Solve the formula for r.

Answer:

plot the point at 1

Step-by-step explanation:

a) 1/2, b) 1/4, c) 3/13, d) 7/26 (fraction of black and face cards) in a traditional Western pack of playing cards.

A traditional Western pack of playing cards consists of four suits: Hearts (colored red), Diamonds (colored red), Spades (colored black), and Clubs (colored black). Each suit has 13 cards: Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, and King.

a) To find the fraction of the playing cards that are red, we need to add up the number of red cards and divide by the total number of cards in the deck. There are two red suits, Hearts and Diamonds, and each has 13 cards. So there are 26 red cards in total. Since there are 52 cards in a deck, the fraction of red cards is 26/52 or 1/2.

b) To find the fraction of cards that are Diamonds, we simply divide the number of Diamonds (13) by the total number of cards (52). This gives us a fraction of 13/52 or 1/4.

c) To find the fraction of face cards, we need to add up the number of face cards and divide by the total number of cards in the deck. In each suit, there are three face cards: King, Queen, and Jack. So there are 12 face cards in each deck (4 suits x 3 face cards per suit). Therefore, there are 12/52 or 3/13 face cards in the deck.

d) To find the fraction of black and face cards, we need to count the number of black cards and the number of face cards that are also black. There are two black suits, Spades and Clubs, and each has 13 cards. So there are total 26 black cards. Of these 26 cards, there are 12 face cards (King, Queen, and Jack) which are not black, leaving 14 black cards which are face cards. Therefore, the fraction of black and face cards is 14/52 or 7/26.

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The equivalent expressions of [tex]x^3[/tex] are[tex]\frac{(x ^ 6)}{(x ^ 3)}[/tex]and [tex]\frac{(x^{-3}) }{(x^{-6}) }[/tex], the expressions [tex]\frac{(x^{30}) }{(x^{10})}[/tex] and [tex]\frac{(x ^ 4) ^ 2)}{x ^ 2}[/tex] are not equivalent to [tex]x^3[/tex].

What are equivalent expressions?

Equivalent expressions are different algebraic expressions that have the same value when evaluated for a particular set of variables.

The equivalent expressions  [tex]x^3[/tex] are:

[tex]\frac{(x ^ 4) ^ 2)}{x ^ 2}[/tex] : This expression can be simplified as follows:

=[tex]\frac{(x ^ 4) ^ 2)}{x ^ 2}[/tex]

= [tex]\frac{(x ^ 8)}{(x ^ 2) }[/tex]

=[tex]x^{8-2}[/tex]

= [tex]x^6[/tex]

[tex]\frac{(x ^ 6)}{(x ^ 3)}[/tex] : This expression can be simplified as follows:

=[tex]\frac{(x ^ 6)}{(x ^ 3)}[/tex]

= [tex]x^{6-3}[/tex]

=[tex]x^3[/tex]

[tex]\frac{(x^{30}) }{(x^{10})}[/tex] : This expression can be simplified as follows:

=[tex]\frac{(x^{30}) }{(x^{10})}[/tex]

=[tex]x^{30-10}[/tex]

=[tex]x^{20}[/tex]

[tex]\frac{(x^{-3}) }{(x^{-6}) }[/tex] : This expression can be simplified as follows:

=[tex]\frac{(x^{-3}) }{(x^{-6}) }[/tex]

=[tex]x^{-3-(-6)}[/tex]

=[tex]x^{-3+6}[/tex]

=[tex]x^{3}[/tex]

Therefore, the equivalent expressions of [tex]x^3[/tex] are[tex]\frac{(x ^ 6)}{(x ^ 3)}[/tex]and [tex]\frac{(x^{-3}) }{(x^{-6}) }[/tex] , the expressions [tex]\frac{(x^{30}) }{(x^{10})}[/tex] and [tex]\frac{(x ^ 4) ^ 2)}{x ^ 2}[/tex] are not equivalent to [tex]x^3[/tex].

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For the given elementary chemical reaction, the solution to the question is: C = a^2 * (1-t^2/400(1-a))

The question asks about calculating the concentration of C in a chemical reaction. Given that the reaction equation is as follows: A + B → C The rate of reaction can be expressed as: dc/dt = k[A][B] Where, k is the rate constant[A] is the concentration of reactant A in moles/L[B] is the concentration of reactant B in moles/L, c is the concentration of product C in moles/L

The initial concentration of A and B is [A] = a moles/L, [B] = b moles/L Let r be the rate of reaction, i.e. r = dc/dt Thus, using the equation r = k[A][B], we get r = k(a)(b)Now, we can write a differential equation for the concentration of C as follows: dc/dt = r, with initial concentration of C as 0 moles/L∴ dc/dt = kab

Substituting r = k(a)(b) in the equation, we get dc/dt = kabdc/db = kab*dt Differentiating both sides, we get, ln(C) = kab*t + C where C is a constant, ln(C) = ln(a^2) = 2ln(a) = C When a = b, the concentration of C will be maximum at t = (1/k)(ln(a)).

Thus the concentration of C as a function of time (when a = b) is given by C = a^2 * (1-t^2/2)If [C] = a after 20 seconds, then using the equation, we get a = a^2 * (1 - 20^2 * k^2/2)Therefore, 1 = a * (1 - 200k^2) Solving this equation for k, we get, k = ± sqrt[(1-a)/200a^2] For the positive value of k, the concentration of C as a function of time is given by C = a^2 * (1-t^2/400(1-a)).

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The solution of the system is a = -1, b = 1, c = 0, and d = -3.

To find the cubic function f(x) = ax³ + bx² + cx + d that satisfies the given equations by using a system of equations and solving the system using matrices, we proceed as follows:Equations for the given cubic function:f(-2) = a(-2)³ + b(-2)² + c(-2) + d = -7 ...(1)f(-1) = a(-1)³ + b(-1)² + c(-1) + d = 2 ...(2)f(1) = a(1)³ + b(1)² + c(1) + d = -4 ...(3)f(2) = a(2)³ + b(2)² + c(2) + d = -7 ...(4)The matrix form of the system of equations is given by AX = B, whereA = [(-2)³ (-2)² -2 1; (-1)³ (-1)² -1 1; (1)³ (1)² 1 1; (2)³ (2)² 2 1],X = [a; b; c; d], andB = [-7; 2; -4; -7].The augmented matrix form of the system of equations is given by [A|B] = [(-2)³ (-2)² -2 1 -7; (-1)³ (-1)² -1 1 2; (1)³ (1)² 1 1 -4; (2)³ (2)² 2 1 -7].Performing the row operations, we get the row echelon form of the augmented matrix as follows:[A|B] = [1 0 0 0 -1; 0 1 0 0 1; 0 0 1 0 0; 0 0 0 1 -3].Therefore, the solution of the system is a = -1, b = 1, c = 0, and d = -3.Hence, the cubic function f(x) = ax³ + bx² + cx + d that satisfies the given equations is given by f(x) = -x³ + x² - 3.

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Answer:

No

Step-by-step explanation:

[tex]\frac{6}{5}=1.2[/tex]

[tex]\frac{4}{3} =1.33[/tex]

[tex]\frac{6}{5} < \frac{4}{3}[/tex]

Hope this helps.

Answer:

No

Step-by-step explanation:

6/5=4/3

18=20

9≠10

Answer:347

Step-by-step explanation:=

347 ⇔ 347 R 0

8328 divided by 24

=

347 with a remainder of 0

The equation of the given graph is: y = cosine (x + pi)

By convention, the cosine function like most other trigonometric functions has a period of 2π.

Since, the parental function is y = cos x, which has y-intercept at y = 1, and x-intercept at π/2.

From observation, the function showed in the graph attached has y-intercept at y = -1 and x-intercept at π/2.

This can be interpreted to mean that the function has been translated leftwards π units.

Ultimately, the function that belongs to this graph is; y = cosine (x + pi)

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Answer: D. y = cosine (x + pi)

Step-by-step explanation:

Answer:

It depends on the values of x and y. If x is positive and y is negative, then option A (x + y) would have a negative value. If y is greater than x, then option B (x - y) would have a negative value. If either x or y (or both) is negative, then option C (x*y) could have a negative value. Option D (x/y) could also have a negative value if x is negative and y is positive, or if both x and y are negative.

Answer:

Step-by-step explanation:

B because it has subtraction

Absolutely, Jada's response is right. A square is a quadrilateral with four equal-length sides. A quadrilateral is a square if all four sides measure 5 cm.

Unfortunately, there is no alternative form Jada could have drawn that meets the requirement of all four sides measuring 5 cm. Every other quadrilateral with four equal-length sides is likewise a square. If Jada had drawn a quadrilateral with one or more sides of varying lengths, the specified criterion would not have been met. As a result, the only design Jada could have sketched that meets the requirement of having all four sides measure 5 cm is a square. It is worthwhile to investigate the properties of quadrilaterals and how they connect to the conditions presented in the problem. A quadrilateral is a four-sided polygon. Quadrilaterals come in a variety of shapes, including squares, rectangles, parallelograms, trapezoids, and kites. Certain quadrilaterals have unique qualities, such as opposing sides that are parallel or all angles that are right angles. The criterion in the provided problem is that all four sides of the quadrilateral measure 5 cm.

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Probability 0.919

The probability that the pooled sample variance, S2p, is less than 6.9157 is given by:

P(S2p < 6.9157) = P(S2p - S20 < 6.9157 - S20)

where S20 = ((n1-1)S21 + (n2-1)S22)/(n1+n2-2)



Here, n1 = 10 and n2 = 11. The individual sample variances S21 and S22 are both equal to 4, since both X and Y are samples from N(μ, 4).


Therefore, S20 = ((10-1)4 + (11-1)4)/(10+11-2) = 4.


Hence, P(S2p < 6.9157) = P(S2p - 4 < 6.9157 - 4) = P(S2p - 4 < 2.9157)


The probability can be computed using a chi-square cumulative distribution table. We obtain:

P(S2p - 4 < 2.9157) = 0.919.

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The Probability P(Sp² ​<6.9157) is 0.6672.

To solve this problem, we need to first recognize that the statistic Sp² follows a chi-squared distribution with 10+11-2 = 19 degrees of freedom, where:

Sp² = [(nX-1)*SX² + (nY-1)*SY²]/(nX+nY-2)

Here, nX = 10, nY = 11, SX² is the sample variance of X and SY² is the sample variance of Y.

Since X and Y are both normally distributed, we know that the sample variances SX² and SY² follow chi-squared distributions with 9 and 10 degrees of freedom, respectively, and scaled by the common variance sigma² = 4.

So we have:

SX² ~ chi-squared(9)*4 = chi-squared(36)

SY² ~ chi-squared(10)*4 = chi-squared(40)

Now we can use the fact that the sum of two independent chi-squared random variables with k1 and k2 degrees of freedom follows a chi-squared distribution with k1+k2 degrees of freedom.

Therefore, Sp² = [(nX-1)*SX² + (nY-1)*SY²]/(nX+nY-2) follows a chi-squared distribution with 9+10 = 19 degrees of freedom and scale parameter 4/(nX+nY-2) = 4/19.

To find P(Sp² < 6.9157), we can use a chi-squared distribution table or calculator. Using a chi-squared calculator, we find:

P(Sp² < 6.9157) = 0.6672

Therefore, the probability that Sp² is less than 6.9157 is 0.6672.

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Answer:

-16²+1,000 > 300  [After an edit in the original expression, as noted below).

Step-by-step explanation:

The equation d = -16² +1,000 tells us the height above ground, d, of the object after t seconds.  When t = 0 seconds, the ball has not been dropped yet, but the equation tells us that d = 1,000 at t = 0.  That means the object starts at 1,000 feet above ground.

We want the time it takes for the object to reach any height greater than 300 feet above ground.  This is a tad (metric for just a tiny bit) unexpected, since even at time of 0 the object is greater than 1,000 feet.

Looking at the answer options, note that the left side of the inequalities is -16^2+100.  I will assume the 4th option has a typo:  the f^2.  It should read the same as the others.  

      -16^2+100 is the distance, d.  So to help us think this through, let's rephrase the answer options in terms of distance, d:

1)    d<300

2)   d≤300

3)   d≥300

4)   d>300

   The question asks "We want the time it takes for the object to reach any height greater than 300 feet above ground."

Option 4 says d>300, or height greater than 300.  That is the inequality that matches the question.  [Note:  It did not say greater than or equal to (option 3).]

With the applicatiοn οf Distributive Prοperty οf Multiplicatiοn, the fοllοwing equatiοn 3 (x + 2) + 5 can be written as

3*x + 3*2 + 5

The distributive prοperty οf multiplicatiοn is a mathematical rule that states that the prοduct οf a number and a sum can be οbtained by adding the prοducts οf the number and each term in the sum. In οther wοrds, a(b+c) = ab + ac. This prοperty can be used tο simplify expressiοns by breaking them dοwn intο smaller parts.

It is an impοrtant cοncept in algebra and is οften used tο sοlve equatiοns and simplify expressiοns. The distributive prοperty can alsο be applied tο variables and expοnents, and is a fundamental principle in the study οf algebraic structures such as rings and fields.

With the applicatiοn οf Distributive Prοperty οf Multiplicatiοn, the fοllοwing equatiοn 3 (x + 2) + 5 can be written as

3*x + 3*2 + 5

further simplified will give 3x + 6 + 5 = 3x + 11

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Based on the principle of Inequality, Attached image is a graph of the inequality for  |x| < 5. The red region is the solution set.

A mathematical statement known as an equation demonstrates the relationship between two or more numbers and variables by utilizing mathematical operations such as addition, subtraction, multiplication, division, exponents, and so forth.

Therefore, An expression that demonstrates a non-equal comparison of numbers and variables is called an inequality. So, the graph that best represents this solution set is a number line with open circles at x = -5 and x = 5 and a shaded region in between, indicating that all values of x within this range satisfy the inequality.

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Answer:

£602.84 in New York

Step-by-step explanation:

London Cost:

Converting pound to dollars:

£800 * 1.41 = $1128

Paris cost:

Converting euro to pounds:

€880/1.16 = £759

Converting pound to dollars again:

£759 * 1.41 = $1070

New york cost:

$850

The lowest price is in new york which is:

$850/1.41 = £602.84

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