The gravitational acceleration is 9.81 m/s2 here on earth at sea level. what is the gravitational acceleration on the top of mount everest?

Running up the flight of stairs produces more horsepower than strolling up them does. because running causes you to go through energy more quickly.

Work (in joules) equals your weight (in newtons) times the staircase's height (in meters.) The power you now possess is equal to the sum of the labor you completed and the time it took, or: Work (in joules) divided by time equals power (in watts) (in seconds.) The college alumnus questionnaire's physical activity index (PAI) is calculated on the basis of the assumption that every 20 steps is equivalent to 8 kcal of energy expenditure. This amount equates to a 0.40 kcal energy cost. You put in the same amount of effort as your potential energy changes.

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A transverse wave is one in which the motion of the medium's particles is perpendicular to the wave's direction of propagation.

A wave is a dynamic disturbance of one or more quantities that propagates through time. When waves oscillate frequently around an equilibrium value at a certain frequency, they are said to be periodic.

It is a mechanical wave that conveys kinetic energy through the movement of the particles affected when a wave moves a particle of matter. The behavior of the wave's particles sometimes referred to as the oscillation of the wave, is used to categorize different types of mechanical waves.

The movement of the medium's particles as a transverse wave travels through it is side-to-side and perpendicular to the wave's direction of travel. Any direction in relation to up and down is acceptable as long as it creates a line of motion that is perpendicular to the direction of travel.

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The maximum energy is 6.2 eV.

Photoelectric effect: Some electrons are released from the metal surface when photons strike it. The photoelectric effect is the name given to this occurrence.

The work function (φ) of a metal is the minimal amount of energy required to remove electrons from its surface.

Maximum kinetic energy is the most energy that electrons have when they are expelled off a metal surface (KEmax).

The work function of sodium is 2.1 eV.

The wavelength of the radiation is 150 nm.

Work function, φ = 2.1 eV

Wavelength, λ = 150 nm = 150 × 10⁻⁹ = 15 × 10⁻⁸ m

Einstein's photoelectric equation is given as:

E = φ + KE(max)

KE(max) = E - φ

KE(max) = ( hc / λ ) - φ

KE(max) = ( 6.63 × 10⁻³⁴) × 3 × 10⁸ / (15 × 10⁻⁸ × 1.6 × 10⁻¹⁹) - 2.1

KE(max) = 0.8287 × 10 - 2.1

KE(max) = 8.3 eV - 2.1 eV

KE(max) = 6.2 eV

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A ferris wheel having a radius of 8 m has a velocity of 8 m / s. is there a danger of the riders flying off .  No, the ferris wheel is not moving too fast.

What is a velocity?

Velocity may be a vector quantity that refers to "the rate at which an object changes its position." Imagine an individual moving rapidly - one step forward and one step back - always returning to the original starting position. While this might end in a frenzy of activity, it might result in a zero velocity.

What is the two types of velocity?

Constant velocity: is that the speed at which an object travels equal displacements in equal times. Variable velocity: it's the speed at which an object cuts different displacements at different times.

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For a total trip of several hours' duration, a ratio of the total distance traveled to the total time elapsed is average speed.

The overall distance that is covered by an object in a given amount of time is its average speed. In essence, average speed serves as a tool for calculating the rate of travel time and distance.

The average speed is a scalar quantity.

It is represented by magnitude and lacks direction. The formula for an object’s general average speed is given as follows:

[Average Speed = The Total Distance Traveled / The Total Time Taken

The SI unit for the average speed is m/s.

Meter per second

The S.I. speed unit is the meter per second. Additionally, speed is expressed in kmph or that can be said as kilometers per hour.

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If an object from a tall building falls, it will take it 4.995 seconds to reach a speed of 49 m/s.

The time taken for an object to fall can be calculated using the following equation of motion:

V = u + at

Where;

According to this question, an object from a tall building falls. The time it would take to reach a speed of 49m/s can be calculated as follows:

49 = 0 + 9.81(t)

49 = 9.81t

t = 49/9.81

t = 4.995s

Therefore, if an object from a tall building falls, it will take it 4.995 seconds to reach a speed of 49 m/s.

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Answer:

100 yd * 3 ft/yd / 3.281 ft/m = 91.4 m

Check" 91.4 m " 3.281 ft/yd = 299.9 ft = 100 yd

Then driving force for the membrane is hyperpolarized.

The electrical potential difference across the cell membrane that exactly balances the ion concentration gradient is known as the equilibrium potential. Since the system is in equilibrium, the membrane potential will normally stay at the equilibrium potential.

Additionally, the equilibrium potential for a group of ions in a membrane provides us with a baseline for how this membrane is operating or behaving in a given situation where it is not at rest.

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The condition under which a system of forces is reduced to a single force is - One can replace the force - couple system at O by a single force R acting along a new line of action if R and vector M₀ are mutually perpendicular.

What is a force?

Hence, the only condition is if R and vector M₀ are mutually perpendicular, then the system of forces can be reduced to a single force.

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Answer:

The wave takes 3.2 s at 0.75 m s⁻¹ to travel across a slinky. The length of slinky is 2.4 m.

What is a wave?

A wave is defined as a disturbance that travels from one spot to another through a medium. As an example of a wave, consider a slinky wave. When stretched from end to end and maintained at rest, the slinky assumes a natural state known as the equilibrium or rest position. The slinky's coils automatically assume this posture, equally spaced apart. The initial particle is pushed or shifted from its equilibrium or rest state to introduce a wave into the slinky.

Explanation:

As we know, [tex]speed=\frac{distance}{time}[/tex]

Therefore, [tex]distance = speed[/tex] × [tex]time[/tex]

=> d = 0.75 x 3.2

       = 2.4 m

Hence, the distance the wave travels or the length of the slinky is 2.4 m.

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He started from point O . After traveled he reached at the same point O.

from the graph given which is attatched :

OA = 700m ab = 300 m bc = 400m

CD = 600m DE = 1200m EF = 300m and FO = 100m

total distance covered =  700+ 300 + 400 + 600 + 1200 + 300 + 100

= 3600m

hence he covered 3600m distance

since, he started from point O and after travelled he reaches the same point from where he started means the initial and final position is same

therefore the total displacement is zero

displacement = 0

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No, the statement does not justify the situation because when the Net Force is 0 then it means that Inertia is greater than Force. So, it follows Newton's first law of Motion

The first law of motion which is often referred to as the 'Law of Inertia' states that an object tends to remain in the motion it's set in. If the object is set in motion it'll tend to be in motion or if the object is at rest then it'll tend to stay at rest. The object will only change its position when an external force is applied to it.

This tendency to remain in its state of motion is called 'Inertia' which acts as a resistance force when an external force is applied. If the magnitude of the external force is less than the Inertia object will not change its state of motion. So when the net force applied to an object is 0 the object will follow the Law of Inertia.

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The vector of linear combination = u is -7/3 i - 8/3 j - k , a) linear combination is xi + yj + zk = (1/3) (-7i -8j-3k) b ) linear combination is 19/3 i + 17/3 j + 6 k

The vector u is  [tex]-7/3[/tex] i - [tex]8/3[/tex] j - k.

The linear combination 2u + 3v + 5w  is 19/3 i + 17/3 j + 6k.

in line with the posed question.

v = (2, 3, 1)

w = (1, 1, 1)

And

3u + 2v + 4w = (1, 2, 3)

From,

v = (2, 3, 1)⇒ v = 2i + 3j + 1k

w = (1, 1, 1)⇒ w = I + j + j

Evaluation :

a). Let u be the vector xi + yj + zk.

Here,

3u + 2v + 4w = (1, 2, 3)

I + 2j + 3k = 3u + 2v + 4w

I + 2j + 3k = 3(xi + yj + zk) + 2(2i + 3j + k) + 4(i + j + k)

I + 2j + 3k = 3xi + 3yj + 3zk + 4i + 6j + 2k + 4i + 4j + 4k

I + 2j + 3k = 3xi + 3yj + 3zk + 8i + 10j + 6k

I + 2j + 3k - 8i -10j -6k = 3xi + 3yj + 3zk

-7i -8j -3k = 3xi + 3yj + 3zk

xi + yj + zk = (1/3) (-7i -8j-3k)

b). The linear combination

2u + 3v + 5w

= 2(-7/3i -8/3j - k ) + 3(2i + 3j + k) + 5(i + j + k)

= -14/3 i -16/3j -2k + 6i + 6j + 3k + 5i + 5j + 5k

= -14/3 i -16/3j -2k  + 11i + 11j + 8k

= 19/3 i + 17/3 j + 6k

What is a linear combination of a vector?

A linear combination is  of two or more vectors in which the vector obtained by adding two or more vectors (with different directions) which are then  multiplied by scalar values.

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Einstein’s understanding of curved space-time helped him understand gravity better on Earth.

The man Albert Einstein was the person who first brought up the idea of relativity. The relativity theory drove home the assertion that there are no absolutes in the universe.

On the other hand, the works of Aristotle and Newton about gravity did not include this element of relativity. Though the work of Newton was highly empirical, the results did not incorporate the ideas of relativity.

Thus, what distinguishes Einstein from Newton and Aristotle is Einstein’s understanding of curved space-time helped him understand gravity better on Earth.

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While an object moves along a curved path it is not possible for acceleration to be zero.

The term acceleration has to do with the change of velocity with time. We know that velocity is a vector quantity. Since velocity is a vector quantity, it means that velocity would have both magnitude and direction.

Given the fact that the magnitude of the velocity of the object that is moving along a curved path may be constant, the direction of the velocity still changes.

Owing to the fact that we must consider both changes in magnitude and direction of velocity, it then follows that while an object moves along a curved path it is not possible for acceleration to be zero.

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The average velocity for the time interval from 2.10 s to 2.85 s is Vavg = 18 m/s.

What is  average velocity?

A vector quantity is average velocity. The change in position or displacement (∆x) divided by the time intervals (∆t) during which the displacement happens is the definition of average velocity. Depending on how the displacement is spelled out, the average velocity might be either positive or negative.

Vavg = d X/ d T

Here d X = change in distance

and d T = change in time

there Therefore    dT= 2 x 9 x t

so, at t= 2.10s x = 37.8 m/s

at t= 2.85s  x= 51.3 m/s

Therefore     Vavg = (51.3 m/s - 37.8 m/s) / ( 2.85s - 2.10s )

Vavg = 18 m/s

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When you are halfway around the stadium, average speed value cannot be 0.

Average speed = Total distance travelled / Time taken.

Since you ran halfway across the stadium, a certain amount of distance has been covered. The only way the average speed can be zero is if you remained stationary over a given interval of time.

In a distance-time graph, at the halfway point in the stadium, slope is equal to zero. So, Instantaneous speed is zero. In a Velocity-time graph, at the halfway point in the stadium, slope is equal to zero. So, Instantaneous acceleration is zero. In a Velocity ( w.r.t. time )-time graph, at the halfway point in the stadium, slope is equal to zero. So, Average acceleration is zero.

Therefore, when you are halfway around the stadium, average speed value cannot be 0.

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The period of the pendulum is √2 seconds.

We need to know about pendulum experiments to solve this problem. The pendulum is a simple experiment to calculate gravitational acceleration. The gravitational acceleration can be calculated by

g = 4π² . L / T²

where g is gravitational acceleration, L is the length of the string and T is the period.

From the question above, we know that:

T1 = 1 s

L1 = 5 cm

L2 = 10 cm

By using proportionality, the squared period is proportional to the length. Hence,

T² ~ L

Using the ratio, we can write

T1² / T2² = L1 / L2

1² / T2² = 5 / 10

1 / T2² = 1 / 2

T2² = 2

T2 = √2 second

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Two trains are seen as 150 km apart, if they are moving towards each other, they have 1.875 hours before the two trains collide.

The motion or the speed of any object present with relation to a certain point is referred to as relative motion. For instance, a ball thrown upward while in a moving object, like a bus, would be travelling at the same speed with respect to the bus, and would fall again in relation to that speed.

The same physical rules that govern objects at rest on the planet also govern objects in any reference frame that is moving relative to the earth at a constant speed.

The Initial position of Train A = 0 km

The Initial position of Train B = 150 km

x= xi + vi*t

We have to set them equal to each other to find when their positions are the same.

50t = -30t + 150

t = 1.875 hr.

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Answer:

zero

Explanation:

Answer: chicken nuggy

Explanation:

because chicken muggy

The horizontal distance is equal to the half of the circumference of wheel.

x = 2 πr/2

= πr

= 3.14 * 45 * 10^-2

=1.413m

The vertical distance is equal to the diameter of wheel.

y=2r

= 2 * 45 * 10^-2

= 0.9m

The magnitude of the displacement of P is,

r^2 = x^2 + y^2

r^2 = (1.413)^2 + ( 0.9m)^2

r = 1.675

the angle is  tanθ

 θ= 32.5

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The magnitude of the force experienced by the negative charge is 0.198N.

The Coulombs law is an expression that states that  magnitude of the force between two charges q and Q separated by a distance r is given by

F=k|Q|q|r2

where k is Coulomb constant.

Answer and Explanation:

Let us visualize corners of the square as four points on the xy-axis. The four points would be origin (0,0), then (78.9 cm, 0), then (0, 78.9 cm) and (78.9 cm, 78.9 cm). These points are corners of the square described in the question. Let  negative charge be at origin. Let charge 1 be located at (78.9 cm, 0), that is, its located along x-axis, a distance 78.9 cm away from the negative charge. The force due to this charge 1 acts in positive x-direction as the two charges attract. Let charge 2 be at point (0, 78.9 cm) and the force due to this charge acts in the positive y-direction. Charge 2 is also 78.9 cm away from negative charge. Let charge 3 be located at point (78.9 cm, 78.9 cm). Force due to this charge has the x and y-components. The angle this force makes with positive x-axis is 45 degrees since this is a square. The distance between charge 3 and negative charge is

√(78.9cm)2+(78.9 cm)2 =111.5814501cm.

Now we can calculate force on the negative charge due to each individual positive charge. Force due to the charge 1 is [tex]F_{1} =k|+q||-q| r^{2}(8.98755*109N.m^{2}/C^{2})*(2.68*106)*(2.68*106)^{2}(0.789m)^{2} =0.1036947816N[/tex]

in positive x-direction. Force due to the charge 2 has same magnitude as force due to charge 1, but acts in the positive y-direction.

F2 =0.1036947816N

The force due to the charge 3 is

[tex]F_{3}=k|+q||-q| r^{2} =(8.98755*109N.m^{2}/C^{2})*2.68*10^{-6} )^{2}(1.115814501m)^{2}= 0.05184739076N[/tex]

The x and y-components of force due to charge 3 are

F3,x=F3cos45=(0.05184739076√22)N=0.03666164159N

in positive x-direction, and

F3,y=F3sin45=(0.05184739076√22)N=0.03666164159N

in positive y-direction.

Therefore, x-component of the resultant force experienced by the negative charge is

Fx=F1+F3,x=0.1036947816N+0.03666164159N=0.1403564232N

and y-component is

Fy=F2+F3,y=0.1036947816N+0.03666164159N=0.1403564232N

Therefore, magnitude of the force experienced by the negative charge is

[tex]F= \sqrt{Fx_{2}+F_{2y} }= \sqrt{(0.1403564232N)^{2}+(0.140356432N)^{2} } =0.198493973N[/tex] =0.198N

correct to the three significant figures.

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v = 1.24 m/s

The net force on the sphere along x  axis direction is zero so,

∑fx = 0

T sineθ  = qE

The net   force on the sphere along y aixs direction is  zero so,

∑fy = 0

T cosθ  = mg

From the above two  equations, we got

tan θ =qE÷mg

The charge on the sphere is

q = mg ÷ E tan θ

= 82.27 micro coloumb

so, now The speed of the sphere at the bottom is

v = [tex]\sqrt{x} 2gl(1-cos\theta )[/tex]

v= [tex]\sqrt{x} 2( 9.8)(0.23)(1-cos13.4)[/tex]

v = 1.24 m/s

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Answer:

40kg(88pounds)

Explanation:

.

.

.

.

.

.

Answer: ≈ 40.8 kilograms (89.9 pounds)

Explanation: Well, assuming the boy is on Earth, then the gravitational acceleration is approximately 9.8 m/s^2.

So, we get: mass = weight / gravitational acceleration

Put two and two together and you get 400-N / 9.8 m/s^2 ≈ 40.8 kg (89.9 pounds).

The total power emitted by the radio transmitter is 6.67×[tex]10^{4}[/tex]W .

The given parameters;

amplitude of the electric field, E = 0.2 V/m

distance of the transmitter, = 10 km = 10,000 m

The intensity of the radio wave from the transmitter is calculated as follows

[tex]I=E^{2}[/tex]/μc

I = [tex]5.305[/tex]×[tex]10^{-5}[/tex] [tex]W/m^{2}[/tex]

The total power emitted by the radio transmitter is calculated as follows;

I= P/A

P= IA

P = 6.67×[tex]10^{4}[/tex]W.

A radio transmitter, often known as a transmitter, is an electronic device used in electronics and telecommunications that uses an antenna to emit radio waves. A radio frequency alternating current is produced by the transmitter and applied to the antenna. The antenna emits radio waves after being stimulated by this alternating current.

All radio-communicating electronic devices, including radio and television broadcasting stations, cell phones, walkie-talkies, wireless computer networks, Bluetooth-enabled gadgets, garage door openers, two-way radios in aircraft, ships, and spacecraft, radar systems, and navigational beacons, require transmitters as essential component parts.

A transmitter could be a standalone electronic device or an electrical circuit housed inside another electronic gadget.  

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Two nonnegative real numbers with a sum of 46 that have the largest possible product is 23 and 23.

Explanation

Any no's half when multiplied by itself gives the larges possible outcome also being the sum of the given no. as 46

Some trials

23 + 23 = 46        ,       23 × 23 = 529

22 + 24 = 46        ,       22 × 24 = 528

21 + 25  = 46        ,        21 × 25 = 525

Hence, proven that Any no's half when multiplied by itself gives the larges possible outcome also being the sum of the given number.

Any number that exists in the physical universe is a real number. Everywhere we look, we see numbers. Natural numbers are used to count things, while rational numbers are used to represent fractions,

irrational numbers are used to calculate a number's square root, integers are used to measure temperature, and so on. A group of real numbers is created by these various kinds of numbers.

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When we set the object adjacent to the flashlight and not exactly into its beam of light, we probably won't initially notice a shadow.

However, if we place the object directly in the path, we should be able to see a shadow of it on the wall.

What is shadow?

A shadow, or black place, is produced whilst an opaque item deflects light from a mild source. at the back of a light-emitting gadget, it fills the whole three-dimensional area. A 2-D backward projection of the object obstructing the mild may be used to conceptualise the cross section of a shadow.

mild goes in a directly line, therefore setting an object subsequent to a flashlight however out of the mild's direct route prevents us from seeing a shadow. because the object became out of the mild's direct direction, it was not able to block the light from the flashlight's source.

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The angular acceleration of the tyres is -4.213 rad/[tex]s^{2}[/tex] .

Here we have to use the third equation of motion in case of rotational motion so as to calculate the angular acceleration of the tires. It is given by

[tex]w\w\limits^2_f =w\w\limits^2_i + 2\alpha \theta[/tex]

Then, converting the transitional velocity to rotational velocity,

vi = 95km/hr = 95 x 5/18 m/s = 26.39 m/s

vf = 55 km/hr = 55 x 5/18 m/s =15.28 m/s

Diameter of tire = 0.80m

Radius of tire = Diameter of tire/2 = 0.80/2 = 0.40m

Therefore,

wi = [tex]\frac{vi}{r}[/tex] = 26.39/0.40 rad/s = 65.98 rad/s

wf = [tex]\frac{vf}{r}[/tex] = 15.28/0.40 rad/s = 38.20 rad/s

[tex]\theta[/tex] = 65 revolutions= 2[tex]\pi[/tex] x 65 = 408.40 radians

so we have,

[tex]\alpha[/tex] = [tex]\frac{w_{f}^2 - w_{i}^2 }{2 \theta }[/tex] = [tex]\frac{38.20^2 - 65.98^2}{2*408.4}[/tex]=  -4.213 rad/[tex]s^{2}[/tex]

Hence the angular acceleration of the Tyres is -4.213 rad/[tex]s^{2}[/tex].

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