Task: Use the following situation to answer Parts A and B Instructions At noon, a tank contains 100 gallons of water. The table shows the input and output of water from pipes A, B, and C. The pipes begin operating simultaneously at noon. A B C Pipe Flow IN (gallons per minute) a (2) = 172 6(2) = 80 Flow OUT (gallons per minute) c (2)=30r Complete each of the 2 activities for this Task. Activity 1 of 2 Let T (2) represent the amount of water in the tank x minutes after all of the pipes A, B, and C are opened. Which of the following functions represents T (x)? O A T (2) = 100 + a(z) +b(2) - c(x) OCT (x) = 100 + a (x) +b(2) + c(2) OBT () = a (x) + b() +(2) ODT (2) = a (x) +b(x) - c(:) Activity 2 of 2 Using the equation, after how many minutes will the tank be empty?
Answers
Answer:
1. Option C2. NeverStep-by-step explanation:
Refer to attached for the table and clearer version of the question
As per table A and B pipes feed the tank and C is the outlet
Considering initial volume of 100 gallons, the amount of water in the tank after x minutes is:
T(x) = 100 + a(x) + b(x) - c(x), this is option C.We can calculate when tank is going to be empty:
0 = 100 + 25x + 10x - 30x0 = 5x + 1005x = -100x = -20Since we got negative number, the tank is not going to be empty when all 3 pipes are open.
The function which represent T (x) for the tank which contains 100 gallons of water and input and output of water from pipes A, B, and C is,
[tex]T(x)=100+a(x)+b(x)-c(x)[/tex]
The tank will not be empty when all the three pipes are in operation.
What is a function?If we have two sets A and B as:
[tex]A = \{a_1, a_2, ... \}\\B = \{b_1, b_2, ... \}[/tex]
Then, function
[tex]f:A \rightarrow B[/tex]
is a connection of elements of A to B such that one element of A is connected to only single element of B, and not many.
The connected pairs are then written as:
[tex]\{(a_i_1,b_j_1), (a_i_2, b_j_2), ... \}[/tex]
Under the function f.
The table shows the input and output of water from pipes A, B, and C.
Pipe A B C
Flow In (gallons/minute) a(x)=25x b(x)=10x
Flow Out (gallons/minute) c(x)=30x
The pipes begin operating simultaneously at noon. Let T (2) represent the amount of water in the tank x minutes after all of the pipes A, B, and C are opened.
At noon, a tank contains 100 gallons of water. In the above table A and B shows the inlet of water while C shows the out let of the water.
So, 100, A and B added in the function while C will be subtracted as,
[tex]T(x)=100+a(x)+b(x)-c(x)[/tex]
Thus, the function in option C represents T (x).
Now use this equation, to find the number of minutes for the tank be empty. For this equation, the equation equal to zero as,
[tex]T(x)=100+25x+10x-30x[/tex]
[tex]0=100+25x+10x-30x\\-100=5x\\x=-20[/tex]
This negative value of x tells that if all the three pipes are open, the tank is never become empty completely.
Thus, the function which represent T (x) for the tank which contains 100 gallons of water and input and output of water from pipes A, B, and C is,
[tex]T(x)=100+a(x)+b(x)-c(x)[/tex]
The tank will not be empty when all the three pipes are in operation.
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Answer:
B.
Step-by-step explanation:
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0.05 per ounce
Step-by-step explanation:
5.20 per 40 is 0.13 per ounce
whereas
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Is 8(3x+2) and 4(6x÷4) equivalent?
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Answer:
x= - 8/9
Step-by-step explanation:
what is the 12
th term rule of the linear sequence 13 7 1 -5 -11
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Answer:
-53, f(n) = -6(n-1) + 13
Step-by-step explanation:
given the equation to this linear/arithmetic sequence for the nth term: f(n) = -6(n-1) + 13
f(12) = -6(12-1) + 13
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______________
f(n) = f(1) + d(n-1)
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The random variables X and Y are jointly continuous, with a joint PDF of the form fX,Y(x,y)={cxy,0,if 0≤x≤y≤1,otherwise, where c is a normalizing constant. For x∈[0,0.5] , the conditional PDF fX|Y(x|0.5) is of the form axb . Find a and b .
Answers
Answer:
The value of a and b are 8 and 1 respectively
Step-by-step explanation:
[tex]f_{x,y}(x,y)=\left\{\begin{matrix}cxy ,\text{if} 0 \leq x \leq y \leq 1\\ 0 , \text{otherwise}\end{matrix}\right.[/tex]
[tex]\int_{0}^{1}\int_{x}^{1}cxy \text{dy dx}=1\\\\c\int_{0}^{1}x\left ( \frac{y^2}{2}\right )_{x}^{1} \text{ dx}=1\\\\\frac{c}{2}\int_{0}^{1}x\left ( 1-y^2\right )\text{dx}=1\\\\\frac{c}{2}\int_{0}^{1}(x-x^3)\text{dx}=1\\\\\frac{c}{2}\left [ \frac{x^2}{2}-\frac{x^5}{4} \right ]_{0}^1=1\\\\\frac{c}{2}\left [ \frac{1}{2}-\frac{1}{4} \right ]=1\\\\\frac{c}{2}\left ( \frac{1}{4} \right )=1\\\\c=8[/tex]
Conditional pdf of [tex]f_{x,y}(x|0.5)[/tex]
[tex]f_{x,y}(x|0.5)=\frac{f_{xy}(x,y=0.5)}{f_{y}y}[/tex]
Normalizing pdf of 1
[tex]f_{y}y=\int_{0}^{y} 8yx \text{dx}[/tex]
[tex]f_{y}y=8y[\frac{x^2}{2}]_{0}^{y}\\f_{y}y=4y(y^2)\\f_{y}y=4y^3\\f_{x|y}(x|0.5)=\frac{8x(0.5)}{4(0.5)^3}=\frac{2x}{0.25}=8x[/tex]
We are given that PDF [tex]f_{x|y}(x|0.5)[/tex] is of the form [tex]ax^b[/tex]
So, on comparing 8x with [tex]ax^b[/tex]
So, a = 8 , b = 1
So, the value of a and b are 8 and 1 respectively
The resulting value of a and b given the conditional PDF of fX|Y(x|0.5) is mathematically given as
a = 8 , b = 1 .
What are the values of a and b?Question Parameters:
a joint PDF of the form fX,Y(x,y)={cxy,0,if 0≤x≤y≤1,
For x∈[0,0.5]
the conditional PDF fX|Y(x|0.5)
Generally, the equation for the function of (x,y) is mathematically given as
[tex]f_{x,y}(x,y)=\left\{\begin{matrix}cxy ,\text{if} 0 \leq x \leq y \leq 1\\ 0 ,\end{matrix}\right.[/tex]
Therefore
[tex]\int_{0}^{1}\int_{x}^{1}cxy \text{dy dx}=1[/tex]
[tex]c\int_{0}^{1}x\left ( \frac{y^2}{2}\right )_{x}^{1} \text{ dx}=1[/tex]
[tex]\frac{c}{2}\left [ \frac{x^2}{2}-\frac{x^5}{4} \right ]_{0}^1=1[/tex]
[tex]\\\\\frac{c}{2}\left ( \frac{1}{4} \right )=1[/tex]
C=8
Where, the conditional PDF fX|Y(x|0.5)
[tex]f_{x,y}(x|0.5)=\frac{f_{xy}(x,y=0.5)}{f_{y}y}[/tex]
We have
[tex]f_{y}y=8y[\frac{x^2}{2}]_{0}^{y}\[/tex]
[tex]f_{y}y=4y^3[/tex]
[tex]f_{x|y}(x|0.5)=\frac{8x(0.5)}{4(0.5)^3}[/tex]
f_{x|y}(x|0.5)=8x
In conclusion. with the pdf in the form of ax^2
8x comparing ax^b
The value of a = 8 , b = 1 .
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Step-by-step explanation:
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y y = 1x-2
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What is Slope of Line?The slope of the line is the ratio of the rise to the run, or rise divided by the run. It describes the steepness of line in the coordinate plane.
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Step-by-step explanation:
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Step-by-step explanation:
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4
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HHH H
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OL
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Answer:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
3 centimer divided by 3 is 1. 1 cm a second. 6 centimeters didvided by 6 is 1.
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Damien left his house at time Zero and drove to the store, which is 12 blocks away, at a speed of 6 blocks per minute. then he stopped and went into the store for 5 minutes. from there, he drove in the same direction at speed of 2 blocks per minute until he got to the bank, which is 12 blocks away from the store. he stopped at the bank for 2 minutes. then he drove home at a speed of 6 blocks every minute. make a graph of showing the number of blocks away from home that Damien is x minutes after he leaves his house, until he gets back home.
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Answer:
johanna prepares a mixture of salad mixed with mayonnaise carrots cucumber lettuce and cheese. what type of mixture divine salad is? why do you think so
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Answer:
I'm on Edulastic.com taking a 100 Q test and this question is on it!
Step-by-step explanation:
Imao im fgging confused
The graph of the required line [tex]\bold{y=\frac{x}{4}+2}[/tex] is given below.
Slope point form of equation of line: -An equation of line with slope m and passing through point (p, q) is:
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We have been given the slope of the line m = 1/4,
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Using the slope-point form equation of line would be,
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So, the equation of the line is [tex]y=\frac{x}{4} +2[/tex].
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because 18/2 is 9
Answer:
Step-by-step explanation:
18 divided by 2 would be 9 so k=9
(x + 8)(x-8)
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Step-by-step explanation:
we know the formula(x^2-y^2)=(x+y)(x-y)
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dhvbhdvhdhddjbd
Step-by-step explanation:
Laura had 192 dollars to begin with. She just spent b dollars. Using b, write an expression for the number of dollars she has left
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Step-by-step explanation:
If Laura had $192 and she spent $b, the expression is $192-$b. Hope it helps!
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Answer:
s=3
Step-by-step explanation:
Answer:
s=3
Step-by-step explanation:
simplify the equation to the form, which is simple to understand
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Answers
Answer:
4, 1
Step-by-step explanation:
If you take 2, 8 and make it a ratio you get 2 : 8.
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For the other answer, you want to divide 2 by 8.
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Mary has a bag with 80 pieces of candy. She gives ¼ of her candy to John and 10% to Lisa. How much more candy did she give to John then Lisa?
Answers
Answer:
12 pieces
Step-by-step explanation:
80 pieces of candy
1/4 is 25% or 20 pieces of candy
10% would be 8 pieces of candy
subtract the two. Your answer is 12
Answer:
He had 14 more pieces
Step-by-step explanation:
So 80/4 is 20 pieces. So we know John has 20. Now she has 60 left since 80-20 is 60. Now 10 percent of 60 would be 6 pieces. We can subtract 6 from 20 to find out how many more pieces John had. 20-6 is 14. So John had 14 more than Lisa