the square below has anarea of 49ft2 what is the perimeter of the square

Answers

Answer 1

Answer:

28ft

Explanation:

if it's a square then each side is equal

the square root of 49 is 7

each side is 7 ft

7 ft times 4 sides is 28ft

Answer 2
the answer is 98 because you do 49ft2 divided by two and then that would be the answer to one side so to find the answer you multiply that by 4

Related Questions

what is safe storage of produced materials exlain long ​

Answers

Answer:

Stacking storage sacks/ bags by interlocking, and placing heavier object on lower shelves.

Explanation:

Not sure what you meant exactly, but this is my best guess.

How much 1.75 M H3PO4, in mL, would you need to add to 50.00 mL of 3.50 M Ca(OH)2 in order to neutralize the solution

Answers

The volume of the 1.75 M H₃PO₄ solution required to neutralize 50 ml of 3.5 M Ca(OH)₂ solution is 66.67 mL

Balanced equation

2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O

From the balanced equation above,

The mole ratio of the acid, H₃PO₄ (nA) = 2The mole ratio of the base, Ca(OH)₂ (nB) = 3

How to determine the volume of H₃PO₄ Molarity of acid, H₃PO₄ (Ma) = 1.75 MVolume of base, Ca(OH)₂ (Vb) = 50 mLMolarity of base, Ca(OH)₂ (Mb) = 3.5 MVolume of acid, H₃PO₄ (Va) =?

MaVa / MbVb = nA / nB

(1.75 × Va) / (3.5 × 50) = 2/3

(1.75 × Va) / 175= 2/3

Cross multiply

1.75 × 3 × Va  = 175 × 2

5.25 × Va = 350

Divide both side by 5.25

Va = 350 / 5.25

Va = 66.67 mL

Thus, the volume of the H₃PO₄ solution needed is 66.67 mL

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Which of the compounds below will dissociate in water? Check all that apply.
Ba(NO3)2
CaSO4
CO2
H2CO3
Mg3(PO4)2
those numbers are subscripts

Answers

An ionic compound does dissociate to a large extent in water. The compound that will completely dissociate in water here is Ba(NO3)2.

What is a soluble compound?

A soluble compound is a compound that can dissociate to a large extent in water. Not all compounds are soluble in water. Only ionic compounds are soluble in water.

The compound that  would dissolve in water among the list of compounds here is Ba(NO3)2.

Learn more about ionic compounds: https://brainly.com/question/9167977?

Answer:

A) Ba(NO3)2

B) CaSO4

C) CO2

D) H2CO3

E) Mg3(PO4)2

Explanation:

Wish I could give a good explanation, but I am still learning myself. Try searching up a video explaining this concept!

What do ferns and gymnosperms have in common?They are all vascular plants.
Reproduction depends on birds, bees, and other animals.
They all produce seeds.
They depend on water for fertilization.

Answers

Answer:

They are all vascular plants.

Explanation:

Vascular plants, also known as tracheophytes, are highly advanced plant creatures with leaves, stems, and roots, as well as a vascular system made up of conducting vessels. Ferns are herbaceous, pteridophytic vascular plants that do not produce flowers or seeds. Gymnosperms are vascular plants that produce seeds but do not produce blooms. Because the seeds aren't covered or protected by an ovary, they can be seen on the plant's leaves or other components. Angiosperms are flowering plants containing seeds that develop inside the ovary, which develops and produces fruit.

Answer:

They all produce seeds

Explanation:

In Fig C, which pair of electrons is the lone pair?
H:P:H
Fig C
H
O Top
O Left
Bottom
O Right

Answers

Answer:

bottom right top left fig

Kinetic friction is the frictional force needed to start an object at rest into
motion.
O A. True
O B. False

Answers

Answer:false you are welcome

Explanation:

Answer: False I hope this helpful please mark me brainlist

Explanation:

Kinetic friction is the friction acting upon a moving object. It would be the frictional force against you if you pulled a box across a table.Static friction is the frictional force needed to overcome to get an object at rest into motion.

Explain how oxygen and carbon dioxide move with breathing.

Answers

Answer/Explanation:

With oxygen, it is what you breathe in so obviously, it is going to move around into your body. But with carbon dioxide, it is what you breathe out. When you breathe in, your body takes in the oxygen and the releases the carbon dioxide. Carbon dioxide is what plants actually consume, while they release oxygen.

I hope this helps!

-No one

determine the degree of ionization at pH 2.0​

Answers

Answer:

answer in the picture above

Looking at the figure, the overall (SiO4) molecule, which forms the common mineral quartz, has a tetrahedral shape. It is probably a:
non-polar molecule
polar molecule

Answers

non-polar molecule because the chemical formula is in a tetrahedral form(O4) and the (Si) is in the centre. I hope this will help you

Consider the structure shown.

A central S atom is bonded to three O atoms, two through a single line and one through two lines. There are six dots around two of the O atoms and 4 dots around the third O atom.

Determine the number of shared and unshared electrons in the structure.

shared (bonding) electrons:
unshared (lone, nonbonding) electrons:
Determine the number of shared and unshared pairs of electrons in the structure.
shared (bonding) pairs of electrons:
unshared (lone, nonbonding) pairs of electrons:
Determine the total number of valence electrons in the structure.
total valence electrons:

Answers

There are eight lone pairs and four bond pairs of electrons in the SO3 molecule. The valence electrons are found on the valence shell of the molecule.

Lewis structure of SO3

The molecule SO3 is represented by the Lewis structure shown in the image attached to this answer. The central atom in the molecule is sulfur.

There are sixteen non bonding electrons in the molecule and eight bonding electrons in the molecule Hence, we have eight lone pairs and four bond pairs of electrons in the molecule as shown in the Lewis structure.

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(a)Determine the number of KNO3 molecules in 0.750 mol KNO3.
(b) What is the mass (in milligrams) of 2.39 x 1020 molecules of Ag2SO4.
(c) Estimate the number of NaHCO2 molecules in 3.429 g of NaHCO2.

Answers

A. The number of molecules in 0.750 mole of KNO₃ is 4.515×10²³ molecules

B. The mass (in milligrams) of 2.39×10²⁰ molecules of Ag₂SO₄ is 124 mg

C. The number of molecules in 3.429 g of NaHCO₂ is 3.04×10²² molecules

Avogadro's hypothesis

1 mole of substance = 6.02×10²³ molecules

A. How to determine the number of molecules

1 mole of KNO₃ = 6.02×10²³ molecules

Therefore,

0.750 mole of KNO₃ = 0.75 × 6.02×10²³

0.750 mole of KNO₃ = 4.515×10²³ molecules

B. How to determine the mass of Ag₂SO₄

6.02×10²³ molecules = 312 g of Ag₂SO₄

Therefore,

2.39×10²⁰ molecules = (2.39×10²⁰ × 312) / 6.02×10²³

2.39×10²⁰ molecules = 0.124 g

Multiply by 1000 to express in mg

2.39×10²⁰ molecules = 0.124 g × 1000

2.39×10²⁰ molecules = 124 mg of Ag₂SO₄

C. How to determine the number of molecules

68 g of NaHCO₂ = 6.02×10²³ molecules

Therefore,

3.429 g of NaHCO₂ = (3.429 × 6.02×10²³) / 68

3.429 g of NaHCO₂ = 3.04×10²² molecules

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At 4.5 atm of pressure, the solubility of a gas is 9.5 g/L.
How much gas, in grams, will dissolve in 1 L if the pres.
sure is reduced by 3.5 atm?

Answers

For a gas at 4.5 atm of pressure, the solubility of a gas is 9.5 g/L.

How much gas, in grams, is mathematically given as

s2=8.3782grams

What is the amount of gas in grams?

Generally, the equation for the   is mathematically given as

Si /S2 √P1/√P2

Therefore

[tex]s2=9.5*\sqrt{3.5}/\sqrt{4.5}[/tex]

s2=8.3782g

In conclusion. The solubility is

s2=8.3782g

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What are the processes that lead to the formation of sedimentary rocks? I WILL GIVE BRAINLIEST

A.weathering and erosion followed by dispersion.
B.volcanic eruptions followed by dispersion,
C. volcanic eruptions followed by compaction
D.weathering and erosion followed by compaction

Answers

Answer:

erosion, weathering, dissolution, precipitation, and lithification So,D.weathering and erosion followed by compaction

Explanation:

mark me brainliest!!

When 20.4g of sodium metal are mixed with chlorine gas, are 52.0 g of sodium chloride
produced? Explain (use calculations to prove your answer.
.ves or no
-with amounts shown)

Answers

Answer: True

Explanation:

[tex]\mathrm{The\ balanced \ chemical \ equation\ is\ :}\\$2 \mathrm{Na}{(s)}+\mathrm{Cl}_{2}(g) \rightarrow 2 \mathrm{NaCl}(s)[/tex]

For Na

[tex]\\$Given mass $=20.4 \mathrm{~g}$ \ \ Molecular mass $=23 \mathrm{~g}\ \ $Number of moles $=\frac{\text { Given mass }}{\text { Molecular mass }}$$$\begin{aligned}&=\frac{20.4}{23} \\&=0.887 \text { moles }\end{aligned}$$Stoichiometric ratio of $\mathrm{Na}$ is same as that of $\mathrm{NaCl}$ i.e., $1: 1$.$\therefore$ Moles of $\mathrm{NaCl}=0.887$ motes[/tex]

For NaCl

[tex]$$\\\begin{aligned}\text { Molecular mass } &=23+35.5 \\&=58.5 \mathrm{~g}\end{aligned}$$[/tex]

[tex]\begin{aligned}\\& $\therefore$ Mass of $\mathrm{NaCl}$ produced will be=\text { No.of moles } \times \text { Molecular mass } \\&=0.887 \times 58.5 \\&=51.9 \\&\simeq 52 \mathrm{~g} \quad\end{aligned}$$[/tex]

Therefore, it is true that when 20.4g of sodium metal are mixed with chlorine gas, 52.0 g of sodium chloride is produced

Explanation:

The answer: True

I explained the answer to your question in the submitted photo

When Thomas Edison first sold electricity, he used zinc coulometers to measure charge consumption. (In a coulometer the cathode is weighed before a current is passed through it, and then again after the passage of current. The weight increase is proportional to the amount of current that flows through the cathode.) If the zinc plate in one of Edison's coulometers increased in mass by 7.85 g, how much charge had passed through it

Answers

When the zinc plate in one of Edison's coulometers increased in mass by 7.85 g, the amount of charge that had passed through it is 23,173 C.

Ionization of zinc

The zinc metal will ionize as shown below;

Zn²₊ + 2e⁻ → Zn

The molar mass of zinc metal is given as 65.38 g/mol

Amount of charge passed through 65.38 g/mol

Amount of charge that will deposite the given mass of zinc is calculated as follows;

e⁻ = 96500 C

2e⁻ = 2 x 96500 C = 193,000 C

Amount of charge passed through 7.85 g

65.38 g -------> 193,000 C

7.85 g -----------> ?

= (7.85 x 193,000)/(65.38)

= 23,173 C

Thus, when the zinc plate in one of Edison's coulometers increased in mass by 7.85 g, the amount of charge that had passed through it is 23,173 C.

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• How do the physical and chemical properties of each packaging type help create new and better product?

Answers

Answer:

chemical composition and physical properties of packaging materials determine their ability to fulfill the various functions expected from the package. 

Suppose that a car's starter motor draws 221 A of current for 6.20 s to start the car. What mass of Pb is oxidized in the lead–acid battery to supply this much electricity?

1.47 grams
Actually, I figured it out., here is the answer in case anyone is wondering:
It has two electrons in the process and Q is 1370.2 (Q= I*T= 221*6.2=1370.2) this gets to 1370.2/192736 (the number on the denominator is due to that fact that there are two electrons involved) That equals 0.007 Mols, and then using the grams per mol from the periodic table for lead, we get that value is equal to 1.47 grams.

Answers

The lead acid battery produces energy by oxidation of lead. The amount of lead oxidized in this case is 1.47 g.

What is lead acid battery?

The lead acid battery is the common accumulator that we have in use. It is made up of a cell that contains lead electrodes in an acid.

The oxidation of lead occurs according to thr equation;

Pb(s) ----> Pb^2+(aq) + 2e

If 207 g of Pb is oxidized by 2(96500)C

x g of lead is oxidized by (221 * 6.20) C

x = 207 g * (221 * 6.20) C/2(96500)C

x = 1.47 g

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What does absolute zero physically mean at the particle level?
ASAP!

Answers

Answer:

Absolute zero is the lowest limit of the thermodynamic temperature scale, a state at which the enthalpy and entropy of a cooled ideal gas reach their minimum value, taken as zero kelvin.

If 22.00 mL of 2.00 M potassium iodide is needed to reach the equivalence point with 18.00 mL of lead (II) nitrate, determine the molarity of the lead (II) nitrate solution. Note: First write the balance equation between potassium iodide and lead (II) nitrate.

Answers

The molarity of the lead(II) nitrate solution if 22.00 mL of 2.00 M potassium iodide is needed to reach the equivalence point with 18.00 mL of lead (II) nitrate is 1.2M.

How to calculate molarity?

The molarity of a solution can be calculated using the following formula:

CaVa/CbVb = na/nb

Where;

Ca = concentration of acidCb = concentration of baseVa = volume of acidVb = volume of basena = number of moles of acidnb = number of moles of base

The balanced equation of the reaction is as follows:

Pb(NO3)2 (aq) + 2KI (aq) → 2KNO3 (aq) + PbI2 (s)

22 × 2/18 × Cb = 2/1

44/18Cb = 2

Cb = 44 ÷ 36

Cb = 1.2M

Therefore, the molarity of the lead(II) nitrate solution if 22.00 mL of 2.00 M potassium iodide is needed to reach the equivalence point with 18.00 mL of lead (II) nitrate is 1.2M.

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What volume of .15M NaOH could be produced with only 5 grams of NaOH and water?

Answers

The volume of 0.15M NaOH that could be produced with only 5 grams of NaOH and water is 0.83L.

How to calculate volume?

The volume of a substance can be calculated using the following expression:

Molarity = number of moles ÷ volume

The number of moles of NaOH can be calculated by dividing the mass of NaOH by its molar mass.

Molar mass of NaOH = 40g/mol

n = 5/40

n = 0.125moles

Volume of NaOH = 0.125mol ÷ 0.15M

Volume = 0.83L

Therefore, the volume of 0.15M NaOH that could be produced with only 5 grams of NaOH and water is 0.83L.

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NH4NO3+Zn(OH)2

Balance the equation

Answers

Answer:

Balanced equation: Zn (NO 3) 2 + 2 NH 4 OH = 2 NH 4 NO 3 + Zn (OH) 2 Reaction type: double replacement

Explanation:

Amory turns the light on in her house. Looking at the lights, she begins to wonder how the charges are moving through the bulb. Which statement best describes how the charges move through the bulb ?

Answers

The statement 'when charges pass through the bulb, light is produced' best describes how the charges move through the bulb.

What is an electrical charge?

An electrical charge is a type of positive or negative charge of the particles that move in a conductor.

At the atomic level, protons are positively charged particles, electrons are negative, and neutrons do not have a charge.

The electrical charges depend on the charge's initial time, the final time, and the net outward current.

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Use the bond energy to calculate an approximate value of ΔH for the following reaction. Which is the more stable form of FNO2?

Answers

The Lewis structures in which there are no formal charges is the most stable. Hence, structure (b) is the  more stable form of FNO2.

Lewis structure

The question is incomplete but I will try to answer you as much as I can. Now the equation is missing hence we can't numerically caculate the enthalpy chnage of the reaction from bond energies. However, we can do this using the formula; Σbond energy of reactants - bond energy of products.

Concerning the Lewis structures of FNO2, the most stable structure is structure (b) as shown in the image attached where the atoms have no formal charges.

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Calculate the volume in mL of 0.279 M Ca(OH)2 needed to neutralize 24.5 mL of 0.390 M H3PO4 in a titration.



Note: the answer should have 3 significant digits. Do not include the unit mL in the answer.

Answers

The volume of the 0.279 M Ca(OH)₂ solution required to neutralize 24.5 mL of 0.390 M H₃PO₄ is 51.4 mL

Balanced equation

2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O

From the balanced equation above,

The mole ratio of the acid, H₃PO₄ (nA) = 2The mole ratio of the base, Ca(OH)₂ (nB) = 3

How to determine the volume of Ca(OH)₂ Molarity of acid, H₃PO₄ (Ma) = 0.390 MVolume of acid, H₃PO₄ (Va) = 24.5 mLMolarity of base, Ca(OH)₂ (Mb) = 0.279 MVolume of base, Ca(OH)₂ (Vb) =?

MaVa / MbVb = nA / nB

(0.39 × 24.5) / (0.279 × Vb) = 2/3

9.555 / (0.279 × Vb) = 2/3

Cross multiply

2 × 0.279 × Vb = 9.555 × 3

0.558 × Vb = 28.665

Divide both side by 0.558

Vb = 28.665 / 0.558

Vb = 51.4 mL

Thus, the volume of the Ca(OH)₂ solution needed is 51.4 mL

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Nitrogen (iv) oxide is passed through the combustion tube before copper is heated.Give a reason for this?​

Answers

to generate steam which act on copper

According to the given equation, how many moles of O, are required to react with 4.71 moles of C4H10?
2C4H10 + 1302 —8CO2 + 10 H

Answers

According to the given equation, 2C4H10 + 1302 — 8CO2 + 10H, 2 moles of O are required to react with 4.71 moles of C4H10.

How to calculate number of moles?

The number of moles of a compound can be calculated stoichiometrically as follows:

The balanced chemical equation is given as follows:

2C4H10 + 1302 — 8CO2 + 10H

Based on the above equation, 2 moles of C4H10 reacts with 13 moles of O

Therefore; 4.71 moles of C4H10 will react with 4.71 × 6.5 = 30.62 moles of O

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Answer: 30.6

Explanation:

In picture 4, the net force on the car is mostly the result of? A. Gravity. B. Constant velocity. C. Wind. D. Friction.

Answers

Answer:

D beacuse I think that's Force

What is the total number of atoms contained in 3.63 moles of nickel?

Answers

Answer:

Explanation:

1 mole of nickel contains 6.02 * 10^23 atoms

3.63 mols of nickel contain x atoms.

What you have is a proportion. A proportion consists of 2 ratios or 4 parts.

Of the 4 parts, you know three of them. The problem is to solve for the 4th.

1/3.63 = 6.02*10^23 / x               Cross multiply

x = 3.63 * 6.02* 10^23                Combine the right.

Answer: x = 2.19*10^24 atoms

*PLEASE HELP**
Which of the following aqueous solutions would have the lowest freezing point?
0.1 M sodium chloride
0.1 M calcium phosphate
0.2 M potassium sulfide
0.3 M aluminum nitrate
0.3 M barium chloride

Answers

Answer:

0.1 M Calcium phosphate

Explanation:

Which is also

0.1mCal2

Amphetamine (C9H13N) is a weak base with a pKb of 4.2.

Calculate the pH of a solution containing an amphetamine concentration of 215 mg/L .
Express your answer to two decimal places.

Answers

Weak base: [OH⁻] = √Kb.C

pKb = 4.2

[tex]\tt Kb=10^{-4.2}[/tex]

c = concentration

MM Amphetamine (C9H13N) = 135.21 g/mol

c = 215 mg/L = (0.215 g : 135,21 g/mol) / L = 0.00159 mol/L = 1.59  x 10⁻³ mol/L

[tex]\tt [OH^-]=\sqrt{10^{-4.2}\times 1.59\times 10^{-3}}=3.17\times 10^{-4}[/tex]

pOH = 4 - log 3.17

pH = 14 - (4 - log 3.17)

pH = 10 + log 3.17 = 10.50

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