The Marshall Track Team is running a relay race. There are 7 students on the team. The race is ½ of a mile long and each student runs the same distance. How far does each student run? Show your thinking with a drawing, a number line or tape diagram, and an equation. Enter your answer, work and/or explanation in the space provided.

Answer:

C. b= a+4

Step-by-step explanation:

Answer:

Ends at 2:00

Step-by-step explanation:

12:15 + 1:30 = 13:45.

13:45 + 00:15 = 14:00

14 - 12 = 2

Recess ends at 2:00

Answer:

2p

Step-by-step explanation:

ok so 12:15 + 1 hour = 1:15pm

1:15pm + 30 minutes = 1:45pm

so that's the time that class ends at.

now Gabe has recess for 15 minutes.

so 1:45pm + 15 minutes = 2pm

Gabe's recess finishes at 2pm

hope that helps : )

Answer:

8 root 2 or 11.3

Step-by-step explanation:

square 16 and divide by two to find square of other sides. Then root it to find answer

Answer:   8 root 2 or 11.3

Step-by-step explanation:

square 16 and divide by two to find square of other sides. Then root it to find answer

Answer: this is a function.

f(x)=y

Step-by-step explanation:

domain -> 1,2,3

values: 3,7,-1

Answer:

7.21

Step-by-step explanation:

It should be tan(k)=32/40

Tangent is opposite/adjacent and 24/32 is adjacent/opposite which is not a trig function.

Answer: 23

Step-by-step explanation:

If I am not mistaken, you should find

what times 2 plus 14 equals 60 which would be......

23

Answer:

-7/4

Step-by-step explanation:

(-1,2) (3,-5)

x1 y1 x2 y2

-5-2=-7

3-(-1)=4

-7/4

There are 16 fruits in each of the boxes found under the stairs.

An equation is an expression used to show the relationship between two or more numbers and variables.

Let x represent the number of pears, hence:

Number of fruit in first box = 12 + (1/9)x

Number of fruit in second box = number of fruit in third box = (8/9)x ÷ 2 = (4/9)x

Therefore:

12 + (1/9)x = (4/9)x

x = 36

First box = second box = third box = (4/9) * 36 = 16

There are 16 fruits in each of the boxes found under the stairs.

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[tex]\bf \colorbox{black} {\bf {\textcolor{blue}{ }{ \bf { \textcolor{orange}{ }{ \bf{ \textcolor{cyan}{mathematics = }}}}}}}[/tex]

(3×2-2)+(5×2+5×-1)=

(6-2)+(10-5)=

4+5=

[tex] \bf \textcolor{green}{ \underbrace{9}}[/tex]

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's simplify ~

[tex]\qquad \sf  \dashrightarrow \:(3 \times 2 - 2) + (5 \times 2 + 5 \times ( - 1))[/tex]

Use BODMAS/PEDMAS rule here :

[tex]\qquad \sf  \dashrightarrow \:(6- 2) + (10 + ( - 5))[/tex]

[tex]\qquad \sf  \dashrightarrow \:4 + (10 - 5)[/tex]

[tex]\qquad \sf  \dashrightarrow \:4 + 5[/tex]

[tex]\qquad \sf  \dashrightarrow \:9[/tex]

Hope it helps you ~

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

Answer/Step-by-step explanation:

Given:

Seven more than the quotient of a number b and 45 is greater than 5

So:

Seven more than the quotient of a number b and 45 is greater than 5

=

7 + b/45 > 5

Solve if needed:

[tex]\begin{bmatrix}\mathrm{Solution:}\:&\:b > -90\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-90,\:\infty \:\right)\end{bmatrix}[/tex]

[tex]\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}[/tex]

[tex]7+\frac{b}{45}-7 > 5-7[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]\frac{b}{45} > -2[/tex]

[tex]\mathrm{Multiply\:both\:sides\:by\:}45[/tex]

[tex]\frac{45b}{45} > 45\left(-2\right)[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]b > -90[/tex]

~Lenvy~

Answer:

3

Step-by-step explanation:

I hope its helped<8 thank you

Answer:

214130

Step-by-step explanation:

27.6 /100 = 59100 / x

x = 214130

Answer:

Step-by-step explanation:

Quantum numbers describe the states of electrons in their respective orbitals in an atom.

Quantum numbers are mathematical descriptions that show the possible states of an electron.

There are four types of quantum number

principal quantum number (n)

angular momentum quantum number (l)

magnetic quantum number (ml)

spin quantum number (ms)

The values for the principal quantum number (n) are integers greater than zero.

The values for the angular momentum quantum number (l) are integers from 0 to n - 1.

The values for the magnetic quantum number (ml) are integers from -l to l.

The values for the spin quantum number (ms) are -1/2 and 1/2.

Learn more about quantum numbers:

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The function [tex]u(x)=-x+3x^{2} -8[/tex] is a quadratic function due to the highest exponent being 2.

Given functions are:

[tex]u(x)=-x+3x^{2} -8[/tex]

[tex]v(x)=2x^{2} +8x^3+9x[/tex]

[tex]y(x)=x^{2} +3x^5+4[/tex]

[tex]z(x) =7x^{2} +2x^3-3[/tex]

A function of the form [tex]f(x)=ax^{2} +bx+c[/tex] with [tex]a\neq 0[/tex] is called a quadratic function means the highest exponent of polynomial should be 2.

Let us check one by one.

[tex]u(x)=-x+3x^{2} -8[/tex]

Highest exponent =2

The function is also of form [tex]f(x)=ax^{2} +bx+c[/tex] so u(x) is a quadratic function.

The functions v(x), y(x), and z(x) are having highest exponents as 3,5, and 3 respectively so they are not quadratic functions.

Hence, the function [tex]u(x)=-x+3x^{2} -8[/tex] is a quadratic function due to the highest exponent being 2.

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Answer:

48 in³

Base Area:

[tex]\hookrightarrow \sf \dfrac{1}{2} *base*height[/tex]

[tex]\hookrightarrow \sf \dfrac{1}{2} *3*8[/tex]

[tex]\hookrightarrow \sf 12 \ in^2[/tex]

Volume:

[tex]\hookrightarrow \sf 12 * 4[/tex]

[tex]\hookrightarrow \sf 48 \ in^3[/tex]

Answer:

[tex]\rightarrow \sf x^2=\:17x\:+\:60[/tex]

change sides

[tex]\rightarrow \sf x^2 -17x -60 = 0[/tex]

breakdown, (60 : 20 * 3)

[tex]\rightarrow \sf x^2 -20x +3x-60 = 0[/tex]

factor the following

[tex]\rightarrow \sf x(x -20) +3(x-20) = 0[/tex]

collect into groups

[tex]\rightarrow \sf (x +3)(x-20) = 0[/tex]

final answer

[tex]\rightarrow \sf x=-3, \ 20[/tex]

Answer:

(x-20) (x+3) =0

Step-by-step explanation:

x ^ 2 = 17x + 60​

Subtract 17x from each side

x ^ 2 - 17x = 60​

Subtract 60 from each side

x ^ 2 - 17x - 60=0

What 2 numbers multiply by -60 and add to -17

-20 * 3 = -60

-20 +3 = -17

(x-20) (x+3) =0

​

Answer:

Simplify the radical by breaking the radicand up into a product of known factors.

Exact Form:

3

√

75

5

Decimal Form:

0.84343266

…

Answer:

[tex]\frac{27}{125}[/tex]

Step-by-step explanation:

[tex](\frac{3}{5})^{3}[/tex] is [tex]\frac{3^{3}}{5^{3}}[/tex]

[tex]3^{3} = 27[/tex] and [tex]5^{3} = 125[/tex]

[tex]\frac{27}{125}[/tex]

Answer:

I believe this is what they are asking on your problem.

Answer:

  30 cm²

Step-by-step explanation:

You want to know the area of the given shape.

The formula for the area of a parallelogram is ...

  A = bh

A line from B to E divides the figure into two congruent parallelograms, each having a base of 5 cm and a height of 3 cm.

The area of the figure is ...

  A = 2 × (5 cm)(3 cm) = 30 cm²

__

Additional comment

If you draw a line from F to D you get a triangle FED that perfectly matches the space ABC. Moving ∆FED to fill ∆ABC transforms the figure into a rectangle that is 5 cm high and 6 cm wide. Its area is (5 cm)(6 cm) = 30 cm².

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Answer:

Lower Quartile: 7

Median: 12

Upper Quartile: 16.5

Step-by-step explanation:

First, to find anything you must reorganize the numbers according from smallest to biggest. In this case, it would be:

4, 6, 8, 9, 10, 14, 15, 16, 17, 18

Let's find the median first. The median is in the middle of the data set, and there are 10 numbers in this data set. We need to find the middle of two numbers to find the median, 10 and 14, which would be 12.

To find the lower quartile, you must look at the numbers below the median. Those would include 4, 6, 8, and 9. There is a even number of digits, meaning that we might find the middle of two numbers, 6 and 8, which is 7.

Then, the Upper Quartile which is the same process. Look at 15, 16, 17, and 18. It is a even number of digits so we need to find the middle of 16 and 17, which would equal 16.5.

Hope this helped!

Answer:

it classified as a

error.

Step-by-step explanation:

Answer:

r 4    3.99797

Step-by-step explanation:

Hey ! there

Answer:

Step-by-step explanation:

In this question we have given that a circle have a circumference of 25.12 . And we are asked to find the radius of the circle .

We have to solve this question with the help of circumference formula for circle that is ,

[tex] \qquad\: \quad\underline{\boxed{ \frak{{Circumference_{(Circle)} = 2\pi r}}}}[/tex]

Where ,

Solution : -

For solving the question we must have to substitute value of π , radius and then we have to equate it with given circumference that is 25.12. So ,

[tex] \longmapsto \qquad \:\: 2 \times 3.14 \times r = 25.12[/tex]

Step 1 : By multiplying 2 , 3.14 and r , We get :

[tex] \longmapsto \qquad \: \:6.28r = 25.12[/tex]

Step 2 : Dividing with 6.28 on both sides :

[tex] \longmapsto \qquad \: \: \dfrac{ \cancel{6.28}r}{ \cancel{6.28}} = \cancel{\dfrac{25.12}{6.28} }[/tex]

On further calculations, We get :

[tex] \longmapsto \qquad \: \: \pink{\underline{\boxed{ \frak{r = 4}}}}[/tex]

Verifying : -

Now we are verifying our answer by finding the circumference of circle and equating it with 25.12 and if it will equal to 25.12 then our answer is correct . So ,

Therefore our answer is correct .

Please Note : We aren't using any unit for the values because in the question no units are provided .

An asymptote is a straight line that approaches a curve indefinitely but does not intersect at any point. There are asymptotes at t [tex]\dfrac{3}{2}\rm\ and\ \dfrac{-1}{3}[/tex].

An asymptote is a straight line that approaches a curve indefinitely but does not intersect at any point. In other words, when a curve approaches infinity, it approaches an asymptote line.

The function that is given to us is:

[tex]f(x)=\dfrac{x+1}{6x^2-7x-3}[/tex]

As in the function, there is a fraction therefore, the denominator should not be zero in order for the function to be defined. Therefore, there are asymptotes at

[tex]6x^2-7x-3 = 0\\[/tex]

Substituting the value in the formula of the quadratic equation we will get,

[tex]D=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\D = \dfrac{-(-7)\pm\sqrt{(-7)^2-4(6)(-3)}}{2(6)}\\\\D =\dfrac{-(-7)\pm\sqrt{11}}{12} = \dfrac{3}{2}, \dfrac{-1}{3}[/tex]

Thus, there are asymptotes at  [tex]\dfrac{3}{2}\rm\ and\ \dfrac{-1}{3}[/tex].

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Answer:

[tex]\bf A)\;17[/tex]

Step-by-step explanation:

[tex]\tt 5q-10=75[/tex]

[tex]\tt 5q-10+10=75+10\;\; \bf\; Add\;10\:to\:both\:sides[/tex]

[tex]\tt 5q=85\;\;\;\bf Simplify[/tex]

[tex]\tt \cfrac{5q}{5}=\cfrac{85}{5}\;\;\; \bf Divide\:both\:sides\:by\:5[/tex]

[tex]\tt q=17\;\; \;\bf Answer[/tex]

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