The listed occupations of stockholders of a national computer company included 9% who were housewives. If six of these stockholders are randomly selected, what is the probability that none are housewives?

Answers

Answer 1

Answer:

no se la respuesta

Step-by-step explanation:

no se la respuesta

Answer 2

The probability that none of the six selected stockholders are housewives is,

⇒ 56.8%

The term probability refers to the likelihood of an event occurring. Probability means possibility.

The probability of an event occurring can be calculated by subtracting the probability of the event not occurring from 1.

Given that,

The listed occupations of stockholders of a national computer company included 9% who were housewives.

Since 9% of the stockholders are housewives.

Hence, the probability that a randomly selected stockholder is not a housewife is,

= [tex]1 - 9%[/tex]%

= [tex]1 - 0.09[/tex]

= [tex]0.91[/tex]

So, The probability that none of the six selected stockholders are housewives is,

⇒ [tex](0.91)^6[/tex]

⇒ [tex]0.5678[/tex]

Learn more about the probability visit:

https://brainly.com/question/13604758

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Given : ABCD is a square with each side 5cm .

To Find : The area of the shaded region .

Solution : On observing the figure we can see two quadrants , quadrant ADC & quadrant ABC .

If we join A to C , then it will be common for triangles ADC & ABC . And they will be congruent by SSS congruence condition.

Therefore the area of both quadrants will also be equal . Now we can find area of quadrant as ;

[tex]\large\boxed{\red{\bf Area_{quadrant}=\dfrac{\pi r^2}{4}}}[/tex]

Here radius will be equal to 5cm .

⇒ Area = πr² / 4 .

⇒ Area = π (5cm)² / 4 .

⇒ Area = 22/7 × 25 × 4 cm².

Area = 19.64 cm² .

So , total area of both quadrants = 39.28 cm² .

Also , area of square will be :

[tex]\large\boxed{\bf{\red{Area_{square}=(side)^2}}}[/tex]

⇒ Area = 5cm × 5cm .

Area = 25 cm².

Now , subtract area of one quadrant from the area of square = 25cm² - 19.64 cm² = 5.36 cm².

Similarly area of other white region = 5.36cm² .

And the areas sum will be = 5.36cm² × 2 = 10.72cm² .

Now , from the figure it's clear that ,

⇒ Area of unshaded region + Area of shaded region = 25cm².

⇒ 10.72cm² + ar( Shaded region ) = 25cm².

⇒ ar ( Shaded region ) = 25cm² - 10.72cm².

ar ( Shaded region ) = 14.28 cm².

Hence the area of shaded region is 14.28 cm².

[tex]\large\boxed{\red{\bf Answer = 14.28cm^2}}[/tex]

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Step-by-step explanation:

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