The Lopez family is driving to the state fair. First, they drove 32 kilometers to stop for a snack. Then, they drove another 35 kilometers and stop for gas. There were 17 kilometers left to drive.

How many kilometers does the family have to drive to get to the state fair?

Step-by-step explanation:

1. The rabbit would be hopping at 3 feet per second.

You would first:

1. Divide each sides by 2

This would result into 3 = 1.

2. Given, 6 = 2.

If we said feet (6) = x and 2 (seconds) = y,

x = y or

feet = second (6 = 2).

Answer:

C(90) = 15.35

Step-by-step explanation:

Given the function, C(n) = 0.06n + 9.95:

where C = total cost of texting plan

n = number of texts sent in a month

9.95 = flat fee

To find C(90):

Substitute 90 as the input, n,  for the function:

C(90) = 0.06n + 9.95

C(90) = 0.06(90) + 9.95

C(90) = 5.40 + 9.95

C(90) = 15.35

C(90) represents the cost of sending 90 texts in a month is $15.35.

Please mark my answers as the Brainliest if you find my explanations and solutions helpful :)

Answer:

wait I will give the answer in 2 minutes

Step-by-step explanation

Answer:

60 people are in the team altogether

Answer:

60

Step-by-step explanation:

to find the percentage of girls on the swim team, you would multiply a number by 30 percent. to find the number in all, you would divide 18 by 30 percent

18/0.3 = 60

there are sixty people on the swimming team

Answer:

Typical transactions include ATM withdrawals, debit card payments, and e-transfers.

Answer:

13.5%

Step-by-step explanation:

Answer:

No

Step-by-step explanation:

Unit rate consists of at least one 1. the unit rate for this would be 1 slice for $1.25

please mark brainliest

Answer:The answer is 43.47517

Step-by-step explanation:

I did the test and reviewed it

Answer:

5 7/12

Step-by-step explanation:

3 1/4 + 2 1/3

Multiply the fractions by a number in order to have the same denominator. ( in this case 12)

3 3/12 + 2 4/12

Add straight across

5 7/12

Answer:

198 pancakes.

Step-by-step explanation:

Answer:

198

Step-by-step explanation:

Answer:

By using the formula, Parts /whole = percent/100, ⇒ 25/ 50 × 100 = 50%. So, 50 % of 50 is 25 proportion.

Answer:

a) w=6

b) a=3

c) c=7

Step-by-step explanation:

[tex]3w+6=4w[/tex]

[tex]\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}[/tex]

[tex]3w+6-6=4w-6[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]3w=4w-6[/tex]

[tex]\mathrm{Subtract\:}4w\mathrm{\:from\:both\:sides}[/tex]

[tex]3w-4w=4w-6-4w[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]-w=-6[/tex]

[tex]\mathrm{Divide\:both\:sides\:by\:}-1[/tex]

[tex]\frac{-w}{-1}=\frac{-6}{-1}[/tex]

[tex]w=6[/tex]

___________________________________________

[tex]a+18=7a[/tex]

[tex]\mathrm{Subtract\:}18\mathrm{\:from\:both\:sides}[/tex]

[tex]a+18-18=7a-18[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]a=7a-18[/tex]

[tex]\mathrm{Subtract\:}7a\mathrm{\:from\:both\:sides}[/tex]

[tex]a-7a=7a-18-7a[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]-6a=-18[/tex]

[tex]\mathrm{Divide\:both\:sides\:by\:}-6[/tex]

[tex]\frac{-6a}{-6}=\frac{-18}{-6}[/tex]

[tex]a=3[/tex]

Step-by-step explanation:

[tex] \green{\large\underline{\sf{Solution-}}}[/tex]

Given pair of linear equations are

[tex]\rm :\longmapsto\:0.4x + 0.3y = 1.7 \\ \\ \rm :\longmapsto\:0.7x - 0.2y = 0.8[/tex]

can be rewritten as on multiply by 10,

[tex]\rm :\longmapsto\:4x + 3y = 17 - - - - (1)\\ \\ \rm :\longmapsto\:7x - 2y = 8 - - - - - (2)[/tex]

[tex]\rm :\longmapsto\:2y = 7x - 8[/tex]

[tex]\rm\implies \:\boxed{\tt{ y = \frac{7x - 8}{2}}} - - - - (3) [/tex]

On substituting the value of y in equation (1), we get

[tex]\rm :\longmapsto\:4x + 3\bigg( \dfrac{7x - 8}{2} \bigg) = 17[/tex]

[tex]\rm :\longmapsto\:\dfrac{8x + 21x - 24}{2} = 17[/tex]

[tex]\rm :\longmapsto\:29x - 24 = 34[/tex]

[tex]\rm :\longmapsto\:29x = 34 + 24[/tex]

[tex]\rm :\longmapsto\:29x = 58[/tex]

[tex]\bf\implies \:x = 2 - - - - (4)[/tex]

On substituting x = 2 in equation (3), we get

[tex]\rm :\longmapsto\:y = \dfrac{7 \times 2 - 8}{2} [/tex]

[tex]\rm :\longmapsto\:y = \dfrac{14 - 8}{2} [/tex]

[tex]\rm :\longmapsto\:y = \dfrac{6}{2} [/tex]

[tex]\bf\implies \:y = 3[/tex]

So, we get

[tex]\begin{gathered}\begin{gathered}\bf\: \rm :\longmapsto\:\begin{cases} &\bf{x = 2} \\ \\ &\bf{y = 3} \end{cases}\end{gathered}\end{gathered}[/tex]

From equation (1),

[tex]\rm :\longmapsto\:0.4x + 0.3y = 1.7[/tex]

On substituting the value of x and y, we get

[tex]\rm :\longmapsto\:0.4(2) + 0.3(3) = 1.7[/tex]

[tex]\rm :\longmapsto\:0.8 + 0.9 = 1.7[/tex]

[tex]\rm :\longmapsto\:1.7 = 1.7[/tex]

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

To solve systems using Method of Substitution, follow this procedure:

1. Select one equation and solve it for one of its variables.

2. In the other equation, substitute the value of one variable evaluated in step 1 to reduced the equation to one variable.

3. Solve the equation to get the value of this variable

4. Substitute the value found in to first equation involving both variables and solve for the other variable.

Answer:

1.75

Step-by-step explanation:

you divide 7 by 4

7÷4= 1.75

Answer:

log 4

---------   that's the answer yw

   9

Step-by-step explanation:

Answer: C - 35

Step-by-step explanation:

If the ratio is 3:5:2 and red books is 21, I believe the answer is C, 35 as  5 times 7 equals to 35.

Answer:

C (35)

Step-by-step explanation:

21 red

There are only 3 red which means you have to find out how you get 21

Find what numbers go with 3

3x7 is 21

mutiply yellow by 7 and get your answer (5x7)

35

Answer:

I think if you want to enlarge it add 10 to all three sides to get the sides of 13 16 and 16

Answer: 3x^2

Step-by-step explanation: Find the greatest common factor for the numerical part. For 3, 15, and 21 the greatest common factor is 3. Find the GCF for the variable part which is x^2. Multiply 3 and x^2 to get 3x^2.

8x² - 24 = 8 (x² - 3)

Answer:A

Step-by-step explanation:

Answer:

a^(4/15)

Step-by-step explanation:

rules of indices:

WHEN MULTIPLYING POWERS WITH THE SAME BASE YOU ADD THE POWERS

a^(1/5) × a^(2/3) = a^(1/5 + 2/3)

a^(13/15)

WHEN DIVIDING POWERS WITH THE SAME BASE YOU SUBTRACT THE POWERS

a^(13/15) / a^(3/5) = a^(13/15 - 3/5)

a^(4/15)

NOTE: YOU HAVE TO FOLLOW BODMAS RULE IN THE QUESTION.. AND PLEASE LOOK OUT FOR THE POWERS WITH THE SAME BASE. IF BASE IS DIFFERENT YOU CANNOT SIMPLIFY...

Answer:

169 I think?

Step-by-step explanation:

if you look at images of number rows 169 is the only one in it with the others

Answer:

this property is commutative property

Answer:

Commutative

Step-by-step explanation:

Step-by-step explanation:

We have,

[tex]\displaystyle\sf{\,^{n}C_{n-1}+\,^{n}C_{n-2}}[/tex]

[tex]\displaystyle\sf{=\dfrac{n!}{(n-1)!(n-(n-1))!}+\dfrac{n!}{(n-2)!(n-(n-2))!}}[/tex]

[tex]\displaystyle\sf{=\dfrac{n!}{(n-1)!(n-n+1)!}+\dfrac{n!}{(n-2)!(n-n+2)!}}[/tex]

[tex]\displaystyle\sf{=\dfrac{n!}{(n-1)!(1)!}+\dfrac{n!}{(n-2)!(2)!}}[/tex]

[tex]\displaystyle\sf{=\dfrac{n(n-1)!}{(n-1)!(1)!}+\dfrac{n(n-1)(n-2)!}{(n-2)!(2)!}}[/tex]

[tex]\displaystyle\sf{=\dfrac{n}{1}+\dfrac{n(n-1)}{2}}[/tex]

[tex]\displaystyle\sf{=n+\dfrac{n^2-n}{2}}[/tex]

[tex]\displaystyle\sf{=\dfrac{2n+n^2-n}{2}}[/tex]

[tex]\displaystyle\sf{=\dfrac{n^2+n}{2}}[/tex]

[tex]\displaystyle\sf{=\dfrac{n(n+1)}{2}}[/tex]

Using the combination formula, it is found that the value of the expression is given by:

(b) n(n + 1)/2

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this problem:

[tex]C_{n, n-1} = \frac{n!}{(n-1)!(n - n + 1)!} = \frac{n(n-1)!}{(n-1)!} = n[/tex]

[tex]C_{n, n-2} = \frac{n!}{(n-2)!(n - n + 2)!} = \frac{n(n-1)(n-2)!}{(n-2)!2!} = \frac{n(n-1)}{2}[/tex]

Then, adding these values:

[tex]n + \frac{n(n-1)}{2} = \frac{2n + n^2 - n}{2} = \frac{n(n + 1)}{2}[/tex]

Hence option b is correct.

More can be learned about the combination formula at https://brainly.com/question/25821700

Answer: x=2 because for any y value the x value is always 2.

Answer:

y=ex+4 ok hope you get it right

Answer:

9

Step-by-step explanation:

Answer:

-1, 0, 1/2, 1, 4/3

Step-by-step explanation: