Given that:
[tex]\cos A=\frac{5}{13}[/tex]Where:
[tex]0And:[tex]\cos B=\frac{3}{5}[/tex]Where:
[tex]0You need to remember that, by definition:[tex]\theta=\cos ^{-1}(\frac{adjacent}{hypotenuse})[/tex]Therefore, applying this formula, you can find the measure of angles A and B:
[tex]A=\cos ^{-1}(\frac{5}{13})\approx67.38\text{\degree}[/tex][tex]B=\cos ^{-1}(\frac{3}{5})\approx53.13\text{\degree}[/tex](a) By definition:
[tex]\sin \mleft(A+B\mright)=sinAcosB+cosAsinB[/tex]Knowing that:
[tex]\sin \theta=\frac{opposite}{hypotenuse}[/tex]You can substitute the known values into the equation in order to find the opposite side for angle A:
[tex]\begin{gathered} \sin (67.38\text{\degree)}=\frac{opposite}{13} \\ \\ 13\cdot\sin (67.38\text{\degree)}=opposite \\ \\ opposite\approx12 \end{gathered}[/tex]Now you know that:
[tex]\sin A=\frac{12}{13}[/tex]Using the same reasoning for angle B, you get:
[tex]\begin{gathered} \sin (53.13\text{\degree)}=\frac{opposite}{5} \\ \\ 5\cdot\sin (53.13\text{\degree)}=opposite \\ \\ opposite\approx4 \end{gathered}[/tex]Now you know that:
[tex]\sin B=\frac{4}{5}[/tex]Substitute values into the Trigonometric Identity:
[tex]\begin{gathered} \sin (A+B)=sinAcosB+cosAsinB \\ \\ \sin (A+B)=(\frac{12}{13})(\frac{3}{5})+(\frac{5}{13})(\frac{4}{5}) \end{gathered}[/tex]Simplifying, you get:
[tex]\begin{gathered} \sin (A+B)=\frac{36}{65}+\frac{20}{65} \\ \\ \sin (A+B)=\frac{36+20}{65} \end{gathered}[/tex][tex]\sin (A+B)=\frac{56}{65}[/tex](b) By definition:
[tex]\sin \mleft(A-B\mright)=sinAcosB-cosAsinB[/tex]Knowing all the values, you get:
[tex]\begin{gathered} \sin (A-B)=(\frac{12}{13})(\frac{3}{5})-(\frac{5}{13})(\frac{4}{5}) \\ \\ \sin (A-B)=\frac{36-20}{65} \\ \\ \sin (A-B)=\frac{16}{65} \end{gathered}[/tex](c) By definition:
[tex]\tan (A+B)=\frac{\tan A+\tan B}{1-\tan A\cdot\tan B}[/tex]By definition:
[tex]\tan \theta=\frac{opposite}{adjacent}[/tex]Therefore, in this case:
- For angle A:
[tex]\tan A=\frac{12}{5}[/tex]- And for angle B:
[tex]\tan B=\frac{4}{3}[/tex]Therefore, you can substitute values into the formula and simplify:
[tex]\tan (A+B)=\frac{\frac{12}{5}+\frac{4}{3}}{1-(\frac{12}{5}\cdot\frac{4}{3})}[/tex][tex]\tan (A+B)=\frac{\frac{56}{15}}{1-\frac{48}{15}}[/tex][tex]\tan (A+B)=\frac{\frac{56}{15}}{-\frac{11}{5}}[/tex][tex]\tan (A+B)=-\frac{56}{33}[/tex](d) By definition:
[tex]\tan (A-B)=\frac{\tan A-\tan B}{1+\tan A\cdot\tan B}[/tex]Knowing all the values, you can substitute and simplify:
[tex]\tan (A-B)=\frac{\frac{12}{5}-\frac{4}{3}}{1+(\frac{12}{5}\cdot\frac{4}{3})}[/tex][tex]\tan (A-B)=\frac{\frac{16}{15}}{\frac{21}{5}}[/tex][tex]\tan (A-B)=\frac{16}{63}[/tex](e) Knowing that:
[tex]\sin (A+B)=\frac{56}{65}[/tex][tex]\tan (A+B)=-\frac{56}{33}[/tex]Remember the Quadrants:
By definition, in Quadrant II the Sine is positive and the Tangent is negative.
Since in this case, you found that the Sine is positive and the Tangent negative, you can determine that this angle is in the Quadrant II:
[tex]A+B[/tex]-ractions:
On a website, there is an ad for jeans every 5 minutes, an ad for sneakers
every 10 minutes, and an ad for scarves every 45 minutes.
If they all appeared together at 9:00 P.M., when is
the next time they will all appear together?
ICM to solve the problem
Answer:
Step-by-step explanation:
I would like to know if I have this question correct thank you
Remember that
For a 95% confidence interval --------> the value of z=1.960
Find out the value of
[tex]Z\frac{s}{\sqrt{n}}=1.960(\frac{12}{\sqrt{36}})=3.92[/tex]therefore
[tex]\begin{gathered} 230\pm3.92 \\ 230+3.92=233.92 \\ 230-3.92=226.08 \\ therefore \\ The\text{ answer is} \\ (226.08,233.92) \end{gathered}[/tex]A soup can has a radius of 4.3 cm and a height of 11.6 cm. What is the volume of the soup can to the nearest tenth of a cubic centimeter?A. 1816.8B. 49.9C. 168.4D. 673.8
hello
to solve this problem, we need to identify the shape of the soup can first since soup is a liquid and carries the shape of whatever container its in.
volume of a cylinder is given as
[tex]\begin{gathered} V=\pi r^2h \\ \pi=3.142 \\ r=\text{radius} \\ h=\text{height} \end{gathered}[/tex][tex]\begin{gathered} v=\text{ ?} \\ r=4.3\operatorname{cm} \\ h=11.6\operatorname{cm} \\ \pi=3.142 \\ v=\pi r^2h \\ v=3.142\times4.3^2\times11.6 \\ v=673.9\operatorname{cm}^3 \end{gathered}[/tex]from the calculations above, the volume of the soup is equal to 673.9cm^3 which corresponds with option D
lineal or no?1) 2x+y=52) y= x + 6 --- 2thanks
1) 2x+y=5 ...... It is a linear equation
2) y= x + 6 ....... It is a linear equation
Because they are of first degree and they contain x and y (equations of a line)
If f(x) = 8x2 - 18x + 5, find when f(x) = -4
Setting the given equation equals -4 we get:
[tex]\begin{gathered} 8x^2-18x+5=-4 \\ 8x^2-18x+5+4=0 \\ 8x^2-18x+9=0 \end{gathered}[/tex]Notice that:
[tex]8x^2-18x+9=8(x^2-\frac{9}{4}x+\frac{9}{8})=8(x-\frac{3}{2})(x-\frac{3}{4})[/tex]Therefore, f(x)=-4 when x=3/2 or x=3/4.
How many solutions does the equation 5(m + 3) = 6-7m have? Explain how you found your answer.
Expand the left hand side using distributive property:
[tex]\begin{gathered} 5\cdot m+5\cdot3=6-7m \\ 5m+15=6-7m \\ \text{Add 7m to both sides:} \\ 5m+15+7m=6-7m+7m \\ 12m+15=6 \\ \text{subtract 15 from both sides:} \\ 12m+15-15=6-15 \\ 12m=-9 \\ \text{divide both sides by 12:} \\ \frac{12}{12}m=-\frac{9}{12} \\ m=-\frac{3}{4} \end{gathered}[/tex]Solve the inequality and graph the solution set.3 ≤ 4x + 1 < 9
Okay, here we have this:
Considering the provided inequality, we are going to solve it and graph the solution set, so we obtain the following:
3 ≤ 4x + 1 < 9
3 -1≤ 4x + 1 -1< 9-1
2 ≤ 4x < 8
2/4 ≤ 4x/4 < 8/4
1/2 ≤ x < 2
In interval notation the solution set will be: [1/2, 2)
And if we plot this solution interval we get:
Where the solution set will be the purple part.
Hi, can you help me answer this question please, thank you!
Consider that you have a population greater than 30, then, you can use the normal distribution to determine the margin of error.
Use the following formula:
[tex]\bar{x}\pm Z_{\frac{\alpha}{2}}\frac{s}{\sqrt[]{n}}[/tex]where:
x: mean = 33
s: standard deviation = 2
n = 31
Z: z-value for 98%
The value of Z can be found on a table for the normal distribution. For a margin of error at 98%, you get for Z:
Z = 2.326
Replace the previous values of the parameters into the formula for the margin of error (confidence interval):
[tex]\begin{gathered} 33\pm(2.326)\frac{2}{\sqrt[]{31}}= \\ 33\pm0.83 \end{gathered}[/tex]Then, the margin of error is:
(33.00 - 0.83 , 33.00 + 0.83) = (32.17 , 33.83)
hii so i got this question wrong a while ago and im reviewing it id like some help finding out how to solve it
Answer:
Options 1, 3, and 4.
Explanation:
Given the expression:
[tex]3x\mleft(x-12x\mright)+3x^2-2\mleft(x-2\mright)^2[/tex]Step 1: The term -2(x-2)² is simplified by first squaring the expression x-2.
[tex]\begin{gathered} 3x(x-12x)+3x^2-2(x-2)^2 \\ =3x(x-12x)+3x^2-2(x-2)(x-2) \\ =3x(x-12x)+3x^2-2(x^2-2x-2x+4) \\ =3x(x-12x)+3x^2-2(x^2-4x+4) \end{gathered}[/tex]Step 2: The parentheses are eliminated through multiplication.
[tex]=3x^2-36x^2+3x^2-2x^2+8x-8[/tex]Step 3: After multiplying, the like terms are combined by adding and subtracting.
[tex]\begin{gathered} =3x^2-36x^2+3x^2-2x^2+8x-8 \\ =-32x^2+8x-8 \end{gathered}[/tex]The three options that are correct are Options 1, 3, and 4.
In 2009, there were 6.1 million females enrolled in degree granting institutions of higher education. over the next several years this number increased at a rate of 400,000 per year. estimate the number of females enrolled in 2024. y = ______ millionthe equation of the line that models this information is;y = 0.4t + 6.1Determine what year 12.9 million females will be enrolled.
Notice that
400,000 = 0.4 million
That's why the equation that models that information has the factor 0.4, since it expresses the result in millions of females.
Now, we need to notice that t, in the expression 0.4t + 6.1, is the number of years passed since 2009. So, in the year 2024, we have:
t = 2024 - 2009 = 15
Therefore, the number of females enrolled in 2024 can be estimated to be:
y = (0.4 * 15 + 6.1) million
y = (6 + 6.1) million
y = 12.1 million
Now, to determine the year when 12.9 million females will be enrolled, we first need to find t corresponding to y = 12.9, and then add it to the year 2009.
y = 0.4t + 6.1
12.9 = 0.4t + 6.1
12.9 - 6.1 = 0.4t
6.8 = 0.4t
t = 6.8/0.4
t = 68/4
t = 17
Therefore, the year when it happens will be:
2009 + 17 = 2026
6. A profit function for a new business follows the functionP(x) = 1/3x^2 - 6x, where x represents the number of months.After how many months will the company begin to make aprofit?A. 2B. 9C. 12D. 18
ANSWER
It will take 18 months before the company starts making a profit.
STEP-BY-STEP EXPLANATION
Given information
[tex]P(x)\text{ = }\frac{1}{3}x^2\text{ - 6x}[/tex]Where x is the number of months.
Step 1: Make P(x) = 0
[tex]\begin{gathered} \text{ p(x) = }\frac{1}{3}x^2\text{ - 6}x \\ 0\text{ = }\frac{1}{3}x^2\text{ - 6}x \end{gathered}[/tex]Step 2: Find x from the above equation
[tex]\begin{gathered} 0\text{ = }\frac{1}{3}x^2\text{ - 6x} \\ \text{Add 6x to the both sides} \\ 0\text{ + 6x = }\frac{1}{3}x^2\text{ - 6x + 6x} \\ 6x\text{ = }\frac{1}{3}x^2 \\ \text{cross multiply} \\ 6x\text{ }\times3=x^2 \\ 18x=x^2 \\ \text{Divide both sides by x} \\ \frac{18\cancel{x}}{\cancel{x}}\text{ = }\frac{\cancel{x^2}}{\cancel{x}} \\ x\text{ = 18 months} \end{gathered}[/tex]Therefore, it will take 18 months before the company starts making a profit.
Determine the value of b for which x = 1 is a solution of the equation shown.
2x + 14 = 10x + b
B=
The linear equation has the solution x = 1 only if the value of b is 6
For which value of b is x = 1 a solution?
Here we have the linear equation:
2x + 14 = 10x + b
If we replace x by 1 in that equation, we will get:
2*1 + 14 = 10*1 + b
2 + 14 = 10 + b
16 = 10 + b
To find the value of b such that x = 1 is a solution, we need to isolate b, to do so we need to subtract 10 in both sides.
16 - 10 = 10 + b - 10
6 = b
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Two Way Tables, URGENT
Step-by-step explanation:
a) modal number is 3
b) mean is x = ∑fx/n
= ((5•1)+ (2•10)+(3•15)+(7•4)+(3•5))/(5+10+15+7+3)
= 113/40
= (Decimal: 2.825)
The vertex of a quadratic function is (2, -1) and its y-intercept is 7. Find the function,
Given:-
[tex]\text{vertex}=(2,-1),y-intercept=7[/tex]To find:-
The function.
So the formula is,
[tex]y=a\mleft(x-h\mright)^{2}+k[/tex]So substituting we get,
[tex]y=7(x-2)^2-1[/tex]So the value. we get,
[tex]\begin{gathered} y=7(x-2)^2-1 \\ y=7(x^2-4x+4)-1 \end{gathered}[/tex]Since the value of x is,
[tex]\begin{gathered} y=7x^2-28x+28-1 \\ y=7x^2-28x+27 \end{gathered}[/tex]So the value,
[tex]y=7x^2-28x+27[/tex]Which of the following is equal to the rational expression below when x+112x² – 121x +11A. +11B.X+ 11c. -11XD. X-11
SOLUTION
From the question we have
[tex]\frac{x^2-121}{x+11}[/tex]from difference of two squares, we have
[tex]\begin{gathered} \frac{(x-11)(x+11)}{x+11} \\ x+11\text{ above cancels the one below, we have } \\ x-11 \end{gathered}[/tex]Hence the answer is option D
Please helpwhat does A∩B=∅ mean. Thus, please help with:Suppose Pr(A)=0.3, Pr(B)=0.4 and A∩B=∅. Find:a- Pr(A∩B)b- Pr(A∪B)
Given: A and B are two sets such that-
[tex]\begin{gathered} A\cap B=\phi \\ Pr(A)=0.3 \\ Pr(B)=0.4 \end{gathered}[/tex]Required: To determine-
[tex]\begin{gathered} Pr(A\cap B) \\ Pr(A\cup B) \end{gathered}[/tex]Explanation: Since A and B have no common elements, the events are independent events or disjoints or mutually exclusive.
For independent events, we have-
[tex]Pr(A\cap B)=Pr(A).Pr(B)[/tex]Substituting the values into the formula-
[tex]\begin{gathered} Pr(A\cap B)=0.3\times0.4 \\ =0.12 \end{gathered}[/tex]Recall that-
[tex]Pr(A\cup B)=Pr(A)+Pr(B)-Pr(A\cap B)[/tex]Substituting the values into the formula and further solving as-
[tex]\begin{gathered} Pr(A\cup B)=0.3+0.4-0.12 \\ =0.7-0.12 \\ =0.58 \end{gathered}[/tex]Final Answer: a)
[tex]Pr(A\cap B)=0.12[/tex]b)
[tex]Pr(A\cup B)=0.58[/tex]I need help with this question Write and expression that models the situation:Sarah has spent x dollars out of the 30 dollars she started with.
Okay, here we have this:
Considering that it says "spent", it represents an outflow of money, therefore we take it as negative, so we obtain:
Actual Situation: Initial money - money spent
Actual Situation: 30 - x
What are the explicit and recursive formulas for the sequence 540, 180, 60, 20, ...?
Here we have a geometric sequence, the recursive formula is:
Aₙ = (1/3)*Aₙ₋₁
And the explicit formula is:
Aₙ = (1/3)*ⁿ⁻¹*540
How to get the recursive formula?
Here we have the following sequence:
540, 180, 60, 20, ...
This seems to be a geometric sequence, to check this, we need to take the quotients between consecutive terms and see if we get the same thing.
180/540 = 1/3
60/180 = 1/3
20/60 = 1/3
So yes, this is a geometric sequence where the common ratio is 1/3, so each term is (1/3) times the previous one, so the recursive formula is:
Aₙ = (1/3)*Aₙ₋₁
And the explicit formula is:
Aₙ = (1/3)*ⁿ⁻¹*A₁
Where A₁ is the first term, in this case 540, so the formula becomes:
Aₙ = (1/3)*ⁿ⁻¹*540
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find the value of x so that AB and DC are parallel
According to the properties of a parallelogram, the consecutive interior angles are supplementary, this is that the sum of its measures is 180.
Use the expressions given for 2 of the consecutive angles to find the value of x. Remember, the sum of these expressions must be 180.
[tex]\begin{gathered} (3x+15)+(7x+25)=180 \\ 10x+40=180 \\ 10x=140 \\ x=\frac{140}{10} \\ x=14 \end{gathered}[/tex]x has a value of 14.
Find the area of the triangle.
The area of the triangle given as in the attached image to the task content is; 1 ft².
What is the area of the triangle as indicated in the attached image?It follows from the task comtent that the area of the triangle given be determined.
Since the area of a triangle is given by the formula; Area = (1/2) × base × height.
Since the base of the triangle in discuss is 3 ft and it's height (altitude) as given in the task content is; (2/3) feet.
It follows that the area is;
Area = (1/2) × 3 × (2/3).
Area = 1 ft².
Ultimately, the area of the triangle is; 1 ft².
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determine whether AB and AC are parallel,perpendicular,or neither.A(9,-3) , B(9,4), C(-2,10), D(-2,6)
We first determine the value of AB & CD:
AB (0, 7)
CD (0, -4)
We will calculate first if they are perpendicular:
[tex](0,7)\cdot(0,-4)=0\cdot0+(7)(-4)=-28\ne0[/tex]From this, we know AB and CD are not perpendicular.
Now, in order to know if they are parallel, we will do as follows:
[tex](0,7)x=(0,-4)[/tex]From this, we will have:
[tex](0,7x)=(0,-4)\Rightarrow7x=-4\Rightarrow x=-\frac{4}{7}[/tex]From this we have that they are multiple of each other, therefore they are parallel.
7. You are single and claim 1 allowance. You presently earn $319 per week.
Starting next week you will receive a 5 percent increase in pay and will earn
$335.00. How much more will you have withheld from your weekly pay for federal income tax?
I will withdraw 3 % of the of my weekly pay for federal income tax.
How do you calculate weekly pay for federal income tax?An income tax is a charge levied against people or organizations in relation to the income or profits they make. In most cases, income tax is calculated as the sum of the tax rate and the amount of taxable income. The type of taxpayer and the type of income are two factors that can affect the tax rate. Individuals (or family units) and corporations are subject to income taxes. The basis for calculating individual income tax is the income received. Since the burden is presumably on the individuals who pay it, it is typically categorized as a direct tax. Income taxes are assessed against both businesses and people based on their profits. Taxable income can be earned from a variety of sources, including earnings, salaries, dividends, interest, royalties, and rent.
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In a factory, the profit, P, varies directly with the inventory, I. If the factory has a profit of $60,000 when their inventory is 1,500 units, find the profit for an inventory of 50 units.
The factory has a profit of $60 000when their inventory is 1, 500 units
Let x be the profit for an inventory of 50 units
$60 000 = 1,500 units
X = 50 units
cross-multiply
1500X = $60 000 x 50
1500X =3,000,000
Divide both-side of the equation by 1500
1500X/1500 = 3,000,000/1500
x= $2000
The factory has a profit of $2000 for an inventory of 50 units
Use the strategy to simplify 4/576Write the prime factorization of the radicand.442834O42/2832O 4./283²O4. 2882
To simplify the fraction we will need to facto
I need help I need help I need help I need help I need help i need help I need help
Answer:
5) The midrange is 19.5ºF
6) The midrange is 67.5º
Explanation:
The problem tell us how to calculate the midrange.
In (5) the minimum and maximum values are given (-6ºF and 45ºF, respectively). Using the formula:
[tex]Midrange=\frac{-6+45}{2}=\frac{39}{2}=19.5ºF[/tex]In (6), we need to find the minimum and maximum values from a list of them. We can see that the minimum is 58º and the maximum 77º
Then:
[tex]Midrange=\frac{58+77}{2}=\frac{135}{2}=67.5º[/tex]What is the position of see on the number line belowWrite your answer as a fraction or mixed number
Answer:
1/3
Explanation:
We can see that from 0 to 1 the number line is divided into 6 parts and the point is right after the second part. Therefore, the fraction that represents point C is 2/6
This fraction is also equal to 1/3 because we can divide the line from 0 to 1 into 3 parts and take the first. The point will be at the exact same position of C.
Therefore, the answer is:
1/3
Consider the line y=7x-1Find the equation of the line that is perpendicular to this line and passes through the point −2, 3.Find the equation of the line that is parallel to this line and passes through the point −2, 3.Note that the ALEKS graphing calculator may be helpful in checking your answer.Equation of per pendicular line:Equation of parallel line:
Algebra / Graphs and Functions / Equations of Parallel and Perpendicular Lines
We have the line:
[tex]y=7x-1.[/tex]We must find the equation:
0. of the perpendicular line,
,1. and the parallel line,
to the given line that passes through the point (-2, 3).
1) Perpendicular line
The equation of the perpendicular line has the form:
[tex]y=m_p\cdot(x-x_0)+y_0.[/tex]Where mₚ is the slope, and (x₀, y₀) = (-2, 3).
From the equation of the given line, we see that its slope is m = 7. The slope of the perpendicular line mₚ is given by the equation:
[tex]\begin{gathered} m\cdot m_p=-1, \\ 7\cdot m_p=-1, \\ m_p=-\frac{1}{7}. \end{gathered}[/tex]Replacing mₚ = -1/7 and (x₀, y₀) = (-2, 3) in the equation of the perpendicular line, we get:
[tex]y=-\frac{1}{7}\cdot(x-(-2))+3=-\frac{1}{7}\cdot(x+2)+3=-\frac{1}{7}\cdot x-\frac{2}{7}+3=-\frac{1}{7}\cdot x+\frac{19}{7}.[/tex]2) Parallel line
The equation of the perpendicular line has the form:
[tex]y=m_p\cdot(x-x_0)+y_0.[/tex]Where mₚ is the slope, and (x₀, y₀) = (-2, 3).
From the equation of the given line, we see that its slope is m = 7. The parallel line has the same slope as the given line, so we have:
[tex]\begin{gathered} m_p=m, \\ m_p=7. \end{gathered}[/tex]Replacing mₚ = 7 and (x₀, y₀) = (-2, 3) in the equation of the parallel line, we get:
[tex]y=7\cdot(x-(-2))+3=7\cdot(x+2)+3=7x+14+3=7x+17.[/tex]3) Graph
Plotting the equations obtained, we get the following graph:
Answer1) Equation of the perpendicular line:
[tex]y=-\frac{x}{7}+\frac{19}{7}[/tex]2) Equation of the parallel line:
[tex]y=7x+17[/tex]Write the equation of a line the goes through point
(3,-4) and is perpendicular to the line x = 1.
keeping in mind that x = 1 is just a vertical line, Check the picture below.
Plot the vertex of f(x) = (x − 2)2 + 2.
Take into account that the general function of a parabola in vertex form is given by:
[tex]f(x)=a(x-h)^2+k[/tex]where (h,k) is the vertex of the parabola.
By comparing the previous general function with the given function:
[tex]f(x)=(x-2)^2+2[/tex]you can notice that:
h = 2
k = 2
Hence, you can conclude that the vertex of the given function is (2,2)
Determine the reasonableness of a solution to a logarithmic equation
SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Write the given equation
[tex]\log_3x=7[/tex]STEP 2: State the law of logarithm
[tex]\begin{gathered} If\text{ }\log_ab=c \\ \Rightarrow b=a^c \\ By\text{ substitution,} \\ \therefore\log_aa^c=c \end{gathered}[/tex]STEP 3: Substitute the given values in the question to get the correct answer
[tex]\begin{gathered} \log_3x=7 \\ x=3^7 \\ By\text{ substitution,} \\ \log_3(3^7)=7 \end{gathered}[/tex]Hence, Answer is:
[tex]\log_3(3^7)=7[/tex]OPTION A