someone please help
i will give brainliest

Answer:

x + y = 7

Step-by-step explanation:

Answer:

The correct answer is c

Answer:

Answer is c

Step-by-step explanation:

Your welcome

Answer:

Closer to 0 than 0.5, or under zero

Step-by-step explanation:

On a vertical number line, anything above zero is positive, and anything under zero is negative. If 0.5 is the greater number, then it has to be closer to zero, or under it.

Answer:

The other number would be located below 0.5 on the vertical number line.

Step-by-step explanation:

Answer:

x=2

Step-by-step explanation:

3x+1-x=5

add like terms

2x+1=5

subtract 1 from both sides

2x=4

divide by 2 from both sides

x=2

Answer:

3x+1-x=5

2x+1=5

2x=4

x=2 please give me brainlist

Step-by-step explanation:

Answer:

Step-by-step explanation:

an hour, or 60 minutes

Answer:

60 minutes

Step-by-step explanation:

i d 1 0 t

Answer:

It will be $85,  34÷ 4

will give you 8.5 then you multiply it by 10,× 10=85

Answer:

272

Step-by-step explanation:

56:7=8 (she earns 8$ in 1 hour)

8×34=272

Answer

Step-by-step explanation:

rise over run so it'd be 3/3 positive or y= 3x-3

Answer:

= -32a+64b

Step-by-step explanation:

thats the answer

Answer:

????

Step-by-step explanation:

Answer:

where's the shape

Step-by-step explanation:

what's the length and width, maybe I can help

59.9%

Sorry I don’t have time to explain in the middle of an exam

The rate of growth needs to be 59.9%.

The formula used to determine the future value of an investment when interest is compounded continuously is:

FV =  A x [tex]e^{r}[/tex] x N

$320,000 = $16,000 x [tex]e^{r}[/tex] x 5

Divide both sides by $16,000

20 = 5[tex]e^{r}[/tex]

Take the In of both sides

In(20) = 5r

Divide both sides by 5

r = 59.9%

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Answer: 10

Step-by-step explanation:

25 ÷ 2.5 = 10

10 gigabytes

Answer:

The second step is Distributive Property and the third is Subtraction Property of Equality

Step-by-step explanation:

The 1/2 is being distributed in the second step making the 8x to 4x and the 6 to 3.

The third step involves the subtraction of "x" from the right hand side and the left hand side.

Answer:

[tex]y=6x+43[/tex]

Step-by-step explanation:

We want the equation of a line that is parallel to [tex]y=6x+1[/tex] which also passes through (-7, 1).

Since the new line is parallel, it must have the same slope as the original line.

The slope of the original line is 6.

Hence, the slope of our new line must also be 6.

We know that the slope is 6.

And it passes through the point (-7, 1).

So, we can use the point-slope form:

[tex]y-y_1=m(x-x_1)[/tex]

Where m is the slope and (x₁, y₁) is a point.

Substitute:

[tex]y-1=6(x-(-7))[/tex]

Simplify:

[tex]y-1=6(x+7)[/tex]

Distribute:

[tex]y-1=6x+42[/tex]

Add 1 to both sides. Hence, our equation is:

[tex]y=6x+43[/tex]

Answer:

204 is the answer

Step-by-step explanation:

204 is the answer

Paki heart nalang po kung nakatulong

Answer:

its the 3rd

Step-by-step explanation:

Answer:

Vectors are usually described in terms of their components in a coordinate system. Even in everyday life we naturally invoke the concept of orthogonal projections in a rectangular coordinate system. For example, if you ask someone for directions to a particular location, you will more likely be told to go 40 km east and 30 km north than 50 km in the direction 37° north of east.

In a rectangular (Cartesian) xy-coordinate system in a plane, a point in a plane is described by a pair of coordinates (x, y). In a similar fashion, a vector

→

A

in a plane is described by a pair of its vector coordinates. The x-coordinate of vector

→

A

is called its x-component and the y-coordinate of vector

→

A

is called its y-component. The vector x-component is a vector denoted by

→

A

x. The vector y-component is a vector denoted by

→

A

y. In the Cartesian system, the x and y vector components of a vector are the orthogonal projections of this vector onto the x– and y-axes, respectively. In this way, following the parallelogram rule for vector addition, each vector on a Cartesian plane can be expressed as the vector sum of its vector components:

Step-by-step explanation:

Answer:

approximately 85 m

Step-by-step explanation:

use the law of cosines

x²=120²+90²-2(120)(90)cos(45)

*120 & 90 are given values

*45 is from 25+20; bcuz of alternate interior angles, the other angle from mirror 1 is 25 degrees, making the total 45 degrees

x=√120²+90²-2(120)(90)cos(45)

x=85, the distance btwn origin point and mirror 2

Answer:

-11

Step-by-step explanation:

Answer:

53

Step-by-step explanation:

5 choices × 5 choices × 5 choices = 53 possible 3 digit codes including repeats

 [tex]\boldsymbol{125}[/tex] unique [tex]3[/tex] digit codes can be created from the [tex]5[/tex] digits.

Given that digits are [tex]=\boldsymbol{\{1,2,3,4,5 \}}[/tex].

Number of digits [tex]=\boldsymbol{5}[/tex]

With repetition" means that repetition is allowed. Thus, in each of the three places, we have five choices.

Therefore,

Number of unique three digit codes can be created from the five digits [tex]=5\times 5\times 5[/tex]

[tex]=\boldsymbol{125}[/tex]

So, [tex]\boldsymbol{125}[/tex] unique [tex]3[/tex] digit codes can be created from the [tex]5[/tex] digits.

Find out more information about permutations here:

https://brainly.com/question/26852614?referrer=searchResults

Answer:

8

Step-by-step explanation:

128/6=8

Answer:

8.

divide 128 by 16 and its ^

Answer:

Step-by-step explanation:

You suck free points

The change of the distance travelled by the ball when the angle of launch

changes can be found by linear approximation.

Reasons:

The distance of the player from the basket = 18.6 ft.

Height from which the jump shot is launched = 10 ft.

Angle of the jump shot = 36°

The initial velocity = 25 ft./s

According to Newton's Law of motion, the distance an object travels when

released at an angle θ, with an initial velocity, v, is given by the following

horizontal range formula equation;

[tex]s = \dfrac{1}{32} \cdot v^2 \cdot sin(2 \cdot \theta)[/tex]

[tex]\dfrac{ds}{d\theta} =\dfrac{d}{d\theta } \left( \dfrac{1}{32} \cdot v^2 \cdot sin(2 \cdot \theta) \right)= \dfrac{v^2 \cdot cos(2 \cdot \theta)}{16}[/tex]

By linear approximation, we have;

[tex]\Delta s = \dfrac{ds}{d\theta} \times \Delta \theta[/tex]

Which gives;

[tex]\Delta s =\dfrac{25^2 \cdot cos(2 \times 36^{\circ})}{16}\times \Delta \theta \approx 12.07 \times \Delta \theta[/tex]

360° = 2·π radians

[tex]12.07 ^{\circ} = \dfrac{2 \cdot \pi}{360} \times 12.07 \approx 0.211 \ radians[/tex]

Δs ≈ 0.211·Δθ

Therefore;

The change in the distance, Δs, when the angle changes by Δθ is 0.211·Δθ.

Learn more here:

https://brainly.com/question/17026396

Answer:k=5b/4 - 3/4

Step-by-step explanation:

Answer:

[tex]k=\frac{5}{4}b - \frac{3}{4}[/tex]

Step-by-step explanation:

-3k + 7k = 5b - 3

4k = 5b - 3

[tex]k=\frac{5}{4}b - \frac{3}{4}[/tex]

Answer:

B

a proportional relationship in a graph needs to go through the 0.0, and also needs to be a stright line.

Answer:

a) 323 kph with a directional bearing of S 22° E

Step-by-step explanation:

to find the ground speed:

just do the pythagorean theorem.

c²=300²+120²

c²=104400

c=323

to find the directional bearing:

use the law of sines!

sin(90)/323 = sin(θ)/120

(*explanation: since the plane is heading due south and the wind is from due west, it makes a 90 degree angle; and the side opposite of the 90 degree angle is 323. set it equal to sin theta over 120; theta is the angle u r trying to find, and the side opposite of it is 120)

cross multiply:

120sin90=323sin(θ)

divide 323 on both sides:

sin(θ)=0.3715

use inverse sin to find out degree measure:

sin⁻¹(0.3715)=21.8

rounds up to 22.

The ground speed and direction of the plane is 323 kph with a directional bearing of S 22° E. Therefore, option A is the correct answer.

To find the ground speed of the plane, we need to know what a vector is

What is a vector?

A vector is a variable that has both magnitude and direction.

Since the airplane is headed due south with an airspeed of 300 kph, its vector is V = (-300 kph)j.

Also, the wind is blowing from the west at 120 kph. Its vector is v = (-120 kph)i

Now, the ground speed of the plane V' is the resultant vector of the airspeed and wind speed.

A resultant vector is the sum of two or more vectors.

So, V' = v + V

V' = (-120 kph)i + (-300 kph)j

So, its magnitude V' = √(x² + y²) where

x = -120 kph and

y = -300 kph.

So, V' = √[(-120 kph)² + (-300 kph)²]

= √[14400 kph² + 90000 kph²]

= √(104400 kph²)

= 323.11 kph

≅ 323 kph

The direction of the plane

Its direction, Ф = tan⁻¹(y/x)

Ф = tan⁻¹(-300 kph/-120 kph)

Ф = tan⁻¹(2.5)

Ф = 68.2°

From the South-line we have α = 90° - Ф = 90° - 68.2° = 21.8° ≅ 22°

So, the directional bearing of the plane is S22°E.

So, the ground speed and direction of the plane is 323 kph with a directional bearing of S 22° E.

Learn more about the ground speed of a plane and direction here:

brainly.com/question/11861018

#SPJ2

Answer:

5

Step-by-step explanation:

there is not enough info to because we do not have the detentions are the difference of triangle A or B

Answer:

36

Step-by-step explanation:

40 * .10 = 4

40-4 = 36

Answer:

14. [tex]y = -2x -1[/tex]

15. [tex]y = -\frac{3}{4}x +3[/tex]

16. [tex]y= 4x + 9[/tex]

17. [tex]y = -\frac{5}{3}x -2[/tex]

18. [tex]y= -\frac{2}{3}x -5[/tex]

19. [tex]y = 4x -3[/tex]

20. [tex]y = -3x -7[/tex]

Step-by-step explanation:

Solving (14):

Given

[tex](x_1,y_1) = (-7,13)[/tex]

[tex]Slope (m) = -2[/tex]

Equation in [tex]slope- intercept[/tex] form is:

[tex]y - y_1 = m(x-x_1)[/tex]

Substitute values for y1, m and x1

[tex]y - 13 = -2(x -(-7))[/tex]

[tex]y - 13 = -2(x +7)[/tex]

[tex]y - 13 = -2x -14[/tex]

Collect Like Terms

[tex]y = -2x -14 + 13[/tex]

[tex]y = -2x -1[/tex]

Solving (15):

Given

[tex](x_1,y_1) = (-4,6)[/tex]

[tex]Slope (m) = -\frac{3}{4}[/tex]

Equation in [tex]slope- intercept[/tex] form is:

[tex]y - y_1 = m(x-x_1)[/tex]

Substitute values for y1, m and x1

[tex]y - 6 = -\frac{3}{4}(x - (-4))[/tex]

[tex]y - 6 = -\frac{3}{4}(x +4)[/tex]

[tex]y - 6 = -\frac{3}{4}x -3[/tex]

Collect Like Terms

[tex]y = -\frac{3}{4}x -3 + 6[/tex]

[tex]y = -\frac{3}{4}x +3[/tex]

Solving (16):

Given

[tex](x_1,y_1) = (-5,-11)[/tex]

[tex](x_2,y_2) = (-2,1)[/tex]

First, we need to calculate the [tex]slope\ (m)[/tex]

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

[tex]m = \frac{1 - (-11)}{-2 - (-5)}[/tex]

[tex]m = \frac{1 +11}{-2 +5}[/tex]

[tex]m = \frac{12}{3}[/tex]

[tex]m = 4[/tex]

Equation in [tex]slope- intercept[/tex] form is:

[tex]y - y_1 = m(x-x_1)[/tex]

Substitute values for y1, m and x1

[tex]y - (-11) = 4(x -(-5))[/tex]

[tex]y +11 = 4(x+5)[/tex]

[tex]y +11 = 4x+20[/tex]

Collect Like Terms

[tex]y= 4x + 20 - 11[/tex]

[tex]y= 4x + 9[/tex]

Solving (17):

Given

[tex](x_1,y_1) = (-6,8)[/tex]

[tex](x_2,y_2) = (3,-7)[/tex]

First, we need to calculate the [tex]slope\ (m)[/tex]

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

[tex]m = \frac{-7 - 8}{3- (-6)}[/tex]

[tex]m = \frac{-7 - 8}{3+6}[/tex]

[tex]m = \frac{-15}{9}[/tex]

[tex]m = -\frac{5}{3}[/tex]

Equation in [tex]slope- intercept[/tex] form is:

[tex]y - y_1 = m(x-x_1)[/tex]

Substitute values for y1, m and x1

[tex]y - 8 = -\frac{5}{3}(x -(-6))[/tex]

[tex]y - 8 = -\frac{5}{3}(x +6)[/tex]

[tex]y - 8 = -\frac{5}{3}x -10[/tex]

Collect Like Terms

[tex]y = -\frac{5}{3}x -10 + 8[/tex]

[tex]y = -\frac{5}{3}x -2[/tex]

18.

Given

[tex](x_1,y_1) = (-6,-1)[/tex]

[tex]y = -\frac{2}{3}x+1[/tex]

Since the given point is parallel to the line equation, then the slope of the point is calculated as:

[tex]m_1 = m_2[/tex]

Where [tex]m_2[/tex] represents the slope

Going by the format of an equation, [tex]y = mx + b[/tex]; by comparison

[tex]m = -\frac{2}{3}[/tex]

and

[tex]m_1 = m_2 = -\frac{2}{3}[/tex]

Equation in [tex]slope\ intercept\ form[/tex] is:

[tex]y - y_1 = m(x-x_1)[/tex]

Substitute values for y1, m and x1

[tex]y - (-1) = -\frac{2}{3}(x - (-6))[/tex]

[tex]y +1 = -\frac{2}{3}(x +6)[/tex]

[tex]y +1 = -\frac{2}{3}x -4[/tex]

[tex]y= -\frac{2}{3}x -4 - 1[/tex]

[tex]y= -\frac{2}{3}x -5[/tex]

19.

Given

[tex](x_1,y_1) = (-2,-11)[/tex]

[tex]y = -\frac{1}{4}x+2[/tex]

Since the given point is parallel to the line equation, then the slope of the point is calculated as:

[tex]m_1 = -\frac{1}{m_2}[/tex]

Where [tex]m_2[/tex] represents the slope

Going by the format of an equation, [tex]y = mx + b[/tex]; by comparison

[tex]m_2 = -\frac{1}{4}[/tex]

and

[tex]m_1 = -\frac{1}{m_2}[/tex]

[tex]m_1 = -1/\frac{-1}{4}[/tex]

[tex]m_1 = -1*\frac{-4}{1}[/tex]

[tex]m_1 = 4[/tex]

Equation in [tex]slope\ intercept\ form[/tex] is:

[tex]y - y_1 = m(x-x_1)[/tex]

[tex](x_1,y_1) = (-2,-11)[/tex]

Substitute values for y1, m and x1

[tex]y - (-11) = 4(x - (-2))[/tex]

[tex]y +11 = 4(x +2)[/tex]

[tex]y +11 = 4x +8[/tex]

Collect Like Terms

[tex]y = 4x + 8 - 11[/tex]

[tex]y = 4x -3[/tex]

20.

Given

[tex](x_1,y_1) = (-10,3)[/tex]

[tex](x_2,y_2) = (2,7)[/tex]

First, we need to calculate the slope of the given points

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

[tex]m = \frac{7 - 3}{2 - (-10)}[/tex]

[tex]m = \frac{7 - 3}{2 +10}[/tex]

[tex]m = \frac{4}{12}[/tex]

[tex]m = \frac{1}{3}[/tex]

Next, we determine the slope of the perpendicular bisector using:

[tex]m_1 = -\frac{1}{m_2}[/tex]

[tex]m_1 = -1/\frac{1}{3}[/tex]

[tex]m_1 = -3[/tex]

Next, is to determine the coordinates of the bisector.

To bisect means to divide into equal parts.

So the coordinates of the bisector is the midpoint of the given points;

[tex]Midpoint = [\frac{1}{2}(x_1+x_2),\frac{1}{2}(y_1+y_2)][/tex]

[tex]Midpoint = [\frac{1}{2}(-10+2),\frac{1}{2}(3+7)][/tex]

[tex]Midpoint = [\frac{1}{2}(-8),\frac{1}{2}(10)][/tex]

[tex]Midpoint = (-4,5)[/tex]

So, the coordinates of the midpoint is:

[tex](x_1,y_1) = (-4,5)[/tex]

Equation in [tex]slope- intercept[/tex] form is:

[tex]y - y_1 = m(x-x_1)[/tex]

Substitute values for y1, m and x1: [tex]m_1 = -3[/tex] & [tex](x_1,y_1) = (-4,5)[/tex]

[tex]y - 5 = -3(x - (-4))[/tex]

[tex]y - 5 = -3(x +4)[/tex]

[tex]y - 5 = -3x-12[/tex]

Collect Like Terms

[tex]y = -3x - 12 +5[/tex]

[tex]y = -3x -7[/tex]