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A: height is increasing from 0-2 interval.
B: Height remains the same on 2-4
C: 4-6 the height is decreasing the fastest, because the slope is the steepest on that interval.
D: Baloon would be on the ground at 16 seconds, and will not fall down further. that is the way it is in real-world (constraint).
Related Questions
Neptune is about how many times as far from the Sun as Mars is fronthe Sun?Neptune = 2,600, 000,000MarS= 143,000,000Solution:
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The ratio of sand to gravel 4 to 9
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Since we are told there are 4 parts of sand for every 9 of gravel, the ratio of sand to gravel is 4/9.
1.) A gourmet shop wants to mix coffee beans that cost $3.00 per pound with coffee beans that
cost $4.25 per pound to create 25 pounds of a new blend that costs $3.50 per pound. Find the
number of pounds of each needed to produce the new blend.
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Explanation:
3.00 x 15 = 45$ ( old blend )
4.25 x 10 = 42.5$ ( new blend )
25 pound in total cost $87.50
To find the average cost per pound divide total cost by # of pounds.
87.50 divided by 25 pounds is $3.50
A truck rental is $25 plus $.35/mi. Find out how many miles Ken traveled if his bill was $51.95.
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So,
We could write the following equation, where "x" is the number of miles travelled.
[tex]0.35x+25=51.95[/tex]If we solve this equation, the first thing we're going to do is to let all "x terms" in a side of the equation and all the numbers in the other side. If "25" is summing in a side, it will change its sign when we pass it to the other side. Like this:
[tex]0.35x=51.95-25[/tex]Now, we substract the numbers above and get:
[tex]0.35x=26.95[/tex]Now, if 0.35 is multiplying "x", we are going to pass this number to divide the amount in the other side:
[tex]x=\frac{26.95}{0.35}=77[/tex]Therefore, Ken travelled 77 miles.
Theoretical Probabilities. Use the theoretical method to determine the probability ofthe following outcomes and events. State any assumptions that you make. Drawing a red card (heart or diamond) from a standard deck of cards
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Recall that the theoretical probability that an event occurring is given by the following quotient:
[tex]\frac{\text{favorable cases}}{total\text{ cases}}.[/tex]We know that there are 26 red cards in a standard deck, therefore:
[tex]P(\text{Drawing a red car)=}\frac{26}{52}=0.5.[/tex]Answer: 0.5.
Form a polynomial whose zeros and degree are given.Zeros: -4, multiplicity 2; -3, multiplicity 1; degree 3O x3 + 8x2 + 40x + 48O x3 - 11x2 + 24x - 48O x3 + 11x2 + 40x + 48O x3 - 11x2 + 40% - 48
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use the above diagram to answer the following questions.
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Remember that the sum of the interior angles is 180. Then, we have the following equation:
[tex]55^{\circ}+65^{\circ}\text{ + }\angle M\text{ = 180}[/tex]This is equivalent to:
[tex]120^{\circ}\text{ + }\angle M=180^{\circ}[/tex]solve for M-angle:
[tex]\text{ }\angle M=180^{\circ}-\text{ 120}^{\circ}=60^{\circ}[/tex]Then, te correct answer is :
[tex]\text{ }\angle M^{}=60^{\circ}[/tex]What is the x values that satisfies the linear equations on the graph?
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In the linear equations shown on the coordinate grid, the values of x that satisfies both equations is 2 (option b).
The graph of both equations intersect at the point where x equals 2.
how much must be deposited at the beginning of every six months in account that pays 6% compounded semi-annually so that account will contain 21,000 at the end of three years
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The formula for Final Amount, A after compounding for n period of times is given by
[tex]A=p(1+\frac{r}{100})^n[/tex]Where A = amount
p= principal
r = rate (in %)
n = number of compounding periods
From the question.
A=21,000, p = ?, r=6, n = 3 x 2 = 6
[tex]\begin{gathered} 21000=p(1+\frac{6}{100})6 \\ \\ 21000=p(1+0.06)^6 \\ 21000=p(1.06)6 \\ 21000=p(1.41852) \\ 21000=1.41852p \\ p=\frac{21000}{1.41852} \\ p=14,804.17 \end{gathered}[/tex]The amount that must be deposited at the beginning is 14,804.17
Find the restricted values of x for the following rational expression. If there are no restricted values of x, Indicate "No Restrictions".
−5r – 8/x² + 4
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The restricted values of x for the following rational expression.
x = 0
x = -3/4
What are restriction value?Restricted values are those values in a rational expression that bring the denominator to zero. When referring to "Market Value," the term "restricted value" denotes the property's value under the assumption that it is subject to a temporary governmental or private limit on rentals and tenant income levels. The denominator's real numbers that have a value of 0 are not included in the domain. The word "restrictions" refers to these values. Similar to how fractions are simplified, rational expressions can be too. Cancel the common factors after factoring the numerator and denominator. Place a zero as the denominator. Put the equation to rest. The restricted values are the answer or answers.
Rational expressions should first be multiplied, and then the numerator and denominator should be factored. Next, common factors should be cancelled. Notify yourself of the domain's limitations.
−5x– 8/x² + 4 = 0
- 5x - 8/[tex]x^{2}[/tex] = -4
x = 0
x = -3/4
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Calculate the net price and trade discount (use net price equivalent rate and single equivalent discount rate) for the following: Sony Hd flat-screen list price: 899 chain discount: 5/4 net price: Trade discount
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The net price and trade discount for the good is.539.4 and 359.6 respectively.
How to calculate the net price?From the information given, tuw.Sony Hd flat-screen list price is 899 and has a discount: 5/4 net price:
The net price will be:
= List price × (1 - Discount rate)
= 899 × (1 - 40%)
= 899 × 60%
= 899 × 0.6
= 539.4
The trade discount will be:
= List price - Net price
= 899 - 539.4
= 359.6
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Complete question:
Calculate the net price and trade discount (use net price equivalent rate and single equivalent discount rate) for the following: Sony Hd flat-screen list price: 899 chain discount: 5/4 net price and discount 40%
good night I will send a picture of work
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In the form of the equation
S = m D + b
S represented on the y-axis
D represented on the x-axis
The independent is x
The dependent is y
Then D is the independent
S is the dependent
let us find the correct answer
A salaried employee receives an annual salary of $40000. there are 26 pay periods during the year. during the current pay period, She receives a bonus of $200 what is her gross pay for this pay period ?A. $1,938.46B. $1,738.46C. $1,538.46D. $1,338.46
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ANSWER:
C. $1,538.46
STEP-BY-STEP EXPLANATION:
To understand the question we must take into account that it is the gross payment, which is the payment received by the employee agreed with the company, without taking into account deductions or bonuses.
Therefore, we calculate it with the total payment divided by the amount of payments, like this:
[tex]\begin{gathered} p=\frac{40000}{26} \\ \\ p=\text{ \$}1538.46 \end{gathered}[/tex]So the correct answer is C. $1,538.46
I can't solve them 15 here and 15 on another post
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6. Measure of angle 1 is 60 degrees because it congruent to angle 4 because they are opposed by the vertex
7. Measure of angle 3 is equal to 180 - angle 1 - angle 2 = 180 - 60 - 40 = 80 because these three angles sum 180 degrees
8. Measure of angle 5 is 40 degrees because it congruent to angle 2 because they are opposed by the vertex
9. Measure of angle 6 is equal to angle 3, because they are congruent, so it measures 80 degrees
10. Mesure of angle 7 is equal to the sum of angles 1 and 2 because they are congruent, so measure of angle 7 is 100
11. 80
12. 60
13. 120
14. 60
15. 120
Miguel is judging an essay contest. He has to select the best, second best, and third best. If there are 6 essays entered, how many ways could he choose the top essays?
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There are 120 ways to choose the top essays.
What is Multiplication?To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.
Given that;
There are 6 essays entered.
And, He has to select the best, second best, and third best.
Now,
Since, There are 6 essays entered.
Hence, The number of ways to choose the top essays = [tex]^{6} P_{3}[/tex]
= 6! / 3!
= 6×5×4
= 120
Thus, The number of ways = 120
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What is the y-intercept of the line that passes through the point (4,-9) with a slope of -1/2
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Answer:
The y-intercept b for the derived equation is;
[tex]b=-7[/tex]Explanation:
Given that the line passes through the point (4,-9) and has a slope of -1/2;
[tex]\begin{gathered} \text{slope m=-}\frac{1}{2} \\ \text{ point (4,-9)} \end{gathered}[/tex]Applying the point-slope form of linear equation;
[tex]y-y_1=m(x-x_1)[/tex]substituting the slope and the given point;
[tex]\begin{gathered} y-(-9)=-\frac{1}{2}(x-4) \\ y+9=-\frac{1}{2}x+\frac{4}{2} \\ y+9=-\frac{x}{2}+2 \\ y=-\frac{x}{2}+2-9 \\ y=-\frac{x}{2}-7 \end{gathered}[/tex]Comparing it to the slope intercept form of linear equation;
[tex]y=mx+b[/tex]where;
m = slope
and b = y-intercept
Therefore, the y-intercept b for the derived equation is;
[tex]b=-7[/tex]Solve the inequality below to determine and state the smallest possible value of x in the solution set. - 7(x + 4) + 3x < 8x - 2(2x - 2)
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given the inequality :
- 7(x + 4) + 3x < 8x - 2(2x - 2)
so,
-7x - 28 + 3x < 8x - 4x + 4
combine like terms:
-7x + 3x - 8x + 4x < 28 + 4
-8x < 32
Divide both sides by -8
Do not forget to flip the inequality sign
so,
x > -4
so, The solution is the interval ( -4 , ∞ )
On the number line the solution will be :
The smallest possible interger of x = -3
Supposed g is a one-to-one function with the following valuesg(-7)= -6g(11)= -1
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Given:
The function g(x) is one-one.
[tex]g(-7)=-6[/tex][tex]g(11)=-1[/tex]Required:
We need to find the values of the inverse image of the function g(x).
Explanation:
Recall that the image of distinct elements of the function is distinct.
There exist an inverse of g(x) since g(x) is one to one.
The inverse image of the given can be written as follows.
Consider the equation
[tex]g(-7)=-6[/tex][tex]g^{-1}g(-7)=g^{-1}(-6)[/tex][tex]g^{-1}(-6)=-7[/tex][tex]g(11)=-1[/tex][tex]g^{-1}g(11)=g^{-1}(-1)[/tex][tex]g^{-1}(-1)=11[/tex]Final answer:
[tex]g^{-1}(-6)=-7[/tex][tex]g^{-1}(-1)=11[/tex]Rewrite the equation by completing the square. x^{2}-6x-16 = 0
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Answer:
Step-by-step explanation:
x^2 - 6x - 16 = x^2 - 6x + 9 - 9 - 16 = (x - 3)^2 - 25
Sara’s dogsMorning: 39, 21, 12, 27, 23, 19, 31, 36, 25Afternoon: 15, 51, 8, 16, 43, 34, 27, 11, 8, 39Comparing the morning and afternoon groups Create frequency tables to represent the morning and afternoon dogs as two sets of data. Group the weights into classes that range 10 pounds.
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Answer;
Medain for morning is 25
Median for evening is 21.5
Explanation;
Here, we want to create frequency tables for each of the given groups
We start with the morning group
The frequency table for it is as follows;
Now, we proceed to the afternoon group
We have this as follows;
Lastly, we will want to get the median value of both groups
To do this, we need to re-arrange the values in the data set in ascending or descending order
For the purpose of this solution, we shall be using the ascending order mode. Then from here, we pick out the middle value
For the morning group, we have;
12, 19,21, 23,25,27,31,36,39
Since the numbers are 9, the middle number will be the 5th number since it leaves equal spread of values on the left and right
Thus, we have the median value as 25
The afternoon set, we have it as;
8,8,11,15,16,27,34,39,43,51
We proceed to choose the mid 5th values comig from both ends
We have this as;
We have these values as; 16 and 27
We add these and divide by 2
We have this as;
[tex]\frac{16+27}{2}\text{ = 21.5}[/tex]
Lucky Champ owes $209.10 interest on a 6% loan he took out on his March 17 birthday to upgrade an oven in his Irish restaurant, Lucky's Pub and Grub. The loan is due on August 17. What is the principal? (Use 360 days a year.)
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Based on the interest owed on the loan and the date that the loan is due and when Lucky Champ took it, the principal for the loan is $8,200.
How to find the principal?First, find the period of the loan:
= 14 days in March + 30 + 31 + 30 + 31 + 17 days in August
= 153 days
The interest can be found by the formula:
= Principal x Interest rate x Period
The Principal can therefore be found by the formula:
= Interest owed x Number of days in year / Number of days x 100 / 6
= 209.10 x 360 / 153 x 100 / 6
= $8,200
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can someone please help me find the value of x?
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Since we have a right triangle, we can relate the angle 28 with x and side 34 by meand of the sine function, that is,
[tex]\sin 28=\frac{34}{x}[/tex]where x is the hypotenuse. By moving x to the left hand side, we have
[tex]x\cdot\sin 28=34[/tex]and by moving sin28 to the right hand side, we get
[tex]x=\frac{34}{\sin 28}[/tex]since sin28=0.4694, we have
[tex]x=\frac{34}{0.4694}[/tex]then, x is given by
[tex]x=72.42[/tex]by rounding down, the answer is option D: x=72.4
a wood cutter measures a piece of wood to be 830 grams.There are 1000 grams in a kilogram and a kilogram is equal to about 2.2 pounds.Whats is the mass of the wood in pounds
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The mass of the wood in pounds is 1.826 pounds.
How to calculate the value?From the information, the wood cutter measures a piece of wood to be 830 grams and there are 1000 grams in a kilogram and a kilogram is equal to about 2.2 pound.
Therefore,the mass will be represented as x
This will be:
830 grams = 0.83 kilograms
0.83/1 = x/2.2
Cross multiply
x = 2.2 × 0.83
x = 1.826 pounds.
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Can you help me with my math homework?"There are 600 seats in the auditorium. This is 112 less than the number of seats in the gymnasium. How many seats are in the gymnasium? Let s= the number of seats in the gymnasium"
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According to the problem, there are 600 seats in the auditorium.
112 less than the number of seats in the gymnasium.
So, to find the number of seats in the gymnasium, we just have to add 122 and 600 because the auditorium has 112 seats less.
[tex]s=600+112=712[/tex]Hence, there are 712 seats in the gymnasium.A model of a 51 foot long airplane is 25 in long how is is a tire that is 1/6 tinch
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The length of the tire on the airplane given the length of the tire on the model is 17 / 50 foot.
What is the length of the tire?The first step is to determine the scale of the model. In order to determine the scale, divide the length of the airplane by the length of the plane in the model.
Scale of the model = length of the airplane / length of the model
51 / 25 = 1 inch represents 2 1/25 foot
The next step is to multiply the scale determined in the previous step by the length of the tire.
Length of the tire on the airplane = scale x length of the tire in the model
1 / 6 x 2 1/25
1/6 x 51 / 25 = 17 / 50 foot
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Find the slope of the line that contains the two points.ROUND YOUR ANSWER TO TWO DECIMAL PLACES.
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The slope of a line is given by the following formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Where (x1,y1) and (x2,y2) are the coordinates of the given points. Replace the given values and solve for m:
[tex]m=\frac{8-(-4)}{-6-0}=\frac{8+4}{-6}=\frac{12}{-6}=-2[/tex]The slope of the line that contains the two given points is -2.
Which of the following tools did the Greeks limit themselves to in their
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The Greeks limited themselves to using only compass and ruler in their formal geometric constructions.
Answer: Options B and D.
What is the slope and y-intercept?
y=7x+2
Options:
Blank # 1
Blank # 2
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Answer:
Step-by-step explanation:
18098
what do I do to compute the exact average of the fractions, in decimal form?
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Average is computed as follows:
[tex]\begin{gathered} \text{Avg=}\frac{\text{ sum of terms}}{\text{ number of terms}} \\ \text{Avg}=\frac{5+0.2+2}{3} \\ \text{Avg}=\frac{7.2}{3} \\ Avg=2.4 \end{gathered}[/tex]Suppose a mutual fund yielded a return of 14% last year. Its CAPM beta (β) is 1.2. The risk-free rate was 5% last year and the stock market return was 10% last year. What is the alpha (α) of the mutual fund?
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The Jensen's Alpha of the mutual fund is given as follows:
α = 3.
Jensen's AlphaThe Jensen's Alpha of a mutual fund is calculated according to the rule presented as follows:
α = [Rp - (Rf + Bp x (Rm - Rf))]
The parameters of the problem are defined as follows:
Rp is the expected portfolio return.Rf is the risk free rate.Bp is the beta of the portfolio.Rm is the expected market return.Hence, in the context of this problem, the values of the parameters are given as follows:
Rp = 14, Rf = 5, Bp = 1.2, Rm = 10.
Hence the Jensen's Alpha of the mutual fund is given as follows:
α = [Rp - (Rf + Bp x (Rm - Rf))]
α = [14 - (5 + 1.2 x (10 - 5))]
α = 3.
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