**Answer:**

(a) The force changes its magnitude with respect to displacement, hence the total work will be sum of increment of work in three steps:-

step 1 . from 0 to 0.25m .

force = 0.6 N

displacement= 0.25m

work done =( force × displacement) = (0.25 × 0.6 ) = 0.15 joule.

step 2:- .

work done in moving from 0.25 to 0.50 m.

work done = ( force × displacement) = ( 0.4 × 0.25) = 0.10 Joule. .

step 3 :-

work done in moving from 0.50 to 0.75 m

work done = 0.8 × 0.25 = 0.200 joule.

hence total work done = ( 0.20+0.10+0.15) = 0.45 joule. ans

(b) similar concept you have to use here also.

step 1:

from 0.20 to 0.50, force of magnitude 0.4 N acts on the object.

Work done = ( 0.50-0.20)× 0.4 = 0.30 × 0.4 = 0.12 joule.

step :- 2

from 0.50 to 0.55 , force of magnitude 0.8 N acts on the block.

work done = 0.8× ( 0.55- 0.50) = 0.04 joule

total work done = 0.04 + 0.12 = 0.16 joule. ans

What causes the difference in the angle of the sun on the Earth's surface throughout the year?

**Answer:**

The axis is tilted and points to the North Star no matter where Earth is in its orbit. Because of this, the distribution of the Sun's rays changes. ... It also means that the angle at which sunlight strikes different parts of Earth's surface changes through the year.

**Explanation:**

Pls sub to bdoggaming if this helped

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!pls

I think this is the solution:

1: U-1, F,-4

2: Na-6, Mo-1, O-4

3: Bi-1, O-1, C-1, I-1

4: In-9, N-1

5: N-2, H-4, S-1, C-1

6: Ge- 15, N-4

7: N-1, H-4, C-1, I-1, O-3

8: H-7, F-1

9: N-1, O-5, H-1, S-1

10: H-8

11: Nb-1, O-1, C-1, I-3

12: C-3, F-3, S-1, O-3, H-1

13: Ag-1, C-1, N-1, O-1

14: Pb-6, H-1, As-1, O-4

1: U-1, F,-4

2: Na-6, Mo-1, O-4

3: Bi-1, O-1, C-1, I-1

4: In-9, N-1

5: N-2, H-4, S-1, C-1

6: Ge- 15, N-4

7: N-1, H-4, C-1, I-1, O-3

8: H-7, F-1

9: N-1, O-5, H-1, S-1

10: H-8

11: Nb-1, O-1, C-1, I-3

12: C-3, F-3, S-1, O-3, H-1

13: Ag-1, C-1, N-1, O-1

14: Pb-6, H-1, As-1, O-4

Which of these is Newton's 3rd law of motion?

Equal and opposite forces

F = m x a

Inertia

Gravity

the answer is equal and opposite forces.

Use the sentence to answer the question.

Light is affected by gravity.

Which inference can be made based on this fact?

(1 point)

Light behaves differently in space than on Earth.

Light behaves differently in space than on Earth.

Gravity causes light to refract.

Gravity causes light to refract.

Light moves faster in space than on Earth.

Light moves faster in space than on Earth.

Stronger gravity causes an increase in light.

**Answer:**

Light behaves differently in space than on Earth.

**Explanation:**

Because the gravity field is greater near earth than in most of space. Not the areas near stars, black holes, pulsars, and such but in the vast emptyness between the clumpy spots.

A 0.50-kg block attached to an ideal spring with a spring constant of 80 N/m oscillates on a horizontal frictionless surface. The total mechanical energy is 25 J. The maximum speed of the block is:

**Answer:**

**Explanation:**

easy way

when system is all kinetic energy, velocity is at a maximum

E = ½mv²

v = √(2E/m) = √(2(25)/0.5) = √100 = **10 m/s**

harder way

ω = √(k/m) = √(80/0.5) = √160 rad/s

When the system is entirely spring potential, the amplitude A is

E = ½kA²

A = √(2E/k) = √(2(25)/80) = 0.790569... = 0.79 m

maximum velocity is ωΑ = 0.79√160 = **10 m/s**

Question 4 of 10

What is thermodynamics?

A. The movement of matter

B. The flow of fluids

C. The movement of particles

D. The flow of energy, heat, and work

SUBMIT

**Answer:**

**Explanation:**

D.

Thermodynamics is the study of how different types of energy is transferred through the chemical systems

**Answer: Thermodynamics is the flow of energy, heat, and work.**

**Explanation: This is seen in the formula for the first law of thermodynamics, U = Q - W, or “The change of the internal energy of a system (U) is equal to the heat absorbed (Q) minus the work done by that system (W).”**

I need a short answer ?

**Answer:**

**Explanation:**

7a) t = d/v = 100/45cos14.5 = 2.29533...= **2.30 s**

7b) h = ½(9.81)(2.29533/2)² = 6.46056... = **6.45 m**

** **or

h = (45sin14.5)² / (2(9.81)) = **6.47 m**

which rounds to the same 6.5 m when limiting to the two significant digits of the initial velocity.

What are sound detectors?

**Answer:**

A sound detector comes in the shape of a rectangular board which comprises a microphone as well as a processing circuitry.

**Answer:**

Sound detection sensor works similarly to our Ears, having diaphragm which converts vibration into signals.

A car travels a certain distance from A to B with a speed of 60km/hr and then returns along the same path to the starting point with a speed of 40km/hr. Find the average speed and average velocity.

a) Km/hr

b) m/s

wrong answers will be reported!

**Answer:**

**Explanation:**

Speed is total distance traveled over time taken to do so.

If AB is measured in kilometers, time (t) for the whole trip is

t = AB/60 + AB/40

t = 2AB/120 + 3AB/120

t = 5AB/120 hrs

Average speed is distance over time

s = 2AB / (5AB/120)

s = 2(120)/5

**s =** **48 km/hr**

**s = **48(1000 m/km / 3600 s/hr) = 13.333333.... **13 m/s**

Velocity is displacement over time.

As displacement is zero, velocity is zero

**v = 0 km/hr = 0 m/s**

Pretty harsh reporting answers just because they are wrong.

I need help. please look at the image below and let me know I need this by 7:20 am pst.

**Answer:**

3(1.5) =** 4.5 V**

**Explanation:**

2 examples of non fossil fuels ?

**Answer:**

-> Hydropower

-> Solar power

**Explanation:**

-> Hydropower

[] The power of water! It is the use of falling or fast-running water to produce electricity for power. Impoundments or da*ms are mainly used in this type of power source.

-> Solar power

[] The power of the sun! It is the use of sunlight, or solar energy, to produce electricity for power. You have probably heard of solar panels, and this is the main way to collect it.

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

**Answer:**

Wind energy and solar power

**Explanation:**

they do not use fossil fuels

An object, initially traveling at a velocity of 73 m/s, experiences an acceleration of -9.8 m/s^2. How much time will it take it to come to rest?

7.4 s

**Explanation:**

Given:

[tex]v_0 = 73\:\text{m/s}[/tex]

[tex]v = 0[/tex]

[tex]a = -9.8\:\text{m/s}^2[/tex]

[tex]t = ?[/tex]

To solve the time it takes for the object to come to a stop, we are going to use the equation below:

[tex]v = v_0 + at \Rightarrow t = \dfrac{v - v_0}{a}[/tex]

Using the given values above, we get

[tex]t = \dfrac{0 - 73\:\text{m/s}}{-9.8\:\text{m/s}^2}[/tex]

[tex]\;\;\;\;= 7.4\:\text{s}[/tex]

5.000 km =

3.125

mi

8.000 fl oz =

mL

**Answer:**

236.588 mL

**Explanation:**

The formula for an approximate result is to multiply the volume value by 29.574

[tex]8.000 \times 29.574 = 236.588[/tex]

Is that what you were asking for?

Cody hits up food king and uses a scale to weigh the mass of an apple. if the spring potential energy in the scale is .09 j and is spring is stretched 0.6 meters, calculate the spring constant

**Answer:**

**oK so here's** **what you should do is add .09 and 0.6**

**Explanation:**

A wheel in the shape of a flat, heavy, uniform, solid disk is initially at rest at the top of an inclined plane of height 2.00 m when it begins to roll down the incline. If rolling and sliding friction are neglected, what is the linear velocity, in m/s, of the center-of-mass of the wheel when it reached the bottom of the incline?

**Answer:**

**Explanation:**

If friction is neglected, the wheel cannot roll and can only slide frictionlessly and will have the same velocity at the bottom of the ramp as if it had been in free fall as it has converted the same amount of potential energy.

mgh = ½mv²

v = √(2gh) = √(2(9.81)(2.00)) = 6.26418... =** 6.26 m/s**

However if we do not ignore all friction and the wheel rolls without slipping down the slope, the potential energy becomes linear and rotational kinetic energy

mgh = ½mv² + ½Iω²

mgh = ½mv² + ½(½mR²)(v/R)²

2gh = v² + ½v²

2gh = 3v²/2

v = √(4gh/3) =√(4(9.81)(2.00)/3) = 5.11468... = **5.11 m/s**

why is it so important that you take care of your nervous system?

**Answer:**

The nervous system handles the stress response, which, if overworked, can eventually lead to diseases ranging from high blood pressure to diabetes.

**Explanation:**

hope I helped

If you apply a net force of 100 N to the hoverboard, and it accelerates

2m/s/s, how much mass does it have?

**Answer:**

**Explanation:**

The mass of an object given only the force acting on it and it's acceleration can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force in N

a is the acceleration in m/s²

From the question

f = 100 N

a = 2 m/s²

We have

[tex]m = \frac{100}{2} = 50 \\ [/tex]

We have the final answer as

50 kgHope this helps you

A 5 kilograms bowling ball is dropped out a window. It hits the ground, and bounces upward. The velocity change of the ball is noted to be 15 m/s downward and 12 m/s upward. What is the contact time for the ball if the force applied on the ball from the ground is equal to 10 N?

**Answer:**

13.5

**Explanation:**

Mass: 5kg

Initial Velocity: -15

Final Velocity: 12

Force: 10

We can use the equation: Vf = Vi + at

We need to find acceleration, and we can use the equation, F=ma,

We have mass and the force so it would look like this, 10=5a, and 5 times 2 would equal 10, so acceleration would be 2.

Now we have all the variables to find time.

Back to Vf = Vi + at, plug the numbers in, 12 = -15 + 2(t)

Plugging them in into desmos gives 13.5 for time.

Air currents escape room level 3 how to do it

**Answer:**

just do it. it's simple be smart friends

What initial speed v is required if the blocks m1 =2.5 kg and m2=1.5 kg are to travel a distance d =7.0cm before coming to rest? Assume the coefficient of kinetic friction between m1 and the tabletop is ųk=0.21

**Answer:**

*OPTRIMUM** **PRIDE** **URGH** **URGH** **URGH** *

**Explanation:**

**AHHAAHAHAHAHA**

HELPPP!! Thanks!

If you only wanted to increase the particle motion of a gas without increasing any of its other properties, which would the most correct situation?

a. Keep the gas at a constant pressure and keep the temperature constant, but increase the volume of the gas

b. Keep the gas in a fixed container at constant pressure and increase the temperature

c. Keep the gas in a fixed container at constant pressure and decrease the temperature

d. Keep the gas at a constant volume and keep the temperature constant, but decrease the pressure of the gas

**Answer:c i think**

**Explanation: not sure**

8 N to the left , and 4 N to the right. Find the net force. Is this balanced?

**Explanation:**

12N by first law of newton is net force after colloision

A mars surface exploration vehicle drops a rock off a 1.00 I'm high vertical Cliff. The sound of the rock landing at the base of the cliff is recorded by instruments on the vehicle 27.1 seconds later. Calculate the acceleration due to gravity on Mars given that the speed of sound on Mars is 320 m/s

The **acceleration **due to **gravity **on **Mars **is** 11.81 m/s²**.

The given parameters:

The **equation **of motion to determine the **acceleration **due to **gravity **on the moon is calculated as follows;

[tex]s = vt + \frac{1}{2} gt^2[/tex]

where;

Since the **time **measured is **two way time**, the new equation for the **total distance** traveled is calculated as;

[tex]v = \frac{2d}{t} \\\\2d = vt\\\\d = \frac{vt}{2} \\\\d = \frac{320 \times 27.1}{2} \\\\d = 4,336 \ m[/tex]

The **acceleration **due to **gravity **is calculated as follows;

[tex]s = vt + \frac{1}{2} gt^2\\\\4,336 = 0 \ + \ \frac{1}{2} \times g \times (27.1)^2\\\\4,336 = 367.21g\\\\g = \frac{4,336}{367.21} \\\\g = 11.8 1 \ m/s^2[/tex]

Thus, the **acceleration **due to **gravity **on **Mars **is** 11.81 m/s²**.

Learn more about **acceleration **due to **gravity **here: https://brainly.com/question/88039

Explain how the linear rate spring operates?

A linear spring has the same diameter along its entire length, and this uniform diameter gives it a constant spring rate.

A 300 cm rope under a tension of 120 N is set into oscillation. The mass density of the rope is 120 g/cm. What is the frequency of the first harmonic mode (m

**Answer:**

**Explanation:**

f = [tex]\sqrt{T/(m/L)} / 2L[/tex]

T = 120 N

L = 3.00 m

(m/L) = 120 g/cm(100 cm/m / 1000 g/kg) = 12 kg/m

(wow that's massive for a "rope")

f = [tex]\sqrt{120/12} /(2(3))[/tex])

**f = **[tex]\sqrt{10\\}[/tex]/6 = **0.527 Hz**

This is a completely silly exercise unless this "rope" is in space somewhere as the weight of the rope (353 N on earth) far exceeds the tension applied.

A much more reasonable linear density would be 120 g/m resulting in a frequency of √1000/6 = 5.27 Hz on a rope that weighs only 3.5 N

The number of wavelengths that pass a fixed point on a wave is called ______?

**Explanation:**

it's called a wave frequency

im pretty sure but than again I'm in Middle School but just trust me

**Answer:**

wave frequency i think. hope its helps

The diagram below shows a 5.00-kilogram block

at rest on a horizontal, frictionless table.

5.00-kg

block

Table

Which of the following is the correct name and strength of the force holding the block up?

The **name **and **strength **of the **force **holding the **block **up is **50 N upward - Normal force.**

The given parameters:

The **weight **of the block acting **downwards **due to gravity is calculated as follows;

W = mg

where;

W = 5 x 10

W = 50 N *(**downwards**)*

Since the **block **is at **rest**, an a force equal to the weight of the block must be acting upwards. This force is known as **normal reaction.**

Fₙ = 50 N *(**upwards**)*

Thus, the **name **and **strength **of the **force **holding the **block **up is **50 N upward - Normal force.**

Learn more about **Normal force** here: https://brainly.com/question/14486416

The block will remain on the table because the **normal force balances with the weight of the block**. The correct answer is **50 N upward normal force**

From the diagram shown a 5.00-kilogram block at rest on a horizontal, frictionless table. The weight of the block will act downward which will be

**Weight W = mg**

let g = 10 m/[tex]s^{2}[/tex]

W = 5 x 10

W = 50 N

The block will also produce an equal but in opposite direction of a normal force which is** equal to the weight of the block**. That is,

Normal force N = 50 N

The block will remain on the table because the normal force balances with the weight of the block.

Therefore, the correct name and strength of the force holding the block up is **50 N upward normal force**.

Learn more about stability here: https://brainly.com/question/517289

A wagon of dog treats (combined mass 55 kg) is rolling at 2.1 m/s. A dog with mass 21 kg dives into the wagon, colliding with just enough momentum to make both stop. If the collision between the dog and the wagon lasts 0.1 s, what is the magnitude of the average force that will be exerted on the dog by the collision with the wagon

**Answer:**

**Explanation:**

An impulse results in a change of momentum

If the wagon and dog both stop, they must have had equal and opposite momentums

FΔt = mΔv

F = mΔv/Δt = m(v₁ - v₀)/(t₁ - t₀)

v₁ = t₀ = 0

F = m(v₀)/t₁

**F =** 55(2.1)/0.1 = **1155 N**

We could have also figured the dog's initial velocity and used the dog's mass in the equation as well. Result would be identical.

Important parts of stydi g physics

**Answer:**

put your question in proper way' i hope you understand.

**Explanation:**

WILL GIVE BRAINLIEST!!! NO LINKS PLZ!!!!

A 225 g hockey puck is sliding on ice in an arena towards the end boards that are 15.7 m away. The puck is travelling 12.0 m/s when it slides into some rough ice (coefficient of kinetic friction= 0.550).

Determine:

a) the acceleration of the puck on the rough ice.

b) the distance from the end boards the puck is when it comes to a stop.

Please show work.

**Answer:**

**Explanation:**

a) the acceleration of the puck on the rough ice.

a = μg = 0.550(9.81) = 5.3955 = **5.40 m/s²**

(comes from μ = F/N = ma/mg = a/g)

b) the distance from the end boards the puck is when it comes to a stop.

v² = u² + 2as

0² = 12.0² + 2(-5.40)s

s = 13.3 ft

so distance from the boards is

15.7 - 13.3 = **2.4 m**

by the way...that's some VERY rough ice...more like sand.

HELP!!! PLEAAASSEEEE
in unlocking christmas, what holiday emblem is embedded in the keys given to kate and kevin?
When a baseball curves to the right (a curveball) , air is flowing faster over the right side than over the left side. at the same speed all around the baseball, but the ball curves as a result of the way the wind is blowing on the field. faster over the left side than over the right side. faster over the top than underneath.
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