The following data points represent the number of children in each household in Cam's neighborhood.
0, 0,6,3,1,5, 0, 2,0
How many households in Cam's neighborhood have 0 children?
households

The Following Data Points Represent The Number Of Children In Each Household In Cam's Neighborhood.0,

Answers

Answer 1

Answer:

4

Step-by-step explanation:

We can see that 9 households are represented in the data, 4 of them are zeros. This means 4 households in Cam's neighborhood have 0 children.


Related Questions

Write the fraction in simplest form.
12x^2/28x

Answers

Answer: (-6x - 5) • (2x + 3)

Step-by-step explanation:

((0 -  (22•3x2)) -  28x) -  15

Pull out like factors :

-12x2 - 28x - 15  =   -1 • (12x2 + 28x + 15)

Trying to factor by splitting the middle term

3.2     Factoring  12x2 + 28x + 15

The first term is,  12x2  its coefficient is  12 .

The middle term is,  +28x  its coefficient is  28 .

The last term, "the constant", is  +15

Step-1 : Multiply the coefficient of the first term by the constant   12 • 15 = 180

Step-2 : Find two factors of  180  whose sum equals the coefficient of the middle term, which is   28 .

     -180    +    -1    =    -181

     -90    +    -2    =    -92

     -60    +    -3    =    -63

     -45    +    -4    =    -49

     -36    +    -5    =    -41

     -30    +    -6    =    -36

     -20    +    -9    =    -29

     -18    +    -10    =    -28

     -15    +    -12    =    -27

     -12    +    -15    =    -27

     -10    +    -18    =    -28

     -9    +    -20    =    -29

     -6    +    -30    =    -36

     -5    +    -36    =    -41

     -4    +    -45    =    -49

     -3    +    -60    =    -63

     -2    +    -90    =    -92

     -1    +    -180    =    -181

     1    +    180    =    181

     2    +    90    =    92

     3    +    60    =    63

     4    +    45    =    49

     5    +    36    =    41

     6    +    30    =    36

     9    +    20    =    29

     10    +    18    =    28    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  10  and  18

                    12x2 + 10x + 18x + 15

Step-4 : Add up the first 2 terms, pulling out like factors :

                   2x • (6x+5)

             Add up the last 2 terms, pulling out common factors :

                   3 • (6x+5)

Step-5 : Add up the four terms of step 4 :

                   (2x+3)  •  (6x+5)

            Which is the desired factorization

Answer: (-6x - 5) • (2x + 3)

12x^2/28x in simplest form is 3x/7

Which polynomial function could be represented by the graph below?

Answers

Answer:

C

Step-by-step explanation:Only one that makes sence just look at the graph

What is the definition of a Pythagorean triple?

Answers

Answer:

a set of numbers that are used to find the hypotenuse

Step-by-step explanation:

brainliest

The integer solutions to the Pythagorean theorem, are called Pythagoras triples.

Definition of Pythagorean Triples:

The integer solutions to the Pythagorean theorem, [tex]a^{2} +b^{2} =c^{2}[/tex] are called Pythagorean triples which contains three positive integers a, b and c.

For example:

(3, 4, 5)

By evaluating we get

[tex]3^{2} +4^{2} =5^{2}[/tex]

⇒ 9 + 16 = 25

Hence, 3, 4 and 5 are Pythagorean triples.

Learn more about Pythagorean Triples here:

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what is the area of a 45 degree sector of a circle with a radius of 12 in.

Answers

given ,

a circle of radius 12 inches

and [tex]\theta[/tex] = 45°

now we know that ,

[tex]\\{Area \: of \: sector = \frac{\theta}{360\degree} \times \pi \: r {}^{2} } \\ \\ [/tex]

let's now plug in the values of radius and theta as 12 inches and 45° respectively ,

[tex]\\\dashrightarrow \: \frac{45}{360} \times \frac{22}{7} \times 12 \times 12 \\ \\ \dashrightarrow \: \frac{1}{8} \times \frac{22 \times 12 \times 12}{7} \\ \\ \dashrightarrow \: \frac{22 \times 12 \times 12}{56} \\ \\ \dashrightarrow \: \frac{3168}{56} \\ \\ \dashrightarrow \: 56.57 \: inches {}^{2} (approx.)[/tex]

hope helpful :D

Help ASAP.
i need you to please break it down ive tried and just don't understand ​

Answers

Answer:

A) -4

Step-by-step explanation:

Question

[tex]\sf evaluate \ \dfrac{-4+(m+2)}{n} \ \sf when \ m=\dfrac23 \ and \ \sf n=\dfrac13[/tex]

Solution

Substitute the given values of m and n into the original expression:

[tex]\sf \implies \dfrac{-4+(\frac23+2)}{\frac13}[/tex]

Carry out the operation in the brackets first [tex]\sf (\frac23+3)=\frac83[/tex]

[tex]\sf \implies \dfrac{-4+\frac83}{\frac13}[/tex]

Now carry out the operation in the numerator [tex]-4+\frac83=-\frac43[/tex]

[tex]\sf \implies \dfrac{-\frac43}{\frac13}[/tex]

Dividing by a fraction is the same as multiplying by the flipped version of the fraction (flipped = swap the numerator and denominator of the fraction we are dividing by):

[tex]\sf \implies -\dfrac43 \div \dfrac13=-\dfrac43 \times \dfrac31[/tex]

To multiply a fraction, simply multiply the numerators and multiply the denominators:

[tex]\sf \implies -\dfrac43 \times \dfrac31=\dfrac{-4 \times 3}{3 \times 1}=-\dfrac{12}{3}[/tex]

Finally simplify:

[tex]\sf \implies -\dfrac{12}{3}=-4[/tex]

For a sample of n = 16 scores, what is the value of the population standard deviation (o) necessary to produce each of the following standard error values?
a. Ом = 8 points
b. Ом =4 points
с. Ом = 1 point

Answers

Using the Central Limit Theorem, it is found that the values of the population standard deviation [tex]\sigma[/tex] needed are given by:

a) [tex]\sigma = 32[/tex]

b) [tex]\sigma = 16[/tex]

c) [tex]\sigma = 4[/tex]

What does the Central Limit Theorem state?

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard error [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

In this problem, we have that n = 16.

Item a:

s = 8, hence:

[tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

[tex]8 = \frac{\sigma}{\sqrt{16}}[/tex]

[tex]\sigma = 32[/tex]

Item b:

s = 4, hence:

[tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

[tex]4 = \frac{\sigma}{\sqrt{16}}[/tex]

[tex]\sigma = 16[/tex]

Item c:

s = 1, hence:

[tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

[tex]1 = \frac{\sigma}{\sqrt{16}}[/tex]

[tex]\sigma = 4[/tex]

More can be learned about the Central Limit Theorem at https://brainly.com/question/24663213

[tex]x^{2} -36\frax+5/(x+6)[/tex]

Answers

the answer is

x^{2}-31x+5b

Jack is 3 times as old as Lacy. 9 years ago the sum of their ages was 22 . How old are they now?

Answers

Answer:

Jack is 31

Lacy is 10

Step-by-step explanation:

x - 9 = 22

since jack is 3 times as old as lacy,

the formula is

3x - 9 = 22

3x = 31

x = 10.3

So Jack is 31

And Lacy is 10

To prove this, subract 9 (years) from both ages

It will give you an approximate sum of 22 years for both their ages, as the question states

Since Lacy is a little over 10 years old, Jack is 31 instead of 30

The formula was taken from someone elses answer so sorry if it`s wrong

d If the width of a rectangle with perimeter P is 6 units, what is its length?

Answers

Step-by-step explanation:

width is 6 units

P=2(l+w)

p=2(l+6)

l+6=p/2

l= (p/2)-6

The length of the reactangle with a width of 6 units and perimeter p units is (P/2)-6 units.

What is the perimeter of a rectangle?

A perimeter is a closed route that surrounds, outlines, or embraces a rectangle. The perimeter of a rectangle is given by the formula,

[tex]\rm Perimeter= 2(Length +width)[/tex]

As it is given that the width of the rectangle is 6 units, while the perimeter of the rectangle is P. Now if we write about the perimeter of the rectangle, it can be written as,

[tex]\rm Perimeter= 2(Length +width)[/tex]

[tex]P = 2(l+6)\\\\\dfrac{P}{2} = (l+6)\\\\l = \dfrac{P}{2}-6[/tex]

Hence, the length of the reactangle with a width of 6 units and perimeter p units is (P/2)-6 units.

Learn more about Perimeter:

https://brainly.com/question/2142493

Estimate f(4.04) for f as in the figure

Answers

Answer:

2.013  to 3 DP's.

Step-by-step explanation:

f(4.04)  will be very close to the tangent line.

Equation of tangent line

is y - 4 = m(x - 10)

m = (4-2) / (10-4) = 1/3

y - 4 = 1/3(x - 10)

y = 1/3x - 10/3 + 4

y = 1/3x + 2/3

So the require estimate of f(4.04)

= 1/3(4.04) + 2/3

= 2.013333

HELP ME OUT PLS!!!!!!!

The model represents an equation. What value of x makes the equation true?

A) 15/4

B) 15/8

C) -15/4

D) -15/8​

Answers

Answer:

B

Step-by-step explanation:

-6x + 6 = 2x - 9

-6x + 15 = 2x

15 = 8x

x = 15/8

Help picture below problem 10

Answers

Answer:

180-52=128

Do mark BRAINLIEST

What is the area?
This is 6th grade math

Answers

Answer:

Find the base, and then the height of this rhombus;

Base: 7 square units

Height: 7 square units

Multiply your base by the height to get the area;

Because the formula for the area of a rhombus is, A = BH

So,

A = 7(7)

A(area) = 49 square units.

Urgente!!! Doy 20 puntos

Answers

Answer:

74-7, 0, +9

Step-by-step explanation:

Hope this helps

Andrew drinks 1.9 litres of water each day for three years. By rounding the amount of water an the number of days to one significant figure find the approximate amount of water he drinks during the three years. [One year = 365 or 366 days]

Answers

Answer:

2081days or 2086days

Step-by-step explanation:

1.9(365)=693.5

1.9(366)=695.4

693.5(3)=2080.5

695.4(3)=2086.2

Alex had $750,000 he lost 80% how many dollars did he lose ​

Answers

Answer:

$600,000

Step-by-step explanation:

GIven;

Alex had $750,000 he lost 80%

To Find;

How many dollars did he lose ​

Solve;

$750,000 * 80% = 600,000

Hence, Alex lost $600,000.

~Learn with Lenvy~

Answer:75,000

Step-by-step explanation:he has 750,000 but he loses 80% so he has 75,000 about.

Given m \| nm∥n, find the value of x. (7x-10)° (6x-5)°

Answers

7x-10=6x-5

We simplify the equation to the form, which is simple to understand

7x-10=6x-5

We move all terms containing x to the left and all other terms to the right.

+7x-6x=-5+10

We simplify left and right side of the equation.

+1x=+5

We divide both sides of the equation by 1 to get x.

x=5

A construction company is building the house shown below. They need to use a scale
of 1 in: 8f (1 inch = 8 feet). They measured the drawing to find that that the height of
the building is 2.5 in.
1.) Explain to the construction workers how they would use this information to
calculate the height of the final building.
2.) What is the height of the final building?
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Answers

Using proportions, we have that:

The height of the building is found using a rule of three.The height is of 20 feet.

What is a proportion?

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

The scale is of 1 inch = 8 feet. What is the height for 2.5 inches? The rule of three is given by:

1 inch - 8 feet.

2.5 inches - x feet

Applying cross multiplication, the height in feet of the final building is given by:

x = 8 x 2.5 = 20 feet.

More can be learned about proportions at https://brainly.com/question/24372153

The height of the building is calculated by representing 1 inch as 8 feet. The final building has a height of 20 feet.

What is scaling?

Scaling is the increase or decrease in the height of an object by a scale factor k.

Given that the scale used is:

1 inch = 8 feet. Hence:

Since the height of the building is 2.5 in, hence:

Height of the final building = 2.5 in * 8 ft per 1 in = 20 feet

The height of the final building is 20 feet.

Find out more on scaling at: https://brainly.com/question/25722260

A farmer wants to know how many of his cows have no spots. He has 200 cows total. He takes a random sample of 40 cows. Of these, 11 of the cows have no spots. What can the farmer predict about the entire population?


The farmer can predict that 11 cows in the entire population have no spots


The farmer can predict that 55 cows in the entire population have no spots


The farmer can predict that 40 cows in the entire population have no spots


The farmer can predict that all of the cows have no spots

Answers

Answer:

The farmer can predict that 55 cows in the entire population have no spots.

Step-by-step explanation:

The farmer can predict that 40 cows in the entire population have no spots, the correct option is C.

How to find the confidence interval for population proportion from large sample?

Suppose we're given that:

Favourable Cases X (in count, in sample)

Sample Size N

Level of significance =[tex]\alpha[/tex]

Then, the sample proportion of favorable cases is:

[tex]\hat{p} = \dfrac{X}{N}[/tex]

The critical value at the level of significance[tex]\alpha is Z_{1- \alpha/2}[/tex]

The corresponding confidence interval is:

[tex]CI = & \displaystyle \left( \hat p - z_c \sqrt{\frac{\hat p (1-\hat p)}{n}}, \hat p + z_c \sqrt{\frac{\hat p (1-\hat p)}{n}} \right)[/tex]

The given information;

The farmer took a random sample of 40 cows out of 200 total cows and found that 11 of those cows have no spots. We can use this sample data to make a prediction about the entire population using statistical inference.

Now,

Plugging in the values, we get:

CI = 0.275 ± 1.96sqrt((0.275(1-0.275))/40)

CI = 0.275 ± 0.139

CI = (0.136, 0.414)

This means that we can be 95% confident that the true proportion of cows with no spots in the entire population lies between 0.136 and 0.414.

the farmer can predict that between 13.6% and 41.4%

Therefore, by confidence interval the answer will be  farmer can predict that 40 cows in the entire population have no spots

Learn more about confidence interval for population proportion here:

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A wire is first bent into the shape of a triangle. Each side of the triangle is 16 long. Then the wire is unbent and reshaped into a rectangle. If the length of the rectangle is 15 in, what is its width?

Answers

Answer:

the width is 9in

Step-by-step explanation:

perimeter of triangle =3×16 = 48

let w= width of rectangle

perimeter of triangle = perimeter of rectangle

48= 2(15 +w)

24= 15 + w

w= 9


[tex] \\ { \rm{If \: }{\tt{A = \left [ \: \begin{array}{ c c c} \: \: \: \: 2 & -3 & - 5 \\ - 1 & \: \: \: 4 & \: \: \: \: 5 \\ \: \: \: \: 1& - 3 & - 4\end{array} \: \: \: \right] \: and \: B = \left[\begin{array}{c c c} \: \: \: \: 2 & - 2 & - 4 \\ - 1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & - 2 & - 3\end{array} \right]}}}, { \rm{shown \: that \: AB = A \: and \: BA = B}}[/tex]
[tex] \: [/tex]
Don't Spam
Explain well ​

Answers

Answer:

Given:

[tex] \\ {\tt{A = \left [ \: \begin{array}{ c c c} \: \: \: \: 2 & -3 & - 5 \\ - 1 & \: \: \: 4 & \: \: \: \: 5 \\ \: \: \: \: 1& - 3 & - 4\end{array} \: \: \: \right] \: and \: B = \left[\begin{array}{c c c} \: \: \: \: 2 & - 2 & - 4 \\ - 1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & - 2 & - 3\end{array} \right]}}[/tex]

Matrix A is of order 3 × 3 and Matrix B is of order 3 × 3

To Show:

Matrix AB = A , BA = B

Formula Used:

[tex]\\ { \rm{ \left[ \begin{array}{c c c} a_{11} & a_{12} & a_{13} \\ a_{21} & a_{22} & a_{23} \\ a_{31} & a_{32} & a_{33}\end{array} \right] \times \left[ \begin{array}{c c c} b_{11} & b_{12} & b_{13} \\ b_{21} & b_{22} & b_{23} \\ b_{31} & b_{32} & b_{33} \end{array} \right] = \: \left[ \begin{array}{c c c} \: \: a_{11}b_{11} + a_{12}b_{21} + a_{13}b_{31} & a_{11}b_{12} + a_{12}b_{22} + a_{13}b_{32} & a_{11}b_{13} + a_{12}b_{23} + a_{13}b_{33} \\ \: \: a_{21}b_{11} + a_{22}b_{21} + a_{23}b_{31} & a_{21}b_{12} + a_{22}b_{22} + a_{23}b_{32}&a_{21}b_{13} + a_{22}b_{23} + a_{23}b_{33} \\ \: \: a_{31}b_{11} + a_{32}b_{21} + a_{33}b_{31}&a_{31}b_{12} + a_{32}b_{22} + a_{33}b_{32} & a_{31}b_{13} + a_{32}b_{23} + a_{33}b_{33}\end{array} \right]}}[/tex]

If A is a matrix of order a×b and B is a matrix of order c×d , then matrix AB exits and is of order a×d , if and only if b = c.

[tex] \: \: [/tex]

If A is a matrix of order a×b and B is a matrix of order c×d , then matrix BA exits and is of order c×b , if and only if d = a.

[tex] \: \: [/tex]

____________________________________________________________________

For Matrix AB, a = 3, b = c = 3, d = 3 , thus Matrix AB is of order 3×3

[tex]\\ { \rm{Matrix \: AB = \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: 4 & \: \: \: \: 5 \\ \: \: \: \: 1 & -3 & -4 \end{array} \right] \times \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right] = \left[\begin{array}{c c c} \: \: \: \: 2(2)-3(-1)-5(1) & \: \: \: \: 2(-2)-3(3)-5(-2) & \: \: \: \: 2(-4)-3(4)-5(-3) \\ -1(2)+4(-1)+5(1) & -1(-2)+4(3)+5(-2) & -1(-4)+4(4)+5(-3)\\ \: \: \: \: 1(2)-3(-1)-4(1) & \: \: \: \: 1(-2)-3(3)-4(-2) & \: \: \: \: 1(-4)-3(4)-4(-3) \end{array} \right]}}[/tex]

[tex]\\ {\rm{Matrix \: AB = \left[ \begin{array}{c c c} \: \: \: \: 4 + 3 - 5 & \: \: \: -4 -9 + 10 & \: \: -8 - 12 + 15 \\ -2 - 4 + 5 & \: \: \: \: \: \: + 2 + 12 - 10 & \: \: \: \: \: 4 + 16 - 15 \\ \: \: \: \: \: 2 + 3 - 4 & \: \: -2 - 9 + 8 & -4 - 12 + 12 \end{array} \right] = \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: \: 4 & \: \: \: 5 \\ \: \: \: \: 1 & -3 & -4 \end{array} \right]}}[/tex]

[tex]\\ {\rm{Matrix \: AB = \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: \: 4 & \: \: \: 5 \\ \: \: \: \: 1 & -3 & -4 \end{array} \right] = Matrix \: A}}[/tex]

Matrix AB = Matrix A____________________________________________________________________

For Matrix BA, a = 3, b = c = 3, d = 3 , thus Matrix BA is of order 3 × 3

[tex]\\ {\rm{Matrix \: BA = \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right] \times \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: \: 4 & \: \: \: \: 5 \\ \: \: \: \: \: 1 & -3 & -4 \end{array} \right]}}= \left[ \begin{array}{c c c} \: \: \: \: \: 2(2) -2(-1) -4(1) & \: \: \: \: 2(-3) -2(4) -4(-3) & \: \: \: \: 2(-5) -2(5) -4(-4) \\ \: -1(2) + 3(-1) + 4(1) & -1(-3) + 3(4) +4(-3) & -1(-5) + 3(5) + 4(-4) \\ \: \: \: \: \: 1(2) -2(-1) -3(1) & \: \: \: \: 1(-3) -2(4) -3(-3) & \: \: \: \: 1(-5) -2(5) -3(-4) \end{array} \right][/tex]

[tex]\\{ \rm{Matrix \: BA = \left[ \begin{array}{c c c} \: \: \: \: 4 + 2 - 4 & \: \: \: -6 -8 + 12 & \: \: -10 - 10 + 16 \\ -2 - 3 + 4 & \: \: \: \: \: \: +3 + 12 - 12 & \: \: \: \: \: + 5 + 15 - 16 \\ \: \: \: \: \: 2 + 2 - 3 & \: -3 -8 +9 & \: \: \: \: \: -5 -10 + 12 \end{array} \right] = \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right]}}[/tex]

[tex]\\{ \rm{Matrix \: BA = \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right] = Matrix \: B}}[/tex]

Matrix BA = Matrix B____________________________________________________________________

(2x+3)+(5x17)+90=180

Answers

Answer:

x=10

Step-by-step explanation:

Answer:

x is 10 degrees

Step-by-step explanation:

180-90=90

(2x+3)+(5x+17) = 90

7x+20=90

7x=70

x=10

Given mſn, find the value of x.
(6x-7)º
m
(4x-10°

Answers

Answer:

x = 3

Step-by-step explanation:

These angles are actually equal to each other

This is because when two lines intersect, the two opposite angles are the same.

Since they are the same, you can set them equal to each other

Like so:

6x - 7 = 4x - 1

Then solve:

6x - 7 = 4x - 1

6x = 4x +6

2x = 6

x = 3

PLEASE HELP! 50 POINTS! Consider the following set of sample data: (34, 32, 34, 32, 40, 37, 31, 31, 29, 27). Which of the following will give a 95% t confidence interval for the mean of the population from which the sample was drawn?

Answers

Answer:

(15.23,41.016)

Step-by-step explanation:

WE must determine the mean of the data set: Which is the sum of the set divided by the number in the set.
[tex]= (21 + 24 + 25 + 32 + 35 + 31 + 29 + 28)/8 = 225/8 = 28.125[/tex]
We must also determine the standard deviation: Which is the square root of the variance and the variance is the sum of squares of the sample number minus the mean divided by the number if the set data:
[tex]= ((21 - 28.125)^{2} + (24 - 28.125)^{2} +(25 - 28.125)^{2} + (32 - 28.125)^{2} + (35 - 28.125)^{2} + (31 - 28.125)^{2} + (29 - 28.125)^{2} (28 - 28.125)^{2}[/tex]
[tex]= 148.877/8 = 18.6[/tex]
The 95% confidence interval is defined as: The mean ± 1.96*standard deviation divided by the sqaure root of the number of data in the set:
[tex]= 28.125 + (1.96 *18.6)/(\sqrt{8} )[/tex]
[tex]= 41.016[/tex]
[tex]= 28.125 - (1.96 * 18.6)/(\sqrt{8}) = 15.23[/tex]
The confidence interval for this data set is (15.23,41.016)

Answer:

32.7 ± 2.262(1.19)

Step-by-step explanation:

See attached pictures

How many distinct 3 digit code can i create such that this code is divisible by 4.
For example these codes are rejected since they have repeating numbers/less than 3 digits:
024/100/112/996/444

Answers

The other answer is just wrong.

There are 9•9•8 = 648 distinct 3-digit codes. The first digit can be any numeral from 1-9, the next digit can be any from 0-9 minus the one used in the first position, and the last digit can be any from 0-9 minus both the numerals used in the first two positions.

But that doesn't even account for the divisibility constraint.

Let the code be [tex]abc[/tex]. We can expand this as

[tex]100a + 10b + c[/tex]

In order for this to be divisible by 4, we observe that

[tex]100a + 8b + 2b + c = 4 (25a + 2b) + (2b+c)[/tex]

so we only need [tex]2b+c[/tex] to be divisible by 4.

The last digit must be even, so there are only 5 choices for the last digit. I list the possibilities and outcomes below. For some integer [tex]k[/tex], we need

[tex]c=0 \implies 2b=4k \implies b=2k[/tex]

[tex]c=2 \implies 2b+2=4k \implies b = 2k-1[/tex]

[tex]c=4 \implies 2b+4 = 4k \implies b = 2(k-1)[/tex]

[tex]c=6 \implies 2b+6 = 4k \implies b = 2k-3[/tex]

[tex]c=8 \implies 2b+8=4k \implies b = 2(k-2)[/tex]

Ignoring [tex]a[/tex] for the moment, in the cases of [tex]c\in\{0,4,8\}[/tex], [tex]b[/tex] is also even. This leaves 3 choices for [tex]c[/tex] and 2 choices for [tex]b[/tex].

Likewise, in the cases of [tex]c\in\{2,6\}[/tex], [tex]b[/tex] is odd. This leaves 2 choices for [tex]c[/tex] and 5 choices for [tex]b[/tex].

Now taking into account the choice for [tex]a[/tex], we have the following decision tree.

• If [tex]a\in\{2,6\}[/tex] and [tex]c\in\{0,4,8\}[/tex], then [tex]b\in\{0,2,4,6,8\}\setminus\{a,c\}[/tex] - a total of 2•3•3 = 18 codes.

• If [tex]a\in\{4,8\}[/tex] and [tex]c\in\{0,4,8\}\setminus\{a\}[/tex], then [tex]b\in\{0,2,4,6,8\}\setminus\{a,c\}[/tex] - a total of 2•2•3 = 12 codes.

• If [tex]a\in\{2,6\}[/tex] and [tex]c\in\{2,6\}\setminus\{a\}[/tex], then [tex]b\in\{1,3,5,7,9\}\setminus\{a,c\}[/tex] - a total of 2•1•5 = 10 codes.

• If [tex]a\in\{4,8\}[/tex] and [tex]c \in\{2,6\}[/tex], then [tex]b\in\{1,3,5,7,9\}[/tex] - a total of 2•2•5 = 20 codes.

• If [tex]a\in\{1,3,5,7,9\}[/tex] and [tex]c\in\{0,4,8\}[/tex], then [tex]b\in\{0,2,4,6,8\}\setminus\{c\}[/tex] - a total of 5•3•4 = 60 codes.

• If [tex]a\in\{1,3,5,7,9\}[/tex] and [tex]c\in\{2,6\}[/tex], then [tex]b\in\{1,3,5,7,9\}\setminus\{a\}[/tex] - a total of 5•2•4 = 40 codes.

Hence there are a total of 18 + 12 + 10 + 20 + 60 + 40 = 160 codes.

ANSWER FOR EXTRA POINTS ⭐️⭐️⭐️

Answers

It should be b) from my recollection.

the answer is b if i remeber

Use Demos Graphing Calculator
Rob works part time at the Fallbrook Riding Stable. He makes $5 an hour exercising
horses and $10 an hour cleaning stalls. Because Rob is a full-time student, he can
work no more than 12 hours per week. However, he must make at least $60 per
week.

Which of the following is a possible solution for this system of inequalities?

A. 1 hour exercising and 1 hour cleaning

B. Two hours exercising and five hours of cleaning

C. Seven hours of exercising and eight hours of cleaning

D. Two hours exercising and eight hours cleaning

Answers

Answer:

D. Two hours exercising and eight hours cleaning

Step-by-step explanation:

Rob works part time at the Fallbrook Riding Stable. He makes $5 an hour exercising horses and $10 an hour cleaning stalls. Because Rob is a full-time student, he can work no more than 12 hours per week. However, he must make at least $60 per week.

x = hrs. exercising horses

y = hrs. cleaning stalls

Equations:

Hours he can work per week:

x + y ≤ 12

Amount of money he can make per week:

5x + 10y ≥ 60

Now, graph your equations into desmos.

As you can see in the graph, the correct answer is D (2, 8)

Check your answer by hand:

x + y ≤ 12

2 + 8 ≤ 12

10 ≤ 12

This statement is correct

5x + 10y ≥ 60

5(2) + 10(8) ≥ 60

10 + 80 ≥ 60

90 ≥ 60

This statement is correct

Therefore, the correct answer is D

Hope this helps!

What is a number greater then 0.6 but less than 0.7

Answers

Answer:

0.65 is a number greater than 0.6 but less than 0.7

3 lines are shown. A line with points M, H, K intersects a line with points J, H, L at point H. A line extends from point H to point P between angle K H J. Angle M H L is 140 degrees and angle K H P is 20 degrees.
What is mAnglePHJ?

100°
120°
140°
160°

Answers

Answer:

120

Step-by-step explanation:

 Given:

3 Lines

A line with points M, H, K intersects a line with points J, H, L at point H.

A line extends from point H to point P between angle K H J.

Angle M H L is 140 degrees and angle K H P is 20 degrees.

Solve:

Since, Angle M H L is 140 degrees and angle K H P is 20 degrees.

Then 140 - 20 = 120

Answer is 120

~Lenvy~

I will give the brainiest if you get it right.

Answers

Answer:

  1 ≤ x < 7/4

Step-by-step explanation:

The function f(x) is defined as increasing on the domain (-8, 4), so the ordering of the arguments is not changed by the function. We can solve the inequality as though f(x) = x, which is increasing everywhere.

Inequality solutions

  f(4x -3) ≥ f(2 -x²)

  4x -3 ≥ 2 -x² . . . . . . using our assumed definition of f(x)

  x² +4x -5 ≥ 0 . . . . . subtract 2-x²

  (x -1)(x +4) ≥ 0 . . . . factored form; zeros at -4, +1

The values of x that make this true are ones that make the factors have the same signs: x ≤ -4 or x ≥ 1.

Domain restrictions

The domain of f(x) is -8 < x < 4, so we require the arguments of f be restricted to those values

Left side

  -8 < 4x -3 < 4

  -5 < 4x < 7

  -5/4 < x < 7/4

Right side

  -8 < 2 -x² < 4 . . . . . right side is always true

  x² < 10 . . . . . . . . . . . add x² +8

  |x| < √10 . . . . . . . . . . less restrictive than the the left-side restriction

Solution

With the given domain restrictions on f(x), the inequality will be true on the interval ...

  1 ≤ x < 7/4

__

Additional comment

The attached graph shows the left-side function argument (dashed blue) and the right-side function argument (dashed green) with the given domain restrictions. The red curve is the difference in function values for the function defined as above. It is only non-negative between 1 and 1.75 as we found above.

This general behavior is applicable for any f(x) that can be described as in the problem statement. For example, f(x) = √(x+8) also gives an increasing curve for the difference f(4x-3)-f(2-x²) on the interval (-5/4, 7/4) with an x-intercept of +1.

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