The period of rotation of Mars is 1 day and 37 minutes. Determine its frequency of rotation in Hertz.

Answers

Answer 1

The frequency of rotation of Mars is 0.0000113 Hertz.

Given the following data:

Period = 1 day and 37 minutes.

To find the frequency of rotation in Hertz:

First of all, we would convert the the value of period in days and minutes to seconds because the period of oscillation of a physical object is measured in seconds.

Conversion:

1 day = 24 hours

24 hours to minutes = [tex]60[/tex] × [tex]24[/tex] = [tex]1440[/tex] minutes

[tex]1440 + 37 = 1477 \; minutes[/tex]

1 minute = 60 seconds

1477 minute = X seconds

Cross-multiplying, we have:

[tex]X = 60[/tex] × [tex]1477[/tex]

X = 88620 seconds

Now, we can find the frequency of rotation of Mars by using the formula:

[tex]Frequency = \frac{1}{Period}\\\\Frequency = \frac{1}{88620}[/tex]

Frequency of rotation = 0.0000113 Hertz

Therefore, the frequency of rotation of Mars is 0.0000113 Hertz.

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Related Questions

PLEASE HELPPPPPPPPPPPPP

Answers

Answer: sliding

Explanation:

A snow skier slowing to a stop after skiing down a mountain is an example of sliding friction

Answer:

static friction

Explanation:

Five example of effect of gravitation in our daily life
Five example of effect of gravity in our daily life
Five example of free fall in our daily life​

Answers

Answer:

The apple

falling to our death

the earth pulling us down

what a rock falls onto our head and we die

when a child falls into a volcano and lives for 2 seconds and then dies

Explanation:

How many significant figures are in the following measurements? a. 3000000000 m/sA bike rider accelerates uniformaly at 2.0m/s^2 in 7.0 s. What was the speed of the object after 2.0 seconds?

Answers

Answer: 1 sig fig

Explanation: because 0s aren‘t significant and yes decimal points matter but after the decimal it’s a 0. So it is 1. If it was 0.30 it would be 2 sig figs but 0.03 would be one sig fig.

1. A bicyclist travels for 1.5 hours at an average speed of 23 km/h. How far does the bicyclist travel
in that time?

Answers

Explanation:

23 km/hr x 1.5 hrs = 34.5 km

34.5 km = 34500 meters

In this case your finding d or distance. So you would have to multiply the time by speed. The time in this case is 1.5hrs, the speed in 34.5km/h. So multiply and you’ll get 34.5m

50 POINTS! pls answer

Answers

Thanks for points...

But can you type this question.. As it becomes hard to answer if it's in the picture..

Answer:

The correct answer is C - 7.8 < 7 5/6 < 7.9

Step-by-step explanation:

First, convert 7 5/6 to decimal form --> 7.83.

If you don't know how to convert, think about what 5/6 is equal to and put it in decimal form. Add your decimal to the whole number, and there is your answer.

7.83 is in between 7.8 and 7.9, so it must be the answer.

I hope this helps!

How does the current in a resistor change if the voltage across the resistor is
increased by a factor of 2?

Answers

If the voltage across a resistor is increased by a factor of two, the current in the resistor doubles.

What is ohm’s law?

When all physical parameters and temperature are constant, Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.

This current-voltage connection may be expressed mathematically as,

The Equation of Ohm's Law;

V∝I

V'∝I'

Hence, if the voltage across a resistor is increased by a factor of two, the current in the resistor doubles.

To learn more the ohm's law refer to the link;

https://brainly.com/question/796939

#SPJ1

1 oto chạy trên 1 đoạn đường thẳng từ địa điểm A đến địa điểm B phải mất 1 khoảng thời gian t, Tốc độ của oto trong nửa đầu của khoảng thời gian này là 60km/h và trong nửa cuối là 40km/h. Tính tốc độ trung bình của oto trên cả đoạn đường AB

Answers

Answer:

Explanation:

t = (½d)/60 + (½d)/40

t = (½d)/60(2/2) + (½d)/40(3/3)

t = (½d)2/120 + (½d)3/120

t = (½d)5/120

t = (½d)/24

t = d/48

v = d/t

v = d / (d/48)

v = 48 km/h

Explain what would happen if an ebonite rod charged with fur is brought together with an acetate rod charged with silk

Answers

Answer:

The ebonite becomes negatively charged, and the fur becomes positively charged.

Explanation:

When an ebonite rod is rubbed against animal fur, some of the electrons from atoms of the fur are transferred to the rod.The ebonite becomes negatively charged, and the fur becomes positively charged.(a) A positive charge (+) and a negative charge (–) attract each other. (b) Two negative charges repel each other. (c) Two positive charges repel each other.

What is the word meaning for every for each

Answers

Used for talking about the relationship between 1 # or an amount of another

Answer:

There grateful for each and every aportunity they've been given

FIGURE 1 shows a 10 kg uniform metal rod with 2.0 m long pivoted at its centre C. A 20 N force is exerted on the rod, 0.5 m from point C. If the rod is in equilibrium, determine the
a) force, F needed.
b) magnitude and the direction of the force exerted at point C. ​

Answers

Answer:

Explanation:

Assuming we are looking parallel to a horizontal pivot pin with positive UP to the top of the picture, and the 20 N force acts perpendicular to the rod.

Sum moments about C to zero assume CW is the positive moment.

The rod mass causes no moment because there is no moment arm about C.

Fsin50[1.0} - 20[0.5] = 0

F = 10/sin50

F = 13 N

Summing vertical forces to zero With R being the pin reaction at C

Ry - F - 20sin50 - mg = 0

Ry = 13 + 20sin50 + 10(9.8)

Ry = 126.32 N

Summing horizontal forces to zero assuming a right directed force is positive.

Rx + 20cos50 = 0

Rx = -12.855...

R = √(-12.855² + 126.32²) = 126.972

R = 127 N

θ =arctan(126.32/-12.855) = 95.8107... = 5.8° CCW from UP

a bean is placed evenly on a pivot point (fulcrum) on one side of 10N weight is placed 2m from the pivot and a 40N weight a further 4m from the pivot point. How far from the pivot point must the centre of gravity of an 80N weight placed to perfectly balance the beam horizontally?​

Answers

Answer:

hope you will understand

Explanation:

A projectile is launched
horizontally from a cliff
top at 16 m/s.
Determine the values
of the velocity
components at 1-
second intervals of
time.

Answers

The vertical component of the velocity after the given time is -9.8 m/s while the horizontal component of the velocity is 16 m/s.

The given parameters;

initial horizontal velocity, vₓ = 16 m/sinitial vertical velocity, [tex]v_y =0[/tex]time interval 1 seconds

The components of the velocity can be horizontal or vertical velocity.

The vertical component of the velocity is affected by acceleration due to gravity while the horizontal component of the velocity is not affected by gravity.

The vertical component of the velocity is calculated as;

[tex]v_y = v_0_y -gt\\\\v_y = 0 - (1\times 9.8)\\\\v_y = -9.8 \ m/s[/tex]

The horizontal component of the velocity is constant since it is not affected by gravity.

The horizontal component of the velocity = 16 m/s

Thus, the vertical component of the velocity after the given time is -9.8 m/s while the horizontal component of the velocity is 16 m/s.

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in a paragraph of lines explain how would you simplify the topic for grade 10 learners electricity and magnetism

Answers

Electricity is the movement of electrons around a closed-loop known as a circuit.

Magnetism is a phenomenon that results from the motion of electric charges phenomenon resulting in the attractive and repulsive forces between objects.

Both electricity and magnetism are known to be similar in nature in that a magnetic field that is changing can create an electric field and also a changing electric field can create a magnetic field.

Learn more here: https://brainly.com/question/12132070

A jet plane is traveling with a velocity of 720 kilometers/hour due north. There is a crosswind of 40 kilometers/hour from the east. Find the resultant velocity and the direction of the jet plane.

A.
720 kilometers/hour in the direction of 3.2° west of north
B.
720 kilometers/hour due north
C.
721 kilometers/hour in the direction of 3.2° west of north
D.
520 kilometers/hour in the direction of 45° east of north

Answers

Answer:

Option c is correct v = 721 km/h θ = 3.2°

Explanation:

In pic is further explanation: A triangle means division

The magnitude of the velocity of the plane can be found by calculating the resultant of the two velocities:

 R= [tex]\sqrt{(720km ÷ h^)^2 + (40km ÷ h)^2) = 721.1 km ÷ h}[/tex]

The direction can be found as follows:  

0 = tan^-1 (720km ÷ h/40km ÷h) = 86.8

where 720 km/h represents the velocity towards north, while 40 km/h represents the velocity towards west, so the angle is measured with respect to east. Therefore:

the direction is 86.8*north of west

(Hope this helps can I pls have brainlist (crown)1

Answer:

See image

Explanation:

Plato

In a science fiction novel two enemies, Bonzo and Ender, are fighting in outer spce. From stationary positions, they push against each other. Bonzo flies off with a velocity of +1.8 m/s, while Ender recoils with a velocity of -2.6 m/s. Determine the ratio mBonzo/mEnder of the masses of these two enemies.

Answers

Answer:

Explanation:

Conservation of momentum

Initial momentum is zero

mB(1.8) + mE(-2.6) = 0

mB(1.8) = mE(2.6)

mB/mE = 2.6/1.8

A ball of mass 2 kg is being pulled sideways by a force 3 N to the right, and a force of 8N to the left - these are the only forces acting on it..

1.) What is the net force in the horizontal (x) direction?

2.) what is the acceleration in the horizontal (x) direction?​

Answers

Answer:

Explanation:

1.) What is the net force in the horizontal (x) direction?

Fnet = 8 - 3 = 5 N left

2.) what is the acceleration in the horizontal (x) direction?​

a = Fnet/m = 5/2 = 2.5 m/s² left

Jake lifted a 10-kg bell by a distance of 0.50 meters in 0.50 seconds. How much power did Jake use?​

Answers

Answer:

10 watts

Explanation:

first calculate work.

Work =force×distance cos thita

10Kg×0.50M cos 0= 5joules

Therefore, Power=Work÷ Time

Therefore, 5joules÷0.50s=10 watts.

The driver of a 1,500 kg car is traveling at 25 m/s. A deer runs into the road and the driver slams on the brakes. If it takes the car 5 seconds to stop, the acceleration of the car is ____ m/s2.


a.
0.25 m/s2


b.
-0.25 m/s2


c.
5 m/s2


d.
-5 m/s2

Answers

Answer:

c.

5 m/s2

Explanation:

Δv = at

a = Δv/t

a = (0 - 25)/5

a = 5 m/s²

the game in the suburbs and rural areas of the Philippines is/are called_____?? ​

Answers

Answer:

Games such as Patintero, Tumbang Preso, Piko, Sipa, Turumpo, and many others, are still played daily in neighborhoods.

Explanation:

Hope this helps... Maybe

7. A 77 kg girl and a 62 kg boy face each other on friction free roller skates. The girl pushes the boy, who moves away at a speed of 2.5 m/s. What is the girl's speed? ​

Answers

Answer:

[tex]\sf\longmapsto \: 2.0m/s[/tex]

Explanation:

Initial momentum = 0

[tex]\sf\longmapsto \: 77 \: velocity + 62 \times 2.5 = 0[/tex]

[tex]\sf\longmapsto \: 77 \: velocity = - 155[/tex]

[tex]\sf\longmapsto \: velocity = \frac{ - 155}{77} [/tex]

[tex]\sf\longmapsto \: \: velocity = - 2.012[/tex]

[tex]\sf\longmapsto \: 2.0 \: m/ s[/tex]


Assuming that the slug's body is 3% salt, what is the most likely prediction that would result from placing the slug into a 6% salt solution?

Answers

Answer: As i know, please see the Explanation

Explanation:The cell contains 3% salt, so we can safely assume that it contains 100%−3%=97% water.

A 5.0 kg cannonball is fired horizontally at 68 m/s from a 15-m-high cliff. A strong tailwind exerts a constant 12 N horizontal force in the direction the cannonball is traveling. What is the extra distance (d)?

Answers

Answer:

3.7 m

Explanation:

ASSUMING this means extra distance beyond where the cannonball would land WITHOUT the wind assistance but in general ignoring air resistance. Hmmmmmm...tricky

The ball drops from vertical rest to ASSUMED horizontal ground 15 m below in a time of

t = √ (2h/g) = √(2(15)/9.8) = 1.75 s

Without the tail wind, the ball travels horizontally

d = vt = 68(1.75) = 119 m

The tailwind exerts a constant acceleration on the ball of

a = F/m = 12/5.0 = 2.4 m/s²

The average horizontal velocity during the flight is

v(avg) = (68 + (68 + 2.4(1.75)) / 2 = 70.1 m/s

so the distance with tailwind is

d = v(avg)t = 70.1(1.75) = 122.675 m

The extra distance is 122.675 - 119 = 3.675 = 3.7 m

Please help with this diagram as soon as possible.

Answers

This is the answer .....

Un hamster fait tourner sa cage de 27cm de diamètre a raison de 14tours par minute .quel est le module de l accélération centripète d un morceau de nourriture collé sur la paroi extérieure de la cage ?

Answers

Answer:

Explanation:

a_c = ω²R

14 rev/min (2π rad/rev)(1 min/60 s) = 1.466 rad/s

a_c = 1.466²(0.27/2)

a_c = 0.29 m/s²

Le hamster est lent

A strong magnetic field surrounds Earth. How does Earth’s magnetic field help humans?

Answers

Answer:

it deflects most of the solar wind, whose charged particles would otherwise strip away the ozone layer that protects the Earth from harmful ultraviolet radiation

Why do you think some things float and some things sink?

Answers

because somethings carry meaning into life and other things are useless information that take up unnecessary space
some things are heavier and some things are lighter.

As an airplane leaves the runway and goes into the air, has acceleration occurred?

a
Yes, the plane changed direction.

b
No, the speed is not mentioned.

c
Not enough information.

d
No, acceleration does not include going in an upwards direction.

Answers

A, yes because the plane is using air resistance and acceleration is increasing while it goes up. Although you don’t know speed, still yes.

một viên đạn được bắn lên với vận tốc v0=800m/s theo phương hợp với mặt phẳng nằm ngang một góc 30 độ. xác định tầm xa của viên đạn

Answers

Step 1 First Draw a Diagram.

 

Step 2 Identify the givens

 

g= -9.8 m/sec2

x0 = 0 m

Y-Yo= 80m

V0 = 800m/s -30o inclined from horizontal

Xf= ?

t = ?

Step 3  * A 2 dimensional problem so break it down into x component and y component

 

 

Step 4   x component  

 

x= [Vox ][cos 30o][t]

x= [800m/s][cos 30o][tsec]

x=[692.8m/s][tsec]       <---------------Need t

 

Step 5 y component

 

 

Y-Yo= Voy - 1/2gt2

80m= -[v][sin30o][t] -1/2gt2

1/2gt2+[v][sin30o][t]+80m=0   <-------Form Quadratic Equation

Solve for t

 

t=   -[v sin 30]  +/-   [(v sin 30)-(4)(1/2)(9.8)(80)]1/2

                      (2)(1/2)(9.8)

 

t= 400+/- 398

        9.8

t= 0.2 sec

 

 

Step 6 Plug this into initial x component equation

 

x=[692.8m/s][tsec]

PLz help Asap 10 POINT
I MIGHT GIVE BRAINLIST IF RIGHT AND IF I CAN.

Answers

Answer:

Mars has a thin atmosphere

Explanation:

Okay, so this is going to sound crazy but bare with me. Mar's atmosphere is thin. There is little to no gravitational pull for the atmosphere to stay. Also, no, humans will not be able to live on Mars because the atmosphere, quite literally, contains 1% oxygen. Hopefully this helps! Earth's is thick because of the gravitational pull and gases in Earth's surface.

Help me with this please

Answers

Answer:

for the secound one i think it would be 45.87 let me know if this is wrong I love to get my feed back

Explanation:

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