The deepest section of ocean in the world is the Mariana Trench, located in the Pacific Ocean. Here,the ocean floor is as low as 10,918m below the surface. If the index of refraction of water is 1.33, howlong would it take a laser beam to reach the bottom of the treach?

Answers

Answer 1

Given:

The depth of the trench, d=10,918 m

The refractive index of the water, n=1.33

To find:

The time it takes for the laser beam to reach the bottom of the ocean.

Explanation:

The refractive index of water is given by,

[tex]n=\frac{c}{v}[/tex]

Where c is the velocity of the laser in vacuum and v is the velocity of the laser in water.

On substituting the known values,

[tex]\begin{gathered} 1.33=\frac{3\times10^8}{v} \\ \implies v=\frac{3\times10^8}{1.33} \\ =2.3\times10^9\text{ m/s} \end{gathered}[/tex]

The velocity is given by the equation,

[tex]v=\frac{d}{t}[/tex]

Where t is the time it takes for the laser to reach the bottom of the trench.

On substituting the known values,

[tex]\begin{gathered} 2.3\times10^8=\frac{10,918}{t} \\ \implies t=\frac{10,918}{2.3\times10^8} \\ =47.5\times10^{-6}\text{ s} \\ =47.5\text{ }\mu\text{s} \end{gathered}[/tex]

Final answer:

The laser beam would reach the bottom in 47.5 μs


Related Questions

what is a tone? multiple choice question. a sound with definite and steady vibrations a note that is emphasized the distance between two pitches the distinctive sound quality of an instrument

Answers

A tone is a sound with definite and steady vibrations.

What is tone?
The author's attitude toward the topic they are writing about is the definition of tone in literature. The Latin word tonus, which means a sound or accent, and the French word tonne, which denotes a musical sound, are the origins of the word tone. Whether the author intends it or not, the reader always picks up on the tone of a work of literature. The words an author chooses as well as how they are used make up their diction. The way an author speaks affects the reader's mood. The syntax, point of view (a particular attitude as well as way of describing a subject), diction, and degree of formality used in writing all convey the tone of the piece. Writing can take on a formal or informal tone.

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name two powers of the president

Answers

Answer:

The President can issue executive orders, which direct executive officers or clarify and further existing laws.

The President also has the power to extend pardons and clemencies for federal crimes.

Explanation:

complete the table=x =0 2 3 4 6 8 y=30 27 24

Answers

Answer: (x=1 y=30) (x=2 y=27) (x=3 y=24) (x=4 y=21) (x=5 y=18) (x=6 y=15) (x=7 y=12) (x=8 y=9) (x=9 y=6) (x=10 y=3) etc its going down by 3 so 30-3=27 27-3=24 24-3=21 etc

hope i helped

Explanation:

a flat coil of wire consisting of 17 turns, each with an area of 50 cm2, is positioned perpendicularly to a uniform magnetic field that increases its magnitude at a constant rate from 3 t to 6 t in 2.0 s. what is the magnitude of the emf (in volts) induced in the coil? your answer should be a number with two decimal places, do not include the unit.

Answers

The magnitude of electromotive force is 0.13 volt.

We need to know about the electromotive force of induction to solve this problem. The emf induction appears when there is any change in magnetic flux. The magnitude of emf can be determined by

ε = N dΦ / dt

where N is coil turns, ε is electromotive force, dΦ is change in magnetic flux and dt is time interval.

From the question above, the parameters given are

B1 = 3T

B2 = 6T

dt = 2 s

N = 17

A = 50 cm² = 5 x 10¯³ m²

Find the change in magnetic flux

dΦ = (Φ2 - Φ1)

dΦ = (B2 . A - B1 . A)

dΦ = A (B2 - B1)

dΦ = 5 x 10¯³(6 - 3)

dΦ = 15 x 10¯³ Tm²

By substituting the given parameters, we can calculate electromotive force

ε = N . dΦ / dt

ε = 17 . 15 x 10¯³ / 2

ε = 0.13 volt

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How far could you speed walk in 90 seconds based on your speed for the 10 meter trail

Answers

Answer:

Explanation:

Given,

Time ( t ) = 90 seconds

Distance ( d ) = 10 meter

To find : Speed ( v ) = ?

Formula : -

v = d/t

v = 10/90

v = 1/9 m/s ( meters per second )

Hence,

1/9 m/s is the speed walk in 90 seconds for the 10 meter trail.

5. An object travels with constant speed through 1km for one minutes and 20 seconds and accelerates with 0.125m/s² for 20 seconds, what is the total displacement? A) 1250 m B) 275 m C) 1275 m D) 1225m​

Answers

Answer:

C)  Total displacement = 1275 m or 1.275 km

Explanation:

We'll break this into two parts:  

1) Displacement during constant speed, and

2) Displacement during the acceleration phase.

Constant Speed

The displacement for this segment is already stated:  1 km.  But the information includes the time, which will allow us to calculate the speed of travel.  We'll need this for the next phase of acceleration.

Distance = Speed x Time

Speed = Distance/Time

Time = 1 minute + 20 sec, or 80 sec.

Speed = 1 km/80 sec

Speed = 0.0125 km/sec

Since we'll be using meters (not km) in the next step, convert 0.0125 km/sec to m/sec with a conversion factor:  

  (0.0125 km/sec)*(1000m/1 km) = 12.5 m/sec

Acceleration Phase

The obect is moving at a speed of 12.5 m/sec (from above) and then accelerates at a rate of 0.125 m/sec^2 for 20 seconds.

The distance (s) an object travels during this acceleration (a) is gven by:

  s = vi*t + (1/2)a*t^2,

where vi is the initial velocity (12.5 m/sec in this case), a is the acceleration (0.125 m/sec^2), and t is the time (20 seconds).

s = (12.5 m/sec)(20 sec) + (1/2)(0.125 m/sec^2)*(20 sec)^2

s = 275 meters

Now add the two distances:

1) Constant Speed Phase = 1000 m

2)  Acceleration Phase    =  275 m

Total displacement = 1275 m or 1.275 km

Instructions:Draw a speed graph in the box that matches thefollowing scenario:A runner jogged 40m at a slow pace for 40seconds. She then stopped for 40 seconds to gea drink of water. After that, she sped up and ran60m more in 20 seconds.Tip:y axis - total of 100 mx axis - total of 100 s

Answers

Given data:

1) Runner jogged 40 m at a slow pace for 40 sec.

2) Stopped for 40 sec.

3) Again funs for 60 m in 20 sec.

a lighthouse is located on a small island 5 km away from the nearest point p on a straight shoreline and its light makes seven revolutions per minute. how fast (in km/min) is the beam of light moving along the shoreline when it is 1 km from p? (round your answer to one decimal place.)

Answers

188.4 km/min is the beam of light moving along the shoreline.

The lighthouse is 5 km far away from the nearest Point P on a straight shoreline. This is often radius of the encirclement of the beam of light moving at 7 rpm.

At 7 rpm, One Circumference of the sunshine takes 70/7 = 10 seconds 2πr is= 2.π.5 km in 10 seconds or

In one second the beam covers 10π/10 = π km or 3.14 km/s.

Now, if the purpose P is 1 km away from the lighthouse, the Radius is reduced to 1 from 5 km,

Consequently The Angular displacement would remain the identical but the speed would be slower for one circumference i.e. 2πr in 10 seconds.

Or one second= (2π.1)/10

= .628π km

= π/10

= 3.14 km/s

By converting km/s into km/min

The answer will be = 188.4 km/min.

188.4 km/min fast (in km/min) is the beam of light moving along the shoreline when it is 1 km from point P.

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a passenger walks along the aisle of a train at a speed of 1.3 m/s. the train moves at a speed of 30.2 m/s with respect to the ground. calculate the relativistic correction to the classical value of the passenger speed with respect to the ground. what is the percentage of this correction?

Answers

The parameters of speed are time divided by distance.The most often used unit of speed in daily life is the kilometer per hour (km/h), or miles per hour in the US and the UK. The SI's unit of speed is the metre per second (m/s) (mph).

How are speeds determined?

Speed is calculated as follows: speed = distance * time.Knowing the units for distance and time is necessary to calculate the units for speed.The units will be in metres per second (m/s) in this example since the distance is measured in metres (m) and the time is measured in secondsWe have provided The passengers' speed in relation to the train is 2.30 mph, not 2.30 g.Additionally, the passenger is moving at a speed of 30.2m/s relative to the ground.And at a 28 degree angle to the north-west.Therefore, the cost for us passengers will be 4.5 cost 28 and the I. component will be 30.2 signed 28.

Now that we know the train's velocity with respect to the ground, we can calculate the passengers' velocity with respect to the train by subtracting the train's velocity with respect to the ground.We shall rearrange this equation once we have determined a city of trained individuals with regard to the ground.Now, if we just insert all of these variables, the passenger's velocity is equal to 30.2 28° I + 4.5 Cost 28° J minus 2.30 G.And after calculation, this will be equal to 3.97 G -2.30 G less, or -2.11 I.Furthermore, this will result in -2.11 I plus 1.67 G.The equation for training velocity with respect to the ground will now be as follows.The size and direction of the trend's velocity with respect to the ground must be determined.Therefore, the magnitude will be 2.11 sq plus 1.67, square root off.We shall rearrange this equation once we have determined a city of trained individuals with regard to the ground.Now, if we just insert all of these variables, the passenger's velocity is equal to -4.5 9 28° I + 4.5 Cost 28° J minus 2.30 G.Calculating yields a value of 2.69 meters per second, and the direction is equal to 2.11 divided by 1.67, which will result in 51.63 agreement.As a result, the trend's magnitude and direction will be B, 2.69 m/s, and 51.63°, respectively, with regard to the ground.

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As a result, the trend's magnitude and direction will be B, 2.69 m/s, and 51.63°, respectively, with regard to the ground.

How are speeds determined?Knowing the units for distance and time is important to determine the units for speed. In this example, the units will be measured in metres per second (m/s), as the distance is measured in metres (m) and the time is measured in seconds.We have said that, rather than 2.30 g, the passengers' speed in respect to the train is 2.30 mph.In addition, the passenger is traveling at a relative speed of 30.2 m/s to the ground.Additionally, at a 28-degree northwestern angle.As a result, our guests will pay 4.5 cost 28 and the I. component will be signed at 30.2 and be.

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The potential energy of a roller coaster is 50 joules. The kinetic energy of the same coaster is 50 joules. What is the mechanical energy of the coaster?.

Answers

A roller coaster's mechanical energy is equal to 100 Joules if its P.E. and K.E. are each 50 Joules.

As a result, the roller coaster has a mechanical energy of 100 Joules.

explanation?

50 Joules is the potential energy of a roller coaster.

A roller coaster has kinetic energy of 50 Joules.

In order to determine the roller coaster's mechanical energy:

The entire amount of potential energy (P.E.) and kinetic energy (K.E.) that an object or body possesses is known as mechanical energy.

(ME)=50+50

Mathematically, the formula for mechanical energy states that it is equal to 100 joules when the given values are substituted.

As a result, the roller coaster has a mechanical energy of 100 Joules.

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A particle’s position along the x-axis is described by the functionx(t) = A t + B t2,where t is in seconds, x is in meters, and the constants A and B are given below.Randomized VariablesA = -4.9 m/sB = 6.9 m/s2q. Enter expression interms of A,B, t for the velocity of the particle as a function of time? What time will the velocity be zero?

Answers

Given,

The position function is, x(t)=At+bt²

A=-4.9 m/s

B=6.9 m/s²

The velocity is described as the rate of change if the displacement with time.

That is, the velocity is the time derivative of the displacement.

Therefore on differentiating the given function with respect to the time, we get the expression for the velocity.

i.e.,

[tex]\begin{gathered} v(t)=\frac{d(At+Bt^2)}{dt} \\ =A+2Bt \end{gathered}[/tex]

Therefore the expression for the velocity is A+2Bt

To know at what time the velocity will be zero,

[tex]A+Bt=0[/tex]

On simplifying the above equation,

[tex]t=\frac{-A}{B}[/tex]

On substituting the known values in the above equation,

[tex]t=\frac{-(-4.9\text{ )}}{6.9}=0.71\text{ s}[/tex]

Therefore the velocity will be zero at 0.71 s

On his trip from home to school, Noah Omwerk drives along three streets after exiting the driveway. He drives 1.85 miles south, 2.43 miles east, and 0.35 miles north. Determine the magnitude of Noah's resultant displacement. And the angle from East to South.

Answers

The resultant displacement of Noah from the question is  2.9 miles.

What is the resultant displacement?

The displacement is a vector quantity. Recall that a vector quantity is going to posses both a magnitude and a direction as we can see. This implies that the result of the vector which is the single vector that has the combines effect in magnitude and direction as all the vectors put together would be obtained by a geometric rather than an algebraic method. We now have to apply the rules that are used to obtain the resultant vector in each of the cases that does apply here.

We are now told that he drives 1.85 miles south, 2.43 miles east, and 0.35 miles north. The resultant of the vector in the North - South direction is; 1.85 miles - 0.35 miles = 1.5 miles.

Then the general resultant vector is obtained from;

R = √(1.5)^2 + (2.43)^2

R = 2.9 miles

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A 4 coulombs charged particle experiences an electric force of 200 N when placed at point P in an electric field. The magnitude of the electric field at point P is :
a) 5 N/C
b) 800 N/C
c) 0.02 N/C
d) 50 N/C

Answers

(d) 50N/C

The magnitude of the electric field at point 'P' is 50N/C.

It is derived from the basic concepts of Electrostatics. Coulomb's Law is the basis of relations in Electrostatics. It resembles Newton's Law of Gravitation.

Using the relation between Electric force, charge, and Electric field:

                                          F = qE

F = 200N; q = 4C

                                     200 = (4)E

                                          E = 50N/C  

It is widely used in the calculation of Electric Force and Electric Field. The S.I. Unit of the Electric Force is Newton. The S.I. Unit of the Electric Field is N/C. The S.I. Unit of charge is Coulomb.

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Which answer best describes "displacement"?

A. Displacement is a vector quality showing total length of an area traveled by a particular object.
B. Displacement is a scalar quantity which accounts for how far away an object is after a period of time has elapsed from its initial starting point.
C. Displacement is a scalar quality showing total length of an area traveled by a particular object.
D. Displacement is neither a vector nor scalar quantity, which accounts for how far away an object is after a period of time has elapsed from its initial starting point.

Answers

Answer: The answer is the letter

A

Explanation:

Because displacement Its a vector and the letter A says than displacement is a vector quality showing total length of an area traveled by a particular object.

Answer:

(Question 1) Which answer best describes displacement?

(Answer) Displacement is a vector quality showing total length of an area traveled by a particular object.

(Question 2) Kelley is playing pool and hits the cue into the nine ball, which is directly in the center of the pool table. The nine ball travels a total of 7 meters before stopping, 1 meter to the left of the initial starting point of the nine ball. Which sentence reflects the correct statement regarding distance and displacement when considering the motion of the nine ball?

(Answer) The nine ball traveled a distance of 7 meters and was displaced by 1 meter.

(Question 3) What is velocity?

(Answer) Velocity is a vector quantity that tells the distance an object has traveled over a period of time.

(Question 4) Imagine a time-position graph where the velocity of an object is constant. What will be observed on the graph concerning the slope of the line segment as well as the velocity of the object?

(Answer) The slope of the line is equal to zero and the object will be stationary.

(Question 5) Select the option that best summarizes the reason for the use of position-time graphs when studying physical science.

(Answer) The position-time graphs show the relationship between the position of an object (shown on the y-axis) and the time (shown on the x-axis) to show velocity.

Explanation:

just did the quick check, UwU enjoy

9. a supply plane needs to drop a package of food to scientists working on a glacier inalaska. the plane flies 100 m above the glacier at a speed of 150 m/s. how far short of the target should it drop the package?

Answers

[tex]X=150m/s * 4.518s =677.63m[/tex] far short of the target  it will drop the package.

How far short of the target should it drop the package?

First we can find the total time in order to reach the ground using the following kinematic formula:

[tex]y_{f} =y_{i}+v_{iy}+ \frac{1}{2} gt^{2}[/tex]

And replacing we have:

[tex]-100 =0+0- \frac{1}{2} (9.8)t^{2}[/tex]

And solving for t we got:

[tex]t=\sqrt{ \frac{2* (-100)}{-9.8} }=4.518 s[/tex]

And now we can find the final distance on the x axis using the formula:

[tex]D = Vxt[/tex]

The velocity on x not changes and is the same plane speed [tex]Vx=150m/s[/tex] , if we replace we got:

[tex]X=150m/s * 4.518s =677.63m[/tex]

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one steel ball and one aluminum ball are the same size but the steel ball weighs twice as much as the other. the balls are dropped from the roof of a single-story building at the same instant of time. the time it takes the balls to reach the ground below will be:

Answers

It is same for both the balls. Due to the fact that balls fall freely regardless of their weight, both metallic balls take the same amount of time to reach the ground.

When two identically sized objects are dropped from a certain height, they will fall with gravitational acceleration (g). The weight of the objects will not affect how long it takes them to reach the ground. The density of the medium in which an object is dropped affects how long it takes for each object to travel there. Due to the influence of gravity and the same medium, we can therefore infer that both metal balls will take the same amount of time to reach the ground (air). Experiments have been conducted in vacuum rooms and show that when the balls are released from the top of the store, the acceleration of attraction to the floor is gravity and it has a value of 9.8 meters/square second regardless of its weight.

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A man is pulling on a rope with a force of 44 N
directed at an angle of 63◦
to the horizontal.
What is the x-component of this force?
Answer in units of N.

Answers

Answer:

20 N

Explanation:

Vertical component will be   44 sin 63

HORIZONTAL component is  44 cos 63  N = 19.97 =~ 20 N

a thin, horizontal, 10-cm-diameter copper plate is charged to 3.5 nc. if the electrons are uniformly distributed on the surface, what are the strength and direction of the electric field

Answers

While negative point charges always move in the direction of the opposing electric field, positive point charges always move in the other direction. An electric field is a vector quantity. They cannot be added directly, but they can be vectorially inserted.

What are the electric field's strength and direction?

A physical field called an electric field surrounds electrically charged particles and attracts or repels all other charged particles nearby. It can also refer to the physical field surrounding a system of charged particles.

While negative point charges always move in the direction of the opposing electric field, positive point charges always move in the other direction. An electric field is a vector quantity.

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Hey surveyor is drawing property lines . He draws one line that is 25.0 m long and is 20° south of west.  how long is the western component of the vector he has drawn?

Answers

Answer:

23.5 m

Explanation:

25 m * cos 20   =23.5 m

after driving a portion of the route, the taptap is fully loaded with a total of 27 people including the driver, with an average mass of 70 kgkg per person. in addition, there are three 15- kgkg goats, five 3- kgkg chickens, and a total of 25 kgkg of bananas on their way to the market. assume that the springs have somehow not yet compressed to their maximum amount. how much are the springs compressed? enter the compression numerically in meters using two significant figures. view available hint(s)

Answers

When something, like a spring, is stretched, the added length is referred to as its extension.According to Hooke's law, as long as the limit of proportionality is not crossed, a spring's extension is directly proportionate to the force exerted.

Solve the problem ?

The ends of an extension spring connect to two devices.The hooks and loops on the extension springs store and compress energy.An extension spring delivers return force to connected mechanisms via hooks or loops.The no-load position is where tightly wrapped extension springs normally rest. Total mass refers to the combined weight of the shell, its structural and support equipment, and the heaviest load that may be conveyed.

The spring's compression at the specified weight is 0.80cm.

"Your inquiry is incomplete because it appears to be lacking the information below,"

The taptap's spring has a k value of 2.4 104 N/m.

the settings provided;

Each of the 27 people weighs 69 kg.

Each of the three goats weighs 15 kg.

Each of the five hens weighs 3 kg.

The weight of the bananas is 25 kg

The taptap's total mass, which includes every passenger, is computed as;

the people's combined mass is 27 x 70 or 1960 kg.

The goats' combined mass is 3 x 15 =45 kg.

The birds' combined mass is equal to 5 x 3 = 15 kg.

The bananas weigh a total of 25 kilograms

The extension of the spring

=   1960×9.8/2.4×104

= 19208/24000

=  0.80 cm

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A tennis ball moves 22 meters southward, then 12 meters northward, then 16 meters southward, and finally 34 meters northward

Answers

The resultant displacement of the tennis ball is 8 m northward.

What is displacement?

The displacement of an object is the change in the position of the object. The displacement of an object describes the shortest point between the final and initial position of an object.

The displacement of the tennis ball is calculated as follows;

d = (12 m north + 34 m north) - (22 m south + 16 m south)

d = (46 m north) - (38 m south)

d = 8 m northward

Thus, the resultant displacement of the tennis ball for the given motion is 8 m northward.

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The compete question is below:

A tennis ball moves 22 meters southward, then 12 meters northward, then 16 meters southward, and finally 34 meters northward. find the resultant displacement of the tennis ball.

After every movement in north and south direction multiple times, the displacement of the tennis ball is 8 meters in north direction.

What is displacement?

The definition of displacement is the modification of an object's position. It has a direction and magnitude and is a vector quantity. It is shown as an arrow that travels from the initial location to the conclusion.

According to the question, the tennis ball moves 22 meters in south direction then it moves towards north and travels for 12 meters again it turns to south and covers 16 meters and at last it covers 34 meters in the north direction.

d = (12 m + 34 m ) north direction - (22 m + 16 m ) south direction

d = 8 meters in north direction.

Hence, the total displacement done by the tennis ball is 8 meters in the north direction.

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an 81-kg baseball player slides into second base. the coefficient of kinetic friction between the player and the ground is 0.49. (a) what is the magnitude of the frictional force? (b) if the player comes to rest after 1.6 s, what was his initial velocity?

Answers

a) The magnitude of the frictional force= -µ mg = 0.49*81*9.8 = 389 N

b)The player comes to rest after 1.6 s,  his initial velocity Vi = 7.68 m/s

Acceleration due to friction = - µ g = - 4.80 m/s^2.

V = V0 + at

V = 0

a = - 4.802 m/s^2

t = 1.6 s

V0 = V - at = 0 + 4.8*1.6 = 7.68 m/s

the acceleration of the player due to frictional force is given as

a = f/m = 388.96 /81 = 4.8 m/s2

final velocity = Vf = 0

time = t = 1.6 sec

using the formula

Vf = Vi + at          (Vi = initial velocity)

Vi = Vf - at

Vi = 0 - (-4.8) (1.6)   (a = -4.8   since player is slowing down)

Vi = 7.68 m/s

A force known as friction exists between two surfaces that are sliding or attempting to glide over one another. Friction, for instance, makes it challenging to push a book across the floor. The direction in which an object moves or attempts to move is always the direction in which friction operates. When anything moves faster or slower in a straight line, it is said to have been acceleration. Because the direction is constantly changing, even motion on a circle accelerates at a constant pace.

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two power lines, each 300 m in length, run parallel to each other with a separation of 23 cm . part a if the lines carry parallel currents of 130 a , what is the magnitude of the magnetic force each exerts on the other? express your answer using two significant figures.

Answers

The magnitude of the magnetic force each exerts on the other is 4.41 N.

The magnitude of the magnetic force depends on the current through the wire, the length of the wire, and the radius of separation. It can be written as

F = μ₀ . I1 . I2 . L / (2π . a)

where F is a magnetic force, μ₀ is vacuum permeability (4π x 10¯⁷ H/m), I1 and I2 is current through the wire, L is the length of the wire and a is the radius of the wire.

From the question above, the given parameters are

L = 300 m

a = 23 cm = 0.23 m

I1 = I2 = 130 A

By substituting the parameters, we can calculate the magnetic force

F = μ₀ . I1 . I2 . L / (2π . a)

F = 4π x 10¯⁷ . 130 . 130 . 300 / (2π . 0.23)

F = 4.41 N

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a 2.6 m diameter penstock carries water at a velocity of 7m/s to an 80% efficient hydroelectricity generation facility in west virginia that produces 12 mw. another 2.275 m diameter penstock carries water at a velocity of 3 m/s to a 74% efficient hydroelectric generation facility in arkansas that produces 9 mw. what is the ratio of the heads of arkansas' reservoir to west virginia's reservoir?

Answers

The ratio of the heads of arkansas' reservoir to west virginia's reservoir is 1813 : 1120

Consider the West virginia reservoir,

To calculate the head of the virginia reservoir, we will use

φ = P / nρgh                      ...(1)

where φ is the flow rate, P is the power generated, n is efficiency, ρ is the density of water, g is the acceleration due to gravity and h is the head.

Given that flow rate is 7 m/s, power generated is 12 mw, 80% is the efficiency.

We know that density of water is 1000 [tex]kg/m^{3}[/tex] and  acceleration due to gravity is 9.8 [tex]m/s^{2}[/tex]

By using equation (1)

h = P / φnρg

h = [tex]\frac{12}{7 * \frac{80}{100} * 1000*9.8 }[/tex]

h = 13440

Similarly, the head of the arkansas reservoir will be

Given that flow rate is 3 m/s, power generated is 9 mw, 74% is the efficiency.

h = P / φnρg

h = [tex]\frac{9}{3 * \frac{74}{100} * 1000*9.8 }[/tex]

h = 21756

Now, the ratio of the heads of arkansas' reservoir to west virginia's reservoir is

= (heads of arkansas) / (head of the virginia)

= 21756 / 13440

= 1813 : 1120

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Whoever answers asap gets marked Brainliest! A hockey puck with a mass of 0.12 kg is traveling across the ice at a velocity of 150 m/s downfield. What is the momentum of the hockey puck?

P = 18 N

P = 18 kg * m/s

P = 8 * 10 - 4 kg * m/s

M = 18 kg * m/s

Answers

Answer:

Explanation:

Momentum = m * v  = .12 * 150 = 18 kg m/s

In the diagram below, two of the three rays used to find the image position are shown. Which of the following best describes the third (missing) ray?A.A ray incident parallel to the axis refracts outward, as if it came from the focus on the left hand side.B.A ray incident through the vertex continues through the lens without refracting.C.A ray incident parallel to the axis refracts so that it passes through the focus on the right hand side.D.A ray incident on a path that would take it through the right focus refracts parallel to the axis.

Answers

Answer:

C. A ray incident parallel to the axis refracts so that it passes through the focus on the right hand side

Explanation:

The third ray is the blue ray in the following figure

Therefore, the third ray is a ray parallel to the axis that refracts and passes through the focus of the right side.

So, the answer is:

C. A ray incident parallel to the axis refracts so that it passes through the focus on the right hand side

A truck is traveling at a constant velocity of 30 m/s. How long will it take to travel 1000 meters?

Answers

A truck is traveling at a constant velocity of 30 m/s. It  will take the time to travel 1000 meters is (t)=33.33 S.

What is velocity?

The velocity means the ratio of distance and time. Mathematically it means the distance divided by time. It can be measured in m/s and cm/s.

How can we calculate the time?

To calculate the time we are using thee formula here is,

S=vt

Or, t=S/v

Here we are given,

S = The covered distance of the car = 1000 m

v= The velocity of the car. = 30 m/s.

We have to calculate the time taken by truck = t

Now we put the values in the above equation, we get

t=S/v

Or, t=1000/30

Or, t=33.33 S

From the calculation we can say that,  It will take the time to travel 1000 meters is (t)=33.33 S.

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if the speed of a car is increased by 65%, by what factor will its minimum braking distance be increased, assuming all else is the same? ignore the driver's reaction time.

Answers

If the speed of the car is increased by 65%, the stopping distance of the car will be increased by 272.25%.

Let us say, the car is moving with velocity U, the stopping time of the car is T and the stopping distance of the block is d,

Now, we should use the equation of motion,

U²-V² =2aD

Where,

U is initial velocity,

V is final velocity,

D is the stopping distance,

a is the acceleration.

We know, at the final velocity will be zero,

So,

U² = 2aD

U =√(2aD)

Now, if the speed is increased by 65%, let us say the stopping distance becomes D'.

So,

U+65%U = √(2aD')

165U/100 = √(2aD')

Now, putting U = √(2aD),

165√(2aD)/100 = √(2aD')

(1.65)²D = D'

D' = 2.7225D

Now,

∆D = D' - D/D × 100

∆D = 2.7225 × 100

∆D = 272.25%

So, the stopping distance increased by 272.25%.

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A meteorite is found to contain two isotopes of element x, x-12, and x-14. Experimental analysis determined 95% of the element is isotope x-12, whereas 5% of the element is isotope x-14. What is the average atomic mass of element x?.

Answers

Considering the definition isotopes and atomic mass of an element, the average atomic mass of element x is 12.1

Definition of isotope

The same chemical element can have the same atomic numbers, but the number of neutrons is different. These atoms are called isotopes of the element.

Definition of atomic mass

The atomic masses of chemical elements are calculated as the weighted average of the masses of the different isotopes of each element, taking into account the relative abundance of each of them.

Atomic mass of the element in this case

In this case, you know:

Isotope x-12 is 95% abundant (the atomic mass is 12).Isotope x-14 is 5% abundant (the atomic mass is 14).

The average mass of the element x can be calculated as:

average mass of element x=12 amu×0.95 + 14 amu×0.05

average mass of element x= 12.1 amu

Finally, the atomic mass of the element x is 12.1.

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a pellet gun fires ten 3.0 g pellets per second with a speed of 400 m/s. the pellets are stopped by a rigid wall. what is the magnitude of the average force on the wall from the stream of pellets?

Answers

Answer:

Explanation
The speed of the block when it has moved a distance of 0.0150 m from it's initial position is 0.32 m/s .

When a spring is compressed by a force F, the potential energy is stored on it.
If the spring is released, the potential energy turns into kinetic energy.
The object is replaced by the call-back force which occurs on the spring F' = K.∆x
K= 815 N/m
∆x= 0.0190 m
F' = 815.0.019 = 15.8 N
Ff= k.m.g
Ff = 0.35 . 2.55. 9.81 = 8.76 N friction force acceleration of object is-
a= F' - Ff/m
V^2 = 2.a . displacement
V^2 = 2.264. 0.0200.
V^2 = 0.1056
V=√0.1056.
V= 0.32 m/s

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