The length is twice the sum of its width 3. What are the dimension of the rectangle if it’s area 216 square inches?

The Length Is Twice The Sum Of Its Width 3. What Are The Dimension Of The Rectangle If Its Area 216 Square

Answers

Answer 1

Assume that the width of the rectangle = x

Since the length is twice the sum of the width and 3, then

[tex]\begin{gathered} L=2(x+3) \\ L=2x+6 \end{gathered}[/tex]

Since the area of the rectangle is 216 square inches, then

Multiply the length and the width, then equate the product by 216

[tex]\begin{gathered} (x)(2x+6)=216 \\ 2x^2+6x=216 \end{gathered}[/tex]

Divide all terms by 2 to simplify

[tex]\begin{gathered} \frac{2x^2}{2}+\frac{6x}{2}=\frac{216}{2} \\ x^2+3x=108 \end{gathered}[/tex]

Subtract 108 from both sides

[tex]\begin{gathered} x^2+3x-108=108-108 \\ x^2+3x-108=0 \end{gathered}[/tex]

Now, let us factorize the trinomial into 2 factors

[tex]\begin{gathered} x^2=(x)(x) \\ -108=(-9)(12) \\ (x)(-9)+(x)(12)=-9x+12x=3x \end{gathered}[/tex]

Then the factors are

[tex]x^2+3x-108=^{}(x-9)(x+12)[/tex]

Equate them by 0

[tex](x-9)(x+12)=0[/tex]

Equate each factor by 0, then find the values of x

[tex]x-9=0[/tex]

Add 9 to both sides

[tex]\begin{gathered} x-9+9=0+9 \\ x=9 \end{gathered}[/tex][tex]x+12=0[/tex]

Subtract 12 from both sides

[tex]\begin{gathered} x+12-12=0-12 \\ x=-12 \end{gathered}[/tex]

Since the width can not be a negative number (no negative length)

Then the width of the rectangle = 9

Let us find the length

[tex]\begin{gathered} L=2(9)+6 \\ L=18+6 \\ L=24 \end{gathered}[/tex]

Then the dimensions of the rectangle are 9 inches and 24 inches


Related Questions

Solve the equation.k²=47ks.(Round to the nearest tenth as needed. Use a comma to separate answers as needed.

Answers

The initial equation is:

[tex]k^2=47[/tex]

Then, we can solve it calculating the square root on both sides:

[tex]\begin{gathered} \sqrt[]{k^2}=\sqrt[]{47} \\ k=6.9 \\ or \\ k=-6.9 \end{gathered}[/tex]

Therefore, k is equal to 6.9 or equal to -6.9

Answer: k = 6.9 or k = -6.9

[tex] f(x) = 3x^{2} - 2x + 3[/tex]if (-3,n) is an element of the function what is the value of n?

Answers

SOLUTION

[tex]\begin{gathered} f(x)=3x^2\text{ - 2x + 3 } \\ \text{Here, (-3, n) can be written as (x, y), where x = -3 and y = n} \\ \text{Also y is also = f(x). } \\ \text{That is y = }3x^2\text{ - 2x + 3 } \end{gathered}[/tex]

Now putting x = -3 into f(x) or y, we have that

[tex]\begin{gathered} y=3(-3)^2\text{ -2(-3) + 3} \\ y\text{ = 3(9) + 6 + 3} \\ y\text{ = 27 + 6 + 3} \\ y\text{ = 36. } \\ \text{Since y = n, therefore, n = 36. } \end{gathered}[/tex]

The value of n is 36

find the equation of the axis of symmetry of the following parabola algebraically. y=x²-14x+45

Answers

Answer:

x = 7, y = -4

(7, -4)

Explanation:

Given the below quadratic equation;

[tex]y=x^2-14x+45[/tex]

To find the equation of the axis of symmetry, we'll use the below formula;

[tex]x=\frac{-b}{2a}[/tex]

If we compare the given equation with the standard form of a quadratic equation, y = ax^2 + bx + c, we can see that a = 1, b = -14, and c = 45.

So let's go ahead and substitute the above values into our equation of the axis of symmetry;

[tex]\begin{gathered} x=\frac{-(-14)}{2(1)} \\ =\frac{14}{2} \\ \therefore x=7 \end{gathered}[/tex]

To find the y-coordinate, we have to substitute the value of x into our given equation;

[tex]\begin{gathered} y=7^2-14(7)+45 \\ =49-98+45 \\ \therefore y=-4 \end{gathered}[/tex]

13 nickels to 43 dimes in a reduced ratio form

Answers

The reduced ratio form of 13 nickels to 43 dimes is 13/86.

What is a ratio?

a ratio let us know that how many times one number contains another number.

We are given 13 nickels and 43 dimes.

We know that 1 dime equal to 2 nickels.

Hence 43 dimes equals 86 nickels.

Now we find the ratio of the 2.

Which will be [tex]\frac{13}{86}[/tex]

Hence the reduced ratio form is 13/86.

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Jackson purchased a pack of game cards that was on sale for 22% off. The sales tax in his county is 6%. Let y represent the oeiginal price of the card.. Wrote an expression that can be used to determine the final cost of the cards.

Answers

Given:

Discount - 22% = 0.22

Sales Tax - 6% = 0.06

Required:

Expression for the final cost of the cards, x

Solution:

Let: y represent the original price of the card.

x represent the final cost of the cards

D represent the discounted cost of the cards

Assume that the the sales tax is applied to the price after the discount.

D= Original Price ( 1 - Discount) = y ( 1 - 0.22) = 0.78y

To compute for the final cost,

Final Cost = D + Tax

Tax = 0.06 D

x = D + 0.6(D)

x = 1.06D

x = 1.06 ( 0.78 y)

x = 0.827y

Answer:

The final cost of the card can be describe by the expression:

x = 0.827y

I’m confused on this question. I just have to choose which one

Answers

SOLUTION:

Case: Circle theorems

Method:

From the given circle

Theorem: The angle at the center of the circle is twice the angle at the circumference formed by the same segment.

The implication to the circle in the question is:

[tex]\begin{gathered} \hat{mST}=2m\angle2 \\ OR \\ m\angle2=\frac{1}{2}(\hat{mST}) \end{gathered}[/tex]

Final answer

[tex]m\operatorname{\angle}2=\frac{1}{2}(\hat{mST})[/tex]

I need help with this question can you please help me

Answers

Given the following question:

[tex]\begin{gathered} x^2+3x-5=0 \\ \text{ Convert using the quadratic formula:} \\ x^2+3x-5=0=x_{1,\:2}=\frac{-3\pm\sqrt{3^2-4\cdot\:1\cdot\left(-5\right)}}{2\cdot\:1} \\ x_{1,\:2}=\frac{-3\pm \sqrt{3^2-4\cdot \:1\cdot \left(-5\right)}}{2\cdot \:1} \\ \text{ Solve} \\ 3^{2}-4\times1(-5) \\ 1\times-5=-5 \\ 3^2-4\times-5 \\ 3^2=3\times3=9 \\ =29 \\ =\sqrt{29} \\ x_{1,\:2}=\frac{-3\pm \sqrt{29}}{2\cdot \:1} \\ \text{ Seperate the solutions:} \\ x_1=\frac{-3+\sqrt{29}}{2\cdot \:1} \\ x_2=\frac{-3-\sqrt{29}}{2\cdot\:1} \\ \text{ Simplify} \\ 2\times1=2 \\ x=\frac{-3+\sqrt{29}}{2} \\ x=\frac{-3-\sqrt{29}}{2} \end{gathered}[/tex]

Your answers are the first and second options.

he two-way frequency table given shows the results from a survey of students who attend the afterschool program.


Takes Art Class Doesn't Take Art Class Total
Plays a Sport 45 120
Doesn't Play a Sport 45
Total 225

Does the data show an association between taking an art class and playing a sport?
There is a strong, positive association.
There is a strong, negative association.
There is a weak, positive association.
There is a weak, negative association.

Answers

The association between the variables art class and playing a sport is classified as follows:

There is a strong, negative association.

What is the association between the two variables?

The association between variables can be classified either as positive or as negative, as follows:

Positive: both variables behave similarly, either both increases or both decreasing.Negative: the variables behave in an inversely manner, with one increasing and the other decreasing, or vice-versa.

In the context of this problem, it is found that of the students that take art class, the majority do not play a sport, while among those who do not take art class, the majority play a sport, hence there is a strong and negative association between the two variables.

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Find the expression for the possible width of the rectangle.

Answers

Given the area of the rectangle is given by the following expression:

[tex]A=x^2+5x+6[/tex]

The area of the rectangle is the product of the length by the width

So, we will factor the given expression

To factor the expression, we need two numbers the product of them = 6

and the sum of them = 5

So, we will factor the number 6 to find the suitable numbers

6 = 1 x 6 ⇒ 1 + 6 = 7

6 = 2 x 3 ⇒ 2 + 3 = 5

So, the numbers are 2 and 3

The factorization will be as follows:

[tex]A=(x+3)(x+2)[/tex]

So, the answer will be the possible dimensions are:

[tex]\begin{gathered} \text{Length}=x+3 \\ \text{Width}=x+2 \end{gathered}[/tex]

Use the graph below to determine the equation of the circle in (a) center-radius form and (b) general form.10-(-3,6)(-6,3(0,3)-10(-3,0)1010

Answers

Question:

Solution:

An equation of the circle with center (h,k) and radius r is:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

This is called the center-radius form of the circle equation.

Now, in this case, notice that the center of the circle is (h,k) = (-3,3) and its radius is r = 3 so that the center-radius form of the circle would be:

[tex](x+3)^2+(y-3)^2=3^2[/tex]

To obtain the general form, we must solve the squares of the previous equation:

[tex](x+3)^2+(y-3)^2-3^2\text{ = 0}[/tex]

this is equivalent to:

[tex](x^2+6x+3^2)+(y^2-6y+3^2)\text{ - 9 = 0}[/tex]

this is equivalent to

[tex]x^2+6x+9+y^2-6y\text{ = 0}[/tex]

this is equivalent to:

[tex]x^2+y^2+6x-6y\text{ +9= 0}[/tex]

so that, the general form equation of the circle would be:

[tex]x^2+y^2+6x-6y\text{ +9= 0}[/tex]

thus, the correct answer is:

CENTER - RADIUS FORM:

[tex](x+3)^2+(y-3)^2=3^2[/tex]

GENERAL FORM:

[tex]x^2+y^2+6x-6y\text{ +9= 0}[/tex]

help meeeeeeeeee pleaseee !!!!!

Answers

The simplified answer of the composite function is as follows:

(f + g)(x) = 2x + 3x²(f - g)(x) = 2x - 3x²(f. g)(x)  = 6x³(f / g)(x) = 2 / 3x

How to solve composite function?

Composite functions is a function that depends on another function.  A composite function is created when one function is substituted into another function.

In other words, a composite function is generally a function that is written inside another function.

Therefore,

f(x) = 2x

g(x) = 3x²

Hence, the composite function can be simplified as follows:

(f + g)(x) = f(x) + g(x)  = 2x + 3x²

(f - g)(x) = f(x) - g(x)  = 2x - 3x²

(f. g)(x) = f(x) . g(x) = (2x)(3x²) = 6x³

(f / g)(x) = f(x) / g(x) = 2x / 3x² = 2 / 3x

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The ratio of the volume of two spheres is 8:27. What is the ratio of their radii?

Answers

We have that the volume of the spheres have a ratio of 8:27.

[tex]undefined[/tex]

This means that the relation between linear measures, like the radii, will be the cubic root of that ratio

The table below shows possible outcomes when two spinners that are divided into equal sections are spun. The first spinner is labeled with five colors, and the second spinner is labeled with numbers 1 through 5. Green Blue Pink Yellow Red 1 Gi B1 P1 Y1 R1 1 2 . G2 B2 P2 Y2 R2 3 G3 B3 P3 Y3 R3 4 G4 B4 P4 Y4 R4 5 G5 B5 P5 Y5 R5 According to the table, what is the probability of the first spinner landing on the color pink and the second spinner landing on the number 5?

Answers

Answer:

P = 0.04

Explanation:

The probability is equal to the number of options where the first spinner is landing on the color pink and the second spinner is landing on the number 5 divided by the total number of options.

Since there is only one option that satisfies the condition P5 and there are 25 possible outcomes, the probability is:

[tex]P=\frac{1}{25}=0.04[/tex]

So, the answer is P = 0.04

Write an expression to determine the surface area of a cube-shaped box, S A , in terms of its side length, s (in inches).

Answers

The cube consists of 6 equal faces thus the surface area of the cube in terms of its side length s is 6s².

What is a cube?

A three-dimensional object with six equal square faces is called a cube. The cube's six square faces all have the same dimensions.

A cube is become by joining 6 squares such that the angle between any two adjacent lines should be 90 degrees.

A cube is a symmetric 3 dimension figure in which all sides must be the same.

The cube has six equal squares.

It is known that the surface area of a square = side²

Therefore, the surface area of the given cube is 6 side².

Given cube has side length = s

So,

Surface area = 6s²

Hence the cube consists of 6 equal faces thus the surface area of the cube in terms of its side length s is 6s².

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Question
Mrs. Hanson has a potato salad recipe that calls for 238 pounds of potatoes, but she wants to make 112 times as much as the recipe calls for.

The diagram represents the number of pounds of potatoes that Mrs. Hanson needs.

How many pounds of potatoes does Mrs. Hanson need?

Answers

Answer:

3 9/16 lbs

Step-by-step explanation:

12/13+-1/13 equals what ?

Answers

Given:

[tex]\frac{12}{13}+(-\frac{1}{13})[/tex]

Adding a negativen number is the same as subtracting that number, so:

[tex]\frac{12}{13}-\frac{1}{13}[/tex]

Since both denominators (bottom number ) are equal we can subtract the numerators ( top numbers)

[tex]\frac{(12-1)}{13}=\frac{11}{13}[/tex]

Answer:

[tex]\frac{11}{13}[/tex]

3. The data in the table gives the number of barbeque sauce bottles (y) that are sold with orders of chicken wings (x) for each hour on a given day at Vonn's Grill. Use technology to write an equation for the line of best fit from the data in the table below. Round all values to two decimal places.

Answers

1) Let's visualize the points

2) To find the equation for the line of best fit we'll need to follow some steps.

2.1 Let's find the mean of the x values and the mean of the Y values

2.2 Now It's time to find the slope, with the summation of the difference between each value and the mean of x times each value minus the mean over the square of the difference of the mean of x and x.

To make it simpler, let's use this table:

The slope then is the summation of the 5th column over the 6th column, we're using the least square method

[tex]m=\frac{939.625}{1270.875}=0.7393\cong0.74[/tex]

The Linear coefficient

[tex]\begin{gathered} b=Y\text{ -m}X \\ b=14.625-0.73(19.875) \\ b=0.11625\cong0.12 \end{gathered}[/tex]

3) Finally the equation of the line that best fit is

[tex]y=0.73x+0.12[/tex]

Shaun deposits $3,000 into an account that has an rate of 2.9% compounded continuously. How much is in the account after 2 years and 9 months?

Answers

The formula for finding amount in an investment that involves compound interest is

[tex]A=Pe^{it}[/tex]

Where

A is the future value

P is the present value

i is the interest rate

t is the time in years

e is a constant for natural value

From the question, it can be found that

[tex]\begin{gathered} P=\text{ \$3000} \\ i=2\frac{9}{12}years=2\frac{3}{4}years=2.75years \end{gathered}[/tex][tex]\begin{gathered} e=2.7183 \\ i=2.9\text{ \%=}\frac{2.9}{100}=0.029 \end{gathered}[/tex]

Let us substitute all the given into the formula as below

[tex]A=3000\times e^{0.29\times2.75}[/tex][tex]\begin{gathered} A=3000\times2.21999586 \\ A=6659.987581 \end{gathered}[/tex]

Hence, the amount in the account after 2 years and 9 months is $6659.99

Factor the quadratic expression2x²+x-62x+ +x-6= (Factor completely.)

Answers

2x² + x - 6

The coefficient of x² is 2 and the constant term is -6. The product of 2 and -6 is -12. The factors of -12 which sum 1 are -3 and 4 so:

2(2x - 3) + x(2x - 3)

Factor 2x - 3 from 2(2x - 3) + x(2x - 3):

(2x - 3)(x + 2)

Use the appropriate differenatal formula to find© the derivative of the given function6)3(16) 96) = (x²-1) ²(2x+115

Answers

[tex]\begin{gathered} a)f^{\prime}(x)=\sqrt{1+x^{2}}+\frac{2x^{2}}{3(1+x^{2})^{\frac{2}{3}}} \\ \\ b)f^{\prime}(x)=\frac{6x(x^{2}-1)^{2}(2x+1)-2(x^{2}-1)^{3}}{(2x+1)^{2}} \end{gathered}[/tex]

1) We need to differentiate the following functions:

[tex]\begin{gathered} a)\:f(x)=x\sqrt[3]{1+x^2}\:\:\:\:Use\:the\:product\:rule \\ \\ \\ \frac{d}{dx}\left(x\right)\sqrt[3]{1+x^2}+\frac{d}{dx}\left(\sqrt[3]{1+x^2}\right)x \\ \\ \\ 1\cdot \sqrt[3]{1+x^2}+\frac{2x}{3\left(1+x^2\right)^{\frac{2}{3}}}x \\ \\ \sqrt[3]{1+x^2}+\frac{2x^2}{3\left(x^2+1\right)^{\frac{2}{3}}} \\ \\ f^{\prime}(x)=\sqrt[3]{1+x^2}+\frac{2x^2}{3\left(1+x^2\right)^{\frac{2}{3}}} \end{gathered}[/tex]

Note that we had to use some properties like the Product Rule, and the Chain Rule.

b) We can start out by applying the Quotient Rule:

[tex]\begin{gathered} g(x)=\frac{(x^2-1)^3}{(2x+1)} \\ \\ f^{\prime}(x)=\frac{\frac{d}{dx}\left(\left(x^2-1\right)^3\right)\left(2x+1\right)-\frac{d}{dx}\left(2x+1\right)\left(x^2-1\right)^3}{\left(2x+1\right)^2} \\ \\ Differentiating\:each\:part\:of\:that\:quotient: \\ \\ ------- \\ \frac{d}{dx}\left(\left(x^2-1\right)^3\right)=3\left(x^2-1\right)^2\frac{d}{dx}\left(x^2-1\right)=6x\left(x^2-1\right)^2 \\ \\ \frac{d}{dx}\left(x^2-1\right)=\frac{d}{dx}\left(x^2\right)-\frac{d}{dx}\left(1\right)=2x \\ \\ \frac{d}{dx}\left(x^2\right)=2x \\ \\ \frac{d}{dx}\left(1\right)=0 \\ \\ \frac{d}{dx}\left(2x+1\right)=2 \\ \\ Writing\:all\:that\:together: \\ \\ f^{\prime}(x)=\frac{6x\left(x^2-1\right)^2\left(2x+1\right)-2\left(x^2-1\right)^3}{\left(2x+1\right)^2} \\ \end{gathered}[/tex]

Thus, these are the answers.

ten B В 15 cm А 20 cm С C

Answers

Tangent segment, of a circle

Apply formulas

20^2 - 15^ 2 = AB^2

Also

15^2 = 20•( 20 - AB)

225 = 400 - 20AB

Then

20AB = 400-225= 175

AB = √ 175= 13 + 6/25 =13.24

Explain when you can cancel a number that is in both the numerator and denominator and when you cannot cancel out numbers that appear in both the numerator and the denominator.

Answers

Let me write here an example of a common number/term in both numerator and denominator that we can cancel.

[tex]\frac{4xy}{4}=xy[/tex]

In the above example, we are able to cancel out the common number 4 because they are stand alone numbers. We can divide 4 by 4 and that is 1. Hence, the answer is just xy.

Another example:

[tex]\frac{(x+2)(x-1)}{(x+2)(2x-1)}=\frac{(x-1)}{(2x-1)}[/tex]

In the above example, we are able to cancel out (x + 2) because this term is a common factor to both numerator and denominator.

In the example, we can also see that -1 is a common number however, we cannot cancel it out because the number -1 is not a standalone factor. It is paired with other number/variable. (x - 1) and (2x - 1) are both factors but are not the same, that is why, we are not able to cancel that.

Another example:

[tex]\frac{(x+2)+(x-1)}{(x+2)+(2x-1)}=\frac{(x+2)+(x-1)}{(x+2)+(2x-1)}[/tex]

As we can see above, (x + 2) is a common term however, we cannot cancel it. We can only cancel common terms if they are common factors of both numerator and denominator. (Notice the plus sign in the middle. )

The term (x + 2) above is not a factor of the numerator and denominator, hence, we cannot cancel it.

69=2g-24 I NEED TO FIND G

Answers

G = 46.5

Add 24 to 69 to get 93. Then divide 93 by 2 to get G

A local real estate company has 5 real estate agents. The number of houses that each agent sold last year is shown in the bar graph below. Use this bar graph to answer the questions.

Answers

Given:

Rachel sold 4 houses.

Heather sold 4 houses.

Kaitlin sold 12 houses.

Lena sold 11 houses.

Deshaun sold 3 houses.

Required:

a) We need to find which agent sold the most houses.

b) We need to find the number of houses Lna soldemore than Heather.

c) We need to find the number of agents who sold fewer than 4 houses.

Explanation:

a)

The greatest number of houses sold =12 houses.

Kaitlin sold 12 houses.

Answer:

The agent Kaitlin sold the most houses.

The agent sold 12 houses.

b)

Lena sold 11 houses.

Heather sold 4 houses.

The difference between 11 and 4 is 11-4 =7.

Answer:

Lena sold 7 housmore than Heather

If the two triangles shown below are similar based on the giveninformation, complete the similarity statement, otherwise choose the"Not Similar" button.А18 in9 inHB7 in14 inACAB-ANot Similar

Answers

1) Two triangles are similar if they have congruent angles and proportional sides (for each corresponding leg).

2) So let's check whether there are similar triangles by setting a proportion:

[tex]\begin{gathered} \frac{HC}{CA}=\frac{JH}{CB} \\ \frac{9}{18}=\frac{7}{14} \\ Simplify\text{ both:} \\ \frac{1}{2}=\frac{1}{2} \end{gathered}[/tex]

3) So yes they are similar, i.e. ΔCAB ~ΔHGJ

Based on the experimental probability, predict the number of times that you will roll a 5 if you roll the number cube 300 timesExperiment result on previews question: The number 5 was rolled 9 times out of 20 on a previous question

Answers

Explanation: To understand this problem we need to know that there are two different types of probability. The experimental probability and the theoretical probability.

- The experimental probability occurs once you conduct the experiment and after the experiment, you calculate the probability using the result of the experiment.

- The theoretical probability occurs before the experiment. Once you have information about the situation so you calculate the probability the get a specific result before trying.

Step 1: For this question, once we have a number cube with faces 1,2,3,4,5 and 6 and we want to know the experimental probability to get a 5 once you roll the cube 300 times you would need to get in real life a number cube and to roll it 300 times. After this experiment we would get all the results of each time we roll it and we would know how many times (from 300 times) we got a number 5. After that, we would use the following formula

[tex]Experimental_{probability}=\frac{number\text{ of times we got a number 5}}{300}[/tex]

Once the get this result we finish the question.

Consider the following functions round your answer to two decimal places if necessary

Answers

Solution

Step 1:

[tex]\begin{gathered} f(x)\text{ = }\sqrt{x\text{ + 2}} \\ \\ g(x)\text{ = }\frac{x-2}{2} \end{gathered}[/tex]

Step 2

[tex]\begin{gathered} (\text{ f . g\rparen\lparen x\rparen = }\sqrt{\frac{x-2}{2}+2} \\ \\ (\text{ f . g\rparen\lparen x\rparen }=\text{ }\sqrt{\frac{x\text{ +2}}{2}} \end{gathered}[/tex]

Step 3

Domain definition

[tex]\begin{gathered} The\:domain\:of\:a\:function\:is\:the\:set\:of\:input\:or\:argument\:values \\ \:for\:which\:the\:function\:is\:real\:and\:defined. \\ \mathrm{The\:function\:domain} \\ x\ge \:-2 \\ \\ \:\mathrm{Interval\:Notation:}\text{ \lbrack-2, }\infty) \end{gathered}[/tex]

Final answer

A committee of five members is to be randomly selectedfrom a group of nine freshman and seven sophomores.Which expression represents the number of different committeesof three freshman and two sophomores that can be chosen?

Answers

The answer would be the product of the number of 3 freshman groups by 2 sophomores groups.

The number of 3 freshman groups is given by

[tex]C^9_3=\frac{9\times8\times7}{3\times2\times1}=84[/tex]

The number of 2 sophomore groups is given by

[tex]C^7_2=\frac{7\times6}{2\times1}=21[/tex]

Now, doing their product

[tex]21\times84=1764[/tex]

We have 1764 different committees of three freshman and two sophomores.

I need help on doing this finding the slope of a line

Answers

Given:

[tex](x_1,y_1)=(1,6)and(x_2,y_2)=(6,1)[/tex][tex]\text{Slope(m)=}\frac{y_2-y_1}{x_2-x_1}[/tex][tex]\text{Slope(m)=}\frac{1-6}{6-1}[/tex][tex]\text{Slope(m)}=-\frac{5}{5}[/tex][tex]\text{Slope (m)=-1}[/tex]

Can someone do it for me please

Answers

Step-by-step explanation:

13.

a/7 + 5/7 = 2/7

a/7 = 2/7 - 5/7 = -3/7

a = -3

14.

6v - 5/8 = 7/8

6v = 7/8 + 5/8 = 12/8

v = 12/8 / 6 = 2/8 = 1/4

15.

j/6 - 9 = 5/6

j - 54 = 5

j = 5 + 54 = 59

16.

0.52y + 2.5 = 5.1

0.52y = 5.1 - 2.5 = 2.6

y = 2.6/0.52 = 5

17.

4n + 0.24 = 15.76

4n = 15.76 - 0.24 = 15.52

n = 15.52/4 = 3.88

18.

2.45 - 3.1t = 21.05

-3.1t = 21.05 - 2.45 = 18.6

t = 18.6/-3.1 = -6

Other Questions
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