The largest tensile force that can be applied to the cables given a rod with diameter 1.5 is 2013.15lb
The static equilibrium is given as:
F = P (Normal force)
Formula for moment at section
M = P(4 + 1.5/2)
= 4.75p
Solve for the cross sectional area
Area = [tex]\frac{\pi d^{2} }{4}[/tex]
d = 1.5
[tex]\frac{\pi *1.5^{2} }{4}[/tex]
= 1.767 inches²
Solve for inertia
[tex]\frac{\pi *0.75^4}{4}[/tex]
= 0.2485inches⁴
Solve for the tensile force from here
[tex]\frac{F}{A} +\frac{Mc}{I}[/tex]
30x10³ = [tex]\frac{P}{1.767} +\frac{4.75p*0.75}{0.2485} \\\\[/tex]
30000 = 14.902 p
divide through by 14.902
2013.15 = P
The largest tensile force that can be applied to the cables given a rod with diameter 1.5 is 2013.15lb
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The battery of an aircraft and even your car has the negative
as the ground. The question is why was the negative not the
positive chosen to be the ground?
What's the difference between a scale and a scale drawing?
scale is used to make a scale drawing. every scale drawing has it's sclae written for proper interpreatation
What is a scale?
A Scale is the ratio of a sketched model and the actual measuremnts while a scale drawing is a sketched model that was carefully made such that every measurement in the sketch could be represented to the site or actual mearuement through the scale with very little or no error
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To make a scale drawing, scale is used. For correct interpretation, every scale drawing has its own scale inscribed on it.
What exactly is a scale?A scale drawing is a sketched model that has been meticulously prepared so that every measurement in the sketch may be conveyed to the site or actual measurement through the scale with very little or no mistake.
A weighing apparatus or equipment with two pans of equal weight hung from its ends —usually used in the plural, either pan or tray of a balance scale.
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Joe maylan an employee of acme company has been sent to do some work in the highland company's main lobby. This job will take two days. Which type of pass should joe be given?
The type of Pass that Joe Maylan should be given is called; Temporary Pass
What is temporary pass?In factories or industries, there are different types of pass given to workers and visitors visit such places on a daily basis. In this case Joe maylan is going to do a job in the company for just 2 days and as such the type of pass he willl get will be a temporary pass.
It will be a temporary pass because it is a document pass issued for short-term use or due to an emergency.
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Explain the difference between a geostationary and a polar orbit, as it relates to satellites
A geostationary orbit is in same direction as the spinning of the earth while polar orbit is along the poles
What is an orbit as used for satellites?Orbit describes the pathway a satellite moves. the pathway is usually circular.
Polar orbit refers to orbits that traces along the poles that is North pole and South pole. owing to the spherical nature of the earth polar orbits are shorter. This allows for a shorter time to complete a revolution.
Geostationary orbit as against the polar orbit , geostationary orbits traces same path as the Earth's spinning. This path os longer and will require more time to complete. Satellites tracing this orbits are launched further away about 36000 km above the earths surface while satellites on polar orbits is shorter about 200 km - 2000 km
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Why is Tungsten (74) much stronger than Aluminium (13)
though both are metallic?
Answer:
Tungsten element has the second highest melting point. Pure tungsten can easily cut down with the help of hacksaw.
Answer: Because it does not undergo oxidation and it has a very high melting point when it glows in bulb it temperature goes upto 2500°C
Step-by-step Explanation:
The strength is mainly depends on the some of factors which are described below.
●molecular structure:- The molecular structure is responsible fir the intermolecular force of a metal or material which causes the increase and decrease of strngth of a metal. Tungsten molecular structure is much stringer then that of aluminium.
●Temperature:-The temlerature also plays a rule in the strenghtNess of a metal. Tge high temprature makes a metal soft.
●Composition :- The composition is mostly important for the strengthnesa of material. For ex the pure iron metal is much weeker the alotrophy of iron.
Omar owns a stall selling handmade cosmetics, and wants to launch an e-commerce site. He has lots of experience selling his products in person at markets, but is now hoping to reach more customers online.
Can you advise Omar on how to make both his online and offline business successful?
Answer:
He could put up advertisements all over the town and pay a few websites or search engines to have his company and ads be more common. He should also use some designs and make his company's sign very adequate.
the section of the area to be examined is shown circumscribed by broken lines with circles at
the connecting points.
This question is about Circle Geometry. it evaluates connected and broken lines with respect to circles.
What is Circle Geometry?This refers to the body of knowledge in mathematics that has to do with the various problems associated with the Circle.
In real-world scenarios, circle geometry is used in technologies involving:
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It was a mistake that i put in under 13 of age can you put it for 27
Answer:
ill try to help you :)
Explanation:
In approximately 50 words, describe one thing a professional in an increased demand green construction occupation could do to add to the function, sustainability, and energy efficiency of the construction of a shopping center.
answer:Numbers of green increased demand occupations are growing and include power system operators and dispatchers. There are many green enhanced skill occupations which are being changed; some examples include continuous mining machine operators, electrical engineers, geological sample test technicians, mechanical engineers, and power plant operators, who are all receiving new tasks related to renewable energy generation
The things that the professional in an increased demand green construction occupation can add in the construction of a shopping center include:
Radiant floors.Solar power.Great water recycling.What is a green buidling?It should be noted that a green building simply means a design, construction, or operation that eliminates the negative impact on the climate and natural environment.
In this case, in order to illustrate energy efficiency, it's important to use radiant floors, geothermal system, energy efficient window systems, etc.
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what is happening in the mechanical engineering field right now
Answer:
With the ongoing pandemic, businesses have shifted their operations to online platforms while people have been forced to resort to work-from-home lifestyles to prevent the further prevent the spread of the virus.
Correctly complete the statement below with the appropriate term.
As engineers sketch, they take periodic (_____) to verify that the design maintains the appropriate ratio for the given scale.
Engineers take periodic site measurements to verify the scale conveys true information
Site Measurements
measureants is the amount or extent of something ascertained through use of calibrated instrument called measuring instrument. When measurements are done on site it is called site measurements.
Engineers use the site measurements to scale their sketches hence to ensure the scale is always correct periodic measurements should be taken.
On-site measurements value and sketch measurement value gives the scale which is the ratio, should be maintained always
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Explain how the ideal vapour compression refrigerator cycle is an improvement upon the Carnot cycle. Use any two of the problems to explain.
During the design of spherical pressure vessel for space programs, a primary criterion is the mass of the vessel (which determines how much it costs to put it into the orbit). Given the stress in a thin walled spherical vessel is tensile and given by:
Tensile stress in a thin wall spherical shell is given by
σ = ( p r ) /2t
Tensile stressThis is the type of stress that involves pulling out. it is the opposite of compressive stress.
The tensile stress, σ at the circumference of the shell is the hoop stress. The value equals that of pressure acting on the area.
Therefore:
σ * 2πr * t = p * πr^2
where
2πr = circumference of a circle
πr^2 = area of a circle
p = internal pressure
t = thickness
σ * 2πr * t = p * πr^2
σ = ( p r ) /2t
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Explain what a structural engineer does?
Explanation:
Structural Engineers create drawings and specifications, perform calculations, review the work of other engineers, write reports and evaluations, and observe construction sites. A Professional Engineer's license is required in order to practice Structural Engineering.
When are we going to abandon internal combustion engines?
Answer:
2035
Explanation:
Most car and truck companies say that they will completely get rid of internal combustion engines by 2035.
A piece of copper steel (specific heat = 490 kg K) has a mass of 300 g. If is heated to
150°C, then plunged into 4.00 kg water (specific heat = 4180 kg at 20°C, what will
be the final temperature at equilibrium?
The Given Data were properly outline and the relation for the quantity of heated at equilibrium was used to compute the temperature as 18.84°C
Heat CapacityGiven Data
Mass of Copper m1 = 300g = 0.3kgSpecific heat of copper c1 = 490Kg KInitial Temperature of Copper T1= 150°CMass of water m2 = 4kgSpecific heat of water = 42180 Kg KInitial Temperature of water T1= 20°CAt equilibrium, the final temperature of the system T2 will be same for both copper and water
McΔT(copper) = McΔT(water)
0.3*490*(T2 - 150) = 4*4180*(T2-20)
147*(T2 - 150) =16720*(T2-20)
147T2 - 22050 = 16720T2 - 334400
collect like terms
147T2 -16720T2 = - 334400+22050
147T2 -16720T2 = - 334400+22050
-16573T2 = -312350
16573T2 = 312350
Divide both sides by 16573
T2 = 312350/16573
T2 = 18.84°C
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Many appliances come with___ratings, which mean that the
device or machine will run with fewer associated costs than previous
models.
What is the definition of gross axle weight rating?.
state 5 general rules for cleat wiring
A strain gauge is used to measure the strain on a vibrating beam which can vibrate up to a maximum frequency of 60 Hz. The strain gauge analog signal is converted in to a digital signal via an Analog to Digital Converter (ADC) in order to store the data on a computer hard drive. The engineer responsible for this measurement mistakenly selects a sampling frequency of 90 Hz for the ADC. (a) Determine the alias frequency due to the small sampling frequency. (b) Propose a sampling frequency that will not result into aliasing of the analog signal (make sure to provide your rationale for selecting this frequency)
The aliased frequency that is due to small sampling frequency is 675 Hz.
The proposed sampling frequency is 2f = 120
How to solve for the aliased frequencyThe signal frequency that is given in the question is 60Hz
The sampling frequency is 90Hz
a. Using Nyquist frequency,
fn = 0.5*90Hz = 45Hz
The aliased frequency = |n*fn - fs|
aliased frequency = |n*fn - fs|
We have n >= 1/Fs = 17ms
Then the aliased frequency is = 17 x 45 - 90
= 675 Hz
b) The Nyquist sampling theoremIn order to avoid aliasing the sampling frequency, this has to be at least two times the highest frequency.
Therefore Fs =
2xF = 120Hz
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Water is flowing steadily through a venturi that is oriented vertically. The venturi is attached to a mercury manometer that reads a 14. 3-inch deflection. 14. 3" z 30" 12" 6" a. ) 5 Points. In which direction is the water flowing? Justify your answer
Due to the fact that there is a 14.3inch deflection in the manometer, water is flowing towards the regions that have low pressure.
How does this water flow to low region areas?The fluid that is contained in the manometer is moving towards areas of low pressure. This means they are going to areas with high velocity.
The areas that have low cross sections would flow with a constant rate. This venturi would have low pressure because it has low cross sectional area.
The fluid in the device would then have to move from bottom to top towards the neck of the mercury.
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A square aluminum plate 5 mm thick and 150 mm on a side is heated while vertically suspended in quiescent air at 75°c. determine the average heat transfer coefficient for the plate when its temperature is 15°c by two methods: using results from the similarity solution to the boundary layer equations, and using results from an empirical correlation.
By using the boundary layer equation, the average heat transfer coefficient for the plate is equal to 4.87 W/m²k.
Given the following data:
Surface temperature = 15°C
Bulk temperature = 75°C
Side length of plate = 150 mm to m = 0.15 meter.
How to calculate the average heat transfer coefficient.Since we have a quiescent room air and a uniform pole surface temperature, the film temperature is given by:
[tex]T_f=\frac{T_{s} + T_{\infty} }{2} \\\\T_f=\frac{15 + 75 }{2} \\\\T_f = 45[/tex]
Film temperature = 45°C to K = 273 + 45 = 318 K.
For the coefficient of thermal expansion, we have:
[tex]\beta =\frac{1}{T_f} \\\\\beta =\frac{1}{318}[/tex]
From table A-9, the properties of air at a pressure of 1 atm and temperature of 45°C are:
Kinematic viscosity, v = [tex]1.750 \times 10^{-5}[/tex] m²/s.Thermal conductivity, k = 0.02699 W/mk.Thermal diffusivity, α = [tex]2.416 \times 10^{-5}[/tex] m²/s.Prandtl number, Pr = 0.7241.Next, we would solve for the Rayleigh number to enable us determine the heat transfer coefficient by using the boundary layer equations:
[tex]R_{aL}=\frac{g\beta \Delta T l^3}{v\alpha } \\\\R_{aL}=\frac{9.8 \;\times \;\frac{1}{318} \;\times \;(75-15) \;\times \;0.15^3 }{1.750 \times 10^{-5}\; \times \;2.416 \times 10^{-5} } \\\\R_{aL}=\frac{9.8\; \times 0.00315 \;\times \;60\; \times\; 0.003375 }{4.228 \times 10^{-10} }\\\\R_{aL}=1.48 \times 10^{7}[/tex]
Also take note, g(Pr) is given by this equation:
[tex]g(P_r)=\frac{0.75P_r}{[0.609 \;+\;1.221\sqrt{P_r}\; +\;1.238P_r]^\frac{1}{4} } \\\\g(P_r)=\frac{0.75(0.7241)}{[0.609 \;+\;1.221\sqrt{0.7241}\; +\;1.238(0.7241)]^\frac{1}{4} }\\\\g(P_r)=\frac{0.543075}{[0.609 \;+\;1.221\sqrt{0.7241}\; +\;1.238(0.7241)]^\frac{1}{4} }\\\\g(P_r)=\frac{0.543075}{[2.5444]^\frac{1}{4} }\\\\g(P_r)=\frac{0.543075}{1.2630 }[/tex]
g(Pr) = 0.430
For GrL, we have:
[tex]G_{rL}=\frac{R_{aL}}{P_r} \\\\G_{rL}=\frac{1.48 \times 10^7}{0.7241} \\\\G_{rL}=1.99 \times 10^7[/tex]
Since the Rayleigh number is less than 10⁹, the flow is laminar and the condition is given by:
[tex]N_{uL}=\frac{h_{L}L}{k} = \frac{4}{3} (\frac{G_{rL}}{4} )^\frac{1}{4} g(P_r)\\\\h_{L}=\frac{0.02699}{0.15} \times [\frac{4}{3} \times (\frac{1.99 \times 10^7}{4} )^\frac{1}{4} ]\times 0.430\\\\h_{L}= 0.1799 \times 62.9705 \times 0.430\\\\h_{L}=4.87\;W/m^2k[/tex]
Based on empirical correlation method, the average heat transfer coefficient for the plate is given by this equation:
[tex]N_{uL}=\frac{h_{L}L}{k} =0.68 + \frac{0.670 R_{aL}^\frac{1}{4}}{[1+(\frac{0.492}{P_r})^\frac{9}{16}]^\frac{4}{19} } \\\\h_{L}=\frac{0.02699}{0.15} \times ( 0.68 + \frac{0.670 (1.48 \times 10^7)^\frac{1}{4}}{[1+(\frac{0.492}{0.7241})^\frac{9}{16}]^\frac{4}{19} })\\\\h_{L}=4.87\;W/m^2k[/tex]
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Pouring molten aluminum into a mold and allowing it to cool forms:
A)
a stamped part.
B)
a cast part.
C)
an extruded part.
D)
a hydroformed part.
Hi :)
The answer is B. A cast part
How does a cast part form?
Molten material is then poured into a mould cavity that takes the form of the finished part. The molten material then cools, with heat generally until it solidifies into the desired shape.
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Q6. Ask for two numbers. If the first one is larger than the second, display the second number first and then the first number, otherwise show the first number first and then the second.
Answer:
Number1 = input("Choose a number: )
Number2 = input("Choose a second number: )
if number1 > number2:
print(number2\nnumber1)
else:
print(number1\nnumber2)
Explanation:
I'm assuming that you want it in python.
A glass of water with a mass of 0.45kg at 20∘C is to be cooled to 0∘C by dropping ice cubes at 0∘C into it. The latent heat of fusion of ice is 334kJ/kg, and the specific heat of water is 4.18kJ/kg⋅∘C. The amount of ice that needs to be added is.
By using the concept of heat transfer, we need to add 0.045kg or 45g of ice to the glass of water to cool it from 20∘C to 0∘C.
The heat lost by the water is equal to the heat gained by the ice cubes. We can use the following equation to calculate the heat transfer:
Q = m_w * c_w * ΔT + m_i * L_f
where Q is the heat transfer, m_w is the mass of water, c_w is the specific heat of water, ΔT is the temperature change (20-0 = 20∘C), m_i is the mass of ice, and L_f is the latent heat of fusion of ice.
We know the values of m_w (0.45kg), c_w (4.18kJ/kg⋅∘C), ΔT (20∘C), and L_f (334kJ/kg). We can rearrange the equation to solve for m_i:
m_i = (Q - m_w * c_w * ΔT) / L_f
Substituting the values, we get:
m_i = [(0.45kg) * (4.18kJ/kg⋅∘C) * (20∘C) - 0] / (334kJ/kg
m_i = 0.045kg
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Which of the following would not be a good reason to use a linear model?
Thank
The disadvantage of using a linear model is that; It is sensitive to outliers and prone to multicollinearity.
What is the Linear Regression Model?Linear regression is defined as a regression technique whereby the independent variable has a linear relationship with the dependent variable.
Now, there are some advantages of this model in statistics such as;
Linear regression performs exceptionally well for linearly separable data.It is easy to implement and interpret.It carries out extrapolation beyond a specific data set.However, there are some disadvantages such as;
It is very sensitive to outliers.
It is prone to having multicollinearity.
It assumes linearity between dependent and independent variables.
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In surveying , supposing we can not pull the tape because it is passing through a shallow river. What will i do to obtain an accurate distance?
Answer:
Hold the tape in place and go down to the end.
Explanation:
A traffic flow has density 61 veh/km when the speed is 59 veh/hr. If a flow has a jam density of 122 veh/km, what is the maximum flow in veh/hr (in whole number)? Use Greenshield Model.
Since this traffic flow has a jam density of 122 veh/km, the maximum flow is equal to 3,599 veh/hr.
Given the following data:
Density = 61 veh/km.Speed = 59 km/hr.Jam density = 122 veh/km.How to calculate the maximum flow.According to Greenshield Model, maximum flow is given by this formula:
[tex]q_{max}=\frac{V_f \times K_i}{4}[/tex]
Where:
[tex]V_f[/tex] is the free flow speed.[tex]K_i[/tex] is the Jam density.In order to calculate the free flow speed, we would use this formula:
[tex]V_f =2 V\\\\V_f =2\times 59\\\\V_f=118\;km/hr[/tex]
Substituting the parameters into the model, we have:
[tex]q_{max}=\frac{118 \times 122}{4}\\\\q_{max}=\frac{14396}{4}[/tex]
Max flow = 3,599 veh/hr.
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Select true/false for each of the following statements regarding copper & copper alloys:: (a) copper has a higher elastic modulus than aluminum. (b) the density of copper is closer to that of aluminum than it is to iron. (c) bronze is an alloy of copper and zinc. (d) copper and its alloys form a green tarnish over time, consisting of sulfides and carbonates. (e) copper is relatively resistant to corrosion by neutral and even mildly basic water, making it useful for freshwater plumbing applications.
A: Copper has a higher elastic modulus than aluminum.
TrueB: The density of copper is closer to that of aluminum than it is to iron.
FalseC: Bronze is an alloy of copper and zinc.
FalseD: Copper and its alloys form a green tarnish over time, consisting of sulfides and carbonates.
TrueE: Copper is relatively resistant to corrosion by neutral and even mildly basic water, making it useful for freshwater plumbing applications.
TrueA transistor with a height of 0.4 cm and a diameter of 0.6 cm is mounted on a circuit board. The transistor is cooled by air flowing over it with an average heat transfer coefficient of 30 W/m2°C air = 30°C If the air temperature is 55°C and the transistor case temperature is not to exceed 70°C, determine the amount of power this transistor can dissipate safely. Disregard any heat transfer from the transistor base.
The minimum safety power that is safely dissipated using a transistor of height 0.4cm and diameter 0.06cm is 0.04665
Calculation for the exposed area[tex]\pi DL +\frac{\pi }{4} D^2\\\\Area = 3.14 * 0.6*0.4+\frac{3.14}{4} *0.6^2[/tex]
D = diameter = 0.6cm
Length = height = 0.4cm
Area = 1.0367cm²
minimum safety heat that is dissipatedhA (Ts - Tair)
30 * 1.0367 x 10⁻⁴(70-55)
= 0.04665
The minimum safety power that is safely dissipated is 0.04665W
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