The original price of a camera was $50 and the sale price this week is $38. What is the percent of change in the price
of the camera?
A.24% B. 12% C.20% D.25%

Answers

Answer 1

Answer:

24%

Step-by-step explanation:

x (original price) = 50$

y (sale price) = 38$

p (percentage) = ?

p = (x - y) / x

p = (50-38) / 50

p = 12/50

p = 0.24

p = 24%

Answer 2

Answer:

24%

Step-by-step explanation:

i did it in my head


Related Questions

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t) = -4.9t^2 + 148 t + 227. Assuming that the rocket will splash down into the ocean, at what time does splashdown occur? The rocket splashes down after 32 seconds. How high above sea-level does the rocket get at its peak? The rocket peaks at meters above sea-level.

Answers

Answer:

A.) 24.08 seconds

B.) 825.42 metres

Step-by-step explanation:

function of time is given as

h ( t ) = − 4.9 t 2 + 118 t + 115 .

Where a = -4.9, b = 118, c = 115

Let's assume that the trajectory of the rocket is a perfect parabola.

The time t the rocket will reach its maximum height will be at the symmetry of the parabola.

t = -b/2a

Substitute b and a into the formula

t = -118/-2(4.9)

t = 118/9.8

t = 12.041 seconds

Since NASA launches the rocket at t = 0 seconds, the time it will splash down into the ocean will be 2t.

2t = 2 × 12.041 = 24.08 seconds

Therefore, the rocket splashes down after 24.08 seconds.

B.) At maximum height, time t = 12.041s

Substitute t for 12.041 in the function

h ( t ) = − 4.9 t 2 + 118 t + 115

h(t) = -4.9(12.041)^2 + 118(12.041) + 115

h(t) = -4.9(144.98) + 118(12.041) + 115

h(t) = -710.402 + 1420.82 + 115

h(t) = 825.42 metres

Therefore, the rocket get to the peak at 825.42 metres

Point G ia on line segment FH Given FG = 5x + 2 GH = 3x -1 and FH = 9 determine the numerical length of FG

Answers

Answer:

Step-by-step explanation:

FG=7

The table shown below displays the distance that students on a track team walked during after-school practice.
Student
Distance (Miles)
John
2.75
Paul
2
Sierra
1.4
Anastasia
31
What was the total distance, in miles, that the students walked during after-school practice?

Answers

The total distance should be: 37.15 miles

Explanation:

You just add all of the distances together:
• 2.75 + 2 + 1.4 + 31= 37.15 miles


Anastasia's distance is much different than the others so in case you meant to put 3.1 here is the answer to that:
• 2.75 + 2 + 1.4 + 3.1= 9.25 miles

help please i’ll thank you

Answers

So first, we must figure out how many dollars = pesos

1 United States Dollar equals

22.38 Mexican Peso

With this, we convert the Dollars from the math problem, to the pesos in the math problem, which is done for us. So we have to figure out how much pesos equal a dollar.

510 Mexican Peso equals

22.80 United States Dollar

In the diagram of circle A, what is the measure of
ZXYZ?
35°
70°
75°
140°

Answers

Using the intersecting secant theorem:

Angle xyz = 1/2( wz- XX)

Xyz = 1/2(175-105)

Xyz = 1/2(70)

Xyz= 35

The answer is 35 degrees

The measure of <XYZ is 35 degrees

Circle geometry

To find the measure of<XYZ, we will use the expression as shown below:

The angle at the vertex is half the difference of the intercepted arcs

<XYZ = 1/2(175 - 105)

<XYZ = 1/2(70)
<XYZ = 35 degrees

Hence the measure of <XYZ is 35 degrees

Learn more on geometry here: https://brainly.com/question/24375372

Determine the measure of each angle. Then describe each angle as acute, right, obtuse, or straight.

Answers

I think it was meant for paper you need to be able too mesure this

5.1436 rounded to the nearest tenth

Answers

Answer:

5.1

Step-by-step explanation:

we have

5.1436

since 4 is less than five we cannot pass the 1 to 2

so it stays like

5.1

What is the translation for this graph? O (X-4, Y-3)
O (X-3. y - 4)
O (X-3. y. 4)
O (X- 4. y-3)

Answers

Answer:

wow dis might take a while to solve

12x+12=13x−12 how many sultions

Answers

.....................................................................................................................................................................................................................................................................

evaluate each expression. (1/3)^4

Answers

Answer:

1/81

Step-by-step explanation:

[tex] \huge \bigg( \frac{1}{3} \bigg)^{4} = \frac{1}{ {3}^{4} } = \frac{1}{81} \\ [/tex]

A small pebble has a mass of
about
20 L
b.
20 ml
20 g
20 kg
d.

Answers

Answer:

20g

since mass should be in kg or gram if small then g

What is one equivalent ratio for 1/3

Answers

Answer: 2/6

Step-by-step explanation:

Answer:

[tex]\frac{2}{6}[/tex]

Step-by-step explanation:

In order to create an equal ratio to [tex]\frac{1}{3}[/tex], we need to find a constant to multiply both the numerator and the denominator by.

Let's do 2.

[tex]1\cdot 2 = 2\\\\3\cdot 2 = 6\\\\[/tex]

So:

[tex]\frac{2}{6}[/tex]

Hope this helped!

The reciprocal of 2 4/7 is? a. 7/18 b. 1/2 c. 18/7 d.7/8

Answers

[tex]\text{Hello! :)}[/tex]

[tex]\large\boxed{A. 7 / 18}[/tex]

[tex]\text{Convert 2 4/7 into an improper fraction:}\\\\2*7 + 4 = 18 \\\\\text{(To find the numerator of the fraction)}\\\\\text{Fraction in improper form: 18/7}\\\\\text{Reciprocal of fraction: Swap numerator and denominator:}\\\\18/7 \text{ becomes } 7 / 18[/tex]

compare these numbers

Answers

Answer:

  [tex]-3.97621,\ -2.5,\ 2\frac{1}{4},\ \sqrt{11},\ 3.\overline{6}[/tex]

Step-by-step explanation:

√11 is about 3.32.

Smallest-to-largest, the numbers are ...

  [tex]-3.97621,\ -2.5,\ 2\frac{1}{4},\ \sqrt{11},\ 3.\overline{6}[/tex]

One of the most spectacular and least known hummingbirds is the Marvelous Spatuletail, Loddigesia mirabilis, found in only in a single remote valley in northern Peru (see photo below). In this valley the mean density is 3 spatuletails per 100-hectare quadrat. (a) What is the probability a random quadrat contains less than 3 spatuletails

Answers

Answer:

P(x < 3) = 0.42319

Step-by-step explanation:

From the given information:

The mean density [tex]\lambda =[/tex] 3

Let x be the random variable that follows a Poisson distribution.

Therefore:

[tex]\mathtt{P(x) = \dfrac{e^{-\lambda} \lambda ^x}{x!}}[/tex]     for x =1, 2, 3...

However, the probability that a random quadrat contains less than 3 spatuletails can be computed as:

[tex]\mathtt{P(x <3 ) = \dfrac{e^{-3}3 ^0}{0!}+ \dfrac{e^{-3}3 ^1}{1!}+ \dfrac{e^{-3} 3 ^2}{2!} }[/tex]

[tex]\mathtt{P(x <3 ) =e^{-3} \begin{pmatrix} \dfrac{3 ^0}{0!}+ \dfrac{3 ^1}{1!}+ \dfrac{3 ^2}{2!} \end {pmatrix} }[/tex]

[tex]\mathtt{P(x <3 ) =e^{-3} \begin{pmatrix} \dfrac{1}{1}+ \dfrac{3 }{1}+ \dfrac{9}{2} \end {pmatrix} }[/tex]

[tex]\mathtt{P(x <3 ) =e^{-3} \begin{pmatrix} 1+3+ 4.5 \end {pmatrix} }[/tex]

[tex]\mathtt{P(x <3 ) =e^{-3} \begin{pmatrix}8.5 \end {pmatrix} }[/tex]

P(x < 3) = 0.42319

Find the x-intercept of the graph of the linear equation y = -1/2 x+3.
Help me please!!
Due soon!!

Answers

(6,0) that’s the right answer

Answer:

6

Step-by-step explanation:

got it right

An investigator compares the durability of two different compounds used in the manufacture of a certain automobile brake lining. A sample of 71 brakes using Compound 1 yields an average brake life of 41,628 miles. A sample of 31 brakes using Compound 2 yields an average brake life of 36,379 miles. Assume the standard deviation of brake life is known to be 4934 miles for brakes made with Compound 1 and 4180 miles for brakes made with Compound 2. Determine the 98% confidence interval for the true difference between average lifetimes for brakes using Compound 1 and brakes using Compound 2. Step 1 of 2 : Find the critical value that should be used in constructing the confidence interval.

Answers

Answer:

98%  Confidencce Interval is ( 3030.6, 7467.4 )

Step-by-step explanation:

Given that:

Sample size [tex]n_1 =[/tex] 71

Sample size [tex]n_2 =[/tex] 31

Sample mean [tex]\overline x_1 =[/tex] 41628

Sample mean [tex]x_2 =[/tex] 36,379

Population standard deviation [tex]\sigma_1[/tex] = 4934

Population standard deviation [tex]\sigma_2 =[/tex] 4180

At 98% confidence interval level, the level of significcance = 1 - 0.98 = 0.02

Critical value at [tex]z_{0.02/2} = 2.33[/tex]

The Margin of Error = [tex]z \times \sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma^2_2}{n_2} }[/tex]

= [tex]2.33 \times \sqrt{\dfrac{4934^2}{71}+\dfrac{4180^2}{31} }[/tex]

= [tex]2.33 \times \sqrt{\dfrac{24344356}{71}+\dfrac{17472400}{31} }[/tex]

= [tex]2.33 \times \sqrt{906504.06 }[/tex]

= 2218.40

The Lower limit = [tex]( \overline x_1 - \overline x_2) - (Margin \ of \ error)[/tex]

= ( 41628 - 36379 ) - ( 2218.40)

= 5249 - 2218.40

= 3030.6

The upper limit = [tex]( \overline x_1 - \overline x_2) + (Margin \ of \ error)[/tex]

= ( 41628 - 36379 ) + ( 2218.40)

= 5249 + 2218.40

= 7467.4

∴  98%  Confidencce Interval is ( 3030.6, 7467.4 )

Solve 5x - (2x - 1) = 2, Answer is a decimal round to the hundredth (2 digits) or use / for fraction bar.

Answers

5x - (2x - 1) = 2

Distribute the - sign.

5x - 2x + 1 = 2

Combine like terms.

3x + 1 = 2

Subtract 1 from both sides.

3x = 1

Divide both sides by 3

x = 1/3 or 0.33

What is the value of -3.5

Answers

Answer:

[tex]3.5[/tex]

Step-by-step explanation:

The value of [tex]|-3.5|[/tex] is [tex]3.5[/tex], because you have [tex]|-3.5|[/tex] and it will change to [tex]3.5[/tex] by the absolute value, which it turned from negative to a positive.

A store offers customers a 40% discount on the price of x of selected items. Then, the store takes off an additional 16% at the cash register. Write a price function P(x) that computes the final price of the item in terms of the original price x.

P(x) = ?

Answers

Answer:

x-40%-16%

Step-by-step explanation:

Solve the equation t+ 25 =26

Answers

Answer:

t = 1

Step-by-step explanation:

t + 25 = 26

Subtract 25 from each side

t = 1

Peter leaves Mitchell's house traveling 30 mph. Mitchell leaves 15 min later, trying to catch up to peter, going 40 mph. if they drive along the same route, how long will it take Mitchell to catch Peter?

Answers

Answer:

  45 minutes

Step-by-step explanation:

At 30 mph for 1/4 hour, Peter has a 7.5 mile head start. After he leaves, Mitchell closes that gap at the rate of 40-30 = 10 miles per hour. It will take him ...

  t = d/s

  t = (7.5 mi)/(10 mi/h) = 0.75 h

to catch Peter.

Mitchell will catch Peter in 45 minutes.

__

Alternate Solution

Another way to look at it is that Mitchell's 10 mph advantage is 1/3 of Peter's speed, so it will take 1/(1/3) = 3 times the period of Peter's head start:

  3 × 15 minutes = 45 minutes . . . for Mitchell to catch Peter

_____

You can write equations involving time and distance and see where the distances traveled become the same. You need to be careful choosing the time reference, since you're concerned with Mitchell's travel time. I personally prefer to work "head start" problems by considering the differences in time and speed, as above. This is where you end up using the equations approach, anyway.

Aaron is a high school graduate working as a retail clerk. He earns a median salary for a high school graduate. Aaron is thinking about going to college to get an associate's degree. If he completes his degree in 2 years and college costs total $30,000, how long will it take Aaron to recover his investment, assuming that he earns the median salary and continues to work full time while he is attending school? A graph titled Median Annual Household Income by Educational Attainment of Householder, 1997. Professional degree, 92,228 dollars; doctorate degree, 87,232 dollars; master's degree, 68,115 dollars; Bachelor's degree or more, 63,292 dollars; Bachelor's degree, 59,048 dollars; associate degree, 45,258 dollars; some college, no degree, 40,015 dollars; high school graduate, 33,779 dollars; ninth to twelfth grade, 19,851 dollars; than twelfth grade, 15,541 dollars. a. about 2.5 years b. about 5.5 years c. about 8.5 years d. about 11.5 years

Answers

Answer:

i would say c

Step-by-step explanation:

Given f(x)=3x-1 find f(-1)

Answers

Answer:

f( - 1) = - 4

Step-by-step explanation:

f(x) = 3x - 1

To find f(-1) substitute the value of x that's

- 1 into f(x). That's for every x in f(x) replace it with - 1 and solve

That's

f( - 1) = 3(-1) - 1

= - 3 - 1

We have the final answer as

f(-1) = - 4

Hope this helps you

whats - 1/64 as cubed

Answers

Answer: 1/4

Step-by-step explanation:

Find the first partial derivatives of the function f(x,y,z)=4xsin(y−z)

Answers

Answer:

[tex]f_x(x,y,z)=4\sin (y-z)[/tex]

[tex]f_x(x,y,z)=4x\cos (y-z)[/tex]

[tex]f_z(x,y,z)=-4x\cos (y-z)[/tex]

Step-by-step explanation:

The given function is

[tex]f(x,y,z)=4x\sin (y-z)[/tex]

We need to find first partial derivatives of the function.

Differentiate partially w.r.t. x and y, z are constants.

[tex]f_x(x,y,z)=4(1)\sin (y-z)[/tex]

[tex]f_x(x,y,z)=4\sin (y-z)[/tex]

Differentiate partially w.r.t. y and x, z are constants.

[tex]f_y(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial y}(y-z)[/tex]

[tex]f_y(x,y,z)=4x\cos (y-z)[/tex]

Differentiate partially w.r.t. z and x, y are constants.

[tex]f_z(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial z}(y-z)[/tex]

[tex]f_z(x,y,z)=4x\cos (y-z)(-1)[/tex]

[tex]f_z(x,y,z)=-4x\cos (y-z)[/tex]

Therefore, the first partial derivatives of the function are [tex]f_x(x,y,z)=4\sin (y-z), f_x(x,y,z)=4x\cos (y-z)\text{ and }f_z(x,y,z)=-4x\cos (y-z)[/tex].

Which one of these shapes is not like the other and why?

Answers

A and B is not, because if you were to make the A bigger it'll be the same as B, so I think is C

How hard is 6th grade math?

Answers

Answer:

super easy i can help you whenever

Step-by-step explanation:

im in high and i had As in 6th

Answer:

a little hard you just have to understand it

Step-by-step explanation:

help me please. 15 POINTS BRAINLEST ANSWER EVER (y+4)–(y–1)=6y

Answers

Answer:

5/6

Step-by-step explanation:

y+4-y+1=6y

5=6y

y=5/6

Solution for (y+4)-(y-1)=6y equation:

Simplifying

(y + 4) + -1(y + -1) = 6y

Reorder the terms:

(4 + y) + -1(y + -1) = 6y

Remove parenthesis around (4 + y)

4 + y + -1(y + -1) = 6y

Reorder the terms:

4 + y + -1(-1 + y) = 6y

4 + y + (-1 * -1 + y * -1) = 6y

4 + y + (1 + -1y) = 6y

Reorder the terms:

4 + 1 + y + -1y = 6y

Combine like terms: 4 + 1 = 5

5 + y + -1y = 6y

Combine like terms: y + -1y = 0

5 + 0 = 6y

5 = 6y

Solving5 = 6y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6y' to each side of the equation.

5 + -6y = 6y + -6y

Combine like terms: 6y + -6y = 0

5 + -6y = 0

Add '-5' to each side of the equation.

5 + -5 + -6y = 0 + -5

Combine like terms: 5 + -5 = 0

0 + -6y = 0 + -5

-6y = 0 + -5

Combine like terms: 0 + -5 = -5

-6y = -5

Divide each side by '-6'.

y = 0.8333333333

Simplifying

y = 0.8333333333

Crude oil Imports to one country from another for 2009-2013 could be approximated by the following model where t is time in years since the start of 2000,
(1) --33428001 - 1,000 thousand barrels per day (9 st s 13)
According to the model, approximately when were oil imports to the country greatest? HINT (See Example 1) (Round your answer to two decimal places.)
How many barrels per day were imported at that time? (Round your answer to two significant digits.)
thousand barrels

Answers

Answer:

Time = approximately mid 2012Oil import rate = 3600 barrels

Step-by-step explanation:

Unclear part of the questionI(t) = −35t² + 800t − 1,000 thousand barrels per day (9 ≤ t ≤ 13) According to the model, approximately when were oil imports to the country greatest?  t =  ? Solution

Given the quadratic function  

The vertex of a quadratic function is found by a formula: x = -b/2a

As per given function:

b = 800, a = -35

Then

t = - 800/2*(-35) = 11.43 which is within given range of 9 ≤ t ≤ 13

This time is approximately mid 2012.

Considering this in the function, to get oil import rate for the same time:

l(11.43) = -35*(11.43)² + 800*11.43 - 1000 = 3571.4285

Rounded to two significant figures, the greatest oil import rate was:

3600 barrels

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