar multiplication of vector -7/4 w is given by
[tex]-\frac{7}{4}w=-\frac{7}{4}(-\frac{1}{2}i-\frac{3}{2}j)[/tex][tex]=\frac{7}{8}i+\frac{21}{8}j[/tex]Hence, the linear combination is 7/8 i + 21/8 j
Write an inequality for the graph shown below. Use x for your variable. + -11-10-9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10 11 X
according to the graph, inequality is:
[tex]x\ge3[/tex]Which describes the product when two fractions greater than 0 and less than 1 are multiplied?
When you multiply two numbers, one of them greater than 0 and the other one lower than 1. The result is a number that is lower than the first one, that is, a number lower than the number greate than 0.
I need help solving an optimization math problem please :)
Answer:
Explanation:
Let the side opposite the river = x
Let the adjacent side to the river = y
Given parallelogram ABCD, diagonals AC and BD intersect at point E. AE=2x, BE=y+10, CE=x+2 and DE=4y−8. Find the length of AC.A. 8B. 6C. 2D. 4
Answer:
the length of the diagonal AC is;
[tex]8[/tex]Explanation:
Given the parallelogram ABCD, diagonals AC and BD intersect at point E.
[tex]\begin{gathered} AE=2x \\ CE=x+2 \\ BE=y+10 \\ DE=4y+8 \end{gathered}[/tex]Recall that the diagonals of a parallelogram bisect each other;
So;
[tex]AE=CE[/tex]substituting AE and CE;
[tex]\begin{gathered} 2x=x+2 \\ 2x-x=2 \\ x=2 \end{gathered}[/tex]To calculate the length of AC;
[tex]\begin{gathered} AC=2x+x+2=3x+2 \\ since\text{ x=2} \\ AC=3x+2=3(2)+2 \\ AC=6+2 \\ AC=8 \end{gathered}[/tex]Therefore, the length of the diagonal AC is;
[tex]8[/tex]XYZ is a right-angled triangle. A is a point on line XZ and B is a point on line XY. XA = XB What is the size of angle XAB? xzy= 34 degrees
A. Monkey man
Step-by-step explanation:
M+o+n+k+e
Solve the problem15) 21 and 22 are supplementary angles. What are the measures to the nearest hundredth) of the two angles?5x - 92I
∠1 is 31.5°
∠2 is 148.5°.
Given:
∠1 = x
∠2 = 5x-9
The measure of ∠1 and ∠2 are supplementary angles.
First, the value of x can be calculated as,
[tex]\begin{gathered} \angle1+\angle2=180\degree \\ 5x-9+x=180\degree \\ 6x-9=180\degree \\ 6x=180+9 \\ 6x=189 \\ x=\frac{189}{6} \\ x=31.5 \\ x=\angle1 \end{gathered}[/tex]Substitute the value of x in ∠2.
[tex]\begin{gathered} \angle2=5x-9 \\ =5(31.5)-9 \\ =157.5-9 \\ =148.5 \end{gathered}[/tex]Hence, the measure of ∠1 is 31.5° and the measure of ∠2 is 148.5°.
Two train leave stations 210 miles apart at the same time and travel toward each other. One train travels at 80 miles per hour while the other traves a 70miles per hout. How long will it take for the two trains to meet?___ hours Do not do any rounding
SOLUTION
At the same time t,
Train 1 would have covered a distance of 80t, since distance = average speed x time.
Train 2 would have covered a distance of 70t.
Now both added should give 210 miles
That is 80t + 70t = 210
150t = 210
t = 210/150
t = 1.4 hours
estimate 794 divided by 18=?
Answer:
C 40
Step-by-step explanation:
794 is about 800
18 is about 20
800/20=40
State 3 solutions to the inequality: (1 Point) 3−4>5
We have the inequality:
[tex]3x\text{ - 4 }>5[/tex]Let's find out 3 solutions, as follows:
3x - 4 > 5
Adding 4 at both sides of the inequality:
3x - 4 + 4 > 5 + 4
3x > 9
Dividing by 3 at both sides, we have:
3x/3 > 9/3
x > 3
Now, we can find 3 solutions that fulfill the condition of the inequality:
x = 4, x = 5, x = 6
These three solutions are > 3