we have the following system
[tex]\begin{gathered} \begin{cases}x+y=60 \\ 5x+2y=246\end{cases} \\ \end{gathered}[/tex]where x is the number of mega million ticktets and y the number of scratch off tickets, so we have that y=60-x and we get that
[tex]\begin{gathered} 5x+2(60-x)=246 \\ 5x-2x+120=246 \\ 3x=126 \\ x=\frac{126}{3}=42 \end{gathered}[/tex]so they bought 42 mega million tickets and 18 scratch off
Is my answer correct help please
Answer:
No, the correct answer is C.
Step-by-step explanation:
Five less than a number m = m - 5. and not 5 - m, so false.
I have an image can I show it to you?
Answer:
Rhombus
Explanation:
Looking at the given figure, the correct option is a Rhombus because the figure is a quadrilateral and all of its sides have the same length, opposites sides are parallel and opposite angles are equal.
For each equation in the table, give the slope of the graph.
Answer:
1. undefined
2. 0
3. -6
Step-by-step explanation:
Slope-intercept form: y = mx + b
m = slope
b = y-intercept.
Since the equation x = -6 is a vertical line, the slope is undefined.
Since y = -6 is a horizontal line, the slope is 0.
The slope of y = -6x is -6. This is because it is the coefficient of the variable x.
Which relation is a function? choose all the correct answers.[1] (1, 0), (3, 0), (1, 1), (3, 1) (1, 3) [2] (1, 1), (2, 2), (3, 3), (4, 4), (5, 8)[3] (2, 7), (6, 5), (4, 4), (3, 3), (2, 1)[4] (9, −3), (9, 3), (4, −2), (4, 2), (0, 0)
A relation is a function if an input value has only one output value. This means that a value of x must have only one value of y. Looking at the options,
1) for x = 1, there are different values of y. They include y = 0, 1, 3
for x = 3, y = 0, 1
This means that it is not a function
2) No value of x has more than one value of y. Thus, no input has more than one output. This means that it is a function
3) for x = 2, there are different values of y. They include y = 7, 1
This means that it is not a function
4) for x = 9, there are different values of y. They include y = - 3, 3
for x = 2, there are different values of y. They include y = - 2, 2
This means that it is not a function
Thus, the correct option is
[2] (1, 1), (2, 2), (3, 3), (4, 4), (5, 8)
Show that (3 * 8 * x)⁷ = 6⁷ * 4⁷ * x⁷
Answer:
Q.E.D.
Explanation:
Given the expression
[tex](3\times8\times x)^7[/tex]We want to show that it is equal to the right-hand side.
Now, we note that: 8 = 2 x 4
Substituting 8 = 2 x 4, we have:
[tex]=(3\times2\times4\times x)^7[/tex]We then go further to get:
[tex]=(6\times4\times x)^7[/tex]Distributing the exponent, we have:
[tex]=6^7\times4^7\times x^7[/tex]This is the given right-hand side of the equation as required.
Which of the following distribution belongs to discrete distribution?Even distributionOdd distributionInteger distributionReal numbers distribution
Explanation:
Discrete probability distribution:
It counts the occurrences that have countable or finite outcomes.
As the even numbers, odd numbers are countably infinite .
The real numbers are not countable.
So, the discrete distributions are Integer distribution.
express the quadratic function f(x)=3x^2 + 6x - 2 in the form a(x + h)^2 + k where a,h and k are constants
Answer:
Explanation:
Given:
[tex]f(x)=3x^2+6x-2[/tex]First, we do completing the square on the given function to express it into vertex form. So,
We write it in the form:
[tex]\begin{gathered} x^2+2ax+a^2 \\ \end{gathered}[/tex]And, factor out 3: So,
[tex]\begin{gathered} 3(x^2+2x-\frac{2}{3}) \\ \text{where:} \\ 2a=2\text{ or a=1} \\ \text{Hence} \\ 3(x^2-2x-\frac{2}{3}+1^2-1^2) \end{gathered}[/tex]Since:
[tex]\begin{gathered} x^2+2ax+a^2=(x+a)^2 \\ So, \\ x^2+2x+1^2=(x+1)^2 \end{gathered}[/tex]Then,
[tex]\begin{gathered} 3(x^2-2x-\frac{2}{3}+1^2-1^2) \\ =3((x+1)^2-\frac{2}{3}-1^2) \\ \text{Simplify} \\ f(x)=3(x+1)^2-2-3 \\ f(x)=3(x+1)^2-5 \end{gathered}[/tex]Therefore, the answer is:
[tex]f(x)=3(x+1)^2-5[/tex]If you are given a rectangle, what are the degrees of its rotational symmetry? (I need all of them between but not including 0 and 360 degrees)
A rectangle is an Order 2 of symmetry because it matchs its fugure only 2 times while rotating through 360 degrees.
The degrees of symmetry can be calculated as:
[tex]\frac{360\degree}{\text{Order}}=\frac{360\degree}{2}=180\degree[/tex]We see that at 180 degrees of rotation the shape is identical to the original shape.
This does not repeat for any other angle between 0 and 360 degrees.
Answer: 180 degrees.
Each of John’s notebook is 3/4 inches wide. If he has 36 inches of space remaining on his bookshelf, how many notebooks will fit? Write your answer in simplest form.
Given that:
- The width of each of John’s notebooks is:
[tex]\frac{3}{4}in[/tex]- The space remaining on his bookshelf is:
[tex]36in[/tex]Let be "x" the number of notebooks that will fit in John's bookshelf.
Knowing that:
[tex]\frac{3}{4}in=0.75in[/tex]You can set up the following proportion:
[tex]\frac{1}{0.75}=\frac{x}{36}[/tex]Now you have to solve for "x":
[tex]\begin{gathered} (\frac{1}{0.75})(36)=\frac{x}{36} \\ \\ \frac{36}{0.75}=x \end{gathered}[/tex][tex]x=48[/tex]Hence, the answer is:
[tex]48\text{ }notebooks[/tex]perform the calculation then round to the appropriate number of significant digits
The given expression is,
[tex]\frac{308.45}{1.12}[/tex]On division we get,
[tex]\frac{308.45}{1.12}=275.4017[/tex]On rounding we get, 275.402.
A boat is heading towards a lighthouse, whose beacon-light is 140 feet above the water. The boat’s crew measures the angle of elevation to the beacon, 10∘∘ . What is the ship’s horizontal distance from the lighthouse (and the shore)? Round your answer to the nearest tenth of a foot if necessary.
see the figure below to better understand the problem
we have that
tan(10∘)=140/x -----> by TOA
solve for x
x=140/tan(10∘)
x=794 ft
therefore
The answer is 794 feetAnswer:
Step-by-step explanation:
tan 10=140/x
x=140 / tan 10
x=794
Find the length of line segment MN. Round to the nearest hundredths place.
First, look th the graph and set the coordinate of the points:
M = (mx,my)= (-1,2)
N = (nx,ny)= (4,0)
Now, apply the distance formula:
[tex]\text{Distance =}\sqrt[]{(mx-nx)^2+(my-ny)^2}[/tex]Replace with the coordinates:
[tex]D\text{ =}\sqrt[]{(-1-4)^2+(2-0)^2}[/tex][tex]D=\sqrt[]{(-5)^2+2^2}=\sqrt[]{25+4}=\sqrt[]{29}\text{ =5.3}9[/tex]Distance: 5.39
How do you solve this?
Answer: B
Step-by-step explanation:
Answer: The answer is B
Step-by-step explanation:
Justin earns a base salary of $1500 per month at
the jewelry shop. He also earns a 3% commission
on all sales. If Just sold $82,975 worth of jewelry
last month, how much would he make for the
month including his base salary and commission?
The total salary earned by the Justin including the commission is $3959.25.
What exactly is the commission?A commission is extra money earned based on job performance.Members believe to be paid a specified amount of money depending on achievement marketed, sessions closed, recruits placed, and so on—when they agree to a commission-based position as well as commission framework (more by signing the agreement).For the given question;
The base salary of Justin is $1500.
The commission earned by Justin is 3%.
The jewelry of worth $82,975 last month.
Let x be the total commission earned.
Then,
3% of 82,975 = x
x = 3× 82,975 / 100
x = $2489.25
Total salary = base salary + commission
Total salary = $1500 + $2489.25
Total salary = $3959.25
Thus, the total salary earned by the Justin including the commission is $3959.25.
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Line segment AB has a midpoint C.If AC=17 and AB = 5x-6, then find the value of x
From that diagram that is drawn above, C is the midpoint of the line AB:
AC = 17
AB = 5x - 6
Since C is the midpoint of AB;
AB = 2AC = 2CB:
5x - 6 = 2(17)
5x - 6 = 34
5x = 34 + 6
5x = 40
x = 40/5
x = 8
After every score in a sample is multiplied by 5,the mean is found to be M = 40.What was the value for the original mean?
Since each of the data value is multiplied by 5, the new mean will be 5 times the original mean.
To get the original mean, we need to divide by 5.
Therefore the original mean is given by:
[tex]\frac{40}{5}=8[/tex]Answer: 8
A cookie recipe calls for 3/4 of a cup of flour and makes 2dozen cookies. How many cookies can Julia make if she has 12cups of flour and wants to use it all
Given that 3/4 of a cup of flour is used to cook 2 dozen cookies,
[tex]\frac{3}{4}\text{ cup of flour}\equiv2\text{ dozen cookies}[/tex]Consider the conversion,
[tex]1\text{ dozen}=12\text{ units}[/tex]So it follows that,
[tex]\frac{3}{4}\text{ cup of flour}\equiv2\cdot12=24\text{ cookies}[/tex]Multiply both sides by 4/3 as follows,
[tex]\begin{gathered} \frac{3}{4}\cdot\frac{4}{3}\text{ cups of flour}\equiv24\cdot\frac{4}{3}\text{ cookies} \\ 1\text{ cup of flour}\equiv32\text{ cookies} \end{gathered}[/tex]So, 32 cookies can be cooked using 1 cup pf flour.
Given that Julia has 12 cups of flour, so the number of cookies that she can cook, is calculated as,
[tex]12\text{ cups of flour}\equiv32\cdot12=384\text{ cookies.}[/tex]Thus, Julia can make 384 cookies if she uses 12 cups of flour.
graph a line that is parallel to the given line. determine the slope of the given line and the one you graphed in simplest form. click and drag on the graph to draw a line. Click and drag to plot a parallel line. The line will change colors when a parallel or perpendicular line is drawn accurately.
Choosing two points of the line given ( Lg ):
• A( ,0, -4, )
,• B( -,1.5, 0, )
Procedure:
0. Finding the slope ( ,m ,) of ,Lg:
[tex]m_{Lg}=\frac{y_2-y_1}{x_2-x_1}[/tex][tex]m_{Lg}=\frac{0_{}-(-4)_{}}{-1.5_{}-0_{}}=\frac{4}{-1.5}=-\frac{8}{3}[/tex][tex]m_{Lg}=-\frac{8}{3}[/tex]Also, based on point (0, -4), we can determine the intersection in y - axis ( b = -4). Therefore, the equation of the line given is:
[tex]y=mx+b[/tex][tex]y=-\frac{8}{3}x-4[/tex]To determine the parallel slope ( mp ), we know that parallel lines have the same slope:
[tex]m_p=m_{Lg}=-\frac{8}{3}[/tex]For the new graph, you would have to choose a different parameter b, all the equation would be the same except b. Choosing b = 3 as an example:
[tex]y=-\frac{8}{3}x+3[/tex]Answer:
• Original slope: -8/3
,• Parallel slope: -8/3
Louis food out six different size at the picnic at the end of the picnic he noticed this about about the pies one whole apple pie was eaten and 3/4
Louis had 6 different pies. Some of them were eating and we want to know how much pie there's left. First, we have the information that one apple pie was entirely gone. From this, we know there were 5 pies remaining.
[tex]6-1=5[/tex]Then, he also noticed the other apple pie had 3/4 gone. Which means that 1/4 of this second apple pie was leftover.
[tex]1-\frac{3}{4}=\frac{1}{4}[/tex]Applying this same logic, we can deduct all the slices that were eaten from the total amount of pie we had at first to get the leftovers.
[tex]\begin{gathered} 6-1-\frac{3}{4}-\frac{1}{2}-\frac{1}{8}-\frac{5}{8}-\frac{3}{4} \\ =5-\frac{1}{2}-\frac{6}{4}-\frac{6}{8} \\ =5-2-\frac{3}{4} \\ =3-\frac{3}{4} \\ =2+\frac{1}{4} \end{gathered}[/tex]What we've done in this last equation, was taking our first amount of pies (6), subtract the whole apple pie that was eaten (1), the three quarters that were eaten from the other apple pie (3/4) and the other eaten slices from the others.
Which means, the result of this calculation is our amount of leftover slices.
We still have 2 and a quarter pies.
Other than no solutions to use interval notation to Express the solution set and then graph the solution set on the number line
Answer
[tex]7(4x-4)-12x<4(1+4x)-3[/tex]Open the bracket
[tex]\begin{gathered} 28x-28-12x<4+16x-3 \\ collect\text{ the like terms} \\ 28x-12x_{}-16x<4-3+28 \\ 16x-16x<1+28 \\ 0<29 \end{gathered}[/tex]True for all x
[tex](-\infty,\infty)[/tex]Real world compositions: A manufacturer sells a lawn mower to a store at $75 over the manufacturing cost. The store then sells the lawn mower for 140% of the price paid to the manufacturer. Determine the function of the price of a lawn mower in terms of the cost to manufacture the mower. What price will a customer pay for this mower if the manufacturer's cost was $230? Solve using composite functions
From the information provided, the lawn mower is sold at a price which is $75 over the cost of manufacture.
If the cost of manufacture is x, then we would have;
[tex]f(x)=x+75[/tex]Also, the store now sells the lawn mower for 140% of the price paid to the manufacturer. Therefore, we would have;
[tex]g(x)=f(x)1.4[/tex]Hence, if the manufacturer's cost is $230, the customer would be paying g(x). When the cost x is now given as 230, we wou;d have;
[tex]\begin{gathered} f(230)=230+75 \\ f(230)=305 \\ \text{Hence;} \\ g(x)=f(x)1.4 \\ g(x)=305\times1.4 \\ g(x)=427 \end{gathered}[/tex]ANSWER:
The function of the price is;
[tex]f(x)=x+75[/tex]The price a customer pays when the cost of manufacturing is $230 would now be $427
I need help with this question! I tried to work the question out but the answer I got is not an answer choice.
Given:
The given expression is
[tex]2\times72-3\times8+6\times5+4[/tex]Required:
We have to find the value of the given expression.
Explanation:
[tex]\begin{gathered} 2\times72-3\times8+6\times5+4 \\ =144-24+30+4 \end{gathered}[/tex][tex]\begin{gathered} =120+30+4 \\ =150+4 \end{gathered}[/tex][tex]=154[/tex]Final answer:
Hence the final answer is
Graph the function. Plot five points on the graph of the function as follows.
A rectangle has an area ofx² + 9x + 14Find the expressions that represent the dimensions of the rectangle.O (x - 2) and (x - 7)O (x + 3) and (x + 6)(x + 2) and (x + 7)O (x + 1) and (x + 14)
x² + 9x + 14
The area of a rectangle is the product of the length and the width.
Factorizing the expression
x² + 9x + 14 = x² + 7x + 2x + 14
= x(x + 7) + 2(x + 7)
= (x + 7)(x + 2)
Hence the dimensions are (x + 2) and (x + 7)
Dylan’s boat can carry 40 people across a river. Last month, 2504 people road on Dylan’s boat. What is the least number of trips that Dylan could have made across that river.
The required least number of trips that Dylan would have made across the river is 62.
Given that,
Dylan’s boat can carry 40 people across a river. Last month, 2504 people rode on Dylan’s boat. What is the least number of trips that Dylan could have made across that river is to be determined.
In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication, and division,
Here,
Total people road = 2504
Maximum people can road at single trip = 40
Least number of trip = 2504 / 40
Least number of trip = 62
Thus, the required least number of trips that Dylan would have made across the river is 62.
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in the figure below, when the sun angle of elevation is 50°, the tree casts a shadow 80 feet long which can be used to find the height of the tree?
We can use the tangent of 50º. The height is approximately 95.34 ft
1) We can trace a right triangle over that mark and calculate that height, using a trigonometric ratio.
2) As we have the adjacent leg to that 50º angle and the opposite leg, we can use the tangent of 50º to find that height out.
[tex]\begin{gathered} \tan (50)=\frac{x}{80} \\ x=80\cdot\tan (50) \\ x\approx\text{ 95.34} \end{gathered}[/tex]3) Hence the answer is
We can use the tangent of 50º. The height is approximately 95.34 ft
use 3.14for πThe area of the circle is
The general expression for the area of circle with radius r is express as :
[tex]\text{ Area of circle = }\Pi(radius)^2,\text{ where }\Pi=3.14[/tex]In the given circle : radius is 5ft
Substitute radius = 5 ft in the expression for the area of circle :
[tex]\begin{gathered} \text{ Area of circle = }\Pi(radius)^2 \\ Area\text{ of circle=3.14}\times5\times5 \\ \text{ Area of Circle = 78.5 ft}^2 \end{gathered}[/tex]Answer : Area of circle is 78.5 square feet
1Choose the equation that matches the table below.X-101331521Ny-5-27O y = -7x+5O y = 5xOy=3x-2Oy=x-2
Given:
The coordinates are:
Find-:
The equation of a line
Explanation-:
The general equation is:
[tex]y=mx+c[/tex]Where,
[tex]\begin{gathered} m=\text{ Slope} \\ \\ (x,y)=\text{ Coordintes of line} \\ \\ c=\text{ y-intercept} \end{gathered}[/tex]The formula of the slope is:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Choose any two points from the chart is:
[tex]\begin{gathered} (x_1,y_1)=(-1,-5) \\ \\ (x_2,y_2)=(0,-2) \end{gathered}[/tex]Then the slope is:
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ \\ m=\frac{-2-(-5)}{0-(-1)} \\ \\ m=\frac{-2+5}{0+1} \\ \\ m=\frac{3}{1} \\ \\ m=3 \end{gathered}[/tex]If the slope of the line is 3, then the equation becomes:
[tex]\begin{gathered} y=mx+c \\ \\ y=3x+c \end{gathered}[/tex]The value of "c" is:
Choose any one point.
[tex](x,y)=(0,-2)[/tex]The value of "c" is:
[tex]\begin{gathered} y=3x+c \\ \\ (x,y)=(0,-2) \\ \\ -2=3(0)+c \\ \\ -2=0+c \\ \\ c=-2 \end{gathered}[/tex]The equation of line is:
[tex]\begin{gathered} y=mx+c \\ \\ y=3x+(-2) \\ \\ y=3x-2 \end{gathered}[/tex]The equation of line is y = 3x-2
Convert the following rectangular equation to polar form.Assume a>0 3x^2+3y^2-4x+2y=0
The given equation is,
[tex]3x^2+3y^2-4x+2y=0[/tex]The polar form of the equation can be determined by using the substitution
[tex]\begin{gathered} x=r\cos \theta \\ y=r\sin \theta \end{gathered}[/tex]using the substitution,
[tex]\begin{gathered} 3(x^2+y^2)-4x+2y=0 \\ 3(r^2\cos ^2\theta+r^2\sin ^2\theta)-4r\cos \theta+2r\sin \theta=0 \\ 3r^2-4rcos\theta+2r\sin \theta=0 \\ r(3r-4\cos \theta+2\sin \theta)=0 \\ r=0\text{ and }(3r-4\cos \theta+2\sin \theta)=0 \\ (3r-4\cos \theta+2\sin \theta)=0 \end{gathered}[/tex]Thus, the above equation gives the required polar form of the circle.
Trent earns scores of 60, 90, and 72 on three chapter tests for a certain class. His homework grade is 68 and his grade for a class project is 64. The overall average for the course is computed as follows: the average of the three chapter tests makes up 50% of the course grade; homework accounts for 10% of the grade; the project accounts for 20%; and the final exam accounts for 20%. What scores can Trent earn on the final exam to pass the course if he needs a "C" or better? A "C" or better requires an overall score of 70 or better, and 100 is the highest score that can be earned on the final exam. Assume that only whole-number scores are given. To obtain a "C" or better, Trent needs to score between and Inclusive.
A: 90% - 100%
B: 80% - 89%
C: 70% - 79%
D: 60% - 69%
F: 0% - 59%
Using the data provided:
[tex]0.5(\frac{60+90+72}{3})+0.1(68)+0.2(64)+0.2(x)\ge70[/tex]Where:
x = Score of the final exam in order to get at least a C.
Solve for x:
[tex]\begin{gathered} 37+6.8+12.8+0.2x\ge70 \\ 56.6+0.2x\ge70 \\ 0.2x\ge70-56.6 \\ 0.2x\ge13.4 \\ x\ge\frac{13.4}{0.2} \\ x\ge67 \end{gathered}[/tex]He needs to score between 67 and 100