The equilibrium constant for the reaction Ni(s) + 4CO(g) ® Ni(CO)4(g) is 3.0 104 at 25°C. What
is the equilibrium constant for the reaction Ni(CO)4(g)
Ni(s) + 4CO(g)?

Answers

Answer 1

The reaction quotient at chemical equilibrium is K=2.0 105; regardless of the initial concentrations, the equilibrium constant is constant for the given reaction.

What factors affect the equilibrium constant's value?

Temperature-dependent equilibrium constants are unaffected by the amount of a reaction, the presence of a catalyst, or inert substances. Moreover, it is unaffected by reactant quantities, pressures, or concentrations. In general, the reaction determines how much the equilibrium constant depends on temperature.

What characteristics does the equilibrium constant have?

The balanced equation's form determines the equilibrium constant for a reaction. K is inverted if the equation is turned around. K is increased to the nth power if the equation is multiplied by n different factors.

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Related Questions


All voltmeters have two probes attached to make a measurement explain why you cannot make a voltmeter with a single probe to measure the voltage of a wire

Answers

As voltages is a potential in relation to a reference, one probe must be on the reference or "zero" planes and the other must be on the point being measured.

Why does a voltmeter not accurately read voltage?

because the voltmeter uses some of the main circuit's current. Main present in the circuit diminishes as a result, and the voltmeter's reading of the potential difference does not correspond to its true value.

Why are there two probes on a voltmeter?

Nothing is measured at a specific point by the voltmeter. It gauges the voltage (V) differential between two circuit locations. Thus, a multimeter has two leads rather than one.

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What is the half‑life of an isotope that decays to 12.5% of its original activity in 64.9 h?

Answers

Answer:

The half-life of an isotope is the time taken for half of the original activity to decay.

We know that the isotope decays to 12.5% of its original activity. So, the fraction of the original activity remaining is:

0.125 = 1/2^3

This means that the isotope has undergone three half-lives.

The time taken for three half-lives is:

3 x half-life = 3 x 64.9 h = 194.7 h

Therefore, the half-life of the isotope is:

time/half-life = number of half-lives

64.9 h/half-life = 1

194.7 h/half-life = 3

Solving for half-life:

64.9 h/half-life = 1

half-life = 64.9 h

Therefore, the half-life of the isotope is 64.9 hours.

I need help with this question please this is non graded thanks

Answers

The answer is .130g of H2

How many H atoms are there in 0.510 moles of H

Answers

Answer:

No. of H atoms in 0.51 moles of H+ = 3.0713 * 10^23 atom

Explanation:

according to the definition of mole which states that the mole is the unit of amount of substance that equals Avogadro's number"Na = 6.022 * 10^23" (i.e. one mole of O2 contains 1Na of molecules, one mole of Ca = 1Na of atoms )

So

the number of atoms in 0.51 moles of H = 0.51 * 6.022 * 10^23 = 3.0713 * 10^23 atom

Picture attached below.

Answers

a. The estimated gas-phase enthalpy change for the reaction, ΔH is 493 kJ/mol.

b. The reaction is endothermic

c. The spontaneity of the reaction cannot be determined from the given data.

What is the enthalpy change of the reaction?

To estimate the gas phase enthalpy change using bond dissociation enthalpies, we need to calculate the sum of the bond dissociation energies of the bonds broken minus the sum of the bond dissociation energies of the bonds formed.

Using the OWL Table Reference, we can obtain the following bond diwsociation energies:

C-H bond dissociation energy: 413 kJ/mol

S-H bond dissociation energy: 339 kJ/mol

C-S bond dissociation energy: 259 kJ/mol

Breaking the bonds in the reactants requires:

1 C-H bond energy: 413 kJ/mol

1 S-H bond energy: 339 kJ/mol

Forming the bonds in the products releases:

1 C-S bond energy: 259 kJ/mol

Therefore, the estimated gas-phase enthalpy change for the reaction is:

ΔH = (bond energies of reactants broken) - (bond energies of products formed)

ΔH = (413 kJ/mol + 339 kJ/mol) - 259 kJ/mol

ΔH = 493 kJ/mol

b. The estimated gas-phase enthalpy change is positive, hence the reaction requires energy to proceed and is endothermic.

c. To determine whether the reaction is likely to proceed spontaneously in the direction written, we need to consider the Gibbs free energy change (ΔG) of the reaction. The Gibbs free energy change is related to the enthalpy change (ΔH) and the entropy change (ΔS) by the equation:

ΔG = ΔH - TΔS

where T is the temperature in Kelvin.

If the Gibbs free energy change is negative (ΔG < 0), the reaction is spontaneous in the forward direction. If the Gibbs free energy change is positive (ΔG > 0), the reaction is non-spontaneous in the forward direction and spontaneous in the reverse direction. If the Gibbs free energy change is zero (ΔG = 0), the reaction is at equilibrium.

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compare simple feedback to feedforward control configuration. which one you trust to perform better in achieving your control objective? Why?

Answers

Choice between feedback and feedforward control depends on the specific application and control objective. In many cases, a combination of both feedback and feedforward control may be used to achieve the desired performance and reliability.

What is Configuration?

In general, the term "configuration" refers to the arrangement or structure of components in a system or device. It can refer to the physical arrangement of hardware components or the logical arrangement of software components, as well as the settings and options that determine the behavior of a system or device.

In the context of control systems, "configuration" may refer specifically to the arrangement of sensors, actuators, and controllers used to achieve a desired control objective. This can include the physical placement of sensors and actuators within a system, as well as the software configuration of control algorithms and feedback mechanisms.

Both feedback and feedforward control are important types of control systems used to achieve a desired control objective. In simple feedback control, the control system measures the output of a system and adjusts the input accordingly to maintain a desired setpoint. In feedforward control, the control system predicts the output of a system based on known inputs and adjusts the input accordingly to achieve a desired output.

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SO4 ^2- + Pb^2+ + H2O -> PbO2 + H2SO3
name of the oxidized element:
formula of oxidized:
name of element reduced:
formula of reducing:

Answers

In the redox reaction, Nitrogen element is oxidized and sulfur element is reduced.  act as reducing agent and  act as an oxidizing agent.

What is redox used for?

Redox reaction, also known as an oxidation-reduction reaction, is the reaction in which both oxidation and reduction occur at the same time. The definition of an oxidation reaction is the process by which a substance loses its electrons. In this, an element's oxidation condition progresses. Or we could state that electrons are lost during decomposition.

A substance gains electrons during a reduction reaction, which is defined as such. In this, an element's oxidation state is reduced. Or we can say that in reduction, the gain of electrons takes place. Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

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Balancing chemical equations with interfering coefficients
Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients.
CH,(CH,) ,CH,(0) +O,(g) →+ CO,(g) + H,O(g)
0-0
00

Answers

The balanced chemical equation is: C3H8 + 5O2 → 3CO2 + 4H2O

When balancing chemical equations, can only the coefficients be changed, not the subscripts, the number in front of each reactant or product?

Chemical equations may only be balanced by changing the coefficients; subscripts cannot be changed. The ratios of the atoms in the molecule and the resulting chemical characteristics alter when subscripts are changed.

First, let's balance the carbon and hydrogen atoms by placing a coefficient of 3 in front of CO2 and 4 in front of H2O:

C3H8 + 5O2 → 3CO2 + 4H2O

Now, let's balance the oxygen atoms by placing a coefficient of 5 in front of O2:

C3H8 + 5O2 → 3CO2 + 4H2O

The equation is now balanced with coefficients of 1, 5, 3, and 4, respectively.

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WILL GIVE BRAINLIEST
ANSWER QUESTION IN PICTURE

Answers

Answer:

0.635 grams

Explanation:

Given balanced chemical equation:

[tex]\large\boxed{\rm Cu+2AgNO_3 \rightarrow 2Ag+Cu(NO_3)_2}[/tex]

Molar massesCopper (Cu) = 63.546 g/molSilver (Ag) = 107.868 g/molNitrogen (N) = 14.007 g/molOxygen (O) = 15.999 g/mol

Therefore, the molar mass of Silver Nitrate (AgNO₃) is:

[tex]\rm AgNO_3=107.868+14.007+(3 \cdot 15.999)=169.872\;g/mol[/tex]

Calculate the moles of each reactant by dividing the given mass by the molar mass:

[tex]\rm Moles\;of\;Cu=\dfrac{5.00\;g}{63.55\;g/mol}\approx 0.0787\;mol\;(3\;s.f.)[/tex]

[tex]\rm Moles\;of\;AgNO_3=\dfrac{1.00\;g}{169.872 \;g/mol}\approx 0.00589\;mol\;(3\;s.f.)[/tex]

Silver nitrate (AgNO₃) is the limiting reactant since we have fewer moles of it.

From the balanced equation, 2 moles of AgNO₃ produces 2 moles of Ag. Therefore, the number of moles of Ag produced is:

[tex]\rm 0.00589 \;mol\;AgNO_3 \times \dfrac{2 \;mol\; Ag}{2 \;mol \;AgNO_3} =0.00589 \;mol\;Ag[/tex]

Calculate the mass of Ag by multiplying the number of moles by the molar mass of Ag:

[tex]\begin{aligned} \rm Mass\;of\;Ag&=\rm 0.00589\; mol \times 107.868\; g/mol\\&=\rm 0.635\; g\;(3\;s.f.)\end{aligned}[/tex]

Therefore, 0.635 grams of Ag will be produced from 5.00 g of Cu and 1.00 g of AgNO₃.

Fungi associated with greenhouse tomatoes and their management project work

Answers

A fungus, is responsible for grey mould (Botrytis cinerea). It affects tomato plants (and other plants) in greenhouses and fields and is a frequent and frequently serious fungal disease.

What is the short definition of a greenhouse?

A structure with glass roof and walls is known as a greenhouse. Tropical flowers and tomatoes are among the plants that are grown in greenhouses. Even in the winter, a greenhouse keeps a comfortable temperature inside. Sunlight enters the greenhouse during the day and heats the air and plants within.

Why do greenhouses cause issues?

The industry contributes considerably to climate change by emitting more than 3.3 million tonnes of greenhouse gases each year. In general, building greenhouses pollutes the environment and has negative effects. Construction sites contribute to contamination of the air, water, soil, and noise.

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1. Predict the molecular structure and bond angles for XeCl2. Approximate bond angles are sufficient.

2. Predict the molecular structure and bond angles for ICl3. Approximate bond angles are sufficient.

Answers

XeCl2 has a linear molecular geometry. The Xe-Cl bond angle is 180 degrees. Xe is the central atom, and it has two lone pairs of electrons and two bonded chlorine atoms.

ICl3 has a trigonal bipyramidal molecular geometry. The I-Cl bond angle in the equatorial positions is 120 degrees, and the I-Cl bond angle in the axial position is 180 degrees. The I atom is the central atom, and it has two lone pairs of electrons and three bonded chlorine atoms.

XeCl2 has a linear molecular geometry, with bond angles of 180 degrees. The Xe atom is at the center, with two Cl atoms attached to it. The molecule has two lone pairs on the Xe atom, which repel the bonding electron pairs, causing them to be farther apart and producing a linear shape.

ICl3 has a trigonal bipyramidal molecular geometry, with bond angles of approximately 90 degrees and 180 degrees. The I atom is at the center, with three Cl atoms attached to it in a trigonal planar arrangement, and two lone pairs on the I atom occupy two of the axial positions. The repulsion between the bonding and nonbonding electron pairs cause the bond angles to deviate from the ideal angles.

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C2H6O+3 O2-> 2 CO2 + 3H2O
Two chemists conduct the reaction and measure a percent yield of carbon dioxide of 89%. IF the actual yield was 22.32 moles of carbon dioxide gas at STP, what was the theoretical yield of carbon dioxide?

Answers

Theoretical yield of CO2 is 25.07 moles.  The percent yield of a reaction is the ratio of the actual yield to the theoretical yield, expressed as a percentage, and is a measure of the efficiency of the reaction.

What is Theoretical Yield?

Theoretical yield is the maximum amount of product that can be obtained from a given amount of reactants, assuming complete conversion of the reactants and 100% efficiency of the reaction. In other words, it is the amount of product that would be obtained if the reaction proceeded to completion without any side reactions or losses of product.

The balanced chemical equation for the combustion of C2H6O (ethanol) is:

C2H6O + 3O2 → 2CO2 + 3H2O

The stoichiometry of the equation shows that 1 mole of C2H6O reacts with 3 moles of O2 to produce 2 moles of CO2. Therefore, the theoretical yield of CO2 can be calculated based on the amount of C2H6O used in the reaction.

Assuming that the percent yield of CO2 is 89%, we can calculate the actual yield of CO2 as follows:

Actual yield of CO2 = 89% x theoretical yield of CO2

If the actual yield of CO2 is 22.32 moles at STP, we can calculate the theoretical yield of CO2 as follows:

Theoretical yield of CO2 = Actual yield of CO2 / (89%/100%)

Theoretical yield of CO2 = 22.32 moles / 0.89 = 25.07 moles

Therefore, the theoretical yield of CO2 is 25.07 moles.

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a 10 mole solution of nitric acid is made from 315 g of HNO3 what volume of water is required to make the acid

Answers

We obtain a 10 moles/L = 10 M remedy by boiling 5 mole of HNO3 into 0.5 L of water. Hence, to create a 10 M solution, 315 g of HNO3 must be dissolved in 0,5 L of water.

What are the four sorts of moles?

Moles come in four different categories: acquired nevi, spitz nevi, dysplastic nevi, and congenital moles. Below are some distinctions between each.

Why causes moles to come out of nowhere?

Why moles suddenly arise later in life is unknown to researchers. The majority of those that do are benign and most likely result from aging, prescription drug use, burns or prolonged sun exposure, as well as genetic abnormalities. Every mole that develops and seems unusually can raise suspicions. More recent lesions are much more likely to grow into cancer.

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Calculate How many moles are in 125 g of water?

Answers

The molar mass of water (H2O) is approximately 18 grams per mole. To calculate the number of moles in 125 grams of water, we divide 125 g by 18 g/mol:

125 g ÷ 18 g/mol ≈ 6.94 mol

Therefore, there are approximately 6.94 moles of water in 125 grams of water.

What mass of oxygen combines with 2.88 mol
of magnesium in the reaction
2 Mg(s) + O2(g) −→ 2 MgO(s)?
Answer in units of g.

Answers

Answer:

46.08 g of O2

Explanation:

The balanced chemical equation for the reaction shows that 1 mol of O2 reacts with 2 mol of Mg to form 2 mol of MgO.

Therefore, to calculate the mass of O2 that reacts with 2.88 mol of Mg, we need to use the mole ratio between Mg and O2.

Mole ratio of Mg to O2 is 2:1, meaning that for every 2 moles of Mg, 1 mole of O2 reacts.

So, for 2.88 mol of Mg, we need 1.44 mol of O2 (2.88 mol Mg x 1 mol O2 / 2 mol Mg).

The molar mass of O2 is 32 g/mol.

Therefore, the mass of O2 needed is:

mass = number of moles x molar mass = 1.44 mol x 32 g/mol = 46.08 g.

Therefore, 46.08 g of O2 is needed to react with 2.88 mol of Mg.

What volume of 0.550 M HCl can be prepared from 35.0 mL of 11.7 M HCl? Responses 1.13 mL 1.13 mL 18.4 mL 18.4 mL

Answers

Answer:

To calculate the volume of 0.550 M HCl that can be prepared from 35.0 mL of 11.7 M HCl, we can use the following formula: M1V1 = M2V2 where M1 is the initial concentration of HCl (11.7 M), V1 is the initial volume of HCl (35.0 mL), M2 is the final concentration of HCl (0.550 M), and V2 is the final volume of HCl that we need to calculate. Rearranging the formula to solve for V2, we get: V2 = (M1V1) / M2 Substituting the given values, we get: V2 = (11.7 M)(35.0 mL) / 0.550 M V2 = 747.27 mL Therefore,

Choose the products that complete the reaction. The chemical equations may not be balanced.
HCI + NaOH →?
O NaCl + H₂O
ONaCl + CO₂ + H₂O
ONaCl + H₂
DONE✔

Answers

First one NaCl+H2O it is double displacement reaction

Liquid octane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water . If 29.2g of carbon dioxide is produced from the reaction of 20.6g of octane and 98.6 of oxygen gas, calculate the percent yield of carbon dioxide.
Round your answer to 3 significant figures.

Answers

Now, we can calculate the percent yield of carbon dioxide using the following equation Percent yield of CO2 = 61.5% .

What is carbon dioxide?

Carbon dioxide (CO2) is a colorless, odorless gas composed of one carbon atom and two oxygen atoms. It exists in the Earth's atmosphere as a trace gas, making up approximately 0.04% of the atmosphere by volume. In nature, it is produced by the respiration of living organisms and through the decay of organic matter.

It is also a byproduct of many human activities such as burning fossil fuels, producing cement, and manufacturing plastic. Carbon dioxide is an important greenhouse gas, which means it absorbs and traps heat in the atmosphere, resulting in global warming.

The given reaction is:

CH3CH2CH3 + O2 → CO2 + H2O

m(octane) = 20.6 g

m(O2) = 98.6 g

m(CO2) = 29.2 g

Using the given information and the balanced equation, we can determine the theoretical yield of carbon dioxide by using the following equation:

m(CO2) (theoretical) = (m(octane) × molar mass of octane) / molar mass of CO2

m(CO2) (theoretical) = (20.6 g × 72 g/mol) / 44 g/mol

m(CO2) (theoretical) = 47.45 g

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Full Question ;

Liquid octane CH3CH26CH3 reacts with gaseous oxygen gas O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. If 29.2g of carbon dioxide is produced from the reaction of 20.6g of octane and 98.6g of oxygen gas, calculate the percent yield of carbon dioxide. Round your answer to 3 significant figures.

Consider a titration of 20.00mL of 0.7698M butanoic acid (HA, monoprotic acid, Ka=1.52x10^-5) with 14.34 mL of 0.8322M KOH. What is the pH of this solution?

Answers

The helium sample will occupy a volume of 11.12 L if the pressure is reduced to 5.15 atm while maintaining the temperature at 20 °C.

How do monoprotic and diprotic acids differ?

The ability of monoprotic acids to donate one hydrogen atom or proton to their aqueous solution as opposed to diprotic acids to provide two hydrogen atoms or protons is the primary distinction between the two types of acids.

The pressure and volume of a gas are related by the following equation, known as Boyle's law:

P1V1 = P2V2

where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume, respectively.

Using this equation, we can solve for V2:

P1V1 = P2V2

V2 = (P1V1) / P2

Plugging in the values given in the problem, we get:

V2 = (5.79 atm x 9.89 L) / 5.15 atm

V2 = 11.12 L

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What type of characteristic is passed from a parent to their offspring?

Answers

Answer:

Traits are the characteristics that are passed from a parent to their offspring. These traits are inherited through the genetic material that is passed down from the parent to the offspring during reproduction. The genetic material contains the instructions for building and maintaining an organism, and these instructions are passed down from generation to generation. Traits can be physical, such as eye color or hair texture, or they can be behavioral, such as the ability to learn or communicate. The study of inheritance and traits is known as genetics.

Explanation:

2KClO3 → 2KCl + 3O2

How many moles of potassium chloride, KCl, are produced by the decomposition of 7.6 moles of potassium chlorate, KClO3?

Answers

Answer:

From the balanced chemical equation, 2 moles of KClO3 produce 2 moles of KCl. Therefore, 1 mole of KClO3 will produce 1 mole of KCl.

So, 7.6 moles of KClO3 will produce 7.6 moles of KCl.

Explanation:

Write the net ionic equation, including phases, that corresponds to the reaction

Cu(ClO4)2(aq)+Na2CO3(aq)⟶CuCO3(s)+2NaClO4(aq)
Cu
(
ClO
4
)
2
(
aq
)
+
Na
2
CO
3
(
aq
)

CuCO
3
(
s
)
+
2
NaClO
4
(
aq
)

Answers

Answer:

Cu^2+(aq) + CO3^2-(aq) ⟶ CuCO3(s)

Explanation:

The balanced chemical equation for the given reaction is:

Cu(ClO4)2(aq) + Na2CO3(aq) ⟶ CuCO3(s) + 2NaClO4(aq)

We first need to identify the spectator ions to write the net ionic equation. These are ions that appear on both sides of the equation and do not participate in the reaction. In this case, the spectator ions are Cu^2+ and ClO4^-, as they appear unchanged on both sides.

The net ionic equation is obtained by removing the spectator ions from the balanced equation. Therefore, the net ionic equation for this reaction is:

Cu^2+(aq) + CO3^2-(aq) ⟶ CuCO3(s)

Note that Na+ and ClO4^- are not included in the net ionic equation because they do not participate in the formation of the solid product (CuCO3).

please look at screenshot question is there

Answers

The calculated molarity of Br is 0.0093 mol/L. Molarity is the number of moles of solute per one liter of solution

Elaborating:

Mol FeBr2 = mass / molar mass

= 0.30 g / 215.65 g/mol

= 0.00139 mol

Each mol FeBr2 has two mol Br- anions , so mol Br- ions here will be :

= 2 x 0.00139 mol

= 0.00278 mol

Molarity of Br- anions = mol / volume (L)

= 0.00278 mol / 0.300 L

= 0.0093 mol/L

How can I determine molarity?

Molarity (M) is the most common way to describe the concentration of a solution. Molarity is calculated by dividing the volume of the solution in liters by the molecular weight of the solute: M is equal to moles of solute per liter of solution.

For what reason do we utilize molarity?

One of the most common units used to measure a solution's concentration is molarity. A solution's molarity is useful because it tells you not only whether it has been diluted or concentrated, but also its actual concentration.

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Given the analyte of Adipic acid with F=0.1 M and volume=0.01 L and 146.142 g/mol. Given Titrant NaOH=0.05 M. Given a titration curve where Pka1 is at 0.01 L titrant added with a ph of 4.43 and Pka2 is at 0.03 L titrant added with a PH of 5.41. Given the first equivalence point is at 0.02 L titrant added and the second equivalence point is at 0.04 L added. Find the PH values when titrant added=0, at equivalence point 1(0.02 L added), at 0.037 L titrant added, and at equivalence point 2(0.04 L added)

Answers

Using the Henderson-Hasselbalch equation, the pH value when no titrant is added is 4.44.

What is the pH of the Adipic solution?

To solve this problem, we need to use the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

where;

pH is the pH value,pKa is the acid dissociation constant,[A-] is the concentration of the conjugate base, and[HA] is the concentration of the acid.

We can use this equation to calculate the pH values at different points during the titration.

When no titrant is added:

At this point, we have only the adipic acid in the solution, so we can use the equation:

pH = pKa + log([A-]/[HA])

pH = pKa + log(0/0.1)

pH = pKa = 4.44

pH = 4.44

The other pH values are obtained similarly using the Henderson-Hasselbalch equation.

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Question 16
Identify if the following reaction is balanced or not balanced: BF3 + Li₂SO3 →→ B₂(SO3)3 + LIF
(A) Balanced
B) Not Balanced

Answers

Answer:not

Explain:

Because there is 3 boron’s on the reaction side and 2 on the products

What is t in Cell 3, 7 and 5, 8 with the correct units?

Answers

A healthy T cell count is defined as 500–1,600 T cells per cubic millimeter of blood (cells/mm3), according to HIV.gov.

What is t in Cell 3, 7 and 5, 8 with the correct units?

In cell C1, enter a number, such as 5. Then type another number, such as 3, in D1. To begin the formula, enter an equal sign (=) in cell E1. Type C1+D1 after the equal sign.

The cell-permeant Cell Event TM Caspase-3/7 Green Detection Reagent is a four-amino acid peptide (DEVD) coupled to a nucleic acid-binding dye. The proteins caspase-3 and caspase-7 are active during apoptosis and are able to break the DEVD peptide's caspase 3/7 recognition sequence.

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What can happen to a supersaturated solution

Answers

Crystals will precipitate out of a supersaturated solution when it is disturbed. At that point, the solution will be saturated, making it impossible to dissolve any additional crystals.

What happens if you heat a supersaturated solution?

A saturated solution becomes unsaturated when heated because the solute becomes more soluble. Since the intermolecular space between the particles expands when a saturated solution is heated because the kinetic energy increases.

What consequences does supersaturation have?

Rapid nucleation creates a significant quantity of nucleus surface area on which growth takes place at high supersaturations. As a result, when large supersaturations are obtained, the growth rate is also rapid, which causes the desupersaturation to occur more quickly.

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Collin is conducting a study about chimpanzee communication methods. Which of the following note excerpts from his recent trip to the zoo would be good to include in his study?
a.
Male chimpanzee sleeping in tree for an hour
b.
Baby chimpanzee playing in tree branches for an hour
c.
Female chimpanzee walks away when male chimpanzee approaches
d.
Male chimpanzee eats bananas rather than vegetables during feeding time


Please select the best answer from the choices provided

A
B
C
D

Answers

C would be the best answer to include in Collin's study about chimpanzee communication methods.

The female chimpanzee walking away when the male chimpanzee approaches can provide information about social behavior and interactions between chimpanzees, which is relevant to the study of their communication methods. The other options are not directly related to communication methods.

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What feature does a liquid have if it's considered volatile?
A. It evaporates rapidly at a low temperature.
B. It doesn't freeze unless it gets below absolute zero.
C. It contains a lot of oxygen to support combustion.
D. It releases energy when it contacts water.

Answers

A. It evaporates rapidly at a low temperature,liquid have if it's considered volatile.

Volatility refers to the ability of a liquid to evaporate quickly at a low temperature. Liquids that evaporate quickly are considered volatile. This is due to the fact that the vapor pressure of the liquid is higher than the atmospheric pressure, allowing the molecules of the liquid to escape more easily into the air.Volatility  is a measure of how easily a material vaporizes or evaporates. It is a measure of the tendency of a material to escape from the liquid or solid state and enter into the gaseous state. Volatility is usually measured by the rate of evaporation or vaporization of a material.

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Find Δ, , , and Δ for the freezing of water at −30.00 °C. The specific heat of ice is 2.087 Jg·°C and its heat of fusion is −333.6 J/g.

Δ=
J/g

=
J/g

=
J/g

Δ=
J/g

Answers

To find ΔH for the freezing of water at -30.00°C, we need to take into account the heat energy required to cool water from -30.00°C to 0°C and the heat energy required to freeze the water at 0°C.

First, let's calculate the heat energy required to cool water from -30.00°C to 0°C:

ΔH1 = mCΔT

where m is the mass of water that freezes, C is the specific heat capacity of ice, and ΔT is the change in temperature.

Since we are starting with water at -30.00°C and cooling it to 0°C, ΔT = 30.00°C. The mass of water that freezes is 1 g (since we are considering the freezing of 1 g of water). The specific heat capacity of ice is 2.087 J/g·°C.

ΔH1 = (1 g)(2.087 J/g·°C)(30.00°C) = 62.61 J

Next, let's calculate the heat energy required to freeze the water at 0°C:

ΔH2 = mL

where m is the mass of water that freezes and L is the heat of fusion of water, which is -333.6 J/g (note that the negative sign indicates that heat is released during the phase change from liquid to solid).

Since we are considering the freezing of 1 g of water, the mass is 1 g.

ΔH2 = (1 g)(-333.6 J/g) = -333.6 J

The total heat energy required for the freezing of water at -30.00°C is the sum of ΔH1 and ΔH2:

ΔH = ΔH1 + ΔH2 = 62.61 J - 333.6 J = -270.99 J

Therefore, ΔH for the freezing of water at -30.00°C is -270.99 J.

Note: The units of ΔH are J/g since we calculated the heat energy required to freeze 1 g of water.
Final answer:

The total energy involved in the freezing of water at -30°C is calculated in two steps: one for the temperature change from -30°C to 0°C, and the other for the phase change from water to ice. The energies are calculated separately and then added together, yielding a final energy of -271 J/g.

Explanation:

The question pertains to the calculation of energy (Δ) for the freezing of water at -30°C. In this case, we are dealing with the energy required to heat ice from -30°C to 0°C (temperature change), and the energy required to convert the ice at 0°C to water at 0°C (phase change).

Let's call the first q1, which can be calculated using the formula q = mcΔt, where 'm' stands for mass (let's consider 1 gram for simplicity), 'c' is the specific heat capacity of ice (2.087 Jg·°C), and ' Δt' is the temperature change (30°C). Plugging in these values, we get q1 = 2.087*30 = 62.61 J.

Now, the second energy q2 is calculated using the formula q=ml, where ' l' is the heat of fusion (-333.6 J/g). Here q2 = -333.6*1 = -333.6 J (negative implies energy is removed).

Finally, to find the overall energy for the phase change, we add the calculated energies together. So, Δ = q1 + q2 = 62.61 - 333.6 = -271 J/g (using energy conservation principles).

Learn more about Energy Calculation here:

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