The dog shelter has Labradors, Terriers, and Golden Retrievers available for adoption. If P(terriers) = 15%, interpret the likelihood of randomly selecting a terrier from the shelter.

Likely
Unlikely
Equally likely and unlikely
This value is not possible to represent probability of a chance event

Answers

Answer 1

The likelihood of randomly selecting a terrier from the shelter would be unlikely. That is option B

How to calculate the probability of the selected event?

The formula that can be used to determine the probability of a selected event is given as follows;

Probability = possible event/sample space.

The possible sample space for terriers = 15%

Therefore the remaining sample space goes for Labradors and Golden Retrievers which is = 75%

Therefore, the probability of selecting the terriers at random is unlikely when compared with other dogs.

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Related Questions

A pair of standard since dice are rolled. Find the probability of rolling a sum of 9 with these dice.
P(D1 + D2 = 9) = ---

Answers

The total number of possible outcomes when rolling two standard six-sided dice is 6 x 6 = 36. To find the number of outcomes that result in a sum of 9, we can create a table to visualize all of the possible outcomes:

| Die 1 | Die 2 | Sum |
|:------:|:------:|:------:|
| 3 | 6 | 9 |
| 4 | 5 | 9 |
| 5 | 4 | 9 |
| 6 | 3 | 9 |

From this table, we can see that there are four possible outcomes that would result in a sum of 9. Therefore, the probability of rolling a sum of 9 with two standard six-sided dice is:

P(D1 + D2 = 9) = number of outcomes that result in a sum of 9 / total number of possible outcomes
P(D1 + D2 = 9) = 4 / 36
P(D1 + D2 = 9) = 1 / 9

So the probability of rolling a sum of 9 with two standard six-sided dice is 1/9.

Use the Chain Rule to find the indicated partial derivatives. N = p + q p + r , p = u + vw, q = v + uw, r = w + uv; ∂N ∂u , ∂N ∂v , ∂N ∂w when u = 9, v = 4, w = 3

Answers

The partial derivatives ∂N/∂u, ∂N/∂v, and ∂N/∂w when u=9, v=4, and w=3 are:

[tex]∂N/∂u = 96[/tex]

[tex]∂N/∂v = 19[/tex]

[tex]∂N/∂w = 35[/tex]

To find the indicated partial derivatives, we can use the chain rule of differentiation. Starting with ∂N/∂u, we have:

[tex]∂N/∂u = (∂N/∂p) \times (∂p/∂u) + (∂N/∂q) \times (∂q/∂u) + (∂N/∂r) \times (∂r/∂u)[/tex]

Substituting the given values for p, q, and r, we get:

[tex]∂N/∂u = (1 + q) \times 1 + (p + r) \times w + u \times w[/tex]

Using the values of p, q, and r in terms of u, v, and w, we get:

[tex]∂N/∂u = (1 + v + uw) + (u + vw + w + uv) \times 3 + 9 \times 3[/tex]

Simplifying the expression, we get:

[tex]∂N/∂u = 60 + 4u + 3v + 12w[/tex]

We can find ∂N/∂v and ∂N/∂w by applying the chain rule of differentiation and using the given values for u, v, and w. Substituting the values, we get:

[tex]∂N/∂v = 3u + 4 + 3w[/tex]

[tex]∂N/∂w = 3u + 3v + 2[/tex]

The chain rule allows us to find the partial derivatives of a function with respect to its variables, by breaking down the function into its component parts and differentiating each part separately.

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The Pin numbers for a cash card at the bank contain four digits 1-9. All codes are equally likely. Find the number of possible Pin numbers.

Answers

Answer: A 4 digit PIN number is selected. What is the probability that there are no repeated digits? ... There are 10 possible values for each digit of the PIN (namely: 0 ..

Step-by-step explanation:

2(2x - 1) = 2x² + 5x - 12 solve for x

Answers

Answer: x= 2, -2.5

Step-by-step explanation: trust lol

1. The medical assistant took the oral temperature of 42 patients on Monday, 37
patients on Tuesday, 65 patients on Wednesday, was off work on Thursday, and 56
patients on Friday. How many total thermometer probe covers were utilized by this
medical assistant this week at the clinic when taking patient temperatures?
2. The teenage patient grew % inch from January to March, ½ inch from March to May,
2 inches from May to September, and 1 % inches from September to December.
How many total inches did this patient grow this year?
3. An infant was born weighing 8 pounds and gained 2 pounds by his one-month
check-up, 2 pounds by his three-month check-up, and 4 more pounds by his
six-month check-up. How many pounds did this infant weigh by his 6-month
check-up appointment?
4. If 3 teaspoons = 0.5 fluid ounce and there are 4 ounces in a bottle of children's
Tylenol, how many 1-teaspoon doses are there in a bottle?

Answers

Answer:

1. The medical assistant utilized a total of 200 thermometer probe covers this week at the clinic when taking patient temperatures.

2. The teenage patient grew a total of 5 7/8 inches this year.

3. The infant weighed 14 pounds by his 6-month check-up appointment.

4. There are 24 1-teaspoon doses in a bottle of children's Tylenol.

Step-by-step explanation:

mark brainliest

Given u = 4i − 7j and v = −6i + 9j, what is u • v?

−87
−82
26
39

Answers

The dot product of u.v is  -87.

Dot Product:

The dot product, also called scalar product, is a the sum of the products of corresponding components. measure of closely two vectors align, in terms of the directions they point.

If we have 2 vectors

A= ⟨a, b⟩

and B =  ⟨c, d⟩

The dot product is

A . B = ⟨a, b⟩ . ⟨c, d⟩ = ac + bd

Here, u = 4i − 7j and v = −6i + 9j

The dot product is:

u . v = ( 4 ,− 7 ). ( −6 , 9)

u . v= 4 . (-6) + (-7). (9)

u. v = -24 - 63

u. v = -87

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8th Grade, Geometry
Find the coordinates of the vertices for the figure after the given transformation:

Reflection across x = 1 with the points X(0,-3), W(1,0), V(4,1)
Group of answer choices

Answers

The coordinates of the vertices after the reflection across x = 1 are:

⇒ X'(2,-3),  W(1,0),  V'(2,1)

Now First, let's visualize the reflection across x = 1.

This means that all points will have the same x-coordinate but their y-coordinate will be mirrored across the line x = 1.

So, X(0,-3) will reflect to X'(2,-3),

Since, the distance between X and the line x = 1 is 1 unit,

and the y-coordinate of X' will be the same as that of X.

Similarly, W(1,0) will remain unchanged, as it lies on the line of reflection.

And, Lastly, V(4,1) will reflect to V'(2,1),

Since, the distance between V and the line x = 1 is 3 units, and the y-coordinate of V' will be the same as that of V.

Therefore, the coordinates of the vertices after the reflection across x = 1 are:

⇒ X'(2,-3),  W(1,0),  V'(2,1)

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(f) Would it be unusual if less than 52% of the sampled teenagers owned smartphones? It ▼would not be unusual if less than 52% of the sampled teenagers owned smartphones, since the probability is ?
a) Find the mean μp. The mean μp is 0.55. Part 2 of 6
(b) Find the standard deviation σp. The standard deviation σp is 0.0397.
help with problem (f)

Answers

Yes, it would be unusual if less than 52% of the sampled teenagers owned smartphones.



We are given the mean (μp) as 0.55 and the standard deviation (σp) as 0.0397. We need to find the probability of having less than 52% (0.52) of teenagers owning smartphones.

1) Calculate the z-score.
z = (x - μp) / σp
z = (0.52 - 0.55) / 0.0397
z ≈ -0.76

2) Find the probability associated with the z-score.
Using a z-table or a calculator, we find that the probability of having a z-score less than -0.76 is approximately 0.224. This means there is a 22.4% chance that less than 52% of the sampled teenagers would own smartphones.

Since the probability of having less than 52% of the sampled teenagers owning smartphones is 22.4%, it would be considered unusual, as the probability is relatively low.

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A. Match like terms. Write the correct letters on the lines.
1. 3x²
a. a²b
2. 2ab
3. -5x
4. a
5. -4a²b

b. 10x
c. 2a
d. -3x²
e. 2ba

Answers

Answer:

1) d. -3(x^2)

2) e. 2ba

3) b. 10x

4) c. 2a

5) a. (a^2)b

Page < 3 > of 4 0 ZOOM + Question 4
A study was conducted to test the effectiveness of a software patch in reducing
system failures over a six-month period. Results for randomly selected installations
are shown. The "before" value is matched to an "after" value, and the differences
are calculated. The differences have a normal distribution. Test at the 1% significance level.
Installation. a. b. c. d. e. f. g. h
Before. 3. 6. 4. 2. 5. 8. 2. 6
After. 1. 5. 2. 0. 1. 0. 2. 2
c) What is the p-value?
a) What is the random variable?
b) State the null and alternative hypotheses.
d) What conclusion can you draw about the software patch?

Answers

a) The random variable in this study is the difference in system failures before and after applying the software patch for each installation.

b) Null hypothesis (H0): There is no significant difference in system failures before and after applying the software patch.
c) Alternative hypothesis (H1): There is a significant difference in system failures before and after applying the software patch.

d) The p-value of approximately 0.0034.

e) The software patch is effective in reducing system failures.

We have,
a)

What is the random variable?
The random variable in this study is the difference in system failures before and after applying the software patch for each installation.

b)
State the null and alternative hypotheses.
Null hypothesis (H0): There is no significant difference in system failures before and after applying the software patch.
Alternative hypothesis (H1): There is a significant difference in system failures before and after applying the software patch.

Now, let's calculate the differences and their mean and standard deviation to find the t-statistic and p-value:
Differences: 2, 1, 2, 2, 4, 8, 0, 4
Mean (µ) = (2+1+2+2+4+8+0+4)/8 = 23/8 = 2.875
Standard Deviation (σ) = √[((2-2.875)^2 + (1-2.875)^2 + ... + (4-2.875)^2)/7] = 2.031009
Standard Error (SE) = σ/√n = 2.031009/√8 = 0.718185

t-statistic = (µ - 0)/SE = (2.875 - 0)/0.718185 = 4.004006

c)

What is the p-value?
Since we are testing at the 1% significance level and it's a two-tailed test, we need to find the p-value for a t-statistic of 4.004006 with 7 degrees of freedom.

Using a t-distribution table or calculator, we get a p-value of approximately 0.0034.

d)

What conclusion can you draw about the software patch?
Since the p-value (0.0034) is less than the 1% significance level (0.01), we reject the null hypothesis.

This means that there is a significant difference in system failures before and after applying the software patch, indicating that the software patch is effective in reducing system failures.

Thus,

a) The random variable in this study is the difference in system failures before and after applying the software patch for each installation.

b) Null hypothesis (H0): There is no significant difference in system failures before and after applying the software patch.
c) Alternative hypothesis (H1): There is a significant difference in system failures before and after applying the software patch.

d) The p-value of approximately 0.0034.

e) The software patch is effective in reducing system failures.

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Mr. Fowler's science class grew two different varieties of plants as part of a experiment. When the plant samples were fully grown, they compared their heights.

Answers

Answer:

Step-by-step explanation:

Option D is the correct option.

What is Mean Absolute Deviation?

'The mean absolute deviation (MAD) is the mean (average) distance between each data value and the mean of the data set.'

According to the given problem,

The mean height Variety A = 19 [ from the table ]

The mean height of variety B = 13 [ from the table ]

The spread is given by the mean absolute deviation, which 1.2 for Variety A and 2.4 for Variety B. So we can see that, the spread in Variety A is lesser than the spread in Variety B, which shows that the average height of Variety A varies less than the average height of Variety B.

We can see from the table that the average height of a variety A is indeed greater than that of Variety B. Also we can see that the Mean Absolute deviation of Variety A is 1.2 which is lesser than the Mean Absolute deviation of Variety B.

Hence, option D is correct since the average height of Variety A is greater than Variety B, and also the mean varies lesser in Variety A than in Variety B.

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Answer:

D

Step-by-step explanation:

hope this helps

If the range for a set of data is 24, from 2 to 26, and the mean is 17, what can you conclude about the data?

A. Not enough information to draw a valid conclusion.

B. There probably isn't a mode.

C. The median will be 17 also.

D. 17 is the typical data value.

Answers

The correct statement is,

⇒ Not enough information to draw a valid conclusion.

Given that;

If the range for a set of data is 24, from 2 to 26,

And, the mean is 17.

Now, We know that;

To find mean we have to need that all the terms, but here only first and last terms are given.

Thus, Not enough information to draw a valid conclusion.

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HELP ME ASAP PLS I NEED IT FOR A TEST

Answers

Answer: 250 square centimeters

Step-by-step explanation:

Height (h) = 10 cm

Length (l) = 5 cm

Width (w) = 5 cm

Plugging in these values into the formula, we get:

SA = 2(5)(5) + 2(5)(10) + 2(5)(10)

SA = 50 + 100 + 100

SA = 250

So, the surface area of the rectangular prism is 250 square centimeters (cm^2).

Mr. smith is taking an extravagant trip to Puerto Rico. He knows he can bring 1.5 bags for every $52.50 he pays. If his flight costs $262.50 how many bags can Mr. smith bring?

Answers

Mr. Smith can bring 6 bags on his trip to Puerto Rico.

Here's how to calculate it:

First, calculate how many bags Mr. Smith can bring per dollar:

1.5 bags / $52.50 = 0.0286 bags per dollar (rounded to the nearest ten-thousandth)

Next, divide the cost of his flight by the rate of bags per dollar:

$262.50 x 0.0286 = 5.99 bags (rounded to two decimal places)

Since Mr. Smith can't bring a fraction of a bag, we round down to the nearest whole number. Therefore, Mr. Smith can bring 6 bags on his trip to Puerto Rico.
I think the answer is. 7.5

if the money supply doubles and the velocity of money is stable, what will happen to real gdp in the long run

Answers

If the money supply doubles and the velocity of money is stable, the long-run impact on real GDP will depend on other factors that influence the economy's overall growth. In the short term, a sudden increase in the money supply may boost economic activity and output as businesses have more access to credit and consumers have more disposable income to spend.

However, in the long run, the economy's potential output is determined by its ability to produce goods and services efficiently, which is reflected in the level of real GDP.
If the money supply continues to grow faster than the economy's capacity to produce, it can lead to inflation, which can erode the purchasing power of money and reduce economic growth. Therefore, in the long run, the impact of a doubling of the money supply on real GDP will depend on whether it leads to sustainable economic growth or inflationary pressures.

Moreover, the relationship between money supply, velocity, and real GDP is complex and influenced by various factors, such as fiscal policy, monetary policy, technological progress, and demographic changes. Therefore, while a doubling of the money supply may lead to short-term growth, its long-term impact on real GDP depends on the broader economic context in which it occurs.
If the money supply doubles and the velocity of money remains stable, in the long run, the real GDP may not be significantly affected. Here's a step-by-step explanation of this scenario:

1. When the money supply doubles, there will be more money circulating in the economy. This increase may initially lead to higher demand for goods and services, causing prices to rise.

2. The velocity of money, which is the rate at which money is exchanged from one transaction to another, remains stable. This means that the overall pace of economic transactions doesn't change.

3. In the short run, the increased money supply may lead to a temporary boost in economic activity and possibly higher nominal GDP. However, this increase is primarily due to the inflation caused by the rise in prices, not necessarily an increase in the production of goods and services.

4. In the long run, the economy will adjust to the higher money supply, and the real GDP will return to its original level. This is because the long-run growth of the real GDP is determined by factors such as productivity, technological advancements, and the availability of resources, rather than changes in the money supply.

5. Eventually, the economy will reach a new equilibrium with higher prices, but the real GDP will remain unchanged in the long run. The increase in the money supply will only lead to higher inflation, not a sustainable increase in real economic output.

In summary, doubling the money supply while keeping the velocity of money stable may temporarily boost nominal GDP, but it won't result in a long-term increase in real GDP, as other factors determine its growth.

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PLEASE HELP I DON'T KNOW WHAT TO DO

Solve for f (n) and show your work.
The question asks whether repeating two simple arithmetic operations will eventually transform every positive integer into 1.

Answers

Yes, repeating two simple arithmetic operations will eventually transform every positive integer into 1.

Checking whether repeating two operations will transform every positive integer into 1.

From the question, we have the following parameters that can be used in our computation:

f(n) = n/2 if n%2 = 0

f(n) = 3n + 1 if n%2 = 1

The above definition means that

f(n) = n/2 if n is even

f(n) = 3n + 1 if n is odd

To check if repeating operations would transform to 1, we can set n = 10

and then evaluate the function values

So, we have

f(10) = 10/2 = 5

f(5) = 3(5) + 1 = 16

f(16) = 16/2 = 8

f(8) = 8/2 = 4

f(4) = 4/2 = 2

f(2) = 2/2 = 1

See that the end result of the operations is 1

Hence, repeating two operations will transform every positive integer into 1

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PLEASE HELP!!!!!!!!!!Test scores for the 31 members of the algebra class are represented in the histogram below. How many students scored in the interval 80≤S<99

A. 13
B. 20
C. 17
D. 34

Answers

Answer:

option c

Step-by-step explanation:

as it is between 80 and closely 100 adding both the intervals gives 17

Prove that n^3 +3n +4 is e(2n^3).

Answers

Answer:

To prove that n^3 + 3n + 4 is Θ(2^n), we need to show that it is both O(2^n) and Ω(2^n).

First, let's show that it is O(2^n). To do this, we need to find constants c and n0 such that n^3 + 3n + 4 <= c * 2^n for all n >= n0.

We can start by simplifying the left-hand side: n^3 + 3n + 4 <= n^3 + n^3 + n^3 (since 3n <= n^3 and 4 <= n^3 for all n >= 1).

So we have: n^3 + 3n + 4 <= 3n^3

Now, for n >= 1, we know that 2^n <= 3^n, so we can write: 3n^3 >= 2^n

Therefore, we have: n^3 + 3n + 4 <= 3n^3 <= c * 2^n for c = 3 and n0 = 1.

So, n^3 + 3n + 4 is O(2^n).

Next, let's show that it is Ω(2^n). To do this, we need to find constants c and n0 such that n^3 + 3n + 4 >= c * 2^n for all n >= n0.

One way to approach this is to try to find a lower bound for n^3 + 3n + 4 by removing some terms (because we want to show that the left-hand side is at least as big as some constant times 2^n, and the more terms we have on the left-hand side, the harder that is to do).

If we remove the 3n and the 4, we have n^3 <= n^3.

If we remove only the 4, we have n^3 + 3n >= n^3.

Either way, we have: n^3 + 3n >= n^3 >= c * 2^n for c = 1 and n0 = 1.

Therefore, n^3 + 3n + 4 is Ω(2^n).

Since we have shown that n^3 + 3n + 4 is both O(2^n) and Ω(2^n), we can conclude

Step-by-step explanation:

We have shown that n^3 + 3n + 4 is in the order of e(2n^3), as required.

To prove that n^3 + 3n + 4 is in the order of e(2n^3), we need to show that there exist positive constants c and n0 such that:

n^3 + 3n + 4 <= c * e(2n^3) for all n >= n0

Taking natural logarithm on both sides of the inequality, we get:

ln(n^3 + 3n + 4) <= ln(c) + 2n^3

Now, we need to show that there exist positive constants c and n0 such that the inequality holds.

Taking the derivative of the left-hand side of the inequality, we get:

d/dn (ln(n^3 + 3n + 4)) = (3n^2 + 3) / (n^3 + 3n + 4)

For n >= 1, we have:

3n^2 + 3 <= 3n^3 + 3n^2 <= 6n^3

n^3 + 3n + 4 >= n^3

Therefore,

d/dn (ln(n^3 + 3n + 4)) <= (6n^3) / n^3 = 6

This means that the function ln(n^3 + 3n + 4) is bounded above by a constant of 6. Thus, we can set c = e^6 and n0 = 1.

For all n >= 1, we have:

ln(n^3 + 3n + 4) <= 6 + 2n^3

n^3 + 3n + 4 <= e^(6 + 2n^3) = e^6 * e^(2n^3)

Therefore, we have shown that n^3 + 3n + 4 is in the order of e(2n^3), as required.

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What is the number of possible outcomes for the tree diagram below?

Answers

Answer:

It's D. 6.I think i am right,you can choose letter D.If it's be false you can scold me ok?

Karl and Leonard want to make soup. In order to get the right balance of ingredients for their tastes they bought 3 pounds of potatoes at $3.62 per pound, 5 pounds of cod for $4.56 per pound, and 3 pounds of fish broth for $3.66 per pound. Determine the cost per pound of the soup The cost per pound of the soup is $(Round to the nearest cent)

Answers

The cost per pound of the soup is $4.06 per pound (rounded to the nearest cent).

To find the cost per pound of the soup, we need to calculate the total cost of all the ingredients and divide it by the total weight of the soup.

The total cost of potatoes is 3 pounds × $3.62 per pound = $10.86.

The total cost of cod is 5 pounds × $4.56 per pound = $22.80.

The total cost of fish broth is 3 pounds × $3.66 per pound = $10.98.

So, the total cost of all the ingredients is:

$10.86 + $22.80 + $10.98 = $44.64

The total weight of the soup is 3 + 5 + 3 = 11 pounds.

Thus, the cost per pound of soup is:

$44.64 / 11 pounds = $4.06 per pound

Therefore, the cost per pound of the soup is $4.06 per pound (rounded to the nearest cent).

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2.2 Loads endured by a cable are assumed to be from an exponential distribution with probability distribution function f(x;1) = le-te A sample of loads was 2.39 3.11 2.91 2.51 3.08 and the rate parameter, lambda, was estimated to be the sample variance of the load. Use the information in this sample to derive formulae for calculating the following probabilities:- 2.2.1 the maximum load is at least 3, [4 2.2.2 the minimum load is no more than 4.11, [4] EFFE 2.2.3 the median load is between 1.2 and 6. [4] 2.2.4 the range of the load is at most 2.5. [4]

Answers

The estimated value of λ and x = 2.91, we get:

P(1.2 ≤ median load ≤ 6) = 1 - e^(-0.38*2.91) - (

2.2.1 To calculate the probability that the maximum load is at least 3, we first need to find the distribution of the maximum load. Let X be the random variable representing the loads. Then the probability that the maximum load is less than or equal to x is given by:

P(X ≤ x)^n = (1 - e^(-λx))^n

where n is the sample size. Taking the derivative of this expression with respect to x and setting it equal to zero, we get:

n(1 - e^(-λx))^(n-1)λe^(-λx) = 0

Solving for x, we get

x = -ln(1 - 1/n)/λ

Now, we can calculate the probability that the maximum load is at least 3 as follows:

P(X ≤ 3)^n = (1 - e^(-λ*3))^n

P(maximum load ≥ 3) = 1 - P(X ≤ 3)^n

Substituting the estimated value of λ (sample variance of the loads) and the sample size n = 5, we get:

P(maximum load ≥ 3) = 1 - (1 - e^(-0.38*3))^5 ≈ 0.578

Therefore, the probability that the maximum load is at least 3 is approximately 0.578.

2.2.2 To calculate the probability that the minimum load is no more than 4.11, we can use the same approach as in 2.2.1, but with the inequality flipped:

P(minimum load ≤ 4.11) = 1 - P(X ≥ 4.11)^n

where we need to find the distribution of the minimum load. The probability that the minimum load is greater than or equal to x is given by:

P(X ≥ x) = e^(-λx)

Substituting the estimated value of λ and x = 4.11, we get:

P(minimum load ≤ 4.11) = 1 - e^(-0.38*4.11) ≈ 0.448

Therefore, the probability that the minimum load is no more than 4.11 is approximately 0.448.

2.2.3 To calculate the probability that the median load is between 1.2 and 6, we first need to estimate the median load from the sample. The sample is already sorted as 2.39, 2.51, 2.91, 3.08, 3.11. The median load is the middle value, which is 2.91.

The probability that the median load is less than or equal to x is given by:

P(median load ≤ x) = P(X1 ≤ x, X2 ≤ x, X3 ≥ x, X4 ≥ x, X5 ≥ x) + P(X1 ≤ x, X2 ≤ x, X3 ≥ x, X4 ≥ x, X5 ≤ x) + P(X1 ≤ x, X2 ≤ x, X3 ≥ x, X4 ≤ x, X5 ≥ x)

where Xi represents the ith load in the sample. The probability that the median load is between 1.2 and 6 is then given by:

P(1.2 ≤ median load ≤ 6) = P(median load ≤ 6) - P(median load ≤ 1.2)

Substituting the estimated value of λ and x = 2.91, we get:

P(1.2 ≤ median load ≤ 6) = 1 - e^(-0.38*2.91) - (

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Can I get some help on this? I keep on getting it wrong and I don't know what happened.
I know they are congruent figures.

Answers

The two figures are not similar and hence will not exactly map to each other

What are similar polygons

In math, two polygons qualify as similar only under the following condition:

Corresponding angles being congruent: this indicates that one polygon's angles match measurements with objectivity to another.Corresponding sides are proportionate: Meaning that the ratio between either length proportions remains uniform no matter which analogous sides we scrutinize in both polygons.

In the polygon the ratio of the sides are not proportional. the sides are

Red: 3 units x 3 units

Blue: 1.5 units x 4 units

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BRAINLIST
SHow all steps pls it was due yesterday!

Answers

Answer:

Step-by-step explanation:

help asap!! find the center of:

9x^2+y^2-18x-6y+9=0
show work pls!!

Answers

Answer:

To find the center of the given ellipse, we need to first put the equation in standard form:

9x^2 + y^2 - 18x - 6y + 9 = 0

We can start by completing the square for both the x and y terms. For the x terms, we can add and subtract (18/2)^2 = 81 to get:

9(x^2 - 2x + 81/9) + y^2 - 6y + 9 = 0

Simplifying inside the parentheses, we get:

9(x - 9/3)^2 + y^2 - 6y + 9 = 0

For the y terms, we can add and subtract (6/2)^2 = 9 to get:

9(x - 3)^2 + (y - 3)^2 = 36

Dividing both sides by 36, we get:

[(x - 3)^2]/4 + [(y - 3)^2]/36 = 1

Comparing this to the standard form of an ellipse:

[(x - h)^2]/a^2 + [(y - k)^2]/b^2 = 1

We can see that the center of the ellipse is at the point (h, k), which in this case is (3, 3). Therefore, the center of the given ellipse is (3, 3).

Step-by-step explanation:

Answer:

center, = 9, 3

radius = 9

Step-by-step explanation:

9x² + y² - 18x - 6y + 9 = 0

equation of a circle is,

x² + y² + 2ax + 2by + c = 0

where center of a circle equals, -a, -b

radius = √a² + b² - c

by comparing the general equation from the given equation,

2ax = - 18x

a = -9

2by = -6y

b = -3

center of a circle -a, -b will be 9,3

radius = √81 + 9 -9

=√81

=9

find the perimeter of the regular hexagon
answers to choose from:
26 ft
60 ft
30 ft
15 ft

Answers

The perimeter of the regular hexagon is 30ft

The goal is to prove that this argument is valid. There is no restriction on which rules you use. This proof can be done in different ways, for instance there is a solution without CP or IP. (A.B) = C, (A.B) V-C /: A =B

Answers

To prove the validity of the argument, we need to show that the conclusion (A=B) follows logically from the premises ((A.B)=C and (A.B)V-C).

To prove the validity of the argument (A.B) = C, (A.B) V-C /: A = B, we can use the following steps:

1. Assume that A ≠ B, and then use the distributive law of conjunction and disjunction to rewrite the premise as follows: (A.B) V (-A.-B) V C
2. Apply De Morgan's laws to simplify the above expression to: (-A V -B) V (A V -C) V (B V -C)
3. Use the distributive law of disjunction over conjunction to further simplify the expression to: (-A V -B V A V -C) V (-A V -B V B V -C)
4. Use the law of excluded middle to simplify the first part of the expression to: (-A V -C) V (-B V -C)
5. Apply the rule of inference known as disjunctive syllogism to conclude that: -C
6. Substitute -C into the original premise to obtain (A.B) V -(-C), which is equivalent to (A.B) V C
7. Use the distributive law of conjunction over disjunction to rewrite the above expression as follows: (A V C).(B V C)
8. Apply the rule of inference known as simplification to obtain A V C and B V C
9. Use the law of excluded middle to simplify the second part of the expression to: -C V B
10. Apply the rule of inference known as disjunctive syllogism to conclude that: A
11. Use a similar argument to show that B must also be true.
12. Therefore, we have shown that if (A.B) = C and (A.B) V-C, then A = B, which proves the validity of the argument.

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help asap plsss solve trig problem

Answers

Answer:

Set your calculator to degree mode.

cos(48°) = y/35

y = 35cos(48°)

tan(20°) = x / 35cos(48°)

x = 35cos(48°)tan(20°) = 8.5 inches

Answer:

8.5 in

Step-by-step explanation:

Find height, h, of the triangle:

cos48 = h/35

h = cos48(35) = 23.42

tan20 = x/23.42

x = tan20(23.42) = 8.524 ≈ 8.5 in

A teacup has a diameter of 6 centimeters. What is the teacup’s radius?

Answers

Answer:

3 centimeters

Step-by-step explanation:

if an income of Rs.3 lakhs is to be received after 1 year at 5% rate of interest? Not yet answered A. 1.835 B. None of these C. 1.1 Flag question D. 2.85

Answers

The closest answer is B. None of these

To find the present value of an income of Rs. 3 lakhs to be received after 1 year at a 5% rate of interest, you can use the present value formula:

Present Value (PV) = Future Value (FV) / (1 + Interest Rate) ^ Number of Years

1. Repeat the question in your answer: The present value of an income of Rs. 3 lakhs to be received after 1 year at a 5% rate of interest is:

2. Step-by-step explanation:

Step 1: Identify the values for the formula.
- Future Value (FV) = Rs. 3 lakhs
- Interest Rate = 5% or 0.05
- Number of Years = 1

Step 2: Plug the values into the formula.
PV = Rs. 3,00,000 / (1 + 0.05) ^ 1

Step 3: Calculate the present value.
PV = Rs. 3,00,000 / 1.05

PV ≈ Rs. 2,85,714.29

Based on the given options, the closest answer is B. None of these, as the calculated present value is approximately Rs. 2,85,714.29, which does not match any of the provided options.

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Using the diagram, which of the following statements is true?




Using the diagram, which of the following statements is true?


-5 can be categorized as a whole number, integer, and rational number.


can be categorized as an integer and a rational number.


5.0 can only be categorized as a rational number.


can be categorized as a whole number, integer, and rational numb

Answers

The whole number(s) are 3 and -2.  A whole number doesn't have fractions or places after the decimal.  

How to explain the number

The natural number(s) is 3.  Think of a natural number as those used for counting, like "1, 2, 3, 4..."

The integer(s) are 3 and -2.  An integer includes positive or negative whole numbers, and 0.

The rational number(s) are 3, -2, and 1/4.  A rational number can be written as a fraction.

And irrational number, the square root of 5, cannot be written as a fraction.  It is the opposite of a rational number.  

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Using diagram whole numbers, natural numbers, integers, and rational or irrational numbers, which category does -2, 3, 1/4, and square root of 5

which is a whole number, natural number, integer, or rational or irrational number: -2, 3,  1/4, and square root of 5

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