Show that the solution of the initial value problem y(t) + y(t) = g(t), y(to) = 0, y'(to) = 0. is y(t) = sin sin(t - s)g(s)ds. to

dy/dx for the equation [tex]x^7 - xy^4 + y^7 = 1[/tex]can be obtained by using implicit differentiation.

To find dy/dx, we differentiate each term of the equation with respect to x while treating y as a function of x.

Differentiating the first term, we apply the power rule: 7x^6.

For the second term, we use the product rule: [tex]-y^4 - 4xy^3(dy/dx).[/tex]

For the third term, we apply the power rule again: [tex]7y^6(dy/dx).[/tex]

The derivative of the constant term is zero.

Simplifying the equation and isolating dy/dx, we have:

[tex]7x^6 - y^4 - 4xy^3(dy/dx) + 7y^6(dy/dx) = 0.[/tex]

Rearranging terms and factoring out dy/dx, we obtain:

[tex]dy/dx = (y^4 - 7x^6) / (7y^6 - 4xy^3).[/tex]

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The cost of the cylinder in terms of the single variable, r, alone is 2000π + πr⁴

The volume of a cylinder is given by πr²h. We know that the volume of the cylinder must be 1000π cubic feet, so we can set up the following equation:

πr²h = 1000π

h = 1000/r²

The cost of the cylinder is given by 2πr²h + πr² = 2πr²(1000/r²) + πr² = 2000π + πr⁴

The cost of the cylinder in terms of the single variable, r, alone is:

Cost of cylinder = 2000π + πr⁴

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Answer:

Step-by-step explanation:

Functions are not differentiable at sharp corners.  For an absolute value function, a sharp corner happens at the vertex.

f(x) = a |x -h| + k  where (h, k) is the vertex

For your function:

g(x) = |x-6| + 2     the vertex is at (6, 2) so the function is not differentiable at (6,2)

b) There are 2 ways to solve this.  You can break down the derivative or know the slope.  We will take a look at slope.  The derivative is the slope of the function at that point. We know that there is no stretch to your g(x) function so the slope left of (6,2) is -1 and the slope right of (6,2) is +1  

Knowing this your g' will all be -1 or +1

g'(0) = -1

g'(1) = -1

g'(7) = 1

g'(14) = 1

The given integral is as follows.∮2xy dx + x²y dy, where c is the triangle vertices (0,0), (1,3), and (0,3).Here, x = x and y = xy. Therefore, we have to calculate the integrals with respect to x and y to use Green's theorem.∮2xy dx = [x²y]10 + [x²y]03 + ∫03 2x dy= [x²y]10 + [x²y]03 + [xy²]03= 3∫03 xy dy = 3[x(y²/2)]03 = 0∮x²y dy = [xy³/3]03= 3∫03 x² dy = 3[x³/3]03 = 0.

Therefore, the value of the integral is 0.

A formula for Green's theorem- Green's theorem states that: ∮P dx + Q dy = ∬(dQ/dx - dP/dy) d, A where the curve C encloses a region of the surface.

Therefore, it can be concluded that Green's theorem relates double integrals to line integrals over e C.

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To solve the given differential equation using Laplace transforms, we apply the Laplace transform to both sides of the equation. By transforming the differential equation into an algebraic equation in the Laplace domain and using the initial conditions, we find the Laplace transform of the unknown function. Then, by taking the inverse Laplace transform, we obtain the solution in the time domain.

Let's denote the unknown function as Y(s) and its derivative as Y'(s). Applying the Laplace transform to the given differential equation, we have sY(s) - y(0) = 3s/(s^2 + 9) - 11/(s^2 + 9). Using the initial conditions y(0) = 0 and y'(0) = 6, we substitute these values into the Laplace transformed equation. After rearranging the equation, we solve for Y(s) in terms of s. Next, we take the inverse Laplace transform of Y(s) to obtain the solution y(t) in the time domain.

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The general form of the solution to the given recurrence relation is:

[tex]a_n = A(2^n) + B(3^n) + C((-5)^n)[/tex], where A, B, and C are constants determined by the initial conditions of the recurrence relation.

The general form of the solution for the linear homogeneous recurrence relation is typically expressed as a linear combination of the roots of the characteristic equation.

To find the characteristic equation, we assume a solution of the form:

[tex]a_n = r^n[/tex]

Substituting this into the given recurrence relation, we get:

[tex]r^n = 4r^{n-1} + 11r^{n-2} - 30r^{n-3[/tex]

Dividing through by [tex]r^{n-3[/tex], we obtain:

[tex]r^3 = 4r^2 + 11r - 30[/tex]

This equation can be factored as:

(r - 2)(r - 3)(r + 5) = 0

The roots of the characteristic equation are r = 2, r = 3, and r = -5.

Therefore, the general form of the solution to the given recurrence relation is:

[tex]a_n = A(2^n) + B(3^n) + C((-5)^n)[/tex]

where A, B, and C are constants determined by the initial conditions of the recurrence relation.

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In the given differential equation, if F(x, y) = C is a solution, the task is to determine the value of F(0, 2). The options provided are a) 4, b) 0, c) 8, and d) 1.

To find the value of F(0, 2), we substitute the values x = 0 and y = 2 into the equation F(x, y) = C, which is a solution of the given differential equation.

Plugging in x = 0 and y = 2 into the differential equation, we have:

[2(2cos0 + 1) + 4(2)cos(z)]dy + [2(2 - 0) + 2]dx = 0.

Simplifying, we get:

[2(3) + 8cos(z)]dy + 4dx = 0.

Integrating both sides of the equation, we have:

2(3y + 8sin(z)) + 4x = K,

where K is a constant of integration.

Since F(x, y) = C, we have K = C.

Substituting x = 0 and y = 2 into the equation, we get:

2(3(2) + 8sin(z)) + 4(0) = C.

Simplifying, we have:

12 + 16sin(z) = C.

Therefore, the value of F(0, 2) is determined by the constant C. Without further information or constraints, we cannot definitively determine the value of C or F(0, 2) from the given options.

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Answer: A≈1134

Step-by-step explanation:

The answer to the question is that the area of a circle is given by the formula A=πr2

where A is the area and r is the radius. To find the area of a circle with a radius of 19 m, we need to plug in the value of r into the formula and use an approximation for π

, such as 3.14. Then, we need to round the answer to the nearest whole number. Here are the steps:

A=πr2

A=3.14×192

A=3.14×361

A=1133.54

A≈1134

Therefore, the area of the circle is approximately 1134 square meters.

W(r) represents the number of new homes purchased nationwide each month in thousands, W''(r) represents the rate of change of the rate of change of new homes purchased, W(6) = 115 means that at an interest rate of 6 percentage points, 115 thousand new homes are purchased, and W(6) = -20 means that at an interest rate of 6 percentage points, there is a decrease of 20 thousand new homes purchased

(a) The units of W(r) would be thousands of new homes purchased nationwide each month, since W represents the number of new homes in thousands.

(b) The units of W''(r) would be thousands of new homes purchased nationwide each month per percentage point squared, as the double derivative represents the rate of change of the rate of change of new homes purchased with respect to the interest rate.

The statement W(6) = 115 means that when the interest rate is 6 percentage points, the number of new homes purchased nationwide each month is 115 thousand.

The statement W(6) = -20 means that when the interest rate is 6 percentage points, the number of new homes purchased nationwide each month is -20 thousand. This negative value suggests a decrease or reduction in the number of new homes purchased at that specific interest rate.

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The expression for  (f/g)(x) is  (x-1)/(x-4).

The given function are;

f(x)=x²-2x+1

g(x)=x²+3x-4

Now proceeding the function f(x),

f(x) = x²-2x+1

     = (x - 1)²

And

g(x) =  x²+3x-4

      =  x² + 4x - x -4

      =  x(x + 4) - (x + 4)

      = (x-1)(x-4)

Now dividing the functions

(f/g)(x) =  (x - 1)²/(x-1)(x-4)

          = (x-1)/(x-4)

Hence,

⇒ (f/g)(x) = (x-1)/(x-4)

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The required derivative of the given function is[tex]$\frac{dy}{dx}=19-\frac{y}{2x}$[/tex]

The given function is 8xy = [tex]76x^2[/tex]- 8%.

A financial instrument known as a derivative derives its value from an underlying asset or benchmark. Without owning the underlying asset, it enables investors to speculate or hedging against price volatility. Futures, options, swaps, and forwards are examples of common derivatives.

Leverage is a feature of derivatives that enables investors to control a larger stake with a smaller initial outlay. They can be traded over-the-counter or on exchanges. Due to their complexity and leverage, derivatives are subject to hazards like counterparty risk and market volatility.

To find the derivative of the given function y, we need to differentiate both sides of the equation with respect to x:8xy = 76x^2 - 8% (Given)

Differentiate with respect to x,

[tex]\[\frac{d}{dx}\left[ 8xy \right]=\frac{d}{dx}\left[ 76{{x}^{2}}-8 \right]\][/tex]

Using the product rule of differentiation,\[8x\frac{dy}{dx}+8y=152x\]

Rearranging the terms, [tex]\[8x\frac{dy}{dx}=152x-8y\][/tex]

Dividing both sides by 8x,\[\frac{dy}{dx}=\frac{152x-8y}{8x}\]Simplifying, we get,\[\frac{dy}{dx}=19-\frac{y}{2x}\]

Hence, the required derivative of the given function is[tex]$\frac{dy}{dx}=19-\frac{y}{2x}$[/tex]

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Answer:

190

Step-by-step explanation:

Therefore, (0.101101101...)2 can be expressed as 1410 / 99 for the given binomial expansion.

The solution to the given question is as follows(a) To obtain the binomial expansion of (1 - x)-1 up to and including the term in x2, we use the following formula:

(1 + x)n = 1 + nx + n(n - 1) / 2! x2 + n(n - 1)(n - 2) / 3! x3 + ...The formula applies when n is a positive integer. When n is negative or fractional, we obtain a more general formula that applies to any value of n, such as(1 + x)n = 1 / (1 - x) n = 1 - nx + (n(n + 1) / 2!) x2 - (n(n + 1)(n + 2) / 3!) x3 + ...where the expansion is valid when |x| < 1.Substituting -x for x in the second formula gives us(1 - x)-1 = 1 + x + x2 + x3 + ...

The binomial expansion of (1 - x)-1 up to and including the term in x2 is therefore:1 + x + x2.To solve for (1 – x)(2 – 3x) in the form A + - X B 2-3x, we expand the expression (1 - x)(2 - 3x) = 2 - 5x + 3x2.

The required expression can be expressed as follows:A - BX 2-3x = A + BX (2 - 3x)Setting (2 - 3x) equal to 1, we get B = -1.Substituting 2 for x in the original equation gives us 3. Hence A - B(3) = 3, which implies A = 0.Thus, (1 – x)(2 – 3x) can be expressed in the form 0 + 1X(2 - 3x).

Therefore, (1 – x)(2 – 3x) in the form A + - X B 2-3x is equal to X - 6.(b) (i) To express 1 / 3 in terms of powers of 2, we proceed as follows:1 / 3 = 2k(0.a1a2a3...)2-1 = 2k a1. a2a3...where 0.a1a2a3... represents the binary expansion of 1 / 3, and k is an integer that can be determined as follows:2k > 1 / 3 > 2k+1

Dividing all sides of the above inequality by 2k+1, we get1 / 2 < (1 / 3) / 2k+1 < 1 / 4This implies that k = 1, and the binary expansion of 1 / 3 is therefore 0.01010101....Therefore, 1 / 3 can be expressed as a sum of a geometric series as follows:1 / 3 = (0.01010101...)2= (0.01)2 + (0.0001)2 + (0.000001)2 + ...= (1 / 4) + (1 / 16) + (1 / 256) + ...= 1 / 3(ii)

To convert (0.101101101...)2 to a rational number, we use the fact that any repeating binary expansion can be expressed as a rational number of the form p / q, where p is an integer and q is a positive integer with no factor of 2 or 5. Let x = (0.101101101...)2. Multiplying both sides by 8 gives8x = (101.101101101...)2. Subtracting x from 8x gives7x = (101.101)2. Multiplying both sides by 111 gives777x = 111(101.101)2= 11101.1101 - 111.01

Thus, x = (11101.1101 - 111.01) / 777= (10950.8 - 7) / 777= 10943.8 / 777= 1410 / 99 Therefore, (0.101101101...)2 can be expressed as 1410 / 99.

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The range of the piecewise function is [4, ∞), the correct option is the first one.

Here we have function g(x), which is a piecewise function, so it behaves differently in different parts of its domain.

Now, we can see that when x < 2, the function is quadratic with positive leading coefficient, so it will tend to infinity as x → -∞

Then we have g(x) = 2x when x ≥ 2, this line also tends to infinity.

Now let's find the minimum of the range.

When x = 0, we will have:

g(0) = 0² + 5 = 5

That is the minimum (because if x ≠ 0 we will have a larger value)

And when x = 2 we use the other part:

g(2) = 2*2 = 4

That is the minimum value of the line.

Then the range is [4, ∞)

The correct option is the first one.

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The derivative of  h(x) = 6 dt pH - = t+1  is 6x + C where C is the constant of integration

The fundamental theorem of calculus Part 1 is used to find the indefinite integral of a function by evaluating its definite integral between the specified limits.

The fundamental theorem of calculus Part 2 is used to evaluate the definite integral of a function between two limits by using its indefinite integral.Function h(x) is given as h(x) = 6dt pH - = t+1First, we need to find the indefinite integral of the function.

The indefinite integral of h(x) with respect to t is: 6dt = 6t + C Where C is the constant of integration.To evaluate the definite integral of h(x) between two limits, we use the fundamental theorem of calculus Part 1, which states that the derivative of the definite integral of a function is the original function.

In other words, if F(x) is the antiderivative of f(x), then: d/dx ∫a to b f(x) dx = f(x)Given that h(x) = 6dt pH - = t+1, we can evaluate the definite integral of h(x) using the limits t = a and t = x.

So, we have: h(x) = ∫a to x 6dt pH - = t+1 Differentiating we get  d/dx ∫a to x 6dt pH - = t+1= 6x + C

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Therefore, the probability that more than 50% of the people in the sample are married is approximately 0.115 (rounded to three decimal places).

To solve this problem, we can use the normal approximation to the binomial distribution since the sample size is large (n = 1000) and the proportion of married persons (p) is not too close to 0 or 1.

The mean of the sample proportion can be calculated as:

μ = p = 0.482

The standard deviation of the sample proportion can be calculated as:

σ = sqrt((p * (1 - p)) / n) = sqrt((0.482 * (1 - 0.482)) / 1000) ≈ 0.015

To find the probability that more than 50% of the people in the sample are married, we need to calculate the z-score and find the area under the normal curve to the right of this z-score.

The z-score can be calculated as:

z = (x - μ) / σ = (0.5 - 0.482) / 0.015 ≈ 1.200

Using a standard normal distribution table or a calculator, we can find that the area to the right of z = 1.200 is approximately 0.1151.

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The point that is equidistant to the points (9,3), (7,-1) and (-1,3) is: (4, 3)

Let us say that the point that is equidistant from the three given points is (x, y). Thus:

The distance is:

√(x - 9)² + (y - 3)² = √(x - 7)² + (y + 1)² = √(x + 1)² + (y - 3)²

√(x - 9)² + (y - 3)² = √(x + 1)² + (y - 3)²

(x - 9)² + (y - 3)² = (x + 1)² + (y - 3)²

(x - 9)² =  (x + 1)²

x² - 18x + 81 = x² + 2x + 1

20x = 80

x = 4

Similarly:

√(x - 7)² + (y + 1)² = √(x + 1)² + (y - 3)²

(x - 7)² + (y + 1)² = (x + 1)² + (y - 3)²

Putting x = 4, we have:

(4 - 7)² + (y + 1)² = (4 + 1)² + (y - 3)²

= 9 + y² + 2y + 1 = 25 + y² - 6y + 9

8y = 24

y = 3

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The integral ∫(0 to 3) x^2 dx can be written as the limit of a Riemann sum as the number of subintervals approaches infinity.

To evaluate the limit, we can use the formula for the sum of the squares of the first n natural numbers:

Σ(i=1 to n) [tex]i^2[/tex] = n(n + 1)(2n + 1)/6

In this case, the integral is from 0 to 3, so a = 0 and b = 3. Therefore, the width of each subinterval is Δx = (3 - 0)/n = 3/n.

Plugging these values into the Riemann sum formula, we have:

∫(0 to 3) x^2 dx = lim (n→∞) Σ(i=1 to n) [tex](iΔx)^2[/tex]

= lim (n→∞) Σ(i=1 to n) [tex](3i/n)^2[/tex]

= lim (n→∞) Σ(i=1 to n) [tex]9i^2/n^2[/tex]

Applying the formula for the sum of squares, we have:

= lim (n→∞) ([tex]9/n^2[/tex]) Σ(i=1 to n)[tex]i^2[/tex]

= lim (n→∞) ([tex]9/n^2[/tex]) * [n(n + 1)(2n + 1)/6]

Simplifying further, we get:

= lim (n→∞) ([tex]3/n^2[/tex]) * (n^2 + n)(2n + 1)/2

= lim (n→∞) (3/2) * (2 + 1/n)(2n + 1)

Taking the limit as n approaches infinity, we find:

= (3/2) * (2 + 0)(2*∞ + 1)

= (3/2) * 2 * ∞

= ∞

Therefore, the value of the integral ∫(0 to 3) x^2 dx is infinity.

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In total, the salesperson receives $450 (weekly salary) + $270 (extra payment for selling 18 items in excess) = $720 for the week.

The salesperson's base salary is $450 per week. For selling 218 items, the salesperson sold 18 items in excess of the 200 items threshold. Therefore, the salesperson receives an extra payment of $15 per item for those 18 items, which amounts to an additional $270 (18 items x $15 per item). So in total, the salesperson receives $450 (weekly salary) + $270 (extra payment for selling 18 items in excess) = $720 for the week.

Salary is the term used to describe the set amount of money an employee is paid for the labour or services they provide to a company. It acts as a monetary incentive for the person's abilities, knowledge, and commitment to the business and is often expressed as an annual or monthly sum. Salaries can vary significantly depending on a number of variables, including the position held, the sector, the location, the level of skill, and the size and financial resources of the company.

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The Taylor series for f(x) = x - 3 centered at c = 1 is given by f(x) = -2 + (x - 1).

The Taylor series is the power series of a function f(x) that is represented as the sum of its derivative values evaluated at a single point, multiplied by the corresponding powers of x − a. If you need to find the Taylor series for f(x) = x - 3 centered at c = 1, then the answer is given below.Taylor series for f(x) = x - 3 centered at c = 1:It can be obtained by the following steps:First, we need to find the n-th derivative of the function f(x) using the formula:dn/dxⁿ (f(x)) = dⁿ-¹/dxⁿ-¹ (df(x)/dx)Now, let us differentiate the given function f(x) = x - 3:df(x)/dx = 1dn/dx (f(x)) = 0dn/dx² (f(x)) = 0dn/dx³ (f(x)) = 0dn/dx⁴ (f(x)) = 0...We can see that all higher derivatives are zero for the given function f(x) = x - 3. Therefore, the nth term of the Taylor series for the given function is: fⁿ(c) (x - c)ⁿ/n!The Taylor series for f(x) = x - 3 centered at c = 1 can be represented as follows:f(x) = f(1) + f'(1)(x - 1) + f''(1)(x - 1)²/2! + f'''(1)(x - 1)³/3! + ...= -2 + (x - 1)

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To calculate the cell voltage, we can use the Nernst equation, which relates the cell potential to the concentrations of the species involved in the redox reaction.

By plugging in the given concentrations of the reactants and using the appropriate values for the reaction coefficients and the standard electrode potentials, we can determine the cell voltage.

The Nernst equation is given as: Ecell = E°cell - (RT/nF) * ln(Q)

where Ecell is the cell potential, E°cell is the standard cell potential, R is the gas constant, T is the temperature in Kelvin, n is the number of electrons transferred in the balanced redox equation, F is Faraday's constant, and Q is the reaction quotient.

In this case, we are given the concentrations of V2+ (0.566 M) and H+ (3.34 M) in one half-cell, and VO2+ (3.21 M) and Fe2+ (2.27 M) in the other half-cell. The balanced redox equation shows that 2 electrons are transferred.

We also need to know the standard electrode potentials for the V2+/VO2+ and Fe2+/Fe3+ half-reactions. By plugging these values, along with the other known values, into the Nernst equation, we can calculate the cell voltage. Round the answer to three significant digits to obtain the final result.

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When the company has 5 workers and the average salary per worker is $35000, then increasing the number of workers by one will increase the average payroll by $45000.

a) We need to find dA/dw when w = 5 and S(5) = 35000 and S'(5) = 2000.

We know that A(w) = wS(w).

By product rule, dA/dw = wdS/dw + S.

We need to find dA/dw when w = 5.So, dA/dw = 5dS/dw + S  ...............................(1)

Given, S(5) = 35000.

So, we know the value of S at w = 5.

Given, S'(5) = 2000.

So, dS/dw at w = 5 is 2000.

Now, putting w = 5, dS/dw = 2000 and S = 35000 in equation (1), we get

dA/dw = 5dS/dw + S= 5 × 2000 + 35000= 45000

Therefore, the value of dA/dw at w = 5 when S(5) = 35000 and S'(5) = 2000 is 45000.b) In part (a), we found that dA/dw = 45000 when w = 5. Therefore, when the company has 5 workers and the average salary per worker is $35000, then increasing the number of workers by one will increase the average payroll by $45000. The units of dA/dw are in dollars/worker. Therefore, if we increase the number of workers by one, then the average payroll will increase by $45000 per worker.

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The hollow sphere must have an angular speed of ω1 in order to have the same kinetic energy (k1) as the uniform sphere.

The kinetic energy (K) of a rotating object can be calculated using the formula K = (1/2) I ω², where I is the moment of inertia and ω is the angular speed. For a hollow sphere, the moment of inertia (I) is given by I = (2/3) m R², where m is the mass and R is the radius.

If the kinetic energy of the hollow sphere is k1, we can set up the equation (1/2)(2/3) m R² ω1² = k1. Simplifying this equation, we get (1/3) m R² ω1² = k1.

Now, let's consider a uniform sphere with the same mass and radius as the hollow sphere. The moment of inertia for a uniform sphere is given by I = (2/5) m R². Since the kinetic energy (k1) is the same for both the hollow and uniform spheres, we can set up another equation: (1/2)(2/5) m R² ω2² = k1. Simplifying this equation, we get (1/5) m R² ω2² = k1.

Since k1 is the same in both equations, we can equate the right sides: (1/3) m R² ω1² = (1/5) m R² ω2². Canceling out the mass and radius terms, we have (1/3) ω1² = (1/5) ω2².

Therefore, in order for the hollow sphere to have the same kinetic energy as the uniform sphere, it must have an angular speed of ω1, which is related to the angular speed of the uniform sphere (ω2) by the equation ω1² = (3/5) ω2².

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The correct relationship between a and b that must be true in the given system of inequalities is ∣a∣ > ∣b∣. The answer is C

What is a system of inequalities?

A system of inequalities refers to a set of multiple inequalities that are considered simultaneously. The solution to the system consists of all the values that satisfy each inequality in the system. It represents a region in the coordinate plane where the shaded area encompasses all the valid solutions for the given set of inequalities.

Given the inequalities y < -x + a and y > x + b, we know that the point (0,0) satisfies both of these inequalities. Plugging in x = 0 and y = 0 into the inequalities, we get:

0 < a   (from y < -x + a)

0 > b   (from y > x + b)

From these equations, we can conclude that a must be greater than 0 (since 0 < a) and b must be less than 0 (since 0 > b). To compare their magnitudes, we take the absolute values:

∣a∣ > 0   (since a > 0)

∣b∣ < 0   (since b < 0)

Since the magnitude of a (∣a∣) is greater than the magnitude of b (∣b∣), the correct relationship is ∣a∣ > ∣b∣, which is option C.

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The class boundaries for the given class are 14.2-18.6. The midpoint of the given class is 16.4. The width of the given class is 3.4 units.

The class boundaries, midpoint, and width for the class 14.7-18.1 are as follows:

Class Boundaries

For the given class, we must first identify the upper and lower boundaries.

The lower boundary is calculated by subtracting 0.5 from the lower class limit, and the upper boundary is calculated by adding 0.5 to the upper class limit.

Lower boundary = Lower class limit - 0.5 = 14.7 - 0.5 = 14.2

Upper boundary = Upper class limit + 0.5 = 18.1 + 0.5 = 18.6

Thus, the class boundaries for the given class are 14.2-18.6.

MidpointTo find the midpoint of a class, we add the upper and lower class limits and divide by 2.

Therefore, the midpoint of the class 14.7-18.1 can be calculated as follows:

Midpoint = (Lower class limit + Upper class limit) / 2= (14.7 + 18.1) / 2= 16.4

Therefore, the midpoint of the given class is 16.4.

Width

The width of the class is obtained by subtracting the lower class limit from the upper class limit.

Hence, the width of the given class is:

Width = Upper class limit - Lower class limit= 18.1 - 14.7= 3.4

Therefore, the width of the given class is 3.4 units.

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The function S(x) = 4(x - 2x) for x > 0 is increasing on the open interval (0, +∞) and does not have any relative maxima or minima.

To determine the intervals on which S(x) is increasing or decreasing, we need to examine the derivative of S(x). Taking the derivative of S(x) with respect to x, we get:

S'(x) = 4(1 - 2) = -4

Since the derivative is a constant (-4) and negative, it means that S(x) is decreasing for all values of x. Therefore, S(x) does not have any relative maxima or minima.

In terms of intervals, the function S(x) is decreasing on the entire domain of x > 0, which means it is decreasing on the open interval (0, +∞). Since it is always decreasing and does not have any turning points, there are no relative maxima or minima to be found.

In summary, the function S(x) = 4(x - 2x) for x > 0 is increasing on the open interval (0, +∞), and it does not have any relative maxima or minima.

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Answer:

  (-2, 0) and (4, -6)

Step-by-step explanation:

You want the ordered pair solutions to the system of equations ...

We can set the f(x) equal, rewrite to standard form, then factor to find the solutions.

  x² -3x -10 = -x -2

  x² -2x -8 = 0 . . . . . . . add x+2

  (x +2)(x -4) = 0 . . . . . . factor

The values of x that make the product zero are ...

  x = -2, x = 4

The corresponding values of f(x) are ...

  f(-2) = -(-2) -2 = 0

  f(4) = -(4) -2 = -6

The ordered pair solutions are (-2, 0) and (4, -6).

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The derivative of [tex]f(x) = (9x^4 - 3\sqrt{x} )^7[/tex] using the Chain Rule is given by [tex]7(9x^4 - 3\sqrt{x} )^6 * (36x^3 - (3/2)(x^{-1/2}))[/tex].

The derivative of [tex]f(x) = -6x*(2x^3 - 1)^5[/tex] using the Product Rule is given by [tex]-6(2x^3 - 1)^5 + (-6x)(5(2x^3 - 1)^4 * (6x^2))[/tex].

To find the derivative using the Chain Rule, we start by taking the derivative of the outer function [tex](9x^4 - 3\sqrt{x} )^7[/tex], which is [tex]7(9x^4 - 3\sqrt{x} )^6[/tex].

Then, we multiply it by the derivative of the inner function [tex](9x^4 - 3\sqrt{x} )[/tex], which is [tex]36x^3 - (3/2)(x^{-1/2})[/tex].

To find the derivative using the Product Rule, we take the derivative of the first term, -6x, which is -6.

Then, we multiply it by the second term [tex](2x^3 - 1)^5[/tex].

Next, we add this to the product of the first term and the derivative of the second term, which is [tex]5(2x^3 - 1)^4 * (6x^2)[/tex].

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Given data: A bus that holds a maximum of 94 people Profit function: P(x) = x(47 - 0.5x) - 94where x represents the number of people taken on the toura. To find out how many people the guide should take on the tour to maximize the profit, we need to find the derivative of the profit function and equate it to zero.

P(x) = x(47 - 0.5x) - 94Let's differentiate P(x) with respect to x using the product rule. P(x) = x(47 - 0.5x) - 94P'(x) = (47 - x) - 0.5x = 47 - 1.5xNow, we equate P'(x) = 0 to find the critical point.47 - 1.5x = 0- 1.5x = -47x = 47/1.5x = 31.33Since we cannot have 0.33 of a person, the maximum number of people the guide should take on the tour is 31 people to maximize the profit.b. Suppose the bus holds a maximum of 41 people. To find the number of people who should go on the tour to maximize the profit, we repeat the above process. We use 41 instead of 94 as the maximum capacity of the bus.P(x) = x(47 - 0.5x) - 41Let's differentiate P(x) with respect to x using the product rule. P(x) = x(47 - 0.5x) - 41P'(x) = (47 - x) - 0.5x = 47 - 1.5xNow, we equate P'(x) = 0 to find the critical point.47 - 1.5x = 0- 1.5x = -47x = 47/1.5x = 31.33Since we cannot have 0.33 of a person, the maximum number of people the guide should take on the tour is 31 people to maximize the profit.c. To find the derivative of the given function P(x) = x(47 - 0.5x) - 94, let's use the product rule. P(x) = x(47 - 0.5x) - 94P'(x) = (47 - x) - 0.5x = 47 - 1.5xThus, the derivative of the function P(x) = x(47 - 0.5x) - 94 is P'(x) = 47 - 1.5x.

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The Fourier series and the Fourier cosine series of f(x) = -x on the given intervals are identically zero.

To determine the Fourier series of the function f(x) = -x on the interval [-1, 1], we can use the general formulas for the Fourier coefficients.

The Fourier series representation of f(x) on the interval [-1, 1] is given by:

F(x) = a₀/2 + Σ(aₙcos(nπx/L) + bₙsin(nπx/L)), where L is the period (2 in this case).

To find the Fourier coefficients, we need to compute the values of a₀, aₙ, and bₙ.

A₀ = (1/L) ∫[−L,L] f(x) dx = (1/2) ∫[−1,1] -x dx = 0

Aₙ = (1/L) ∫[−L,L] f(x) cos(nπx/L) dx = (1/2) ∫[−1,1] -x cos(nπx) dx = 0 (due to symmetry)

Bₙ = (1/L) ∫[−L,L] f(x) sin(nπx/L) dx = (1/2) ∫[−1,1] -x sin(nπx) dx

Using integration by parts, we find:

Bₙ = (1/2) [x (1/nπ) cos(nπx) + (1/nπ) ∫[−1,1] cos(nπx) dx]

    = -(1/2) (1/(nπ)) [x sin(nπx) - ∫[−1,1] sin(nπx) dx]

    = (1/2nπ²) [cos(nπx)]├[−1,1]

    = (1/2nπ²) [cos(nπ) – cos(-nπ)]

    = 0 (since cos(nπ) = cos(-nπ))

Therefore, all the Fourier coefficients a₀, aₙ, and bₙ are zero. This means that the Fourier series of f(x) = -x on the interval [-1, 1] is identically zero.

For the Fourier cosine series on [0, 1], we only consider the cosine terms:

F(x) = a₀/2 + Σ(aₙcos(nπx/L))

Since all the Fourier coefficients are zero, the Fourier cosine series of f(x) on [0, 1] is also zero.

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