The parking brake on a 1200kg automobile has broken, and the vehicle has reached a momentum of 7800kg.m/s. What is the velocity of the vehicle?

Answers

Answer 1

Answer:

Velocity of the vehicle (v) = 6.5 m/s

Explanation:

Mass of automobile (m) = 1200 kg

Momentum of vehicle (p) = 7800 kg m/s

By using formula of momentum:

[tex] \rm p = mv \\ \rm 7800 = 1200 \times v \\ \rm v = \frac{7800}{1200} \\ \rm v = 6.5 \: m {s}^{ - 1} [/tex]


Related Questions

A baseball player at practice is pushing a tackling dummy across the field. He initially has to push the 130 kg dummy with 600 Newton’s of force to get it to start moving and maintain a force of 475 to keep it moving at a steady state. What are the coefficient of friction static and kinetic with the dummy on the ground
.

Answers

Answer:

Static= 600/(130*9.8)=0.47

Kinetic=475/(130*9.8)=0.37

I need help!
A car has a mass of 1,200 kg and the road can provide a maximum force of 24 kN on the car what is the maximum acceleration?

Answers

Answer:

The acceleration of the car with the mass of 1200kg and a force of 11 × 10³N is 9.17m/s²

Explanation:

what is volume help plz

Answers

Answer:

Explanation:

Volume = Length x width x height

Multiply the length, width and, height to get the volume of the question.

What is the sum of 130+125+191? A. 335. B. 456. C. 446. D. 426.
If we minus 712 from 1500, how much do we get? A. 788. B. 778. C. 768. D. 758.
50 times of 8 is equal to: A. 80. B. 400. C. 800. D. 4000.
110 divided by 10 is: A. 11. B. 10. C. 5. D. None of these.
FRIEND ME!!!

Answers

1. C- 446
2. A- 778
3. B- 400
4. A- 11

A log has a density of. 8 g/cmÂł. What will happen to this log in freshwater, which has a density of 1. 0 g/cmÂł? It will sink. It will float. It will move deeper. It will decrease in density.

Answers

When a log of wood is put over the freshwater, the log start to float. Option B is correct.

Density:

It can be defined as the amount of substance per unit volume. It is usually denoted by D. It is measured in the [tex]\bold { kg/m^3}[/tex].

The less dense object always floats over the more dense substance.

For example- Here, The density of the log is 0.8 [tex]\bold{ cm^3}[/tex] and the density of the of water is 1.0 [tex]\bold{ cm^3}[/tex] .

Since, the density of the log is lesser than the density of the water.

Therefore, when a log of wood is put over the freshwater, the log start to float.

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Write any three facts in the support of molecular theory

Answers

Answer:

Every gas is made up of very small particles called molecules. Molecules of a gas are separated from each other by large distances so that volume is negligible as compared to total volume of gas. The force of gravitation on the molecules is also negligible.

Hope that helps. x

:

Jacob has a disk that sinks to the bottom when placed in a vessel of water. He cuts some holes in the disk and immerses it again in a vessel of water. Which of these is likely to happen?

Answers

Answer:

it will float up cause its has gravity

When Jacob cuts some holes in the disk and immerses it again in a vessel of water it will now float at the top. Thus, the correct option for this question is A.

Why does an object float at the top of the water?

An object floats when the weight force on the object is balanced by the upward push of the water on the object. The upwards push of the water increases with the volume of the object that is underwater. It is not affected by the depth of the water or the amount of water.

According to the context of this question, when a disk does not have holes in it, it will definitely sink to the bottom of the water because it has high density, but when the hole is made in the disk, the water is passed out from them and now, the upward force is minimized that cause less density as compared to previous.

Therefore, when Jacob cuts some holes in the disk and immerses it again in a vessel of water it will now float at the top. Thus, the correct option for this question is A.

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A 1500 kg car travels 50 m north in 20 seconds. What is the magnitude of the average velocity of the car during the 20 second interval?
a. 2.5 m/s
b. 5.0 m/s
c. 6.5 m/s
d. 7.0 m/s

Answers

Answer:

a. 2.5 m/s

Explanation:

50 / 20 = 2.5 m/s

what happens to light when it travels from air into water

Answers

Answer:

Water is more dense than air. When water goes through a denser thing, the light is "bent" more towards the "normal" which is a straight, vertical line.

Follow me on  i n s t a g r a m, message me and I'll follow you back: ifaulkner24

Do I look good yes or no

Answers

Answer:

0/10

Explanation:

_--------------------

Answer:

No. -infinity/10

Explanation:

Ew. Just why, like no.

I need help with this physics question

Answers

Answer:

its B hope you have a good Day

A 3-column table with 1 row. The first column titled distance travelled (meters) has entry 6. 1. The second column labeled lower track elapsed time (seconds) has entry 4. 92. The third column labeled higher track elapsed time (seconds) has entry 3. 36. Based on the time measurements in the table, what can be said about the speed of the car on the lower track as compared to the higher track? How can the reasoning for the above answer be best explained? On the higher track, the elapsed time is. Calculate speeds for each track. How much faster was the car on the higher track than the lower track?.

Answers

Answer:

B,A,A

Explanation:

Answer:

Other guy is correct b,a,a

Explanation:


[tex] \huge \rm༆ question ༄[/tex]


Calculus proof of second equation of motion ~ ​

Answers

Newton's second equation of motion :-

S=ut+1/2at^2 [where, u is the initial velocity, a is the acceleration and t is the time interval]

This Equation simply finds a relation between distance travelled by a particle (classically) under uniform acceleration.

So let's see what pieces of information (bundles of equations) do we have with us, initially.

We have, a very primary equation with us,

dS/dt = v… (I)

(Considering motion in a straight line only)

And we also have the equation

dv/dt = a…(II)

Simply replacing the v in eqn (II) by eqn (I), we find

d2S/dt^2 = a…(III)

This is what we need to solve. It's easy.

You know,

d2S/dt^2 = d/dt(dS/dt) = a

⟹ dS/dt = ∫adt = at+c1

Since, dS/dt is the velocity of the particle,

Therefore, at t = 0, dS/dt|t = 0 = u

⟹ u = a∗0 + c1 = c1

⟹ c1 = u

Therefore, dS/dt = u + at

Thus, S = ∫(udt + atdt)

⟹ S = ut + 1/2at^2 +c^2

If say, the particle is already having a displacement S0 the moment you start measuring it's motion. Then, at t = 0, S = S0

This makes S = S0 +ut + 1/2at^2

Since, in most of the practical cases, we start measuring a motion when the particle starts displacing (i.e., when S0=0 ),

We get

S = ut + 1/2at^2

Hope it helps :)

desventajas de la fricción cinética

Answers

Answer:

Please translate this into Spanish! Sorry I can't :(

Explanation:

Disadvantages of Friction:

Friction produces unnecessary heat leading to the wastage of energy.

The force of friction acts in the opposite direction of motion, so friction slows down the motion of moving objects.

Forest fires are caused due to the friction between tree branches.

explain the difference between vector and scalar quantities

Answers

Answer:

vector quantity have both magnitude and direction but scalar quantities have only magnitude

A 300 g ball swings in a vertical circle at the end of a 1.3-m-long string. When the ball is at the bottom of the circle, the tension in the string is 13 N.
What is the speed of the ball at that point?

Answers

Answer:

0.23N for the speed

at the bottom of the circle

During chemical reactions, bonds between atoms break and form. What does this mean in terms of subatomic particles? (1 point)
O Electrical fields of charged particles interact, bonding those with the same charge.
Electrical fields of neutral particles interact, bonding those with opposite charges.
O Electrical fields of neutral particles interact, bonding those with the same charge.
o Electrical fields of charged particles interact, bonding those with opposite charges

Answers

During chemical reactions, bonds between atoms break and form Electrical fields of charged particles interact, bonding those with opposite charges.

What is the chemical bonds?

During chemical reactions, bonds between atoms break and form Electrical fields of charged particles interact, bonding those with opposite charges.

Since we know that every element have electrons in their atoms and every atom have vacant shells.

So during chemical reactions the elements fulfill their vacant shells and form bonds between each other it can be ionic or it can be covalent bond.

But when atoms breaks the bond their will be the positively or negatively charged electrons left in the atoms.

Hence During chemical reactions, bonds between atoms break and form Electrical fields of charged particles interact, bonding those with opposite charges.

To know more about chemical bonds follow

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When a squid pushes against the water, the squid moves forward because the

______________ pushes against the _______________.​

Answers

Answer:

water pushes against the squid

A gas in a closed container is heated with 10J of energy, causing the lid of the container to rise 2m with 3N of force. What is the total change in energy of the system

Answers

Explanation:

For this problem, use the first law of thermodynamics. The change in energy equals the increase in heat energy minus the work done.

ΔU=Q−W

We are not given a value for work, but we can solve for it using the force and distance. Work is the product of force and displacement.

W=FΔx

W=3N×2m

W=6J

Now that we have the value of work done and the value for heat added, we can solve for the total change in energy.

ΔU=Q−W

ΔU=10J−6J

ΔU=4J

Answer is 4J

i think this may help you very much

pls help me, its just fill in the blank

Answers

1. Frequency

2. Reflected

3. Absorbed

4. Black

1. Three students are using sports equipment to model the relative motion of
Earth, the moon and the sun.
A. Identify which ball would be used to model the Sun, Earth and the Moo
B. Describe the relative (in relation to each other) motions of these bodies

Answers

The basketball would be sun then baseball earth and finally golf ball moon.

Answer:

The golf ball would be revolving around the baseball while the baseball would be revolving around the basketball.

Explanation:

The basketball would be represented as the Sun, the baseball would be represented as the Earth and the golf ball would be represented as the moon. Since the Moon revolves around the Earth and the Earth revolving around the Sun makes a perfect explaination for this question.

An object, initially at rest, moves 475 m in 19 s. What is its acceleration? *

Answers

u=0s=475mt=19s

[tex]\\ \sf\Rrightarrow s=ut+\dfrac{1}{2}at^2[/tex]

[tex]\\ \sf\Rrightarrow s=0(19)+\dfrac{1}{2}a(19)^2[/tex]

[tex]\\ \sf\Rrightarrow 475=\dfrac{361a}{2}[/tex]

[tex]\\ \sf\Rrightarrow 950=361a[/tex]

[tex]\\ \sf\Rrightarrow a\approx 2.3m/s^2[/tex]

An object is dropped from a 42 m tall building. How long does it take to reach the ground?

Answers

Answer:

2.1 seconds

Explanation:

let D represent the height in meters

let g represent gravity in meters per second squared

let t represent time in seconds

D= -42 meters (negative because it falls down)

g= -9.8m/s^2

t= [tex]\frac{-42 meters}{9.8 m/s^2}[/tex]

this gives t= 4.2857 s^2

the meter units cancel out in the division

now we must simplify the units to singular seconds so...

[tex]\sqrt{4.3 s^{2} }[/tex] which simplifies to [tex]\sqrt{4.3}[/tex] x [tex]\sqrt{s^{2} }[/tex]

this equals 2.1 seconds

A boxer throws a punch with a force of 1,400 N that lasts 0.02 s. What is the impulse of this punch? (1 point) 28 kg⋅m/s 28 kilograms times meters per second 280 kg⋅m/s 280 kilograms times meters per second 70,000 kg⋅m/s 70,000 kilograms times meters per second 7,000 kg⋅m/s

Answers

The impulse of the boxers punch is 28 kgm/s.

The given parameters;

applied force by the boxer, F = 1400 Ntime of force action, t = 0.02 s

The impulse of the boxers punch is calculated as follows;

[tex]J = Ft[/tex]

where;

F is the applied force (N)t is the time of force action (s)

The magnitude of the impulse is calculated as follows;

[tex]J = 1400 \times 0.02 \\\\J = 28 \ kg m/s[/tex]

Thus, the impulse of the boxers punch is 28 kgm/s.

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‍12/3/21 A wave in the ocean has a wavelength of 24 m and a frequency of 8 Hz,What is the wave's speed?

Answers

Answer:

192 m/s

Explanation:

The speed of the wave given only it's frequency and wavelength can be found by using the formula

[tex]c = f \times \lambda[/tex]

where

c is the velocity of the wave in m/s

[tex] \lambda[/tex] is the wavelength in m

f is the frequency in Hz

From the question we have

c = 8 × 24 = 192

We have the final answer as

192 m/s

Hope this helps you

What is the relationship between momentum and speed?

Answers

Answer:

Momentum is directly proportional to the object's mass and also its velocity.

Explanation:

Thus the greater an object's mass or the greater its velocity, the greater its momentum. Momentum p is a vector having the same direction as the velocity v.

A(n) 1700 kg car is moving along a level road at 21 m/s. The driver accelerates, and in the next 10 s the engine provides 22000 J of additional energy. If 3666.67 J of this energy must be used to overcome friction, what is the final speed of the car

Answers

The final speed of the car at the given conditions is 30.1 m/s.

The given parameters:

Mass of the car, m = 1700 kgVelocity of the car, v = 21 m/sTime of motion, t = 10 sAdditional energy provided by the engine, E₁ = 22,000 JEnergy used in overcoming friction, E₂ = 3,666.67 J

The change in the energy applied to the car is calculated as;

[tex]\Delta E = E_1 - E_2\\\\\Delta E = 22,000 \ J \ - \ 3,666.67 \ J\\\\\Delta E = 18,333.33 \ J[/tex]

The final speed of the car is calculated as follows;

[tex]\Delta E = \frac{1}{2} m(v_f^2 - v_0^2)\\\\v_f^2 - v_0^2 = \frac{2\Delta E}{m} \\\\v_f^2 = \frac{2\Delta E}{m} + v_0^2\\\\v_f = \sqrt{ \frac{2\Delta E}{m} + v_0^2} \\\\v_f = \sqrt{ \frac{2\times 18,333.4}{1700} + (21)^2} \\\\v_f = 30.1 \ m/s[/tex]

Thus, the final speed of the car at the given conditions is 30.1 m/s.

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A car which is traveling at a velocity of 27 m/s undergoes an acceleration of 5.5 m/s^2 over a distance of 430 m. How fast is it going after that acceleration?

Answers

73.9m/s (1dp)

1) list everything that you are given using suvat, where s is distance, u is initial velocity(speed), v is final velocity(speed), a is acceleration and t is time

s = 430m

u = 27 m/s

v = ? (we need to work out)

a = 5.5m/s^2

t = (we are not given this value)

2) use an equation that doesn't involve the time

[tex] {v}^{2} = u {}^{2} + 2as[/tex]

3) input the values that we have

[tex] {v}^{2} = ( {27})^{2} + 2(5.5)(430)[/tex]

[tex]v {}^{2} = 5459[/tex]

[tex]v = \sqrt{5459} = 73.9[/tex]

so the answer is 73.9m/s to 1dp

PLEASEE IS FOR A TEST!!!Which ionic compound is BOTH correctly written and named??
A mg0 magnesium oxide
B Mn02 manganese oxide
C N02 nitrogen oxide
D SrBr strontium bromide

Answers

Answer:

Letter A

Explanation:

Manganese dioxide- Mn02

Nitrogen Dioxide- n02

Strontium bromide- SrBr

A car weighing 8000N is traveling at 45 m/s on a perfectly flat, frictionless road. If the driver slams on the brakes, how far will thw car slide before it comes to a stop?

Answers

Without friction, the car cannot stop...

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