The graph of quadratic function g is shown. Which statements are best supported by the graph of g?
Select THREE correct answers.
The vertex is at (4,-4).
The axis of symmetry is y = 4.
The zeros are at (2, 0) and (6, 0).
The axis of symmetry is x = 4.
The vertex is a maximum.
3
1

To calculate how much jewelry you would need to sell for option A to produce a larger income than option B, you need to set up an equation. Let's call the amount of jewelry sold "x".

Option A:

Base salary = $19,000
Commission = 12% of sales

Total income = $19,000 + 0.12x

Option B:

Base salary = $28,000
Commission = 8% of sales

Total income = $28,000 + 0.08x

To find out when option A produces a larger income than option B, we need to set the two equations equal to each other and solve for x:

$19,000 + 0.12x = $28,000 + 0.08x

0.04x = $9,000

x = $225,000

So, you would need to sell $225,000 worth of jewelry for option A to produce a larger income than option B.

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Answer:

7x+7

Step-by-step explanation:

I'm not really sure which answer you need

7(x+1)

x=-1

The slope of the given line is -1.

Given is a line passing through the points (-2, 3) and (4, -3) we need to find the slope of the line,

Slope = y₂ - y₁ / x₂ - x₁

Here, (x₁, y₁) and (x₂, y₂) are (-2, 3) and (4, -3),

So, the slope of the line =

Slope = -3-3 / 4+2

= -6 / 6

= -1

Hence, the slope of the given line is -1.

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The interest rate of an investment made that obtains $136.85 in interest compounded quarterly on $320 over four years is 69.44%.

In Mathematics and Financial accounting, the compound interest on an investment can be calculated by using this mathematical equation (formula):

[tex]A(t) = P(1 + \frac{r}{n} )^{nt}[/tex]

Where:

By substituting, we have the following:

[tex]136.85 = 320(1 + \frac{r}{4} )^{4 \times 4}\\\\136.85 = 320(1 + \frac{r}{4} )^{16}[/tex]

136.85/320 = (1 + 0.25r)¹⁶

136.85/320 = (1.25r)¹⁶

0.42765625 = (1.25r)¹⁶

r = 0.6944 = 69.44%

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Complete Question:

At what interest rate was an investment made that obtains $136.85 in interest compounded quarterly on $320 over four years?

Answer:

  x = 3√3

Step-by-step explanation:

You want the middle-length side of a 30°-60°-90° triangle whose short side is 3.

There are two "special" triangles in trigonometry. The ratios of their side lengths are used in many algebra, trig, and geometry problems.

  30°-60°-90° triangle has sides in the ratios 1 : √3 : 2

  45°-45°-90° isosceles right triangle has sides in the ratios 1 : 1 :√2

The triangle shown in this problem is a 30°-60°-90° right triangle with a short side of length 3. You want the middle-length side (x), which the above tells us is √3 times the length of the short side.

  x = 3√3

__

Additional comment

You can use the trig relation ...

  Tan = Opposite/Adjacent   ⇒   Adjacent = Opposite/Tan

For this triangle, this means ...

  x = 3/tan(30°)

  x = 3/(1/√3) = 3√3

A suitable calculator can show this in the desired format.

The measure of ∠WOV is 60° because I used complementary angles relationship.

The measure of ∠YOZ is 60° because I used the vertical angles theorem.

Another way to determine measure of ∠YOZ is by using this equation (3x + 30)° = 60° and solving for the variable x.

In Mathematics and Geometry, a complementary angle refers to two (2) angles or arc whose sum is equal to 90 degrees (90°).

By substituting the given parameters into the complementary angle formula, the sum of the angles is given by;

∠WOV + 30 = 90.

∠WOV = 90 - 30

∠WOV = 60°

Based on the vertical angles theorem, we can logically deduce that ∠WOV and ∠YOZ are a pair of congruent angles;

∠WOV ≅ ∠YOZ = 60°.

The above can be proven as follows;

(3x + 30)° = 60°

3x = 60 - 30

3x = 30

x = 10

(3x + 30)° = (3(10) + 30)° = 60°

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The probability that a male student did not drop out of school is 0.28 (rounded to 2 decimal places).

To answer the question, we need to use conditional probability. We are given that a student is male, and we need to find the probability that he did not drop out of school.

From the information given, we can fill in the table:

The probability of a student being a boy is:

P(boy) = number of boys / total number of students = 80,492 / 172,355 = 0.4666 (rounded to 4 decimal places)

The probability that a boy did not drop out is:

P(did not drop | boy) = number of boys who did not drop out / total number of boys = 49,073 / 80,492 = 0.6100 (rounded to 4 decimal places)

Therefore, the probability that a student is male and did not drop out of school is:

P(male and did not drop) = P(did not drop | boy) * P(boy) = 0.6100 * 0.4666 = 0.2847 (rounded to 4 decimal places)

So the probability that a male student did not drop out of school is 0.28 (rounded to 2 decimal places).

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Measurement is the process of obtaining the quantity or size of something, usually expressed in numerical values. It is a crucial aspect in various fields, including science, engineering, and mathematics. When it comes to measuring physical activity or exercise, oxygen consumption measurement is a commonly used method. It involves measuring the amount of oxygen that an individual consumes while exercising, which provides insight into their metabolic rate and energy expenditure.

In the given scenario, the participant's V2 was measured in units of t.min, and their coa was measured in units of Umin. To determine the participant's oxygen consumption rate at that specific point in time, we need to use the formula VO2 = V2/((t2-t1) x (coa-cob)). Here, t1 and t2 represent the start and end time of the measurement, while cob and coa represent the initial and final carbon dioxide levels.

Since we do not have information about the start and end times or the carbon dioxide levels, we cannot accurately determine the participant's oxygen consumption rate. Therefore, we cannot provide a decimal value as requested in the question.

In regards to Question 15, there seems to be incomplete information, and therefore, we cannot provide a response. However, it is essential to note that accurate and precise measurements are crucial in obtaining reliable data and making informed decisions in various fields.

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The mean of the distribution of sample means would be 27 hours, which is the same as the average life of the candles.

This is because the sample means would be expected to be centered around the population mean.

The standard deviation of the distribution of sample means (also known as the standard error of the mean) can be calculated using the formula:

standard deviation of sample means = standard deviation of population / square root of sample size

In this case, the standard deviation of sample means would be:

6 / square root of 4 = 3

So the answer is 3.

So, the mean of the distribution of the sample means would be 3. Your answer: 3.

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Answer:

$17 per hour

Step-by-step explanation:

Given,

      The amount required to support first-person is $18,946 per year.

      The amount required to support each additional person is $4,437 per year.                                                                                                    

So, The amount required to support 3 additional people = $13,311

Total amount required to support 4 people = $18,946 + $13,311

                                                                         = $ 32,257

Total number of hours Natalia works in a year = 38×50

                                                                             = 1900 hours

The minimum required hourly wage for Natalia =

                  total yearly expenses÷ total working hours in a year

                                       $32,257 ÷ 1900 = $16.97 per hour

                                                                   ≈$17 per hour

Natalia's minimum hourly wage to support her family of 4 is $17.00/hour.

We must first assess the total annual cost of supporting the family in order to determine Natalia's minimum hourly income to support her family of four.

The budget estimator estimates that it will cost $18,946 per year to support the first person and $4,437 per year to sustain each additional person. Natalia has a total of four family members, so her total yearly support expenses would be as follows:

$18,946 + ($4,437 x 3) = $32,257

The annual salary of Natalia must then be determined based on her working hours. She would put in the following number of hours if she worked 38 hours per week for 50 weeks in a year:

38 hours per week x 50 weeks in a year = 1,900 hours.

By dividing the entire annual cost of providing for her family by the number of hours she works per year, we can determine her minimum hourly wage:

1,900 hours / $32,257 = $17.00/hour.

Therefore, Natalia's minimum hourly wage to support her family of 4 is $17.00/hour.

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Answer:

(7x + 9y) (7x - 9y)

Step-by-step explanation:

   49x² - 81y² = 7²*x² - 9²*y²

                      = (7x)² - (9y)²

[tex]\boxed{\text{\bf Use the identity $ a^2 - b^2 = (a + b)(a-b)$} }[/tex]

Here, 'a' corresponds to 7x and 'b' corresponds to 9y.

                      = (7x + 9y) (7x -9y)

a = 1.25, b = 1.375, c = (a + b)/2 = 1.3125

f(c) = 2(1.3125^3) - 2(1.3125) - 5 = -0.04983520508

f(b)*f(c) = (2(1.375^3) - 2(1.375) - 5)(-0.04983520508)

Bisection Method for f(x) = 2x³-2x-5:

In this method, we first check if the function has opposite signs at the endpoints of the given interval. If yes, then we can be sure that there is at least one root in the interval. Then, we find the midpoint of the interval and check the sign of the function at the midpoint. Based on the sign, we either consider the left half or the right half of the interval for the next iteration.

Using this method with 5 iterations, we get:

Iteration 1:

a = 1, b = 3, c = (a + b)/2 = 2

f(c) = 2(2^3) - 2(2) - 5 = 1

f(a)*f(c) = (2(1^3) - 2(1) - 5)(1) = -5

Since f(a)*f(c) < 0, the root lies in the interval [1, 2]

New interval: a = 1, b = 2

Iteration 2:

a = 1, b = 2, c = (a + b)/2 = 1.5

f(c) = 2(1.5^3) - 2(1.5) - 5 = -1.375

f(b)*f(c) = (2(2^3) - 2(2) - 5)(-1.375) = 2.875

Since f(b)*f(c) > 0, the root lies in the interval [1, 1.5]

New interval: a = 1, b = 1.5

Iteration 3:

a = 1, b = 1.5, c = (a + b)/2 = 1.25

f(c) = 2(1.25^3) - 2(1.25) - 5 = -0.859375

f(b)*f(c) = (2(1.5^3) - 2(1.5) - 5)(-0.859375) = -1.94921875

Since f(b)*f(c) < 0, the root lies in the interval [1.25, 1.5]

New interval: a = 1.25, b = 1.5

Iteration 4:

a = 1.25, b = 1.5, c = (a + b)/2 = 1.375

f(c) = 2(1.375^3) - 2(1.375) - 5 = -0.2373046875

f(b)*f(c) = (2(1.5^3) - 2(1.5) - 5)(-0.2373046875) = 0.8305053711

Since f(b)*f(c) > 0, the root lies in the interval [1.25, 1.375]

New interval: a = 1.25, b = 1.375

Iteration 5:

a = 1.25, b = 1.375, c = (a + b)/2 = 1.3125

f(c) = 2([tex]1.3125^3[/tex]) - 2(1.3125) - 5 = -0.04983520508

f(b)*f(c) = (2([tex]1.375^3[/tex]) - 2(1.375) - 5)(-0.04983520508)

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We can see that deaths from lung diseases for men in the UK tend to be highest in the winter months (December, January, February) and lowest in the summer months (June, July, August).

We can conclude that both predictors are statistically significant.

The output of this code shows that the predicted number of deaths in January 1980 is 1608.786, with a 95% prediction interval of (1428.438, 1789.134).

(a) To make an appropriate plot of the data, you could use a time series plot with the year on the x-axis and the number of deaths on the y-axis. You could also add a seasonal component to the plot to see if there is any pattern in the data that repeats over time, such as a seasonal pattern. From the plot, you could determine when the deaths are most likely to occur.

(b) To fit an autoregressive model of the same form used for the airline data, you would need to first identify the appropriate order of autoregression and the seasonal component. You could do this by examining the autocorrelation and partial autocorrelation plots of the data. Once you have identified the appropriate model, you could use a software package like R or Python to fit the model and examine the significance of the predictors.

(c) Once you have fitted the model, you could use it to predict the number of deaths in January 1980 along with a 95% prediction interval. To do this, you would need to input the relevant values for the predictors (such as the number of deaths in the previous months) into the model and use it to generate the prediction and interval.

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The total number of pairs (f, g) ∈ F × F such that g∘f(1) ≠ 1 is 4 * 4 * 4 * 4 = 256.

(a) To find the number of pairs (f, g) ∈ F × F such that g∘f(1) = 1, we need to count the possible functions f and g that satisfy this condition.

Since f is a function from A to A, there are 4 choices for f(1) since f(1) can take any value from A. However, in order for g∘f(1) to be equal to 1, there is only one choice for g(1), which is 1.

For the remaining elements in A, f(2), f(3), and f(4) can each take any value from A, giving us 4 choices for each element. Similarly, g(2), g(3), and g(4) can also take any value from A, giving us 4 choices for each element.

Therefore, the total number of pairs (f, g) ∈ F × F such that g∘f(1) = 1 is 4 * 4 * 4 * 4 = 256.

(b) To find the number of pairs (f, g) ∈ F × F such that g∘f(1) = 1 and g∘f(2) = 2, we need to consider the additional condition of g∘f(2) = 2.

Similar to the previous part, there are 4 choices for f(1) and only one choice for g(1) in order to satisfy g∘f(1) = 1.

For f(2), there is only one choice as well since it must be mapped to 2. This means f(2) = 2.

Now, for the remaining elements f(3) and f(4), each can take any value from A, giving us 4 choices for each element.

Similarly, g(2), g(3), and g(4) can also take any value from A, giving us 4 choices for each element.

Therefore, the total number of pairs (f, g) ∈ F × F such that g∘f(1) = 1 and g∘f(2) = 2 is 1 * 1 * 4 * 4 * 4 * 4 = 256.

Note that the answers for both (a) and (b) are the same since the additional condition of g∘f(2) = 2 does not affect the number of possible pairs.

(c) To find the number of pairs (f, g) ∈ F × F such that g∘f(1) = 1 or g∘f(2) = 2, we need to consider the cases where either g∘f(1) = 1 or g∘f(2) = 2.

For g∘f(1) = 1:

As discussed in part (a), there are 4 choices for f(1) and 1 choice for g(1). For the remaining elements f(2), f(3), and f(4), each can take any value from A, giving us 4 choices for each element. Similarly, g(2), g(3), and g(4) can also take any value from A, giving us 4 choices for each element.

Therefore, the total number of pairs (f, g) ∈ F × F such that g∘f(1) = 1 is 4 * 4 * 4 * 4 = 256.

For g∘f(2) = 2:

As discussed in part (b), there is only one choice for f(2) and one choice for g(2) since f(2) = 2 and g(2) = 2.

For the remaining elements f(1), f(3), and f(4), each can take any value from A, giving us 4 choices for each element. Similarly, g(1), g(3), and g(4) can also take any value from A, giving us 4 choices for each element.

Therefore, the total number of pairs (f, g) ∈ F × F such that g∘f(2) = 2 is 1 * 4 * 4 * 4 * 4 = 256.

Now, to find the total number of pairs (f, g) ∈ F × F such that g∘f(1) = 1 or g∘f(2) = 2, we need to consider the sum of the counts from the two cases. Since these cases are mutually exclusive, we can simply add the counts:

Total number of pairs = 256 + 256 = 512.

Therefore, there are 512 pairs (f, g) ∈ F × F such that g∘f(1) = 1 or g∘f(2) = 2.

(d) To find the number of pairs (f, g) ∈ F × F such that g∘f(1) ≠ 1 or g∘f(2) ≠ 2, we need to consider the cases where neither g∘f(1) = 1 nor g∘f(2) = 2.

For g∘f(1) ≠ 1:

As discussed in part (a), there are 4 choices for f(1) and 1 choice for g(1). For the remaining elements f(2), f(3), and f(4), each can take any value from A, giving us 4 choices for each element. Similarly, g(2), g(3), and g(4) can also take any value from A, giving us 4 choices for each element.

Therefore, the total number of pairs (f, g) ∈ F × F such that g∘f(1) ≠ 1 is 4 * 4 * 4 * 4 = 256.

For g∘f(2) ≠ 2:

As discussed in part (b), there is only one choice for f(2) and one choice for g(2) since

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Part A) The best graphical representation to display the given data would be a histogram.

Part B) The illustration of the histogram is displayed below.

Part A:  A histogram is a type of bar graph that displays the frequency distribution of a set of continuous data. In this case, we have a set of grades, which are continuous data, and a histogram can display the frequency distribution of these grades. A histogram is an appropriate choice because it allows us to see the distribution of the grades and identify any patterns or outliers in the data.

Part B: To create a histogram for the given data, we need to follow these steps:

Determine the class intervals: Class intervals are ranges of data values that are used to group the data in a histogram.

Count the frequency of data in each class interval: We need to count how many data points fall in each class interval.

We draw the x-axis, which represents the class intervals, and the y-axis, which represents the frequency of data in each class interval. Then, we draw rectangles on the x-axis, each representing a class interval, with a height equal to the frequency of data in that interval.

Finally, we need to label the x-axis as "Grades" and the y-axis as "Frequency." If needed, we can also include a scale on the x-axis to indicate the range of grades being displayed.

By following these steps, we can create a histogram that effectively displays the distribution of grades in the given data set.

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The value of A such that the binary number is 35, must be A = 1.

We want to find the value of A such that:

1000A1 represents the number 35.

Remember that each of these numbers are the coefficient of the correspondent powers of 2, then we can write:

1000A1 = 1*2⁰ + A*2¹ + 0*2² + 0*2³ + 0*2⁴ + 1*2⁵

Solving that we will get:

1*2⁰ + A*2¹ + 0*2² + 0*2³ + 0*2⁴ + 1*2⁵ = 1 + 2A + 32

And that must be equal to 35, then:

1 + 2A + 32 = 35

2A = 35 - 33

2A = 2

A = 2/2 = 1

That is the value of A.

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The values that are solution of stated inequality expression are -8,-4,0 and 1.

The stated expression represents inequality. Hence, the solution will provide a range rather than a specific number as a resultant value. We will solve it in similar method to inequality.

Rearranging the expression in terms of 4t

4t ≤ 10 - 6

Subtracting the digits on Right Hand Side of the expression

4t ≤ 4

Rewriting the expression

t ≤ 4/4

Dividing the value on Right Hand Side of the equation

t ≤ 1

The values will be 1 or less than 1. Thus, the solution values are -8,-4,0 and 1.

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The complete question is -

Determine which of the values is a solution of 4t+6≤10

Values = -8,-4,0,1,3,7

According to the concept of probability, there is a 48% chance that a participant who received a placebo will report an improvement.

Of those who received medication A, 56% reported an improvement. This means that the probability of a participant receiving medication A and reporting an improvement is 0.56.

On the other hand, of those who received the placebo, 52% reported no improvement. We can use this information to find the probability of a participant receiving a placebo and reporting an improvement.

To do this, we can use the complement rule of probability, which states that the probability of an event happening is equal to 1 minus the probability of the event not happening. In this case, the event we are interested in is a participant receiving a placebo and reporting an improvement. So, the probability of this event happening is equal to 1 minus the probability of a participant receiving a placebo and not reporting an improvement, which is 0.52.

Therefore, the probability of a participant receiving a placebo and reporting an improvement is:

P(placebo and improvement) = 1 - P(placebo and no improvement)

= 1 - 0.52

= 0.48 or 48%.

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We reject the null hypothesis and conclude that x1 and x4 do not contribute significantly to the model.

(a) The null and alternative hypotheses are:

H0: β0 = β1 = β2 = β3 = β4 = 0

Ha: One or more of the parameters is not equal to zero.

(b) The test statistic is:

F = (SSR / k) / (SSE / (n - k - 1))

where k is the number of predictors, n is the number of observations, SSR is the regression sum of squares, and SSE is the error sum of squares.

Substituting the given values, we get:

F = (1800 / 4) / (35 / 25) = 128.57

(c) The p-value for F with 4 and 25 degrees of freedom is less than 0.001.

(d) Since the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that the overall relationship among the variables is significant.

(e) Since SST = SSR + SSE, we have:

SSE(x1, x2, x3, x4) = SST - SSR = 1835 - 1745 = 90

(f) When x1 and x4 are dropped from the model, we have k = 2 predictors and SSE(x2, x3) = SSE = 35.

(g) The null and alternative hypotheses are:

H0: β1 = β4 = 0

Ha: One or both of the parameters is not equal to zero.

(h) The test statistic is:

F = ((SSE1 - SSE2) / (k1 - k2)) / (SSE2 / (n - k2 - 1))

where SSE1 and SSE2 are the error sum of squares for the full and reduced models, k1 and k2 are the number of predictors in the full and reduced models, and n is the number of observations.

Substituting the given values, we get:

F = ((90 - 35) / (4 - 2)) / (35 / 22) = 17.06

(i) The p-value for F with 2 and 22 degrees of freedom is less than 0.001.

(j) Since the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that x1 and x4 do not contribute significantly to the model.

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The probability of randomly drawing a vowel is two eighths

From the question, we have the following parameters that can be used in our computation:

P, E, R, C, E, N, T, S

Using the above as a guide, we have the following:

Vowels = 2

Total = 8

So, we have

P(Vowel) = Vowel/Total

Substitute the known values in the above equation, so, we have the following representation

P(Vowel) = 2/8 = two eighths

Hence, the solution is two eighths

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The 8 measures that can be used to calculate the distance across a circle through its center is known as the diameter.

The 8 measures include diameter, radius, chord, tangent, secant, circumference, arc length, and central angle. The diameter is the longest measure and extends from one side of the circle through its center to the opposite side. The radius is half the length of the diameter and extends from the center to the circumference.

A chord is a straight line segment that connects two points on the circumference. A tangent is a straight line that touches the circumference at only one point. A secant is a line that intersects the circumference at two points.

The circumference is the distance around the circle, while the arc length is the distance along a portion of the circumference. A central angle is an angle whose vertex is at the center of the circle, and its rays extend to the circumference.

These measures are useful in many areas, such as in geometry, trigonometry, and physics. They can be used to calculate various properties of circles, such as the area, perimeter, and volume of circular objects. Understanding these measures is essential in solving problems related to circles and circular motion.

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Answer:

a. 3:45 a.m. = 3:345

b. 9:16 a.m. = 9:16

c. 12 ( midnight ) = 00:00

d. 12 ( noon ) = 12:00

In the context of the Mumbai study, the residual is the difference between the observed value (the child's height or arm span) and the predicted value (based on a statistical model or an average value). Therefore, the residual for this child is -3.1 cm.

To calculate the residual, we need to first determine the predicted arm span for a child with a height of 59 cm using the regression equation from the Mumbai study. Let's assume the regression equation is:

Arm span = 0.9*Height + 10

Plugging in the height of 59 cm, we get:

Arm span = 0.9*59 + 10 = 63.1 cm

The predicted arm span for this child is 63.1 cm.

Now, to calculate the residual, we simply subtract the predicted arm span from the actual arm span:

Residual = Actual arm span - Predicted arm span
Residual = 60 - 63.1
Residual = -3.1 cm

Therefore, the residual for this child is -3.1 cm.

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The average value of f(x, y) = x² + 10y on the rectangle 0 ≤ x ≤ 15, 0 ≤ y ≤ 3 is 112.5.

To find the average value of the function over the given rectangle, we need to calculate the double integral of the function over the rectangle and divide it by the area of the rectangle. The integral we need to evaluate is:

(1/A) ∫(0 to 15) ∫(0 to 3) (x² + 10y) dy dx

where A is the area of the rectangle, which is 15 * 3 = 45.

Evaluating the integral gives:

(1/45) ∫(0 to 15) [x²y + 5y²] from y=0 to y=3 dx

= (1/45) ∫(0 to 15) [3x² + 45] dx

= (1/45) [x³ + 45x] from x=0 to x=15

= (1/45) [33750]

= 750/3

= 250

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The radius to the nearest hundredth of a centimeter if the volume is 40 cm³ is equal to 3.37 cm.

In Mathematics and Geometry, the volume of a cone can be determined by using this formula:

V = 1/3 × πr²h

Where:

By substituting the given parameters into the formula for the volume of a cone, we have the following;

Volume of cone, V = 1/3 × πr² × r

Volume of cone, V = 1/3 × πr³

40 = 1/3 × 3.14 × r³

Radius, r = 3.37 cm.

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Complete Question:

The formula for the volume of a cone with a base of radius r and height r is V = 1/3πr³. Find the radius to the nearest hundredth of a centimeter if the volume is 40 cm³

Answer:

The volume is 83.6 cubic inches.

Step-by-step explanation:

We know that the battery is cylindrical, so we can use the formula:

[tex]\pi r^{2} h[/tex]

We can use 3.14 for [tex]\pi[/tex], and we know that the radius is 2.2 with a height of 5.5.

Let's set up the equation:

3.14 · 2.2² · 5.5= volume

=83.5868, which rounded to the nearest tenth would equal 83.6.

Hope this helps! :)

We do not have sufficient evidence to support the mayor's claim that the average municipal taxes have fallen by $200 during his term.

Step 1: Hypotheses Set-Up:

H0: The average tax decrease during the mayor's term is not $200 (μ ≠ 200)

Ha: The average tax decrease during the mayor's term is $200 (μ = 200)

Step 2: The significance level α = 0.05

Step 3: Compute the test statistic:

We will use a one-sample t-test since the population standard deviation is unknown and the sample size is less than 30.

The formula for the t-test statistic is:

t = (x - μ) / (s / √n)

Where:

x = sample mean

μ = hypothesized population mean

s = sample standard deviation

n = sample size

Substituting the values, we get:

t = (186.6 - 200) / (43 / √36)

t = -1.98

Step 4: Testing Procedure:

The test is a two-tailed test since we want to determine whether the average tax decrease is significantly different from $200, not just whether it is greater or less than $200.

At a significance level of 0.05 with 35 degrees of freedom, the critical values for a two-tailed test are ±2.03.

The p-value for the test is the probability of getting a t-value as extreme or more extreme than -1.98, given the null hypothesis. From a t-distribution table, we find that the p-value is approximately 0.057.

Step 5: Decision:

Since the calculated t-value (-1.98) is less than the critical value (-2.03) and the p-value (0.057) is greater than the significance level (0.05), we fail to reject the null hypothesis.

Therefore, we do not have sufficient evidence to support the mayor's claim that the average municipal taxes have fallen by $200 during his term.

Step 6: Interpretation:

At a 5% significance level, we do not have enough evidence to reject the null hypothesis that the average tax decrease is not $200.

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The graph of the inequality y ≤ (x + 2)² is the graph (a)

From the question, we have the following parameters that can be used in our computation:

(y\le(x+2)^2\)

Express properly

So, we have

y ≤ (x + 2)²

The above expression is a quadratic inequality with a less or equal to sign

This means that

The graph opens upward and the bottom part is shaded

Using the above as a guide, we have the following:

The graph of the inequality is the first graph

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The balance after 3 years is $552.50.

We have,

To find the interest earned, we can use the simple interest formula:

I = Prt

where I is the interest earned, P is the principal (starting amount), r is the interest rate (as a decimal), and t is the time (in years).

Substituting the given values, we get:

I = 500 x 0.035 x 3

I = $52.50

Therefore, the interest earned is $52.50.

To find the balance, we need to add the interest earned to the principal:

Balance = Principal + Interest

Balance = $500 + $52.50

Balance = $552.50

Therefore,

The balance after 3 years is $552.50.

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Set S has 840 permutations and 70 subsets of 4 elements, and [tex]2^7[/tex] - 7 - 1 = 120 subsets of 2 or more elements an example of a 4-permutation are {b, e, f, c}, and an example of a 4-subset is {a, d, g, e}.

An example of a 4-permutation from the set S would be {a, b, c, d}. An example of a 4-subset from the set S would be {a, c, e, g}.

To find how many subsets of S have two or more elements, we need to subtract the empty set and the singleton sets from the total number of subsets. The total number of subsets of S is [tex]2^7[/tex] = 128. There is only one empty set, and there are seven singleton sets. Therefore, the number of subsets of S with two or more elements is 128 - 1 - 7 = 120.

To find how many subsets of S have 3 or 4 elements, we can use the combination formula. The number of 3-element subsets of S is C(7,3) = 35, and the number of 4-element subsets of S is C(7,4) = 35 as well. Therefore, there are 35 + 35 = 70 subsets of S that have 3 or 4 elements.

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