Answer:
There were 378 students who chose to study French their freshman year. This means that 72% of the total number of students chose to study French their freshman year. Therefore, the total number of students must be 378 / 0.72 = 527.5. This means that there were 148.5 students who chose not to take French their freshman year.
Step-by-step explanation:
You pick a card at random.
1 2 3 4
What is P(factor of 24)?
Write your answer as a percentage rounded to the nearest tenth
Answer:
100%
Step-by-step explanation:
All of the numbers are factors of 24. So, picking a factor of 24 is guaranteed, so the probability is 1.
This is equal to 100%.
What is the slope of a line parallel to the line whose equation is 5x-3y=18
Slope and slant both refer to an incline away from a reference surface or line that is generally straight.The definition of slope is "a vertical inclination in an oblique direction"Here, the land abruptly slopes either upward or downhill.
How to Determine a Line's Slope?
slope,The inclination of a line with respect to the horizontal is measured numerically.The ratio of the vertical to the horizontal distance between any two points on a line, ray, or line segment is known as its slope in analytic geometry ("slope equals rise over run"). To determine how much the y coordinates have changed, find the difference.To determine how much the x coordinates have changed, find the difference.Find the slope by dividing y by x.
Y=mx+b, where m is the slope and b is the y-intercept, is the slope-intercept form.
y=mx+b
Change the formula to 3y+18=5x.
−3y+18=5x
From both sides of the equation, deduct 18.
−3y=5x−18
Simplify by multiplying each term in 3y=5x18 by 3.
Subtract 3 from each term in 3y=5x18.
−3y/−3=5x/−3+−18/−3
Make the left side simpler.
Tap to take additional steps:Y= -5X/3+-18/-3
Make the right side simpler.
Tap to take additional steps: y=5x/3+6
Write in the form y=mx+b.
Tap to take additional steps: y=5/3x+6
The slope is- 5/3 using the slope-intercept form.
.
m=−5/3
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if RS=2x+6 ST=x+4 and RT= 40 Find RS
RS + ST = RT
Substituting with data,
2x + 6 + x + 4 = 40
(2x + x) + (6 + 4) = 40
a portion of the graph of f(x) = -x^2 - 2x +8 is shown. which of the following describes all solutions for f(x)?
Given the function:
[tex]f(x)=-x^2-2x+8[/tex]Let's determine the expression which describes the solution for f(x).
From the graph, we can see the x-values go from -5 to 3.
The expression which describes the solution will be:
[tex](x,-x^2-2x+8),where-5\leq x\leq3[/tex]ANSWER:
[tex](x,-x^{2}-2x+8), where-5\leqslant x\leqslant3[/tex]Find the area of this trapezoid. Be sure to include the correct un4 cm6 cm4 cm15 cm
So,
Here we have the following trapezoid:
Remember that the area of a trapezoid can be found if we apply the following formula:
[tex]A=\frac{1}{2}(\text{base}1+\text{base}2)\cdot\text{height}[/tex]Where bases 1 and 2 are the greater and smaller bases respectively.
So, if we replace:
[tex]\begin{gathered} A=\frac{1}{2}(15+4)\cdot4 \\ A=\frac{1}{2}(19)\cdot4 \\ A=9.5\cdot4 \\ A=38 \end{gathered}[/tex]So the area is 38cm^2.
What it 3 1/8 + 3/4?
The given expression is:
[tex]\begin{gathered} 3\frac{1}{8}+\frac{3}{4}=3\frac{1+6}{8} \\ =3\frac{7}{8} \end{gathered}[/tex]Therefore, the value of the expression is:
3 7/8
.
The probability that the degree is not a bachelor's given that thr recipient Is male is
Answer
Probability that the degree is not a bachelor's given that thr recipient Is male = 0.36
Explanation
The probability of an event is calculated as the number of elements in the event divided by the total number of elements in the sample space.
For this question,
Number of degrees that are not bachelor's degree given to a male = Number of associate's degree given to a male = 239
Total number of males = 239 + 427 = 666
Probability that the degree is not a bachelor's given that thr recipient Is male = (239/666)
= 0.36
Hope this Helps!!!
Identify the value for C in the following equation that would make theconic section a hyperbola: 2x2 + y2 + 3x + 5y + 1 = 0
ANSWER:
C = -1
STEP-BY-STEP EXPLANATION:
We know that the general formula of hyperbola is the following
[tex]\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1[/tex]Which means that the sign must have y must be negative for it to be a hyperbola.
Therefore y must be equal to -1.
[tex]2x^2-1y^2+3x+5y+1=0[/tex]Consider the angle shown below with an initial ray pointing in the 3-o'clock direction that measures θ radians (where 0≤θ<2π). The circle's radius is 2 units long and the terminal point is (−1.79,−0.89).The terminal point is how many radius lenghts to the right of the circle's center?h= radii Then, cos−1(h)=Does the number we get in part (b) give us the correct value of θ? Therefore, θ=
Given the terminal point ( -1.79 , -0.89 )
So, the x- coordintes = -1.79
[tex]\begin{gathered} \theta=\cos ^{-1}h \\ \\ h=-\frac{1.79}{2} \\ \\ \theta=\cos ^{-1}(-\frac{1.79}{2})=206.5^o \end{gathered}[/tex]
Determine if the following lines are parallel (never intersect), perpendicular (intersect at a 90 degree angle), intersecting (intersect at just one point), or coinciding (intersect at all points)?y = -x + 11, 2y = -2x + 22
Given
The lines,
[tex]\begin{gathered} y=-x+11\text{ \_\_\_\_\_\lparen1\rparen} \\ 2y=-2x+22\text{ \_\_\_\_\_\_\lparen2\rparen} \end{gathered}[/tex]To find:
Whether the lines are perpendicular, coinciding, intersecting or parallel?
Explanation:
It is given that,
[tex]\begin{gathered} y=-x+11\text{ \_\_\_\_\_\lparen1\rparen} \\ 2y=-2x+22\text{ \_\_\_\_\_\_\lparen2\rparen} \end{gathered}[/tex]That implies,
Since the slope of the two lines are,
[tex]\begin{gathered} m_1=-1 \\ m_2=\frac{-2}{2}=-1 \\ \therefore m_1=m_2 \end{gathered}[/tex]Hence, the two lines are parallel.
Graph the equation. y = 2x 20 N 18 16 14 12 10 8 6 4 N. 0 1 2 3 4 ул 6 10 2. y = 2x
Make a table, and give values to x.
Solve the equation and obtain y values.
Graph the points and join them:
x = 0
y= 2x = 2 (0) = 0
x= 2
y= 2(2) = 4
x= 4
y= 2(4) = 8
Graph:
a normal distribution with u= 40 with o=4 what is the probability of selecting a score greater than x=44?
We have the following information:'
[tex]\begin{gathered} \mu=40 \\ \sigma=4 \\ x=44 \end{gathered}[/tex]We want to calculate the following probability:
[tex]P(X>44)[/tex]then, using the information that we are given, we havE:
[tex]P(X>44)=P(X-\mu>44-40)=P(\frac{X-\mu}{\sigma}>\frac{44-40}{4})=P(\frac{X-\mu}{\sigma}>1)[/tex]since:
[tex]Z=\frac{X-\mu}{\sigma}[/tex]we have the following:
[tex]P(X>44)=P(Z>1)=0.1587[/tex]therefore, the probability of selecting a score greater than 44 is 15.87%
DEF is a right triangle. If FE= 12 and DE= 5, find DF.
Answer:
DF = 13
Explanation:
The Pythagoras theorem says that
[tex]FE^2+ED^2=DF^2[/tex]Now in our case,
FE = 12
ED =
. Math and Science During winter months, freshwater fish sense the water getting colder and swim to the bottoms of lakes and rivers to find warmer water. If a fish 7 swims of the depth of a 32-foot deep lake, how many feet down did the fish swim?[tex]51[/tex]
The total depth of the lake is:
[tex]32\text{ ft}[/tex]And we need to find how many feet are 7/8 of the depth.
To find how much is 7/8 out of 32 ft what we do is multiply 32 by 7/8:
[tex]32\times\frac{7}{8}[/tex]This multiplication can also be represented as follows:
[tex]\frac{32}{8}\times7[/tex]We start by solving the division:
[tex]4\times7[/tex]and finally, we solve the multiplication:
[tex]4\times7=28[/tex]-->the fish swam 28 ft.
Answer: 28 ft
In college, we study large volumes of information- information that, unfortunately, we go not often retain for very long. The function f(x) = 80e +20 describes the percentage of information, fx), that a particular person remembers x weeks after learning the information. a. Substitute 0 for x and, without using a calculator, find the percentage of information remembered at the moment it is first learned. b. Substitute 1 for x and find the percentage of information remembered after 1 week C. Find the percentage of information that is remembered after 4 weeks. d. Find the percentage of information that is remembered after 1 year.
a)
[tex]f(0)=80\cdot e^{-0.5\cdot0}+20=100[/tex]b)
[tex]f(1)=80\cdot e^{-0.5}+20=68.52[/tex]c)
[tex]f(4)=80\cdot e^{-0.5\cdot4}+20=30.82[/tex]d)
[tex]f(48)=80\cdot e^{-0.5\cdot48}+20=20[/tex]What number is 3/4 of 17
3/4 of 17 is equal to the product of 3/4 times 17, that is,
[tex]\frac{3}{4}\times17=\frac{3\times17}{4}[/tex]which gives
[tex]\frac{3\times17}{4}=\frac{51}{4}[/tex]in decimal form, the answer is 12.75.
Question 1 4 pts Match each quadratic expression that is written as a product with an equivalent expression that is expanded. A. (x + 2)(x + 6) [Choose ] [Choose ] B. (2x + 3)(x + 2) 2x^2 + 10x + 12 X^2 + 12x + 32 C. (X + 8)(x + 4) x^2 + 8x + 12 2x^2 + 12x + 16 D. (x + + 2)(2x + 6) [Choose ]
(x +2) (x +6) ------> x^2 +8X + 12
(2x + 8) (x +2) -------> 2x^2 +12x + 16
(x +8) (x+4) ------------> x^2 +12x +32
(x + 2) (2x+6) ----------> 2x^2 +10x +12
Rectangle WXYZ has vertices located at W(−6, 4), X(−6,−1), Y(2,−1), and Z(2, 4) on a coordinate plane. It is translated 4 units right and 2 units down to produce rectangle W'X'Y'Z'. What is the location of the vertices of the transformed rectangle?
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
Rectangle WXYZ
W(−6, 4)
X(−6,−1)
Y(2,−1)
Z(2, 4)
Step 02:
Translated
4 units right ===> x + 4
2 units down ===> y - 2
W' (−6+4, 4 -2) = W' (-2, 2)
X' (−6+4,−1 - 2) = X' (-2,-3)
Y' (2+4,−1-2) = Y' (6,-3)
Z' (2+4, 4-2) = Z' (6, 2)
The answer is:
W' (-2, 2)
X' (-2,-3)
Y' (6,-3)
Z' (6, 2)
Solve the following system of linear equations by graphing.{5x - 2y = 10 {x - y = -1 Graph the equations on the same set of axes.Note: Use different points on each line when plotting the graphs.The solution point is: (_, _)
Kindly Check below
1) The first thing we need to do in this question, is to pick the method we are going to use to solve this system. Let's use the Elimination Method.
2) So, let's solve this system analytically (algebraically):
[tex]\begin{gathered} 5x-2y=10 \\ x-y=-1\:\:(\times-2) \\ \\ 5x-2y=10 \\ -2x+2y=2 \\ ------- \\ 3x=12 \\ \\ \frac{3x}{3}=\frac{12}{3} \\ \\ x=4 \end{gathered}[/tex]Now, let's plug into the 2nd original equation x=4 and solve it for y:
[tex]\begin{gathered} x-y=-1 \\ \\ 4-y=-1 \\ \\ -y=-1-4 \\ \\ y=5 \end{gathered}[/tex]So we know the solution is (4,5).
3) Now, let's graph these equations by setting two t-tables. Let's rewrite those equations from the Standard form to the Slope-intercept form.
5x-2y=10 -2y=10-5x, y=-5+5/2x
x-y=-1,-y=-1-x, y=x+1
4) Now, let's plot those points and trace the lines through them
(-2,-10), (-1,-7.5), (0,-5), (1,-2.5), (2,0)
(-2,-1), (-1,0), (0,1), (1,2), (2,3)
What is the diameter of a circle with radius 15
Given Data:
The radius of the circle is r=15.
The diameter of the circle can be determined as,
[tex]\begin{gathered} d=2r \\ =2\times15 \\ =30 \end{gathered}[/tex]Thus, the required diameter of a circle is 30.
what is 1 5/8 + 2 1/3=
1 5/8 + 2 1/3
= 3 23/24
Explanation:1 5/8 + 2 1/3
= 1 + 2 + 5/8 + 1/3
= 3 + 23/24
= 3 23/24
9(11 - x) = 3(3x -9) what is x
x = 7
Explanation:9(11 - x) = 3(3x -9)
Expanding the expression:
9(11) - (9x) = 3(3x) -3(9)
99 - 9x = 9x - 27
collect like terms:
99 + 27 = 9x + 9x
126 = 18x
Divide both sides by 18:
126/18 = 18x/18
x = 7
...
>
Question
A triangle with area 40 square inches has a height that is four less than six times the width. Find the width and height of the
triangle
Provide your answer below:
width:
inches, height:
inches
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SUBMIT
Math
SOLUTION
Given the question, the following are the solution steps to answer the question.
STEP 1: Write the formula for the area of the triangle
[tex]Area=\frac{1}{2}\times base\times height[/tex]STEP 2: Represent the statements to get an equation
[tex]\begin{gathered} width=base \\ From\text{ the statement,} \\ six\text{ times of the width}=6w \\ four\text{ less than six times the width }=6w-4 \\ \therefore height=6w-4 \end{gathered}[/tex]STEP 3: Substitute into the formula in step 1
[tex]\begin{gathered} height=6w-4,width=base=w,Area=40in^2 \\ Area=\frac{1}{2}\times w\times(6w-4) \\ Area=\frac{w(6w-4)}{2}=\frac{6w^2-4w}{2}=40 \end{gathered}[/tex]STEP 4: Cross multiply
[tex]\begin{gathered} 6w^2-4w=40\times2 \\ 6w^2-4w=80 \\ Subtract\text{ 80 from both sides} \\ 6w^2-4w-80=80-80 \\ 6w^2-4w-80=0 \\ Divide\text{ through by 2, we have:} \\ 3w^2-2w-40=0 \\ By\text{ factorization;} \\ 3w^2-12w+10w-40=0 \\ 3w(w-4)+10(w-4)=0 \\ (w-4)(3w+10)=0 \end{gathered}[/tex]STEP 5: Find the values of w
[tex]\begin{gathered} w-4=0,w=0+4,w=4 \\ 3w+10=0,3w=0-10,3w=-10,w=\frac{-10}{3} \\ \\ Since\text{ the width cannot be negative, width=4 inches} \end{gathered}[/tex]STEP 6: Find the height
[tex]\begin{gathered} Recall\text{ from step 2:} \\ h=6w-4 \\ Substitute\text{ 4 for w} \\ h=6(4)-4=24-4=20in \end{gathered}[/tex]Hence,
width = 4 inches
height = 20 inches
You have two spinners each with three sections of equal size labeled with numbers 1,2,3. You spin both and observe the numbers. Let x be the sum of the two numbers. Find the probability distribution for X.
From the given problem with two spinners with three sections of equal size labeled as 1, 2, and 3.
Spinner 1 : 1 2 3
Spinner 2 : 1 2 3
The sum is as follows :
1+1 = 2
1+2 = 3
1+3 = 4
2+1 = 3
2+2 = 4
2+3 = 5
3+1 = 4
3+2 = 5
3+3 = 6
There are 9 total outcomes
There are (1) 2,
(2) 3's
(3) 4's
(2) 5's
and
(1) 6
and their corresponding probability can be calculated by :
[tex]\text{probability}=\frac{\text{ quantity}}{\text{ total quantity}}[/tex]Probability of 2 = 1/9
Probability of 3 = 2/9
Probability of 4 = 3/9 or 1/3
Probability of 5 = 2/9
Probability of 6 = 1/9
Construct the probability distribution :
To check if your probability distribution is correct.
The sum of P(X) must be equal to 1
1/9 + 2/9 + 1/3 + 2/9 + 1/9 = 1
Therefore the distribution is correct.
Which of the following statements is not true based on the given graph?abd0OlbicasbCO
The Solution.
From the given number line graph, we can see clearly that the following option are true.
[tex]undefined[/tex]The only option that is not true is
[tex]undefined[/tex]Students were divided into 10 teams with 12 on each team. later, the same day students were divided into teams with 3 on each team. how many teams were there then?
At first, the students were divided into 10 teams with 12 on each of them; we can write this as:
team 1 = 12 students
team 2 = 12 students
team 3 = 12 students
team 4 = 12 students
team 5 = 12 students
team 6 = 12 students
team 7 = 12 students
team 8 = 12 students
team 9 = 12 students
team 10 = 12 students
Sum up the number all the students and this adds up to: 120 students.
Then, the question says these 120 students were divided into teams with 3 students on each team.
This time the number of teams created will be more.
team 1 = 3 students
team 2 = 3 students
teams 3 = 3 students
...
And so on.
In order to get the number of teams, we simply divide the number of students by the number of students in a team.
[tex]\frac{120}{3}=40\text{ teams}[/tex]Therefore, the number of 3 person teams are 40 teams
A right triangle is shown in the graph.
right triangle on coordinate plane with hypotenuse labeled t and one endpoint of hypotenuse at r comma s and the other endpoint at x comma y, vertical line from point x comma y and horizontal line from r comma s that meet at right angle of triangle, horizontal dotted line from point r comma s to point s on y axis, horizontal dotted line from point x comma y to point y on y axis, vertical dotted line from point r comma s to point r on x axis, and vertical dotted line from right angle to point x on x axis
Part A: Use the Pythagorean Theorem to derive the standard equation of the circle with center at (r, s) and a point on the circle at (x, y). Show all necessary math work. (3 points)
Part B: If (r, s) = (7, –4) and t = 10, determine the domain and range of the circle. (4 points)
Part C: Is the point (9, 1) inside the border of the circle if (r, s) = (7, –4) and t = 10? Explain using mathematical evidence. (3 points
Part a: The standard equation of circle: (x - r)² + (y - s)² = t².
Part b: Domain = {17, -3} and Range = {-14, 6}.
Part c: Point (9, 1) lies inside the circle.
What is termed as the Pythagorean Theorem?The Pythagorean theorem, or Pythagorean theorem, explains the relation between the three sides of such a right-angled triangle. The the hypotenuse's square is equal to the total of the squares of the remaining two sides of a triangle, according to Pythagoras' theorem.For the given question,
The right triangle are given with two of ts vertices as (r, s) and (x, y).
The distance between these two points is 't'.
Part a: The standard equation of the circle.
Centre of circle = (r,s) and
Point on the circle = (x, y)
Using Pythagorean Theorem,
(x - r)² + (y - s)² = t²
Thus, the standard equation of the circle is (x - r)² + (y - s)² = t²
Where, t is the radius of the circle.
Part b: Domain and range.
(r, s) = (7, –4) and t = 10,
For x values in the domain r ± t and y values in the range s ± t, the circle would be defined.
Domain = 7 ± 10 = {17, -3}
Range = -4 ± 10 = {-14, 6}
Part c: Point (9, 1) lies inside or not.
(r, s) = (7, –4) and t = 10
Point (9, 1) = (x, y)
Put the values;
(x - r)² + (y - s)² ≤ t²
(9 - 7)² + (1 + 4)² ≤ 10²
2² + 5² ≤ 10²
4 + 25 ≤ 100
29 ≤ 100
Thus, the points (9, 1) lies inside the circle.
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A traffic light weighing 16 pounds is suspended by two cables (see figure). Find the tension in each cable. (Round your answers to one decimal place.) lb (smaller value) lb (larger value)
Step 1: Draw an image to illustrate the problem
Consider the forces along the horizontal axis.
[tex]\begin{gathered} -T_1\cos \theta_1+T_2\cos \theta_2=0 \\ \text{ therefore} \\ T_2\cos 20^0=T_1\cos 20^0 \end{gathered}[/tex][tex]\text{ Dividing both sides by }\cos 20^0[/tex][tex]\begin{gathered} \frac{T_2\cos20^0}{\cos20^0}=\frac{T_1\cos 20^0}{\cos 20^0} \\ \text{thus} \\ T_2=T_1 \end{gathered}[/tex]Consider the forces along the vertical axis.
[tex]\begin{gathered} T_1\sin 20^0+T_2\sin 20^0-16=0 \\ T_1\sin 20^0+T_1\sin 20^0-16=0\text{ (}T_1=T_2) \\ \text{ Thus} \\ 2T_1\sin 20^0=16 \\ T_1=\frac{16}{2\sin 20^0}\approx23.39\text{ pounds} \end{gathered}[/tex]then T₁ = 23.39 pounds
Since T₁=T₂, then T₂ = 23.39 pounds
Hence, smaller value = 23.4 pounds to one decimal place and
larger value = 23.4 pounds to one decimal place
why you can always solve a right triangle if you know the measures of one side and one acute angle.
In a right triangle, one angle is always 90.
If you know one acute angle, you automatically know the other (3rd) angle.
3 angles are solved.
Now, comes the sides.
If you already know 1 side, you can easily know another side by using the basic trig identities SIN, COS, or TAN.
When you know 2 sides, the 3rd side can always be find using:
• pythagorean theorem, or
,• again, trigonometric ratios (sin, cos, tan).
find a b c d e f from the picture
Given data:
The value of a is (3+4+2)=9
The value of b is (5+1+2)=8
The value of c is (1+8+1)=10
The value of d is (