We observe the Andromeda galaxy as it was 2.5 million years ago since it is around 2.5 million light years away.
We observe the Andromeda galaxy as it was 2.5 million years ago since it is around 2.5 million light years away. The Andromeda galaxy's light was first visible 2.5 million years ago. The Andromeda galaxy may have gotten a few thousand light years nearer to us during those 2.5 million years. While the diameter of the Andromeda galaxy itself is roughly 200 thousand light years, the uncertainty in the 2.5 million light year distance estimate is on the order of 100 thousand light years (simply because estimating the distance to other galaxies is difficult).
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a 2.0-mm-diameter glass bead is positively charged. the potential difference between a point 2.0 mm from the bead and a point 4.0 mm from the bead is 500 v. what is the charge on the bead?
The glass bead has a 0.001 m radius. The distance between the first and second points from the bead's center is 0.003 and 0.005 meters, respectively.
How big is a circle's radius?The radius of a circular is the distance a circle's center from any point along its perimeter. Usually, "R" or "r" is used to indicate it.
In geometry, what is a radius?A radius is indeed a line segment that has one endpoint in the circle's center and the other terminus on the circumference of the circle. Circle's diameter equals the radius The diameter of a circle is a line segment that has its ends on the circle and passes through its center. Radius x 2 equals the diameter.
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a) Two tugboats are towing a tanker of mass 3.30 x 107 kg. If one tug is pulling at 2.40 X 104 N [E16°N] and the other is pulling at 2.40 x 104 N [E9°S], calculate the acceleration of the tanker, assuming no resistance. Use both vector methods to solve this part of the problem.
b) If the tanker has a resistive force on it of 5.60 x 10³ N, find its acceleration using the component method.
c) Calculate the speed reached in each of the two cases after 2.0 minutes. Convert it to km/h.
d) Calculate the distance required in each case to reach a speed of 5.0 km/h.
So the net force acting on the tanker is: F_net = sqrt(Fx^2 + Fy^2) = 2.4 x 10^4 N And the acceleration of the tanker is: a = F_net / m = 2.4 x 10^4 N / 3.3 x 10^7 kg = 7.27 x 10^-4 m/s^2.
How to calculate net force and acceleration?
To find the acceleration of the tanker using vector methods, we can use the following equation:
F_net = ma
where F_net is the net force acting on the tanker, m is the mass of the tanker, and a is the acceleration of the tanker.
In this case, the two tugboats are pulling in opposite directions, so we need to find the vector sum of their forces to find the net force acting on the tanker.
Using the component method, we can find that the x-component of the net force is:
Fx = 2.4 x 10^4 N * cos(16) - 2.4 x 10^4 N * cos(9) = -2.4 x 10^4 N
and the y-component of the net force is:
Fy = 2.4 x 10^4 N * sin(16) + 2.4 x 10^4 N * sin(9) = 0 N
So the net force acting on the tanker is:
F_net = sqrt(Fx^2 + Fy^2) = 2.4 x 10^4 N
And the acceleration of the tanker is:
a = F_net / m = 2.4 x 10^4 N / 3.3 x 10^7 kg = 7.27 x 10^-4 m/s^2
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a body at temperature of 100f is placed in a room of temperature 50. the room temperature does not change appreciably. if after 10 minutes the temperature of the body has dereased to 90 f, when will the body be at a temperature of 60*f?
The body will be at a temperature of 60°F after around 72 minutes.
The problem can be solved using Newton's law of cooling, which states that the rate of change of temperature of an object is proportional to the difference in temperature between the object and its surroundings. Mathematically, this can be represented as:
T(t) = T_s + (T₀ - T_s) e^(-kt)
where T(t) is the temperature of the object after time t, T₀ is the initial temperature of the object, T_s is the temperature of the surroundings, t is time and k is a constant of proportionality called the cooling coefficient.
Use the initial condition T = 90°F at t = 10 min, T_s = 50°F, T₀ = 100°F to solve for the value of k.
T(t) = T_s + (T₀ - T_s) e^(-kt)
90°F = 50°F + (100°F - 50°F) e^(-k)(10)
40°F = 50°F e^(-k)(10)
e^-10k = 0.8
k = 0.0223
thus we can calculate the time it takes for the body to reach a temperature of 60°F:
T(t) = T_s + (T₀ - T_s) e^(-kt)
60°F = 50°F + (100°F - 50°F) e^(-0.0223)(t)
10°F = 50°F e^(-0.0223)(t)
e^(-0.0223)(t) = 0.2
t = 72.1721
t ≅ 72 minutes
Therefore, it would take around 72 minutes for the body to reach a temperature of 60*F.
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a point charge of 8.74 x 10-6 c is at the origin while a second point charge of -5.91 x 10-6 c is at the coordinates (0.53, 0.41) meters. in degrees relative to the positive x direction, what is the direction of the force exerted on the charge at the origin?
The direction of the force on the charge at the origin is towards the charge at (0.53, 0.41) m, since the charges have opposite signs and attract each other.
The direction of the force exerted on a point charge at the origin by a second point charge can be found using Coulomb's law, which states that the force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them. The formula for the force is:
F = k * q1 * q2 / r^2
where k is the Coulomb constant (8.99 x 10^9 N * m^2 / C^2), q1 and
q2 are the charges, and
r is the distance between the charges.
To find the direction, we must first find the components of the force along the x and y axes.
Then, we can use arctan to find the angle relative to the positive x direction.
The distance between the charges can be found using the Pythagorean theorem:
[tex]r = \sqrt{((0.53 m)^2 + (0.41 m)^2)[/tex] = 0.65 m
The x and y components of the force can then be found using the formula:
Fx = F * cos(θ) = k * q1 * q2 * x / r^3
Fy = F * sin(θ) = k * q1 * q2 * y / r^3
where θ is the angle between the force and the positive x direction, and x and y are the x and y components of the displacement vector between the charges, respectively.
Finally, the direction of the force can be found using arctan:
θ = arctan(Fy / Fx)
The direction of the force on the charge at the origin is towards the charge at (0.53, 0.41) m,
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7. Inferring Suppose you plot the distance
traveled by an object at various times and
you discover that the graph is not a straight
line. What does this indicate about the
object's acceleration?
When the graph of distance travelled with time is not straight, it implies that the acceleration is constant.
What is the acceleration of an object?The acceleration of an object is the rate of change of velocity with time.
Mathematically, the formula for the acceleration of an object is given as;
a = Δv / Δt
where;
Δv is the change in velocity of the objectΔt is the change in time of motionThe slope of velocity time graph is acceleration. This implies that acceleration increases with increase in velocity of an object.
However, if the graph of the distance travelled by an object with time is straight, it implies that the velocity is not uniform.
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medical x-rays have a wavelength of 0.052 nm. calculate the frequency of light, in hz (1/s), that this wavelength corresponds to?
The frequency of the light is 5.77 × 10¹⁸ Hz, if the wavelength of the x-rays is 0.052 nm.
Wavelength of the x-ray, λ = 0.052 nm = 5.2 × 10⁻¹¹ m.
Speed of x-rays, v = 3 × 10⁸ m/s
Let the frequency of the x-ray, = n
We know the relationship between speed of the wave, wavelength and the frequency of the wave is as follows:
speed = wavelength × frequency
3 × 10⁸ = 5.2 × 10⁻¹¹ × n
n = (3 × 10⁸)/(5.2 × 10⁻¹¹)
n = 5.77 × 10¹⁸ Hz
Alternate unit of frequency is 1/sec.
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what are tiny solid and liquid particles of matter suspended in the atmosphere?
Answer:
I think the answer you're looking for is particulate matter.
Explanation:
An aircraft decelerate at 0.5 m/.after 8 minute it velocity ha dropped to 160 m/ .find it initial velocity.
Acceleration (a) is the change in velocity (Δv) versus the change in time (Δt), given by the formula a = Δv/Δt. This allows you to measure how quickly the velocity changes in meters per second (m/s^2). Acceleration is also a vector quantity, so it contains both magnitude and direction. Negative acceleration is termed as deceleration
Deceleration can be calculated by dividing the final velocity minus the initial velocity by the time it takes for this velocity to drop.
The known and unknown quantities from the question are as follows:
u = initial velocity = ? m/s
v = final velocity = 160 m/s
a = acceleration = -0.5 m/s²
t = time interval = 8 min × 60 s/1 min = 480 s
Calculate the initial velocity using the following kinematic equation.
v = u + at
Solve for u.
u = v - at
u = 160 m/s - (-0.5 m/s² × 480 s) = 400 m/s
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what is the magnitude and direction of the electric force on an electron ina uniform electric field of strenght 2360n/c that points due east
The magnitude of the electric force on the electron is 2360 N and it points due east.
What is electric force?Electric force is an attractive or repulsive force between two particles that have an electric charge. This force is generated when two charged particles interact due to their charges. The strength of the electric force depends on how much charge each particle has, as well as their distance from each other. Electric forces are responsible for phenomena such as static electricity and lightning, and they can also be used to power electric motors and other devices.
This is because an electric field exerts a force on a charged particle in the direction that is opposite to the direction of the field. Since the electric field points due east, then the force on the electron will point due west.
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1. A quarterback passes a football at a velocity of 15.2 m/s at an angle of 40° to the horizontal
toward an intended receiver 27.4 m downfield. The pass is released 1.3 m above the ground. Assume
that the receiver is stationary. Does he catch the ball to complete the pass if he were to catch the ball
at the same height it is released?
The intended receiver did not receive the ball since the ball travelled a shorter distance.
What is the time of motion of the ball?
The time of motion of the ball is calculated by applying the following formula as shown below.
h = vt + ¹/₂gt²
where;
v is the velocity of the ballg is the acceleration due to gravityt is the time of motion1.3 = ( 15.2 x sin40 )t + ¹/₂ ( 9.8 )(t²)
1.3 = 9.8t + 4.9t²
4.9t² + 9.8t - 1.3 = 0
solve the quadratic equation suing formula method;
t = 0.13 second
The horizontal distance of the ball is calculated as;
d = Vₓt
d = ( 15.2 x cos 40) x 0.13
d = 1.51 m
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asportscar, electro-fiasco i, can accelerate uniformly to 100 km/h in 3.5 s. its maximum braking rate can not exceed 0.7g. what is the minimum time required to go 1.0 km, assuming it begins and ends at rest?
The minimum time required to travel 1.0 km is 8.75 seconds.
What is travel?Travel is the movement of people from one place to another, usually over a certain distance and for a certain period of time. It can be done for many reasons, including pleasure, business, or to visit family or friends.
This can be calculated by taking the total distance traveled (1.0 km) and dividing it by the average speed (100 km/h). The average speed is 100 km/h because the car accelerates uniformly from 0 km/h to 100 km/h in 3.5 seconds.
Therefore, the total time required is 10 seconds (1 km / 100 km/h). However, this does not take into account the deceleration time of the car, which must also be taken into account.
The maximum braking rate of the car is 0.7 g, which is equivalent to 7 m/s2. Since the car must come to a complete stop at the end of the 1.0 km journey, the time required for deceleration must be calculated. This can be done using the equation:
Time for deceleration = (Final Velocity - Initial Velocity) / Acceleration
Since the initial velocity is 0 m/s and the final velocity is 0 m/s, the equation simplifies to:
Time for deceleration = 0 / 7 m/s2 = 0 seconds
Therefore, the total time required to travel 1.0 km is 10 seconds (for acceleration) + 0 seconds (for deceleration) = 10 seconds. Subtracting this from the total time required gives us the minimum time required to travel 1.0 km, which is 8.75 seconds.
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a skier starts from rest on the higher peak. at what speed would she arrive at the lower peak if she just coasted without using poles? assume there is no friction.
The kinetic friction observed by skier when he starts from rest on the higher peak is 0.0.0313.
Here is the information we need:
h1 denotes the starting height (850 m)
The final height is given by h2 (750 m)
is the inclination angle (30°)
k is the kinetic friction coefficient.
The total distance traveled is given by d.
The distance traveled downward is denoted by d1.
The distance traveled uphill is denoted by d2.
Where:
d=d1 + d2 =h1/sin + h2/sin =850/sin30+750/sin30
=3200 m
Because the skier begins and ends at rest, the change in kinetic energy is zero.
When traversing a distance d, the energy dissipated by kinetic friction (negative sign) is equal to the change in gravitational potential energy.
[h2-h1]k =h1-h2d
=850-750/3200
=0.0313
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Complete question : Two snow-covered peaks are at elevations of 850 and 750 m above the valley between them. Both elevations have an incline of 30 degrees. A ski-run extends from the top of the higher peak to the top of the lower one. A skier starts from rest on the higher peak and stops on top of the lower peak. What is the kinetic friction coefficient?
if dust deosnt have an intitial charge , then how can a charged object(such as a piece of paper) attract bits of dust, since coulombs law states tgat two different charges are needed for an attractive force?
Dust particles can acquire a charge through a process called triboelectrification, which occurs when two materials rub against each other, transferring electrons from one material to the other.
What is triboelectrification?Triboelectrification is the phenomenon in which a charge is generated through the contact and separation of two materials. It is also known as "friction electrification" or "contact electrification".
When dust particles rub against a piece of paper, transferring electrons from the dust particles to the paper and giving the dust particles a negative charge. Once the dust particles have acquired a charge, they can be attracted to a charged object, such as a piece of paper, through Coulomb's law, which states that objects with opposite charges will experience an attractive force.
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what is the process of splitting a uranium atom called?
a. Nuclear Fusion
b. Nuclear Fission
c. Nuclear Confusion
d. Nuclear Dillusion
Nuclear fission produces energy when atoms split apart. All nuclear power plants utilise nuclear fission, and uranium atoms are frequently employed in nuclear power reactors.
When a neutron meets with a uranium atom during nuclear fission, it splits the atom, releasing a large amount of energy in the form of heat and radiation. Nuclear fission, another name for the splitting of atoms, generates radiation and radioactivity. In 1939, Dr. Lise Meitner made the discovery of how radioactivity may be created. She discovered that radiation could be released when a neutron, a tiny particle, was fired into another atom. Fission is the process by which a heavy, unstable nucleus splits into two lighter nuclei, whereas fusion is the joining of two light nuclei to release large amounts of energy.
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Two people push on a shopping cart from opposite sides. In which situation
will the motion of the shopping cart stay the same?
A. The two people push with different amounts of force.
B. One of the people stops applying a force.
C. One of the people applies twice as much force.
D. The two people push with a balanced
face
Two people push on a shopping cart from opposite sides. Situation will the motion of the shopping cart stay the same, the correct option is (D) The two people push with a balanced face.
In this situation, the net force on the shopping cart will be zero, since the two forces are equal in magnitude and opposite in direction. If the forces are balanced, the shopping cart will not accelerate and will stay in the same state of motion (at rest or moving at a constant velocity). In scenario A and C, the forces are not balanced and therefore will cause acceleration. In scenario B, the net force will be non-zero and the acceleration will cause the shopping cart to change its velocity and direction.
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a baseball player feels a frictional force of 400N as she slides into home. what impulse would be created?
The impulse that would be created by the baseball player is 600 Ns.
What is the impulse created by the baseball player?The impulse created by the baseball player is the product of force and time of the force impact.
J = Ft
where;
F is the applied forcet is the time of force actionThe frictional force created by the baseball player = 400 N.
The time of force action = 1.5 seconds
The impulse that would be created by the baseball player is calculated as follows;
J = 400 N x 1.5 seconds
J = 600 Ns
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The complete question is below:
A baseball player feels a frictional force of 400N as she slides into home. what impulse would be created if the force acted for 1.5 seconds?
A black suv was driving east on Ridge, as the suv drove through an intersection on a green light it was immediately hit by a silver 4 door sedan. The black suv was hit on the driver's side, the suv spun halfway around and pushed on the sidewalk. Explain why the suv gets pushed and jumps the crib
Answer:
The black suv gets pushed and jumps the curb because of the momentum the silver sedan had during impact.
Explanation:
Because the silver sedan ran the light and hit the black suv at full speed, the momentum from the sedan will have enough force to push the black suv into the curb.
Suppose that Ben Pumpiniron elevates his 80-kg body up the 2.0-meter stairwell in 1.8
seconds. Calculate Ben's power.
Ben's power is 871W
What is the short definition of power?
Power can be defined as the amount of work completed in a given amount of time. Watt (W), which is derived from joules per second (J/s), is the SI unit of power. Horsepower, or roughly 745.7 watts, is a unit of measurement used to describe the power of machinery and motor vehicles.
We could determine Ben's power rating if this were the case. Ben must presumably push down on the stairs with an 800-Newton force in order to raise his body. Ben's body would be pushed upward by the stairs in this way with just enough force to raise him up the stairs. Ben's power rating might be calculated using these two estimations, as illustrated below.
Power = work done / time
Power = 784*2/ 1.8
P= 871W
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your friend, who is in a field 70 meters away from you, kicks a ball towards you with an initial velocity of 18 m/s. assuming the grass causes the ball to decelerate at a constant rate of 1.0 m/s2, how long does it take for the ball to reach you?
With the use of formula, the time taken for the ball to reach you is 31.6 s
What is Acceleration ?Acceleration can be defined as velocity change per time taken. It is a vector quantity.
Given that your friend, who is in a field 70 meters away from you, kicks a ball towards you with an initial velocity of 18 m/s. assuming the grass causes the ball to decelerate at a constant rate of 1.0 m/s2, to know how long it takes for the ball to reach you, we will use the formula
s = ut - 1/2at² where
v = 0
u = 18 m/s
a = 1 m/s²
s = 70 m
t = ?
70 = 18t - 1/2 × 1 × t²
70 = 18t - 0.5t²
Multiply all by 2
140 = 36t - t²
t² - 36t + 140 = 0
Using completing the square method
t² - 36t + 18² = 18² - 140
( t - 18 )² = 324 - 140
( t - 18 )² = 184
t - 18 = √184
t = 18 + 13.6 or 18 - 13.6
t = 31.6 s or 3.4 s
Therefore, the ball will reach you in the next 31.6 s
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A small car (1400 kg) moving 35 m/s gradually comes to a complete
stop when the brakes are applied. It comes to a complete stop over a
period of 15.2 seconds. What is the force in newtons that is exerted
on the car during this time? (Remember, the force is negative
because it is exerted opposite to the motion).
The force in newtons that is exerted on a car during the given time is 3,223.68N.
How to calculate force?Force refers to a physical quantity that denotes ability to push, pull, twist or accelerate a body.
The force exerted on an object can be calculated by multiplying the mass of the body by the acceleration as follows:
Force = mass × acceleration
Force = mass × speed/time
According to this question, a small car (1400 kg) moving 35 m/s gradually comes to a complete stop when the brakes are applied. It comes to a complete stop over a period of 15.2 seconds.
Force = 1400 × 35/15.2
Force = 3,223.68N
Therefore, 3,223.68N is the force acting on the small car.
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note that in this arrangement, the net charge is zero (so we expect no monopolar field far away). the two visible dipoles also cancel, so we expect no dipolar field far away. what might we call the first surviving term in the distant field?
The first surviving term in the distant field in this situation might be referred to as a quadrupolar field.
The Distant Field SituationThe determination that the first surviving term in the distant field is a quadrupolar field is based on the fact that the net charge and the visible dipoles in the arrangement cancel out, leaving no monopolar or dipolar fields.
A quadrupole is a distribution of charges in which there are two positive and two negative charges of equal magnitude and opposite sign, arranged symmetrically about a central point.
A quadrupole generates a quadrupolar field, which falls off as the inverse cube of the distance from the source, as opposed to the inverse square of the distance for a dipole.
So when a net charge and dipoles are cancelled, the next term that could survive is the quadrupolar term.
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a quartz crystal vibrates with a frequency of 77,621 hz. what is the period of the crystal's motion?
Formula for period:
[tex]T=\dfrac{1}{f}[/tex]
period(measured in seconds) = 1 / frequency(measured in hertz)
__________________________________________________________
Given:
[tex]f=77,621Hz[/tex]
[tex]T=?[/tex]
__________________________________________________________
Finding period:
[tex]T=\dfrac{1}{f}[/tex]
[tex]T=\dfrac{1}{77,621}[/tex]
__________________________________________________________
Answer:
[tex]\fbox{T = 0.0000129}[/tex]
1. A student is sitting on the edge of a swimming pool. The student repeatedly dips his foot in and out of the pool, making waves that move across the water. The student dips his foot slowly at first and then does it faster, each time to the same depth. Which of the following properties of the waves increases as the student dips his foot faster?
A. frequency
B. period
C. velocity
D. wavelength
Frequency of the waves increases as the student dips his foot faster.
What is frequency?
Frequency is a measure of how often something occurs over a given period of time. It can be used to measure the rate of events, such as the number of times a sound or light wave occurs in a given second. Frequency is measured in hertz (Hz), which is the number of occurrences per second. Frequency can also refer to the number of times a certain event occurs in a given sample size, such as the number of times a person visits a website in a month. It is a common measure used in statistics and is often used to compare data sets.
Therefore, Frequency of the waves increases as the student dips his foot faster.
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while in horizontal flight at a speed of 20 m/s, a baseball of mass 0.11 kg is struck by a bat. after leaving the bat, the baseball has a speed of 29 m/s in a direction opposite to its original direction. the magnitude of the impulse given the ball is
The baseball's change in momentum is equal to the impulse applied to it. An object's momentum is determined by multiplying its mass by its velocity. The baseball received an impulse with a magnitude of -5.39 kg*m/s.
The baseball's change in momentum is equal to the impulse applied to it. An object's momentum is determined by multiplying its mass by its velocity.
The baseball's initial momentum is equal to 0.11 kg times 20 m/s, or 2.2 kg/s.
The baseball's ultimate velocity is calculated as (0.11 kilogramme) * (-29 m/s) = -3.19 kgm/s.
The difference between the baseball's final and starting velocities, or its change in momentum, is equal to 5.39 kg*m/s (final momentum - beginning velocities = -3.19 kgm/s - 2.2 kgm/s).
As a result, the baseball received an impulse with a magnitude of -5.39 kg*m/s.
Due to the ultimate velocity being in the opposite direction of the original vector, the impulse is negative.
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A skydiver is falling through the air because his:____. question 7 options: a. weight is over 100 n b. weight force down is greater than the air drag c. drag force needs to be at least 50 n because nothing can stop gravity from making an object fall
The correct option is B. weight force down is greater than the air drag.
What is weight force?Weight force is the force of gravity acting on a body or object. It is the magnitude of the force of gravity acting on an object or body and is determined by the object or body's mass multiplied by the acceleration due to gravity. Weight force is a type of force, and is a vector quantity which has both magnitude and direction. Weight force acts in the downward direction of the Earth's gravitational field and its direction is always towards the center of the Earth. Weight force is important in determining the motion of objects and bodies, and is one of the most important fundamental forces in physics.
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The spring-held follower AB has a mass of 0. 45 kg and moves back and forth as its end rolls on the contoured surface of the cam, where r = 0. 15 m and z=(0. 02cos2θ)m. The cam is rotating at a constant rate of 30 rad/s. The spring is uncompressed when θ = 90∘
The body and through a specific angle experience angular accelerations of 0.87266 rad/sec2 and 12566.8 rad, respectively.
Calculate angular acceleration ?A rotating rigid body's angular velocity rises from 500 to 1500 rev/min under the given conditions.
Time= 120s
Finding - Angle and angular acceleration
The basic idea is that we must change rev/min to rad/sec.
ωf= ωi + αt
ωf- ωi = αt
Formula for angular acceleration: = [f- i]/t
Angle deviation formula: =it + t2/2
Calculations-
Rev/Min to rad/Sec conversion
I equals 500 rev/min
500 x 2 rad/rev x 1 minute and 60 seconds equals 52.3598 rad/sec.
f = 1500 rev/min
=1500 x 2 rad/rev x 1 minute and 60 seconds = 157.079 rad/sec
52.3598 rad/sec for I
ωf=157.079rad/sec
Now, to calculate angular acceleration, use the formula: [f- i]/t.
52.3598 rad/sec − 157.079 rad/sec = 120
1.872666 rad/sec
To calculate the angle deviated, enter -=i t + t2/2.
=52.3598 x 120 + [0.87266 x 120 x120]/2
ΔФ= 12566.8rad
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why (if you are careful) are you able to float a needle on the surface of water?water has adhesive properties.
Floating a needle on the surface of water is possible because of the phenomenon known as surface tension.
Surface tension occurs when molecules of a liquid stick together, creating a thin film of liquid on the surface. This film is able to support objects that are light enough to float.
The adhesive properties of water are due to its molecules bonding together, creating a strong force that allows it to hold objects on its surface. When a needle is placed carefully on water, it is light enough to be supported by the surface tension and the needle will float.
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A 60 kilogram person jumps off a platform, landing while moving at 2. 0 meters per second. Determine the force exerted on the persons feet when he lands if he stops in 0. 25 seconds
The force exerted on the person's feet when he lands if he stops in 0. 25 seconds is found to be 480 N.
What is Force?Force may be characterized as a type of circumstance that significantly deals with the pushing or pulling of an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects.
According to the context of this question,
The mass of a person, m = 60 Kg.
The velocity of a person, v = 2.0 meters/sec.
The time is taken, t = 025 seconds.
The formula for calculating force is as follows:
F = mv/t.= 60 × 2 ÷ 0.25 = 480 N.
Therefore, the force exerted on the person's feet when he lands if he stops in 0. 25 seconds is found to be 480 N.
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A simple pendulum and a mass hanging on a spring both have a period of 1$ when set into small oscillatory
motion on Earth. They are taken to Planet X, which has a larger acceleration due to gravity. Which of the
following statements is true about the periods of the two objects on Planet X compared to their periods on Earth
a. Both are shorter
b. Both are the same
e. Both are longer
d. The period pf the mass on the spring is shorter, that of the pendulum is the same
e. The period of the pendulum is shorter, that of the mass on the spring is the same,
The pendulum's period is shorter, but the mass on the spring's is unchanged. A planet with twice the mass of Earth and the same size will accelerate through space twice as fast.
Given that the time period of a simple pendulum is = T
T = 2π√l/g where l is the pendulum length and g is the gravitational acceleration of the planet.
The time period of a mass-spring system is written as: T = 2π√m/k where m is the mass of system and k is spring constant.
The gravitational acceleration is defined as: g = GM/r^2
AS the acceleration due to gravity on planet X is greater than that of on earth we know that the time period is inversely proportional to g.
So, on planet X the time period is shorter and the mass-spring will remain same because the attached mass and spring constant are the same, the mass spring system is unaffected.
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An experiment is conducted to determine the thermal conductivity of a hot dog. First water is boiled in a large pan and measured to have a temperature of 94°c (at an elevation of 1650 m). The hot dog has dimensions of 12. 5 cm long and 2. 2 cm in diameter
Thermal conductivity may be measured with simple equipment.A slab of the material to be tested is clamped between an ice block and a steam chamber that both maintain constant temperatures of 0 °C and 100 °C.
How is thermal conductivity experiment measured? Thermal conductivity may be measured with simple equipment.A slab of the material to be tested is clamped between an ice block and a steam chamber that both maintain constant temperatures of 0 °C and 100 °C.Temperature variation and nonlinear heat flow specifically are the error sources.There are two ways that temperature can vary at contact surfaces: (a) gradually drifting over the board, and (b) momentarily varying throughout the platen surface.Using the Searle's bar method, calculate Copper's thermal conductivity.Steam is heated in this experiment.Don't touch the steam generator, tubing, or the Searle's bar equipment because they have hot surfaces.To learn more about Thermal conductivity refer
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