The area of a square poster 26 inch. 2. Find the length of one side of the poster to the nearest tenth of an inch.

Answer:

a= d-r +c

Step-by-step explanation:

a-c = d-r

+c

a= d-r +c

Solving for a gives the result as  a = d - r + c

A variable is something which can vary from a given set of numerical values.We can also substitute some specific values to  a variable.

A constant on the other hand is a fix value even if it is denoted by some letter it is a fixed numerical value that can not be changed.

According to the given question

a is the indicated variable.

Given a - c = d - r

               a = d - r + c

moving any constant or variable from one side to another changes the sign of the constant or the variable.

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Answer:

constants are 18, -4 and 28

coefficients are -5, 7

Step-by-step explanation:

constants are numbers not attached to variables

coefficients are numbers attached to variables

Answer:

a=90 b=90 c=90 d=148 e=32 f=148 g= 122 h=58 l=122

Step-by-step explanation:

a is supp. to 90 degrees, therefore it is 90 (180-90)=90.

b and c are vertical angles, therefore they are the same as the angle directly across from them

d is supp. to 32 degrees, therefore it is 148 (180-32)=148

e and f are vertical angles, therefore they are the same as the angle directly across from them

g is supp. to 58 degrees, therefore it is 122 (180-58)=122

h and l are vertical angles, therefore they are the same as the angle directly across from them

Answer:

ALLL OF THEM 12

Step-by-step explanation:

Answer:

4 months are 28 days

Step-by-step explanation:

Answer:

b

d

e

Step-by-step explanation:

the standar form is

[tex]ax^{2} +bx+c=0[/tex]

so it's

[tex]0.5x^{2} -3.2x+5.8=0\\\\-x^2-3x+20=0\\\\\frac{1}{2}x^2+4x-3=0\\\\[/tex]

only that

Answer:

15

Step-by-step explanation:

[tex](a+b)^{3}-12[/tex]

= [tex](2+1)^{3}-12[/tex]

= [tex](3)^{3}-12[/tex]

=(27)-12

=15

Equation:

3 x 5 = 15

15 cookies is the answer.

Sarah and her 4 friends are 5 people in total.

They are each getting 3 cookies.

You are adding three cookies for each friend. That is the same as multiplying 5 times.

Answer:

Step-by-step explanation:

c/5. = 3

5c = 3

c/4. = 3

4c = 3

Answer:

-4

Step-by-step explanation:

8+4y= -8

4y= -8 -8

4y= -16

divide both sides by the coeffient of the variable. in this case divide both sides by 4

y=-4

Answer:

y = -4

Step-by-step explanation:

8+4y= -8

4y = -8 -8

4y = -16

y = (-16) ÷ 4

y = -4

4x + 9 = 56

The value of x.

4x + 9 = 56

The value of 9 changes when we take 9 to the Right Hand Side, we get

4x = 56 - 9

Now, The value of 4 changes when we take 4 to the Right Hand Side, we get

x = 47/4

The value of x is 47/4

AR:AB = 1/5 means that AR has length equal to 1/5 of the length of AB.

To find the x coordinate of R, you take 4/5 of the x coordinate of A plus 1/5 of the x coordinate of B:

4/5 * 1 + 1/5 * 4 = 8/5

You do the same for the y coordinate:

4/5 * (-1) + 1/5 * 4 = 0

So the point R has coordinates (8/5, 0).

Answer:

The common ratio is 5

Step-by-step explanation:

We know this because the first term times 5 equals the second term and the second term times five equals the third term and so forth.

Answer:

e 125x

f 125 x 12 =150

Step-by-step explanation:

Answer:

The probability would be 30/52

Step-by-step explanation:

if there is 52 cards in a deck, there is 26 red card, plus 4 queens equals 30

Answer:

The answer is D

Step-by-step explanation:

The only logical explanation

Equation of the graphed line passing through the points (0, - 4) and (2, 2) is equals to  [tex]y = 3x - 4[/tex].

" Coordinate plane is defined as the two dimensional plane formed by number line named x-axis and y-axis."

Formula used

Standard equation of the line

[tex]\frac{y-y_{1} }{x-x_{1} } =\frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex]

According to the question,

Points passing through coordinate plane,

[tex](x_{1} ,y_{1} ) = (0,-4)\\\\(x_{2} ,y_{2} ) = (2,2)[/tex]

Substitute the coordinates in the formula to get the equation of line ,

   [tex]\frac{y-(-4) }{x-0 } =\frac{2-(-4) }{2-0}[/tex]

⇒ [tex]\frac{y+4 }{x } =\frac{6 }{2}[/tex]

⇒[tex]y + 4= 3x[/tex]

⇒[tex]y=3x-4[/tex]

Hence, the equation of the line is [tex]y=3x-4[/tex].

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Answer:

D. -12

Step-by-step explanation:

if f=4x-9, and g=2x-3, and the value is (f+g), then we have to add the equations. This is equal to 6x-12. And then, in '(f+g)(0)', it is asking what is the y-value at x=0. Plug in 0 into the equation, and the y-value equals -12.

Answer:

(s+2)^3

Step-by-step explanation:

I think this is referring to a square as a box, so the length of a jewelry box would be s. We learn that a shipping box is 2 inches longer, so s+2 = the length of the shipping box.

Volume = Length*Width*Height, but if square, all dimensions are the same, so s+2 to the power of 3 would be your answer.

Answer:answer (s+2)^3

Step-by-step explanation: ( I did it on iready

Answer:

-9x-14

Step-by-step explanation:

Answer:

10 , 30 , 3

Step-by-step explanation:

Your radius: 10 is the greatest

The circumference is 30 that came from 10 x 3( diameter x radius)

and the diameter is 3 which is the smallest

Answer:

in went down 6 floors.

Step-by-step explanation:

9-6=3 so that's how I found the answer.

Answer:

B

Step-by-step explanation:

[tex]6^{\frac{1}{4} } b^{\frac{3}{4} }c^{\frac{1}{4} }\\\\=(6^1b^3c^1)^{\frac{1}{4} }\\\\=(6b^3c)^\frac{1}{4} \\\\=\sqrt[4]{6b^3c}[/tex]

so answer is B

 [tex]6^{\frac{1}{4} }b^{\frac{3}{4} }c^{\frac{1}{4} }[/tex] expressed as a radical is d. [tex]\sqrt[4]{(6b^{3}c )}[/tex]

To answer the question, we need to know what radicals are.

Radicals are roots of numbers. They are written in the form [tex]\sqrt[n]{x}[/tex] where n is the nth root of x.

Now given that we want to express [tex]6^{\frac{1}{4} }b^{\frac{3}{4} }c^{\frac{1}{4} }[/tex] as a radical, we having using the laws of indices

[tex]6^{\frac{1}{4} }b^{\frac{3}{4} }c^{\frac{1}{4} } = (6b^{3}c )^{\frac{1}{4} } \\6^{\frac{1}{4} }b^{\frac{3}{4} }c^{\frac{1}{4} }= \sqrt[4]{(6b^{3}c )}[/tex]

Thus, we have expressed it as a radical.

So,  [tex]6^{\frac{1}{4} }b^{\frac{3}{4} }c^{\frac{1}{4} }[/tex] expressed as a radical is d. [tex]\sqrt[4]{(6b^{3}c )}[/tex]

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Answer:

12/200

Step by Step:

Answer:

To find the 1st term, put n = 1 into the formula, to find the 4th term, replace the n's by 4's: 4th term = 2 × 4 = 8. Example.

Step-by-step explanation:

Hope this helps

Answer:

x=-2

Step-by-step explanation:

[tex]6=x-(-8)\\\\6=x+8\\\\6-8=x+8-8\\\\-2=x[/tex]

Answer:

- 2

Step-by-step explanation:

Step 1:

x - ( - 8) = 6

Step 2:

x + 8 = 6

Step 3:

x = 6 - 8

Answer:

x = - 2

Hope This Helps :)

Answer:

[tex]n^{2}(-3) -8[/tex]

Step-by-step explanation:

So the "product of" means the answer to a multiplication problem. That means -3 is being multiplied by a number which is squared. I used the variable "n" for number but you could use any letter you want.

This is what we have so far,

[tex]n^{2} \\[/tex] x -3 or [tex]n^{2}[/tex](-3)

The term decreased means to reduce or subtract. Which means we are left with....

[tex]n^{2}(-3) -8[/tex]

Hope that helps and have a great day!

"R" is the distance from the origin to the point.

R = √(-3² + 7²)

R = √(9 + 49)

R =  √(58)

R = 7.62

tangent (Θ)  =  7 / -3

Θ  =  arctan (7 / -3)

Θ  =  113.2°  counterclockwise from the x-axis

Answer:

-12.25

Step-by-step explanation:

Let's investigate what happens when negative values appear under the radical symbol (as the radicand) for cube roots and square roots.

In some situations, negative numbers under a radical symbol are OK. For example, radnegnew14is not a problem since (-2) • (-2) • (-2) = -8, making the answer -2. In cube root problems, it is possible to multiply a negative value times itself three times and get a negative answer.

Difficulties, however, develop when we look at a problem such as radnegnew214. This square root problem is asking for a number multiplied times itself that will give a product (answer) of -16. There simply is no way to multiply a number times itself and get a negative result. Consider: (4) • (4) = 16 and (-4) • (-4) = 16.

CUBE ROOTS:

radnn1

BUT

SQUARE ROOTS:

n2

Yes, (-2) x (-2) x (-2) = -8.

No problem.

Nope!   (4) x (4) ≠ -16.

Nope!   (-4) x (-4) ≠ -16.

bullet Square roots are the culprits! The difficulties arise when you encounter a negative value under a square root. It is not possible to square a value (multiply it times itself) and arrive at a negative value. So, what do we do?

statement

The square root of a negative number does not exist among the set of Real Numbers.

When problems with negatives under a square root first appeared, mathematicians thought that a solution did not exist. They saw equations such as x2 + 1 = 0, and wondered what the solution n3 really meant.

In an effort to address this problem, mathematicians "created" a new number, i, which was referred to as an "imaginary number", since it was not in the set of "Real Numbers". This new number was viewed with much skepticism. The imaginary number first appeared in print in the year 1545.

def The imaginary number "i" is the square root of negative one.

neg i

An imaginary number possesses the unique property that when squared, the result is negative.

irad1

Consider: irad2a

The process of simplifying a radical containing a negative factor is the same as normal radical simplification. The only difference is that the irad4 will be replaced with an "i ".

As research with imaginary numbers continued, it was discovered that they actually filled a gap in mathematics and served a useful purpose. Imaginary numbers are essential to the study of sciences such as electricity, quantum mechanics, vibration analysis, and cartography.

When the imaginary i was combined with the set of Real Numbers, the all encompassing set of Complex Numbers was formed.

Answer:

Step-by-step explanation:

[tex]8c-4-2c+5\\\\\mathrm{Group\:like\:terms}\\=8c-2c-4+5\\\\\mathrm{Add\:similar\:elements:}\:8c-2c=6c\\=6c-4+5\\\\\mathrm{Add/Subtract\:the\:numbers:}\:-4+5=1\\=6c+1[/tex]