The bulletin board is in the shape of a square. Find two rational numbers that are within 1/8in. of the actual side length.

[tex]\bold{Heya!}[/tex]

[tex]\sf{= 10}[/tex]

Convert mixed numbers to imporved fractions: [tex]\sf{3 \frac{3}{4} = \frac{15}{4}[/tex]

[tex]\sf{= \frac{15}{4}[/tex] ÷ [tex]\sf{\frac{3}{8}[/tex]

Apply the fraction rule: [tex]\sf{\frac{a}{b}[/tex] ÷ [tex]\sf{\frac{c}{d} = \frac{a}{b} \: x \: \frac{d}c}[/tex]

[tex]\sf{= \frac{15}{4} \: x \: \frac{8}{3}[/tex]

Multiply fractions: [tex]\sf{\frac{a}{b} \: x \: \frac{c}{d} = \frac{a \: x \: c}{b \: x \: d}[/tex]

[tex]\sf{= \frac{15 \: x \: 8}{4 \: x \: 3}[/tex]

Multiply the numbers: [tex]\sf{ 4 \: x \: 3 = 12}[/tex]

[tex]\sf{= \frac{110}{12}[/tex]

Divide the numbers [tex]\sf{\frac{120}{12} = 10[/tex]

[tex]\sf{= 10}[/tex]

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[tex]\underline{Answer :}[/tex]

Jaceysan ~

Answer:

A.15.21

Step-by-step explanation:

In rounding of numbers when the next number is greater than 5 u round it on next number by adding one

Answer:

$6.3

Step-by-step explanation:

Original price = $18

Percentage Discount = 65%

Discount = 18*65% = 18*0.65 = $11.7

Sale Price = Original price - Discount

= $18 - $11.7

= $6.3

The statement that described the triangle properties is that the segment YZ and segment Y"Z" should be proportional when the dilation is done and it should be congruent when the translation should be done.

Given that,

Based on the above information,

Therefore we can conclude that option d is correct.

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Answer:

the first one

Step-by-step explanation:

Answer:

its 1/sqrt{5}+2

The characteristics of this scatter plot

Hence ,this scatter plot has Moderately postive linear relationship without any outliner

The perimeter of the flag Akihiro draws is the sum of the flag's side lengths

The perimeter of the flag Akihiro draws is 20 units

From the coordinate plane, the side lengths of the flag are:

6 units, 4 units, 6 units and 4 units

Add up the side lengths, to determine the perimeter (P)

P = 6 units + 4 units + 6 units + 4 units

Evaluate the sum

P = 20 units

Hence, the perimeter of the flag Akihiro draws is 20 units

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Answer:

20 units

Step-by-step explanation:

Answer:

69

Step-by-step explanation:

The formula for a circumference with the radius is C=2πr=2·π·11≈69.11504mi.

Answer:

C. Students in language arts classes.

Step-by-step explanation:

Because out of all of the options, this one seems like it is the best time that they could get the students attention and get an acurate response.

Answer:

y=2x+3

Step-by-step explanation:

Because the y-intercept starts at 3 and it goes up by 2 and to the side 1 so it would be y = 2x +3

Answer: y = 2x + 3

Step-by-step explanation:

    We will write the equation in slope-intercept form.

y = mx + b

    The slope can be found with "rise over run" since we have clear points on the graph.

    Start at (0, 3), count up 2 units, and count one unit to the right. This gives us a slope of positive 2.

    Rise / run = 2 / 1 = 2

    The "b" value is where the line hits the y-axis. It hits the y-axis at y-coordinate 3, so our y-intercept is positive 3.

    Final equation:

y = 2x + 3

Answer: A

Step-by-step explanation:

The radius of the circle is 7, and the center is at (6,-2), so if we substitute into the formula for the general equation of a circle, we get answer choice A.

Step-by-step explanation:

the third angle in a triangle= 70

Answer:

40

Step-by-step explanation:

10+10+10+10 = 40

A square has 4 sides which is why you add 10, 4 times.

Answer:

x = 30.9

Step-by-step explanation:

[tex]x = \frac{1}{2} (138 - 76.2) = \frac{1}{2} (61.8) = 30.9[/tex]

Answer:

12) x= 21

13) x = 1

14) x = 9

15) x = 1

Step-by-step explanation:

Here, we are being asked to solve the given equations and check our work.

To check the work, we need to substitute the found value of x into the equation to check if it makes a true and correct statement.

12) Solve for x:

[tex]\sf 12)\ \dfrac{2}{3}x + 2 = 16\ \textsf{[subtract 2 from both sides]}\\\\\implies \dfrac{2}{3}x + 2 - 2 = 16 - 2\\\\\implies \dfrac{2}{3}x = 14\ \textsf{[multiply both sides by 3]}\\\\\implies 3\left(\dfrac{2}{3}\right)x = 14(3)\\\\\implies 2x = 42\ \textsf{[divide both sides by 2]}\\\\\implies \dfrac{2x}{2}=\dfrac{42}{2}\\\\\implies \boxed{\sf x = 21}[/tex]

Check your work:

[tex]\sf \dfrac{2}{3}x + 2 = 16\ \textsf{[substitute 21 for the value of x]}\\\\\implies \dfrac{2}{3}(21) + 2 = 16\ \textsf{[multiply]}\\\\\implies \dfrac{42}{3} + 2 = 16\ \textsf{[divide]}\\\\\implies 14 + 2 = 16\ \textsf{[add]}\\\\\implies 16 = 16\ \checkmark \textsf{[true statement]}[/tex]

13) Solve for x:

[tex]\sf 13)\ \dfrac{x}{2} + \dfrac{x}{3} = \dfrac{5}{6}\ \textsf{[multiply both sides by 6 - LCM of 2, 3, and 6]}\\\\\implies 6\left(\dfrac{x}{2} + \dfrac{x}{3}\right) = 6\left(\dfrac{5}{6}\right)\ \textsf{[multiply]}\\\\\implies \left(\dfrac{6x}{2} + \dfrac{6x}{3}\right) = \dfrac{30}{6}\ \textsf{[divide]}\\\\\implies 3x+2x=5\ \textsf{[combine like terms]}\\\\\implies 5x = 5\ \textsf{[divide both sides by 5]}\\\\\implies \dfrac{5x}{5}=\dfrac{5}{5}\\\\\implies \boxed{\sf x = 1}[/tex]

Check your work:

[tex]\sf \dfrac{x}{2} + \dfrac{x}{3} = \dfrac{5}{6}\ \textsf{[substitute 1 for the value of x]}\\\\\implies \dfrac{1}{2} + \dfrac{1}{3} = \dfrac{5}{6}\ \textsf{[rewrite the fractions with a common denominator of 6]}\\\\\implies \dfrac{1\times3}{2\times3} + \dfrac{1\times2}{3\times2} = \dfrac{5}{6}\ \textsf{[multiply]}\\\\\implies \dfrac{3}{6} + \dfrac{2}{6} = \dfrac{5}{6}\ \textsf{[add]}\\\\\implies \dfrac{5}{6} = \dfrac{5}{6}\ \checkmark \ \textsf{[true statement]}[/tex]

14) Solve for x:

[tex]\sf 14)\ \dfrac{x-1}{6} - \dfrac{x+1}{8} = \dfrac{1}{12}\ \textsf{[multiply both sides by 24 - LCM of 6, 8, and 24]}\\\\\implies 24\left(\dfrac{x-1}{6} - \dfrac{x+1}{8}\right) = 24\left(\dfrac{1}{12}\right)\ \textsf{[multiply]}\\\\\implies \left(\dfrac{24x-24}{6}\right) - \left(\dfrac{24x+24}{8}\right) = \dfrac{24}{12}\ \textsf{[divide]}\\\\[/tex]

[tex]\sf\\\implies (4x-4)-(3x+3)=2\ \textsf{[distribute the negative sign]}\\\\\implies (4x-4)+(-3x-3)=2\ \textsf{[combine like terms]}\\\\\implies x - 7 = 2\ \textsf{[add 7 to both sides]}\\\\\implies x - 7 + 7 = 2 + 7\\\\\implies \boxed{\sf x = 9}[/tex]

Check your work:

[tex]\sf 14)\ \dfrac{x-1}{6} - \dfrac{x+1}{8} = \dfrac{1}{12}\ \textsf{[substitute 9 for the value of x]}\\\\\implies \dfrac{9-1}{6} - \dfrac{9+1}{8} = \dfrac{1}{12}\ \textsf{[simplify]}\\\\\implies \dfrac{8}{6} - \dfrac{10}{8} = \dfrac{1}{12}\ \textsf{[rewrite the fractions with a common denominator of 24]}\\\\\implies \dfrac{8\times4}{6\times4} - \dfrac{10\times3}{8\times3} = \dfrac{1\times2}{12\times2}\ \textsf{[simplify]}\\\\[/tex]

[tex]\sf\\\implies \dfrac{32}{24}-\dfrac{30}{24}=\dfrac{2}{24}\ \textsf{[subtract]}\\\\\implies \dfrac{2}{24}=\dfrac{2}{24}\ \textsf{[reduce]}\\\\\implies \dfrac{1}{12}=\dfrac{1}{12}\ \checkmark\ \textsf{[true statement]}[/tex]

15) Solve for x:

[tex]\sf \dfrac{1}{4}+\dfrac{x+1}{8}=\dfrac{1}{2}\ \textsf{[multiply both sides by 8 - LCM of 2, 4, and 8]}\\\\\implies 8\left(\dfrac{1}{4}+\dfrac{x+1}{8}\right)=8\left(\dfrac{1}{2}\right)\textsf{[multiply]}\\\\\implies \left(\dfrac{8}{4}+\dfrac{8x+8}{8}\right)=\dfrac{8}{2}\ \textsf{[divide]}\\\\\implies 2 + x + 1 = 4\ \textsf{[add]}\\\\\implies x + 3 = 4\ \textsf{[subtract 3 from both sides]}\\\\\implies x + 3 - 3 = 4 - 3\\\\\implies \boxed{\sf x = 1}[/tex]

Check your work:

[tex]\sf \dfrac{1}{4}+\dfrac{x+1}{8}=\dfrac{1}{2}\ \textsf{[substitute 1 for the value of x]}\\\\\implies \left(\dfrac{1}{4}+\dfrac{1+1}{8}\right)=\dfrac{1}{2}\ \textsf{[simplify]}\\\\\implies \left(\dfrac{1}{4}+\dfrac{2}{8}\right)=\dfrac{1}{2}\ \textsf{[reduce]}\\\\\implies \left(\dfrac{1}{4}+\dfrac{1}{4}\right)=\dfrac{1}{2}\ \textsf{[add]}\\\\\implies \dfrac{2}{4}=\dfrac{1}{2}\ \textsf{[reduce]}\\\\\implies \dfrac{1}{2}=\dfrac{1}{2}\ \checkmark\ \textsf{[true statement]}[/tex]

Step-by-step explanation:

y= (-2/3) x-6 is parallel to y= (-2/3)x +4 goes through the point (3,-8)

Answer:

10sr2 or 14.1421356

Step-by-step explanation:

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

if the triangle is an Isosceles triangle, then it's other two angles measure 45° each.

So, let's use Trigonometry here :

[tex]\qquad \sf  \dashrightarrow \: \cos(45) = \dfrac{10}{x} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \dfrac{1}{ \sqrt{2} } = \dfrac{10}{x} [/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 10 \sqrt{2} [/tex]

Therefore, the value of x is 10√2 units

Using the given exponential functions, it is found that the graph of g(x) will be less than than the graph of f(x) when x < 0.

The given exponential functions, f(x) and g(x), are respectively given by:

When x < 0, one possible value is x = -1, hence evaluating the functions at these values:

[tex]f(-1) = 3^{-1} = \frac{1}{3}[/tex]

[tex]g(-1) = 7^{-1} = \frac{1}{7}[/tex]

[tex]\frac{1}{3} > \frac{1}{7}[/tex], hence, the graph of g(x) will be less than than the graph of f(x) when x < 0.

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Answer:

if 5=70

  2=?

cross multiply=28

add  70+28=98          

Step-by-step explanation:

Answer:

x=6/5 and x=-(1/2)

Step-by-step explanation:

[tex]f(x) = 10x^3-37x^2+15x+18\\f(x) = \frac{(5x-6)(2x+1)(x-3)}{(x-3)}\\ f(x) = (5x-6)(2x+1)[/tex]

To find the zeros, we set f(x) = 0 for both factors

[tex]5x-6=0\\5x=6\\x=6/5[/tex]

[tex]2x+1=0\\2x=-1\\x=-1/2[/tex]

Therefore the zero's of f(x) are x = 6/5 and x= -(1/2)

Step-by-step explanation:

Q = msdt

or, 940 = m* 0.780* 15

or, 940 = 11.7m

or, 940/11.7 = m

m = 80.341

Therefore the mass of the metal is 80.341g.

Answer:

12.75

Step-by-step explanation:

12.75

Answer:

24 percent

Step-by-step explanation:

Answer:

79-22=57.

Your answer is correct. You also have to fill in the second one (B)

Answer:

79-22=57

Step-by-step explanation:

I can explain on phone

The last step to be carried out in a bid to construct an angle using a protractor is; Connect the endpoint and the mark at the angle measure.

In a bid to construct an angle by means of a protractor, it follows that a sequence of steps must be carried out. These steps are as ordered below;

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Answer: For the last step you have to connect the endpoint and the mark

Step-by-step explanation:

Answer:

11.5

Step-by-step explanation:

10 + a / 4    if a = 6

10 + 6 / 4

10 + 1.5

11.5

I hope this helps! Have a lovely day!! :)

Answer:

23/2 or 11.5

Step-by-step explanation:

Simplify 6/4 --> 3/2

Convert 10 into a fraction --> 20/2

20/2 + 3/2 = 23/2

Answer:

[tex]\implies x^2+y^2-4x -6y+9=0[/tex]

Step-by-step explanation:

Circle is touching y-axis at point (0, 3) and is centered at (2, 3)

-> h = 2, k = 3 & r = 2 units (If a circle touches y -axis then x coordinate of the center will be it's radius)

Equation of circle in standard form is given as:

[tex](x-h)^2 +(y-k)^2 =r^2[/tex]

Plugging the values of h, k and r in the above equation, we find:

[tex](x-2)^2 +(y-3)^2 =2^2[/tex]

[tex]\implies x^2-4x +4+y^2-6y+9=4[/tex]

[tex]\implies x^2+y^2-4x -6y+4+9=4[/tex]

[tex]\implies x^2+y^2-4x -6y+9=0[/tex]

This is the required equation of the circle.

Answer:

a, c, d

Step-by-step explanation:

This is because there share the same answer:

12x + 6

hope this helps =)

Answer:

18.83% (nearest hundredth)

Step-by-step explanation:

Continuous Compounding Formula

[tex]\sf A=P(e)^{rt}[/tex]

where:

Given:

Substituting given values into the formula:

[tex]\sf \implies 1300=420(e)^{6r}[/tex]

[tex]\sf \implies \dfrac{1300}{420}=e^{6r}[/tex]

[tex]\sf \implies e^{6r}=\dfrac{65}{21}[/tex]

Taking natural logs of both sides:

[tex]\sf \implies \ln e^{6r}=\ln \dfrac{65}{21}[/tex]

[tex]\sf \implies 6r\ln e=\ln \dfrac{65}{21}[/tex]

[tex]\sf \implies 6r(1)=\ln \dfrac{65}{21}[/tex]

[tex]\sf \implies 6r=\ln \dfrac{65}{21}[/tex]

[tex]\sf \implies r=\dfrac16 \ln \dfrac{65}{21}[/tex]

[tex]\sf \implies r=0.1883108054...[/tex]

Therefore, the interest rate is 18.83% (nearest hundredth)

A piecewise function is a function that's simply built from pieces of different functions over several intervals.

Your information is incomplete as the function isn't given. Therefore, an overview will be given. It should be noted that a piecewise function simply means a function that's defined by multiple sub functions.

In this case, each sub-function applies to different interval in the domain as it's way of expressing the function.

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