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Answer:

[tex]A=90^0-B\\B+C=180^0-90^0=90^0\\C=90^0-B\\A=C[/tex]

Explanation:

Answer:

The acceleration of the train must be - 0.133 m/s²

Explanation:

A train in order for it to stop 12 m/s in a distance if 541 m

That means the initial velocity of the train is 12 m/s

Its final velocity is zero (stop)

The distance it covers is 541 m

P.S. This is part of the answer of another brainly user this is not my knowledge.

But Hope I helped you

Answer:

-0.133 m/s²

Explanation:

Given:

Δx = 541 m

v₀ = 12 m/s

v = 0 m/s

Find: a

v² = v₀² + 2aΔx

(0 m/s)² = (12 m/s)² + 2a (541 m)

a = -0.133 m/s²

Answer:

Speed is 0.08 m/s.

Explanation:

Given the distance that the bird flies = 3.7 meters

The time is taken by the bird to fly the 3.7 meters = 46 seconds  

We have given distance and time. Now we have to find the speed at which the bird flies. So, to calculate the speed of the bird we have to divide the distance by the time.  

Below is the formula to find the speed.

Speed = Distance / Time

Now insert the given value in the formula.

Speed = 3.7 / 46 = 0.08 m/s

Answer:

Because its wet

Explanation:

Answer:

350 N

Explanation:

F=ma

[tex]f = force \\ m = mass \\ a = acceleration[/tex]

[tex]m = 2(55kg) + 240kg \\ a = 1.0 \frac{m}{ {s}^{2} } [/tex]

Force = 350 Newtons

The net force acting on the elevator would be 350 Newtons as it accelerates upward at 1.00 m/s2.

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

The mathematical expression for Newton's second law is as follows

F = ma

As given in the problem two people each have a mass of 55 kg. They are both in an elevator that has a mass of 240 kg. When the elevator begins to move, the people and the elevator have an upward acceleration of 1.00 m/s2, then we have to find the net force acting on the elevator,

The net force acting on the elevator,

F = ma

F =(2×55 + 240)×1

  = 350 Newtons

Thus, the net force acting on the elevator would be 350 Newtons as it accelerates upward at 1.00 m/s2

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Answer:

F=200N

a=500m/s2​

Mass=?

Explanation:

F=ma

200=m*500

200/500=m

Mass=0.4kg

Answer:

displacement = 55 cm

Explanation:

Initial position = 25 cm

Final position = 80 cm

Displacement = final position-finitial position

Putting values in above formula,

D = 80 cm - 25 cm

D = 55 cm

It means that the displacement of the ant is 55 cm.

Answer:

Electric current in amperes = 1.1808 A

Explanation:

Given:

Intercept protons rate = 1800 protons per second

Area = 41 × 10⁷ km²

Find:

Electric current in amperes

Computation:

Current density = Intercept protons rate × 1.6 × 10⁻¹⁹

Current density = 1800 × 1.6 × 10⁻¹⁹

Current density = 2.88 × 10⁻¹⁶

1 km² = 10⁶m²

So,

Electric current in amperes =  2.88 × 10⁻¹⁶ × 41 × 10⁷ × 10⁶

Electric current in amperes = 1.1808 A

Answer:

A

Explanation:

The paper plane slows down when flying in the air due to air resistance or the friction due to the air around it. As the paper plane have flat surfaces and more surface area, the air resists it's motion more than before. If the paper plane is moving towards left, then friction acts towards left.

The friction always act opposite to the direction of paper plane and resists its motion. Hence, we can say that paper plane slows due to Frictional Force [tex]\red{\bullet}[/tex]

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the boot kecked the ball which is frictinal force

Answer:

Part A

You have to ride 8.0 km before turning north to get to your friend’s house.

Part B

The sine of the angle  θ at the location of the friend's house is 0.8

Explanation:

The remaining part of the question which is an image is attached below

Explanation:

Part A

To determine how far you will ride ride before turning north,

From the diagram, that is the distance of your street.

Let the distance of your street be [tex]A[/tex]

and the distance of your friend's street be [tex]B[/tex]

and let the displacement between your friends house and your house be [tex]C[/tex]

The relation in the diagram shows a right angle triangle.

The sides of the right angle triangle are represented as [tex]A,B[/tex] and [tex]C[/tex].

To find [tex]A[/tex], which is the distance of your street,

From Pythagorean theorem, 'The square of hypotenuse is the sum of squares of the other two sides'

That is,

[tex]/Hypoyenuse/^{2} = /Adjacent/^{2} + /Opposite/^{2}[/tex]

[tex]C[/tex] is the hypotenuse, which is the displacement between your friends house and your house,

Hence, [tex]C = 10.0 km[/tex]

[tex]B[/tex] is adjacent, which is the distance of your friends street

then, [tex]B = 6.0 km[/tex]

and [tex]A[/tex] is the opposite, which is the distance of your house

From Pythagoras theorem, we can then write that,

[tex]C^{2} = B^{2} + A^{2}[/tex]

Then, [tex]10.0^{2} = 6.0^{2} + A^{2}[/tex]

[tex]A^{2} = 100.0 - 36.0\\A^{2} = 64.0\\A = \sqrt{64.0}[/tex]

[tex]A = 8.0km[/tex]

Hence, you have to ride 8.0 km before turning north to get to your friend’s house.

Part B

To find the sine of the angle  θ at the location of the friend's house,

In the diagram, the sine of the angle  θ is given by

[tex]Sin\theta = \frac{Opposite}{Hypotenuse}[/tex]

Hence, [tex]Sin\theta = \frac{A}{C}[/tex]

Then,

[tex]Sin\theta = \frac{8.0}{10}[/tex]

[tex]Sin\theta = 0.8[/tex]

Hence, the sine of the angle  θ at the location of the friend's house is 0.8

A. The amount of distance you have to ride before turning North to get to your friend’s house is 8 kilometers.

B. The sine of the angle (θ) at the location of your friend's house is 0.8.

Given the following data:

A. To determine the amount of distance you have to ride before turning North to get to your friend’s house, we would apply Pythagorean's theorem:

Mathematically, Pythagorean's theorem is given by the formula:

[tex]c^2 = a^2 + b^2\\\\10^2 =6^2+b^2\\\\100=36+b^2\\\\b^2 =100-36\\\\b^2 =64\\\\b=\sqrt{64}[/tex]

b = 8 kilometers

B. To find the sine of the angle (θ) at the location of the friend's house:

Mathematically, the sine of an angle is given by the formula:

[tex]Sin\theta = \frac{opposite}{hypotenuse}[/tex]

Substituting the given parameters into the formula, we have;

[tex]Sin\theta = \frac{8}{10} \\\\Sin\theta = 0.8[/tex]

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Answer:

Please add the multiple choice awensers too then I'll get back to you when I can

Answer:

Answer is D

Explanation:

Answer:

Heat, potential energy, and sound.

Explanation:

Edgenuity says so

The characteristics of the inelastic shocks allow to find the correct answers of in which the kinetic energy can be transformed are:

In a collision the total momentum of the system is conserved, this is an important principle of physics, we have two types of collisions:

In inelastic collision, part of the energy of the movement is transformed into potential energy of configuration of the system.

Let's analyze the different answers:

a) Heat.

True. Heat is a form of energy that, due to the change in the relative friction motion of bodies, is one of the greatest sources of transformation of energy into configuration power energy.

b) Impulse.

False. The impulse is the change of the momentum of the system and this is conserved, therefore the momentum is also conserved.

c) Momentum

False. Momentum is preserved in all crashes.

d) Potential energy.

True. Power energy is a configuration energy, therefore kinetic energy can be transformed into potential energy.

e) The sound.

True. Sound is a wave that carries energy, therefore kinetic energy can be transformed into traveling sound waves.

In conclusion, using the characteristics of inelastic shocks, we can find the correct answers that the kinetic energy can be transformed into are:

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Answer:

1. Golf ball is in the range of only particulate detectable range

2, alpha partcle is in ultraviolet range of wavelength

3.bullet is in xray range of wavelength

All in the EMW spectrum

Answer:

learning new activities like riding a bike and playing sports. and also having the ability to collect information and remember them (memory). <3

Answer:

224.6 N

Explanation:

We can use first the formula to calculate the centripetal acceleration, given by:

[tex]a_c=\frac{v_t^2}{R}[/tex]

where the Vt is the tangential velocity, and R is the radius of the circular motion.

Then, for our case we have:

[tex]a_c=\frac{v_t^2}{R}=\frac{3.5^2}{0.6}\approx 20.42\,\,\frac{m}{s^2}[/tex]

And now we multiply this acceleration by Miguel's mass (11 kg) to obtain the centripetal force acting on him:

[tex]F_c=11 \,*\,20.42\,N = 224.6\,\,N[/tex]

Answer:

225 N

Explanation:

Just answered the question

Answer:

80

Explanation:

because of the denstiy formula

Answer:

a) The magnitude of the satellite's velocity when the thruster turns off is approximately 24.177 meters per second.

b) The direction of the satellite's velocity when the thruster turns off is approximately 62.266º.

Explanation:

Statement is incomplete. The complete description is now described below:

A satellite in outer space is moving at a constant velocity of 21.4 m/s in the y direction when one of its onboard thruster turns on, causing an acceleration of 0.250 m/s2 in the x direction. The acceleration lasts for 45.0 s, at which point the thruster turns off.

(a) What is the magnitude of the satellite's velocity when the thruster turns off

(b) What is the direction of the satellite's velocity when the thruster turns off? Give your answer as an angle measured counterclockwise from the +x-axis. ° counterclockwise from the +x-axis

Let be x and y-directions orthogonal to each other and the satellite is accelerated uniformly from rest in the +x direction and moves at constant velocity in the +y direction. The velocity vector of the satellite ([tex]\vec{v}_{S}[/tex]), measured in meters per second, is:

[tex]\vec{v}_{S} = (v_{o,x}+a_{x}\cdot t)\,\hat{i}+v_{y}\,\hat{j}[/tex]

Where:

[tex]v_{o,x}[/tex] - Initial velocity in +x direction, measured in meters per second.

[tex]a_{x}[/tex] - Acceleration in +x direction, measured in meter per square second.

[tex]t[/tex] - Time, measured in seconds.

[tex]v_{y}[/tex] - Velocity in +y direction, measured in meters per second.

If we know that [tex]v_{o,x} = 0\,\frac{m}{s}[/tex], [tex]a_{x} = 0.250\,\frac{m}{s^{2}}[/tex], [tex]t = 45\,s[/tex] and [tex]v_{y} = 21.4\,\frac{m}{s}[/tex], the final velocity of the satellite is:

[tex]\vec{v}_{S} = \left[0\,\frac{m}{s}+\left(0.250\,\frac{m}{s^{2}} \right)\cdot (45\,s) \right]\,\hat{i}+\left(21.4\,\frac{m}{s} \right)\,\hat{j}[/tex]

[tex]\vec{v_{S}} = 11.25\,\hat{i}+21.4\,\hat{j}\,\,\left[\frac{m}{s} \right][/tex]

a) The magnitud of the satellite's velocity can be found by the resource of the Pythagorean Theorem:

[tex]\|\vec {v}_{S}\| = \sqrt{\left(11.25\,\frac{m}{s} \right)^{2}+\left(21.4\,\frac{m}{s} \right)^{2}}[/tex]

[tex]\|\vec{v}_{S}\| \approx 24.177\,\frac{m}{s}[/tex]

The magnitude of the satellite's velocity when the thruster turns off is approximately 24.177 meters per second.

b) The direction of the satellite's velocity when the thruster turns off is determined with the help of trigonometric functions:

[tex]\tan \alpha = \frac{v_{y}}{v_{x}} = \frac{21.4\,\frac{m}{s} }{11.25\,\frac{m}{s} }[/tex]

[tex]\tan \alpha = 1.902[/tex]

[tex]\alpha = \tan^{-1}1.902[/tex]

[tex]\alpha \approx 62.266^{\circ}[/tex]

The direction of the satellite's velocity when the thruster turns off is approximately 62.266º.

Answer:

(A). The magnitude of the momentum of the marble is 0.004745 kg m/s.

(B). The speed of baseball is 23.0 m/s

Explanation:

Given that,

Mass of marble = 0.0073 kg

Speed = 0.65 m/s

(A). We need to calculate the magnitude of the momentum of the marble

Using formula of momentum

[tex]p = mv[/tex]

Where, m = mass

v = velocity

Put the value into the formula

[tex]p=0.0073\times0.65[/tex]

[tex]p=0.004745\ kg m/s[/tex]

(B). Mass of baseball = 0.136 kg

Momentum of baseball = 3.14 kg m/s

We need to calculate the speed of baseball

Using formula of momentum

[tex]p=mv[/tex]

[tex]v=\dfrac{p}{m}[/tex]

Put the value into the formula

[tex]v=\dfrac{3.14}{0.136}[/tex]

[tex]v=23.0\ m/s[/tex]

Hence, (A). The magnitude of the momentum of the marble is 0.004745 kg m/s.

(B). The speed of baseball is 23.0 m/s

Answer:

D) either 436 Hz or 444 Hz

Explanation:

frequency of the tuning fork, F₁ =  440 Hz

frequency of the piano, F₂ = ?

Beat frequency, F = 4 Hz

Beat frequency is given as the difference between the frequency of the two instruments  and it is given by;

F = F₂ - F₁                    or        F =  F₁ - F₂

F₂ = F + F₁                   or        F - F₁ = - F₂

F₂ = 4 Hz + 440 Hz    or       4 - 440 = - F₂

F₂ = 444 Hz                or      - 436 = - F₂

F₂ = 444 Hz               or         F₂ = 436 Hz

Therefore, the frequency of the piano is 444 Hz or 436 Hz

Answer:

[tex]x=8m[/tex]

Explanation:

Hello,

In this case, the most suitable kinematic equation for the calculation of the squirrel's displacement is:

[tex]x=v_ot+\frac{1}{2}at^2[/tex]

Whereas the initial velocity is zero as it starts from rest, thus, we obtain:

[tex]x=\frac{1}{2}*1.0\frac{m}{s^2}*(2.0s)^2\\ \\x=8m[/tex]

Best regards.

Answer:

I know

Explanation:

Physics= hard

Answer:

The range of initial speeds allowed to make the basket is: [tex]9.954\,\frac{m}{s}\leq v \leq 10.185\,\frac{m}{s}[/tex].

Explanation:

We must notice that basketball depicts a parabolic motion, which consists of combining a constant speed motion in x-direction and free fall motion in the y-direction. The motion is described by the following kinematic formulas:

x-Direction

[tex]x = x_{o} + v_{o}\cdot t \cdot \cos \alpha[/tex]

y-Direction

[tex]y = y_{o} + v_{o}\cdot t\cdot \sin \alpha +\frac{1}{2}\cdot g\cdot t^{2}[/tex]

Where:

[tex]x_{o}[/tex], [tex]y_{o}[/tex] - Initial position of the basketball, measured in meters.

[tex]x[/tex], [tex]y[/tex] - Final position of the basketball, measured in meters.

[tex]v_{o}[/tex] - Initial speed of the basketball, measured in meters per second.

[tex]t[/tex] - Time, measured in seconds.

[tex]\alpha[/tex] - Tilt angle, measured in sexagesimal degrees.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

If we know that [tex]x_{o} = 0\,m[/tex], [tex]y_{o} = 2.20\,m[/tex], [tex]\alpha = 36^{\circ}[/tex], [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], [tex]x = (9.10\pm0.23)\,m[/tex] and [tex]y = 2.70\,m[/tex], the system of equation is reduce to this:

[tex](9.10\pm 0.23)\,m = 0\,m + v_{o}\cdot t \cdot \cos 36^{\circ}[/tex]

[tex]9.10\pm 0.23 = 0.809\cdot v_{o}\cdot t[/tex] (Ec. 1)

[tex]2.70\,m = 2.20\,m + v_{o}\cdot t \cdot \sin 36^{\circ} + \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right) \cdot t^{2}[/tex]

[tex]0.50 = 0.588\cdot v_{o}\cdot t-4.904\cdot t^{2}[/tex] (Ec. 2)

At first we clear [tex]v_{o}\cdot t[/tex] in (Ec. 1):

[tex]v_{o}\cdot t = \frac{9.10\pm 0.23}{0.809}[/tex]

[tex]v_{o}\cdot t = 11.248\pm 0.284[/tex]

(Ec. 1) in (Ec. 2):

[tex]0.5 = 0.588\cdot (11.248\pm 0.284)-4.904\cdot t^{2}[/tex]

Now we clear the time in the resulting expression:

[tex]4.904\cdot t^{2} = 0.588\cdot (11.248\pm 0.284)-0.5[/tex]

[tex]t = \sqrt{\frac{0.588\cdot (11.248\pm 0.284)-0.5}{4.904} }[/tex]

There are two solutions:

[tex]t_{1} = \sqrt{\frac{0.588\cdot (11.248- 0.284)-0.5}{4.904} }[/tex]

[tex]t_{1} \approx 1.101\,s[/tex]

[tex]t_{2} = \sqrt{\frac{0.588\cdot (11.248+ 0.284)-0.5}{4.904} }[/tex]

[tex]t_{2}\approx 1.131\,s[/tex]

The initial velocity is cleared within (Ec. 2):

[tex]v_{o}=\frac{0.50+4.904\cdot t^{2}}{0.588\cdot t}[/tex]

The bounds of the range of initial speed is determined hereafter:

[tex]t_{1} \approx 1.101\,s[/tex]

[tex]v_{o} = \frac{0.50+4.904\cdot (1.101)^{2}}{0.588\cdot (1.101)}[/tex]

[tex]v_{o} = 9.954\,\frac{m}{s}[/tex]

[tex]t_{2}\approx 1.131\,s[/tex]

[tex]v_{o} = \frac{0.50+4.904\cdot (1.131)^{2}}{0.588\cdot (1.131)}[/tex]

[tex]v_{o} = 10.185\,\frac{m}{s}[/tex]

The range of initial speeds allowed to make the basket is: [tex]9.954\,\frac{m}{s}\leq v \leq 10.185\,\frac{m}{s}[/tex].

Answer:

n an electrometer, it is built in such a way that its resistance in parallel is extremely high

Ground in a circuit is a reference point from which voltages are measured

all the instruments must be grounded and we must ground ourselves

Explanation:

When you build a voltmeter you have a resistance in parallel with the galvanometer, therefore when measuring the voltage of a circuit, so that there is no effect (load effect) by the voltmeter, a resistance must be much greater than the resistance where it is is measuring.

In an electrometer, it is built in such a way that its resistance in parallel is extremely high in the order of 10¹²Ω, so its load effect is very small and can be measured with high resistance mu

Electric ground in home and industrial installations is a protection system consisting of a metal piece connected to a buried ground electrode.

Ground in a circuit is a reference point from which voltages are measured and is common to all parts of the circuit

In an experiment where an electrometer is used, all the instruments must be grounded and we must ground ourselves, since it must be an instrument where very small voltages are measured at high impedances.

Sulfur, a nonmetal with 6 valence electrons atom is most likely to accept electrons to form an ionic bond option (D) correct.

Ionic bonds, also known as electrovalent bonds, are a type of connection created in a chemical molecule by the electrostatic attraction of ions with opposing charges.

As we know,

It has been shown that the top of the electronegativity scale is defined by the fundamental atomic particles F>O>N.

Ionic bonds need an electron, often a nonmetal, and an electron, typically a metal. Metals display ionic bonding because there aren't many-electron in outer orbitals.

Thus, sulfur, a nonmetal with 6 valence electrons atom is most likely to accept electrons to form an ionic bond option (D) correct.

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Explanation:

13+x=43>2x

13+x=43>2x+43>2x

13+x=86>4x

x-4x=86-13

3x=73

x=73/3

x=24.333

x=24.4