The octal numeral system is a base 8 positional system that uses the symbols 0,1,2,3,4,5,6,7. Write each base 8 number as a base 10 number. 12 and 117

Answers

Answer 1

Step-by-step explanation:

(12) in base 8

= (1 * 8¹ + 2 * 8⁰) in base 10

= (8 + 2) in base 10

= 10 in base 10.

(117) in base 8

= (1 * 8² + 1 * 8¹ + 7 * 8⁰) in base 10

= (64 + 8 + 7) in base 10

= 79 in base 10.

Answer 2

Using octal numeral system, 12₈ number as 10₁₀ and (117)₈ number as (79)₁₀.

What is octal numeral system?

Octal numeral system has "a base of 8 and uses the number from 0 to 7".

According to the question,

a) (12)₈

          = (1 * 8¹ + 2 * 8⁰)₁₀

          = (8 + 2)₁₀

          = 10₁₀.

b) (117)₈

        = (1 * 8² + 1 * 8¹ + 7 * 8⁰)₁₀

        = (64 + 8 + 7)₁₀

        = (79)₁₀

Hence, using octal numeral system, 12₈ number as 10₁₀ and (117)₈ number as (79)₁₀.

Learn more about octal numeral system here

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Related Questions

The sum of two numbers is 51 and the greater number is twice the smaller number. Find the numbers.
a) set up the variables
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Answers

Answer:

34 and 17

Step-by-step explanation:

x+y=51

2y=x

2y+y=51

3y=51

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2(17)=x

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Answers

Answer:

I solution; x=8

Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

Since he paid 56% with the scholarship, that means $6,057.35 is 44% of the total tuition

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Answers

Answer:

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Answers

Answer:

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Step-by-step explanation:

Step-by-step explanation:

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Answer:

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Answers

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Answers

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Answers

Answer:

We conclude that:

[tex]\frac{x+2}{x+4}-\frac{x-1}{x+6}=\frac{5x+16}{\left(x+4\right)\left(x+6\right)}[/tex]

Step-by-step explanation:

Given the expression

[tex]\frac{x+2}{x+4}-\frac{x-1}{x+6}[/tex]

Least Common Multiple of x+4, x+6:  (x+4) (x+6)

Adjusting fractions based on the LCM

[tex]=\frac{\left(x+2\right)\left(x+6\right)}{\left(x+4\right)\left(x+6\right)}-\frac{\left(x-1\right)\left(x+4\right)}{\left(x+6\right)\left(x+4\right)}[/tex]

since the denominators are equal, combine the fractions:

[tex]\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}[/tex]

so the expression becomes

[tex]=\frac{\left(x+2\right)\left(x+6\right)-\left(x-1\right)\left(x+4\right)}{\left(x+4\right)\left(x+6\right)}[/tex]

[tex]=\frac{x^2+8x+12-\left(x-1\right)\left(x+4\right)}{\left(x+4\right)\left(x+6\right)}[/tex]

[tex]=\frac{x^2+8x+12-x^2-3x+4}{\left(x+4\right)\left(x+6\right)}[/tex]

simplify

[tex]=\frac{5x+16}{\left(x+4\right)\left(x+6\right)}[/tex]

Therefore, we conclude that:

[tex]\frac{x+2}{x+4}-\frac{x-1}{x+6}=\frac{5x+16}{\left(x+4\right)\left(x+6\right)}[/tex]

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Answers

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