The acceleration of the collar at point A is 5 ft/s^2.
A) To determine the normal force on the collar at point A, we need to consider the forces acting on the collar. The only force acting on the collar in the vertical direction is the weight of the collar (5 lb), which is balanced by the normal force exerted by the rod. Therefore, we can write:
N - 5 = 0
where N is the normal force. Solving for N, we get:
N = 5 lb
B) To determine the acceleration of the collar at point A, we need to use Newton's second law, which states that the net force acting on an object is equal to its mass times its acceleration. The net force on the collar is given by the force exerted by the spring, which is equal to the spring constant times the displacement of the collar from its unstretched length. At point A, the displacement of the collar is:
x = L - y = 3 - 0 = 3 ft
where L is the length of the rod and y is the position of the collar on the rod. Therefore, the force exerted by the spring is:
F = kx = 10 lb/ft × 3 ft = 30 lb
The weight of the collar is:
W = mg = 5 lb
where g is the acceleration due to gravity. The net force on the collar is therefore:
Fnet = F - W = 30 - 5 = 25 lb
Using Newton's second law, we can write:
Fnet = ma
where a is the acceleration of the collar. Solving for a, we get:
a = Fnet / m = 25 lb / 5 lb = 5 ft/s^2
Therefore, the acceleration of the collar at point A is 5 ft/s^2.
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Accounting question.help
The computations of the net profit or loss using the following cost valuation methods are as follows:
FIFO, net profit = $20,000
Weighted Average, net profit = $17,555.54.
What are the inventory cost valuation methods?The inventory cost valuation methods include FIFO (First In, First Out), LIFO (Last In, First Out), WAC (Weighted Average Cost), and Specific Identification.
Under the FIFO basis, the cost of inventory is evaluated based on the assumption that inventory that are first brought in are the first to be sold.
Under the Weighted Average Cost method, the average cost is computed by dividing the total cost of goods available for sale by the number of units.
Other inventory cost valuation methods include LIFO and Specific Identification.
FIFO Basis:Cost of Goods Sold = $80,000 ($10,000 x 3 + $12,000 x 2 + $13,000 x 2)
Sales Revenue = $106,000 ($15,000 x 7)
Overhead = $6,000
Net Profit = $20,000 ($106,000 - $80,000 - $6,000)
Weighted Average Cost Basis:Weighted Average Cost per tractor = $11,777.78 ($106,000 ÷ 9)
Cost of Goods Sold = $82,444.46 ($11,777.78 x 7)
Sales Revenue = $106,000 ($15,000 x 7)
Overhead = $6,000
Net Profit = $17,555.54 ($106,000 - $82,444.46 - $6,000)
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In the first group of 5, average was 6.5. In the second group of 15, the average was 4.5. What was the overall average of the two groups?
Step-by-step explanation:
First group of five total score = 5 * 6.5 = 32.5
Group of fifteen total score = 15 * 4.5 = 67.5
total score of 20 is 67.5 + 32.5 = 100
Average = 100 /20 = 5.0
Suppose it is known that the proportion of students at a local high school that take public transit to school is p = 0.15
The distribution of the sample is approximately normal with a mean of 0. 15 and a standard deviation of 0. 03852.
How to describe the distribution ?One can utilize the Central Limit Theorem (CLT) for proportions to detail the dispersion of the sample proportion. Explained by the CLT, if the size of the sample is sufficiently significant enough, then the distribution with respect to the sample proportion will be mostly indistinguishable from a typical distribution.
np ≥ 10
n(1-p) ≥ 10
Given that both conditions are fulfilled, we can essentially posit that the said sample proportion distribution is almost normal. In light of this knowledge, it would be pertinent to ascertain the mean (μ) and standard deviation (σ) of the sample proportion distribution.
Mean = p = 0.15
Standard deviation:
= √ ( ( 0.15 x ( 1 - 0. 15 ) ) / 86 )
= 0.03852
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 1.What did Ruskin write about Nocturne in Black and Gold: Falling Rocket?
2. How did Whistler defend his work in court? ( You need to mention the two paintings he brought with him to court.)
3. What was the outcome of the trial?
4. Why do you think the lawsuit was important in the history of art?
What transformation were used
Since ΔJKL was transformed to create ΔMNO, the sequence of transformations that were used include the following:
Reflection over the y-axis.
(x, y) → (x, y - 9).
What is a reflection over the y-axis?In Geometry, a reflection over or across the y-axis or line x = 0 is represented and modeled by this transformation rule (x, y) → (-x, y).
By applying a reflection over the y-axis to the coordinate of the given triangle JKL, we have the following coordinates:
Coordinate J = (3, 7) → Coordinate J' = (-(3), 7) = (-3, 7).
Next, we would apply a vertical translation by shifting triangle J'K'L' down by 9 units to produce ΔMNO;
(x, y) → (x, y - 9).
J' (-3, 7) → (-3, 7 - 9) = M' (-3, -2).
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I know the answer, but I don't understand how. The answer is 90 degrees
In the circle the measure of arc YP as per the given measurements is equal to option D. 166°
In the circle,
Measure of arc ST = 70°
Measure of arc RS = 96°
Measure of angle YZP = 128°
Arc formed by vertically opposite angles are equal
This implies,
Measure of arc YT = Measure of arc PR
Measure of arc ST + Measure of arc RS + Measure of arc YT = 180°
⇒70° + 96° + Measure of arc YT = 180°
⇒Measure of arc YT = 180° - 166°
⇒Measure of arc YT = 14°
⇒ Measure of arc PR = 14°
Measure of arc YP = 360° - ( Measure of arc (PR + RS + ST + TY ))
⇒ Measure of arc YP = 360° - ( 14° + 96° + 70° + 14° )
⇒Measure of arc YP = 360° -194°
⇒ Measure of arc YP = 166°
Therefore, the measure of arc YP is equal to option D. 166°
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On the first day of school, the eighth graders get to select one of two dances to attend for no cost. They can attend either the Fall Fling or the Spring Social for free.
Of the 144 boys in eighth grade, 82 choose to attend the Fall Fling for free. Of the 156 girls in eighth grade, 75 choose to attend the Spring Social for free.
The president of the eighth grade class constructed the following two-way table to show the numbers of boys and girls that choose each dance. Some of the values and totals are incorrect.
If the following two-way table was constructed from the data, select all the values the president of the eighth grade class has in
the correct spots.
The two-way table constructed from the data showing the numbers of boys and girls that choose each dance category should look like this:
Boys Girls Total
Fall Fling 82 81 163
Spring Social 62 75 137
Total 144 156 300
What is a two-way table?A two-way table is a data display tool that displays the frequencies for two different categories collected from a single group.
A two-way table use rows to represent one category variable and the columns to represent a second category variable, while the cells display the proportions or frequencies of each row and column combination.
The total number of boys in eighth grade = 144
The number of boys who choose to attend the Fall Fling = 82
Therefore, the number of boys who attend the Spring Social = 62 (144 - 82)
The total number of girls in eighth grade = 156
The number of girls who choose to attend the Spring Social = 75
Therefore, the number of girls who attend the Fall Fling = 81 (156 - 75)
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Answer:
62, 82, 163, 300
Step-by-step explanation:
I got this on study island
If a > O and y > 0, which expression is equivalent to v 768219 g372
• A.
162°y18 32g
• B.
-O c. 1604 ° V324,
O D.
8ay18 /12ry
The expression 16x⁹y¹⁸√3xy is equivalent to √769x¹⁹y³⁷
If a > O and y > 0, which expression is equivalent to √769x¹⁹y³⁷
Factor and rewrite the radicand in exponential form:
√16²×3x¹⁸×xy³⁶×y
Simplify the radical expression:
16x⁹y¹⁸ √2²×3xy
Factor and rewrite the radicand in exponential form:
8x⁹y¹⁸√2²×3xy
8x⁹y¹⁸.2√3xy
Multiply the monomials:
16x⁹y¹⁸√3xy
Hence, the expression 16x⁹y¹⁸√3xy is equivalent to √769x¹⁹y³⁷
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In △ABC, AB=6 cm, AC=15 cm, and m∠A=48°.
What is the area of △ABC?
Enter your answer as a decimal in the box. Round only your final answer to the nearest hundredth.
The area of triangle ABC is : 33.44 cm²
What is the Area of a Triangle?The area of a triangle is the region enclosed within the sides of the triangle. The area of a triangle varies from one triangle to another depending on the length of the sides and the internal angles. The area of a triangle is expressed in square units, like, m2, cm2, in2, and so on.
We have the information from the question is:
In triangle ABC :
AB=6 cm,
AC=15 cm, and
m ∠A=48°.
We have to find the area of Triangle ABC
Area of triangle is : 1/2 × bc × (SinA)
Area of Triangle = 1/2 × 6 × 15 × (Sin 48° )
We know the value of Sin 48° is 0.7431
Area of Triangle = (1/2) × 66.88
Area of triangle = 33.44 cm²
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What are the features of the function f(x)=2log3 (x+7)graphed below?
The key features of the function f(x) = 2log₃(x+7) graphed below include the following:
The domain of this function is [-7, ∞]The range of this function [-∞, ∞] or all real numbers.x-intercept = (-6, 0).y-intercept = (0, 2log₃(7)).Vertical asymptote is at: x = -7No extreme points.What is a domain?In Mathematics and Geometry, a domain refers to the set of all real numbers for which a particular function is defined.
Furthermore, the vertical extent of any graph of a function represents all range values and they are always read and written from smaller to larger numerical values, and from the bottom of the graph to the top.
By critically observing the graph of this logarithmic function shown in the image attached above, we can reasonably and logically deduce the following domain and range:
Domain = [-7, ∞].
Range = [-∞, ∞].
In conclusion, we can logically deduce that this logarithmic function has a vertical asymptote is at x equal to negative seven.
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sage team brought 224 cans they brought 3 times cans as asifs team joes team brought 4 times as asifs team how much cans did joes team bring in
The number of cans brought by Joes team is J = 299 cans
Given data ,
Let the number of cans brought by Joes team be J
Now , sage team brought 224 cans
And , sage team brought 3 times cans as asifs team
And , joes team brought 4 times as asifs team
On simplifying the equation , we get
Asif's team brought 224/3 = 74.67 (rounded to the nearest whole number) cans.
Joe's team brought 74.67 x 4 = 298.68
So , J = 299 cans
Hence , the equation is solved and J = 299 cans
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PLEASE HELP FAST I’M HAVING A LITTE TROUBLE PLEASE GIVE THE RIGHT ANSWER
Answer:
C) 1/2 and 8
Step-by-step explanation:
-2x + y = 7 Eq. 1
6x + y = 11 Eq. 2
From Eq. 1:
y = 7 + 2x Eq. 3
From Eq. 2:
y = 11 - 6x Eq. 4
Equalyzing Eq. 3 and Eq. 4:
7 + 2x = 11 - 6x
2x + 6x = 11 - 7
8x = 4
x = 4/8
x = 1/2
From Eq. 3:
y = 7 +2* 1/2
y = 7 + 1
y = 8
Check:
From Eq. 2
6x + y = 11
6*1/2 + 8 = 11
3 + 8 = 11
6) The height h(t) of a projectile is given by
h(t) = −t² + 7t + 9.
Find the time (s) at which the rocket is
20 ft above the ground.
Answer:
2.38 s
4.62 s
Step-by-step explanation:
The height of a projectile is given by the function:
[tex]h(t) = -t^2 + 7t + 9[/tex]
where:
h(t) is the height of the rocket about the ground (in feet).t is the time (in seconds).To determine the time(s) at which the rocket is 20 ft above the ground, set h(t) = 20 and solve for t.
[tex]-t^2+7t+9=20[/tex]
To solve the equation for t, complete the square.
Subtract 9 from both sides:
[tex]-t^2+7t=11[/tex]
Divide both sides by -1:
[tex]t^2-7t=-11[/tex]
Add the square of half the coefficient of the term with the variable "t" to both sides of the equation:
[tex]t^2-7t+\left(\dfrac{-7}{2}\right)^2=-11+\left(\dfrac{-7}{2}\right)^2[/tex]
Simplify:
[tex]t^2-7t+\dfrac{49}{4}=\dfrac{5}{4}[/tex]
We have now created a perfect square trinomial on the left side of the equation. Factor the perfect square trinomial:
[tex]\left(t-\dfrac{7}{2}\right)^2=\dfrac{5}{4}[/tex]
To solve for t, square root both sides:
[tex]t-\dfrac{7}{2}=\pm \sqrt{\dfrac{5}{4}}[/tex]
[tex]t-\dfrac{7}{2}=\pm\dfrac{\sqrt{5}}{2}[/tex]
Add 7/2 to both sides of the equation:
[tex]t=\dfrac{7}{2}\pm\dfrac{\sqrt{5}}{2}[/tex]
[tex]t=\dfrac{7\pm\sqrt{5}}{2}[/tex]
Therefore, the times at which the rocket is 20 ft above the ground is:
[tex]t=\dfrac{7-\sqrt{5}}{2}=2.38\; \rm s[/tex]
[tex]t=\dfrac{7+\sqrt{5}}{2}=4.62\; \rm s[/tex]
Please help, I don't know how to do this !
The lengths of the legs, the circumference and the radius of the circles are;
First part; The diameter = 18 units
The second leg = 9 units
Second part; The circumference = 34·π units
Third part; The radius is r = 36 cm
What is a radius of a circle?The radius of a circle is the distance from the center to the circumference.
First part;
cos(30°) = 9·√3 ÷ The diameter = (√3)/2
The diameter = (9·√3) ÷ ((√3)/2) = 18
The length of the other leg, using the relationship between special triangles is 18/2 = 9
Second part;
The lengths of the legs of the right triangle indicates that we get;
The square of the diameter, D² = 30² + 16² = 1156
The length of the diameter, D = √(1156) = 34
The formula for finding the circumference of a circle, C, based on the diameter can be presented as follows;
C = π × D
Therefore;
The circumference of the circle, C = π × 34
The circumference of the circle = 34·π units
Third part
The length of the 20° arc = 4·π cm
Therefore;
4·π = 2·π·r × 20/360
Where;
r = The radius of the circle
Therefore;
r = (360/20) × 4·π ÷ (2·π) = 36
The radius of the circle, r = 36 cm
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helphelphelphelphelphelphelphelphelphelphelphelphelp
The volume of the flower vase, can be found to be 2, 199 cm ³.
How to find the volume ?The volume of the flower vase can be found by subtracting the volume of the cone from the volume of the rectangular prism.
Volume of rectangular prism :
= Length x Width x Height
= 20 x 12 x 10
= 2, 400 cm ³
The volume of the cone is:
= π x radius ² x height / 3
= π x 4 ² x 12 / 3
= 201. 06 cm ³
Volume of vase:
= 2, 400 - 201. 06
= 2198.94
= 2, 199 cm ³
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If the amount of food available is increased, then the cricket frog population will (increase/decrease/stay the same) over the span of five years.
at+a+fair+Daniel+and+Claire+went+on+a+ride+that+has+two+separate+circular+tracks.+Daniel+rode+in+a+purple+car+that+travels+a+total+distance+of+265+feet+around+the+track+.+Ciara+rode+in+a+yellow+car+that+travels+a+total+distance+of+170+feet+around+the+track.+They+drew+drew+a+sketch+of+the+ride.+What+is+the+difference+ofthe+radii+of+the+two+circle+tracks
Note that the difference in the radii of the two circular tracks is about 13.68 ft
How did we get that?recall that the circumference of a circle is denoted by the expression
C = 2πr
In this case, C = Circumference
and r radius
Since we have two tracks
Let ra = radius of the purple track and
rb = radius of the yello track
So
265 = 2πra
170 = 2πrb
making ra and rb subject of the expression we have
ra = 256/(2π) =40.7436654315 ≈ 40.74
rb = 170 / (2π) = 27.0563403256 ≈ 27.06
Hence, the difference is
40.74 - 27.06 = 13.68ft
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Full Question:
at a fair Daniel and Claire went on a ride that has two separate circular tracks. Daniel rode in a purple car that travels a total distance of 265 feet around the track . Ciara rode in a yellow car that travels a total distance of 170 feet around the track. They drew drew a sketch of the ride. What is the difference ofthe radii of the two circle tracks
Isosceles triangle LMN is graphed with vertices L(0, 1), M(3, 5), and N(6,1). What is the slope of side LN?
Negative StartFraction 4 over 3 EndFraction.
0
StartFraction 4 Over 3 EndFraction.
3
\
If tan A= 28 /45 and cosB= 13 12 and angles A and B are in Quadrant I, find the value of tan(A+B).
The value of Tan A + B is 6.009.
How to solve for the tangent[tex]sin^2 A + cos^2 A = 1sin^2 A = 1 - cos^2 Asin A = sqrt(1 - cos^2 A)sin A = sqrt(1 - (28/45)^2)sin A = sqrt(1 - 784/2025)sin A = sqrt(1241/2025)cos A = 28/45\geq[/tex]
We have to solve for Tan B
[tex]sin^2 B + cos^2 B = 1sin^2 B = 1 - cos^2 Bsin B = sqrt(1 - cos^2 B)sin B = sqrt(1 - (13/12)^2)sin B = sqrt(55/144)Therefore, tanB = sinB / cosB = (sqrt(55/144)) / (13/12) = (12 sqrt(55)) / 143[/tex]
[tex]tan(A+B) = (3207 \sqrt{55}) + 1804 \sqrt{124})) / (3115 - 207 \sqrt{(341)}[/tex]
= 6.009.
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Ben wants to compare the scores of this year's basketball games to the scores of last year's games. He made the following double stem-and-leaf plot to make
his comparison.
Comparison of
Basketball Scores
Between the Last
Two Years
Last
Year
995
97753
6654
9
Stem
OB. 20
OC 16.
0
1
2
3
4
5
What is the difference between the median score this year and the median score last year?
OA 18
OD. 17
This
Year
999
7889
456778
233
2
Find the 13th term of the geometric sequence 4, −8, 16, ...
Answer:
Step-by-step explanation:
use the product to rewrite log16(256b)
Log₁₆(256b) in terms of the logarithm of b, which is the factor that was multiplied by 256 inside the logarithm is 2 + log₁₆(b)
We can use the product rule of logarithms, which states that the logarithm of a product is equal to the sum of the logarithms of the factors.
Therefore, we can write
log₁₆(256b) = log₁₆(256) + log₁₆(b)
We can simplify log₁₆(256) as follows:
log₁₆(256) = log₁₆(16^2) = 2
Therefore, we have:
log₁₆(256b) = log₁₆(256) + log₁₆(b)
= 2 + log₁₆(b)
So, we have rewritten log₁₆(256b) in terms of the logarithm of b, which is the factor that was multiplied by 256 inside the logarithm.
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Help. I need game credits for GMM
The difference of p and z times the sum of p and z is p² - 2pz - z².
How to represent expression?An algebraic expression in mathematics is an expression which is made up of variables and constants, along with algebraic operations such as addition, subtraction, division and multiplication.
Hence, the difference of p and z times the sum of p and z can be represented as follows:
Therefore,
(p - z) × (p + z) = (p - z) (p + z)
(p - z) (p + z) = p² - pz - pz - z²
p² - pz - pz - z² = p² - 2pz - z²
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Find the range of the following: 20, 3, 95, 54, 71, 66
Answer:
92.
Step-by-step explanation:
To find the range of the set of numbers 20, 3, 95, 54, 71, 66, we first need to find the difference between the largest and smallest numbers in the set.
Largest number = 95
Smallest number = 3
Range = Largest number - Smallest number
Range = 95 - 3
Range = 92
Therefore, the range of the set of numbers 20, 3, 95, 54, 71, 66 is 92.
Answer:92
Step-by-step explanation: highest-lowest
it helps to put the terms in order first
95-3=92
The ratio of alcohol and water in a mixture of 72 units is 2 ratio 1 what is the amount of water that must be added to the mixture in order to make this ratio 1 ratio 2
The amount of water needed is 72 liters.
Given that, the ratio of the alcohol and water in a mixture of 72 units is 2 ratio 1, we need to find the amount of water that must be added to the mixture in order to make this ratio 1 ratio 2,
So,
The quantity of water in it = 72 / 3 × 1 = 24
New ratio =
48 / 24+x = 1/2
96 = 24+x
x =72
Hence, the amount of water needed is 72 liters.
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The parallel dotplots below display the number of absences for students in each of two classes.
2 dotplots titled class absences. The number lines go from 0 to 10 and are labeled number of absences. Class D, 0, 7; 1, 11; 2, 4; 3, 3. Class C, 0, 8; 1, 10, 2, 4; 3, 1; 5, 1; 10, 1.
Which of the following statements is true?
The range for the distribution of the number of absences is larger for class D.
The range for the distribution of the number of absences is larger for class C.
The IQR for the distribution of the number of absences is larger for class D.
The IQR for the distribution of the number of absences is larger for class C.
The range, difference of maximum and minimum values, is larger for Class C with a range of 10 compared to Class D with a range of 3. The data provided is not sufficient to calculate the IQR (Interquartile Range) for either class.
Explanation:To begin, let's understand what the terms 'range' and 'IQR' (Interquartile Range) refer to in statistics. The range is simply the difference between the largest and smallest data values. The IQR is the range of the middle 50% of the values when ordered from lowest to highest.
For Class D, the lowest absence number is 0 and the highest is 3, thus the range is 3-0 = 3. For Class C, the lowest absence number is 0 and the highest is 10, so the range is 10-0 = 10. Thus, the range for the distribution of absences is larger for Class C.
Calculating IQR requires determining the 1st Quartile (Q1) and 3rd Quartile (Q3) values and subtracting Q1 from Q3. The data given doesn't include enough information to directly calculate these values and hence, it is impossible to definitively say which class has a larger IQR based on the provided information.
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Area of a regular polygon work
Answer:
Step-by-step explanation:
[tex]\frac{x}{18} =cot~30\\x=18cot~30=18 \times \sqrt{3} =18\sqrt{3} \\base=36\sqrt{3} \\area~of~triangle=3\times \frac{1}{2} \times36\sqrt{3} \times 18=972\sqrt{3} \approx 1683.55~mm^2[/tex]
Ellen bought a pedometer wristband to track how many steps she takes. Each day she recorded the number of steps in a table. At the end of the week, she found her mean number of steps was 10,000. She made a bar graph to show her daily steps for the week. Which graph could show Ellen’s steps?
THANKS SO MUCH!!!
Answer:
it is b got it right on my test
Step-by-step explanation:
The required graph that shows Ellen's steps where her mean steps for a week is 10000 is graph 2 where the data are as,
Day 1 = 11000 , Day 2 = 9000, Day 3 = 10000, Day 4 = 12000, Day 5 = 8000, Day 6 ≈ 10000, Day 7 ≈ 10000
Mean of ungrouped data is the average of all the values of the observation in the data set.
Mean = (Summation of all values in data set)/ (Number of observations)
Here there are 7 observations and the mean number of steps is 10000.
For graph 1 the values for each day of the week are as,
Day 1 = 8000 , Day 2 = 9000, Day 3 = 12000, Day 4 = 2000, Day 5 = 6000, Day 6 = 10000, Day 7 = 10000
Thus, the mean number of steps is = (8000+ 9000+ 12000+ 2000+ 6000+ 10000 + 10000) / 7
= 8143 (approximately) ≠ 10000
For graph 2 the values for each day of the week are as,
Day 1 = 11000 , Day 2 = 9000, Day 3 = 10000, Day 4 = 12000, Day 5 = 8000, Day 6 ≈ 10000, Day 7 ≈ 10000
Thus, the mean number of steps is = (11000+ 9000+ 10000+ 12000+ 8000+ 10000 + 10000) / 7
= 10000
For graph 3 the values for each day of the week are as,
Day 1 = 7000 , Day 2 = 14000, Day 3 = 11500, Day 4 = 10000, Day 5 = 4500, Day 6 = 6000, Day 7 = 11000
Thus, the mean number of steps is = (7000+ 14000+ 11500+ 10000+ 4500+ 6000 + 11000) / 7
= 9143 (approximately) ≠ 10000
For graph 4 the values for each day of the week are as,
Day 1 = 8000 , Day 2 = 9000, Day 3 = 9500, Day 4 = 10000, Day 5 = 9000, Day 6 = 7000, Day 7 = 11000
Thus, the mean number of steps is = (8000+ 9000+ 9500+ 10000+ 9000+ 7000 + 11000) / 7
= 9071 (approximately) ≠ 10000
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What is the solution to this system?
(1, 0)
(1, 6)
(8, 26)
(8, –22)
x = –2
Answer:
Step-by-step explanation:The system of equations represented by the given points is:1x + 0y = 1 (equation 1)
1x + 6y = 1 (equation 2)
8x + 26y = 1 (equation 3)
8x - 22y = 1 (equation 4)
We can use the first equation to solve for x in terms of y:1x + 0y = 1
1x = 1
x = 1
Then we can substitute x=1 into equations 2-4 to obtain three equations in terms of y:1(1) + 6y = 1 => 6y = 0 => y = 0
8(1) + 26y = 1 => 26y = -7/8 => y = -7/208
8(1) - 22y = 1 => -22y = -7/8 - 7 => y = 15/44
Therefore, the solution to the system is x = 1 and y = -7/208 or y = 0 or y = 15/44.
However, we are given that x = -2, which contradicts our solution of x = 1. Therefore, there is no solution to the system with the given values.
$18,389
is invested, part at 10%
and the rest at 8%
. If the interest earned from the amount invested at 10%
exceeds the interest earned from the amount invested at 8%
by $621.02
, how much is invested at each rate? (Round to two decimal places if necessary.)