Someone pls help me with this!

Answer:

The last option.

Explanation:

Since you are going down, the gravitational potential energy would go down too. Thus, the gravitational potential energy decreases.

Since the gravitational potential energy is converted to kinetic energy when you move down, there is an increase in kinetic energy.

Answer:

The fourth option

Explanation:

Answer:

Answers below--

Explanation:

1. F/Force

2.H/Contact force

3.A/Non-contact force

4.C/electric force

5.D/gravity

6.I(i)/magnetic force

7.J/kilogram

8.G/newton

9.B/friction

10.E/lubricant

Answer:

[tex]\mathrm{(a)\:}32,000,000\:\mathrm{Ns},\\\mathrm{(b)\:}390,000\:\mathrm{N}[/tex]

Explanation:

The impulse-momentum theorem states the impulse on an object is equal to the change in momentum of that object. Momentum is given by [tex]p=mv[/tex]. Since mass is constant, the train's change in momentum is:

[tex]\Delta p=m\Delta v=750,000\cdot42=31,500,000=\fbox{$32,000,000\:\mathrm{Ns}$}[/tex](two significant figures).

Impulse is also given as [tex]\Delta p = F\Delta t[/tex], where [tex]F[/tex] is the average force applied and [tex]\Delta t[/tex] is change in time. Since [tex]t[/tex] is given as [tex]80\mathrm{s}[/tex], we have the following equation:

[tex]F\Delta t=\Delta p\\\\F=\frac{\Delta p}{\Delta t},\\\\F=\frac{31,500,000}{80},\\\\F=393,750=\fbox{$390,000\:\mathrm{N}$}[/tex](two significant figures).

Answer:

option 2

Explanation:

you are very welcom

Answer: B. Mechanical Waves

Explanation:

Answer:

156.8 Joules

Explanation:

Work = Force x Displacement

Displacement = 2m

Force (force of gravity) = mass x acceleration due to gravity =  8Kg x 9.8m/s^2

= 78.4N

Work = FxD

Work = 78.4 N x 2m

Work = 156.8 N·m  OR 156.8 Joules

The amount of work done in lifting this box is equal to 156.8 Joules.

Given the following data:

Scientific data:

To calculate the amount of work that is done in lifting this box:

Mathematically, the work done by a person is calculated by using this formula:

[tex]Work\;done = Fd = mgd[/tex]

Where:

Substituting the given parameters into the formula, we have;

[tex]Work\;done = 8 \times 9.8 \times 2[/tex]

Work done = 156.8 Joules.

Read more on work done here: https://brainly.com/question/25573309

Answer:

The horizontal distance traveled by the skydiver is 510.8 m.

Explanation:

Given;

height of fall, h = 800 m

initial velocity of the airplane, u = 40 m/s

The time to fall to the ground is calculated as;

[tex]t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2 \times 800}{9.81} }\\\\t = 12.77 \ s[/tex]

The horizontal distance or range of the motion is calculated as;

R = ut

R = 40 m/s x 12.77 s

R = 510.8 m

Therefore, the horizontal distance traveled by the skydiver is 510.8 m.

Answer: B

"Ball 1 at 0.21 m/s left, Ball 2 at 0.22 m/s left"

Answer:

4km/hr

Explanation:

Answer:

down below

Explanation:

for a scale, kg is used, as well as grams

for force, newtons is used

Answer:

12 m

Explanation:

From the question given above, the following data were obtained:

Mass (m) of bag = 25 kg

Potential energy (PE) = 2940 J

Height (h) =?

Objects carried to a particular height will always experience an acceleration due to gravity of 9.8 m/s².

With the above in mind, we can obtain the height to which the load is lifted to as shown below:

Mass (m) of bag = 25 kg

Potential energy (PE) = 2940 J

Acceleration due to gravity (g) = 9.8 m/s².

Height (h) =?

PE = mgh

2940 = 25 × 9.8 × h

2940 = 245 × h

Divide both side by 245

h = 2940 / 245

h = 12 m

Therefore, the worker lifts the load to a height of 12 m.

Answer:

1m/s²

Explanation:

Given parameters:

Initial velocity  = 2m/s

Final velocity  = 4m/s

Time of chase  = 2s

Unknown:

Acceleration = ?

Solution:

Acceleration is the rate of change of velocity with time;

 A = [tex]\frac{v - u }{t}[/tex]  

A is the acceleration

v is the final velocity

u is the initial velocity

t is the time taken

      A  = [tex]\frac{4 - 2}{2}[/tex]   = 1m/s²

Answer:

30,000kgm/s

Explanation:

Change in momentum is expressed as;

Change in momentum = mass × change in velocity

∆M = m∆v

Mass m = 1.5×10³kg = 1500kg

∆v = 30-10 =20m/s

Substitute into the formula

Change in momentum = 1500(20)

Change in momentum = 30,000kgm/s

Answer:

They have the highest melting point so that mean that the temperature and the are a conductive to electricity.

Explanation:

Answer:

a) 1.55 m/s

b) 2.3 m/s

Explanation:

We know that the boat travels across the river, if we define the river as the x-axis, then the velocity of the boat is only on the y-axis.

Then we can write the velocity of the boat in still water as:

S = (0, B)

Now, when the boat is on the river, the velocity of the boat will be equal to the velocity of the boat in still water plus the velocity of the river.

The velocity of the river is:

v = (R, 0).

Then the velocity of the boat in that river is:

V' = (0, B) + (R, 0) = (R, B)

Now, we know that the velocity of the boat is 10km/h, and it travels at an angle of 34° with respect to the shore.

We can use the Pythagoreans theorem to write the components of this velocity as:

x-axis component = 10km/h*cos(34°) = 8.29 km/h

y-axis component = 10km/h*sin(34°) =  5.59 km/h

Then the velocity of the boat can be written in components as:

velocity = ( 8.29 km/h,  5.59 km/h)

And we knew that the velocity of the boat was written as  (R, B)

Then we must have:

R = 8.29 km/h

B = 5.59 km/h

a) The speed of the boat in m/s:

We know that the speed of the boat is 5.59 km/h.

First, we know that:

1km = 1000m, then:

5.59 km/h = 5.59*(1000m)h = 5,590 m/h

And we know that:

1h = 3600s

Then we can write:

5,590 m/h = 5,590 m/(3600s) = 1.55 m/s

b) The speed of the river in m/s:

We know that the speed of the river is 8.29 km/h

Using the same reasoning as above, we can do the change of units as follows:

8.29 km/h = 8.29 (1000m)/(3600s) = 2.3 m/s

Answer:

1. where the skater turns and goes back in the opposite direction- point w

2. gravitational force of the object

3. point a

4. the bar representing sphere 4 should be twice as tall as the bar representing sphere 2

5. B; its mass is smaller (?)

yolo

Answer:

ABCDEFGHIJKLMNOPQRSTUVWXYZ

Explanation:

Answer:

The energy that will go will for thermal store of the surroundings is 20 J.

Explanation:

Given;

kinetic of the thrown ball, K.E₁ = 50 J

kinetic energy used to move the target, K.E₂ = 30 J

The excess energy that will go will for thermal store of the surroundings;

ΔK.E = K.E₁ - K.E₂

ΔK.E = 50J - 30J

ΔK.E = 20 J

Therefore, the energy that will go will for thermal store of the surroundings is 20 J.

Answer:

[tex]P=203.3819375kg.m/s\\P\approx203.4kg.m/s[/tex]

[tex]\theta=6.4541\textdegree North East\\\theta\approx6.5\textdegree North East[/tex]

Explanation:

From the question we are told that

Mass of first jogger [tex]M=69kg[/tex]

Speed[tex]v_1=1.6m/s[/tex]

Direction [tex]d= East[/tex]

Mass of 2nd jogger [tex]M=63kg[/tex]

Speed [tex]v_2=1.5m/s[/tex]

Direction [tex]d= 14\textdegree north[/tex]

Generally equation for momentum along the the horizontal is mathematically given as

[tex]P_x=m_1v_1 +m_2v_2cos\theta[/tex]

[tex]P_x=(69)*(1.6) +(63)*(1.5)cos14[/tex]

[tex]P_x=202.0929461kg.m/s[/tex]

Generally equation for momentum along the the vertical is mathematically given as

[tex]P_y=m_2v_2cos\theta[/tex]

[tex]P_x=22.86161913kgm/s[/tex]

a)Generally the magnitude of momentum is mathematically given by

[tex]P=\sqrt{(P_x)^2+(P_y)^2}[/tex]

[tex]P=\sqrt{(202.0929461)^2+(22.86161913)^2}[/tex]

[tex]P=\sqrt{41364.21249}[/tex]

[tex]P=203.3819375kg.m/s[/tex]

[tex]P\approx203.4kg.m/s[/tex]

b) Generally the angle [tex]\theta[/tex] is mathematically given by

[tex]\theta=tan^-^1\frac{py}{px} \\[/tex]

[tex]\theta=tan^-^1\frac{22.86161913}{202.0929461}[/tex]

[tex]\theta=tan^-^1(0.1131242805)[/tex]

[tex]\theta=6.4541\textdegree North East[/tex]

The correctly lists the three features shown in the photo is folds, strike-slip faults, and anticlines.

Modern folds are those that emerged recently (on the scale of geological periods), that is, in the Tertiary Period (between 65 million and 2.5 million years ago). Faults are geological structures that originate from vertical (top-down) or inclined internal forces.

The transcurrent fault – also called horizontal fault – occurs when there is displacement in the horizontal plane between the two blocks, being more common in zones where two tectonic plates meet, when these also move horizontally.

See more about transcurrent fault at brainly.com/question/2387953

#SPJ2

Answer: folds, strike-slip faults, and anticlines. (A)

Explanation: Got it right on my exam on Edge.

Explanation:

hehshehebdbajahwwdszsjshshs shsbw

Answer:

Explanation:

The velocity can be found by using the formula

[tex]v = \sqrt{ \frac{2k}{m} } \\ [/tex]

k is the kinetic energy

m is the mass

From the question we have

[tex]v = \sqrt{ \frac{2 \times 4116}{4200} } \\ = 1.4[/tex]

We have the final answer as

Hope this helps you

Answer:

The speed of the lift is 1.4 m/s

Explanation:

Kinetic Energy

Is the type of energy of an object due to its motion. It's proportional to the square of the speed and the mass.

The equation for the kinetic energy is:

[tex]\displaystyle K=\frac{1}{2}mv^2[/tex]

Where:

m = mass of the object

v = speed at which the object moves

The kinetic energy is expressed in Joules (J)

It's given the mass of the lift as m=4,200 kg and its kinetic energy K=4,116 J. To calculate the speed (magnitude of velocity), we solve the formula for v as follows:

[tex]\displaystyle v=\sqrt{\frac{2k}{m}}[/tex]

[tex]\displaystyle v=\sqrt{\frac{2*4,116}{4,200}}[/tex]

[tex]\displaystyle v=\sqrt{1.96}[/tex]

v = 1.4 m/s

The speed of the lift is 1.4 m/s

Answer:

1.5m/s²

Explanation:

Given parameters:

Mass of the wheelbarrow = 50kg

Net force applied  = 75N

Unknown:

Acceleration of the barrow = ?

Solution:

From Newton's second law of motion, we know that:

       Force  = mass x acceleration

 Now insert the parameters and find the acceleration

       75  = 50 x acceleration

      Acceleration  = 1.5m/s²

The given question is incomplete. The complete question is:

Estimate the volume of each ball. Use the formula [tex]v=\frac{4\pi\times r^3}{3}[/tex] where v is the volume and r is the radius. record the volume in table A of your student guide. The radius of the tennis ball is 2.1 cm and the radius of thr golf ball is 2.0 cm. What is the estimated volume of the table tennis ball in [tex]cm^3 [/tex] What is the estimated volume of the golf ball in

Answer: Volume of the tennis ball is [tex]38.8cm^3[/tex] and  Volume of the golf ball is [tex]33.5cm^3[/tex]

Explanation:

We have to find the Volume of tennis ball and golf ball by using the formula [tex]v=\frac{4\pi\times r^3}{3}[/tex]

Radius of the tennis ball = 2.1 cm

Radius  of the golf ball =2.0 cm.

Putting the value of radius in the formula , we get:

Volume of the tennis ball =  [tex]\frac{4\times 3.14\times (2.1cm)^3}{3} =38.8cm^3[/tex]

Volume of the golf ball =   [tex]\frac{4\times 3.14\times (2.0cm)^3}{3} =33.5cm^3[/tex]

Volume of the tennis ball is [tex]38.8cm^3[/tex] and  Volume of the golf ball is [tex]33.5cm^3[/tex]

it's  38.8 and 33.5 hope this helps

Answer:

Gravity controls the movement of the planets around the sun, holds together stars grouped in galaxies, and galaxies grouped in clusters.  The Universal Law of Gravitation depends on two things.  First it depends on mass of each object  and the second factor is the distance between two objects.  If the mass of one object is Larger, the gravitational pull towards it will be larger  and the smaller distance, the larger the gravitational pull will be between the objects. Therefore the Larger planets have more moon and the inner planets have less.

Explanation:

Answer:

3rd law beacuse there a flies

Answer:

T try d add b CD c

Explanation:

Cdgffd

Answer:

A convex lens or converging lens focuses the light rays to a specific point whereas a concave lens or diverging lens diverges the light rays. When these lenses are combined, they produce sharper images. Most of the eyeglass lenses use combinations of convex and concave lenses.

The projectile is any object thrown into space upon which the only acting force is gravity. In other words, the primary force acting on a projectile is gravity. This doesn’t necessarily mean that the other forces do not act on it, just that their effect is minimal compared to gravity. The path followed by a projectile is known as a trajectory. A baseball batted or thrown and the instant the bullet exits the barrel of a gun are all examples of the projectile.

When a particle is thrown obliquely near the earth’s surface, it moves along a curved path under constant acceleration that is directed towards the center of the earth (we assume that the particle remains close to the surface of the earth). The path of such a particle is called a projectile and the motion is called projectile motion. Air resistance to the motion of the body is to be assumed absent in projectile motion.

In a Projectile Motion, there are two simultaneous independent rectilinear motions:

Along the x-axis: uniform velocity, responsible for the horizontal (forward) motion of the particle.

Along y-axis: uniform acceleration, responsible for the vertical (downwards) motion of the particle.

Accelerations in the horizontal projectile motion and vertical projectile motion of a particle: When a particle is projected in the air with some speed, the only force acting on it during its time in the air is the acceleration due to gravity (g). This acceleration acts vertically downward. There is no acceleration in the horizontal direction, which means that the velocity of the particle in the horizontal direction remains constant.

[tex]\sf~~~~~~~~~~~~~~~{\red{\underbrace{\underline{\green{projectile~motion}}}}}[/tex]

Projectile motion is a form of motion in which object or particle is thrown near earth's surface and it moves along a curved path under the action of gravity only.

Answer:

Fscos63

Explanation:

Given that a horizontal pole is attached to the side of a building. There is a pivot P at the wall and a chain is connected from the end of the pole to a point higher up the wall. There is a tension force F in the chain. What is the moment of the force F about the pivot P?

Taking the moment from the pivot point P, that means the moment at point p = 0

Then, if we consider the weight mg of the pole, according to the principle of equilibrium : sum of the upward forces equal to the sum of the downward forces.

Therefore, mg = Fsinø ....... (1)

Also, taking moment at point P

Let the length of the pole = s

The length of the weight of the pole = 1/2 S

Fscosø = mgs/2

The distance s will cancel out

2Fcosø = mg ...... (3)

Substitute mg in equation 1 into equation 3

2fcosø = fsinø

F will cancel out

Tanø = 2

Ø = tan^-1(2)

Ø = 63.4 degree

The moment of force F about pivot point P will be

Moment = force × distance

Moment = Fcos63 × S

Moment = Fscos63