The image seen here is caused by events __________ Earth's surface.
A) above
B) at
C) on
D) under

Answer: a burst

Explanation: a burst of energy could be substatuded for spark of energy

A spark of energy is required to begin the chemical reaction of burning a fossil fuel because; This spark of energy is required to attain the activation energy of the reaction.

Another name for this spark of energy is Ignition.

Definition:

The activation energy of a chemical reaction is the minimum amount of energy required for the commencement of the chemical reaction.

In this case, the spark of energy is required to attain the activation energy of the reaction.

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The correct decay series :

₈₄Po²¹⁴⇒₈₃Bi²¹⁰+₂He⁴+ ₋₁e⁰+ ₀γ⁰

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,  

Decay's reaction :

₈₄Po²¹⁴⇒₈₃Bi²¹⁰+x+y+z

From this decay reaction can be concluded

mass number decreased by 4

atomic number decreased by 1

Then the most suitable are:

Polonium-214 undergoes 1 alpha decay 1 beta decay and 1 gamma emission.

₈₄Po²¹⁴⇒₈₃Bi²¹⁰+₂He⁴+ ₋₁e⁰+ ₀γ⁰

So that the mass number and atomic number are the same both before and after decay

Answer:

Gibbs free energy equation

Explanation:

Answer:

False

Explanation:

humans have 23 pairs

Answer:

p orbitals

Explanation:

Answer:

The correct answer is a = 2 atm, b = 0.66 atm, and c = 1.66 atm.

Explanation:

a. When the temperature is constant, the ideal gas equation, that is, PV = nRT becomes PV = constant, or P1V1 = P2V2

Based on the given information, the pressure of the gas is 1.00 atm, the V1 of the gas is 78 ml, and the V2 of the gas is 39 ml.  

Now using the above formula we get,  

P2 = (P1V1) / (V2)

P2 = 1 atm * 78 ml/39 ml

P2 = 2 atm.  

b) Now the volume V1 is 43.5 ml, and the volume V2 is 65.5 ml at constant temperature, P1 is 1 atm. Now P2 will be,  

P2 = (P1V1) / (V2)

P2 = 1 atm * 43.5 ml/65.5 ml

P2 = 0.66 atm

c) In the given case, when the volume is decreased by 40 percent, let us consider that the volume, V1 be 100 ml, and the volume V2 be 60 ml, the P1 is 1 atm, now the P2 will be,  

P2 = (P1V1) / (V2)

P2 = 1 atm * 100 ml/60 ml

P2 = 1.66 atm.

Answer:

8Ag2S 16Ag + S8

Explanation:

Answer:

24.32 amu

Explanation:

From the question given above, the following data were obtained:

Isotope A (Mg–24):

Mass of A = 24 amu

Abundance (A%) = 79%

Isotope B (Mg–25):

Mass of B = 25 amu

Abundance (B%) = 10%

Isotope C (Mg–26):

Mass of C = 26 amu

Abundance (C%) = 11%

Average atomic mass of Mg =?

Average atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100] + [(Mass of C × C%)/100]

= [(24 × 79)/100] + [(25 × 10)/100] + [(26 × 11)/100]

= 18.96 + 2.5 + 2.86

= 24.32 amu

Thus, the average atomic mass of Mg is 24.32 amu

Answer:

7.8%

Explanation:

Given that:

The initial mass amount of aspirin = 0.020g

The standard molar mass of aspirin = 240 g/mol

Thus, the number of moles = mass/molar mass

= 0.020/240

= 0.0000833 moles

Now, the molarity of aspirin in the solution(diluted) [tex]C_1[/tex] = [tex]\dfrac{8.33 \times 10^{-5}}{0.01}[/tex]

= [tex]= 8.33 \times 10^{-3} \ M[/tex] (provided the volume v = 0.01 L)

The absorbance of the sample solution A =1.07

The path length (b) = 1 cm

From the standard value of salicylic acid, the coefficient (e)= 139.322 /M/cm

Now; according to Beer's law, the concentration of aspirin is:

A = e×b×c

[tex]c = \dfrac{A}{eb}[/tex]

[tex]c = \dfrac{1.07}{139.322 \times 1}[/tex]

c = 0.00768 M

Finally, relating the concentration of the aspirin, the percentage of salicylic acid the product  [tex]= \dfrac{0.00833-0.00768}{0.00833} \times 100[/tex]

= 7.8%

Answer:

[tex]189kJ[/tex]

Explanation:

Hello!

In this case, since one mole of ethanol release 8,842 J per 1 mole of ethanol, we can write:

[tex]\frac{8,842J}{1molC_2H_6H}[/tex]

Thus, since we need the energy released by 982.6 g of ethanol, we compute the moles in such mass of fuel:

[tex]n=982.6g\frac{1mol}{46.08g} =21.3mol[/tex]

Therefore, the result is:

[tex]\frac{8,842J}{1mol}*21.3mol=188,545J[/tex]

Which in kJ is:

[tex]189kJ[/tex]

Best regards!

Answer:

increases

Explanation:

Answer:

F i think i pretty sure F!!!!!!!!

Answer:

C

Explanation:

The third law of thermodynamics states that at absolute zero temperature, the entropy of a perfect crystal is zero. In other words, as the temperature of a system approaches zero, the entropy also approaches a constant value.

The law only holds true only if the crystal has minimal energy and only exist in one state. The entropy becomes zero as the temperature also becomes zero only for a perfect crystal. Otherwise, the law refuses to hold.

The correct option is, therefore, C.

Answer: 1. [tex]2H_2+O_2\rightarrow 2H_2O[/tex]

2. [tex]P_4+3O_2\rightarrow 2P_2O_3[/tex]

3. [tex]N_2+3H_2\rightarrow 2NH_3[/tex]

4. [tex]2K+Cl_2\rightarrow 2KCl[/tex]

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The given equations are balanced as:

1. [tex]2H_2+O_2\rightarrow 2H_2O[/tex]

2. [tex]P_4+3O_2\rightarrow 2P_2O_3[/tex]

3. [tex]N_2+3H_2\rightarrow 2NH_3[/tex]

4. [tex]2K+Cl_2\rightarrow 2KCl[/tex]

Answer:

no

Explanation:

Answer:

See explanation

Explanation:

Taking the acid catalysed hydrolysis of fructose C6H12O6, the mechanism begins with the protonation of an -OH group as shown.

This is now followed by dehydration and formation of a keto-enol tautomer. The keto form is now dehydrated followed by the protonation of a second -OH group.

A second dehydration followed by deprotonation leads to the formation of  5-hydroxymethylfurfural.

Image credit: SciElo

Answer:

yes its what the other person said

Explanation:

Answer:

I⁻ , Sr²⁺ , K⁺

Explanation:

refer to the periodic table and memorize trends in charges.

Answer:

D

Explanation:

D

Answer:

3.22  * 10^-4 M

Explanation:

The cell reaction equation is;

2Al(s) + 3Cu^2+(aq) ------> 2Al^3+(aq) + 3Cu(s)

E° = 0.337 V - (-1.66 V)

E° = 1.997 V

Given that the cell potential is 2.067 V, from Nernst's equation;

E = E° - 0.0592/n log Q

Substituting values;

2.067 = 1.997 - 0.0592/6 log [Al^3+]^2/[1.07]^3

0.07 = - 0.0592/6 log [Al^3+]^2/[1.07]^3

- 7.07 = log [Al^3+]^2/[1.07]^3

Antilog (- 7.07) =  [Al^3+]^2/[1.07] ^3

8.5 * 10^-8 =  [Al^3+]^2/[1.07]^3

[Al^3+]^2 = 8.5 * 10^8  * 1.07 ^3

[Al^3+]^2 = 1.04 * 10^-7

[Al^3+] = √1.04 * 10^-7

[Al^3+] = 3.22  * 10^-4 M

Answer:

75.1

Explanation:

The isomers contains the similar and accurate chemical formulas but at the same time the structure of the molecular is different. This represents that the masses of the molecular would be similar

Therefore the molecular mass of methyl ethanoate, i.e. an isomer propanoic acid is 75.1 i.e. equivalent to the molecular mass of the propanoic acid

So, it should be 75.1

Answer:

P₂ = 299.11 KPa

Explanation:

Given data:

Initial volume = 600 mL

Initial pressure = 70.00 KPa

Initial temperature = 20 °C (20 +273 = 293 K)

Final temperature = 40°C (40+273 = 313 K)

Final volume = 150.0 mL

Final pressure = ?

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₂ = P₁V₁ T₂/ T₁ V₂  

P₂ =  70 KPa × 600 mL × 313 K / 293K ×150 mL  

P₂ = 13146000 KPa .mL. K /43950 K.mL

P₂ = 299.11 KPa