The Maths GCSE test scores of 240 students are shown in the histogram below.

1. The t-value of the data is 1.833

2. The margin of error is 1.66

3. The confidence interval is between 11.66 to 8.34

From the question given;

sample size = 11

sample mean = 10 inches

standard deviation = 3 inches

1.The t-value of the data with a degree of freedom equal to 10 at 0.05 significance level = 1.833

2. Using the formula below, the margin of error is;

[tex]ME = t * \frac{SD}{\sqrt{n} }[/tex]

Substituting the values into the formula above;

ME = 1.833 * 3/√11

ME = 1.66

3. The confidence interval of the data is;

CI = mean ± ME

where CI is the confidence interval, mean is the sample mean, and ME is the margin of error. In this case, the confidence interval is calculated as follows:

CI = 10 +/- 0.96 = 9.04 to 10.96 inches

CI = 10 ± 1.66 = 11.66 to 8.34

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The area of the shaded region is  104 cm²

First, we need to know that the area of a circle is calculated using the formula;

A = πr²

Such that the parameters of the formula are;

First, let us find the area of the small circle

Area = 3.14 × 4²

Find the square value and multiply, we have;

Area = 50.24cm²

Area of the large circle = 3.14 × 7²

Find the square value and multiply

Area = 153. 86cm²

Area of the shaded region = Area of large circle - area of small circle

= 153.86 - 50.24

= 104 cm²

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The room’s area, in square inches is,

⇒ A = 144LW square inches.

We have to given that,

A rectangular room is tiled with tiles 12 inches long and 12 inches wide.

And, The room is L tiles long and W tiles wide.

Hence, Lenght of L tiles,

= 12L

And, Length of W tiles,

= 12W

Since, We know that,

Area of rectangle is,

⇒ A = Length x width

Substitute given values, we get;

⇒ A = 12L x 12W

⇒ A = 144LW square inches.

Therefore, The room’s area, in square inches is,

⇒ A = 144LW square inches.

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The length of the segment shown in the graph is 10 units

The endpoints on the line segment are : (2, - 1) and (-4,7)

The Length of a line segment can obtained using the relation :

Length = √(x2 - x1)² + (y2 - y1)²

Here,

x2 = - 4, x1 = 2, y2 = 7, y1 = - 1

Length of segment = √((-4) - 2)² + (7 - (-1))²

Length of segment = √(-6)² + (8)²

Length of segment = √36 + 64

Length of segment = √100 = 10 units

Therefore, the length of the segment on the graph shown is 10 units.

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The angles of the triangle are ordered as follows:

<B, <C and <A.

We consider a triangle with side lengths and angles related as follows:

Then the lengths and the sines of the angles are related as follows:

sin(A)/a = sin(B)/b = sin(C)/c.

By the law of sines, we have that the greater angle measures are opposite to the greater side lengths.

Hence the angle measures for this problem are ordered as follows:

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The angles of triangle ABC is arranged below

angle b - smallest

angle c

angle a - largest

To determine the angles of triangle ABC in order from smallest to largest, we can use use the knowledge that the side with higest length will face the largest angle.

Let the angles be

angle c is opposite AB = 12

angle b is opposite AC = 11

angle a is opposite BC = 19

Using the knowledge as introduced we have that

angle a > angle c > angle b

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The two other positive angles of rotation that take A to B are 19π/6 and 31π/6.

The unit circle is rotationally symmetric, meaning that any angle of rotation on the unit circle will take a point to another point on the unit circle with the same distance from the origin. This means that if we rotate point A by 7π/6 radians, we can also rotate it by 19π/6 or 31π/6 radians and end up at the same point B.

The point A has polar coordinates (1, 0). This means that it is located at a distance of 1 unit from the origin and has an angle of 0 radians with the positive x-axis.

The point B has polar coordinates (√3/2, 1/2). This means that it is located at a distance of √3/2 units from the origin and has an angle of 7π/6 radians with the positive x-axis.

If we rotate point A by 19π/6 radians, we get a point with polar coordinates (√3/2, -1/2). This point is located at the same distance from the origin as point B and has the same angle with the positive x-axis.

Therefore, the two other positive angles of rotation that take A to B are 19π/6 and 31π/6.

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The voltage drop across resistor R₃ is determined as 237.9 V.

The total current flowing in the circuit is calculated by applying Ohm's law as shown below.

V = IR

I = V / R

where;

Since the circuit is in series connection, the total resistance is calculated as follows;

R = R₁ + R₂ + R₃

R = 76 ohms + 61 ohms + 30 ohms

R = 167 ohms

The current flowing in each circuit component is calculated as;

I = V/R

I = 1325 V / 167Ω

I = 7.93 A

The voltage drop across R₃ is calculated as follows;

V₃ = IR₃

V₃ = 7.93 x 30

V₃ = 237.9 V

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The complete question is below:

This cirucit is in series. Determine the voltage dropped on R3, given:

ET = 1325 V, R1 = 76 Ω, R2 = 61 Ω, R3 = 30 Ω, and R4 = 30 Ω

Answer:

Step-by-step explanation:

Answer:

52750

Step-by-step explanation:

Step 1:  Identify the digit in the tens place:

Step 2:  Examine the digit to the right of the tens place:

Step 3:  Determine the rounding:

Since the digit to the right of the tens place is 4 (which is less than 5), we keep the tens place digit as is.

Original number: 52754.1683

Rounding to the nearest ten: 52750

Thus, rounding 52754.1683 to the nearest ten gives us 52750.

The total area of the quadrilateral DEFG is determined as 154 cm² .

option A.

The total area of the quadrilateral DEFG is calculated by applying the following method.

Consider triangle GDE in the quadrilateral;

base of the triangle = 16 cm

height of the triangle = 8 cm

Area of the triangle GDE = ¹/₂ x base x height

Area of the triangle GDE = ¹/₂ x 16 cm x 8 cm

Area of the triangle GDE = 64 cm²

Consider triangle GEF in the quadrilateral;

base of the triangle = 18 cm

height of the triangle = 10 cm

Area of the triangle GEF = ¹/₂ x base x height

Area of the triangle GEF = ¹/₂ x 18 cm x 10 cm

Area of the triangle GEF = 90 cm²

The total area of the quadrilateral DEFG is calculated as;

Area =  64 cm² +  90 cm²

Area = 154 cm²

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Appling the tangent of circle properties, the length of RS is solved to be

C. 13 in

To find the length of the tangent named RS, we applied the tangent of a circle property which says that the length of tangents to a particular point are equal

This leads to the mathematical equation represented below

SR = 7 in + 6 in

SR = 13 in

thus we can say that length of the tangent SR = 13 in

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The surface area of a square pyramid attached is

40 square units

The surface area of a square pyramid is solved using the formula

= a² + 2 * a * l

where

a = side of the square

l = slant height

In the problem

a = 4

l = 3

plugging in the values

surface area of a square pyramid = 4² + 2 * 4 * 3

surface area of a square pyramid = 16 + 24

surface area of a square pyramid = 40 square units

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According to the synthetic division below, the true statements are as follows:

B. The number 4 is a root of F(x) = 3x2-13x+4.

D. (3x2 - 13x+4) - (x - 4) = (3x - 1)

F. (x-4) is a factor of 3x2.13x+ 4.​

Synthetic divisions are the manual ways of bypassing long divisions while performing the Euclidean dividion of polynomials. For the given expressions, we can determine the true statements in this way:

1. F(x) = 3x² - 13x +4.

(x-4) (3x-1)

So, x = 4 or 1/3

4 is an actual root of the function.

2. (3x² - 13x + 4) ÷ (x - 4) = (3x - 1)

3. 3x² - 13x + 4 = (x-4) (3x-1)

So, since all these expressions are true, they meet the requirements for the synthetic division.

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Complete Question:

According to the synthetic division below, which of the following statements are true? Check all that apply. 4 4)3 -13 12 3 0 O A. The number -4 is a root of F(x) = 3x2.13x + 4. B. The number 4 is a root of F(x) = 3x2-13x+4. O C. (3x2 - 13x + 4) - (x + 4) = (3x - 1) D. (3x2 - 13x+4) - (x - 4) = (3x - 1) O E. (x + 4) is a factor of 3x2 - 13x + 4. IF (x-4) is a factor of 3x2.13x+ 4.​

Check the picture below.

Answer:

Answers following the rounding instructions:  see below for details

BC = 5.1

m∠B = 23°

m∠V = 116°

Step-by-step explanation:

Givens:

AC = 3

AB = 7

m∠A = 41°

Unknowns:

BC = ?

m∠B = ?

m∠C = ?

Find side BC using the law of cosines:  c² = a² + b² - 2ab cos(C)

a² = 3² + 7² - 2(3)(7)(cos41)

a = √9 + 49 - 42(cos41)

a = 5.128 ≈ 5.13

side BC = 5.13

Use the law of sines to find m∠B:  sin(A) / a = sin(B) / b = sin(C) / c

m∠B = sin⁻¹[sin41/5.13 x 3] = sin⁻¹(0.3837) = 22.56 ≈ 22.6°

Sum of interior angles of a triangle is 180, so now you can find m∠C:

m∠C = 180 - 22.6 - 41 = 116.44 ≈ 116.4°

Rounding side BC to nearest tenth: BC = 5.1

Rounding angles to nearest whole degree:

m∠B = 23°

m∠V = 116°

a) We can factor out a common factor of two from the denominator and a half from the numerator: (6p - 7q)/(12p - 14q) = (3p - 7q/2)/(6p - 7q)

b) The numerator and denominator can be factored to provide a common factor of2x²: (6x⁵ - 8x²)/(2x) = 2x³ - 4

c) A common factor of 5 may be extracted from the numerator: (10a + 15b)/5 = 2a + 3b

d) By grouping factors, we may factor the numerator: p² - 6q + 8/3p - 6 = [(p² - 6q) + 8]/[3(p - 2)] = (p - 2)(p - 4)/(p - 2) = p - 4 (where p ≠ 2)

Factorising is the process of employing brackets to represent an expression as the product of its components. We do this by eliminating any elements that are shared by all of the expression's terms. Maths. Algebra. We must eliminate any factors that are shared by each word in an expression before we can factorize it. Expanding brackets is the process's reverse.

Finding an expression's highest common factor (HCF), or the largest number or letter that each term can be split by, is necessary to ensure that it has been properly factorized. Otherwise, there will still be common factors inside the bracket, preventing the expression from being properly factorized.

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The quadratic equation in standard form that corresponds to the graph shown above is f(x) = x² + 2x - 8

In Mathematics and Geometry, the standard form of a quadratic function can be modeled and represented by using the following mathematical expression;

y = ax² + bx + c

Where:

In this scenario and exercise, we would write a quadratic function that represent f(x) in standard form and with a leading coefficient of 1 by using the roots (-4, 0) and (2, 0) as follows;

f(x) = (x + 4)(x - 2)

f(x) = x² - 2x + 4x - 8

f(x) = x² + 2x - 8

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Answer:

I am confident the answer is H.

Explanation:

The horizontal component is found using cos fxn

80 x cos 20 =  75.2 pounds

Answer:

x=12.124

simplified would be x=12

Step-by-step explanation:

To find the other two numbers in the set, we need to determine the missing numbers that satisfy the given conditions.

The mode of a set of numbers is the value(s) that appear(s) most frequently. In this case, the mode is given as 19, which means that 19 appears more times than any other number in the set.

The mean of a set of numbers is calculated by summing all the numbers and dividing by the total count. In this case, the mean is given as 20.

Given that the seven numbers provided are 16, 17, 19, 19, 21, 21, and 25, we can calculate the sum of these numbers:

16 + 17 + 19 + 19 + 21 + 21 + 25 = 138

To find the sum of all nine numbers in the set, we can use the mean formula:

Mean = (Sum of all numbers) / (Total count)

20 = (138 + x + y) / 9

Simplifying the equation, we have:

180 = 138 + x + y

x + y = 42

Now, since the mode is 19, we know that either x or y (or both) must be 19. Since the mode appears twice, we can assign 19 to both x and y:

x = 19

y = 19

Therefore, the other two numbers in the set are both 19.

The volume of the given figure is 750 in.

Given

Base =30in

Height = 8in

Side = 15

Side = 17

Required to calculate the volume of the given figure

Volume = Base x Height + 2 side x side (there are two rectangle)

             = 30 x 8 + 2 x 15 x 17

              = 750

The region that a 2D shape covers in an area versus the space a 3D shape occupies is the main distinction between area and volume. Geometry is filled with a wide variety of shapes and sizes.

A mass is a solid body or an assortment of distinguishable visual components that together make a solid form, such as lines, colors, textures, etc. Length, width, and depth make up the three dimensions of volume.

Thus, the volume of the given figure is 750.

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The new height above sea level would be Option (C) 3980m.

New sea-level = Previously given sea level + 20m

Given,

Height above sea previously = 4000m

Increase in sea level = 20m

Now, since there has been a rise in sea level due to global warming the distance between the previous 4000m mark and the sea level would decrease. This shall now be less than 4000m. The distance/height would reduce by 20m. It can also be observed that the distances below the sea level would increase due to a rise in the sea level mark.

∴ New height above sea level = 4000m - 20m

                                                 = 3980m.

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To solve the equations:

O + O + O = 30

1 - 3 - 5 - 7

9 - 11 -

15

We can start by simplifying the second equation:

1 - 3 - 5 - 7 = -14

9 - 11 - x = -14

To find the value of x, we can solve the equation:

-11 - x = -14

Adding 11 to both sides of the equation:

-11 + 11 - x = -14 + 11

Simplifying:

-x = -3

Multiplying both sides by -1:

(-1) * (-x) = (-1) * (-3)

x = 3

Now, substituting the value of x back into the second equation:

9 - 11 - 3 = -14

-5 - 3 = -14

-8 = -14

This is not a true statement. Therefore, the values provided do not satisfy the equations given.

Based on the information given about the geometry, the value of CF will b A. 6cm.

Since OE and OF are both 4 cm, then OEF is an equilateral triangle. This means that EOF is 60 degrees.

Since AB is 12 cm, then AB is twice the length of OE. This means that ABE is a 30-60-90 triangle.

In a 30-60-90 triangle, the hypotenuse is twice the length of the side opposite the 30 degree angle. This means that CF is 6 cm.

In conclusion, the correct option is A.

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Therefore, we would predict that a catfish with a length of 33 inches would weigh approximately 26.5 pounds.

Jin has decided to research the relationship between the length in inches and the weight of a certain species of catfish. He measures the length and weight of a number of specimens he catches, then throws back into the water. After plotting all his data, he draws a line of best fit.

The given problem is related to a scatter plot, which depicts the relationship between the length in inches and the weight of a certain species of catfish. Based on the scatter plot, it is clear that there is a positive correlation between length and weight.

The correlation between the two variables can be measured using the correlation coefficient, r, which ranges between -1 and 1, where -1 denotes a perfect negative correlation, 1 denotes a perfect positive correlation, and 0 denotes no correlation.

The line of best fit can be determined using the method of least squares.

This method minimizes the sum of the squared errors between the observed values and the predicted values.

The equation of the line of best fit is

y = mx + b,

where m is the slope of the line and b is the y-intercept.

To predict the weight of a catfish with a length of 33 inches, we need to use the equation of the line of best fit.

Let's assume that the equation of the line of best fit is

y = 0.5x + 10,

where y is the weight of the catfish in pounds and x is the length of the catfish in inches.

Then, we can substitute x = 33 into the equation to obtain:

y = 0.5(33) + 10

   = 16.5 + 10

   = 26.5

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Answer:

the volume of the square pyramid is 2430 cubic cm

Answer:

1296 cm³

Step-by-step explanation:

V = a² x [√s²- (a/2)²] / 3

a = 18 cm

s = 15 cm

V = 18² x [√15²-(18/2)²] / 3 = 18² x [√225-81] / 3

V = 324 x (√144/3) = 1296 cm³