slove the inequality of x^3+ 9x^2-10x>0 ?

The height of the flagpole is 45 feet

We have to take note of the different trigonometric identities. They include;

From the information given, we have that;

The angle of elevation, θ = 60 degrees

The shadow of the flagpole is the adjacent side = 26 feet

The opposite side is the height of the flagpole = x

Using the tangent identity, we have;

tan 60 = x/26

cross multiply the values

x = tan 60 × 26

Find the tangent values

x = 1. 732(26)

multiply the values

x = 45 feet

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The non-skewness criterion using estimates for p₁ and p₂ is 0.21 and null hypothesis test for whether a higher proportion of people in Toronto own a French bulldog relative to the proportion of people in Guelph is Z= 1.47.

A statistical hypothesis known as a null hypothesis asserts that no statistical significance can be found in a collection of provided observations. Using sample data, hypothesis testing is performed to judge a theory' veracity. It is sometimes referred to as the "null," and it is denoted by the symbol H₀.

To determine if a theory regarding markets, investment methods, or economies is correct or wrong, quantitative analysts employ the null hypothesis, often known as the conjecture.

a) n₁ = 55, n₂ = 62

x₁ = 15, x₂ = 10

a) Toronto = [tex]P_1[/tex] = [tex]\frac{x_1}{n_1}[/tex] = 15/55 = 0.27

Guelph = [tex]P_2[/tex] = [tex]\frac{x_2}{n_2}[/tex] = 10/62 = 0.21

P = [tex]\frac{x_1+x_2}{n_1+n_2}[/tex] = 15+10/55+62 = 0.21

b) The null hypothesis

H₀ = P₁ - P₂ = 0

H₁ = P₁-P₂ > 0

Test statistics (Z) = [tex]\frac{(P_1-P_2)-0}{\sqrt{P(1-P)(\frac{1}{n_1}+\frac{1}{n_2}) } }[/tex]

= 0.11/0.075

Z= 1.47.

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The probability that at least one random number is greater than 4.55 is 0.718 (rounded to three decimal places).

The probability of at least one number exceeding 4.55 can be calculated as the complement of the probability that all ten numbers are less than or equal to 4.55.

The probability density function of a uniform distribution on the interval [0, 5] is:

f(x) = 1/5, 0 <= x <= 5

The probability that one number is less than or equal to 4.55 is given by:

P(X <= 4.55) = ∫₀⁴.₅₅ f(x) dx = ∫₀⁴.₅₅ (1/5) dx = (1/5) * (4.55 - 0) = 0.91

So, the probability that all ten numbers are less than or equal to 4.55 is:

P(X₁ <= 4.55, X₂ <= 4.55, ..., X₁₀ <= 4.55) = (0.91)^10 = 0.2824

Therefore, the probability that at least one number exceeds 4.55 is:

P(at least one number > 4.55) = 1 - P(all numbers <= 4.55) = 1 - 0.2824 = 0.7176

So the probability that at least one random number is greater than 4.55 is 0.718 (rounded to three decimal places).

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The equation x³ + y³ + z³ = k Is not possible to solve because it is an equation of  degree 3.

We have,

The equation x³ + y³ + z³ = k represents a surface of constant values in a 3D coordinate system.

If we want to solve for one of the variables in terms of the others, it is not possible because it is an equation of degree 3.

However, you can analyze the equation by graphing it and observing the shape of the surface.

It is a special case of an algebraic surface known as an elliptic cone.

If you have a specific value for k, you can plot the surface and observe its shape.

For example, if k = 1, the surface is a twisted cubic curve that intersects the coordinate axes at (1,0,0), (0,1,0), and (0,0,1).

Thus,

The equation is not possible to solve because it is an equation of

degree 3.

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The algebraic expression for Mr. Robinson's budget constraint if running shoes and basketball shorts cost $20 each is:

200 = 20S + 20B, where S is the number of running shoes and B is the number of basketball shorts

The algebraic expression for Mr. Robinson's budget constraint if the cost of the basketball shorts rises to $30 each is:

200 = 20S + 30B

a) If Mr. Robinson spends his entire income on running shoes and basketball shorts, which cost $20 each, we can write the budget constraint as:
200 = 20S + 20B, where S is the number of running shoes and B is the number of basketball shorts.

b) To determine the number of goods he will buy, we need more information about his preferences. Without any further information, we cannot determine the exact quantities of running shoes (S) and basketball shorts (B) he will buy.

c) If the price of basketball shorts rises to $30 each, the budget constraint becomes:
200 = 20S + 30B

d) Again, to determine the number of goods he will buy with the new prices, we need more information about his preferences.

e) To illustrate the results in parts (a) and (c), you would create a graph with running shoes on the x-axis and basketball shorts on the y-axis. The budget constraint in part (a) would be a straight line with a slope of -1 and an intercept of 10 on both axes. For part (c), the budget constraint would be a straight line with a slope of -2/3 and an intercept of 10 on the x-axis and 6.67 on the y-axis.

As for the decomposition of the income and substitution effect, this cannot be determined without more information about Robinson's preferences or the shape of his indifference curves.

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Answer:

1)1) 90

1)2)30

1)3)60

2)1)90

2)2)15

2)3)20

2)4)70

The study could also be used to compare the hospital's performance with national benchmarks and other hospitals to identify areas for improvement.

Suppose a hospital is interested in studying the average length of stay (in days) for patients admitted with a specific diagnosis, such as pneumonia. The hospital can collect data on the length of stay for all patients with this diagnosis over a certain period of time and calculate the sample mean. The population parameter of interest is the true mean length of stay for all patients with this diagnosis.

To create a 95% confidence interval for the population mean, the hospital can use the formula:

Confidence interval = sample mean ± (t-value) x (standard error)

The t-value is based on the sample size and desired confidence level, while the standard error is calculated using the sample standard deviation and sample size. A 95% confidence level is commonly used in medical studies as it provides a good balance between precision and reliability.

Changing the confidence interval to 90% or 99% would affect the width of the interval. A 90% confidence interval would be narrower than a 95% confidence interval, meaning it would provide less precision but more reliability. A 99% confidence interval would be wider than a 95% confidence interval, providing more precision but less reliability.

The findings of the study could be presented to hospital administrators and staff as evidence of the average length of stay for patients with pneumonia. This information can be used to identify areas for improvement, such as reducing the length of stay through better management and care coordination. The study could also be used to compare the hospital's performance with national benchmarks and other hospitals to identify areas for improvement.

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The true mean ages for cars owned by students and faculty is (−0.25, 1.27).

Rounding to two decimal places, the 98% confidence interval is (-0.25, 1.27).

Step 1:

The point estimate for the true difference between the population means is:

x1 - x2 = 7.41 - 6.9 = 0.51

Step 2:

The margin of error can be calculated as:

ME = z*(σ1²/n1 + σ2²/n2)^(1/2)

where z is the critical value for a 98% confidence level, n1 and n2 are the sample sizes, and σ1 and σ2 are the population standard deviations for the two groups.

For a 98% confidence level, the critical value is 2.33 (from a standard normal distribution table).

Substituting the given values, we get:

ME = 2.33*(3.72²/215 + 2.26²/252)^(1/2) = 0.758282

Rounding to six decimal places, the margin of error is 0.758282.

Step 3:

The 98% confidence interval can be calculated as:

(x1 - x2) ± ME

Substituting the values, we get:

0.51 ± 0.76

Therefore, the 98% confidence interval for the difference between the true mean ages for cars owned by students and faculty is (−0.25, 1.27).

Rounding to two decimal places, the 98% confidence interval is (-0.25, 1.27).

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Answer: No

Step-by-step explanation:

If you substitute the x and y values from the coordinates into eh equations, they will not add up.

Answer:

(-8,-30) is a solution

Step-by-step explanation:

The answer is: A) Yes, because the test value 1.15 is in the noncritical region.

To determine if the scientist's belief is warranted, we need to conduct a hypothesis test using the given information. Here are the steps:

1. State the null hypothesis (H0) and alternative hypothesis (H1):
H0: p = 0.67 (67% of geese fly south)
H1: p ≠ 0.67 (the percentage is not 67%)

2. Determine the sample proportion (p-hat) and sample size (n):
[tex]p-hat = \frac{(16-17)}{60} = \frac{43}{60} = 0.717[/tex]
n = 60

3. Calculate the test statistic (z):
[tex]z= \frac{(p-hat  -  p )}\sqrt{\frac{p(1-p)}{n} }[/tex]
[tex]z= \frac{0.717-0.67}{\sqrt{\frac{0.67(0.33)}{60} } }[/tex]
z =1.15

4. Determine the critical region using the significance level (a):
a = 0.05
Since this is a two-tailed test, we divide α by 2 and find the critical values of z. In this case, the critical values are approximately -1.96 and 1.96.

5. Compare the test statistic to the critical values:
Our test statistic (z = 1.15) falls in the noncritical region (-1.96 < 1.15 < 1.96).

Based on these results, the answer is:
A) Yes, because the test value 1.15 is in the noncritical region.

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To determine whether the given sequence converges or diverges, we will examine each of the provided sequences and find their respective limits as n approaches infinity.

1. an = (-1)^n

The sequence alternates between -1 and 1 as n increases. Since it does not approach a specific value, the sequence diverges. Your answer for this sequence is NONE.

2. an = n^2 * e^(-n)

To find the limit as n approaches infinity, we can apply L'Hopital's Rule:

lim (n^2) / (e^n) as n approaches infinity.

Applying L'Hopital's Rule twice, we get:

lim (2n) / (e^n) and then lim (2) / (e^n).

As n approaches infinity, the denominator (e^n) increases without bound, so the limit becomes 0. The sequence converges to 0.

3. an = (3n - 1)! / (3n + 1)!

To find the limit as n approaches infinity, let's rewrite the sequence as:

an = 1 / [(3n)(3n + 1)]

As n approaches infinity, the denominator (3n)(3n + 1) increases without bound, and the sequence converges to 0.

In summary:
1. The sequence (-1)^n diverges (NONE).
2. The sequence n^2 * e^(-n) converges to 0.
3. The sequence (3n - 1)! / (3n + 1)! converges to 0.

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The radius of convergence is r = 1 in the given case.

We can start by using the power series expansion of ln(1+x):

[tex]ln(1+x) = x - x^2/2 + x^3/3 - x^4/4 + ...[/tex]

Now we can substitute this into the integral and use the linearity of integration to obtain:

[tex]∫ x^4 ln(1+x) dx = ∫ x^5 - x^6/2 + x^7/3 - x^8/4 + ... dx[/tex]

We can integrate each term separately to get:

∫ [tex]x^5 dx - ∫ x^6/2 dx + ∫ x^7/3 dx - ∫ x^8/4 dx[/tex]+ ...

Using the power rule for integration, we can simplify this to:

[tex]x^6/6 - x^7/14 + x^8/24 - x^9/36 +[/tex]...

We have now expressed the indefinite integral as a power series with coefficients given by the formula:

[tex]a_n = (-1)^(n+1) / n[/tex]

The radius of convergence of this power series can be found using the ratio test:

[tex]lim |a_(n+1)/a_n| = lim (n/(n+1)) = 1[/tex]

Since the limit is equal to 1, the ratio test is inconclusive, and we need to consider the endpoints of the interval of convergence.

The integral is undefined at x=-1, so the interval of convergence must be of the form (-1,r] or [-r,1), where r is the radius of convergence.

To determine the value of r, we can use the fact that the series for ln(1+x) converges uniformly on compact subsets of the interval (-1,1). This implies that the series fo [tex]x^4[/tex] ln(1+x) also converges uniformly on compact subsets of (-1,1), and hence on the interval (-r,r) for any r < 1.

Therefore, the radius of convergence is r = 1.

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The industry's supply function for 3 identical firms with total cost function C=aq+bq^2 and q=-191 is: Qs = -1/6b - 1/3a - 191/6.

What is indirect utility function?

The indirect utility function is a mathematical function that expresses the maximum utility that a consumer can achieve, given a certain level of income and prices of goods and services

a) The ordinary demand function for Q1 is obtained by maximizing U with respect to Q1 subject to the budget constraint. Let p1 be the price of Q1, and let M be the consumer's income. Then the budget constraint is given by:

p1Q1 + M = 0

Solving for Q1, we get:

Q1 = -M/p1

Substituting this into U, we get:

U = 29192 + 92(-M/p1)

To obtain the ordinary demand function for Q1, we differentiate U with respect to p1 and solve for Q1:

dU/dp1 = -92M/p1^2

Setting this equal to the price of Q1, we get:

p1 = 92M/Q1^2

Solving for Q1, we get the ordinary demand function for Q1:

Q1 = sqrt(92M/p1)

The compensated demand function for Q1 is obtained by finding the cost of maintaining the consumer's utility level after a change in the price of Q1. This is given by:

C(Q1',p1,U) = min{p1Q1' + p2Q2 : U(Q1',Q2) = U}

where p2 is the price of some other good, and U(Q1',Q2) is the utility function with Q1' replacing Q1.

The compensated demand function for Q1 is then obtained by differentiating C with respect to p1 and solving for Q1:

dC/dp1 = -Q1'

Setting this equal to the price of Q1, we get:

p1 = -dC/dQ1' = -d/dQ1'(p1Q1' + p2Q2)

Solving for Q1', we get the compensated demand function for Q1:

Q1' = (p1/p2)Q2

b) The indirect utility function is given by:

V(p1,p2,M) = max{U(Q1,Q2) : p1Q1 + p2Q2 = M}

Using the utility function U = 29192 + 92, the budget constraint p1Q1 + p2Q2 = M, and the ordinary demand function for Q1, we can solve for the indirect utility function:

V(p1,p2,M) = U(Q1(p1,p2,M),Q2(p1,p2,M)) = 29192 + 92(Q1(p1,p2,M))

Substituting the ordinary demand function for Q1 into this equation, we get:

V(p1,p2,M) = 29192 + 92(sqrt(92M/p1))

c) Roy's identity states that the derivative of the indirect utility function with respect to the price of a good gives the compensated demand function for that good:

dV/dp1 = Q1'

Using the indirect utility function derived in part b, we can solve for the demand function for Q1:

dV/dp1 = 92M/(p1^2 sqrt(92M/p1)) = Q1'

Simplifying, we get:

Q1' = 92sqrt(92M/p1)

II. The industry's supply function is obtained by adding the output of each firm at a given price level:

Q = Q1 + Q2 + Q3

where Qi is the output of the ith firm. To find the output of each firm, we need to solve for the profit-maximizing level of output:

πi = piqi - Ci(qi)

where πi is the profit of the ith firm, pi is the price of the good, qi is the output of the ith firm, and Ci

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Complete Question:

I. Consider the utility function U(Q1) = 29192 + 92Q1, where Q1 is the quantity consumed of a certain good.

a) Construct the ordinary and compensated demand functions for Q1.

b) Construct the indirect utility function.

c) Apply Roy's identity to derive the demand for Q1.

II. Consider an industry with 3 identical firms in which the ith firm's total cost function is C = aq + bq^2 (i=1,...,3), where q is the quantity produced by the firm and a, b are positive constants. The market demand curve is given by Qd = 200 - 2P, where Qd is the total quantity demanded in the market and P is the market price. Each firm takes the market price as given.

Derive the industry's supply function.

Please note that the point values given in the original prompt are also included for reference.

The linear equation that models the cab fare is: f(5) = 1.5(5) + 4 = 11.5 dollars

An equation is said to be linear if the maximum power of the variable is consistently 1. Another name for it is a one-degree equation. A linear equation with one variable has the conventional form Ax + B = 0. In this case, the variables x and A are variables, whereas B is a constant.

The equation for a linear equation in one variable is written as ax+b = 0, where a and b are two integers, and x is a variable. This equation has just one solution. For instance, the linear equation 2x+3=8 only has one variable. As a result, this equation has a single solution, x = 5/2.

Here f(x) = 1.5x + 4

where x is the number of miles.

To find the total fare for a 2-mile trip:

f(2) = 1.5(2) + 4 = 7 dollars

To find the total fare for a 3-mile trip:

f(3) = 1.5(3) + 4 = 7.5 dollars

To find the total fare for a 5-mile trip:

f(5) = 1.5(5) + 4 = 11.5 dollars

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Answer:

Volume is very easy juts use this formula to help you.

Formual= L × W × H

Formula = 7 × 8 × 4

Answer 7 × 8 × 4 = 224

( BTW when solving for volume ur always gonna use multiplication and this formula)

a) No, f is not injective.

b) Yes, g is injective.

c) No, f is not surjective.

d) Yes, g is surjective.

(a) Is f injective?
No, f is not injective. A counterexample is f(1,2) = 2 * (1 - 1) = 0 and f(2,2) = 2 * (2 - 1) = 0. Since f(1,2) = f(2,2), the function is not injective.

(b) Is g injective?
Yes, g is injective. To prove this, let's assume g(a1, b1) = g(a2, b2). This means (a1, b1) = (a2, b2), which implies a1 = a2 and b1 = b2. Therefore, g is injective.

(c) Is f surjective?
No, f is not surjective. For example, consider the number 1 in the codomain R. There is no pair (a, b) in the domain such that f(a, b) = 1 because 2 * (a - b) must be an even number.

(d) Is g surjective?
Yes, g is surjective. To prove this, let (c, d) be any element in the codomain. Then g(c, d) = (c, d), so there exists an element in the domain for every element in the codomain. Thus, g is surjective.

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The probability that a point selected will fall on the circle is 0.79

A probability is a number that reflects the chance or likelihood that a particular event will occur. The certainty of an event is is 1 and it is equivalent to 100%

Probability = sample space / total outcome

sample = the area of the circle

total outcome = area of square

area of square = l²

= 22²

= 22 × 22

= 484 units

area of circle = πr²

= 3.14 × 11²

= 3.14 × 121

= 379.94

Therefore ,the probability of a point falling on the circle is

= 379.94/484

= 0.79 ( nearest hundredth)

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A X-squared goodness-of-fit test is performed on a random sample of 360 individuals to see if the number of birthdays each month is proportional to the number of days in the month. X-squared is determined to be 23.5. The P -value for this test is between d) 0.010 < P < 0.025

In this scenario, a X-squared goodness-of-fit test is performed to determine if the number of birthdays each month is proportional to the number of days in the month. With a random sample of 360 individuals and a χ-squared value of 23.5, you need to find the corresponding P-value range.

To find the P-value range, you can use a χ-squared distribution table or calculator. Since there are 12 months in a year, the degrees of freedom for this test will be 12 - 1 = 11.

Upon checking the table or using a calculator, you will find that the P-value for this test is between:

Your answer: d) 0.010 < P < 0.025

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The length of diagonal of square is 6√2 inch.

We have,

side length  = 6 inches

Now, the formula for diagonal length of square as

d = √2a

where a is the side of square.

So, the length of diagonal of square is

= 6√2 inch.

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Here's an example set of numbers:

{5, 10, 12, 15, 18, 20, 22, 22, 25, 30, 30}

Mean = sum of all numbers / total number of numbers

Mean = (5 + 10 + 12 + 15 + 18 + 20 + 22 + 22 + 25 + 30 + 30) / 11

Mean = 20

Median = the middle number when the numbers are arranged in order from smallest to largest

Median = 20 (since there are 11 numbers, the median is the 6th number, which is 20)

Mode = the most frequently occurring number in the set

Mode = 22 (since 22 appears twice in the set, which is more than any other number)

In this example, the mean and median are close together, which indicates that the data is fairly evenly distributed. However, the mode is different from the mean and median, which indicates that there is a skew in the data towards the higher end, since 22 and 30 occur twice each.

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For the quadrilateral ABCD the statement which proves that this quadrilateral is not a rectangle is (a) The slope of CD is "(-5-1)/(-5-5) = 3/5", and the "slope of DA is [3-(-5)]/[-3-(-5)] = 8/2", these "two-segments" are not perpendicular , so the shape is not a rectangle;

The coordinates of the "four-vertices" of the quadrilateral ABCD are :

A(-3,3), B(2,6), C(5, 1), D(-5,-5);

To prove whether the quadrilateral is a rectangle or not, we need to show that its adjacent sides are perpendicular and its diagonals are congruent.

In this question, we are given the coordinates of the four vertices of the quadrilateral.

To determine if it's a rectangle, we use the slope formula to find the slopes of the sides of the quadrilateral. If slopes of adjacent sides are "negative-reciprocals" of each other, then they are perpendicular. If the slopes of the diagonals are equal, then they are congruent.

Using the given coordinates, we find that the slope of CD is = (-5-1)/(-5-5) = 3/5, and

The slope of DA is = [3-(-5)]/[-3-(-5)] = 8/2. These two slopes are not negative reciprocals of each other, so CD and DA are not perpendicular.

So, the quadrilateral is not a rectangle.

Therefore, the correct option is (a).

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The given question is incomplete, the complete question is

The coordinates of the "four-vertices" of the quadrilateral ABCD are :

A(-3,3), B(2,6), C(5, 1), D(-5,-5);

Which statement proves whether or not this quadrilateral is a rectangle?

(a) The slope of CD is (-5-1)/(-5-5) = 3/5, and the slope of DA is 3-(-5)/-3-(-5)=8/2, these two segments are not perpendicular , so the shape is not a rectangle;

(b) The slope of AB is (6-3)/(2-(-3) = 3/5, and slope of BC is (6-1)/(2-5) = -5/3, these two segments are perpendicular , so the shape is a rectangle;

(c) The slope of BC is (6-1)/(2-5) = -5/3, and slope of CD is (-5-1)/(-5-5) = 3/5, these two segments are not perpendicular, so the shape is not a rectangle;

(d) The slope of AB is (6-3)/(2-(-3) = 3/5, and slope of CD is (-5-1)/(-5-5) = 3/5, these two segments are perpendicular , so the shape is a rectangle;

We cannot conclude that the new beta-blocker medicine is effective at treating high blood pressure at a significance level of αα = 0.01.  

We can perform a chi-squared test to determine if there is a significant difference between the number of subjects in the treatment group who had their high blood pressure successfully treated and the number of subjects in the control group who had their high blood pressure successfully treated.

First, we need to calculate the expected counts for each group. Since we know that the treatment group had 114 successful outcomes, and the control group had 100 successful outcomes, we can calculate the expected counts as follows:

Expected counts for treatment group: (114 * 180) / 210 = 146.7

Expected counts for control group: (100 * 180) / 210 = 187.3

Next, we can calculate the chi-squared value using the formula:

chi-squared = sum(([tex]observed - expected)^2[/tex]/ expected)

where observed and expected are the actual counts and expected counts, respectively.

For the treatment group, the observed count is 114, and the expected count is 146.7. Therefore, we calculate the chi-squared value as:

chi-squared = [tex](114 - 146.7)^2[/tex] / 146.7 = 12.2

For the control group, the observed count is 187.3, and the expected count is 187.3. Therefore, we calculate the chi-squared value as:

chi-squared = (187.3 - [tex]187.3)^2[/tex] / 187.3 = 0

We can then calculate the p-value using the formula:

p-value = 2 * (chi-squared / degrees of freedom)

where degrees of freedom is the number of categories minus 1 for each cell. In this case, we have two cells, one for the treatment group and one for the control group, so the degrees of freedom is 2 - 1 = 1.

Substituting the values into the formula, we get:

p-value = 2 * (12.2 / 1) = 2.44

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Hi! To answer your question, let's denote the total number of processors as n and the total number of jobs as n as well. Since there are n possible assignments for each job, the total number of assignment vectors is n^n.

To find the probability that exactly one processor will be idle, we can use the following steps:

1. Select the idle processor: There are n ways to choose the idle processor.
2. Assign jobs to the remaining (n-1) processors: Each of the n jobs can be assigned to any of the remaining (n-1) processors, which gives us (n-1)^n possible assignment vectors.

Now, to calculate the probability, we can divide the number of assignment vectors with exactly one idle processor by the total number of assignment vectors:

Probability = (n * (n-1)^n) / n^n

This expression gives the probability that exactly one processor will be idle when there are n jobs and n processors.

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We would choose "smaller" for the necessary sample size and "smaller" for the confidence level.

(a) We know that the margin of error E is 4.7 and the population standard deviation is o = 17.5.

The formula for the margin of error is:

E = z* (o/ sqrt(n))

where z is the critical value for the desired level of confidence, o is the population standard deviation, and n is the sample size.

We want to find n, so we can rearrange the formula to solve for n:

n = (z*o/E)^2

For a 99.8% confidence level, the critical value is z = 2.967.

Substituting the values into the formula, we get:

n = (2.967*17.5/4.7)^2

n = 157.82

Rounding up to the nearest integer, we get a sample size of 158.

Therefore, a sample size of 158 must be drawn in order to obtain a 99.8% confidence interval with a margin of error equal to 4.7.

(b) If the required confidence level were 99.5%, the necessary sample size would be smaller.

This is because the critical value for a 99.5% confidence level is smaller than the critical value for a 99.8% confidence level. As the critical value gets smaller, the margin of error also gets smaller, which means we need a smaller sample size to achieve the same margin of error.

So, we would choose "smaller" for the necessary sample size and "smaller" for the confidence level.

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1) Interest amount = $16.5

2) Interest amount = $4.125

3) Interest amount = $8.36

And, After 5 1/2 years;

Interest amount = $22.99

4) Interest amount = $33.02

5) Interest amount = $45.6

Now, We can simplify as;

1) Principal amount = $550

Rate = 3%

Time = 1 year

Hence, We get;

Interest amount = 550 x 3 x 1 / 100

                         = $16.5

2)  Principal amount = $1500

Rate = 3%

Time = 1/4 year

Hence, We get;

Interest amount = 1500 x 3 x 1 / 100 x 4

                         = $4.125

3) Principal amount = $418

Rate = 2%

Time = 1 year

Hence, We get;

Interest amount = 418 x 2 x 1 / 100

                         = $8.36

And, After 5 1/2 years;

Interest amount = 418 x 11 x 1 / 100 x 2

                         = $22.99

4)  Principal amount = $825.5

Rate = 4%

Time = 1 year

Hence, We get;

Interest amount = 825.5 x 4 x 1 / 100

                         = $33.02

5) Principal amount = $1140

Rate = 6%

Time = 1 year

Hence, We get;

Interest amount = 1140 x 6 x 1 / 100

                         = $68.4

And, After 5 4 years;

Interest amount = 1140 x 4 x 1 / 100

                         = $45.6

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The mean number of workers hired in 2018 is 5, the median is 5.5, and the range is 9.

To determine the mean, median, and range for the number of workers hired by the sixteen hoteliers in 2018, follow these steps:

1. Mean: Add all the numbers together and divide by the total count (16 hoteliers).
(4+5+6+5+3+2+8+0+4+6+7+8+4+5+7+9) / 16 = 83 / 16 = 5.1875

The mean number of workers hired is 5.

2. Median: Arrange the numbers in ascending order and find the middle value(s).
0, 2, 3, 4, 4, 5, 5, 5, 6, 6, 7, 7, 8, 8, 9
Since there are 16 numbers, the median will be the average of the 8th and 9th values.
(5 + 6) / 2 = 5.5

The median number of workers hired is 5.5.

3. Range: Subtract the smallest value from the largest value.
9 - 0 = 9

The range for the number of workers hired is 9.

In conclusion, the mean number of workers hired in 2018 is 5, the median is 5.5, and the range is 9.

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The area of the garden is equal to 12.5 m².

In Mathematics and Geometry, the area of a triangle can be calculated by using this formula:

Area = 1/2 × b × h

Where:

Next, we would determine the side lengths of this right triangle by using the distance between coordinates formula;

Distance AB = √[(x₂ - x₁)² + (y₂ - y₁)²]

Distance AB = √[(0 - 4)² + (-2 - 1)²]

Distance AB = √[(-4)² + (-3)²]

Distance AB = √[16 + 9]

Distance AB = 5 meters.

Distance BC = √[(3 - 0)² + (2 + 2)²]

Distance BC = √[(3)² + (4)²]

Distance BC = √[9 + 16]

Distance BC = 5 meters.

Area of garden = 1/2 × AB × BC

Area of garden = 1/2 × 5 × 5

Area of garden = 25/2

Area of garden = 12.5 m².

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For a simple sample from a normally distributed population, the degree of freedom and critical value are 24 and X²(L) = 15.6587, X²(R) = 33.1962 respectively. The confidence of interval for estimate is equals to ( 55.8633 , 81.338 ).

We have a simple random sample selected from a population with a normal distribution. The confidence interval

= 80% = 0.80

Sample size, n = 25

standard deviations, s = 65.7

We have to determine value of degree of freedom, critical values. The degrees of freedom represents the number of variables that are free to vary in a calculation, df = n - 1 where n--> numbers of variable. So, in this case degree of freedom = 25 - 1 = 24

Level of significance, α = 1 - 0.80 = 0.20 [tex]\frac{\alpha}{2} = \frac{0.20}{2}[/tex].

= 0.10

Now, critical values are defined as

[tex]{χ^{2} _R} = {χ^{2_{\frac{\alpha}{2}}}}[/tex]

= [tex] { χ²_{\frac{0.20}{2}}}[/tex]

[tex]= { χ^{2} _{0.10}}[/tex] with 24 degree of freedom is equal to 33.1962. Also, left hand critical value, [tex]{χ^{2}_L = { χ^{2} _{(1 - \frac{\alpha}{2})}}}[/tex]

[tex]= { χ²_{0.90}}[/tex] with 24 degree of freedom is 15.6587. The confidence interval estimate formula is [tex]CI = ( \frac{ (n- 1)s²}{χ²_{0.10, n-1}}, \frac{ (n- 1)s²}{χ²_{0.90, n-1}})[/tex]. Plugging alm known values, CI = [tex](\frac{(25 - 1)s²}{χ²_{0.10, 25-1}},\frac{(25 - 1)s²}{χ²_{0.90, 25 -1}})[/tex].

= ( 55.8633 , 81.338 ).

Hence, required value is (55.8633 , 81.338 ).

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Complete question:

Question content area top Part 1 Use the given information to find the number of degrees of freedom, the critical values

and the confidence interval estimate of. It is reasonable to assume that a simple random sample has been selected from a population with a normal distribution. White Blood Counts of Women 80% confidence; n = 25, s = 65.7.