State the number of complex zeros and the possible number of real and imaginary zeros for each function. Then find all zeros. show all work

State The Number Of Complex Zeros And The Possible Number Of Real And Imaginary Zeros For Each Function.

Answers

Answer 1

We have a cubic function

[tex]f(x)=x^3-3x^2-47x-87[/tex]

One way to find all the zeros is by factoring, we can easily find the first zero using the divisors test if we have an independent term, at our case it's -87, one of the divisors may be a zero. The divisors of -87 is 1, 3, 29 and 87.

If we check for all of the divisors we will see that -3 is a zero. (Check with both signals).

If -3 is a zero, the D'Alembert theorem tells us that f(x) is divisible by (x+3), if we do that division we'll have a quadratic function where we can just apply the quadratic formula, then

There's a theorem that says that, if f(a) is a zero, i.e f(a) = 0, and f(x) is a polynomial, then f(x) is divisible by (x-a), in other words, we can divide f(x) by (x-a) and the rest of the division will be 0.

Therefore, let's divide our function by (x+3)

Then we can write our function as

[tex]f(x)=(x+3)(x^2-6x-29)[/tex]

Look that now we have a quadratic function, and we can easily find its zeros, applying the quadratic formula

[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]

We have a = 1, b = -6 and c = -29. Then

[tex]\begin{gathered} x=\frac{6\pm\sqrt[]{36+4\cdot29}}{2} \\ \\ x=\frac{6\pm\sqrt[]{156}}{2} \\ \\ x=\frac{6\pm2\sqrt[]{38}}{2} \\ \\ x=3\pm\sqrt[]{38} \end{gathered}[/tex]

Now we have all the zeros of f(x), it's

[tex]\begin{gathered} x=-3 \\ \\ x=3+\sqrt[]{38} \\ \\ x=3-\sqrt[]{38} \end{gathered}[/tex]

As we can see there's no complex zero, all the zeros are real numbers.

The max number of complex zeros is 2 because the complex zeros always come in pairs, so if we have 1 complex zero, automatically we have another, for a 3-degree equation, there's a maximum of 2 complex zeros and 1 real zero, or all the of them are real.

Then the correct answer is A)

State The Number Of Complex Zeros And The Possible Number Of Real And Imaginary Zeros For Each Function.

Related Questions

50 Points
A rectangle has sides measuring (2x + 5) units and (3x + 7) units.
Part A: What is the expression that represents the area of the rectangle? Show your work.
Part B: What are the degree and classification of the expression obtained in Part A?

Part C: How does Part A demonstrate the closure property for the multiplication of polynomials?

Answers

The expression that represents the area of the rectangle is 6x²+29x+35.

Given that, a rectangle has sides measuring (2x + 5) units and (3x + 7) units.

What is the area of a rectangle?

The area occupied by a rectangle within its boundary is called the area of the rectangle. The formula to find the area of a rectangle is Area = Length × Breadth.

Part A:

Now, area = (2x+5)(3x+7)

= 2x(3x+7)+5(3x+7)

= 6x²+14x+15x+35

= 6x²+29x+35

So, the area of a rectangle is 6x²+29x+35

Part B:

A polynomial's degree is the highest or the greatest power of a variable in a polynomial equation.

Here, the degree of the expression 6x²+29x+35 is 2.

Part C:

Closure property of multiplication states that if any two real numbers a and b are multiplied, the product will be a real number as well.

Here, we obtained product of two binomials is trinomial

Therefore, the expression that represents the area of the rectangle is 6x²+29x+35.

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The graph of f(a) = > has been transformed to create the graph of g(s) =

Answers

EXPLANATION

The graph of the parent function: f(x) = 1/x has the following form:

Translating the function two units to the left, give us the Image function:

This function is obtained by adding two units to the denominator.

In conclusion, the solution is -2

What is the length of the arc ? ( Precalc )

Answers

We're going to use the following formula:

[tex]L=2\cdot\pi\cdot r\cdot\frac{\theta}{360}[/tex]

If we replace our values:

[tex]L=2\cdot\pi\cdot3\cdot\frac{60}{360}=\pi[/tex]

Therefore, the length is pi.

Express M in terms of B and n: B = 3Mn 2

Answers

We are given the expression B=3Mn/2 and told to express M in terms of B and n. This means that we should apply mathematical operations on both sides of the equation so we "isolate " M on one side of the equality sign. We begin with the given equation

[tex]B=\frac{3\cdot M\cdot n}{2}[/tex]

First, we multiply both sides by 2, so we get

[tex]2\cdot B=3\cdot M\cdot n[/tex]

Next, we divide by 3 on both sides, so we get

[tex]\frac{2\cdot B}{3}=M\cdot n[/tex]

Finally, we divide both sides by n, so we get

[tex]\frac{2\cdot B}{3\cdot n}=M[/tex]

In this case, we have succesfully expressed M in terms of B and n

The dog looked at the cat warily A with interestb viciously c hungrily d with caution

Answers

Answer

Option D is correct.

The dog looked at the cat with caution.

is the same as

The dog looked at the cat warily.

Explanation

The word warily means 'using caution' or 'cautiously'.

Hope this Helps!!!

The table gives a set of outcomes and their probabilities. Let A be the event the outcome is divisible by 3". Find P(A). 12 Outcome Probability Tim elaps 1 0.14 PAUS 2 0.02 3 0.19 Smart out of 4 0.01 5 0.04 7 6 0.17 7 0.15 8 0.28

Answers

Here, we want to get the probability that a selected outcome is divisible by 3

What we have to do here is ti select numbers that are multiples of 3 and add their probabilities

From the given table, the outcomes that are multiples of 3 are;

3 and 6 only

So, we proceed to add the probabilities of these outcomes

Mathematically, we have this as;

[tex]P(A)\text{ = 0.19 + 0.17 = 0.36}[/tex]

A set of pool balls contains 15 balls numbered 1-15.
Without replacement: What is the probability that an odd number ball is picked
out of a box twice without the first one being replaced?
With replacement: What is the probability that an even number ball is picked with
the first ball drawn being inserted back into the box?

Answers

Step-by-step explanation:

a probability is always

desired cases / totally possible cases

the first case I assume means that we need the probability to pick 2 odd-numbered balls in a row, if we do not put the first drawn ball back into the box.

starting condition :

15 basks in total.

1, 3, 5, 7, 9, 11, 13, 15 = 8 odd numbered balls

2, 4, 6, 8, 10, 12, 14 = 7 even numbered balls

the probability for the first ball to be odd numbered :

8/15

now we have

14 remaining balls in total.

7 remaining odd numbered balls.

the probability of the second ball being odd numbered is

7/14 = 1/2

so, the probability of both as one combined event is

8/15 × 1/2 = 4/15 = 0.266666666...

now back to the starting condition.

the probability to pick an even numbered ball is

7/15

we put the ball back in and pull a second time.

the probability to an even numbered ball is

7/15

so, the probability of both as one combined event is

7/15 × 7/15 = 49/225 = 0.217777777...

Lesson 6.07: In a random sample of 74 homeowners in a city, 22 homeowners said they wouldsupport a ban on nonnatural lawn fertilizers to protect fish in the local waterways. The samplingmethod had a margin of error of +3.1%. SHOW ALL WORK!A) Find the point estimate.B) Find the lower and upper limits and state the interval.

Answers

Confidence interval is written in the form,

(point estimate +/- margin of error)

The given scenario involves population proportion

The formula for the point estimate is

p' = x/n

where

p' = estimated proportion of success. p' is a point estimate for p which is the true proportion

x represents the number of success

n represents the number of samples

From the information given,

n = 74

x = 22

p' = 22/74 = 0.297

The formula for finding margin of error is expressed as

[tex]\begin{gathered} \text{margin of error = z}_{\frac{\alpha}{2}}(\sqrt[]{\frac{p^{\prime}q^{\prime}}{n}} \\ q^{\prime}\text{ = 1 - p'} \\ q^{\prime}\text{ = 1 - 0.297 = 0.703} \end{gathered}[/tex]

A) The point estimate is 0.297

B) margin of error = +/-3.1% = 3.1/100 = +/- 0.031

Thus,

the lower limit would be 0.297 - 0.031 = 0.266

Expressing in percentage, it is 0.266 x 100 = 26.6%

the upper limit would be 0.297 + 0.031 = 0.328

Expressing in percentage, it is 0.328 x 100 = 32.8%

Thus, the confidence interval is between 26.6% and 32.8%

I need to help finding the length of the arc shown in red..

Answers

We have the next formula to find the length is

[tex]\text{arc length }=\text{ 2}\pi r(\frac{\theta}{360})[/tex]

where

r=10

theta=45°

[tex]\begin{gathered} \text{arc length=}2\pi(10)\frac{45}{360}=\frac{5}{2}\pi \\ \end{gathered}[/tex]

the arc length is 5/2 pi cm

You start at (9,2). you move left 9 units. where do you end

Answers

If you start at (9,2) and then move left 9 units, you'll end up at (0, 2)

How many different lineups can Coach Lay create using 10 girls to fill 5 spots on the basketball court. Positions do not matter.

Answers

This is the formula for combinations

In this case, n = 10 and k = 5

C = 10!/(10-5)!(5)! = 3628800/(120)(120) = 3628800/14400 = 252

Answer:

252 different line u

A golf course charges you $54 for a round of golf using a set of their clubs, and $42 if you have your own clubs. You decide to buy a set of clubs for $280 and your friend wants to just use the course's clubs.a. Write an equation to describe the cost for x number of rounds for you.b. write an equation to describe the cost for x number of rounds for your friend.c. How many rounds must you play to recover the cost of the clubs? (Find the break-even point).

Answers

Answer

You must play 24 rounds to recover the cost of the club

Step-by-step explanation:

The amount golf charged for using their set clubs = $54

They charged $42 for using personal course

let x be the number of rounds played

let y be the total cost of the clubs

Since you will be buying a set of clubs worth $280

Then, the first equation is

a. y = 280 + 42x

b. y = 54x

c . Calculate the number of rounds that must be played to recover the cost of the clubs

To calculate this, we need to equate equations a and b together

280 + 42x = 54x

Collect the like terms

280 = 54x - 42x

280 = 12x

Isolate x by dividing through by 12

280/12 = 12x/12

x = 23.3333

Hence, you must play 24 rounds to recover the cost of the club

the day of the lowest show the most ever in a single day by random sample of 13 students calculate the 38th and the 60th percentile of data

Answers

We have that the sample consist in n=13 students. The percentile formula is given by

[tex]P_x=\frac{x}{100}\times n\text{ position}[/tex]

where x denotes the percentaje. In the first case, p=38, then, we have

[tex]\begin{gathered} P_{38}=\frac{38}{100}\times13\text{ position} \\ P_{38}=4.94\text{ position} \end{gathered}[/tex]

then, we get

[tex]P_{38}=41[/tex]

that is, P_38 corresponds to 41 miles driven.

In the second case, by substituting x=60 in our formula, we get

[tex]\begin{gathered} P_{60}=\frac{60}{100}\times13\text{ position} \\ P_{60}=7.8\text{ position} \end{gathered}[/tex]

which gives

[tex]P_{60}=56[/tex]

that is, P_60 corresponds to 56 miles driven.

Then, the answers are:

[tex]P_{38}=41[/tex]

This means that approximately 38% of the data lie below 41, when the data are ranked.

[tex]P_{60}=56[/tex]

This means that approximately 60% of the data lie below 56, when the data are ranked.

Priya is mixing drops of food coloring to create purple frosting for a cake. She uses 24 drops of red dye and 16 drops of blue dye. Find the ratio of drops of red dye to total drops of dye. Express as a simplified ratio.

Answers

Priya uses 24 drops of red dye,

She also uses 16 drops of blue dye,

[tex]\begin{gathered} \text{Total drops of dye=}24+16 \\ =40\text{drops of dye} \end{gathered}[/tex]

We are told to find the ratio of drops of red dye to the total drops dye.

[tex]=\frac{\text{red drops of dye}}{\text{total drops of dye}}[/tex][tex]\begin{gathered} =\frac{24}{40}=\frac{3}{5} \\ =3\colon5 \end{gathered}[/tex]

Hence, the ratio of drops of red die to the total drops of die to the simplest rato is

3 : 5.

The volume, V, of a cube with edge length s cm is given by the equation V=s3.Is the volume of a cube with edge length s=3 greater or less than the volume of a sphere with radius 3?If a sphere has the same volume as a cube with edge length 5, estimate the radius of the sphere?Compare the outputs of the two volume functions when the inputs are 2?

Answers

We have that the volume of sphere is

[tex]\begin{gathered} V_s=\frac{4}{3}\pi\cdot r^3 \\ \end{gathered}[/tex]

and the volume of a cube is

[tex]V_c=s^3[/tex]

so if s=r=3. The volume of the sphere is greater.

If they have the same volume, we get that

[tex]\begin{gathered} \frac{4}{3}\pi\cdot r^3=125\rightarrow \\ r^3=\frac{3}{4\cdot\pi}\cdot125\approx29.84\approx30 \\ r=\sqrt[3]{30}\approx3.10 \end{gathered}[/tex]

when s=r=2 we have that

[tex]\begin{gathered} V_s=\frac{4}{3}\pi\cdot8=\frac{32}{3}\pi \\ V_c=8 \end{gathered}[/tex]

so the volume of the sphere is greater

Ali borrowed Php22,000 for 3months at the discount rate of 5 ¼ % from a bank. Find the (a) bank’s discount and (b) proceeds.

Answers

If an M amount is borrowed for a time t at a discount rate of r per year, then the discount D is calculated as

[tex]\begin{gathered} D=M\cdot r\cdot t \\ \\ \text{where} \\ r\text{ is expressed in decimals} \end{gathered}[/tex][tex]\begin{gathered} \text{Given} \\ M=22000 \\ r=5\frac{1}{4}\%\rightarrow5.25\%\rightarrow0.0525 \\ t=\mleft(\frac{3}{12}\mright)\text{or }0.25\text{ (3 months out of 1 year or 12 months} \end{gathered}[/tex]

Substitute the following values to get the bank's discount.

[tex]\begin{gathered} D=Mrt \\ D=(22000)(0.0525)(\frac{3}{12}) \\ D=288.75 \end{gathered}[/tex]

Therefore, the bank's discount is Php 288.75.

To calculate for proceeds, subtract the amount borrowed by the bank's discount.

[tex]\begin{gathered} P=M-D \\ P=22000-288.75 \\ P=21711.25 \end{gathered}[/tex]

The proceeds given to Ali is Php 21,711.25.

9. A researcher gathered data on hours of video games played by school-aged children and young adults. She collected the following data:601241215171711409914110131015163915121698131016651717129(a) Complete the frequency distribution for the data.HoursFrequencyRelative Frequency0-23-56-89-1112-1415-17(b) Which of the following is the correct histogram for this data?246810Hours0369121518Frequency[Graphs generated by this script: setBorder(54,40,20,15); initPicture(0,18,0,10);axes(34,2,1,null,2); fill="blue"; textabs([165,0],"Hours","above");line([0,-0.2],[0,0.2]); text([0,0],"0","below");line([3,-0.2],[3,0.2]); text([3,0],"3","below");line([6,-0.2],[6,0.2]); text([6,0],"6","below");line([9,-0.2],[9,0.2]); text([9,0],"9","below");line([12,-0.2],[12,0.2]); text([12,0],"12","below");line([15,-0.2],[15,0.2]); text([15,0],"15","below");line([18,-0.2],[18,0.2]); text([18,0],"18","below");textabs([0,115],"Frequency","right",90);rect([0,0],[3,6]);rect([3,0],[6,4]);rect([6,0],[9,5]);rect([9,0],[12,7]);rect([12,0],[15,6]);rect([15,0],[18,10]);]246810121416Hours061218Frequency[Graphs generated by this script: setBorder(54,40,20,15); initPicture(0,18,0,16);axes(34,2,1,null,2); fill="blue"; textabs([165,0],"Hours","above");line([0,-0.32],[0,0.32]); text([0,0],"0","below");line([6,-0.32],[6,0.32]); text([6,0],"6","below");line([12,-0.32],[12,0.32]); text([12,0],"12","below");line([18,-0.32],[18,0.32]); text([18,0],"18","below");textabs([0,115],"Frequency","right",90);rect([0,0],[6,10]);rect([6,0],[12,12]);rect([12,0],[18,16]);]2468101214Hours061218Frequency[Graphs generated by this script: setBorder(54,40,20,15); initPicture(0,18,0,14);axes(34,2,1,null,2); fill="blue"; textabs([165,0],"Hours","above");line([0,-0.28],[0,0.28]); text([0,0],"0","below");line([6,-0.28],[6,0.28]); text([6,0],"6","below");line([12,-0.28],[12,0.28]); text([12,0],"12","below");line([18,-0.28],[18,0.28]); text([18,0],"18","below");textabs([0,115],"Frequency","right",90);rect([0,0],[6,12]);rect([6,0],[12,14]);rect([12,0],[18,12]);]2468Hours0369121518

Answers

(a)

Remember that the frequency refers to the number of times a data shows up. In this case, the frequency is the number of data that falls into each interval.la

To find the relative frequency is calculated by dividing each frequency by 38 (the total number of data).

[tex]\begin{gathered} \frac{6}{38}=0.1579 \\ \frac{4}{38}=0.1053 \\ \frac{4}{38}=0.1053 \\ \frac{8}{38}=0.2105 \\ \frac{7}{38}=0.1842 \\ \frac{9}{38}=0.2368 \end{gathered}[/tex]

Let's include the relative frequencies in the table.

On the other hand, the correct histogram has to show the frequencies in the same order. The following histogram shows the correct frequency distribution.

Section 11 - Topic 5Probability and Independence• In your own words, describe what the word independeyou.Now describe dependent..

Answers

In probability , there are two events independent events and dependent events.

Independent Events :

Two events A and B are said to be independent if the fact that one event has occurred does not affect the probability that the other event will occur.

Example

. Choosing a marble from a jar AND landing on heads after tossing a coin.

Dependent Events :

If whether or not one event occurs does affect the probability that the other event will occur, then the two events are said to be dependent.

Example

Buying ten lottery tickets and winning the lottery.

Please help me I need the answer asap.

Answers

Therefore the right answer is option D = 1. The values of the variables will be obtained when the system of linear equations is solved; this is referred to as the solution of a linear equation.

What are linear equations?An equation with the form Ax+By=C is referred to as a linear equation. It consists of two variables combined with a constant value that exists in each of them. The values of the variables will be obtained when the system of linear equations is solved; this is referred to as the solution of a linear equation. If an equation has the formula y=mx+b, with m representing the slope and b the y-intercept, it is said to be linear.A two-variable linear equation can be thought of as a linear relationship between x and y, or two variables whose values rely on each other (often y and x) (usually x).

Hence,

The correct Option is D = 1

Given

[tex]x^2+x-1\\[/tex] = 0

[tex]\frac{1-x}{2x^2} +\frac{ x^2}{2x-2}[/tex] = ?

From  [tex]x^2+x-1\\[/tex] = 0

[tex]x^2 = 1-x[/tex]

Therefore,

[tex]\frac{1-x}{2x^2} +\frac{ x^2}{2x-2}[/tex]  =  [tex]\frac{x^2}{2x^2} + \frac{x^2}{2(x-1)}[/tex]

[tex]\frac{1}{2} + \frac{x^2}{2(x-1)}[/tex]

[tex]\frac{1}{2} + \frac{1}{2}[/tex]

= 1

Therefore the right answer is option D = 1

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Solve the equation for solutions in the interval [0°, 360°). Round to the nearest degree.

Answers

We will have the following:

[tex]\sin (2\theta)=-\frac{1}{2}\Rightarrow2\theta=2\pi n_1+\frac{7\pi}{6}[/tex][tex]\Rightarrow\theta=\pi n_1+\frac{7\pi}{12}[/tex]

Now, we will solve for the following:

[tex]\Rightarrow\pi n_1+\frac{7\pi}{12}\le2\pi\Rightarrow\pi n_1\le\frac{17\pi}{12}[/tex][tex]\Rightarrow n_1\le\frac{17}{12}[/tex]

This value in degrees is:

[tex]\frac{17}{12}\text{radians}=81.169\text{degrees}[/tex]

So, the solution is located in the interval:

[tex]\lbrack0,81\rbrack[/tex]

At a point on the ground 35 ft from base of a tree, the distance to the top of the tree is 1 ft more than 3 times the height of the tree. Find the height of the tree. The height of the tree is ___. (ft^3, ft^2, or ft)(Simply your answer. Round to the nearest foot as needed)

Answers

At a point on the ground 35 ft from the base of a tree, the distance to the top of the tree is 1 ft more than 3 times the height of the tree. Find the height of the tree

see the attached figure to better understand the problem

Applying the Pythagorean Theorem

(3h+1)^2=h^2+35^2

9h^2+6h+1=h^2+1,225

solve for h

9h^2-h^2+6h+1-1,225=0

8h^2+6h-1,224=0

Solve the quadratic equation

Using a graphing tool

the solution is

h=12 ft

The area of an equilateral triangle is decreasing at a rate of 3 cm2/min. Find the rate (in centimeters per minute) at which the length of a side is decreasing when the area of the triangle is 100 cm2.

Answers

The rate at which the length of a side is decreasing when the area of the triangle is 100 cm² is equal to -0.227 centimeters per minute.

What is rate of change?

Rate of change is a type of function that describes the average rate at which a quantity either decreases or increases with respect to another quantity.

How to calculate the area of an equilateral triangle?

Mathematically, the area of an equilateral triangle can be calculated by using this formula;

A = (√3/4)s²

Where:

A represents the area of an equilateral triangle.s represents the side length of an equilateral triangle.

Next, we would determine the side length of a square by making s the subject of formula as follows:

s = (√4A)/√3

s = (√4 × 100)/√3

Side length, s = 15.20

Note: The rate of change (dA/dt) is negative because it is decreasing.

By applying chain rule of differentiation, the rate of change (dA/dt) in area of this equilateral triangle with respect to time is given by:

dA/dt = (√3/4)(2s)ds/dt

dA/dt = (√3/4) × (2 × 15.20) × -3

dA/dt = -0.227 centimeters per minute.

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how do you work the problem 3k+16=5k?

Answers

We have the following:

[tex]3k+16=5k[/tex]

solving for k

[tex]\begin{gathered} 5k-3k=16 \\ k=\frac{16}{2} \\ k=8 \end{gathered}[/tex]

The value of k is 8

Find the equation of the tangent line to the curve y = x^3- 4x - 5 at the point (2, -5).Tangent Line Equation:

Answers

Let's find the derivative of y:

[tex]\begin{gathered} y=x^3-4x-5 \\ \frac{dy}{dx}=3x^2-4 \end{gathered}[/tex]

Evaluate the derivative for x = 2:

[tex]\frac{dy}{dx}\begin{cases} \\ x=2\end{cases}=3(2)^2-4=12-4=8[/tex]

Now, we have the slope, let's use the point-slope formula to find the equation:

[tex]\begin{gathered} y-y1=m(x-x1) \\ _{\text{ }}where\colon \\ (x1,y1)=(2,-5) \\ m=8 \\ y+5=8(x-2) \\ y+5=8x-16 \\ y=8x-21 \end{gathered}[/tex]

Answer:

y = 8x - 21

A container built for transatlantic shipping is constructed in the shape of a right rectangular prism. Its dimensions are 9.5 ft by 5.5 ft by 9 ft. The container is entirely full. If, on average, its contents weigh 0.99 pounds per cubic foot, and, on average, the contents are worth $4.37 per pound, find the value of the container’s contents. Round your answer to the nearest cent.

Answers

step 1

Find out the volume of the rectangular container

[tex]V=L\cdot W\cdot H[/tex]

Substitute given values

[tex]\begin{gathered} V=9.5\cdot5.5\cdot9 \\ V=470.25\text{ ft3} \end{gathered}[/tex]

step 2

Find out the weight of the container

Multiply the volume by the density of 0.99 pounds per cubic foot

0.99*470.25=465.5475 pounds

step 3

Multiply the weight by the factor of $4.37 per pound

so

4.37*465.5475=$2,034.44

therefore

The answer is $2,034.44

Anna's room is a rectangle. Its length is 15 feet and its width is 4 yards. What is the perimeter of the room?

Answers

Answer:

38

Step-by-step explanation:

Perimeter is basically each side added together. 15 + 15 + 4 + 4 is 38. Therefore, it's 38.

John starting playing video games as soon as he got home from school. He played videogames for 45 minutes. Then, it took John 30 minutes to finish his homework. When Johnfinished his homework, it was 4:25 P.M. What time did John get home from school?

Answers

Given:

After coming from school to home,

He played video games for 45 minutes.

Then he took 30 minutes to finish his homework.

When John finished his homework, it was 4:25 PM.

To find:

The time at which John got home from school

Explanation:

According to the problem,

Total time to play video games and do homework is,

[tex]\begin{gathered} 45mins+30mins=75mins \\ =1hr15mins \end{gathered}[/tex]

So, the time he got home from school will be,

[tex]4:25P.M.-1hr15mins=3:10P.M.[/tex]

Final answer:

The time he got home from school is 3:10 P.M.

Find conditions on k that will make the matrix A invertible. To enter your answer, first select 'always', 'never', or whether k should be equal or not equal to specific values, then enter a value or a list of values separated by commas.

Answers

To be a matrix to be invertible the determinant of the matrix must be non zero thus for k ≠ 2 the matrix will be invertible.

What is a matrix?

matrix, a collection of numbers lined up in rows and columns to produce a rectangular array.

In computer graphics, where they have been used to describe picture transformations and other alterations.

The elements of the matrix, also known as the entry, are the numerals.

A matrix will be invertible only and only if the determinant is non-zero.

Given the matrix A.

The determinant of A is that |A| will be,

|A| = -3(8 - 8) - 0(-k + 2) - 3(-4k + 8) ≠ 0

0 + 0 + -3(-4k + 8) |A| ≠ 0

-4k + 8 ≠ 0

-4k ≠ -8

k ≠ 2

Hence "To be a matrix to be invertible the determinant of the matrix must be non zero thus for k ≠ 2 the matrix will be invertible".

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Identify the range of the function shown in the graph. 10 8 4 -10-8-4-2 8 10 O A. -2< y < 2 O B. {-2, 2) O C. y is all real numbers OD. Y > 0

Answers

Answer

Option B is correct.

Range: y is all real numbers.

Explanation

The range of a function refers to the region of values where the function can exist. It refers to the values that the dependent variable [y or f(x)] can take on. It is the region around the y-axis that the graph of the function spans.

For this question, we can see that the graph spans over the entire y-axis.

Hence, the range of this function shown in the graph is all real number.

Hope this Helps!!!

Evaluate the expression when m=9 and n=7.
5m +n
Correction: m = 7 and n = 9

Answers

We have the expression:

[tex]5m+n\text{.}[/tex]

We must evaluate the expression for:

• m = 7,

,

• n = 9.

Replacing the values of m and n in the expression above, we get:

[tex]5\cdot7+9=35+9=44.[/tex]

Answer

44

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