Which expression is equivalent to StartFraction negative 18 a Superscript negative 2 Baseline b Superscript 5 Baseline Over Negative 12 a Superscript negative 4 Baseline b Superscript negative 6 Baseline EndFraction? Assume a not-equals 0, b not-equals 0.
A. StartFraction 2 a squared b Superscript 11 Baseline Over 3 EndFraction
B. StartFraction 2 a squared b Superscript 30 Baseline Over 3 EndFraction
C. StartFraction 3 a squared b Superscript 11 Baseline Over 2 EndFraction
D. StartFraction 3 a squared b Superscript 30 Baseline Over 2 EndFraction
Answer:
B
Step-by-step explanation:
I just took the test
Answer:
A.
Step-by-step explanation:
number of boys and girls are in the class are in the ratio of 7 : 5 the number of boys is 8 more than the number of girls what is a total class strength?
Answer:
Step-by-step explanation:
Given ratio of boys and girls in the class =7:5
No of boys is 8more than the girls
So
Let no of boys in the class =7x
No of girls in the class=5x
7x=5x+8
2x=8
X=8/2
X=4.
Total strength =no of boys + no of girls
=7x+5x
=7×4+5×4
= 28+20
=48.
Total strength in the class is 48.
Answer:
Total class strength = 48
Step-by-step explanation:
Boys : Girls = 7 : 5
Number of boys = 7x
Number of girls = 5x
7x - 5x = 8
2x = 8
x = 8/2
x = 4
Total strength = 7x + 5x = 12x = 12*4 = 48
Which ordered pair is a solution of the equation? Y = 7x - 3
Answer:
y-intercept: ( 0 , − 3 )
x-intercept: ( 3 7 , 0 )
Step-by-step explanation:
Which of these describes the system of linear equations below?
3x-2y=7
6x-4y=14
a) the system has no solutions.
b) the system has infinitely many solutions.
c) the ration of the-coordinate to the y-coordinate of the only solution is 2 : 1.
d) the difference between the x-coordinate and y-coordinate of the only solution is one.
Given:
The system of equations is
[tex]3x-2y=7[/tex]
[tex]6x-4y=14[/tex]
To find:
The correct statement for the given system of equations.
Solution:
On comparing the given equations and general form of linear equation, i.e., [tex]ax+by+c=0[/tex], we get
[tex]a_1=3,b_1=-2,c_1=-7[/tex]
[tex]a_2=6,b_2=-4,c_2=-14[/tex]
Here,
[tex]\dfrac{a_1}{a_2}=\dfrac{3}{6}=\dfrac{1}{2}[/tex]
[tex]\dfrac{b_1}{b_2}=\dfrac{-2}{-4}=\dfrac{1}{2}[/tex]
[tex]\dfrac{c_1}{c_2}=\dfrac{-7}{-14}=\dfrac{1}{2}[/tex]
Since, [tex]\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}[/tex], therefore, the two equations are equivalent and the system has infinitely many solutions.
Hence, the correct option is b.
3x + 12 – 6x ≤ -9 Solve, graph, and express the following inequalities in interval notation.
The solution of inequality 3x + 12 – 6x ≤ –9 will be greater than or equal to 7.
What is inequality?Inequality is defined as an equation that does not contain an equal sign. Inequality is a term that describes a statement's relative size and can be used to compare these two claims.
The inequality is given below.
3x + 12 – 6x ≤ –9
Simplify the equation, then the value of 'x' is calculated as,
3x + 12 – 6x ≤ –9
6x – 3x ≥ 12 + 9
3x ≥ 21
x ≥ 21 / 3
x ≥ 7
The solution of inequality 3x + 12 – 6x ≤ –9 will be greater than or equal to 7.
The solution is shown on the number line.
More about the inequality link is given below.
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What fraction of a metre is 20cm?
Answer:
1/5
Step-by-step explanation:
A metre is 100cm, thus
20cm/100cm= 1/5
19. Jake thinks of a secret number. He says that his secret number is more than 6 units away from 2. Write a
compound inequality that gives the possible values of Jake's number. Graph the inequality.
Need help on this Math problem
Answer:
I hope I helped :)
Step-by-step explanation:
a. The y-intercept represents b. (y = mx + b) also b is 20 because that's where the line touches the y-axis.
b. The slope represents Sam's monthly fee.
c. Sam's monthly fee is 0.4 or 2/5
d. Every 50 minutes is $20.
Subtract 7b(2a 2 +5a-7) from (7a 2 -a+3 )-3b(6a 2 -b+3)
Answer:
[tex]\huge\boxed{-32a^2b+7a^2+3b^2-35ab-a+40b+3}[/tex]
Step-by-step explanation:
[tex]7b(2a^2+5a-7)\qquad|\text{use the distributive property}\\\\=(7b)(2a^2)+(7b)(5a)+(7b)(-7)=14a^2b+35ab-49b\\\\\\(7a^2-a+3)-3b(6a^2-b+3)\qquad|\text{use the distributive property}\\\\=7a^2-a+3+(-3b)(6a^2)+(-3b)(-b)+(-3b)(3)\\\\=7a^2-a+3-18a^2b+3b^2-9b[/tex]
Substraction
[tex](7a^2-a+3-18a^2b+3b^2-9b)-(14a^2b+35ab-49b)\\\\=7a^2-a+3-18a^2b+3b^2-9b-14a^2b-35ab+49b\\\\\text{combine like terms}\\\\=(-18a^2b-14a^2b)+7a^2+3b^2-35ab-a+(-9b+49b)+3\\\\=-32a^2b+7a^2+3b^2-35ab-a+40b+3[/tex]
Find the difference between 7/10 and 1/5.
Answer:
the answer is [tex]\frac{7}{2}[/tex]
Step-by-step explanation:
(Try using Symbolab, I use it all the time it gives the correct answer and it gives good explanations.)
hope this helps :)
What is the exact value of Tangent (StartFraction pi Over 12 EndFraction)
Answer:
a
Step-by-step explanation:
just did it and got right
The required value of the trigonometric operator tan(π/12) = 2 -√3. None of them is correct.
These are the equation that contains trigonometric operators such as sin, cos.. etc. In algebraic operation.
Let,
= [tex]tan(\pi /12) = tan((3-2)\pi /12)[/tex]
[tex]= tan[(3\pi -2\pi )/12]\\=tan(3\pi /2-2\pi /12)\\=tan(\pi /4-\pi /6)\\=\frac{tan(\pi/4)-tan(\pi/6)}{1+tan(\pi/4)tan(\pi/6)}[/tex]
= [tex]\frac{1-1/\sqrt{3} }{1+1*1/\sqrt{3} } \\[/tex]
[tex]=\frac{(\sqrt{3}-1)/\sqrt{3}}{(\sqrt{3}+1))/\sqrt{3}}[/tex]
[tex]=\frac{(\sqrt{3}-1)}{(\sqrt{3}+1)}\\=\frac{(\sqrt{3}-1)(\sqrt{3}+1)}{(\sqrt{3}+1)(\sqrt{3}+1)}\\=\frac{(3-2\sqrt{3}+1)}{(3-1)}\\\\=\frac{(4-2\sqrt{3})}{(2)}\\={(2-\sqrt{3})}\\[/tex]
Thus, the required value of the trigonometric operator tan(π/12) = 2 -√3. None of them is correct.
Learn more about trigonometry equations here:
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The percentage of sprouted seeds for a single crop can be modeled by a logistic function that is represented by y=100/1+99e^-0.89x. Which statements about the scenario are true? Check all that apply.
Answer:
A, B, and C
Step-by-step explanation:
The perimeter of a football field is 920 feet. The width is 60 feet more than one-third of the length. What are the dimensions of a football field?
Given:
Perimeter of a football field = 920 feet.
The width is 60 feet more than one-third of the length.
To find:
The dimensions of a football field.
Solution:
Let the length of the field be x.
Then, width = [tex]\dfrac{1}{3}x+60[/tex]
We know that,
[tex]Perimeter = 2( length + width)[/tex]
[tex]920 = 2(x+\dfrac{1}{3}x+60)[/tex]
[tex]920 = 2(\dfrac{4}{3}x+60)[/tex]
[tex]920 =\dfrac{8}{3}x+120[/tex]
Subtract both sides by 120.
[tex]920-120 =\dfrac{8}{3}x+120-120[/tex]
[tex]800 =\dfrac{8}{3}x[/tex]
Multiply both sides by 3.
[tex]2400 =8x[/tex]
Divide both sides by 8.
[tex]300 =x[/tex]
Now,
[tex]Length = 300\text{ feet}[/tex]
[tex]Width=\dfrac{1}{3}(300)+60[/tex]
[tex]Width=100+60[/tex]
[tex]Width=160\text{ feet}[/tex]
Therefore, the length and width of the football field are 300 feet and 160 feet respectively.
2b+ 9r use b=2 and r=7
Answer:
67
Step-by-step explanation:
2b+9r
2(2)+9(7)
4+63
67
Answer:
67
Step-by-step explanation:
2(2)+9(7)
4+63=67
Have a great day
Central City High's basketball team will be entering the playoffs at the end of their regular season. There will be 3 other teams in the playoffs, with season average scores of 87, 92, and 119. Central City High has played 7 games with an average score of 91. What score range could they have in their eighth and last regular season game to have the second highest season average score in the tournament?
Answer:
99<x<315
Step-by-step explanation:
Answer:
C.
Step-by-step explanation:
edg. 2021
brainliest for right answer
Quadrilateral ABCD has coordinates A(-2,0), B(0,4), C(4,6), and D(2,2). If it is
reflected over the x-axis, what are the coordinates of C'? (Answer as an ordered
pair without spaces)
Answer:
C' (4,-6)
Step-by-step explanation:
Any point being reflected over the x-axis will undergo the following transformation:
(x, y) --> (x, -y)
(4, 6) --> (4, -6)
The coordinates of C',
C(4,6) → C'(4, -6).
What is a reflection?A reflection is a type of transformation that involves flipping a shape, known as the preimage, over a line, known as the line of reflection, to produce a new shape (called the image). You can picture what would happen if you flipped the form over the line in order to graph a reflection.
Given:
Quadrilateral ABCD has coordinates A(-2,0), B(0,4), C(4,6), and D(2,2).
If it is reflected over the x-axis,
The reflection rule:
(x, y) → (x, -y)
The coordinates of C',
C(4,6) → C'(4, -6).
Therefore, the image point of C is C'(4, -6).
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Giving brainiest explain answer
Answer:
A.) -5
Step-by-step explanation:
Slope Formula ---> [tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex] m = slope
[tex]m = \frac{2 - (-3)}{-2 - (-1)}[/tex]
Eliminate negatives:
[tex]m = \frac{2 + 3}{ -2 + 1}[/tex]
Solve:
[tex]m = \frac{5}{-1}[/tex]
Simplify:
[tex]m = -5[/tex]
cal d gradient B(4,-7), c(-6-5) and d two point find d gradient
Answer:
d = - 1/5
Step-by-step explanation:
slope form: m= y2-y1/x2-x1
m= -5-(-7)/-6-4
m= 2/-10
m= - 1/5
Is 12 even or odd? Pick you choice
Answer:
Even
Step-by-step explanation:
—16t^2 + 64t + 3
Please help as soon as possible 33 points if you do it!!
Answer:
51t^3
Step-by-step explanation:
64+3=67
67 +(-16)=51
t^2 +t= t^3
now you just add them up but they cant be combined because one is a number and the other a variable w an exponent so we just get 51t^3
The height in feet of a squirrel running up and down a tree is a function of time in seconds. Here are statements describing the squirrels movement during four intervals of time Match each description with a statement about the average rate of change of the function for that interval. The squirrel runs up the tree
Answer:
answer choices?
Step-by-step explanation:
Please help with the attatched!
Answer: a + b = 40
[tex](3+\sqrt{5})(7-6\sqrt{5})=3.7+7\sqrt{5}-3.6\sqrt{5}-6\sqrt{5}.\sqrt{5}\\\\=21+6.5-11\sqrt{5}\\\\=51-11\sqrt{5}[/tex]
because [tex](3+\sqrt{5})(7-6\sqrt{5})=a+b\sqrt{5}[/tex]
=> a = 51
b = -11
=> a + b = 51 -11 =40
Step-by-step explanation:
Answer:
[tex]a = -9 - 11\sqrt{5} - \sqrt{5}b[/tex]
a = 51
b= -11
if the nth term of a sequence is 5n+1 what is the 12th term?
Answer:
61
Step-by-step explanation:
nth=5n+1
.: 12th=5(12)+1 =60+1
=61
What does the “M” and “B” stands for in the equation y=mx+b?
Answer:
m:number that is multiplied on x b:the y-intercept
Step-by-step explanation:
In the equation of a straight line (when the equation is written as "y = mx + b"), the slope is the number "m" that is multiplied on the x, and "b" is the y-intercept (that is, the point where the line crosses the vertical y-axis). This useful form of the line equation is sensibly named the "slope-intercept form".
In the equation y = mx + b, m represents slope and b represents y intercept.
In the equation y = mx + b, the variables "m" and "b" represent coefficients or constants. Specifically:
"m" represents the slope of the line. It determines the steepness or inclination of the line.
The slope indicates how much y (the dependent variable) changes for each unit change in x (the independent variable).
"b" represents the y-intercept of the line. It is the value of y when x is equal to zero.
The y-intercept is the point where the line intersects the y-axis.
m and b define the equation of a straight line in slope-intercept form, where "m" is the slope and "b" is the y-intercept.
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For a United Way fund-raising dinner, a total of 245 tickets were sold. Adult tickets sold for $6.50, and child tickets sold for $3.00. If $1410.50 worth of tickets were sold, how many adult and child tickets were sold?
Answer:
Adults =193
children=52
Step-by-step explanation:
Step one:
let the number of tickets adults be x
and the number of tickets children be y
x+y=245--------1
6.5x+3y=1410.5---2
Step two:
solve the system of equation using substitution
x+y=245
x=245-y
put x=245-y in equation 2 we have
6.5(245-y)+3y=1410.5
1592.5-6.5y+3y=1410.5
-6y+3y=1410.5-1592.5
-3.5y=-182
y=182/3.5
y=52
put y=52 in x=245-y
x=245-52
x=193
y = 3x = 2
=
- x + 6
Is this true or false? Ill give brainliest
i think true because 0,4 on there is correct and so is 2,0
Mike purchases a $22,000 car and plans to pay back the loan by making monthly payments over the course of 5 years. The interest rate is 3%. Compute Mike’s monthly payments using the amortization formula.
$383.09
$395.32
$427.91
$442.63
1. A relation contains the ordered pairs shown. One of the ordered pairs is missing an x-coordinate. {(-1,4),(0,4),(2,5),(3,-6),(?,7)} What could be the missing x-coordinate if the relation is not a function?
Answer:
There are 4 possible scenarios where given relation could not be a function:
i) [tex](-1, 4), (0,4), (2,5), (3,-6), (-1, 7)[/tex]
ii) [tex](-1, 4), (0,4), (2,5), (3,-6), (0, 7)[/tex]
iii) [tex](-1, 4), (0,4), (2,5), (3,-6), (2, 7)[/tex]
iv) [tex](-1, 4), (0,4), (2,5), (3,-6), (3, 7)[/tex]
Step-by-step explanation:
From Function Theory, we remember that a relation is not a function when at least one element from domain (x-coordinate) is related to one or more elements from range (y-coordinate). Hence, there are four possibilities of making the relation not a function:
i) [tex](-1, 4), (0,4), (2,5), (3,-6), (-1, 7)[/tex]
ii) [tex](-1, 4), (0,4), (2,5), (3,-6), (0, 7)[/tex]
iii) [tex](-1, 4), (0,4), (2,5), (3,-6), (2, 7)[/tex]
iv) [tex](-1, 4), (0,4), (2,5), (3,-6), (3, 7)[/tex]
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What is the coefficient of the fourth term in this expression?
m3+2kn2+mn2+6k2n