The formula P = I-E is used to calculate profit.
P = Profit
I= Income
E = Expenses
The school bake sale earned $72 in sales and had
$125 in expenses.
Find the profit.
b. What does a negative profit mean?

Answer:

To find each length in the new scale drawing, you can multiply each length in the original scale drawing by this scale factor between the two scale drawings. ▫.

fdddkgStep-by-step explanation:

Answer:

1944 cubic cm

Step-by-step explanation:

Find the answer by figuring out the volumes independently for each figure.  After doing that, add both volumes together to get the full volume.

Bottom figure: 1440 cubic cm

Top figure: 504 cubic cm

Add those together: 1944 cubic cm

Answer:

$4440 for all performances

Step-by-step explanation:

11 × ¢120 for short performances

12 × $260 for long performances

$1320 for short performances

$3120 for long performances

To get the totel you add them up

( $1320 + $3120)

The total is $4440

Divide money earned by hours worked to get the hourly rate of $11.00 per gour.

Answer: C. $11.00 per hour

She makes a minimum monthly payment of 62.52 dollars. Then the correct option is B.

The amount of something is expressed as if it is a part of the total which is a hundred. The ratio can be expressed as a fraction of 100. The word percent means per 100. It is represented by the symbol ‘%’.

May currently has a balance of $1,817.43 on her credit card.

If she must make a minimum monthly payment of 3.44% of her total balance.

Then the minimum payment will be given as

Minimum payment = 0.0344 × 1817.43

Minimum payment = 62.519 ≅ 62.52

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Hey there!

A car is purchased for $23,000 . Each year it loses 30% of its value. After how many years will the car be worth $6700 or less? (Use the calculator provided if necessary.) Write the smallest possible whole number answer.

Set up the depreciation equation D(t) where t is the number of years in the life of the car:

D(t) = 23,000/(1.3)^t

The problem asks for D(t)<=6800

23,000/(1.3)^t = 6800

Cross multiply:

7300(1.3)^t = 24,000

Divide each side by 6800

1.3^t = 23000/6800

1.3^t = 3.38

Take the natural log of both sides:

LN(1.3^t) = LN(3.38)

Using the natural log identities, we have:

t * LN(1.3) = 1.22

t * 0.2624 = 1.22

Divide each side by 0.2624

t = 4.6494

Rounding this up, we have t = 5

Answer:

it would be 7647

close enough though

Step-by-step explanation:

Answer:

760

Step-by-step explanation:

Answer:

760 of course

Step-by-step explanation:

3 is below 5 so its 760

If the last digit was a 5 or higher,it'll be 770

Answer

One case of sprite costs 3 dollars, All four cases are $12. You can buy 16 cases of sprite with 48 dollars.

Step-by-step explanation:

How to get the cost for 1 case:

You have 4 cases of sprite which all four combined costs $12. You divide 12 by 4 and get 3.

How to get the amount of cases of sprite you can buy with $48:

divide 48 by 3 and you get 16. Why 3? Because 3 is the amount per case and 16 x 3 is 48. Thank me later!

Answer:

It costs $3 per case of Sprite

With 48 dollars, you could buy 16 cases.

Step-by-step explanation:

12/4 = 3    12 dollars divided buy 4 dollars each equals 3 dollars per case

48/3 = 16  48 dollars divided by 3 dollars per case equals 16 cases of sprite

Answer:

Bottom left = 8

Top right = 15

Middle right = 25

Step-by-step explanation:

Total = 40

3 + 5 = 8

40 / 8 = 5

1 part = 5

5 x 3 = 15

5² = 25

Answer:

$750

Step-by-step explanation:

2500 divided by 100 = 25 and 25 x 30 = 750

Sorry if im wrong

The price for 2500 pencils is $750.

The unitary technique involves first determining the value of a single unit,  followed by the value of the necessary number of units.

For example, Let's say Ram spends 36 Rs. for a dozen (12) bananas.

12 bananas will set you back 36 Rs. 1 banana costs 36 x 12 = 3 Rupees.

As a result, one banana costs three rupees. Let's say we need to calculate the price of 15 bananas.

This may be done as follows: 15 bananas cost 3 rupees each; 15 units cost 45 rupees.

We have,

A box of 100 personalized pencils costs $30.

So, cost of 1 pencil = $30 / 100 = 3/10

Now, the price to buy the 2500 pencils

= 2500 x 3/10

= 250 x 3

= $750

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Steps to finding the line in the diagram with the format 'ax + by = c

1. Find the slope

                  [tex]Slope = \frac{y2-y1}{x2-x1} =\frac{4-0}{0-3} =-\frac{4}{3}[/tex]

2. Set up, with any one point on the line and the slope, in point-slope form

        [tex](y-y0)=m(x-x0)\\(y-4)=-\frac{4}{3} (x-0)\\y-4 = -\frac{4}{3} x\\\frac{4}{3}x+y = 4[/tex]

Answer: [tex]\frac{4}{3}x+y = 4[/tex]

Hope that helps!

Answer:

[tex]\sf 4x+3y=12[/tex]

Step-by-step explanation:

Choose two points on the line:

Let [tex]\sf (x_1,y_1)=(0,4)[/tex]

Let [tex]\sf (x_2,y_2)=(3,0)[/tex]

Use the slope formula to find the slope of the line:

[tex]\sf slope(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{0-4}{3-0}=-\dfrac43[/tex]

Use the point-slope formula to find the equation of the line:

[tex]\sf y-y_1=m(x-x_1)[/tex]

Substitute values into the formula:

[tex]\sf y-4=-\dfrac43(x-0)[/tex]

Expand the brackets:

[tex]\sf y-4=-\dfrac43x[/tex]

Add 4 to both sides:

[tex]\sf y=-\dfrac43x+4[/tex]

Rearrange into the form [tex]ax+by=c[/tex]

Multiply both sides by 3

[tex]\sf 3y=-4x+12[/tex]

Add 4x to both sides:

[tex]\sf 4x+3y=12[/tex]

Step-by-step explanation:

1 ounce = 28grams

x grams = 392

x = 392/28

x = 14.oo ounces

Answer:

1/6

Step-by-step explanation:

Given;

Luis is going to roll a six-sided die. What is the probability that the die lands on the number 4?

Solve:

Six-sided die = 6

There are only one 4 in the six-sided die.

Hence, fraction = [tex]\frac{1}{6}[/tex]

~Lenvy~

Answer:

1

Step-by-step explanation:

5 + 4 - (8 x 3 – 22)* x 4

5 + 4 - (24 - 22) x 4

5 + 4 - 2 x 4

5 + 4 - 8

1

Answer:

16

Step-by-step explanation:

5+4- (8x3-22) ↑4 x4

         16

5+4 - (24-22) ↑4 x4

5+4- (2) ↑4 x4

2x2x2x2=16

hope that helps:)

Answer:

Answer: 1.4

Step-by-step explanation:

P(Northern pike) = 0.7

P(walleye) = 0.3

If 2 fishes are caught :

Number of northern pike (x) :

X = 0

P(walleye 1 st) * p(walleye 2nd) = (0.3 * 0.3) = 0.09

X = 1

P(walleye 1st)*P(Northern pike 2nd) OR P(Northern pike 1st)*P(Walleye 2nd)

= (0.3 * 0.7) + (0.7 * 0.3)

= 0.21 + 0.21

= 0.42

P(x = 2)

P(northern pike 1st) * P(northen pike 2nd)

0.7 *0.7 = 0.49

X: _ 0 _ 1 __ 2

P(x): ___ 0.09 ___ 0.42 ____ 0.49

Expected value of northern pikes :

(0* 0.09) + (1 * 0.42) + (2 * 0.49)

0 + 0.42 + 0.98

= 1.4

Expected value of the number of walleye is 0.5.

The expected value exists as a long-run average value of random variables. It also demonstrates the probability-weighted average of all possible values. Expected value exists as a generally utilized financial concept.

W = # of walleye 0, 1, 2

P(W) 0. 49, 0. 42, 0. 09

To estimate the expected value of the number of walleye.

E(X) =  number of walleye

E(X) = (0 [tex]\times[/tex] 0.49) + (1 [tex]\times[/tex] 0.42) + (2 [tex]\times[/tex] 0.09)

E(X) = 0 + 0.42 + 0.08

E(X) = 0.5

Therefore, the number of walleye expected value = 0.5.

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Answer:

there are 18 milk chocolates

Answer:

Step-by-step explanation:

convert it to fraction first: 2/5 are plain and 3/5 is milk

30÷5= 6

2x6=12

3x6=18

to check wheter or not it is correct add the amount. if it gets the total, it is correct.

Answer:

[tex]\displaystyle y' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \tan^2 x + 5x \big) + \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( 2 \sec^2 x \tan x + 5 \big)}{ \big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)} + \frac{2 \cot x \csc^2 x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2 \big( \sin^2x + 6 \big)} - \frac{2 \cos x \sin x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)^2}[/tex]

General Formulas and Concepts:
Calculus

Differentiation

Derivative Property [Multiplied Constant]:
[tex]\displaystyle (cu)' = cu'[/tex]

Derivative Property [Addition/Subtraction]:
[tex]\displaystyle (u + v)' = u' + v'[/tex]

Derivative Rule [Basic Power Rule]:

Derivative Rule [Product Rule]:
[tex]\displaystyle (uv)' = u'v + uv'[/tex]

Derivative Rule [Quotient Rule]:
[tex]\displaystyle \bigg( \frac{u}{v} \bigg)' = \frac{vu' - uv'}{v^2}[/tex]

Derivative Rule [Chain Rule]:
[tex]\displaystyle [u(v)]' = u'(v)v'[/tex]

Step-by-step explanation:

*Note:

Since the answering box is way too small for this problem, there will be limited explanation.

Step 1: Define

Identify.

[tex]\displaystyle y = \frac{\cos^2 x - 3\sqrt{x} +6}{\sin^2 x + 6} \times \frac{\tan^2 x + 5x}{\csc^2 x + 3}[/tex]

Step 2: Differentiate

We can differentiate this function with the use of the given derivative rules and properties.

Applying Product Rule:

[tex]\displaystyle y' = \bigg( \frac{\cos^2 x - 3\sqrt{x} + 6}{\sin^2 x + 6} \bigg)' \frac{\tan^2 x + 5x}{\csc^2 x + 3} + \frac{\cos^2 x - 3\sqrt{x} +6}{\sin^2 x + 6} \bigg( \frac{\tan^2 x + 5x}{\csc^2 x + 3} \bigg) '[/tex]

Differentiating the first portion using Quotient Rule:

[tex]\displaystyle \bigg( \frac{\cos^2 x - 3\sqrt{x} + 6}{\sin^2 x + 6} \bigg)' = \frac{\big( \cos^2 x - 3\sqrt{x} + 6 \big)' \big( \sin^2 x + 6 \big) - \big( \sin^2 x + 6 \big)' \big( \cos^2 x - 3\sqrt{x} + 6 \big)}{\big( \sin^2 x + 6 \big)^2}[/tex]

Apply Derivative Rules and Properties, namely the Chain Rule:

[tex]\displaystyle \bigg( \frac{\cos^2 x - 3\sqrt{x} + 6}{\sin^2 x + 6} \bigg)' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \sin^2 x + 6 \big) - \big( 2 \sin x \cos x \big) \big( \cos^2 x - 3\sqrt{x} + 6 \big)}{\big( \sin^2 x + 6 \big)^2}[/tex]

Differentiating the second portion using Quotient Rule again:

[tex]\displaystyle \bigg( \frac{\tan^2 x + 5x}{\csc^2 x + 3} \bigg) ' = \frac{\big( \tan^2 x + 5x \big)' \big( \csc^2 x + 3 \big) - \big( \csc^2 x + 3 \big)' \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2}[/tex]

Apply Derivative Rules and Properties, namely the Chain Rule again:
[tex]\displaystyle \bigg( \frac{\tan^2 x + 5x}{\csc^2 x + 3} \bigg) ' = \frac{\big( 2 \tan x \sec^2 x + 5 \big) \big( \csc^2 x + 3 \big) - \big( -2 \csc^2 x \cot x \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2}[/tex]

Substitute in derivatives:

[tex]\displaystyle y' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \sin^2 x + 6 \big) - \big( 2 \sin x \cos x \big) \big( \cos^2 x - 3\sqrt{x} + 6 \big)}{\big( \sin^2 x + 6 \big)^2} \frac{\tan^2 x + 5x}{\csc^2 x + 3} + \frac{\cos^2 x - 3\sqrt{x} +6}{\sin^2 x + 6} \frac{\big( 2 \tan x \sec^2 x + 5 \big) \big( \csc^2 x + 3 \big) - \big( -2 \csc^2 x \cot x \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2}[/tex]

Simplify:

[tex]\displaystyle y' = \frac{\big( \tan^2 x + 5x \big) \bigg[ \big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \sin^2 x + 6 \big) - 2 \sin x \cos x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \bigg]}{\big( \sin^2 x + 6 \big)^2 \big( \csc^2 x + 3 \big)} + \frac{\big( \cos^2 x - 3\sqrt{x} +6 \big) \bigg[ \big( 2 \tan x \sec^2 x + 5 \big) \big( \csc^2 x + 3 \big) + 2 \csc^2 x \cot x \big( \tan^2 x + 5x \big) \bigg] }{\big( \csc^2 x + 3 \big)^2 \big( \sin^2 x + 6 \big)}[/tex]

We can rewrite the differential by factoring and common mathematical properties to obtain our final answer:

[tex]\displaystyle y' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \tan^2 x + 5x \big) + \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( 2 \sec^2 x \tan x + 5 \big)}{ \big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)} + \frac{2 \cot x \csc^2 x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2 \big( \sin^2x + 6 \big)} - \frac{2 \cos x \sin x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)^2}[/tex]

∴ we have found our derivative.

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Topic: Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

The length of the blade of the windmill will be equal to 7 feet.

We have the equation

[tex]\rm h=7 \ Sin(\dfrac{\pi}{21t})+28[/tex]

At the time 't' = 0, the end of the blade is pointing to the right parallel to the ground meaning it is at the same height as the other end. (Ф = 0°)

So, by calculating the maximum height of this end at  Ф = 90°. we can calculate the length of the blade.

Now, we know that a general model equation of a circular simple harmonic motion is represented as

[tex]\rm y=A\ Sinwt+k[/tex]

Where A is the amplitude that is, maximum displacement from mean to maximum position.

ω is the angular frequency.

Comparing the above equations we can conclude that

A = 7

so the difference in blade's end height at Ф = 0° and Ф = 90° is 7 feet.

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Answer:

7ft or option 1

Step-by-step explanation:

Answer:

y = x - 5

Step-by-step explanation:

Line A

Equation

Answer:

A: (x-4) squared

B: x+2

C: 9

D: 14

E: 7

F: 2

Step-by-step explanation:

A: This is because x^2 - 8x + 16 factored is (x-4) squared

B: Square root of something squared will remove the square root

C: Minus the variable x and 2 from the right side

D: Factor

E/F: These numbers make the right side become zero

Answer: WZ=10, YZ=15

Step-by-step explanation:

Answer:

A = bh

A = 45 x 46

A = 2070 inches

Answer:

2070 squre in

Step-by-step explanation:

because the base is 46 and the height is 45 then we just multiply the two together to find the area.

so we solve it and we get

45*46=2070

Answer:

The answer should be B. 86.7

[tex]0.75x = 15[/tex]

[tex]x = \frac{15}{0.75} = 20[/tex]

[tex]0.15(20) = 3[/tex]

Answer: You can use the definition of percentage and the proportions to solve this question. 75% means 75/100, the you want to know which fraction of 15 equals 75/100, which is to solve this proportion: 75/100 = 15/x. Solving for x, x = 15 * 100 / 75 = 20. You can check that the 75% of 20 is equal to 15: 20 * 75% = 20*75/100 = 15. So, the answer is 20.

Step-by-step explanation:

Answer:

15

Step-by-step explanation:

Okay, so we know that Base*Length=Area, so we just have to divide the area by the base, so the formula here is Area/Base=Length.

That would get us 120/8=Length,

and if we just divide 120 by 8 we get 15, so the length is 15

The place values in 5.6 and 1.78 are the positions of the digits in the numbers

In a number, the non-zero digit at the left-most position is the greatest place value

This means that:

The greatest place value in 5.6 is 5 (i.e. ones place)

The greatest place value in 1.78 is 1 (i.e. ones place)

So, we can conclude that the largest place value common in 5.6 and 1.78 is the ones place

Hence, Nichole is correct

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