Answer: Distributive property a(b+c) = ab + ac
-5(7)x + 7(7) = -35x + 49 (D)
At which point would the graphs of the equations below intersect?
{
3
x
−
4
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=
−
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−
6
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5
y
=
7
3x-4y = -2 -6x+5y = 7
A.
(
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2
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-
2
,
-
1
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B.
(
2
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−
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(
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D.
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Answer:
can't explain without you arranging your mathematical expression
Crop yield is the ratio of the number of bushels harvested to the number of acres used for the harvest. This year, the harvest at a farm was 9,396 bushels of soybeans, resulting in a crop yield of 40. 5 bushels per acre. To the nearest whole acre, how many acres were harvested? 232 acres 252 acres 285 acres 295 acres.
The total harvested area is 232 acres .
To determine the number of acres harvested, we simply have to divide the bushels of soybean by the crop yield.
Mathematically we can write it as,
What is the formula for the total land area?The total land area = bushels of soybean / bushels per acre
Substituting the known values,
[tex]Total land area = 9396 / 40.5 = 232[/tex]
Therefore, 232 acres were harvested.
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Answer:The total harvested area is 232 acres
Step-by-step explanation:
Helpppppp!!!
(Show work)
Answer:
( - y - 3 , - x - 1 )
Step-by-step explanation:
( x , y ) ----> ( - y , x ) ----> ( - y - 3 , x + 1 ) ----> ( - y - 3 , - x - 1 )
Unit 10: circles homework 2: central angles & arc measures
The central angle (127 degrees) is the angle at point K
The measures of JL and JML are 127 and 233 degrees, respectively
How to determine the measures of angles JL and JML?From the complete question, we have:
JL = 127 degrees.
The sum of angles at a point is 360 degrees
So, we have:
JML + 127 = 360
Subtract 127 from both sides
JML = 233
Hence, the measures of JL and JML are 127 and 233 degrees, respectively
Read more about circles and arcs at:
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How do you write a decimal for 30 divided by 8
Answer:
3.75?
Step-by-step explanation:
I dont know if this is what youre looking for but I guess?
x=3y+1
2x+4y=12
Solve each system by substitution
The required values are :
[tex]\qquad \sf \dashrightarrow \:x = 4[/tex]
and
[tex]\qquad \sf \dashrightarrow \:y = 1[/tex]
Check the attachment for solution ~
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Can someone please answer & show work? Thanks.
Bruce and his family arrived at the beach at 10:28 a.m. on Saturday morning. They left their house 12 hours and 20 minutes before their arrival at the beach. What time did they leave their house?
Include am or pm in your answer.
help me pls
Answer:
10:48 pm will be your answer
if x=-2 then write the ordered pair that is a solution of 5x-3y=-25
Answer:
(2,11 2/3) or (2,(35/3))
Step-by-step explanation:
5x-3y=-25
For x = 2:
5(2)-3y=-25
10-3y=-25
-3y=-35
y = (35/3) or 11 2/3
(2,11 2/3)
Answer:
X = -2
Y= 5
You use:
5x-3(5)=-25
and
5(-2)-3y=-25
Please Help I'm Confused.
Answer:
The last one
Step-by-step explanation:
Look at A and A'
It moved 4 units to the right and 1 unit down
The same with B, B' and C, C'
PLEASE HELP!!! will give brainlisest
Answer:
[tex]\sf \dfrac{x}{8}-22[/tex]
Explanation:
[tex]\rightarrow \sf \left(\dfrac{7}{8}x-4\right)-3\left(\dfrac{1}{4}x+6\right)[/tex]
remove parenthesis
[tex]\sf \rightarrow \dfrac{7}{8}x-4-\dfrac{3x}{4}-18[/tex]
expand
[tex]\rightarrow \sf \dfrac{7x}{8}-\dfrac{3x}{4}-22[/tex]
simplify
[tex]\rightarrow \sf \dfrac{x}{8}-22[/tex]
Answer:
[tex]\frac18x-22[/tex]
Step-by-step explanation:
Given expression:
[tex](\frac78x-4)-3(\frac14x+6)[/tex]
Expand:
[tex]\implies \frac78x-4-\frac34x-18[/tex]
Gather like terms:
[tex]\implies \frac78x-\frac34x-4-18[/tex]
Change 3/4 into eighths:
[tex]\implies \frac78x-\frac68x-4-18[/tex]
Combine like terms:
[tex]\implies \frac18x-22[/tex]
Which value is a solution to x <
Answer:
0
Step-by-step explanation:
it less than 4 so u can't pick 4,so it is any number less than 4
Answer:
B) 0
Step-by-step explanation:
The open circle on 4 and the arrow pointing to the left means x < 4
x < 4 means that x is smaller than 4
4 = 4 incorrect as this says 4 is equal to 4
0 < 4 CORRECT as zero is smaller than 4
5 > 4 incorrect as 5 is bigger than 4
4.5 > 4 incorrect as 4.5 is bigger than 4
6,402.66 divided by 459438.26
Answer: 0.0139358
Step-by-step explanation: 999,999,999,999,999,999,999,999,999,999,999% sure!
divide, need help again ppl, thanks!
Answers:
5.) [tex]\displaystyle \pm{1\frac{2}{3}}[/tex]
4.) [tex]\displaystyle 2[/tex]
3.) [tex]\displaystyle \pm{1\frac{2}{3}}[/tex]
2.) [tex]\displaystyle 2[/tex]
1.) [tex]\displaystyle \pm{2}[/tex]
Step-by-step explanations:
5.) [tex]\displaystyle \frac{\sqrt{75}}{\sqrt{27}} \hookrightarrow \sqrt{2\frac{7}{9}} \hookrightarrow \frac{\pm{5\sqrt{3}}}{\pm{3\sqrt{3}}} \\ \\ \boxed{\pm{1\frac{2}{3}}}[/tex]
4.) [tex]\displaystyle \frac{\sqrt[5]{96}}{\sqrt[5]{3}} \hookrightarrow \sqrt[5]{32} \hookrightarrow \frac{2\sqrt[5]{3}}{\sqrt[5]{3}} \\ \\ \boxed{2}[/tex]
3.) [tex]\displaystyle \frac{\sqrt{125}}{\sqrt{45}} \hookrightarrow \sqrt{2\frac{7}{9}} \hookrightarrow \frac{\pm{5\sqrt{5}}}{\pm{3\sqrt{5}}} \\ \\ \boxed{\pm{1\frac{2}{3}}}[/tex]
2.) [tex]\displaystyle \frac{\sqrt[3]{24}}{\sqrt[3]{3}} \hookrightarrow \sqrt[3]{8} \hookrightarrow \frac{2\sqrt[3]{3}}{\sqrt[3]{3}} \\ \\ \boxed{2}[/tex]
1.) [tex]\displaystyle \frac{\sqrt{8}}{\sqrt{2}} \hookrightarrow \sqrt{4} \hookrightarrow \frac{\pm{2\sqrt{2}}}{\pm{\sqrt{2}}} \\ \\ \boxed{\pm{2}}[/tex]
I am joyous to assist you at any time.
Help Please!!!!!!!!!!!!!
Answer:
A. 2086 yd²
Step-by-step explanation:
SA = 2lw + 2wh + 2lh
SA = 2*17*20 + 2*20*19 + 2*17*19
SA = 680 + 760 + 646
SA = 2086
Hope this helps :)
(i) Express 0•05 as a common fraction.
(ii) Find the sum of the following;
a. 673•3 + 34•92
b. 6095 + 2540•40
c. 141 + 6•392
Answer:
please rate and mark as brainlest.
Step-by-step explanation:
(i) 1/20
(ii)
a.708.22
b.8635.4
c.147.392
please rate and mark as brainlest.
Use the linear inequality + 8y 24 for Part A, Part B, and Part C. Part A: Determine the boundary line, and state whether the line will be dashed or solid. Part B: Which half-plane should be shaded? Describe where you should shade using the language "above" or "below" the line. Part C: Show your work for Part B to show how you determined which half-plane to shade.
Answer:
Given inequality: [tex]x+8y\leq 24[/tex]
Part A
Solid line: ≤ or ≥
Dashed line: < or >
Therefore, the line will be solid.
Part B
Shading above the line: y > or y ≥
Shading below the line: y < or y ≤
Therefore, shade below the line.
Part C
Make y the subject to determine where to shade.
Given inequality:
[tex]x+8y\leq 24[/tex]
Subtract x from both sides:
[tex]8y\leq 24-x[/tex]
Divide both sides by 8:
[tex]y\leq 3-\dfrac18x[/tex]
[tex]\\ \rm\Rrightarrow x+8y\leqslant 24[/tex]
#Part A
as ≤ is present line will be dashed#Part B
Put (0,0)
0+8(0)≤240≤24Satisfied
Shading below the line and towards origin
#Part C
turn into y=mx+b form
8y≤-x+24y≤-1/8x+3The area of a 2/3 cube
Answer:
2 that's what soup calculated says
You can buy jars of the same jam in two sizes.
Step-by-step explanation:
Large Jar 540g for 2.16
540/2.16 = 250
(Always divide by the smallest ratio)
= 250g per 1£
Small Jar 360g for 1.37
360/1.37=262.77g
= 262.77g per 1£
Small Jar is the best value for money, more grams, same price.
Sketch the graph of y = 5 sin 2x° + 12
Function: y = 5 sin (2(x))+ 12
Find y-intercept:
y = 5 sin 2(0)+ 12
y = 12
[tex]\sf Y\:Intercepts}:\:\left(0,\:12\right)[/tex]
→ Formula for maximum: M = A + |B|
Maximum:
12 + |5|
17
When y = 17
[tex]\rightarrow \sf 17 = 5 sin (2(x))+ 12[/tex]
[tex]\rightarrow \sf \sf 5 sin (2(x)) = 5[/tex]
[tex]\rightarrow \sf sin (2(x)) = 1[/tex]
[tex]\rightarrow \sf 2x = sin^{-1}(1)[/tex]
[tex]\rightarrow \sf 2x = 90^{\circ \:}, \ \ 450^{\circ \:}[/tex]
[tex]\rightarrow \sf x = 45^{\circ \:}, \ \ 225^{\circ \:}[/tex]
maximum: ( 45° , 17 ), (225° , 17), .....
==========================================================
→ Formula for minimum: m = A ‐ |B|
Minimum:
12 - |5|
7
When y = 7
[tex]\rightarrow \sf 7 = 5 sin (2(x))+ 12[/tex]
[tex]\rightarrow \sf 5 sin (2(x)) = -5[/tex]
[tex]\rightarrow \sf 2(x) = sin^{-1}(-1)[/tex]
[tex]\rightarrow \sf x = -45^{\circ \:} , \ \ 135^{\circ \:}[/tex]
minimum: ( -45°,7), (135°, 7), .....
Repeat the same process for finding more values on the x-axis, or just follow the trend of the curve from the points found and sketch the graph easily.
[tex]\sf Domain\:\left(-\infty \: < x < \infty )[/tex]
[tex]\sf Range : 7\le \:f\left(x\right)\le \:17[/tex]
Sketched below:
What are the zeros of this function?
A. x=0 and x=6
B. x=0 and x= -9
C. x=0 and x= -6
D. x=3 and x= -9
Answer:
A
Step-by-step explanation:
The zeros are the roots or x-intercepts
They are located at coordinate points (0, 0) and (6, 0)
This means the answer is A
Hope it makes sense!
Answer:
A. x = 0 and x = 6
Step-by-step explanation:
So, the zeroes of a quadratic are the parts of it that touch the x-axis. When you find those parts, take their x value and you will get the zero.
So, in this parabola, it touches the x-axis at (0, 0) and (6, 0).
The x-values of these are 0 and 6, respectively.
Please Help! Will give Brainlest!
Answer:
amplitude = 2
Step-by-step explanation:
the amplitude is the distance from the x- axis(midline ) to the maximum value , that is
amplitude = 2
[tex]\qquad \qquad \huge \pink {\sf{☁Answer☁}} \\ \\ [/tex]
Option B ( 2 ) ✓
the amount by which the graph of the function travels above and below its midline.OR,
[tex] \sf{amplitude = distance \: from \: undisturbed \: position \div centre \: line \: to \: through \: or \: peak \: }[/tex]
[tex]\purple{\rule{15mm}{2.9pt}} \red{\rule18mm{2.5pt}} \orange{ \rule18mm{2.5pt}}[/tex]
[tex]\sf{\:мѕнαcкεя\: ♪...}[/tex]
What are quadratic equations? What are some examples?
Answer:Examples of quadratic equations are: 6x² + 11x – 35 = 0, 2x² – 4x – 2 = 0, 2x² – 64 = 0, x² – 16 = 0, x² – 7x = 0, 2x² + 8x = 0 etc. From these examples, you can note that, some quadratic equations lack the term “c” and “bx.”
Step-by-step explanation:
A quadratic equation in the variable x is an equation of the form ax^2 + b x + c = 0, where a, b, c are real numbers, a ≠ 0.
What are quadratic equations?Quadratics can be defined as a polynomial equation of a second degree, which implies that it comprises a minimum of one term that is squared. It is also called quadratic equations.
The standard form of a quadratic equation is;
Quadratic equations are the polynomial equations of degree 2 in one variable of type f(x) = ax^2 + bx + c where a, b, c, ∈ R and a ≠ 0.
These are the following examples of the quadratic equation;
x^2-2x
x^2+5x+6
x^2-5x
Any equation of the form p (x) = 0, where p (x) is a polynomial of degree 2, is a quadratic equation.
If we write the terms of p (x) in decreasing order of their degrees, then we get the standard form of the equation.
Learn more about quadratic equations here;
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x-5=16 what operation would you have to do on both sides of the equation to get x by itself
Answer:
Add 5 to both sides
Step-by-step explanation:
x-5=16
+5 +5
x=21
Answer:
Addition
Step-by-step explanation:
x - 5 = 16
x - 5 + 5 = 16 + 5
x = 21
Please help, I'm stuck
Suppose ten distinct, positive integers have a median of $10$. ("Distinct integers" means that no two integers are the same.)
What is the smallest the average of those ten integers could be?
Explain your answer in complete sentences.
Answer:
8 (or 8.4)
Step-by-step explanation:
First, the problem states the words: Distinct and positive.
That means that the smallest number we can use is 0.
We can make 10 blanks for 10 numbers for us to fill in.
_ _ _ _ _ _ _ _ _ _
Since 10 is an even number, and the median is not one single number, it will be the middle of the two numbers.
In this case, our two numbers are the 5th and 6th blank.
Any two numbers can be used, as long as they are the same actual value from 10.
Let us first put in the numbers we can, which are the numbers before the two middle blanks.
0,1,2,3, _ _ _ _ _ _
To find the median between two numbers, we can do:
(a+b) divided by 2 = median
We can use the smallest following number, 4. Then the 6th number will have to be 16 for 10 to be in the middle.
Also try the largest possible number for the 5th blank, 9. Then the 6th number will be 11.
4+16 and 9+11 both equal 20, and 20 divided by 2 is 10. So both of these work.
Now let's place the other numbers in for these two equations.
0,1,2,3,4,16,17,18,19,20
0,1,2,3,9,11,12,13,14,15
If we add the numbers of each together, we get:
0,1,2,3,4,16,17,18,19,20=100
0,1,2,3,9,11,12,13,14,15= 80
If we now divide each sum by 10 (to find the average) we get:
10
8
Since both of these were the most we could go, one with the 5th number as small as possible and one with the 5th number as large as possible.
Since the smaller answer we got was 8, the answer must be 8.
(I believe 0 is a positive integer because it doesn't carry a negative sign. If 0 is not a positive integer, the answer is 8.4. Use the same process
4.5
3
5
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Find the length of x
The length of one leg of an isosceles right triangle is 3 ft. What is the perimeter of the triangle? 3 3 StartRoot 2 EndRoot ft 3 3 StartRoot 3 EndRoot ft 6 3 StartRoot 2 EndRoot ft 6 3 StartRoot 3 EndRoot ft.
The perimeter of the isosceles right triangle comes to be 6+3√2.
Given that the length of one leg of an isosceles right triangle = 3 ft
What is an isosceles right triangle?A right-angle triangle having sides other than hypotenuse equal to each other is called an isosceles right triangle.
So, The length of the other leg of an isosceles right triangle = 3 ft
From Pythagoras theorem
Hypotenuse²=Perpendicular²+Base²
So, in the given isosceles right triangle
Hypotenuse²=Leg 1²+Leg2²
Leg 1=Leg2 = 3 feet
Hypotenuse² = 3²+3²
Hypotenuse = 3√2 ft.
So, the perimeter of the triangle = 3+3+ 3√2
The perimeter of the triangle =6+3√2
Therefore, The perimeter of the isosceles right triangle comes to be 6+3√2.
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Answer:
6 + 3 StartRoot 2 EndRoot ft
Step-by-step explanation:
Edge2022
PLEASE HELP WILL GIVE BRAINLIEST
Answer:
(2, -1)
Step-by-step explanation:
x = 2, y = −1
There are 49 students had their lunch in the cafeteria. One-
seventh of them brought lunches from home. How many
students brought lunches from home? students
Fill in the table using this function rule
y=2x+2
Photo ⬇️
Answer:
Step-by-step explanation:
Put the values of x to the equation y = 2x + 2 and calculate the value of y:
x = 2
y = 2 · 2 + 2 = 4 + 2 = 6
x = 5
y = 2 · 5 + 2 = 10 + 2 = 12
x = 6
y = 2 · 6 + 2 = 12 + 2 = 14
x = 8
y = 2 · 8 + 2 = 16 + 2 = 18