The Cornell System for notetaking
a was developed by Dr. Walter Pauk at Cornell University.
b involves dividing your paper into three sections: Notes in the right-hand ccolumn; labels or possible questions for recall on the left-hand column; and a summary at the bottom.
c is easily done on a computer.
d provides a handy way to review and test yourself using your notes.
e All of the above.

Answer: 10,000

Explanation:

The result from the hypotheis test below shows that there is no significant evidence existing to show difference in the mutation.

The hypothesis for this test has been stated below:

H0: pI - pII = 0

Ha: pI - pII ≠ 0

n1 = 9

p1 = 0.6%

n2 = 12

p2 = 1%

Using the z statistics formula

[tex]\frac{0.006-0.01}{\sqrt{0.000663+0.000825} } \\\\\frac{-0.004}{\sqrt{0.001488} }[/tex]

z = -0.103

p value = z(-0.103) = 0.4589

The pvalue is greater that 0.01

The decision is to fail to reject the null hypothesis.

There is no significant evidence to show that there is a difference in the prevalence of mutation.

Read more on hypothesis testing here: https://brainly.com/question/15980493

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Decide on your essay type and topic. Sometimes, you will already have an assigned essay type or topic, so that will save you one step. ...

Brainstorm and research the topic you’ve chosen. Once you’ve chosen your topic, brainstorm all the different supporting ideas that you can talk about for the topic.

Develop your thesis statement. After you have brainstormed and researched, write down your thesis statement. ...

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Start writing. Using your outline, you can now begin writing your essay. Some writers choose to write their paragraphs in order, beginning with the hook.

The distribution of the trees in the landscape company is an illustration of probability

The distribution of the trees are:

Total = 8 + 13 + 14

Total = 35

The probability is then calculated as:

P(Same type) = P(All fruit trees) + P(All pine trees) + P(All maple trees)

So, we have:

P(Same type) = (8/35 * 7/34 * 6/33 * 5/32) + (13/35 * 12/34 * 11/33 * 10/32) + (14/35 * 13/34 * 12/33 * 11/32)

Evaluate

P(Same type) = 0.0341

Hence, the probability that all 4 winners will select the same type of tree is 0.0341

The probability is then calculated as:

P(3 pine and one maple) = 4 * P(Three maple and One Pine)

So, we have:

P(3 pine and one maple) = 4 * (13/35 * 12/34 * 11/33 * 13/32)

Evaluate

P(3 pine and one maple) = 0.0710

Hence, the probability that 3 pine trees will be selected and the other tree will be a maple is 0.0710

The probability is then calculated as:

P(2 pine and 2 maple) = 4 * P(Two pine and Two maple)

So, we have:

P(2 pine and 2 maple) = 4 * (13/35 * 12/34 * 14/33 * 13/32)

Evaluate

P(2 pine and 2 maple) = 0.0904

Hence, the probability that no fruit trees and 2 of each of the others will be selected is 0.0904

Read more about probability at:

https://brainly.com/question/251701