The density of an object is dependent upon the object’s mass and ---

Answer:

Explanation:

I hope this helps

Answer:

first one 31

second one 23

Explanation:

on edge ;))

Answer:

Its D

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Explanation:

Also I got this question right I had it for an assignment

Answer:

A object, lets say a cup. This cup will never, ever move unless something or someone disturbs it. If something touches or hits this cup the cup will move. But, until the cup gets touched, nothing will EVER make it move.

Explanation:

I hope this helps!!

Answer:

4:A battery with 15 loops or wire around the nail

Explanation:

More loops equals more force

A battery with [tex]15[/tex] loops or wire around the nail have the stronger force.

So, option 4 is correct.

An electromagnet is a system that contains of a magnetic encircled by a coil that conducts an electric current to ionize the core.

Wherever controllable magnetism are required, such as in devices where the magnetic flux must be adjusted, reversed, or turned on and off, an electromagnet is utilized.

A battery with [tex]15[/tex] loops or wire around the nail have the stronger force.

So, option 4 is correct.

Find out more information about magnet here:

https://brainly.com/question/13026686?referrer=searchResults

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 6 × 4

We have the final answer as

Hope this helps you

Answer:

24 n is the answer

Answer:

A 1

B 3

c 4

d 3

Explanation:

we are chaimpon boy i topped my school by cheating so donot study chill and watch movies like of sunny leon and Sabita bhabi

Answer:

48 students will ride on each bus.

Explanation:

192 students divided by 4 busses comes out to 48 students per bus.

Basically: 192/4=48

Answer:

The maximum distance Charles will push down the trampoline ≈ 0.342 m

Explanation:

The given parameters are;

The mass of the trampoline artist, m = 75 kg

The speed with which the trampoline artist lands, v = 9.0 m/s

The value of the spring constant of the trampoline, k = 52,000 N/m

Let x represents the maximum distance Charles will push down the trampoline

Therefore, we have;

Kinetic energy = 1/2·m·v²

The kinetic energy with which the trampoline artist lands  = 1/2 × 75 × 9.0² = 3037.5

The kinetic energy with which the trampoline artist lands  =  3037.5 J

The potential energy stored in a spring = 1/2·k·x² = The kinetic energy with which the trampoline artist lands

∴ 1/2 × 52,000 × x² = 3037.5

∴ x = √(3037.5/(1/2 × 52,000)) ≈ 0.342

The maximum distance Charles will push down the trampoline = x ≈ 0.342 m

Answer:

Option B

Explanation:

Displacement  = Area under the velocity-time graph

So to find the displacement of a particle from 7 to 8 seconds we take the triangle and calculate its area.

[tex]Area\ of\ a\ right\ angled\ triangle = \frac{1}{2}*(base)*(height) \\\\Area\ of\ a\ right\ angled\ triangle = \frac{1}{2}*(1)*(3) \\\\Area\ of\ a\ right\ angled\ triangle = 1.5[/tex]

So the displacement is 1.5 meters

I have an uploaded image so you can understand it better hope it helps

Answer:

10m/s

Explanation:

Answer:

i think its second law of motion.

Explanation:

Answer:

it’s the second law

Explanation:

Spreading my love to everyone, <3

Answer:

E_{k2}=2660 [J] kinetic energy.

Explanation:

The energy in the initial state i.e. when the rollercoaster is at the top is equal to the energy in the final state i.e. when it is at the bottom of the hill.

These states can be represented by means of the second equation.

[tex]E_{k1}+E_{p1}=E_{k2}\\160 + 2500 = E_{k2}\\E_{k2}=2660 [J][/tex]

Since the rollercoaster is located in the bottom of the hill where the potential energy level is zero, therefore there is only kinetic energy in the second state.

The answer is C. Rectum.

Answer:

You have a severe case.

Explanation:

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Answer:

Accelerating

Explanation:

Answer:

B

Explanation:

Answer:

B

Explanation:

I had a feeling

Answer:

tysm

Explanation:

Answer:

OMG THANK U SO MUCH I NEEDED THEMMMMM

Answer:

W = 30.38 N

Explanation:

Given that,

Mass of a rock, m = 3.1 kg

We need to find the weight of the rock on the surface of Earth. Weight of an object is given by :

W = mg

g is the acceleration due to gravity, g = 9.8 m/s²

W = 3.1 kg × 9.8 m/s²

= 30.38 N

So, the weight of the rock on the Earth is 30.38 N.

Answer:

I do believe it is A.

Explanation:

I hope this helps :)

Answer:I believe it is A

Explanation: B just doesn't seem like something an 8th grader would be learning about, and I'm not sure about the other ones.

Answer:

a) El remolque desciende 7.4 cm

b) La carga debe ser de 15715.6 N ó 1603.6 kg

Explanation:

Para los cálculos que involucren muelles, se aplica la Ley de Hooke, la cual relaciona el efecto de una Fuerza y el cambio de longitud que esta ejerce,  en un resorte de elasticidad dada.

Escrito en fórmula:

[tex]F=-k \cdot \Delta L[/tex]

Donde:

F es la fuerza ejercida

k es la constante elástica del muelle

ΔL es la variación de longitud del muelle

El problema indica que al cargar 2100 kg se ejerce una fuerza de 20580 N

Esto se corrobora con la 2da ley de Newton y asumiendo una aceleración de gravedad de 9.8 [tex]\frac{m}{s^{2} }[/tex]

[tex]F_{1} =m \cdot a\\F_{1}=2100kg \cdot 9.8\frac{m}{s^2}\\F_{1}=20580N[/tex]

Esta fuerza comprime o reduce la longitud del muelle en 5.5 cm. Usando estos datos en la Ley de Hooke, podemos obtener la constante elástica k:

[tex]F=-k \cdot \Delta L\\20580N=-k \cdot (-0.055m)\\\\k=\frac{20580N}{0.055m}\\k= 374181\frac{N}{m}[/tex]

Ahora ya tenemos los datos para resolver las preguntas:

Aplicando directamente la formula de la Ley de Hooke:

[tex]F=-k \cdot \Delta L\\\Delta L=\frac{F}{-k} \\\Delta L= \frac{28000N}{-374181\frac{N}{m}} \\\Delta L=-0.074 m = -7.4cm[/tex]

En este caso debemos calcular la fuerza necesaria que haga descender el remolque 4.2cm. Nuevamente utilizando la Ley de Hooke con estos nuevos datos:

[tex]F=-k \cdot \Delta L\\F=-374181\frac{N}{m} \cdot (-0.042m)\\F=15715.6N[/tex]

Si queremos saber la carga en kilogramos:

[tex]F = m \cdot a\\m = \frac{F}{a} \\m = \frac{15715.6N}{9.8\frac{m}{s^2} }\\m= 1603.6 kg[/tex]

Answer:

10.08 m/s

Explanation:

The average speed of a body or an object can be calculated from the ratio of the total distance traveled by the body/object to that of the time taken to cover the distance.

Mathematically,

Average speed = total distance/total time

The total distance covered by Carl Lewis = 100 m

The total time taken = 9.92 s

Hence,

Average speed of Carl Lewis = 100/9.92

                                         = 10.08 m/s

Answer: The live wire is the most dangerous one, since it is at 230 V. it should never touch the earth wire (unless the insulation is between them, of course!), because this would make a complete circuit from your mains supply to the ground (earth). A shock or fire would be highly likely.

Explanation:

Answer:

The velocity of the two cars is 10 m/s after the collision.

Explanation:

Law Of Conservation Of Linear Momentum

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is

P=m.v

If we have a system of bodies, then the total momentum is the sum of them all

[tex]P=m_1v_1+m_2v_2+...+m_nv_n[/tex]

If some collision occurs, the velocities change to v' and the final momentum is:

[tex]P'=m_1v'_1+m_2v'_2+...+m_nv'_n[/tex]

In a system of two masses, the law of conservation of linear momentum  takes the form:

[tex]m_1v_1+m_2v_2=m_1v'_1+m_2v'_2[/tex]

If both masses stick together after the collision at a common speed v', then:

[tex]m_1v_1+m_2v_2=(m_1+m_2)v'[/tex]

The car of mass m1=1000 Kg travels at v1=25 m/s and collides with another car of m2=1500 Kg which is at rest (v2=0).

Knowing both cars stick and move together after the collision, their velocity is found solving for v':

[tex]\displaystyle v'=\frac{m_1v_1+m_2v_2}{m_1+m_2}[/tex]

[tex]\displaystyle v'=\frac{1000*25+1500*0}{1000+1500}[/tex]

[tex]\displaystyle v'=\frac{25000}{2500}[/tex]

v' = 10 m/s

The velocity of the two cars is 10 m/s after the collision.

Please find attached photograph for your answer.