At 75 degrees Celsius, water's autoionization constant, Kw, is 2.0 10 13. The quantity of dissociation of water molecules to form hydronium and hydroxide ions is indicated by the autoionization constants of water.
It should be remembered that the autoionization constant rises as the temperature rises. Kw equals 1.0 x 10-14 [H+][OH-]. Hence, one may determine the [H+] or [OH-] as needed for any liquid at 25°C in any given aquatic condition. Indicate if the substance is acidic, basic, or neutral.
Kwh of electricity are units of energy that represent one megawatt of electricity for one hour (unit symbol: kWh or kWh; frequently abbreviated as kWh). It represents 3.6 megajoules (MJ) in SI-derived units with specific names.
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At 75 degrees Celsius, water's autoionization constant, Kw, is 2.0 10 13. Water's pOH at 75 degrees Celsius is 6.85 as a result.
Using the relationship between the amounts of hydrogen ions (H+) and hydroxide ions (OH) and the ion product constant for water (Kw), we can begin to solve this issue:
Kw = [H⁺][OH⁻]
Kw = [H⁺][OH⁻]
1.995 x 10⁻¹³ = [H⁺][OH⁻]
Since water is neutral, the concentration of hydrogen ions and hydroxide ions must be equal.
[H⁺] = [OH⁻]
Hence, the equation can be rewritten as follows:
1.995 x 10⁻¹³ = [OH⁻]²
When we solve for [OH], we get:
[OH⁻] = √(1.995 x 10⁻¹³) = 1.414 x 10⁻⁷
We can now apply the correlation between pOH and [OH]:
pOH equals -log[OH]
By entering [OH] as the value, we obtain:
pOH is equal to -log(1.414 x 107) = 6.85.
Water's pOH at 75 degrees Celsius is 6.85 as a result.
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Compose the cathode and anode processes of electrolysis of an aqueous solution Li2SO4, the total electrolysis equation
Answer:
Explanation:
The electrolysis of an aqueous solution of Li2SO4 involves the following processes:
At the cathode:
2H2O + 2e- → H2 (g) + 2OH-
At the anode:
2OH- → 1/2O2 (g) + H2O + 2e-
The overall reaction for the electrolysis of Li2SO4 is:
2Li2SO4 (aq) + 2H2O (l) → 2LiOH (aq) + H2 (g) + SO2 (g) + 1/2O2 (g)
Note: The reaction also produces SO2 gas in addition to H2 and O2.
Antifreeze containing ethylene glycol is also needed in automobiles in extremely hot climates. Using what you know about other colligative properties, explain why this is so
The particles in…….can be separated from heterogeneous mixtures by passing the mixture through a filter.
-suspension
-solution
-colloid
-pure substance
The particles in the solution can be separated from heterogeneous mixtures by passing the mixture through a filter (option b).
How particles in the solution can be separated?The particles in the solution can be separated by using different types of methods such as for example a filter that is able to separate particles depending on their size or net charge.
Therefore, with this data, we can see that particles in the solution can be separated depending on their sizes, electrical charges, etc, and for that purpose, we can use a filter of any other type of method.
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The formation of hydrazine (N2H4) from its elements takes place by the following reaction equation.
N2 (g) + 2 H2 (g) → N2H4 (g)
What are the volumes of N2 gas and H2 gas required to form 28. 5 grams of N2H4 at 30oC and 1. 50 atm?
The volumes of N₂ gas and H₂ gas required to form 28.5 grams of N₂H₄ at 30oC and 1.50 atm are 14.3 L and 28.6 L, respectively.
To determine the volumes of N₂ gas and H₂ gas required to form 28.5 grams of N₂H₄ at 30oC and 1.50 atm, we need to use the ideal gas law to calculate the number of moles of each gas needed, and then use the balanced chemical equation to determine the volume of each gas.
Calculate the number of moles of N₂H₄
The molar mass of N₂H₄ is:
Molar mass N₂H₄ = 2 x molar mass N + 4 x molar mass H
Molar mass N₂H₄ = 2 x 14.01 g/mol + 4 x 1.01 g/mol
Molar mass N₂H₄ = 32.05 g/mol
The number of moles of N₂H₄ can be calculated as follows:
n(N₂H₄) = mass / molar mass
n(N₂H₄) = 28.5 g / 32.05 g/mol
n(N₂H₄) = 0.890 mol
Determine the number of moles of N₂ and H₂ required
From the balanced chemical equation, we see that 1 mole of N₂ reacts with 2 moles of H₂ to produce 1 mole of N₂H₄. Therefore, the number of moles of N₂ and H₂ required can be calculated as follows:
n(N₂) = n(N₂H₄) = 0.890 mol
n(H₂) = 2 x n(N₂H₄) = 1.780 mol
Use the ideal gas law to calculate the volumes of N2 and H2
The ideal gas law is given by:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant (0.0821 L atm/mol K), and T is the temperature in Kelvin.
We are given P = 1.50 atm and T = 30oC = 303 K.
For N₂ gas:
n(N₂) = 0.890 mol
R = 0.0821 L atm/mol K
T = 303 K
P = 1.50 atm
Solving for V, we get:
V(N₂) = n(N₂)RT/P
V(N₂) = 0.890 mol x 0.0821 L atm/mol K x 303 K / 1.50 atm
V(N₂) = 14.3 L
For H₂ gas:
n(H₂) = 1.780 mol
R = 0.0821 L atm/mol K
T = 303 K
P = 1.50 atm
Solving for V, we get:
V(H₂) = n(H₂)RT/P
V(H₂) = 1.780 mol x 0.0821 L atm/mol K x 303 K / 1.50 atm
V(H₂) = 28.6 L
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HELP Will GIVE BRAINIEST the soil textural triangle
According to the information in the graph, the soil with the composition of Sand: 20%, Clay 50% and Silt 30%, would be a silty clay soil.
What is the soil texture triangle?The Soil Texture Triangle is a term to refer to a soil analysis tool that is used to calculate the percentage of each component in a soil. The components used in this graph are: Clay, silt and sand. For example, if a soil contains 60% sand, 30% silt and 10% clay, it corresponds to a sandy loam texture.
According to the above, we can infer that a soil with the components of Sand: 20%, Clay 50% and Silt 30% would be a silty clay soil.
Note: This question is incomplete. Here is the complete information:
Classify the soil based on its composition: Sand: 20%, Clay 50% and Silt 30%.
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Alcohols are a key intermediate in organic synthesis since they can oxidized to carbonyl containing functional groups. In this tutorial, we will cover: 1. what happens in an oxidation reaction 2. oxidation of secondary alcohols to ketones 3. oxidation of primary alcohols to aldehydes or carboxylic acids 4. oxidation reagents and how we can control oxidation The previous example showed the simplest alcohol and the oxidation products expected. Note that the oxidation of an alcohol to a higher oxidation state involves loss of hydrogens. This means that tertiary alcohols cannot be oxidized, since it does not have a hydrogen that can be lost. Longer primary and secondary alcohols can also be oxidized. Which of the reactions shown Constitute an oxidation reaction? CH, CHO CH,CH,OH CH,CO,CH CH,CH, OH CH, COH CH CHO - CH.CH OH > OH
The reactions that constitute oxidation reaction are, CH3CH2OH --> CH3CHO, CH3CHO --> CH3COOH, CH3CH2CH2OH --> CH3COCH3.
An oxidation reaction is a chemical reaction in which an atom or molecule loses one or more electrons. In the case of alcohols, oxidation typically involves the loss of hydrogen atoms and the addition of oxygen atoms to form a carbonyl-containing functional group.
The reactions that constitute an oxidation reaction are the ones that involve the loss of hydrogen atoms and the addition of oxygen atoms. In the examples given, the following reactions are oxidation reactions:
1) CH3CH2OH --> CH3CHO (oxidation of a primary alcohol to an aldehyde)
2) CH3CHO --> CH3COOH (oxidation of an aldehyde to a carboxylic acid)
3) CH3CH2CH2OH --> CH3COCH3 (oxidation of a secondary alcohol to a ketone)
The other reactions shown do not involve the loss of hydrogen atoms or the addition of oxygen atoms, and therefore do not constitute oxidation reactions.
Oxidation reagents are chemical compounds that are used to carry out oxidation reactions. Some common oxidation reagents include chromic acid (H2CrO4), potassium permanganate (KMnO4), and sodium hypochlorite (NaClO).
The choice of oxidation reagent and the reaction conditions can be used to control the level of oxidation and the products formed.
For example, using a milder oxidation reagent or lower reaction temperatures can help prevent over-oxidation of the alcohol to a carboxylic acid.
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The temperature of an ideal gas in a sealed container of volume V is increased from T to 3T. What will happen to the pressure, P of this gas?
a. It increases from P to 2P
b. There is no change
c. It increases from P to 3P.
d. It decreases from P to P/3
The temperature of an ideal gas in a sealed container of volume V is increased from T to 3T. The pressure, P of this gas increases from P to 3P. The correct answer is c.
According to the ideal gas law, PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the gas constant, and T is temperature.
If the volume and number of moles of gas are kept constant, then the equation can be simplified to P/T = nR/V. This means that the pressure of the gas is directly proportional to its temperature.
If the temperature of the gas is increased from T to 3T, then the pressure will also increase by a factor of 3. Therefore, the pressure will increase from P to 3P.
So the correct answer is c. It increases from P to 3P.
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Where did the Earth’s “building blocks of life” come from?
Answer:
Australia about half a century ago, scientists have been tantalized by the possibility that the building blocks of life originated in space
Set 1 - Use the balanced chemical equation for the production of rust to solve:
4 Fe + 3 O2 → 2 Fe2O3
If you produced 0.00521 moles Fe2O3, how many moles of Fe were reacted?
If you need to produce 1.867 mol Fe2O3, how many moles O2 are needed to react?
Given 9.54 mol Fe, how many moles O2 will be needed?
Given 0.578 mol O2, how many moles Fe will be needed to react completely?
Answer:
Explanation:
0.01042 moles Fe --how to calculate (0.00521/2 moles X 4 moles) the 2 and 4 are the coefficients in the chemical equation
2.8005 moles O2-- how to calculate (1.867 / 2 X 3 moles O2)
7.155 moles Fe calculate it this way (9.54 / 4 moles Fe X 3 moles O2
0.7707 moles Fe ---(0.578 / 3 moles O2 X 4 moles Fe)
Trans-1,3-dichlorocyclobutane has a meausurable dipole moment. Explain why the individual dipole g
Trans 1,3-Dichlorocyclobutane. The C-cl bonds are opposed to one another, thus the dipole moment should cancel out and be zero. Nevertheless, because of the four-member ring strain, cyclobutene is stable in a puckered configuration with three carbons in one plain and one carbon above the plain.
Because one C-Cl bond in cyclobutene [Trans-1,3-dichlorocyclobutane] is axial and the other is equatorial, they won't cancel each other out and the net dipole moment won't be zero. This hopping never stops. When there is a separation of charge, dipole moments happen. They can occur between two ions in an ionic bond or between atoms in a covalent link; dipole moments result from changes in electronegativity. The dipole moment increases with the difference in electronegativity.
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Complete Question:
Trans-1,3-dichlorocyclobutane has a measurable dipole moment. Explain why the individual dipole moments of C-Cl bonds do not cancel each other t produce a zero net dipole moment?
CHEMISTRY EXCERCISES
1. (a) Class: carboxylic acid; IUPAC name: propanoic acid. (b) Class: alkyl halide; IUPAC name: chloro-1-propane. (c) Class: alkane; IUPAC name: 1-propanecarbonitrile. (d) Class: ester; IUPAC name: ethyl methanoate.
What is IUPAC name?IUPAC stands for International Union of Pure and Applied Chemistry. It is an international scientific organization responsible for developing and promoting international standards in the fields of chemistry and chemical nomenclature. The IUPAC name of a chemical compound is an unambiguous, systematic method for naming compounds according to their chemical structure and physical properties.
(e) Class: ether; IUPAC name: dimethyl ether. (f) Class: acyl halide; IUPAC name: 1-chloro-2,2-difluoropropane-1-carbonyl chloride.
2. (a) Hexanoic acid: CH3CH2CH2CH2CH2COOH. (b) Butanal: CH3CH2CHO. (c) Pent-1-ene: CH2=CHCH2CH2CH3. (d) 1-bromo-2-methylbutane: CH3CH2CH(Br)CH3. (e) Ethyl methanoate: CH3COOCH2CH3. (f) Methoxypropane: CH3OCH2CH3. (g) But-2-yne: CH3C≡CHCH3.
3. Answer: B. CH3CONH2 is an amine because it contains an amine group (NH2).
4. Answer: A. 1-iodopropane is a member of the same homologous series as 1-bromopropane because they both have the same molecular formula (C3H7Br or C3H7I) and the same functional group (halogen).
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A container of gas has a pressure of 745 mm Hg and room temperature is 18 C. How does the temperature of the system change when the pressure is changed to 1 atm?
What increases when a wave period decreases.
depth
distance
energy
speed
time
volume
Imagine there are two large boxes that have the same dimension standing on top of a shaking platform. A student fills up the first box with wooden balls of equal size. The same student fills up the second box with hollow bronze balls of equal size. The bronze balls have a bigger radius but weigh less than the wooden balls. Which set of balls has higher atomic packing factor (APF)? The size of the boxes are much larger than the size of the balls.
a) Box filled with wooden balls has higher APF.
b) Box filled with bronze balls has higher APF. Neither.
c) The APF of both boxes are the same.
d) There is not enough information to make a comparison
The right response is b) APF is higher for a box filled with bronze balls.
The atomic packing factor (APF) is a measure of the amount of space that is occupied by atoms in a crystal structure. It is calculated by dividing the total volume of atoms in a unit cell by the volume of the unit cell. The higher the APF, the more closely packed the atoms are in the crystal structure.
In this case, since the boxes have the same dimensions, the unit cell for both boxes will be the same. However, the size and weight of the balls differ. The wooden balls are more massive than the hollow bronze balls, but they are smaller in size. This means that the wooden balls will have a higher density and will occupy less space than the hollow bronze balls.
Since the APF is calculated based on the volume of atoms in the unit cell divided by the volume of the unit cell, the size and density of the balls will affect the APF. In this case, the hollow bronze balls will occupy more space in the unit cell compared to the wooden balls, as they have a larger radius and lower density. Therefore, the box filled with hollow bronze balls will have a higher APF compared to the box filled with wooden balls.
Therefore, the correct answer is b) Box filled with bronze balls has higher APF.
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2. From class discussions and observations, write a general rule for what happens to particles in
solids, liquids, and gases when they are warmed or cooled. Are there exceptions to this rule?
(3 Marks)
Warmed:
Cooled:
Exceptions:
Answer:
General rule:
When solids, liquids, and gases are warmed, the particles gain kinetic energy and move faster, resulting in an increase in volume for liquids and gases, and a small expansion for solids. When cooled, the particles lose kinetic energy and move slower, resulting in a decrease in volume for liquids and gases, and a small contraction for solids.
Exceptions:
There are some exceptions to this rule, such as water, which exhibits anomalous behavior upon cooling. Water contracts upon cooling until it reaches 4°C, then it begins to expand upon further cooling. Additionally, some solids exhibit a unique property called thermal expansion, where they expand upon heating and contract upon cooling, opposite to the expected behavior.
How many grams are found in 5. 000 mol of carbon tetrachloride
769.11 grams are found in 5.000 mole of carbon tetra chloride. It is calculated by using Mole concept.
The mole is defined as the unit of amount of substance in the International System of Units (SI). The quantity amount of the substance is a measure of how many elementary entities of a given substance are in an object or the sample. The mole is known as containing exactly 6.02214076×1023 elementary entities. It is used in chemistry as a convenient way to express amounts of reactants and products of chemical reactions. The molar mass of a substance is defined as the ratio of the mass of a sample of that substance to its amount of substance. It is clear the the amount of substance is given as the number of moles in the sample. One mole of a substance is equal to 6.022 × 10²³ units of that substance such as of atoms, molecules, or ions.
The number 6.022 × 10²³ is known as the Avogadro's number or the Avogadro's constant. According to the mole concept, the concept of the mole is used to convert between mass and number of particles.
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How many grams of ammonia are needed to make 1.25 L solution with a pH of 11.68?
The mass (in grams) of ammonia, NH₃ needed to make 1.25 L solution with a pH of 11.68 is 0.102 grams
How do i determine the mass of ammonia needed?First, we shall determine the hydroxide ion concentration in the solution. Details below:
pH of solution = 11.68pOH = 14 - 11.68 = 2.32Hydroxide ion concentration [OH⁻] =?pH of a solution is given by the following formula:
pOH = -Log [OH⁻]
Inputting the various parameters, we have
2.32 = -Log [OH⁻]
Multiply through by -1
-2.32 = Log [OH⁻]
Take the anti-log of -2.32
[OH⁻] = Anti-log -2.32
[OH⁻] = 0.0048 M
Next, we shall determine the molarity of the ammonia. Details below:
NH₃(aq) + H₂O <=> NH₄⁺(aq) + OH⁻(aq)
From the above equation,
1 mole of OH⁻ is present in 1 mole of NH₃
Therefore,
0.0048 M OH⁻ will also be present in 0.0048 M NH₃
Next, we shall determine the mole of ammonia. Details below:
Volume = 1.25 LMolarity = 0.0048 MMole of ammonia =?Molarity = Mole / Volume
Cross multiply
Mole of ammonia = molarity × volume
Mole of ammonia = 0.0048 × 1.25
Mole of ammonia = 0.006 mole
Finally, we shall determine the mass of ammonia needed. Details below:
Mole of ammonia = 0.006 moleMolar mass of ammonia = 17 g/molMass of ammonia = ?Mass = Mole × molar mass
Mass of ammonia = 0.006 × 17
Mass of ammonia = 0.102 grams
Therefore, the mass of ammonia needed is 0.102 grams
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if 0.435 g of KMnO4 is dissolved in enough water to give 250 ml of solution, what is the molarity of
KMnO4?
ASAPP PO!! thankyouu!!!!!
Answer:
M = 0.011 mol/L
Explanation:
Molarity = n/V,
n: No. of moles
V: volume in liters
n of KMnO4 (Molar mass = 158 g/mol) = 0.435/158 = 0.00275 moles
Molarity (M) = 0.00275/0.25 = 0.011 mol/L
what is the common name of the following compound? acetone propanal propanone 1-propyl ketone 2-propyl ketone
The common name of the following compound is Acetone.
Acetone is an organic compound that is a colorless, volatile, and flammable liquid. This compound is the most basic ketone and has a variety of applications, including as a solvent, a laboratory reagent, and a precursor to a number of other compounds.It is produced naturally by the human body in minute quantities as a metabolic intermediate. Acetone is also produced naturally by certain plants as a metabolic byproduct.
Acetone is miscible with water and a number of organic solvents, making it an excellent solvent for a variety of applications. Because of its high solvency power, it is used to remove substances like paint and glue from surfaces like plastics and metals. It is also used in the production of polycarbonate plastics and other polymeric materials.
acetone propanal propanone 1-propyl ketone 2-propyl ketone is a ketone with three carbon atoms. The IUPAC name of this compound is propanone, but its common name is acetone.
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pls i already asked for help with this but im honestly just so lost and my parents dont understand. i really need this done and ive been trying to understand it and figure it out but i cant
Answer: 3 ,2, 6
Explanation:
3 Cu(NO3)2 + 2 K3PO4 → Cu3(PO4)2 + 6 KNO3
Why is it important to monitor pollutants in watershed?
monitoring pollutants in a watershed is critical for protecting human health, aquatic ecosystems, and the environment.
It provides valuable information for decision-making, compliance with environmental regulations, and early warning of potential environmental problems.
Monitoring pollutants in a watershed is important for several reasons:
Protecting human health: Polluted water can pose serious health risks to humans.
Protecting aquatic ecosystems: Polluted water can harm aquatic plants and animals.
Compliance with environmental regulations: Polluted water can violate environmental regulations and harm the reputation of businesses and organizations.
Early warning of environmental problems: Monitoring pollutants in a watershed can provide early warning of potential environmental problems. This can help officials take preventive measures to protect the environment and public health before serious problems occur.
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In which of the following reactions is mass and/or
charge not conserved?
A) H₂O → H+ + OH-
B) CIO2 + 2 H2O + 4e → Cl- + 4 OH-
C) H2SO4 + NaOH → Na2SO4 + H+ + 2 OH-
D) ZnCl + H₂O → ZnOH + H+ + Cl−
E) none of the above
Answer:
The answer is E) none of the above.
In all of the given reactions, mass and charge are conserved. The law of conservation of mass states that the mass of reactants must be equal to the mass of the products in a chemical reaction. The law of conservation of charge states that the total charge of the reactants must be equal to the total charge of the products.
In reaction A, the water molecule dissociates into a hydrogen ion (H+) and a hydroxide ion (OH-), but the total mass and charge are still conserved.
In reaction B, the reduction of CIO2 to Cl- is balanced by the oxidation of water to form OH-. The electrons and charge are conserved.
In reaction C, H2SO4 reacts with NaOH to form Na2SO4, H+ and OH-. The mass and charge are conserved.
In reaction D, ZnCl reacts with water to form ZnOH, H+ and Cl-. The mass and charge are also conserved.
What is the mass of 3.01x 1022 molecules of phosphorus, P4 ? {R.AM for phosphorus is 31} *
A gas is known to be one of the following nitrogen oxides: NO, NO2, N2O4, or N2O. It has a density of 1.96 g/L at 273 K and 1.00 atm. Determine its identity.
Please write out the steps too, I am so lost on how to start this question. Thank you so much!
That the calculated molar mass of the gas is closest to the molar mass of N2O. Therefore, the gas is most likely N2O.
What is Density?
Density is a physical property of matter that describes how much mass is contained in a given volume. It is defined as the amount of mass per unit volume, and is typically expressed in units of grams per cubic centimeter (g/cm3) or kilograms per cubic meter (kg/m3).
The gas density and the conditions provided can be used to calculate the molar mass of the gas using the ideal gas law:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
Rearranging this equation to solve for n/V, we get:
n/V = P/RT
M = m/n
where M is the molar mass, m is the mass of the gas, and n is the number of moles.
Since the density is given in grams per liter, we can assume that 1 liter of the gas has a mass of 1.96 grams. Therefore, the number of moles of the gas in 1 liter can be calculated as:
n/V = P/RT = (1 atm)/(0.08206 L·atm/mol·K × 273 K) = 0.0446 mol/L
The number of grams of the gas in 1 liter can be calculated as:
m = density × volume = 1.96 g/L × 1 L = 1.96 g
Therefore, the molar mass of the gas is:
M = m/n = 1.96 g / 0.0446 mol = 43.9 g/mol
Comparing this molar mass to the molar masses of the possible nitrogen oxides:
NO has a molar mass of 30.01 g/mol
N2O4 has a molar mass of 92.01 g/mol
N2O has a molar mass of 44.01 g/mol
We can see that the calculated molar mass of the gas is closest to the molar mass of N2O. Therefore, the gas is most likely N2O.
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what happens during an exothermic reaction
Answer:
During an exothermic reaction, energy is released from the reacting system into the surrounding environment in the form of heat, light, or sound. This means that the products of the reaction have less energy than the reactants, and the overall change in enthalpy (∆H) of the system is negative.
Examples of exothermic reactions include combustion (burning of fuel), oxidation reactions, neutralization reactions, and many types of chemical reactions. In each case, the reaction releases heat or light as a result of the formation of new chemical bonds, which releases energy.
Exothermic reactions are important in many fields, including chemistry, physics, and engineering. They are used in everyday applications such as the burning of fuel in car engines, the production of heat and light from a match or a firework, and the generation of electricity from nuclear reactions.
Explanation:
What are the intermolecular forces present in theobromine?
The intermolecular forces in theobromine include hydrogen bonding and london dispersion.
Intermolecular bonds: What do they mean?Molecules can form intermolecular connections with one another. There are different kinds of them, and they are also called are van der Waals forces.
What occurs when intermolecular forces are applied?Bulk properties like liquid and solid boiling and melting points are governed by intermolecular forces. When the intermolecular attraction interactions that hold molecules together are strong enough for liquids to boil, vapor bubbles are created inside the liquid as a result of the boiling process.
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after you have tried all the materials, add a few drops of dishwashing liquid to the middle of the oil spill. this is the dispersant. answer the questions below. what happened to the oil? why? what happened to the chemicals (dye)? why? what color is the water? why?
The oil will disperse due to the emulsifying properties of the dishwashing liquid, which breaks the oil down into smaller droplets so it can mix with the water more easily. This reduces the overall surface tension, allowing the oil to spread out more evenly in the water. The chemicals (dye) that were added to the oil will be spread out as well, resulting in a less visible stain. The water will take on the color of the dye, so it will appear as a colored stain on the surface of the water.
The oil disperses because the dishwashing liquid acts as an emulsifier and reduces the surface tension of the oil, allowing it to spread out and mix with the water more easily. The dye is spread out as well, resulting in a less visible stain. The water will take on the color of the dye, giving the water a colored appearance.
Overall, the addition of the dishwashing liquid causes the oil to disperse, the dye to spread out, and the water to take on the color of the dye. This makes the oil less visible, making it easier to clean up.
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starting from a fatty acid (note: not acyl-coa) with 15 carbons and 3 double bonds, in the muscle, flag question: question 1 question 11 pts how many cycles of beta oxidation will occur? group of answer choices 2 4 5 6 8 flag question: question 2 question 21 pts how many fadh2 will be produced? group of answer choices 2 3 4 5 6 flag question: question 3 question 31 pts how many atps are produced for its complete oxidation to h2o and co2? group of answer choices 98.5 96.5 48.5 90.5 98 flag question: question 4 question 41 pts if a poison is added to block complex iii, how many atp are produced instead? group of answer choices 96.5 98.5 38 35 45
One FADH2 molecule is created for every beta oxidation cycle. Consequently, after the provided fatty acid is completely oxidised, a total of 7 FADH2 molecules will be created.
How many cycles does a 16 carbon fatty acid go through to convert a four carbon fatty acyl-CoA into two acetyl CoAs?In seven cycles of this oxidation, a 16-carbon fatty acid loses two carbons as acetyl-CoA, producing a total of eight molecules of acetyl-CoA.
How many cycles of -oxidation would be necessary to break down a 20 C fatty acyl chain?Nine rounds of beta oxidation are necessary to completely oxidise a fatty acid with a 20-carbon hydrocarbon tail because the organic byproduct of beta oxidation has two carbons.
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configurate the following element using sub level and group each elemnt v(z=23),Ni(z=28),Cu(z=29),zn(z=30),cr(z=24),Mn(z=25)
Answer:
To configure the electron sublevels and groups for each element, we can use the following format:
Element symbol: [Electron configuration] Sublevel: Group
V (Z=23): [Ar] 3d3 4s2 Sublevel: 3d, 4s Group: 5, 4
Ni (Z=28): [Ar] 3d8 4s2 Sublevel: 3d, 4s Group: 10, 4
Cu (Z=29): [Ar] 3d10 4s1 Sublevel: 3d, 4s Group: 11, 4
Zn (Z=30): [Ar] 3d10 4s2 Sublevel: 3d, 4s Group: 12, 4
Cr (Z=24): [Ar] 3d5 4s1 Sublevel: 3d, 4s Group: 6, 4
Mn (Z=25): [Ar] 3d5 4s2 Sublevel: 3d, 4s Group: 7, 4
calculate the mass fraction of CH3COOH in 3 litres of its 2M solution if the density of the solution is 0.981g/ml