Suppose a normal distribution has a mean of 79 and a standard deviation of
7. What is P(x286)?
OA. 0.975
B. 0.84
O C. 0.025
D. 0.16

Answer:

[tex]3(n + 5) = (n + 5)3[/tex]

So p = 5.

To calculate the moment of inertia of an object, you need to know its mass and the distance it is from the axis of rotation. In this case, the object has a mass of 12 kg and is distributed 4 meters from the axis of rotation. The formula to calculate the moment of inertia is I = mr^2, where the moment of inertia, m is the mass, and r is the distance from the axis of rotation.

Using this formula, we can calculate the moment of inertia of the object:

I = 12 kg x (4 m)^2

I = 192 kgm^2

Therefore, the moment of inertia of the object is 192 kgm^2.
To calculate the moment of inertia for an object, you can use the following formula:

Moment of Inertia (I) = Mass (m) × Distance² (r²)

Given the object's mass is 12 kg and the mass is distributed 4 meters from the axis of rotation, we can plug these values into the formula:

I = 12 kg × (4 m)²

Now, we'll square the distance:

I = 12 kg × 16 m²

Finally, multiply the mass and the squared distance:

I = 192 kg·m²

So, the moment of inertia of the object is 192 kg·m².

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The surface area of the figure is 132 square units.

Option D is the correct answer.

We have,

The figure has two types of shapes.

- 3 rectangles

- 2 triangles

Now,

Area of the 3 rectangles.

= 5 x 10 + 4 x 10 + 3 x 10

= 50 + 40 + 30

= 120 square units

Area of 2 triangles.

= 1/2 x 4 x 3 + 1/2 x 4 x 3

= 1/2 x 12 + 1/2 x 12

= 6 + 6

= 12 square units

Now,

Total surface area.

= 120 + 12

= 132 square units.

Thus,

The surface area of the figure is 132 square units.

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To prove that 1/xy = 1/x * 1/y, we can start by multiplying both sides of the equation by xy.

Multiplying both sides of the equation by xy gives us:

1 = xy * 1/x * 1/y

Next, we can simplify the right-hand side by canceling out the x and y terms that appear in both the numerator and denominator:

1 = y/x + x/y

To further simplify this expression, we can multiply both sides by xy:

xy = y^2 + x^2

This equation can be rearranged to get:

x^2 + y^2 = xy

Finally, we can use the formula for the sum of squares:

x^2 + y^2 = (x+y)^2 - 2xy

Substituting this into the previous equation, we get:

(x+y)^2 - 2xy = xy

Simplifying, we get:

(x+y)^2 = 3xy

Taking the square root of both sides, we get:

x+y = sqrt(3xy)

Dividing both sides by xy, we get:

1/xy = 1/x * 1/y

Therefore, we have proven that 1/xy = 1/x * 1/y.

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The coordinate of final point of A after transformation is,

A'' = (0, - 7)

We have to given that;

Coordinate of A = (0, 7)

We know that;

Rule for the across the x - axis is,

(x, y) = (x , - y)

Hence, We get;

Point after transformation is,

A' = (0, - 7)

And, Rule for the across the y - axis is,

(x, y) = (-x ,  y)

Hence, Point after transformation is,

A'' = (0, - 7)

Thus, The coordinate of final point of A after transformation is,

A'' = (0, - 7)

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Answer:

[tex]0.1212...=\dfrac{4}{33}[/tex]

Step-by-step explanation:

A repeating decimal is a decimal number with a digit (or group of digits) that repeats forever.

There are three ways to show a repeating decimal:

0.1212... is a repeating decimal as there are two duplicates of the repeating block of digits "12" followed by an ellipsis.

To express a repeating decimal as a rational number, begin by assigning the decimal to a variable:

[tex]x=0.1212...=0.\overline{12}[/tex]

Multiply both sides by 100:

[tex]\implies x \cdot 100=0.\overline{12}\cdot 100[/tex]

[tex]\implies 100x=12.\overline{12}[/tex]

Subtract the first equation from the second to eliminate the part after the decimal:

[tex]\begin{array}{crcr}& 100x & = & 12.\overline{12}\\- & x & = & 0.\overline{12}\\\cline{2-4} & 99x & = & 12\phantom{.12}\\\end{array}[/tex]

Divide both sides of the equation by 99:

[tex]\implies \dfrac{99x}{99}=\dfrac{12}{99}[/tex]

[tex]\implies x=\dfrac{12}{99}[/tex]

Reduce the fraction to is simplest form by dividing the numerator and denominator by 3:

[tex]\implies x=\dfrac{12 \div 3}{99 \div 3}=\dfrac{4}{33}[/tex]

[tex]\textsf{Therefore, $0.1212...$ expressed in the form of a rational number is\;$\dfrac{4}{33}$}.[/tex]

Answer:

A P-value < 0.01

Step-by-step explanation:

The density of the ball in the air is given as follows:

d = 4 x 10^5 ounces/ft³.

The density is calculated as the division of the mass by the volume of an object, as follows:

d = m/v.

The ball in this problem is spherical with a diameter of 0.05 feet = radius of 0.025 feet, hence the volume is given as follows:

V = 4 x 3.1416 x 0.025³/3

V = 6.545 x 10^-5 ft³.

The ball in the air is inflated, hence the mass is given as follows:

m = 22.93 ounces.

Thus the density of the ball is given as follows:

d = 22.93/(6.545 x 10^-5)

d = 4 x 10^5 ounces/ft³.

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After the battery is fully charged, Car B can go further than Car A.  Car B, as compared to Car A, had lower variability measurements. After the battery is completely charged, Car B can go further than Car A since Car A has a lower mean and median. Option D is Correct.

The median splits the data in half. A lower median indicates that Car A has less mileage than Car B.

Two measurements exist.

The measure of centre reveals how closely or widely the data are dispersed around the centre.

The measurements of centre are mean, median, and mode.

Car A travelled less since it had a lower mean and median.

We can find out how data changes with a single value using the measure of variability. The data is denser at the mean when the MAD is less. The MAD in Car B is lower. Data that is closer to the centre of the data set has a smaller IQR.

IQR is lower in Car B.

Consequently, automobile B travelled steadily since its IQR and MAD were lower. Option D is Correct.

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Correct Question:

Annabel is comparing the distances that two electric cars can travel after the battery is fully charged. Car A (miles) Car B (miles) Mean 145 200 Median 142 196 IQR 8 4 MAD 6 2 Part A Use the measures of center to make an inference about the data. Use the drop-down menus to complete your answer. Car A can travel further than Car B after the battery is fully charged. Part B Based on the data, which car performs most consistently? Explain. A. Car A because the measures of center are smaller for Car A than for Car B. B. Car B because the measures of center are smaller for Car B than for Car A. C. Car A because the measures of variability are smaller for Car A than for Car B. D. Car B because the measures of variability are smaller for Car B than for Car A.

It is possible for one set of data to have a scatterplot that appears linear while the other does not, even if both groups started with the same number of dice and followed the same removal procedure.

This is because the way the dice were removed could have been different between the two groups, leading to different patterns of results. Additionally, other factors such as the order in which the dice were removed or the number of trials conducted could also affect the resulting scatterplot.

Ultimately, the scatterplot is a visual representation of the relationship between the variables being measured, and it can take on many different forms depending on the specific data and conditions being analyzed.

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The perimeter and area of the given polygon are:

Perimeter = 22.325 units

Area = 25 square units

Using Pythagoras theorem, we can find the length of the sides of the polygon as:

a = √(1² + 3²)

a = √10

b = √(3² + 3²)

b = 2√9

c = √(3² + 3²)

c = 2√9

d = √(1² + 3²)

d = √10

e = 4

Thus:

Perimeter = 2√10 + 4√9 + 4

Perimeter = 22.325 units

Area = 2(¹/₂ * 1 * 3) + 2(¹/₂ * 3 * 3) + (4 * 3)

= 25 square units

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Answer: -15

Step-by-step explanation:

x+y=10

y=-x+10

2x+3(-x+10)=45

2x-3x+30=45

-x=15

x=-15

When a=0.02 and n=24, [tex]X_{left}^{2}[/tex] = 9.260 and [tex]X_{right}^{2}[/tex]= 41.638. In order to calculate [tex]X_{left}^{2}[/tex] and [tex]X_{right}^{2}[/tex] when a=0.02 and n=24, we need to use the chi-squared distribution table. This table provides us with the critical values for a given level of significance (alpha) and degrees of freedom (df).

To answer your question, when a=0.02 and n=24, we will find the [tex]X_{left}^{2}[/tex] and [tex]X_{right}^{2}[/tex] values using the Chi-square distribution table.

Step 1: Determine the degrees of freedom. In this case, the degrees of freedom (df) are equal to n-1, so df = 24 - 1 = 23.

Step 2: Determine the significance level (alpha) and divide it by 2. Since a = 0.02, the significance level is [tex]\frac{\alpha}{2} =0.01[/tex] for each tail (left and right) of the distribution.

Step 3: Use the Chi-square distribution table to find the critical values. Look for the values corresponding to the degrees of freedom (23) and significance level (0.01) in each tail.

According to the Chi-square distribution table:
[tex]X_{left}^{2}[/tex]= 9.260
[tex]X_{right}^{2}[/tex]= 41.638

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The radius of the region is 11.55 mile.

We have,

Population = 175,000

So, population density

= 175,000 / 1318

= 132.77

and, the radius using from the population density

Radius = √area / (22/7)

= √1318 x 7/22

= 11.55 mile

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The average rate of change of f(x) = x with respect to x over the interval a = 1 is 1.

To determine the average rate of change of f(x) = x with respect to x over the interval a, we'll use the formula:

Average Rate of Change = (f(b) - f(a)) / (b - a)

In this case, the interval a is 1, so let's choose an interval b. We can use any value for b, but let's choose b = 2 for simplicity.

Step 1: Find f(a) and f(b)
f(x) = x, so:
f(1) = 1
f(2) = 2

Step 2: Plug the values into the formula
Average Rate of Change = (f(2) - f(1)) / (2 - 1)
Average Rate of Change = (2 - 1) / (2 - 1)

Step 3: Calculate the result
Average Rate of Change = (1) / (1)

The average rate of change of f(x) = x with respect to x over the interval a = 1 is 1.

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The probability of choosing a black chip and then another black chip is,

⇒ 1/3

Since, There are 4 + 6 = 10 chips in the bag.

And, 6 of them are black .

Hence, The probability that the first chip chosen will be black is,

⇒ 6/10

⇒ 3/5.

After that, there is one black chip less in the bag, so there are 9 chips in the bag, 5 of them are black.

Hence, The probability that the second chip chosen will be black is,

⇒ 5/9

Now, Multiply the probabilities to find the probability that the first chip will be black and the second chip will be black:

⇒ 3/5 × 5/9

⇒ 1/3

Thus, The probability of choosing a black chip and then another black chip is,

⇒ 1/3

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Based on the information provided, only one of the independent variables can be an indicator (dummy) variable, which is:

- The player was traded in the last 5 years

Based on the information provided, only one of the independent variables can be an indicator (dummy) variable, which is:

- The player was traded in the last 5 years

This variable can take on a value of 0 or 1, where 0 represents that the player was not traded in the last 5 years, and 1 represents that the player was traded in the last 5 years. The other independent variables are continuous variables (e.g., player's age, player's height, career free throw percentage, average points per game) or categorical variables that do not need to be represented as dummy variables (e.g., the team had greater than 45 wins in the previous season).

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Answer:

[tex]\textsf{y=\frac{1}{3}x+3}[/tex][tex]y = \frac{1}{3} x+3[/tex]

Step-by-step explanation

[tex]\textsf{*slope intercept form: y = mx +b}[/tex]

---------------------------------------------

[tex]\textsf{x - 3y = -9}[/tex]

Subtract x from both sides:

[tex]\textsf{-3y = -x - 9}[/tex]

Divide both sides by -3:

-3y/-3 = -x/-3 - 9/-3

[tex]\textsf{y = 1/3x +3}[/tex]

[tex]-jurii[/tex]

The rise of the line that has a slope of 5/8 and a run of 16 is calculated as: 10.

The slope of a line is defined as the ratio of the rise of the line to the run of the line. This can also be defined as change in y over the change in x of a line.

Given the following:

Slope of a line (m) = 5/8

Run of the triangle = 16

Rise = x

Using the slope formula, we have:

Slope of a line (m) = rise/run

5/8 = x/16

Solve for x:

x = (5 * 16) / 8

x = 80/8

x = 10

Therefore, we can conclude that the rise is 10.

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Answer:

Please mark me the brainliest

Bank Balance  | Amount Owed

---------------------|-------------

-$150               | $150

-$325              | $325

-$275              | $275

To find the amount owed, we simply take the absolute value of each bank balance. The player who owes the greatest amount is the one with the largest absolute value bank balance. In this case, that would be Malcolm, who owes $325.

Step-by-step explanation:

Answer:

1/870 ≈ 0.0011494 or about 0.115% (rounded to 6 decimal places)

Step-by-step explanation:

The first digit can be any of the numbers between 10 and 40, except for those that end in 6 (since the last digit of all three numbers is 6). This leaves us with 30 numbers to choose from for the first digit. Similarly, the second digit can be any of the numbers between 10 and 40, except for those that end in 6 and the one chosen for the first digit. This leaves us with 29 numbers to choose from for the second digit.

For the third digit, we have only one option since we know it ends in 6.

So the total number of possible combinations is:

30 * 29 * 1 = 870

Out of these, only one combination is the correct one. Therefore, the probability of guessing the combination correctly on the first try is:

1/870 ≈ 0.0011494 or about 0.115% (rounded to 6 decimal places)

Answer:

Step-by-step explanation:

To determine if there is a positive linear association between the hours worked and the daily wages of waiters in a restaurant, you can create a scatter plot of the data and look for a pattern.

Once you have the data, you can use a statistical software or a spreadsheet program to create a scatter plot. You can then visually inspect the scatter plot to see if there is a clear pattern of a positive linear association between the two variables.

If there is a positive linear association, the data points on the scatter plot will form a roughly straight line that slopes upwards from left to right. The closer the data points are to the line, the stronger the association.

So, the data table that indicates a positive linear association between the hours worked and the daily wages of waiters in a restaurant is the one where the scatter plot shows a clear upward trend.

Check the picture below.

so if we just get the volume of the whole box, and the volume of the balls, if we subtract the volume of the balls from that of the whole box, what's leftover is the part we didn't subtract, namely the empty space.

[tex]\stackrel{ \textit{\LARGE volumes} }{\stackrel{ whole~box }{(3.5)(3.5)(12.1)}~~ - ~~\stackrel{\textit{three balls} }{3\cdot \cfrac{4\pi (1.65)^3}{3}}} \\\\\\ 148.225~~ - ~~17.9685\pi ~~ \approx ~~ \text{\LARGE 91.8}~cm^3[/tex]

The coefficient of x³ term in the power series expansion of f(x) = [tex]e^x[/tex] sin(x) is 1/15.

To find the coefficient of x³ term in the power series expansion of f(x) = [tex]e^x[/tex] sin(x), we need to write the Taylor series for [tex]e^x[/tex] and sin(x) and then multiply them to get the Taylor series for f(x). The Taylor series for e^x is:

[tex]e^x[/tex] = 1 + x + (x²/2!) + (x³/3!) + ...

The Taylor series for sin(x) is:

sin(x) = x - (x³/3!) + (x⁵/5!) - ...

Multiplying these two series, we get:

f(x) = [tex]e^x[/tex] sin(x) = (1 + x + (x²/2!) + (x³/3!) + ...) × (x - (x³/3!) + (x⁵/5!) - ...)

Expanding this out and collecting the terms with x³, we get:

f(x) = x - (x³/3!) + (7x³/5!) + ...

Therefore, the coefficient of x³ term in the power series expansion of f(x) = [tex]e^x[/tex] sin(x) is -1/6 + 7/120 = 1/15.

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The standard deviation of rainy days in March is approximately 2.55 days.

To find the standard deviation of rainy days in March, we first need to determine the expected value or the mean number of rainy days in March.

The expected value of a binomial distribution can be found using the formula: E(X) = np, where X is the random variable representing the number of rainy days in March, n is the number of trials (days in March), and p is the probability of success (rain) on a given day.

In this case, n = 31 (number of days in March) and p = 0.3 (probability of rain on any given day in March). Therefore, the expected value of rainy days in March is

E(X) = np = 31 × 0.3 = 9.3

Next, we need to find the variance of the binomial distribution, which is given by the formula: Var(X) = np(1 - p).

Var(X) = 31 × 0.3 × (1 - 0.3) = 6.51

Finally, the standard deviation of rainy days in March is the square root of the variance:

SD(X) = √Var(X) = √6.51 ≈ 2.55

Therefore, the standard deviation of rainy days in March is approximately 2.55 days.

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Phil's life expectancy is 56.3 years.

Based on the provided data, the life expectancy for Phil, a 21-year-old male, is 56.3 years. Therefore, the correct answer is 56.3 years.

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The equation which can be used to determine the total amount, t, Frankie will have spent after m months on his cell phone plan is t = 30 + 45m.

Given that,

Frankie has a new cell phone plan.

He will pay a one-time activation fee of 30$, and 45$ each month.

One time activation fee = $30

Amount each month = $45

Amount for m months = 45m

Total amount for the plan = 30 + 45m

If t represents the total amount for the cell phone activation plan, the required equation can be written as,

t = 30 + 45m

Hence the required equation for the cell phone plan is t = 30 + 45m.

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No, the number of sit-ups Anna does, is not proportional to the time she spends doing them.

When Anna starts doing sit-ups for her first triathlon, she does a sit-up every 22 seconds. But we know that as she gets tired, each sit-up takes longer and longer to do. The situps may take 40 seconds or 75 seconds as she gets more tired.

As we can see that there is no constant rate at which she gets tired and take more seconds to do sit-ups. In order to be proportional, the increasing or decreasing rate should be constant. We can see that the time she spends doing them is not increasing or decreasing at a constant rate along with the number of sit-ups she is doing.

Therefore, the number of sit-ups Anna does is not proportional to the time she spends doing them.

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The complete question is "Anna does sit-ups to get ready for her first triathlon. When she starts, she does a sit-up every 22 seconds. But, as she gets tired, each sit-up takes longer and longer to do. Is the number of sit-ups Anna does proportional to the time she spends doing them? "