Solve the problems below as fast as you can because I’m trying to go to sleep but it’s not an assignment or graded or timed please
Answers
Given the inequality:
4m < 24
Let's solve for m.
To solve for m, divide both sides of the inequality by 4:
[tex]\begin{gathered} \frac{4m}{4}<\frac{24}{4} \\ \\ m<6 \end{gathered}[/tex]ANSWER:
m < 6
Related Questions
What are the solutions to the equation ? e^1/4x = (4x) [tex]e^1/4x =abs( 4x)[/tex](Round to the nearest hundredth). The solutions are about x = and
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The solution of the equation e^(x/4) = |4x| for the x by graphical approach is 0.27 and -0.24.
What is the equation?The definition of an equation in algebra is a mathematical statement that demonstrates the equality of 2 mathematical expressions.
A formula known as an equation uses the same sign to denote the equality of two expressions.
As per the given expression,
e^(x/4) = |4x|
The function e^(x/4) is an exponential function and the plot of this function has been plotted below.
The mode function |4x| has also been plotted below.
The point of intersection is the point where both will be the same or the solution meets.
The first point of intersection is (0.267,1.0691) so x = 0.267 ≈ 0.27
The second point of intersection (-0.2357,0.9428) so x = -0.2357 ≈ -0.24
Hence " The solution of the equation e^(x/4) = |4x| for the x by graphical approach is 0.27 and -0.24.".
For more about the equation,
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How do I solve this problem?Mary reduced the size of a painting to a width of 3.3 inches. What is the new height of it was originally 32.5 inches tall and 42.9 inches wide? Round your answer to the nearest tenth.
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Given the follow equivalence
[tex]\frac{Oldwidth}{Oldheight}=\frac{Newwidth}{Newheight}[/tex]where
old width=42.9
Old height= 32.5
New width=3.3
then
[tex]\frac{42.9}{32.5}=\frac{3.3}{Newheight}[/tex][tex]Newheight=3.3*\frac{32.5}{42.9}[/tex][tex]Newheight=2.5[/tex]New height is 2.5 inches
Which of the following graphs shows a negative linear relationship with a correlation coefficient, r, close to -0.5?A. Graph AB. Graph BC. Graph CD. Graph D
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A negative linear relationship occurs when for increasing x values, the values of y are decreasing.
Observing the graphs, we can see a positive linear relationship for graphs A and C (x - increases, y - increases).
For Graph D, we can observe no correlation.
For graph B, we can observe a negative linear relationship (x - increases, y - decreases).
Answer: Graph B
Find the value of x in the triangle shown below.42
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Since we are dealing with a right triangle, we can use the Pythagorean theorem, shown below
[tex]H^2=L^2_1+L^2_2[/tex]In our case, H=4, L_1=2, L_2=x; then,
[tex]4^2=2^2+x^2[/tex]Solving for x,
[tex]\begin{gathered} \Rightarrow x^2=16-4 \\ \Rightarrow x^2=12 \\ \Rightarrow x=\sqrt[]{12}=\sqrt[]{4\cdot3} \\ \Rightarrow x=2\sqrt[]{3} \end{gathered}[/tex]The answer is x=2sqrt(3)
URGENT!! ILL GIVE
BRAINLIEST!!!!! AND 100 POINTS!!!!!
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Answer:
-45 is an integer
√100 = 10 is a whole number
√89 is an irrational number-root
4.919191... is a rational decimal
-2/5 is a rational number-ratio
.12112111211112... is an irrational decimal
Finnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnn
Which of the following point-slope form equations could be produced with the points (3, 4) and (1, -7)?
Answers
Answer:
y - 4 = [tex]\frac{11}{2}[/tex] ( x - 3 )
Step-by-step explanation:
( [tex]x_{1}[/tex] , [tex]y_{1}[/tex] )
( [tex]x_{2}[/tex] , [tex]y_{2}[/tex] )
m = [tex]\frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex]
y - [tex]y_{1}[/tex] = m( x - [tex]x_{1}[/tex] )
~~~~~~~~~~~~~~~
( 3 , 4 )
( 1 , - 7 )
m = [tex]\frac{-7-4}{1-3}[/tex] = [tex]\frac{-11}{-2}[/tex] = [tex]\frac{11}{2}[/tex]
y - 4 = [tex]\frac{11}{2}[/tex] ( x - 3 )
4. 1st drop down answer A. 90B. 114C. 28.5D. 332nd drop down answer choices A. Parallel B. Perpendicular 3rd drop down answer choices A. 180 B. 360 C. 270D. 90 4th drop down answer choices A. 33B. 57C. 90D. 28
Answers
Answer:
Tangent to radius of a circle theorem
A tangent to a circle forms a right angle with the circle's radius, at the point of contact of the tangent.
Part A:
With the theorem above, we will have that the tangent is perpendicular to the line radius drawn from the point of tangency
Therefore,
The value of angle CBA will be
[tex]\Rightarrow\angle CBA=90^0[/tex]Part B:
Since the angle formed between the tangent and the radius from the point of tangency is 90°
Hence,
The final amswer is
Tangent lines are PERPENDICULAR to a radius drawn from the point of tangency
Part C:
Concept:
Three interior angles of a triangle will always have the sum of 180°
Hence,
The measure of angles in a triangle will add up to give
[tex]=180^0[/tex]Part D:
Since we have the sum of angles in a triangle as
[tex]=180^9[/tex]Then the formula below will be used to calculate the value of angle BCA
[tex]\begin{gathered} \angle ABC+\angle BCA+\angle BAC=180^0 \\ \angle ABC=90^0 \\ \angle BAC=57^0 \end{gathered}[/tex]By substituting the values,we will have
[tex]\begin{gathered} \operatorname{\angle}ABC+\operatorname{\angle}BCA+\operatorname{\angle}BAC=180^{0} \\ 90^0+57^0+\operatorname{\angle}BCA=180^0 \\ 147^0+\operatorname{\angle}BCA=180^0 \\ substract\text{ 147 from both sides} \\ 147^0-147^0+\operatorname{\angle}BCA=180^0-147^0 \\ \operatorname{\angle}BCA=33^0 \end{gathered}[/tex]Hence,
The measure of ∠BCA = 33°
Write an equation for the inverse variation represented by the table.x -3, -1, 1/2, 2/3y 4, 12, -24, -18
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By definition, Inverse variation equations have the following form:
[tex]y=\frac{k}{x}[/tex]Where "k" is the Constant of variation.
Given the values shown in the table, you can find the value of "k":
- Choose a point from the table. This could be:
[tex](-3,4)[/tex]Notice that:
[tex]\begin{gathered} x=-3 \\ y=4 \end{gathered}[/tex]- Substitute these values into the equation and solve for "k":
[tex]\begin{gathered} 4=\frac{k}{-3} \\ \\ (4)(-3)=k \\ k=-12 \end{gathered}[/tex]Knowing the Constant of variation, you can write the following equation:
[tex]y=\frac{-12}{x}[/tex]The answer is:
[tex]y=\frac{-12}{x}[/tex]which of the following circles have their centers in the second quadrant
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The circles in option B and D has their centers in the second quadrant
Here, we want to know which of the circles have their centers in the second quadrant
Generally, the equation of a circle can be represented as;
[tex](x-h)^2\text{ + (y-}k)^2=r^2[/tex]where (h,k) represents the center of the circle
Now, let us get the center of each of the circles;
A. (4,-3)
b. (-1,7)
C.(5,6)
D. (-2,5)
The second quadrant has its coordinates in the form (-x,y)
Out of all the options, the option that fits these quadrant is the second and fourth
So the circles in option B and D has its center in the second
Patient Smith was on a diet. He weighed 122.6 kilograms. After one month he weighed 112.8 kilograms. Whatwas his total weight loss in one month?
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If Smith uses both medications, then its dosage is the sum of each.
[tex]\text{total dosage = 48.5 + 0.5 = 4}9\text{ ml}[/tex]The total dosage of the medication would be 49 ml if he got both medications.
If 16 is increased to 23, the increase is what percent of the original number? (This is known as the percent of change.)
Answers
Step 1
Given data
Old value = 16
New value = 23
Step 2
Write the percentage increase formula
[tex]\text{Percentage increase = }\frac{I\text{ncrease}}{\text{Old}}\text{ }\times\text{ 100\%}[/tex]Step 3
Increase = 23 - 16 = 7
[tex]\begin{gathered} \text{Percentage increase = }\frac{7}{16}\text{ }\times\text{ 100\%} \\ =\text{ 43.75\%} \end{gathered}[/tex]If we use 3.14 for pi, describe the ratio between the circumference and the diameter of a circle.
Answers
Solution
The ratio of the circumference of any circle to the diameter of that circle.
[tex]\begin{gathered} \text{circumference of a circle=}\pi d \\ \text{where d is the diameter} \\ \\ \text{circumference of a circle=3.14}d \end{gathered}[/tex]The ratio of the circumference of any circle to the diameter of that circle. Regardless of the circle's size, this ratio will always equal pi.
jen has to put 180 cards into boxes of 6 cards each. she put 150 cards into boxes. write an equation that could use to figure out how many boxes jen need. let b stand for the unknown number of boxes.
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Let b be the number of boxes.
Since each box has 6 cards, we will have the term 6b to get the remaining boxes.
Since Jen already put 150 cards into boxes, we have the following:
[tex]150+6b=180[/tex]for 150 cards, Jen used 25 boxes. We can check that the remaining 5 boxes can be found using the previous equation:
[tex]\begin{gathered} 150+6b=180 \\ \Rightarrow6b=180-150=30 \\ \Rightarrow b=\frac{30}{6}=5 \\ b=5 \end{gathered}[/tex]therefore, the equation is 150+6b=180
=GEOMETRYPythagorean TheoremFor the following right triangle, find the side length x. Round your answer to the nearest hundredth.
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From the triangle, we have:
c = 13
b = 7
Let's solve for a.
The triangle is a right triangle.
To find the length of the missing sides, apply Pythagorean Theorem:
[tex]c^2=a^2+b^2[/tex]We are to solve for a.
Rewrite the equation for a:
[tex]a^2=c^2-b^2[/tex]Thus, we have:
[tex]\begin{gathered} a^2=13^2-7^2 \\ \\ a^2=169-49 \\ \\ a^2=120 \end{gathered}[/tex]Take the square root of both sides:
[tex]\begin{gathered} \sqrt[]{a^2}=\sqrt[]{120} \\ \\ a=10.95 \end{gathered}[/tex]ANSWER:
[tex]10.95[/tex]I need to find out how much money my school loans for donating 2200 pounds of clothing
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Firs we need to find the equation of the line
x= clothing donations (pounds)
y= Amount earned (dollars)
We have the next points
(0,0)
(100,400)
We will calculate the slope
[tex]m=\frac{400-0}{100-0}=4[/tex]Therefore the equation is
y=4x
then if x=2200
y=4(2200)
y=8800
Silvergrove Hardware kept an inventory of 517,110 lawnmowers in the past. With a change inmanagement, the hardware store now keeps an inventory of 70% more lawnmowers. Howmany lawnmowers is that?
Answers
879,087.
EXPLANATION
To find the number of lawnmowers, we need to first find 70% of the number of lawnmowers that was kept in the past. Then add the to the number of lawnmowers kept in the past.
From the given question;
Number of lawnmowers kept in the past = 517, 110.
70% of lawnmowers kept in the past = 70% of 517 110
[tex]\begin{gathered} =\frac{70}{100}\times517\text{ 110} \\ \\ =361\text{ 977} \end{gathered}[/tex]Number of lawnmowers now kept in store = number of lawnmowers kept in the past + 70% of lawnmowers kept in the past
= 517 110 + 361 977
= 879,087.
Describe the features of the function that can be easily seen when a quadratic function is givenin the form: y = ax2 + bx + c and how they can be identified from the equation. How can thisform be used to find the other features of the graph?
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Hello there. To solve this question, we need to remember some properties about quadratic functions and its key features.
Let f(x) = ax² + bx + c, for a not equal to zero.
The main key feature we can see at first glance is the leading coefficient a.
If a < 0, the parabola (the graph of the function) will have its concavity facing down.
If a > 0, the parabola will have its concavity facing up.
It also means the function will have either a maximum or a minimum point on its vertex, respectively.
Another key feature of the function is the y-intercept, i. e. the point in which the x-coordinate is equal to zero, is (0, c).
The x-intercepts of the graph (in plural), are the roots of the function.
If b² - 4ac > 0, we'll have two distinct real roots.
If b² - 4ac = 0, we'll have two equal real roots.
If b² - 4ac < 0, we'll have two conjugate complex roots (not real roots)
This b² - 4ac is the discriminant of the function.
The roots can be found by the formula:
x = (-b +- sqrt(b² - 4ac))/2a
The vertex of the graph can be found on the coordinates (xv, yv), in which xv is calculated by the arithmetic mean of the roots
xv = ((-b + sqrt(b²-4ac))/2a + (-b-sqrt(b²-4ac))/2a)/2 = -b/2a
The yv coordinate can be found by plugging in xv in the function
yv = a(-b/2a)² + b(-b/2a) + c, which will be equal to -(b²-4ac)/4a.
What is the length of the side adjacent to angle 0?
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To answer this question, we always need to take into account the reference angle in a right triangle. The reference angle here is theta, Θ, and we have that:
Then, the length of the side adjacent to theta is equal to 15.
In summary, we have that the length of the side adjacent to the angle Θ is equal to 15.
Under certain conditions, the velocity of a liquid in a pipe at distance r from the center of the pipe is given by V = 400(3.025 x 10-5--2) where Osrs5,5x10 -3. Writeras a function of V.r=where the domain is a compound inequality(Use scientific notation. Use integers or decimals for any numbers in the expression.)Le
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Solving the equation for r:
[tex]\begin{gathered} V=400(9.025\cdot10^{-5}-r^2) \\ r^2=9.025\cdot10^{-5}-\frac{V}{400} \\ r=\sqrt[]{9.025\cdot10^{-5}-\frac{V}{400}} \end{gathered}[/tex]With the first equations, we can establish some limits for V:
With the lowest value for r (r=0):
[tex]\begin{gathered} V=400(9.025\cdot10^{-5}-0^2) \\ V=400(9.025\cdot10^{-5}) \\ V=3.61\cdot10^{-2} \end{gathered}[/tex]With the highest value for r (r=9.5x10^-3)
[tex]\begin{gathered} V=400(9.025\cdot10^{-5}-(9.5\cdot10^{-3})^2) \\ V=400(9.025\cdot10^{-5}-9.025\cdot10^{-5}) \\ V=400(0) \\ V=0 \end{gathered}[/tex]According to the radius range, velocity can be between 0 and 3.61x10^-2
It is also necessary to check the domain of the function considering it is a square root. The argument of an square root cannot be less than 0. Then:
[tex]\begin{gathered} 9.025\cdot10^{-5}-\frac{V}{400}\ge0 \\ 9.025\cdot10^{-5}\ge\frac{V}{400} \\ V\leq400(9.025\cdot10^{-5}) \\ V\leq3.61\cdot10^{-2} \end{gathered}[/tex]This is the same limit for velocity obtained before. Then, we can say for velocity that:
[tex]0\leq V\leq3.61\cdot10^{-2}[/tex]you are packing for a road trip and want to figure out how much you can fit in your rectangular suitcase the suitcase has the following dimensions list length2 1/3ft width 1/3ft 1 1/2ft what is the volume of your suitcase in cubic feet
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The Volume of the suitcase is given by the formula:
Length x width x height = L X W X H
L= 2 1/3ft
W= 1/3ft
H= 1 1/2ft
[tex]\begin{gathered} \text{Volume = 2}\frac{1}{3\text{ }}\text{ x }\frac{1}{3}\text{ x 1}\frac{1}{2}ft^3 \\ V\text{ = }\frac{7}{3}\text{ x }\frac{1}{3}\text{ x}\frac{3}{2}ft^3 \\ V\text{ = }\frac{21}{18}ft^3 \\ V=\text{ }\frac{7}{6}ft^3 \\ V=\text{ 1}\frac{1}{6}ft^3 \end{gathered}[/tex]Volume of the suitcase is 1 1/6 cubic feet
nction.
f(x) = -x² + 3x + 11
Find f(-1)
Answers
Answer:
f(-1) = 7
Step-by-step explanation:
Hello!
You can evaluate for f(-1) by substituting -1 for x in the equation.
Evaluate f(-1)f(x) = -x² + 3x + 11f(-1) = -(-1)² + 3(-1) + 11f(-1) = -1 -3 + 11f(-1) = -4 + 11f(-1) = 7f(-1) is 7.
f(-1) = 2 + -3 + 11
f(-1) = 10
Answer:
f(-1) = 7
Step-by-step explanation:
Hello!
You can evaluate for f(-1) by substituting -1 for x in the equation.
Evaluate f(-1)f(x) = -x² + 3x + 11f(-1) = -(-1)² + 3(-1) + 11f(-1) = -1 -3 + 11f(-1) = -4 + 11f(-1) = 7f(-1) is 7.
f(-1) = 2 + -3 + 11
f(-1) = 10
Use function composition to verify f(x)=-3x+5 and g(x)=5x-3 are inverses. Type your simplified answers in descending powers of x an do not include any spaces between your characters.Type your answer for this composition without simplifying. Use parentheses to indicate when a distribution is needed to simplify. g(f(x))=AnswerNow simplify the composition, are f(x) and g(x) inverses? Answer
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Answer:
• (a)g[f(x)]=5(-3x+5)+5
,• (b)No
Explanation:
Given f(x) and g(x):
[tex]\begin{gathered} f(x)=-3x+5 \\ g(x)=5x-3 \end{gathered}[/tex](a)First, we find the composition, g[f(x)].
[tex]\begin{gathered} g(x)=5x-3 \\ \implies g\lbrack f(x)\rbrack=5f(x)-3 \\ g\lbrack f(x)\rbrack=5(-3x+5)+5 \end{gathered}[/tex](b)Next, we simplify g[f(x)] obtained from part (a) above.
[tex]\begin{gathered} g\mleft[f\mleft(x\mright)\mright]=5\mleft(-3x+5\mright)+5 \\ =-15x+25+5 \\ =-15x+30 \end{gathered}[/tex]Given two functions, f(x) and g(x), in order for the functions to be inverses of one another, the following must hold: f[g(x)]=g[f(x)]=x.
Since g[f(x)] is not equal to x, the functions are not inverses of one another.
( x+y+z = -1), ( y-3z = 11), ( 2x+y+5z = -12)1. determine whether the system is inconsistent or dependent2. if your answer is dependent, find the complete solution. Write x and y as functions of zx=y=
Answers
Inconsistent
Explanation:a) Given:
x + y + z = -1 . . .(1)
y - 3z = 11 . . . (2)
2x + y + 5z = -12 . . .(3)
To find:
If the solution of the system of equations is either consistent dependent solution or an inconsistent one
We need to solve the system of equations. From equation (2), we will make y the subject of formula:
y = 11 + 3z (2*)
Substitute for y with 11 + 3z in both equation (1) and (2):
For equation 1: x + 11 + 3z + z = -1
x + 11 + 4z = -1
x + 4z = -1-11
x + 4z = -12 . . . (4)
For equation 3: 2x + 11 + 3z + 5z = -12
2x + 11 + 8z = -12
2x + 8z = -12-11
2x + 8z = -23 . . .(5)
We need to solve for x and z in equations (4) and (5)
Using elimination method:
To eliminate a variable, its coefficient needs to be the same in both equations
Let's eliminate x. We will multiply equation (4) by 2:
2x + 8z = -24 . . . (4*)
Now both equations have the same coefficient of x. Subtract equation (4) from (5):
2x - 2x + 8z - 8z = -23 - (-24)
0 + 0 = -23 + 24
0 = 1
Let hand side is not the same as right hand side.
When the left hand side is not equal to right hand side, the solution is said to be inconsistent or no sloution.
Your answer is inconsistent
Find the union of E and L.Find the intersection of E and L.Write your answers using set notation (in roster form).
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For the intersection operation we have to look what elements both sets have in common, in this case both E and L has the number 8. Then the second answer is:
[tex]E\cap L=\lbrace8\rbrace[/tex]Now, the union operation adds the all elements into a single set without repetition, in this case the first answer is:
[tex]E\cup L=\lbrace-2,1,2,3,6,7,8\rbrace[/tex]Which of the following is true of points on the line y=5/3 x + 1/2? (1) For every 3 units that increases, y will increase by 5 units. (2) For every 5 units that x increases, y will increase by 2 units. (3) For every 2 units that x increases, y will increase by 1 unit. (4) For every 1 unit that x increases, y will increase by 2 units.
Answers
4) For every 1 unit that x increases, y will increase by 2 units.
1) For the function y=5/3x +1/2
If we remember that "rise over run" mnemonics, that'll make it easier to memorize it.
2) Plotting the graph of this function. Look at point A (1,2)
Counting from bottom to up (2 units "rise" on the y-axis, point A is 1 unit to right "run". So, For every 1 unit that x increases, y will increase by 2 units.
Line g passes through the points (-2.6,1) and (-1.4.2.5), as shown. Find theequation of the line that passes through (0,-b) and (c,0).
Answers
The blue line passes through the points
(-2.6, 1) and (-1.4, 2.5)
I will label the coordinates as follows for reference:
[tex]x_1=-2.6,y_1=1,x_2=-1.4,y_2=2.5[/tex]Step 1: Find the slope of the blue line
The slope between two points is calculated with the formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]We substitute the values and we get that the slope of the blue line is:
[tex]m=\frac{2.5-1}{-1.4-(-2.6)}=\frac{1.5}{1.2}=1.25[/tex]The slope m of the blue line is 1.25.
step 2: With that slope, calculate b (the intercept of the blue line with the y axis).
For this we use the point - slope equation:
[tex]y=m(x-x_1)+y_1[/tex]Where we will use the sane x1 and x2 as in the previous step, so we get
[tex]\begin{gathered} y=1.25(x-(-2.6))+1 \\ y=1.25(x+2.6)+1 \\ y=1.25x+3.25+1 \\ y=1.25x+4.25 \end{gathered}[/tex]We compare this with the slope-intercept equation
[tex]y=mx+b[/tex]And we can see that the incercept b is 4.25
[tex]b=4.25[/tex]step 3: Find the value of c.
to find the value of c, we need to know at which point the blue line crosses the x axis.
Since we already have the equation of the blue line y=1.25x+4.25, and the line crosses the x axis at y=0, we substitute this to find the x value that is equal to c:
[tex]\begin{gathered} 0=1.25x+4.25 \\ -4.25=1.25x \\ \frac{-4.25}{1.25}=x \\ -3.4=x \end{gathered}[/tex]The blue line crosses the x axis at (-3.4,0), thus we can conclude that
[tex]c=-3.4[/tex]Step 4: Define the two point where the orange line passes through.
We know from the picture that the orange line passes through (c,0) and (0,-b)
Since we have the values of c = -3.4 and b=4.25, we can say that the orange line passes through (-3.4, 0) and (0, -4.25)
Step 5: Calculate the slope of the orange line.
the orange line passes through (-3.4, 0) and (0, -4.25), so we define:
[tex]undefined[/tex]A)As the x-value Increases by one, the y-value decreases by 2.26.B)As the x-value increases by one, the y-value decreases by 53.769.C)As the x-value Increases by one, the y-value increases by 2.26.D)As the x-value Increases by one, the y-value Increases by 53.769. Which equation describes the line of best fit for the table below?
Answers
Option A
Explanations:The graph shows an inverse proportion.
As x increases, y decreases in value.
Finding the slope of the graph:
dy / dx = (y₂ - y₁) / (x₂ - x₁)
x₁ = 5, x₂ = 9, y₁ = 40, y₂ = 30
dy / dx = (30 - 40) / (9 - 5)
dy / dx = -10 / 4
dy / dx = -2.5
This means that as x increases by 1, decreases by 2.5
A is the only correct option.
IF P(A)=0.2 P(B)=0.1 and P(AnB)=0.07 what is P(AuB) ?A.0.13 B. 0.23 C. 0.3 D.0.4
Answers
ANSWER
P(AuB) = 0.23
STEP-BY-STEP EXPLANATION:
Given information
P(A) = 0.2
P(B) = 0.1
P(AnB) = 0.07
What is P(AUB)
[tex]P(\text{AuB) = P(A) + P(B) }-\text{ P(AnB)}[/tex]The next step is to substitute the above data into the formula
[tex]\begin{gathered} P(\text{AuB) = 0.2 + 0.1 - 0.07} \\ P(\text{AuB) = 0.3 - 0.07} \\ P(\text{AuB) = 0.23} \end{gathered}[/tex]Find the percent of change from 120 bananas to 40 bananas.
Answers
Answer:
67% decrease
Explanation:
From the given problem:
Initial number of bananas = 120
Final number of bananas = 40
[tex]\begin{gathered} \text{Percent Change=}\frac{Final\text{ Value-Initial Value}}{\text{Initial Value}}\times100 \\ =\frac{40-120}{120}\times100 \\ =-\frac{80}{120}\times100 \\ =-0.667\times100 \\ =-66.7\% \\ \approx-67\% \end{gathered}[/tex]Since we have a negative value, we have a 67% decrease.
Help me to answer this question with vectors, thank you
Answers
To find:
The coordinates of a point P such that PA = PB.
Solution:
Given that A(4, 0) and B(0, 9) are the coordinates.
Let the point P is (x,0) because the point is on x-axis, and it is given that |PA| = |PB|.
So,
[tex]\sqrt{(4-x)^2+(0-0)^2}=\sqrt{(x-0)^2+(0-9)^2}[/tex]Now, squaring both the sides:
[tex]\begin{gathered} (4-x)^2=x^2+9^2 \\ 16+x^2-8x=x^2+81 \\ 8x=-65 \\ x=\frac{-65}{8} \end{gathered}[/tex]Thus, the coordinates of point P are (-65/8, 0).