Answer: y=8-6x
Step-by-step explanation:
HELPPPPP ME PLEASEEEE
the product of 9/10 and 8/9 is...
A: between 0 and 1
B: between 1 and 2
C: between 2 and 3
D: greater than 3
please help with this question (d+2)(-7)
Answer:
-7d-14
Step-by-step explanation:
First, let's distribute -7 to (d+2)
-7xd
-7x2
We will get -7d-14
In 1992, Jason bought a gallon of gas for $1.15. Yesterday, he bought a gallon of gas for $2.12. What is the percentage increase of the price of a gallon of gas from 1992 to yesterday? If necessary, round to the nearest tenth of a percent.
A.
84.3%
B.
45.8%
C.
54.2%
D.
15.7%
In a class 3/4 of the boys like math, 1/2 like science, 1/4 of those who like science do not like math. How many boys like neither math nor science?
A. 1/4
B. 1/6
C. 1/2
D. 1/8
6 ×3(2+9)..can you give the answer of it please
Answer:
Hope this may helps you
Step-by-step explanation:
6×3(11)
6×33
198
Answer:
198
Step-by-step explanation:
6 ×3(2+9)
= 6×3×11
= 6×33
= 198
4. If 100.0g of nitrogen gas (N2) is reacted with 100.0g of hydrogen gas (H2) to form NH3. What are the limiting and excess reactants?
Hint: Convert grams to moles for each reactant and then convert to moles of NH3. You need your balanced equation from answer 1 to determine the mole relationship between each reactant and the product NH3. Use the periodic table to determine the molar mass of all chemical formulas. Fill in the “?” blanks below to show your work.
Balanced equation: 1N2 (g) + 3H2(g) 2NH3(g)
Molar mass of H2 = g/mol
100.0"g " "H" _2×(1"mol " "H" _2)/( ? "g " "H" _2 )×(" ? mol N" "H" _3)/(" ? mol " "H" _2 )= ? "mol N" "H" _3
Molar Mass of N2 = g/mol
100.0"g " "N" _2×(1"mol " "N" _2)/(" ? g " "N" _2 )×(" ? mole N" "H" _3)/(" ? mol " "N" _2 )= ? "mol N" "H" _3
A. What is the excess reactant? Hint: it is the reactant above that makes the most amount of product
B. What is the limiting reactant? Hint: it is the reactant above that makes the least amount of product
C. What is the theoretical yield of ammonia of the reaction?
Molar mass of NH3 = g/mol
100.0"g " "N" _2×(1"mol " "N" _2)/( ? "g " "N" _2 )×( ? "mol N" "H" _3)/( ? "mol " "N" _2 )×(" ? g N" "H" _3)/( 1 "mol N" "H" _3 )= ? "g N" "H" _3
Nitrogen (N) has a molar mass of about 14.007 g/mol, so you have
100.0 g N₂ = (100.0 g) • (1/28.014 mol/g) ≈ 3.570 mol N₂
Hydrogen (H) has a molar mass of about 1.008 g/mol, so
100.0 g H₂ = (100.0 g) • (1/2.016 mol/g) ≈ 49.60 mol H₂
In the balanced reaction, 1 mole of N₂ reacts with 3 moles of H₂ to make 2 moles of NH₃. We have
3.570 • 3 ≈ 10.71
so the reaction would use up all 3.570 mol N₂ and 10.71 mol H₂ to produce about 7.139 mol NH₃.
(A) H₂ is the excess reactant. There is an excess of 49.60 - 10.71 ≈ 38.89 mol H₂.
(B) N₂ is the limiting reactant. All of the N₂ gets consumed in the reaction.
(C) NH₃ has a molar mass of (14.007 + 3 • 1.008) g/mol = 17.031 g/mol. This reaction would theoretically yield about 7.139 mol NH₃, or
7.139 mol NH₃ = (7.139 mol) • (17.031 g/mol) ≈ 121.6 g NH₃
Please please please hellllllppp meeeeee !!!!!!!!!
What is the GCF of the expression -x2y22 - xy2z?
Answer:
i dont onderstand Thais
Bea is asked to graph this system of equations:
8x - 6y=3
-3y + 4x + 4
How many times will the lines intersect?
Answer:
The lines will not intersect, because this system has no solutions
Step-by-step explanation:
Answer:
They will not intersect!
Step-by-step explanation:
A-P-E-X
Of the factors of 12 shown, which also have a sum of 7?
A: 12,1
B: 2,6
C: 3,4
HELP ME PLZ
What is the slope of a parallel to the line that passes through (- 3, 1) and (3, 7)
Answer:
[tex]\frac{2}{3}[/tex]
Step-by-step explanation:
To find the slope, you need to find the [tex]\frac{rise}{run}[/tex] between two points.
[tex]\frac{rise}{run}[/tex] = [tex]\frac{7-1}{3-(-3)}[/tex]
= [tex]\frac{7-1}{3+3}[/tex]
= [tex]\frac{6}{9}[/tex]
= [tex]\frac{2}{3}[/tex]
Answer:
To calculate slope with any two given points the formula is y2 - y1 / x2 - x1. So to solve the problem just plug in the values: 7 - 1 / 3 - (-3), 6 / 6, the slope is 1
Emily has $110 in a savings account this year. She plans on depositing $10 into the savings account each following year. How much money will Emily have in the account after 9 years?
Answer:
.........................
Answer:
200
Step-by-step explanation:
she started with 110 dollars. then u multiple 10 and 9 for the years to come and and the total u had at the beginning giving u 200
Evaluate -5-15+4+15−5−15+4+15minus, 5, minus, 15, plus, 4, plus, 15.
Answer:
-2
Step-by-step explanation:
ur welcome
-1
Step-By step Explanation:
Haya la integral de xarcsenx/((1-x^2)^1/2). Utiliza la sustitución de t= arcsenx
Mi duda está la final, cuando queda - tcost + sent + k, no sé cómo sustituir t= arcsent
Answer:
Explicación más abajo
Step-by-step explanation:
Integración Indefinida
La integral
[tex]I=\int \dfrac{x .arcsen\left(x\right)}{\sqrt{1-x^2}}[/tex]
Se resuelve con el cambio de variables:
t=arcsen(x)
Una vez hechos los cambios, la integral se resuelve en función de t:
[tex]I=sen(t)-t.cos(t)+C[/tex]
Hay que devolver los cambios para mostrarla en función de x.
El cambio de variables también se puede escribir:
x=sen(t)
Recordando que
[tex]cos(t)=\sqrt{1-sen^2(t)}[/tex]
Entonces:
[tex]cos(t)=\sqrt{1-x^2}[/tex]
Devolviendo los cambios:
[tex]I=sen(t)-t.cos(t)+C=x-arcsen(x)\sqrt{1-x^2}+C[/tex]
Es la respuesta correcta
complete the table of values for y=2-x
x= -1, 0, 1, 2, 3, 4,
y= , , , , -1, ,
Answer:
x = -1, 0, 1, 2, 3, 4
y = 3, 2, 1, 0, -1, -2
Answer:
x = -1, 0, 1, 2, 3, 4
y = 3, 2, 1, 0, -1, -2
The regular price of a hooded jacket is $25.75. During a sale, the jacket was marked as 20% off. What was the approximate price of the jacket during the sale?
A.
$5.15
B.
$20.60
C.
$21.62
D.
$23.75
Answer:
5.15 hope this help!!!
Step-by-step explanation:
give this brainlieast so other people can know its not 20.60
simplify x^2 + ax - 2a^2÷
3a^2 - 2ax - x^2?
Answer:
[tex] - \frac{x + 2a}{3a + x} [/tex]
Step-by-step explanation:
[tex] \frac{ {x + ax - 2 {a}}^{2} }{3a {}^{2} - 2ax - {x}^{2} } [/tex]
i) write ax as a difference
[tex] \frac{ {x}^{2} + 2ax - ax - 2 {a}^{2} }{3 {a}^{2} - 2ax - x {}^{2} } [/tex]
ii) write -2ax as a difference
[tex] \frac{ {x}^{2} + 2ax - ax - 2a {}^{2} }{3a {}^{2} + ax - 3ax - x {}^{2} } [/tex]
iii) factor out x from the expression
[tex] \frac{x(x + 2a) - ax - 2 {a}^{2} }{3 {a}^{2} + ax - 3ax - {x}^{2} } [/tex]
iv) factor out -a from the expression
[tex] \frac{x(x + 2a) - a(x + 2a)}{3 {a}^{2} + ax - 3ax - {x}^{2} } [/tex]
v) factor out a from the expression
[tex] \frac{x(x + 2a) - a(x + 2a)}{a(3a + x) - 3ax - {x}^{2} } [/tex]
vi) factor out -x from the expression
[tex] \frac{x(x + 2a) - a(x + 2a)}{a(3a + x) - x(3a + x)} [/tex]
vii) factor out x+2a from the expression
[tex] \frac{(x + 2a)(x - a)}{a(3a + x) - x(3a + x)} [/tex]
viii) factor out 3a+x from the expression
[tex] \frac{(x + 2a)(x - a)}{(3a + x)(a - x)} [/tex]
ix) factor out the negative sign from the expression and rearrange the term
[tex] \frac{(x + 2a)( - ( - a - x))}{(3a + x)(a - x)} [/tex]
x) reduce the fraction a-x
[tex] \frac{(x + 2a)( - 1)}{(3a + x)} [/tex]
[tex] - \frac{x + 2a}{3a + x} [/tex]
Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below are the weights in pounds of 11 players randomly selected from the roster of a championship sports team. Are the results likely to be representative of all players in that sport's league? 278 279 185 299 245 281 291 234 278 227 281
Answer:
Mean = 261.63 poundsMedian = 278 poundsModes: 278 & 281Mid-range = 242Yes all the results will be able to represent all players in the sports leagueStep-by-step explanation:
First of all, we will sort the data.
185 227 234 245 278 278 279 281 281 291 299
Mean:
Mean is defined as the sum of values divided by the number of values.
n = 11
[tex]Mean = \frac{sum}{n}\\= \frac{185+227 +234+ 245+ 278+ 278+ 279+ 281+ 281+ 291+ 299}{11}\\=\frac{2878}{11}\\=261.63\ pounds[/tex]
Median:
As the number of values is odd,
The median will be:
[tex]Median = (\frac{n+1}{2})th\ value\\= \frac{11+1}{2}\\=\frac{12}{2}\\=6th\ value[/tex]
The 6th value is 278
Median = 278
Mode:
Mode is the most frequent value in a data set.
In the given dataset,
278 and 281 are modes as both are repeated twice
Mid-range:
Mid-range is the average of maximum and minimum value
So,
Min = 185
Max = 299
So,
[tex]Mid-range = \frac{Max+Min}{2}\\= \frac{185+299}{2}\\= \frac{484}{2}\\= 242[/tex]
Hence,
Mean = 261.63 poundsMedian = 278 poundsModes: 278 & 281Mid-range = 242Yes all the results will be able to represent all players in the sports leagueBy what percent is 16 greater than 12.
Answer:
28 i assume.
Answer:
The answer is 28% :))
What is the value of the expression shown? 4[4.5 − 2(1.2)]
Suppose a country's population at any time t grows in accordance with the rule dP dt = kP + I where P denotes the population at any time t, k is a positive constant reflecting the natural growth rate of the population, and I is a constant giving the (constant) rate of immigration into the country. If the total population of the country at time t = 0 is P0, find an expression for the population at any time t.
Answer:
[tex]\mathbf{P =\bigg (P_o +\dfrac{ I}{k} \bigg)e^{kt}- \dfrac{I}{k}}[/tex]
Step-by-step explanation:
Given that:
A country population at any given time (t) is:
[tex]\dfrac{dP}{dt}= kP+I[/tex]
where;
P = population at any time t
k = positive constant
I = constant rate of immigration into the country.
Using the method of separation of the variable;
[tex]\dfrac{dP}{kP+1}= dt[/tex]
Taking integration on both sides:
[tex]\int \dfrac{dP}{kP+I}= \int \ dt[/tex]
[tex]\dfrac{1}{k} log (kP + I) = t+c_1 \ \ \ here: c_1 = constant \ of \ integration[/tex]
[tex]log (kP + I) =k t+kc_1[/tex]
By applying the exponential on both sides;
[tex]e^{log (kP + I) }=e^{k t+kc_1 }[/tex]
[tex]KP+I = e^{kt} *e^{kc_1}[/tex]
Assume [tex]e^{kc_1 }= C[/tex]
Then:
[tex]kP + I = Ce^{kt}[/tex]
[tex]kP = Ce^{kt}-I[/tex]
[tex]P =\dfrac{ Ce^{kt}-I}{k} \ \ \---- Let \ that \ be \ equation \ (1)[/tex]
When time t = 0, The Total population of the country is also [tex]P_o[/tex]
[tex]P_o = \dfrac{Ce^{0(t)} -I}{k}[/tex]
[tex]P_o = \dfrac{Ce^{0} -I}{k}[/tex]
[tex]P_o = \dfrac{C-I}{k}[/tex]
C - I = kP₀
C = kP₀ + I
Substituting the value of C back into equation(1), we have:
[tex]P =\dfrac{ (kP_o+1)e^{kt}-I}{k}[/tex]
[tex]P =\dfrac{ (kP_o+1)e^{kt}}{k} - \dfrac{I}{k}[/tex]
[tex]\mathbf{P =\bigg (P_o +\dfrac{ I}{k} \bigg)e^{kt}- \dfrac{I}{k}}[/tex]
Which of these graphs represents a function?
A)
A
B)
B
C)
С
D)
D
You’ve learned to identify whether a function is even or odd both graphically and algebraically. How does the notation for reflections over the x-axis and over the y-axis relate to the notation for even and odd functions? Remember that if f(-x) = f(x), a function is even, and if f(-x) = -f(x), then the function is odd.
Answer:
Because even and odd are 2 different ways to determine whether or not you get the right answer for the chosen function.
Step-by-step explanation:
Hope this helps!!!
Answer:
For even functions, we take f(-x) to be the starting function. The y-axis reflection of this function is f(-(-x)), which is equal tof(x). So the relationship f(-x) = f(x) means that the function is the same as its y-axis reflection.
For odd functions, there are two reflections that must occur. First, we start with f(-x). The y-axis reflection of this function is f(-(-x)) = f(x). When we apply an x-axis reflection to this result, we get -f(-(-x)) = -f(x). So the fact that f(-x) = -f(x) means that odd functions are the same as sequential reflections across both the x-axis and the y-axis. (The same sequence of reflections also represents a rotation 180 degrees about the origin).
Step-by-step explanation:
Lacey is buying a new car. She can get a station wagon, a truck, a hatchback, or a convertible. The outside paint comes in yellow or green. The seats can be covered with white leather or gray fabric. Given these choices, how many different combinations does Lacey have to choose from?
Step-by-step explanation:
4 different vehicles,
2 different paints,
2 different seats.
Total number of combinations = 4 * 2 * 2 = 16.
If point C lies between two points A and B such that AC=BC, then
Answer:
If point C lies between two points A and B such that AC=BC, then point C is the bisector of A and B, that means it is at right the centre.
A certain radioactive isotope has a half-life of 50 years. A scientist determines that there are 200 grams of the radioactive material present today. How
Much of the isotope was present 200 years ago?
im guessing 800 50X4 = 200 and 200X4 = 800
i never learned this but i hope its correct.
Help please!!!
Triangle ABC is similar to triangle PQR, as shown below
Answer:
b:q
Step-by-step explanation:
im pretty sure its that. ive learned this before.
if you flipped them so that c and r were facing the same direction, then b and q would be too.
12 points!! PLEASE
y =(x-3) - 4
rewrite these in standard and factored form!!
Standard form:
x - y = 7
Factored form:
y = x - 7
Answer:
y = x - 3 - 4
y = x - 7
(x - 7 = y)
(x = y + 7)
Step-by-step explanation:
Hope you got it.
Please help me out !!!
Answer:
If the segments AU and UT are equal then AT equals 66, if the segments are not equal then AT equals 6x+24. Depends on what you are learning. Use what you need!
Step-by-step explanation:
4x+5 = 2x+19
2x=14
x=7
4(7)+5+2(7)+19 = 42+24 = 66
Compré 18 cuadernos, 24 carpetas y 17 lapiceras. El precio de las carpetas excede al de los cuadernos en un 40%, mientras que el precio de las lapiceras es el 20% del precio de los cuadernos. Si el importe de la compra fue de $11.825, calcular el precio unitario de cada artículo
Answer:talk some English dude
Step-by-step explanation: