The speed of sound in miles per hour is 767.33 miles/h when the speed of sound in air at room temperature is approximately 343 m/s.
What do you mean by speed of sound?The distance a sound wave travels through an elastic material in one unit of time is measured as its speed of sound. At 20 °C, the speed of sound in air is approximately 343 m/s, or 2.91 or 4.69 seconds for a mile.
The properties of the medium itself determine the speed of a sound wave because sound needs a medium to travel through (such as density, stiffness, and temperature). For every degree, the velocity of sound drops by roughly 6 meters per second. Compression waves, which at a small scale rely on molecules transmitting energy one to another, are used to convey sound through the air.
We are given that 1 mi = 1609 m.
Also we know that 1 hour = 3600 s
Therefore,
343m/s*3000s/h*(1/1609mi/h)=767.433mi/h
Thus, the speed of sound in miles per hour is 767.33 miles/h.
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if an astronaut can throw a certain wrench 14.0 m vertically upward on earth, how high could he throw it on our moon if he gives it the same starting speed in both places?
The formula that we will apply to get to the answer would be:
2as = v² - u²
Using this we will get the answer as 82.35425 m.
Formulation and calculationHere,
U= initial velocity
V= final velocity
S= displacement of the body
A= acceleration of the body/ acceleration due to gravity (as per the question)
Something that has not been mentioned here but is present in the original question is that the acceleration due to gravity has been given as 0.170g.
While throwing the wrench on earth,
v² - u² = 2as
⇒[tex]u = \sqrt{v^2 - 2as}[/tex]
⇒ u = [tex]\sqrt{0-2 * -9.81 * 14}[/tex]
⇒ u= 16.57347 m/s
Since the astronaut gives the same starting speed in both the places so the u on moon would be 16.57347 m/s
While throwing the wrench on moon,
v² - u² = 2as
s = [tex]\frac{v^2 - u^2}{2a}[/tex]
⇒ s = [tex]\frac{0^2 - 16.57347^2}{2 * (-9.81) * 0.17}[/tex]
⇒s = 82.35425 m
so, on moon, the wrench could be thrown a distance of 82.35425 m
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. Electromagnetic induction is used by electric transformers to modify the voltage of current flow. Transformers may change the voltage in two different ways. What are the two ways?
Transformers may change the voltage in two different ways which are
Step up; Using step-up transformersStep down; Using step-down transformersThis is further explained below.
What is electromagnetic induction.?Generally, Electric transformers are devices that can change the direction and speed of the flow of current in an electrical circuit. They do this by adjusting the voltage of the existing flow of current through the use of electromagnetic induction.
In conclusion, There are two distinct methods by which transformers may alter the voltage, and they are
Step up; Using step-up transformersStep down; make use of transformers that scale down the voltageThe step-up transformer is usually used for the transmitting of electric charge through a lengthy distance where power drop might be experienced, while the step-down is used to moderate said transmitted charge to a consumer.
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how research is important on gathering necessary information
Thank you !
A sine wave has a rms value of 208 v. what is the peak value? group of answer choices
A sine wave has a rms value of 208 v, the peak value is 294.15v.
What is rms?The RMS value of a set of values (or a continuous-time waveform) is the square root of the arithmetic mean of the squares of the values, or square of the function that defines the continuous waveform. In physics, RMS current value can also be defined as the "value of the direct current that dissipates same power in a resistor".
Physical scientists often use the term root mean square as a synonym for standard deviation when it can be assumed input signal has zero mean, that is, referring to the square root of mean squared deviation of a signal from a given baseline or fit. This is useful for the electrical engineers in calculating "AC only" RMS of a signal. Standard deviation being the RMS of a signal's variation about the mean, rather than about 0, DC component is removed (that is, RMS(signal) = std e v (signal) if the mean signal is 0).
Mean power, or root mean square (RMS) power handling, refers to how much continuous power speaker can handle. The peak power handling value refers to the maximum power level that speaker is capable of utilizing in short bursts.
Therefore,
Peak value= rms[tex]\sqrt{2}[/tex]
=294.15v
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How many protons will there be if the atom has 3 electrons and a mass of 7 amu
Answer:
[tex]{ \tt{mass \: number = protons + neutrons}} \\ { \tt{7 = p + 3}} \\ { \tt{p = 4}}[/tex]
Olivia was riding her bike at a speed of 4m/s when she began rolling down a hill. The hill caused her to accelerate at a rate of 2m/s 2 until she reached the end of the hill 45m later. How fast was she going when she made it to the bottom of the hill?
The speed of Olivia when she made it to the bottom of the hill is 14m/s.
Kinematics is the study of mechanical points, bodies, and systems in motion without taking into account the forces acting on them or the corresponding physical qualities.
Kinematics equations of motion define the fundamentals of an object's motion, such as its position, velocity, or acceleration over time. These three equations of motion control how an item moves in one, two, and three dimensions.
Kinetics considers physical forces as well as material characteristics such as mass stiffness and tensile or compressive strength. These characteristics can be used to take a theoretical model from kinematics and use physics and thermodynamics to determine how to construct a workable, dependable, and functional real-world system.
Given,
Initial velocity, u = 4m/s
Acceleration, a = 2m/s-2
Displacement, s= 45m
we know that,
[tex]v^{2}= u^{2} + 2as[/tex], where v= final velocity
substituting the value in the above equation, we got
[tex]v^{2}[/tex] = [tex]4^{2} + 2(2)(45)[/tex]
v = [tex]\sqrt{196}[/tex]
v = 14 m/s
Thus, the speed of Olivia going down the hill is 14m/s.
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a block of unknown material is submerged in water. light in the water is incident on the block at an angle of 31°. the angle of refraction in the block is 27°. what is the index of refraction of the unknown material?: * a. 0.67 b. 1.2 c. 1.3 d. 1.5
The unknown material is glass because the refractive index is found out to be 1.5
Calculation and step-by step process[tex]u_{water\\}[/tex]= 1.33
[tex]u_{x}[/tex]=?
[tex]u_{1}[/tex]sini=[tex]u_{2}[/tex]sin27°
[tex]u_{2}[/tex] = 1.33 x [tex]\frac{sin31}{sin27}[/tex]
= 1.33 x (0.51/0.45)
= 1.50
so, deducing from it, we have refractive index = 1.50
Hence the unknown material is glass.
What is index of refraction?
The refractive index (or refraction index) of an optical media in optics is a dimensionless quantity that indicates the capacity of that medium to bend light. The refractive index controls how much light is refracted or twisted when it enters a substance.
The angle of incidence and angle of refraction of a ray as it crosses the interface between two media with refractive indices of n1 and n2 are, respectively, n1 sin 1 and n2 sin 2, which describes this.
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A motorcycle starts from rest and accelerates to a speed of 20 m/s in a time of 8s. What is the motorcycle’s average acceleration?
Answer: Acceleration=Change in speed/time
=(20–8)/10
=1.2m/s²
We can find the distance travelled by using the kinematic equation
S=ut+½at²
S=8*10+½*1.2*100
S=80+0.6*100
S=80+60
S=140m
Explanation: hope this helps and good lucky!!
a mass m is moving with a constant velocity along a line parallel to the x-axis, away from the origin. its angular momentum with respect to the origin:
The Angular momentum of mass m moving with a constant velocity about origin is constant.
Explanation and conceptL= momentum × perpendicular distance of line of action of the momentum from origin.
L=mv×y
Here it is seen that mvy is a constant, therefore the angular momentum is constant.
Concept of angular momentumThe rotational equivalent of linear momentum in physics is called angular momentum, also known as moment of momentum or rotational momentum.
Because it is a conserved quantity, while calculating the total angular momentum of a closed system, it stays constant—it is significant in physics.
The direction and the amplitude of angular momentum are all conserved. The functional characteristics of bicycles and motorbikes, frisbees, rifled bullets, and gyroscopes are due to the conservation of angular momentum.
The conservation of angular momentum also explains why neutron stars rotate rapidly and hurricanes, build spiral structures. In general, conservation restricts a system’s potential motion but does not completely define it.
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What causes cosmic microwave background energy
Answer: The Big Bang!
An astronaut who weighs 700 n on earth is in empty space, very far from any other objects. approximately what is the mass of the astronaut?
the mass of the astronaut will be 70KG, the mass stays the same everywhere.
What is space?The infinite three-dimensional expanse of space is where things and events have relative positions and directions. While modern physicists typically consider it to be a portion of an unbounded four-dimensional continuum known as spacetime, physical space is frequently conceptualized in classical physics as having three linear dimensions. It is believed that grasping the idea of space is essential to comprehending the physical cosmos. Philosophers dispute on whether it is a thing in and of itself, a connection between entities, or a component of a conceptual framework. Mathematicians started looking at non-Euclidean geometries in the 19th and 20th centuries, when space is thought of as curved rather than flat. Space around gravitational fields deviates from Euclidean space, according to Albert Einstein's theory of general relativity.
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A ball is thrown directly downward with an initial speed of 8.55 m/s, from a height of 30.4 m. after what time interval does it strike the ground?
The ball will reach the ground after 1.8 seconds.
We have a ball thrown directly downward.
We have to determine after what time interval does it strike the ground,
According to the question -
u = 8.55 m/s
S = 30.4 m
a = 9.8 m/[tex]s^{2}[/tex]
Using the Second Equation of Motion -
x = ut + [tex]\frac{1}{2} at^{2}[/tex]
Substituting the values -
30.4 = 8.55t + 4.9[tex]t^{2}[/tex]
4.9[tex]t^{2}[/tex] + 8.55t - 30.4 = 0
Solve this quadratic equation, you will get -
t = 1.8 seconds.
Hence, the ball will reach the ground after 1.8 seconds.
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What is a chemical change?
A. The appearance of an object changes, but its makeup remains the same.
B. One kind of matter changes into a different kind of matter with different properties. C. the process by which particles leave a liquid and become a gas.
Answer:
B. one kind of matter changes into a different kind of matter with different properties
When a gas undergoes a quasi-static isobaric change in volume from 10.0 to 2.0 l, 15 j of work from an external source are required. what is the pressure of the gas?
When a gas undergoes a quasi-static isobaric change in volume from 10.0 to 2.0 l, 15 j of work from an external source are required then the pressure of the gas is
Work done is given as
W=PdV
15 = P ×( 20-10)
P = 1.5 bar
Define pressure.The force delivered perpendicularly to an object's surface per unit area across which that force is dispersed is known as pressure (symbol: p or P). The pressure relative to the surrounding air is known as gauge pressure, also written gage pressure[a].
Pressure is expressed using a variety of units. Some of these result from dividing a unit of force by a unit of area; the pound-force per square inch (psi), which is equivalent to one newton per square meter (N/m2) in the SI, is the standard unit of pressure in the imperial and U.S.
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Find a vector function that represents the curve of intersection of the paraboloid z=4x2 4y2 and the cylinder y=5x2. use the variable t for the parameter.
r(t)=ti+5t²j+(4t²+50t⁴)k, For t∈ (-∞, ∞)
First plug the equation of y into the equation of z, so that we get their intersection:
We plug
y=5x²
Into:
z=4x²+4y²
So, we get:
z=4x²+2(5x²)²
z=4x²+2(25x⁴)
z=4x²+50x⁴
Then we set
x=t
And plug that in the equation [tex]y=5x^{2}[/tex] and z.
So that we get:
[tex]y=[/tex]5t², [tex]z=[/tex]4t²+50t⁴
Hence, the vector function r(t) that represents the curve of intersection is:
r(t)=ti+5t²j+(4t²+50t⁴)k, For t∈ (-∞, ∞)
A curve of intersection is made up of the common points of two transversally intersecting surfaces, which means that the surface normals are not parallel at any common point. This restriction applies only when the surfaces are touching or share surface sections.
The intersection of two non-parallel planes in Euclidean 3-space is a line in the simplest situation.
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If she drove back home using the same path she took out to the university and arrives 7.7 h after she first left home, what was her average speed for the entire trip, in kilometers per hour?
The average speed = (2 × the length of the path to the university in km) / (7.7 h)
The exact length of the path to the university is not given in the question but it is not unanswerable, therefore, consider that distance to be L measured in kilometres.If the distance is given in meters you need to convert it to kilometres as the question asks in that unit.The definition of the average speed is the key to the answer to this question which is given by
average speed = total distance covered [tex]\div[/tex] total time elapsed
So, the total distance covered is the addition of the distance of the trip to the university from home and the distance covered the way back home which is twice the distance to the university from home.And the total time taken to cover that distance is measured as 7.7 h and it can be thought of as follows as well.time to go - time to come = total time taken = 7.7 h
Therefore, simple substitution to the above average speed formula yields the required answer as follows,[tex]\begin{aligned}\\ \text{average speed} & =\small \frac{2\times L (km)}{7.7 \, h}\\\\&=\small \frac{2L}{7.7} \,km/h\\\end{aligned}[/tex]
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Did keeping the flies in constant dark conditions abolish the light-emission oscillations?
Yes, the statement is correct that keeping the flies in constant dark conditions abolish the light-emission oscillations
What is light-emission oscillations?The electromagnetic radiation spectrum produced when an electron changes from a high energy state to a lower energy state is known as the emission spectrum of a chemical element or chemical compound. The energy difference between the two states is equal to the photon energy of the emitted photon. Each atom contains a large number of potential electron transitions, and each transition has a distinct energy difference. An emission spectrum is made up of a variety of transitions that result in various radiated wavelengths. The emission spectra of each element is distinct. Therefore, components in materials with an unknown composition can be identified via spectroscopy. Similar to this, chemical examination of substances may make use of the emission spectra of molecules.
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The scientific process is most similar to:
Answer:
the process of solving a mystery.
Explanation:
If the mirror is immersed in water (refractive index 1.33), what is its focal length?
If the mirror is immersed in water whose index of refraction is 1.33 , No change in its focal distance . focal distance of mirrors does not depend on the external medium in which the mirror is immersed.
What happens when a mirror is immersed in water?As the focal length of the convex mirror does not depend on the factor such as the refractive index of any medium. Hence even after the convex mirror is immersed in water, the focal distance remains unchanged. Hence the facility of the convex mirror also remains same.
How is focal distance related to refractive index?Since from lens makers formula we will observe that focal length of lens is inversely proportional to refractive index of medium of lens . Hence net index of refraction of lens decreases when it is dipped in a denser medium than air, hence focal distance increases.
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two large, parallel conducting plates carrying opposite charges of equal magnitude are separated by 2.20 cm. (a) if the surface charge density for each plate has magnitude 47.0 nc>m2 , what is the magnitude of e s in the region between the plates? (b) what is the potential difference between the two plates? (c) if the separation between the plates is doubled while the surface charge density is kept constant at the value in part (a), what happens to the magnitude of the electric field and to the potential difference?
In here E = 5.3 x 10^3 N/C, the potential difference (V) between the two plates is 116.6 V and if d is doubled, electric field E won't change but V gets doubled.
How to calculate by applying the concepts?a) The electric field of infinite parallel plates can be formulated as
E= σ/2ε0 → eq1
Surface charge density is given as 47.0 nc/m2
So, the electric field is independent on d.
Hence the, so the net field is
E = E1 + E2 = σ/2ε0 + σ/2ε0 = σ/ε0
Substituting in eq 1,
E = [47 x 10^(-9) ] / 8.85 x 10^-12 = 5.3 x 10^3 N/C
b) Since the electric potential between them at any point and is given by.
V=Ed → eq 2
So, Substituting in eq 2 yields
V= 2.2 x 10^-2 x 5.3 x 10^3 = 116.6 V
c) If the distance between plates is doubled it will make no changes on the field because the field is independent on d.
For the voltage, according to equation 2 the voltage depends on d so if d is doubled then the potential between plates must be doubled.
Thus, magnitude of e in the region is 5.3 x 10^3 N/C.
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a ball is thrown directly downward with an initial speed of 8.35 m/s from a height of 29.6 m. after what time interval does it strike the gro
Answer:
The ball will be strike at the ground in 15.98s.Explanation:
Given that
a ball is thrown directly downward with an initial speed of 8.35 m/s from a height of 29.6 m.To find
what time interval does it strike the ground ?So, according the question
We have,
Initial speed [tex]u_i = 8.35 m/s[/tex]Initial Height [tex]y_i = 29.6m[/tex]The formula for the ball's height as a function of time is
[tex]y_f = y_i - u_it - \frac{1}{2} gt^2[/tex]------------------(1)
where,
[tex]y_f = final \;height=0\\y_i = initial \;height=29.6m\\u_i = initial \;velocity=8.35m/s\\\;\; g = acceleration \;due\; to\; gravity= 9.81m/s^2[/tex]
Now, putting the all given values ,
[tex]y_f = y_i - u_it - \frac{1}{2} gt^2[/tex]------------------(1)
[tex]0 = 29.6 - 8.35t - \frac{1}{2} \times9.81t^2[/tex]
or,
[tex]9.81t^2 + 16.7t -59.2 = 0\\\\t = \frac{-16.7 \pm \sqrt{(16.7)^2-4\times 9.81\times (-59.2)}}{2}}\\t = \frac{-16.7 \pm \sqrt{278.89+4\times 9.81\times 59.2}}{2}}\\t = \frac{-16.7 \pm \sqrt{278.89+2087.57}}{2}}\\t = \frac{-16.7 \pm \sqrt{2366.46}}{2}}\\t = \frac{-16.7 \pm 48.65}{2}}\\now \; we \; know \; that\; time\;always \; in\;only\;positive\\so,\\t = \frac{-16.7 + 48.65}{2}\\t = \frac{31.95}{2}\\t = 15.98s[/tex]
Answer:
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A rocket is accelerating upward from the surface of earth with an acceleration of 4. 4 m/s2. On board the rocket is a 0. 060 kg chicken egg. What is the apparent weight of the egg?.
The apparent weight of the egg is found to be 0.852 N.
Given here, the mass of the egg is m=0.06kg, acceleration due to gravity g =9.8m/s², acceleration of rocket a = 4.4m/s².
Now, we calculate apparent weight by the formula,
We = m (a + g)
= 0.06( 4.4+ 9.8)
= 0.8528 newton.
Thus, the apparent weight of the egg is found to be 0.8528N.
An object’s perceived weight, which reflects how heavy it is, is a quality. When the force of gravity acting on an object is not counter balanced by a force of equal but opposite normality, the apparent weight of the object will differ from the actual weight of the thing.
The buoyant force pushing up on the object is subtracted from the apparent weight, which is equal to the actual weight (w=mg). The apparent weight of the object at its lowest point would be equal to its normal force.
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how long does it take an automobile traveling in the left lane at 60.1 km/h to overtake (become even with) another car that is traveling in the right lane at 38.1 km/h, when the cars' front bumpers are initially 105.2 m apart?
An automobile traveling in the left lane at 60.1 km/h to overtake (become even with) another car that is traveling in the right lane at 38.1 km/h, when the cars' front bumpers are initially 105.2 m apart and the time taken is t = 17.21 seconds.
To find the time, the given values are,
Distance in,
Left lane = 60.1 km/hr
Right lane = 38.1 km/hr
Initial length d₀ = 105.2 m
What is Distance?The distance covered can be derived using the equation of motion with no acceleration.
distance d = speed v × time t
d = vt
For the first automobile,
v = 60.1 km/h
d₁ = 60.1
For the second automobile,
v = 38.1 km/h
Initial distance d = 105.2 m = 0.1052 km
d = vt + d₀.
d₂ = 38.1 t + 0.1052
For them to meet/overtake each other,
Their distance at that time must be equal.
d₁ = d₂
60.1 t = 38.1 t + 0.1052
60.1 t - 38.1 t = 0.1052
22 t = 0.1052
t = 0.1052 / 22 hr
Converting to seconds
t = 0.1052 / 22 × 3600s
t = 17.21 seconds.
The time taken for an automobile to travel is 17.21 seconds.
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I went for a walk the other day. i went four avenues east (0.80 miles), then twenty-four streets south (1.20 miles), then one avenue west (0.20 miles), and finally eight streets north (0.40 miles). a. what distance did i travel? b. what's my resultant displacement (magnitude and direction relative to due east)?
By using vector
a. the distance traveled is 2.6 miles
b. the resultant displacement is s = ( 0.6 i - 0.8 j ) miles
the magnitude is |s| = 0.6 miles
We need to know about vectors to solve this problem. Vector has magnitude and also direction. Displacement is included in vector. It can be written as
s = sx i + sy j + sz k
where s is displacement, sx is displacement on x-axis, sy is displacement on y-axis and sz us displacement on z-axis.
From the question above, we know that
east = positive x
south = negative y
west = negative x
north = positive y
s1 = 0.8 i
s2 = -1.2 j
s3 = -0.2 i
s3 = 0.4 j
The distance traveled is
s = s1 + s2 + s3 + s4
s = 0.8 + 1.2 + 0.2 + 0.4
s = 2.6 miles
The resultant displacement is
s = s1 + s2 + s3 + s4
s = 0.8 i -1.2 j -0.2 i + 0.4 j
s = ( 0.6 i - 0.8 j ) miles
The magnitude is
|s| = √sx²
|s| = √0.6²
|s| = 0.6 miles
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A utility line worker is installing a new transformer to restore electric power to a neighborhood. She drops a
screwdriver. The screwdriver takes 3.5 seconds to hit the ground. What is the height of the utility pole she
has climbed?
The height of the utility pole she has climbed is 60 m
Motion Under GravityWhen an object is dropped under gravity, the initial velocity is zero. While at the maximum height reached by an object when thrown up, the final velocity will be zero.
Given that a utility line worker drops a screwdriver which takes 3.5 seconds to hit the ground. The height of the utility pole can be calculated by using the formula below
h = ut + 1/2gt²
but u = 0
h = 1/2gt²
Substitute all the parameters into the equation
h = 1/2 × 9.8 × 3.5²
h = 4.9 × 12.25
h = 60.025 m
Therefore, the height of the utility pole she has climbed is 60 m approximately.
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a certain freely falling object, released from rest, requires 1.45 s to travel the last 27.0 m before it hits the ground.
By using uniform motion, the speed before hitting the ground is 23.00 m/s.
We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.
From the question above, we know that
vo = 0 m/s
t = 1.45 s
y = 27 m
g = 9.8 m/s²
By using the second equation, we can calculate the speed before hit the ground.
vt² = vo² + 2a . s
vt² = 0² + 2g . 27
vt² = 2 . 9.8 . 27
vt² = 529.2
vt = 23.00 m/s
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Why does a feather drift back and forth as it falls ?
(I’m confused I think it has something to do with terminal velocity though in my mind)
Answer:
you are very most correct
Explanation:
it does have something to do with terminal velocity and because the weight is so light of it any tiny gust of wind can push it back and forth and because wind is never stable thats why it moves side to side
8
2 points
Select the two words that correctly complete this statement.
The mass number of an atom is affected by the
Neutron
Proton
Electron
and the
0
Answer:
neutron and proton are the answer
A brine solution of salt flows at a constant rate of l/min into a large tank that initially held l of brine solution in which was dissolved kg of salt. The solution inside the tank is kept well stirred and flows out of the tank at the same rate. If the concentration of salt in the brine entering the tank is kg/l, determine the mass of salt in the tank after t min. When will the concentration of salt in the tank reach kg/l?.
which is 0.05 kg/L Just keep in mind that the concentration in the tank will fluctuate over time until it reaches the inflow concentration.
Chemistry involves creating and manipulating solutions frequently, yet a variety of concentration units are employed depending on the reaction or kind of analysis. Molality (M = moles solute/kg solution), mass% (mass solute/mass solution), and mass per volume concentrations are a few examples of frequent units.
After t minutes, the salt mass in the tank with a concentration of
0.02 kg/L is 2 kg.
According to the way the question is written, the tank's concentration is 0.02 kg/L, and its volume, which is independent of its input and outflow quantities, is 100 L. In light of this, multiplying the concentration by the volume will provide the amount of salt in the tank at the specified concentration.
(0.02kg/L)(100L) = 2kg
Just keep in mind that the concentration in the tank will fluctuate over time until it reaches the inflow concentration, which is 0.05 kg/L. The amount of time it will take for that to happen can be predicted by an equation, but that is not the issue being addressed here; rather, it is how much salt will be in the tank at time t when the tank concentration is
0.02 kg/L.
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The complete question is:
In a huge tank that initially stores 100 L of brine solution with 0.5 kg of salt dissolved in it, a brine solution of salt flows at a steady rate of 8 L/min. The interior of the tank is kept thoroughly stirred, and the solution drains at the same rate. Determine the mass of salt in the tank after t minutes when the concentration of salt in the tank reaches 0.02 kg/L if the salt concentration in the brine entering the tank is 0.05 kg/L.
Which scientist disproved aristotle’s idea that heavy objects fall faster than lighter objects? how?.
Galileo disproved Aristotle’s idea that heavy objects fall faster than lighter objects through his findings as specified in his books.
The study of the scientistsThe story goes that Galileo used this experiment to find that the objects fell with the same acceleration, disproving Aristotle’s theory of gravity (which states that objects fall at a speed proportional to their mass) and proving his prediction.
Before Galileo, Aristotle’s writings had been accepted as true for over a thousand years. He claimed that heavier objects fall faster than lighter ones and that an object that weighs twice as much as another will fall twice as fast.
In his book Two New Sciences, Galileo outlined his theories regarding falling objects and projectiles in general (1638).
The two disciplines were the study of motion, which helped establish physics as a discipline, and the science of materials and construction, which made significant contributions to engineering.
This theory of Galileo’s was totally based on a well-known thought experiment that he described in his book.
To know more about Galileo experiment visit:
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