The red line segment on the number line below represents the segment from A to B, where A = 4 and B = 12. Find the value of the point P on segment AB that is of the distance from A to B.

The line integral of the given function, ∫_c y²dx+xdy, along the arc of the parabola x = 4 - y² from (-5, -3) to (0, 2), can be evaluated by parameterizing the curve and then calculating the integral using the parameterization.

To evaluate the line integral, we first need to parameterize the given curve. Since the parabola is defined by x = 4 - y², we can choose y as the parameter. Let's denote y as t, where t varies from -3 to 2. Then, we can express x in terms of t as x = 4 - t².

Next, we differentiate the parameterization to obtain dx/dt = -2t and dy/dt = 1. Now, we substitute these values into the line integral expression: ∫_c y²dx + xdy = ∫_c y²(-2t)dt + (4 - t²)dt.

Now, we integrate with respect to t, using the limits of -3 to 2, since those are the parameter values corresponding to the given endpoints. After integrating, we obtain the value of the line integral.

By evaluating the integral, you will find the numerical result for the line integral along the arc of the parabola x = 4 - y² from (-5, -3) to (0, 2), based on the given function ∫_cy²dx + xdy.

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The function is not a solution of the differential equation xy' - 7y - xe*, x > 0. y = x

To determine if y = x(15+ e^x) is a solution of the differential equation xy' - 7y - xe^x = 0, we need to substitute y and y' into the left-hand side of the equation and see if it simplifies to 0.

First, we find y':

y' = (15 + e^x) + xe^x

Next, we substitute y and y' into the equation and simplify:

x(15 + e^x) + x(15 + e^x) - 7x(15 + e^x) - x^2 e^x

= x(30 + 2e^x - 105 - 7e^x - xe^x)

= x(-75 - 6e^x - xe^x)

Since this expression is not equal to 0 for all x > 0, y = x(15 + e^x) is not a solution of the differential equation xy' - 7y - xe^x = 0.

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The total number of ways you can answer the 12-question true-false exam, assuming that you do not omit any question is 4096 ways

From the question given above, we were told that the total number of questions to be answered is 12 and also, we have two ways (i.e true or false) for answering each question.

From the above information, we can obtain the total number of ways of answering the 12 questions as follow:

Total number of ways = rⁿ

Total number of ways = 2¹²

Total number of ways = 4096 ways

Thus, the total number of ways of answering the 12 questions is 4096 ways

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The value of the expression y' + ky is 0.

Given the function y = Acos(kt) + Bsin(kt), where A, B, and k are constants, we need to find the value of y' + ky.

First, let's find the derivative of y with respect to t.

Taking the derivative of each term separately, we have:

y' = -Aksin(kt) + Bkcos(kt)

Next, we substitute y' into the expression y' + ky:

y' + ky = (-Aksin(kt) + Bkcos(kt)) + k(Acos(kt) + Bsin(kt))

Expanding the terms and rearranging, we have:

y' + ky = -Aksin(kt) + Bkcos(kt) + Akcos(kt) + Bksin(kt)

Combining like terms, we get:

y' + ky = (Bk - Ak)cos(kt) + (Bk + Ak)sin(kt)

To determine the value of y' + ky, we need to consider the coefficient of each trigonometric function.

Since the coefficients Bk - Ak and Bk + Ak are constants, their values will depend on the specific values of A, B, and k.

However, the trigonometric functions cos(kt) and sin(kt) are periodic functions that repeat their values, so their sum will be periodic as well.

Therefore, the value of y' + ky is 0, regardless of the specific values of A, B, and k.

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False. Not every autonomous differential equation is a separable differential equation.

A separable differential equation is a type of differential equation that can be written in the form dy/dx = f(x)g(y), where f(x) and g(y) are functions of x and y, respectively. In a separable differential equation, the variables x and y can be separated and integrated separately.

On the other hand, an autonomous differential equation is a type of differential equation where the derivative is expressed solely in terms of the dependent variable. In other words, the equation does not explicitly depend on the independent variable.

While some autonomous differential equations may be separable, it is not true that every autonomous differential equation can be expressed as a separable differential equation.

Autonomous differential equations can take various forms, and not all of them can be transformed into the separable form. Some autonomous equations may require other techniques or methods for their solution, such as linearization, substitution, or numerical methods. Therefore, the statement that every autonomous differential equation is itself a separable differential equation is false.

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The probability of picking two balls of the same color, regardless of order, can be found by calculating the probability of picking two blue balls, two green balls, or two red balls and summing them up.

The probability of picking two blue balls:

P(2 blue) = (4/13) * (3/12) = 1/13

The probability of picking two green balls:

P(2 green) = (7/13) * (6/12) = 7/26

The probability of picking two red balls:

P(2 red) = (2/13) * (1/12) = 1/78

Now, we sum up the probabilities:

P(both balls same color) = P(2 blue) + P(2 green) + P(2 red) = 1/13 + 7/26 + 1/78 = 9/26

Therefore, the probability of picking two balls of the same color, regardless of order, is 9/26.

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a. The first derivative of f(x) is f'(x) = 28x, and the second derivative is f''(x) = 28.

b. The first derivative of g(t) = f'(t^2 + 2) is 56t(t^2 + 2)

c. The first derivative of v(s) is v'(s) = 2s / (s^2 - 4), and the second derivative is v''(s) = (-2s^2 - 8) / (s^2 - 4)^2.

d.  The first derivative of h(x) is h'(x) = -3, and the second derivative is h''(x) = 0.

(a) To compute the first and second derivatives of the function f(x) = 14x^2 - 12, we'll differentiate each term separately.

First derivative:

f'(x) = d/dx (14x^2 - 12)

= 2(14x)

= 28x

Second derivative:

f''(x) = d^2/dx^2 (14x^2 - 12)

= d/dx (28x)

= 28

Therefore, the first derivative of f(x) is f'(x) = 28x, and the second derivative is f''(x) = 28.

(b) To find the first derivative of g(t) = f'(t^2 + 2), we need to apply the chain rule. The chain rule states that if h(x) = f(g(x)), then h'(x) = f'(g(x)) * g'(x).

Let's start by finding the derivative of f(x) = 14x^2 - 12, which we computed earlier as f'(x) = 28x.

Now, we can apply the chain rule:

g'(t) = d/dt (t^2 + 2)

= 2t

Therefore, the first derivative of g(t) = f'(t^2 + 2) is:

g'(t) = f'(t^2 + 2) * 2t

= 28(t^2 + 2) * 2t

= 56t(t^2 + 2)

(c) To compute the first and second derivatives of v(s) = ln(s^2 - 4), we'll apply the chain rule and the derivative of the natural logarithm.

First derivative:

v'(s) = d/ds ln(s^2 - 4)

= 1 / (s^2 - 4) * d/ds (s^2 - 4)

= 1 / (s^2 - 4) * (2s)

= 2s / (s^2 - 4)

Second derivative:

v''(s) = d/ds (2s / (s^2 - 4))

= (2(s^2 - 4) - 2s(2s)) / (s^2 - 4)^2

= (2s^2 - 8 - 4s^2) / (s^2 - 4)^2

= (-2s^2 - 8) / (s^2 - 4)^2

Therefore, the first derivative of v(s) is v'(s) = 2s / (s^2 - 4), and the second derivative is v''(s) = (-2s^2 - 8) / (s^2 - 4)^2.

(d) To compute the first and second derivatives of h(x) = 523 - 3x + 14, note that the derivative of a constant is zero.

First derivative:

h'(x) = d/dx (523 - 3x + 14)

= -3

Second derivative:

h''(x) = d/dx (-3)

= 0

Therefore, the first derivative of h(x) is h'(x) = -3, and the second derivative is h''(x) = 0.

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The required value of x is 18.4.

Given the right-angled triangle with hypotenuse is x and one side is equal to 13 and angle is 45°.

To find the one side of the triangle by using the trigonometric functions  tan a and then use Pythagoras theorem to find the value of x.

Pythagoras theorem states that [tex]hypotenuse^2 = base^2 + perpendicular^2[/tex].

In triangle, tan a = perpendicular / base.

That implies, tan 45° = 13/x

On evaluating the value tan 45° = 1 gives,

1 = 13/ x

on cross multiplication gives,

x = 13.

By using Pythagoras theorem, find the base of the triangle,

[tex]hypotenuse^2 = base^2 + perpendicular^2[/tex].

[tex]x^{2} = 13^2 +13^2[/tex]

[tex]x^{2}[/tex] = 2 ×[tex]13^{2}[/tex]

take square root on both sides gives,[tex]\sqrt{2}[/tex]

x = 13 [tex]\sqrt{2}[/tex]

x = 13 × 1.141

x  = 18.38

Rounding off to tenths gives,

x = 18.4.

Hence, the required value of x is 18.4.

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We can take advantage of the integrand's symmetry over the y-axis to employ symmetry to evaluate the integral [-8, 8] (3 + x + x2 + x3) d.

As a result, the integral across the range [-8, 8] can be divided into two equally sized pieces, [-8, 0] and [0, 8].

Taking into account the integral throughout the range [-8, 0]: [-8, 0] (3 + x + x² + x³) dx

The integral of an odd function over a symmetric interval is zero because the integrand is an odd function (contains only odd powers of x). The integral over [-8, 0] hence evaluates to zero.

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Inverse Laplace transform for 1/8(s+3) = (1/8)e^(-3t)

Laplace transform can be defined as a technique for solving linear differential equations by transforming them into algebraic equations. Inverse Laplace Transform can be defined as the process of recovering a time-domain signal from its Laplace Transform that maps it into a complex frequency domain.

Therefore, we are to find the inverse Laplace transforms of the given functions.

i) Laplace transform: Y(s)= 8/s + 6Inverse Laplace Transform: y(t)= 8-6e-3t

ii) Laplace transform: Y(s)= 3s/12s²+6s+25Inverse Laplace Transform: y(t)= 1/4e-3t(sin4t+cos4t)

iii) Laplace transform: Y(s)= 1/8(s+3)Inverse Laplace Transform: y(t)= 1/8(e-3t)

Final Answer: Inverse Laplace transform for -8/(s+6) = 8-6e^(-3t) Inverse Laplace transform for 3s/(12s^2+6s+25) = (1/4)e^(-3t) (sin(4t)+cos(4t)) Inverse Laplace transform for 1/8(s+3) = (1/8)e^(-3t)

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Based on the information, the volume of this box is 65776 cm³.

The volume of a box is given by the formula:

V = lwh

We are given that the sum of the width, height, and length must be less than or equal to 258 cm. This can be written as:

l + w + h <= 258

We are given that the sum of l, w, and h must be less than or equal to 258. This means that each of l, w, and h must be less than or equal to 258/3 = 86 cm.

Therefore, the dimensions of the box with maximum volume are 86 cm by 86 cm by 86 cm.

The volume of this box is:

V = 86 cm * 86 cm * 86 cm

= 65776 cm³

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The terms "Fof" and "Dfof" as well as "Gog" and "Dgog" do not have recognized meanings in common usage. Without further context or explanation, it is challenging to provide a precise explanation.



In a hypothetical scenario, "Fof" could represent a function or operation applied to a set or data, and "Dfof" might refer to the domain of that function or the set of inputs on which it operates. Similarly, "Gog" could signify another function or operation, and "Dgog" could represent its domain.

For instance, if "Fof" denotes a function that squares numbers, then "Dfof" would be the set of all possible input values for that function, while "Gog" could represent a different function that takes the square root of a number, and "Dgog" would be the corresponding domain.

However, without specific context or clarification, it is impossible to provide a definitive interpretation. It is crucial to understand the intended meaning of these terms within the specific context in which they are used to provide a more accurate explanation.

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The value of the integral ∫(4r / √(14+2r^2)) dr is 2√(14+2r^2) + C.

To evaluate the integral ∫(4r / √(14+2r^2)) dr, we can use the substitution method. Let's make the substitution u = 14 + 2r^2. To find the differential du, we take the derivative of u with respect to r: du = 4r dr. Rearranging this equation, we have dr = du / (4r).

Substituting the values into the integral, we get: ∫(4r / √(14+2r^2)) dr = ∫(du / √u).

Now, the integral becomes ∫(1 / √u) du. We can simplify this integral by using the power rule of integration, which states that the integral of x^n dx equals (x^(n+1) / (n+1)) + C, where C is the constant of integration.

Applying the power rule, we have: ∫(1 / √u) du = 2√u + C. Substituting the original variable back in, we have:2√(14+2r^2) + C. Therefore, the value of the integral ∫(4r / √(14+2r^2)) dr is 2√(14+2r^2) + C.

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To find the equation of the tangent to the ellipse at a given point, we need to calculate the derivative of the ellipse equation with respect to x.

The equation of the ellipse is given by x^2 + 3y^2 - 76 = 0. By differentiating implicitly with respect to x, we obtain the derivative:

2x + 6y(dy/dx) = 0

Solving for dy/dx, we have:

dy/dx = -2x / (6y) = -x / (3y)

Now, let's find the equation of the tangent at each given point:

(a) Point (7, 3):

Substituting x = 7 and y = 3 into the equation for dy/dx, we find dy/dx = -7 / (3*3) = -7/9. Using the point-slope form of a line (y - y0 = m(x - x0)), we can write the equation of the tangent as y - 3 = (-7/9)(x - 7), which simplifies to y = (-7/9)x + 76/9.

(b) Point (-7, 3):

Substituting x = -7 and y = 3 into dy/dx, we get dy/dx = 7 / (3*3) = 7/9. Using the point-slope form, the equation of the tangent becomes y - 3 = (7/9)(x + 7), which simplifies to y = (7/9)x + 76/9.

(c) Point (1, -5):

Substituting x = 1 and y = -5 into dy/dx, we obtain dy/dx = -1 / (3*(-5)) = 1/15. Using the point-slope form, the equation of the tangent is y - (-5) = (1/15)(x - 1), which simplifies to y = (1/15)x - 76/15.

In summary, the equations of the tangents to the ellipse at the given points are:

(a) (7, 3): y = (-7/9)x + 76/9

(b) (-7, 3): y = (7/9)x + 76/9

(c) (1, -5): y = (1/15)x - 76/15.

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If the two odometer readings were 48,592 and 48,892, and the amount of gas was 8.5 gallons then his miles per gallon will be 35.

To calculate Eric's miles per gallon (MPG), we need to determine the number of miles he traveled on 8.5 gallons of gas.

Given that the odometer readings were 48,592 and 48,892, we can find the total number of miles traveled by subtracting the initial reading from the final reading:

Total miles traveled = Final odometer reading - Initial odometer reading

                   = 48,892 - 48,592

                   = 300 miles

To calculate MPG, we divide the total miles traveled by the amount of gas used:

MPG = Total miles traveled / Amount of gas used

   = 300 miles / 8.5 gallons

Performing the division gives us:

MPG = 35.2941176...

Rounding the MPG to the nearest whole number, we get:

MPG ≈ 35

Therefore, Eric's miles per gallon is approximately 35.

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To evaluate the limit using L'Hôpital's rule, we need to take the derivative of the numerator and denominator separately and then evaluate the limit again.

Given the expression: lim (6x / e^2 + 6x) as x approaches 0

Taking the derivative of the numerator and denominator separately:

The derivative of 6x with respect to x is simply 6.

The derivative of e^2 + 6x with respect to x is 6.

Now we have the new expression:

lim (6 / 6) as x approaches 0

Simplifying, we get:

lim 1 as x approaches 0

Therefore, the limit of the expression is equal to 1.

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The cosine of the angle C between the position vectors of A and B satisfies cos C = cos 6 cos 0' + sin 0 sin ' cos(0 - 0).

Let A be the point on the unit sphere with colatitude 0 and longitude ; let B be the point on the unit sphere with colatitude ' and longitude ¢'.

Write down the position vectors of A and B with respect to the origin, and by considering A·B, show that the cosine of the angle C between the position vectors of A and B satisfies cos C = cos 6 cos 0' + sin 0 sin ' cos(0 - 0).

The position vector of A with respect to the origin is given by the unit vector [x, y, z] which is such that

x = cos 0 sin y = sin 0 sin z = cos 0.

Position vector of A = [cos 0 sin, sin 0 sin , cos 0].

The position vector of B with respect to the origin is given by the unit vector [x, y, z] which is such that:

x = cos ¢' sin 'y = sin ¢' sin 'z = cos '.

Position vector of B = [cos ' sin ¢', sin ' sin ¢', cos '].

Now, A·B = |A| |B| cos C cos C = A·B/|A| |B|= [cos 0 sin ¢' + sin 0 sin 'cos(0 - ¢')] / 1 = cos 6 cos 0' + sin 0 sin 'cos(0 - ¢').

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However, based on the given answer choices, we can determine that the correct option is (1.133, 5.627) to calculate the 95% confidence interval.

To calculate the 95% confidence interval for the difference between the mean travel times for the detour and alternative routes, we need the following information:

Sample size (n): 13

Mean travel time for the detour (x1): Calculate the average travel time for the detour.

Mean travel time for the alternative route (x2): Calculate the average travel time for the alternative route.

Standard deviation for the detour (s1): Calculate the sample standard deviation for the detour.

Standard deviation for the alternative route (s2): Calculate the sample standard deviation for the alternative route.

Degrees of freedom (df): Calculate the degrees of freedom, which is n1 + n2 - 2.

t* value: The t* value for a 95% confidence interval with the given degrees of freedom.

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To determine the temperature of the oven, we can use the concept of thermal equilibrium. When two objects are in thermal equilibrium, they are at the same temperature.

In this case, the thermometer and the oven reach thermal equilibrium when their temperatures are the same.

Let's denote the initial temperature of the oven as T (in °C). According to the information given, the thermometer initially reads 19°C and then reads 27°C after 26 seconds and 28°C after 52 seconds.

Using the data provided, we can set up the following equations:

Equation 1: T + 26k = 27 (after 26 seconds)

Equation 2: T + 52k = 28 (after 52 seconds)

where k represents the rate of temperature change per second.

To find the value of k, we can subtract Equation 1 from Equation 2:

(T + 52k) - (T + 26k) = 28 - 27

26k = 1

k = [tex]\frac{1}{26}[/tex]

Now that we have the value of k, we can substitute it back into Equation 1 to find the temperature of the oven:

T + 26(\frac{1}{26}) = 27

T + 1 = 27

T = 27 - 1

T = 26°C

Therefore, the temperature of the oven is 26°C.

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Answer:

20 students brought their lunch on Thursday.

Step-by-step explanation:

5% of 400 = 20 students

400 x .05 = 20

The given angle, 134.1899 degrees, needs to be converted to degrees, minutes, and seconds format.

To convert the angle from decimal degrees to degrees, minutes, and seconds, we can use the following steps.

First, let's extract the whole number of degrees from the given angle. In this case, the whole number of degrees is 134.

Next, we need to determine the minutes portion. To do this, multiply the decimal portion (0.1899) by 60. The result, 11.394, represents the minutes.

Finally, to find the seconds, multiply the decimal portion of the minutes (0.394) by 60. The outcome, 23.64, represents the seconds.

Combining all the values, we have the converted angle as 134 degrees, 11 minutes, and 23.64 seconds.

In conclusion, the given angle of 134.1899 degrees can be converted to degrees, minutes, and seconds format as 134 degrees, 11 minutes, and 23.64 seconds. This conversion allows for a more precise representation of the angle in a commonly used format for measuring angles.

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The volume under the elliptic paraboloid over the rectangle R=[−1,1]×[−1,1] is 32/5 cubic units.

To calculate the volume under the elliptic paraboloid over the given rectangle, we need to set up a double integral. The volume can be calculated as the double integral of the function z=3x^2+5y^2 over the rectangle R=[−1,1]×[−1,1].

∫∫R (3x^2 + 5y^2) dA

Using the properties of double integrals, we can rewrite the integral as:

∫∫R 3x^2 + ∫∫R 5y^2 dA

The integration over each variable separately gives:

(3/3)x^3 + (5/3)y^3

Evaluating the above expression over the rectangle R=[−1,1]×[−1,1], we get:

[(3/3)(1^3 - (-1)^3)] + [(5/3)(1^3 - (-1)^3)]

Simplifying further:

(2/3) + (10/3)

Which equals 32/5 cubic units. Therefore, the volume under the elliptic paraboloid over the given rectangle is 32/5 cubic units.

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To find F(x), we integrate the given derivative function. F'(x) = 6 implies that F(x) is the antiderivative of 6 with respect to x, which is 6x + C. To find F"(x), we differentiate F'(x) with respect to x. F"(x) is the derivative of 6x + C, which is simply 6.

To find F(x), we need to integrate the given derivative function F'(x) = 6. Since the derivative of a function gives us the rate of change of the function, integrating F'(x) will give us the original function F(x).

Integrating F'(x) = 6 with respect to x, we obtain:

∫6 dx = 6x + C

Here, C is the constant of integration, which can take any value. So, the antiderivative or the general form of F(x) is 6x + C, where C represents the constant.

To find F"(x), we differentiate F'(x) = 6 with respect to x. Since the derivative of a constant is zero, F"(x) is simply the derivative of 6x, which is 6.

Therefore, the function F(x) is given by F(x) = 6x + C, and its second derivative F"(x) is equal to 6.

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The smallest number that, when divided by 21, 45, and 56, leaves a remainder of 7 is 2527.

The remaining 7 must be added after determining the least common multiple (LCM) of the numbers 21, 45, and 56.

Find the LCM of 21, 45, and 56 first:

21 = 3 * 7

45 = 3^2 * 5

56 = 2^3 * 7

The LCM is the product of the highest powers of all the prime factors involved:

[tex]LCM = 2^3 * 3^2 * 5 * 7 = 8 * 9 * 5 * 7 = 2520[/tex]

Now, let's add the remainder of 7 to the LCM:

Smallest number = LCM + Remainder = 2520 + 7 = 2527

Therefore, the smallest number that, when divided by 21, 45, and 56, leaves a remainder of 7 is 2527.

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Given the function f(x) = x² - 6x - 95, we are to calculate the coordinates of the y-intercept and the x-intercepts of the graph of the function in question 10.

We are also to find the interval in which the function is increasing or decreasing.10.1.

Calculation of the y-intercept We recall that the y-intercept is the point at which the graph of the function intersects the y-axis.

At the y-intercept, x = 0.

Therefore, substituting x = 0 in the equation of the function,

we have y = f(0) = (0)² - 6(0) - 95 = -95

Therefore, the coordinates of the y-intercept are (0, -95).10.2.

Calculation of the x-intercepts

We recall that the x-intercepts are the points at which the graph of the function intersects the x-axis.

At the x-intercept, y = 0.

Therefore, substituting y = 0 in the equation of the function,

we have:0 = x² - 6x - 95Applying the quadratic formula,

we have:x = (-b ± √(b² - 4ac)) / 2aWhere a = 1, b = -6, and c = -95.

Substituting the values of a, b, and c, we have:

x = (6 ± √(6² - 4(1)(-95))) / 2(1)x

= (6 ± √(36 + 380)) / 2x = (6 ± √416) / 2x

= (6 ± 8√26) / 2x

= 3 ± 4√26

Therefore, the coordinates of the x-intercepts are (3 + 4√26, 0) and (3 - 4√26, 0).

The interval of Increase or Decrease of the function to find the interval of increase or decrease, we have to first find the critical points.

Critical points are points at which the derivative of the function is zero or undefined.

Therefore, we have to differentiate the function f(x) = x² - 6x - 95.

Applying the power rule of differentiation,

we have f'(x) = 2x - 6Setting f'(x) = 0, we have:

2x - 6 = 0x = 3At x = 3, the function attains a minimum.

Therefore, we have the following intervals:

The function is decreasing on the interval (-∞, 3) and is increasing on the interval (3, ∞).

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The given limit can be expressed as the definite integral: ∫[2 to 8] 5(x^3 - 3x) dx. To express the limit as a definite integral, we can rewrite it in the form: lim [n→∞] Σ[1 to n] f(x_i) Δx where f(x) is the function inside the limit, x_i represents the points in the interval, and Δx is the width of each subinterval.

In this case, the limit is:

lim [n→∞] Σ[1 to n] 5(x^3 - 3x) dx

We can rewrite the sum as a Riemann sum:

lim [n→∞] Σ[1 to n] 5(x_i^3 - 3x_i) Δx

To express this limit as a definite integral, we take the limit as n approaches infinity and replace the sum with the integral:

lim [n→∞] Σ[1 to n] 5(x_i^3 - 3x_i) Δx = ∫[2 to 8] 5(x^3 - 3x) dx

Therefore, the given limit can be expressed as the definite integral:

∫[2 to 8] 5(x^3 - 3x) dx.

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To find the area between the function f(x) = x^3 - 7x - 4 and the x-axis on the domain [-2, 2], we can set up the integral as follows:

∫[-2,2] |f(x)| dx

1. First, we consider the absolute value of the function |f(x)| to ensure that the area is positive.

2. We set up the integral using the limits of integration [-2, 2] to cover the specified domain.

3. The integrand |f(x)| represents the height of the infinitesimally small vertical strips that will contribute to the total area.

4. Integrating |f(x)| over the interval [-2, 2] will give us the desired area between the function and the x-axis.

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The slope-intercept form of the equation is y = 2x.

To find the point-slope form of a line, we use the formula:

y - y₁ = m(x - x₁),

where (x₁, y₁) represents a point on the line, and m is the slope of the line. Given two points, (7,14) and (8,16), we can calculate the slope (m) using the formula: m = (y₂ - y₁) / (x₂ - x₁),

where (x₂, y₂) represents the second point. Plugging in the values, we get:

m = (16 - 14) / (8 - 7) = 2.

Now we can use the point-slope form with either of the two points. Let's use (7,14):

y - 14 = 2(x - 7).

To convert this to the slope-intercept form (y = mx + b), we simplify:

y - 14 = 2x - 14,

y = 2x.

Therefore, the slope-intercept form of the equation is y = 2x.

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The fundamental difference between the t statistic and a z statistic is that the t statistic computes the standard error by dividing the standard deviation by n-1 instead of dividing by n so the correct answer is option (c).

This is because the t statistic is used when the population standard deviation is unknown, and the sample standard deviation is used as an estimate. Therefore, the formula for the standard error of the t statistic adjusts for the fact that the sample standard deviation may not be an exact reflection of the population standard deviation.

Additionally, the t statistic also uses the sample mean in place of the population mean, which is another difference from the z statistic. The z statistic assumes that the population mean is known, while the t statistic is used when the population mean is unknown. Finally, the t statistic uses the sample variance in place of the population variance, which is yet another difference between the two statistics.

Overall, these differences make the t statistic a more flexible and practical tool for analyzing data when the population parameters are unknown.

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[tex]\textit{arc's length}\\\\ s = r\theta ~~ \begin{cases} r=radius\\ \theta =\stackrel{radians}{angle}\\[-0.5em] \hrulefill\\ r=9\\ \theta =\frac{2\pi }{3} \end{cases}\implies s=(9)\cfrac{2\pi }{3}\implies s=(9)\cfrac{2(3.14) }{3}\implies s=18.84 \\\\[-0.35em] ~\dotfill[/tex]

[tex]\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta r^2}{2} ~~ \begin{cases} r=radius\\ \theta =\stackrel{radians}{angle}\\[-0.5em] \hrulefill\\ r=9\\ \theta =\frac{2\pi }{3} \end{cases}\implies A=\cfrac{2\pi }{3}\cdot \cfrac{9^2}{2} \\\\\\ A=\cfrac{2(3.14) }{3}\cdot \cfrac{9^2}{2}\implies A=84.78[/tex]